the focal length of a converging lens is 0.50 meters. an object is placed 1.0 meters from the lens. the distance between the lens and the image is

The acceleration of the object with an applied force of 100N and a mass of 50kg is 2m/s².

Acceleration is defined as the change in velocity per unit time. Velocity is defined as the speed of the object in a particular direction. The acceleration is a vector quantity. The unit of acceleration is m/s².

According to Newton's second law, Force is directly proportional to the acceleration of the object. F = m×a, where F is the force of the object, m is the mass of the object and a is the acceleration of the object.

From the given,

Force, F = 100N

mass of the object, m=50kg

acceleration of the object, a=?

F = m×a

a =F/m

  = 100/50

  =2m/s².

Thus, the acceleration of the object is 2m/s².

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Answer:

So, some examples may include the presence of four or five different species of tree in a woodland forest, or perhaps 100 different species of fish, crustaceans and coral in a certain reef.

l will post the option later

pls mark me brainlest

option d

Answer:

I don't even know

Explanation:

Shower thoughts

Answer:we could be an allusion but we prolly will never kno.. so much of the world is convinced, its all jus a convincing game.. i believe in past lives, future lives. i think in my past life i was stabbed and then the slit my side from the chest to right below my stomach, due to freckles lining up

Answer:

A and B

Explanation:

They contain Chlorophyll

They are relatively tall

The stems help the cactus plant survive by ;D. They hold water in the plant.

The thick, fleshy stems of a cactus plant have the ability to store water. This is an important adaptation that allows the plant to survive in arid environments with limited water availability.

The waxy coating on the stems helps to prevent water loss through evaporation. The stored water in the stems can be utilized by the cactus during periods of drought or when water is scarce, enabling the plant to survive for extended periods without rainfall.

Therefore, option D is the most accurate choice as it describes how the stems of a cactus plant help it survive by storing water.

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The total impedance of the circuit is 40.274 Ω.

To calculate the total impedance of the circuit, we need to consider the resistance and reactance components.

The resistance component is given by the value of the resistor, which is 20 Ω.

The reactance component is given by the inductor, and it depends on the frequency (f) and the inductance (L) according to the formula:

XL = 2πfL

Substituting the given values:

XL = 2π * 60 Hz * 0.093 H ≈ 35.034 Ω

The total impedance (Z) of the circuit is the combination of the resistance and reactance components. Since they are in series, we can use the Pythagorean theorem to calculate it:

Z = \(\sqrt{(R^2 + XL^2)}\)

Substituting the values:

Z = \(\sqrt{(20^2 + 35.034^2)\)

  ≈ 40.274 Ω

Therefore, the total impedance of the circuit is approximately 40.274 Ω.

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Kieran had a greater average speed than Jevon. Let us go into more detail in the explanation below. To compare the average speeds of Kieran and Jevon, we need to find out the speed of each person.

We can use the formula speed = distance/time. Kieran ran 8 laps in 18 minutes, which means he ran 8/18 = 0.44 laps per minute. To find out Kieran's speed, we need to multiply this by the length of one lap. If we assume that the length of one lap is 400 meters, then Kieran's speed is:0.44 laps per minute × 400 meters per lap = 176 meters per minute Jevon ran 6 laps of the track, but we don't know how long it took him.

Therefore, we can't calculate his speed directly. However, we can still compare his speed to Kieran's by using ratios. If we assume that Jevon ran the same length of track as Kieran, then we can write the following equation: Kieran's speed/Jevon's speed = Jevon's time/Kieran's time.

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Answer:

4

Explanation:

Impact Force = mv/2t

Impact force is inversely proportional to t

If m and v are constant and the only thing that changes is t, then:

0.005 s increases by a factor of 4 to 0.020 s

Therefore, impact force reduces by a factor of 4 (1/4 less than when the time of impact was 0.005 s)

If the same force is applied to an object with a small mass, it will experience a greater acceleration due to less inertia and the ease with which it can be accelerated. In contrast, an object with a larger mass will require more force to achieve the same acceleration.

According to Newton's Second Law of Motion, the acceleration of an object is directly proportional to the force applied to it and inversely proportional to its mass. Mathematically, we can express this relationship as:

acceleration = force / mass

Therefore, if the same force is applied to an object with a small mass, it will experience a greater acceleration compared to an object with a larger mass. This is because the smaller mass results in less inertia, meaning it requires less force to cause a given acceleration. In other words, a smaller mass will accelerate more easily when the same force is applied to it. For example, if you apply the same force to a baseball and a bowling ball, the baseball will accelerate much more quickly because it has a smaller mass than the bowling ball. Conversely, if you apply the same force to a truck and a car, the car will accelerate more quickly because it has a smaller mass than the truck.

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Answer:

4.44m/s

Explanation:

Given parameters:

Number of laps  = 4

Length of track  = 400m

Time taken  = 6min

Unknown:

Average speed  = ?

Solution:

The average speed is the total distance covered divided by the time taken.

It is mathematically expressed as;

  Average speed  = \(\frac{total distance}{time taken}\)  

Total distance  = number of laps x length of track  = 4 x 400  = 1600m

Now convert the time to seconds;

         60s  = 1 min

             6 minutes will be 6 x 60 = 360s

So;

  Average speed  = \(\frac{1600}{360}\)  = 4.44m/s

The distance between 1.00 and 0.80 markings on the stem will be 0.45 m.

To solve this problem, we need to use the principle of flotation,

"When a hydrometer is placed in a fluid, it floats at a level where the weight of the hydrometer is equal to the weight of the fluid displaced by the hydrometer."

The distance between the 1.00 and 0.80 markings on the stem corresponds to the volume of fluid displaced by the hydrometer.

Let's assume that the hydrometer floats in water, which has a density of 1000 kg/m³.

Given, weight of the hydrometer = 0.125 N,

So, the volume of water displaced by the hydrometer is:

Volume of water = Weight of hydrometer / Density of water

= (0.125 N) / (1000 kg/m³)

= 0.000125 m³

Since the area of cross-section of the hydrometer is 10⁻⁴ m², the height of water displaced by the hydrometer is:

height of water = volume of water / area of cross-section

= 0.000125 m³ / 10⁻⁴ m²

= 1.25 m

Therefore, the distance between the 1.00 and 0.80 markings on the stem corresponds to a height of 1.25 m - 0.80 m = 0.45 m.

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Benzaldehyde is not soluble in water because it is a non-polar molecule and water is a polar solvent.

Non-polar substances tend to dissolve in other non-polar substances, while polar substances dissolve in polar solvents. This is due to the fact that the polar water molecules form hydrogen bonds with each other, and the non-polar benzaldehyde molecule is unable to interact with these hydrogen bonds. As a result, benzaldehyde remains separate from the water molecules and does not dissolve in water. A non-polar substance is a chemical substance that does not have a charged distribution of electrons, meaning it does not have distinct positive and negative regions. These substances have a uniform distribution of electrons, resulting in a symmetrical molecule that does not have any polar bonds.

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Answer:

To make carrying the loads easier

Answer:

It's convenient and easy to rove a traveller's bag when it has wheels. You could easily drag the bag without hesitation instead of lifting it or pushing it heavily.

Answer:

In the first law, an object will not change its motion unless a force acts on it. In the second law, the force on an object is equal to its mass times its acceleration. In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.

When a 12-ohm lamp is plugged into a 90 V outlet, the current flowing through the circuit can be calculated using Ohm's Law. Ohm's Law states that the current (I) is equal to the voltage (V) divided by the resistance (R).  So, the current flowing through the lamp is 7.5 Amperes.

In this case, the voltage is 90 V and the resistance is 12 ohms.

Substituting these values into the formula, we get:

I = 90 V / 12 Ω = 7.5 A.

Therefore, the current flowing through the lamp is 7.5 Amperes.

This means that a rate of 7.5 Coulombs of charge flows through the lamp per second.

It is important to ensure that the lamp and the electrical circuit are designed to handle this current to prevent overheating or other safety issues.

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Answer:

Below

Explanation:

Find acceleration first

vf = vo + at     (starts from rest so vo = 0)

8 = 0 + at    

8 = at

d = vo t + 1/2 a t^2     (substitute 8 in for 'at')

200 = 0 t  + 1/2 (8) t

200 / 4 = t = 50 seconds for front of train to pass her at 8 m/s

  acceleration = change in velocity / change in time = 8 / 50 = .16 m/s^2

Back of train has to travel 120 meters at initial v = 8 m/s  and accelerating  at .16 m/s^2   :

  d = vo t + 1/2 a t^2

 120 = 8 t + 1/2 ( .16 ) t^2

           .16t^2 + 8t - 120 = 0      Quadratic Formula shows t = 13.25 s

vf = vo  + a t

vf = 8 m/s  + .16 m/s^2 ( 13.25 s) = 10.1 m/s

the critical angle for red light in diamond is 24.51°

critical angle for violet light in diamond is 24.01°.

given:

wavelength of red light λr =660nm

wavelength of violet light λv =410nm

refractive index for air=1

as the refractive index of red and violet colour in diamond is

Refractive index of red color nr= 2.407

Refractive index of violet color nv= 2.451

as it is mentioned that angle is critical angle,thus θr =90°

so,from Snell's law

n1sinθc=n2 sin 90°

Here,

n1 is the refractive index for incident medium

n2 is the refractive index for refractive medium

θc is the critical angle after which light starts reflecting internally

The critical angle for red light is here,n1=2.407, n2=1

n1sinθc=n2 sin 90°

2.407×sin θc=1×1

sin θc =(1/2.407)

θc=sin-1 0.415

θc=24.51°

Thus,the critical angle for red light in diamond is 24.51°

The critical angle for violet light is,

here,n1=2.451,n2=1

n1sinθc=n2 sin 90°

2.407×sin θc=1×1

sin θc= (1/2.451)

θc=sin-1 0.407

=24.01°

Thus,the critical angle for violet light in diamond is 24.01°.

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4.55 seconds

Given, Speed = 330.0 m/s

To find the time, it will take for the sound of thunder to travel 1.5 km, we have to apply the formula for speed :

\(speed = \frac{distance}{time} \)

This implies that:-

\(time = \frac{distance}{speed} \)

So, Let's get started with the steps -

Step 1- Convert 1.5 km to metres.

\(1.5 \: km \: \\ = > \: 1.5 \times 1000 \\ = > 1500 \: m\)

Step 2- Now, to get time, substitute the values you got now in "time=distance/speed"

\(t = \frac{1500}{330}\)

\( => t = 4.55 \: seconds\)

Therefore, the answer is 4.55 seconds

✍️ By Benjemin360 ☺️

Answer: \(30.09\times 10^{-15}\ C\)

Explanation:

Given

The first charge is \(q_1=-6\ C\)

Attraction force \(F=65\ N\)

the second charge is at \(0.005\ m\) away

Suppose the second charge is \(q_2\)

The electrostatic force is given by

\(F=\dfrac{kq_1q_2}{r^2}\)

Insert the values

\(65=\dfrac{9\times 10^9\times 6\times q_2}{[5\times 10^{-3}]^2}\\\\\Rightarrow q_2=\dfrac{65\times 25\times 10^{-6}}{54\times 10^9}\\\\\Rightarrow q_2=\dfrac{1625\times 10^{-6-9}}{54}\\\\\Rightarrow q_2=30.09\times 10^{-15}\ C\)

Answer:

See below

Explanation:

All of the PE (mgh) will be converted to KE (1/2 mv^2)

mgh = 1/2 m v^2

gh = 1/2 v^2

2 gh = v^2

v = sqrt (2gh) = sqrt ( 2 * 9.81 * 45) = 29.7 m/s

Answer:

R = -2500N

Explanation:

Use formula ΣF = Ma. We can split the Net Force into two parts: Fe - Ff  =  Ma.

Fe is the force developed by the engine: 4000N

Ff (R) is the air resistance projected on the vehicle. This is the value we're looking for.

Mass: 1000kg

Acceleration: 1.5m/s^2

Next, just plug in the values and solve.

▪4000N - Ff  =  (1000kg)(1.5m/s^2)

▪Ff = 1500N - 4000N

▪Ff = -2500N

R = -2500N.

The air resistance acting on the car is R = -2500N.

y = y 0 + v 0 y t − 1 2 g t 2 . If we take the initial position y 0 to be zero, then the final position is y = 10 m. The initial vertical velocity is the vertical component of the initial velocity: v 0 y = v 0 sin θ 0 = ( 30.0 m / s ) sin 45 ° = 21.2 m / s .

Answer:

I think its A

Explanation:

Not 100 percent sure tho but they do go up and down in big movements.

Answer:

DONT LISTEN TO THE OTHER PERSON YOU WILL GET A VIRUS ON YOUR COMPUTER

Explanation:

DONT DO IT PWEASEEEEE

The violence-viewing effect is especially pronounced when the observed violence is realistic and when the viewer is desensitized to violence.

When individuals are exposed to violent media, their attitudes toward violence can change, and they may become less sensitive to the consequences of violent actions.

This can lead to an increased likelihood of aggressive behavior in real-life situations.

The violence-viewing effect is more pronounced in children, as their brains are still developing and they are more susceptible to external influences.

Therefore, parents and caregivers should be mindful of the media that children are exposed to and limit their exposure to violent content, particularly when the violence is realistic or graphic.

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The particle is an electron. The field slows down the electron without deflecting it. The direction of the electric field is right.

In physics, the motion of electrically charged particles gives rise to a field called an electric field. It is measured in force per unit charge.

This field applies force on other charged particles.

Particles bearing opposite charges attract each other while particles having similar charges repel each other in the field.

If a positive charge is placed in the field then the field line moves in an outward direction and for a negative charge, the direction of the lines is inward.

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A point charge of magnitude  1.34 nC and negative sign is required at x = 0.3 m to balance the net force on the third charge and make it move in the +x direction with a net force of 6.00 N.

We can use Coulomb's law to calculate the force between q3 and the other charges. Let's call q2 the unknown charge.

The force on q3 due to q1 is

F1 = k * q3 * q1 / r1²

where k is Coulomb's constant, r1 is the distance between q1 and q3, and we use the fact that q1 is negative to get an attractive force. Similarly, the force on q3 due to q2 is

F2 = k * q3 * q2 / r2²

where r2 is the distance between q2 and q3, and we don't know yet whether q2 is positive or negative, so we leave it as q2.

Since the net force on q3 is given to be 6.00 N in the +x-direction, we can set up the following equation

F1 + F2 = 6.00 N

Substituting the expressions for F1 and F2 and plugging in the given values, we get

k * q3 * q1 / r1₂ + k * q3 * q2 / r2₂ = 6.00 N

Simplifying and solving for q2, we get:

q2 = (6.00 N - k * q3 * q1 / r1²) * r2² / (k * q3)

Plugging in the given values, we get:

q2 = (-6.00 N - 8.99 x 10⁹ * (-7.00 x 10⁻¹⁰ C) * (3.00 x 10⁻¹⁰ C) / (0.200 m)²) * (0.300 m)² / (8.99 x 10⁹ * 3.00 x 10⁻¹⁰ C)

Simplifying, we get

q2 = -1.34 x 10⁻⁹ C

Therefore, the magnitude of q2 is 1.34 nC (nanoCoulombs) and its sign is negative.

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When the acceleration is 0, the time t is 1/3 and 2 seconds. The position and velocity at these two times are 6.24 and 4.50, and 63 and 39, respectively.

The motion of a particle is a critical aspect of physics that involves studying the movement of an object over a specific period of time. The motion of a particle is described by its position and velocity at a given time. In this case, the motion of a particle is defined by the equation \(x = 6t^4 - 2t^3 - 12t^2 + 3t + 3\), where x is the position of the particle and t is the time expressed in meters and seconds, respectively. To determine the time, position, and velocity of the particle when acceleration is 0, we need to perform some calculations based on the equation given.

First, let's find the velocity of the particle at a given time t. The velocity of a particle is the derivative of its position, which means that we need to find the first derivative of the equation \(x = 6t^4 - 2t^3 - 12t^2 + 3t + 3\). The derivative of the equation is\(v = 24t^3 - 6t^2 - 24t + 3\). This equation represents the velocity of the particle at any time t.

Next, let's find the acceleration of the particle at a given time t. The acceleration of a particle is the derivative of its velocity, which means that we need to find the first derivative of the equation \(v = 24t^3 - 6t^2 - 24t + 3\). The derivative of the equation is \(a = 72t^2 - 12t - 24\). This equation represents the acceleration of the particle at any time t.

Now, since we are looking for the time, position, and velocity when acceleration is 0, we can set the equation \(a = 72t^2 - 12t - 24\) equal to 0 and solve for t. By using the quadratic formula, we get two values for t, t = 1/3 and t = 2. These two values represent the time when the acceleration is 0.

To find the position and velocity at these two times, we can plug in t = 1/3 and t = 2 into the equation x = \(6t^4 - 2t^3 - 12t^2 + 3t + 3\) and\(v = 24t^3 - 6t^2 - 24t + 3\), respectively. When\(t = 1/3\), the position \(x = 6 * (1/3)^4 - 2 * (1/3)^3 - 12 * (1/3)^2 + 3 * (1/3) + 3 = 6.24\), and the velocity \(v = 24 * (1/3)^3 - 6 * (1/3)^2 - 24 * (1/3) + 3 = 4.50\). When t = 2, the position \(x = 6 * 2^4 - 2 * 2^3 - 12 * 2^2 + 3 * 2 + 3 = 63\), and the velocity \(v = 24 * 2^3 - 6 * 2^2 - 24 * 2 + 3 = 39\).

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