The equation you found in Part D may be factored to give(E2−E1)(E2+E1)=p22c2−p21c2.Consider the term E2+E1. Since we are looking at the "everyday" limit of relativity, where speed is far lower than the speed of light, the kinetic energy will be negligible compared to the rest energy. Using this approximation, find the value of E2+

Answer:

Below

Explanation:

Kinetic Energy = 1/2 * m * v^2

                        = 1/2 * .45 * .2^2 = .009 J

Important Formulas:

\(KE=.5mv^2\)

Kinetic Energy(measured in joules) = .5 * mass(measured in kg) * velocity(measured in m/s)^2

__________________________________________________________

Given:

\(m=0.45kg\)

\(v=0.20m/s\)

\(KE=?\)

__________________________________________________________

\(KE=.5mv^2\)

\(KE=.5(0.45)(0.20)^2\)

__________________________________________________________

\(\fbox{KE = 0.009J}\)

Answer:

The magnitude of the angular acceleration of the wheel is 14.53 rad/s².

Explanation:

The angular acceleration can be found by using the following equation:

\( \omega_{f}^{2} = \omega_{0}^{2} + 2\alpha \Delta \theta \)  (1)

Where:

\( \omega_{f}\): is the final angular velocity = 18 rad/s

\(\omega_{0}\): is the initial angular velocity

α: is the angular acceleration =?

Δθ = 19 rev*(2π/1 rev) = 119.4 rad

The initial angular velocity can be found knowing that the wheel turns through 19 revolutions during a 3 s time interval:

\( \omega_{f} = \omega_{0} + \alpha t \)

Where:  

t: is the time = 3 s

By solving the above equation for ω₀ we have:

\( \omega_{0} = \omega_{f} - \alpha t \)   (2)

Now, by entering equation (2) into (1) we have:

\( \omega_{f}^{2} = (\omega_{f} - \alpha t)^{2} + 2\alpha \Delta \theta \)                        

\( \omega_{f}^{2} = \omega_{f}^{2} - 2\omega_{f} \alpha t + (\alpha t)^{2} + 2\alpha \Delta \theta \)                              

\((9\alpha)^{2} + 130.8 \alpha = 0\)  

By solving the above equation for "α" we have:

α = -14.53    

The minus sign means that the wheel is decelerating.

Hence, the angular acceleration of the wheel is -14.53 rad/s².                                                                                            

I hope it helps you!

Answer:

No, it cannot. The car needs the friction of the surface to drive because the car pushes the surface backwards, and the surfaces makes a reaction force pushing the car forward, and that works because of the friction. In a frictionless surface the tires would rotate in the same place

The patient would start to slide when the bed was at an inclination of 50 degrees.

Between contacting materials that are sliding or attempting to slide over one another, there is a force called friction. For instance, friction makes it challenging to push a book down the floor. Always, friction acts in the direction that is counter to the motion of the object.

The force that prevents motion when the surfaces of two objects come into contact is known as friction. Friction lessens a machine's mechanical advantage, or, to put it another way, friction decreases the output to input ratio.

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During takeoff, the aircraft acceleration at a rate of 231.9 m/s².

At speeds of about Mach 0.8 (981 km/h (610 mph)) and altitudes of roughly 10,000-15,000 m (33,000-49,000 ft) or more, jet aircraft typically cruise most efficiently. The flow Re was established with regard to the hydraulic diameter of the slot-jet in order to examine and assess the impact of jet velocity on flow behaviour.

The speed must first be changed from km/h to m/s:

264 km/h = (264/3.6) m/s = 73.3 m/s

Hence, we can apply the kinematic equation shown below:

v² = u² + 2as

where

v = final velocity = 73.3 m/s

u = initial velocity = 0 m/s

a = acceleration

s = distance = 87 m

Solving for a:

a = (v² - u²) / 2s

a = (73.3² - 0²) / (2 x 87)

a = 231.9 m/s²

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Answer:

Diagram (3).

Explanation:

N3L states that if object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A (\(F_{A} = -F_{B}\)).

The diagram which best represents the gravitational forces, F, between a satellite, S, and Earth is; Choice (3).

The law clearly states a Force of attraction; the two objects come towards each other.

Consequently, Choice (3) best represents the gravitational forces, F, between a satellite, S, and Earth.

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Answer:

24000 kg·m/s

Explanation:

Momentum is Mass x Velocity, so 1200 kg time 20 m/s =  24000 kg-ms/s

The momentum of the car is  24000 Kg•m/s

Momentum is defined as the product of mass and velocity. Mathematically, it can be expressed as:

Momentum = mass × velocity

With the above formula, we can obtain the momentum of the car as follow:

Momentum = mass × velocity

Momentum = 1200 × 20

Momentum of car = 24000 Kg•m/s

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If the engine of a boat on a river is turned off while the boat is moving with a steady speed, several things would happen Loss of propulsion,Drifting,Loss of steering control and Potential hazards.

Loss of propulsion: Without the engine running, the boat would lose its power source for propulsion. The boat would gradually slow down and eventually come to a stop unless other external forces, such as currents or wind, continue to move it.

Drifting: Once the boat comes to a stop, it would start to drift with the current of the river or be affected by wind forces. The direction and speed of the drift would depend on the strength and direction of the current or wind.

Loss of steering control: When the engine is turned off, the boat's steering mechanism, such as a rudder, would also lose power. Without the ability to steer, the boat would follow the course determined by the river's current or the wind direction.

Potential hazards: Depending on the surroundings and the current conditions, there could be potential hazards for a boat that is no longer under power. These hazards might include other vessels, obstacles, shallow areas, or strong currents. The boat's crew would need to take appropriate actions to ensure the safety of the boat and its occupants.

It's important to note that the specific behavior of the boat after the engine is turned off can vary depending on factors such as the size and design of the boat, the strength and direction of the current, and the presence of wind or other external forces.
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When a Cellulose Acetate rod is rubbed with a woolen duster, friction occurs, rubbing loosely held electrons from the rod onto the duster. So, this time, the rod loses electrons. Since the Acetate rod now has fewer electrons than protons it has become positively charged. Hope this helps!

Answer:

The charge becomes positive.

Explanation:

When rubbed with cellulose acetate the charge of the fur/wool will become negative.

The vector with a magnitude of 5 and in the direction of the vector 4i - 3j + k is approximately (20/√26)i + (-15/√26)j + (5/√26)k.

The given vector can be normalized before being multiplied by the desired magnitude. This is how to locate the vector:

The vector that has been provided should be normalized by dividing each of its components by its magnitude. The Pythagorean theorem can be used to determine the magnitude of the vector 4i - 3j + k:

Magnitude = √(4² + (-3)² + 1²) = √(16 + 9 + 1) = √26

Normalize the vector by dividing each component by the magnitude:

Normalized vector = (4/√26)i + (-3/√26)j + (1/√26)k

Multiply the normalized vector by the desired magnitude:

To obtain a vector with a magnitude of 5, multiply each component of the normalized vector by 5:

Desired vector = 5 * ((4/√26)i + (-3/√26)j + (1/√26)k)

Simplifying the expression gives:

Desired vector ≈ (20/√26)i + (-15/√26)j + (5/√26)k

So, the vector with a magnitude of 5 and in the direction of the vector 4i - 3j + k is approximately (20/√26)i + (-15/√26)j + (5/√26)k.

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(a)  The average velocity of the sprinter for the first 4 seconds is 12 m/s.

(b) The instantaneous  velocity of the sprinter at time, t = 5 s is 12 m/s.

(c) The average acceleration of the sprinter between 0 and 4 s is 3 m/s².

(d) The time of race of the sprinter is 12 s.

The average velocity of the sprinter is the change in the total displacement of the sprinter with total time of motion.

From the given graph, the average velocity of the sprinter for the first 4 seconds is 12 m/s.

The instantaneous  velocity of the sprinter at time, t = 5 s from the graph corresponds to 12 m/s, since the velocity of the sprinter from 4 s to 12 seconds is constant.

The average acceleration of the sprinter between 0 and 4 s is calculated as follows;

a = ( 12 m/s - 0 m/s ) / ( 4 s - 0 s )

a = 3 m/s²

The total time of race of the sprinter according to the graph is 12 seconds.

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At its highest temperature, a space heater has a resistance of 17.5 Ω when it is plugged into a wall outlet that supplies a peak voltage of 176.8 V sinusoidally at 60 Hz . the average power output of the space heater is 888 watts.

The average power output of the space heater can be calculated using the root mean square (RMS) values of the voltage and current. The RMS voltage and current are related to the peak voltage and the resistance of the space heater as follows:

V_RMS = V_peak / sqrt(2)

I_RMS = V_RMS / R

where V_RMS is the RMS voltage, I_RMS is the RMS current, V_peak is the peak voltage, and R is the resistance of the space heater.

Substituting the given values, we get:

V_RMS = 176.8 V / sqrt(2) = 124.8 V

I_RMS = 124.8 V / 17.5 Ω = 7.12 A

The average power output of the space heater is given by:

P_avg = V_RMS * I_RMS * cos(θ)

where cos(θ) is the power factor, which we will assume to be 1 for a resistive load like the space heater.

Substituting the values for V_RMS and I_RMS, we get:

P_avg = 124.8 V * 7.12 A * 1 = 888 W.

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Answer:

There is more to motion than distance and displacement. Questions such as, “How long does a foot race take?” and “What was the runner’s speed?” cannot be answered without an understanding of other concepts. In this section we will look at time, speed, and velocity to expand our understanding of motion.

A description of how fast or slow an object moves is its speed. Speed is the rate at which an object changes its location. Like distance, speed is a scalar because it has a magnitude but not a direction. Because speed is a rate, it depends on the time interval of motion. You can calculate the elapsed time or the change in time, Δt, of motion as the difference between the ending time and the beginning time

The SI unit of time is the second (s), and the SI unit of speed is meters per second (m/s), but sometimes kilometers per hour (km/h), miles per hour (mph) or other units of speed are used.

When you describe an object's speed, you often describe the average over a time period. Average speed, vavg, is the distance traveled divided by the time during which the motion occurs.

vavg=

distance

time

You can, of course, rearrange the equation to solve for either distance or time

time =

distance

vavg

.

distance = vavg × time

Suppose, for example, a car travels 150 kilometers in 3.2 hours. Its average speed for the trip is

vavg =

distance

time

=

150 km

3.2 h

47 km/h.

A car's speed would likely increase and decrease many times over a 3.2 hour trip. Its speed at a specific instant in time, however, is its instantaneous speed. A car's speedometer describes its instantaneous speed.

Explanation:

The statement that describes the transformation of the graph of function f onto the graph of function g is: The graph shifts 2 units right and 7 units down.

To determine the transformation of the graph of function f onto the graph of function g, we compare the two functions f(x) and g(x) and observe the changes in the equations.

The function f(x) = (1/x - 3) + 1 represents a reciprocal function that is shifted vertically 1 unit up and horizontally 3 units to the right. The reciprocal function is reflected about the line y = x.

The function g(x) = (1/(1 + 4)) + 3 simplifies to g(x) = 4 + 3 = 7, which is a constant function representing a horizontal line at y = 7.

By comparing the equations, we can see that the transformation from f(x) to g(x) involves the following changes:

The term 1/x in f(x) is replaced by the constant 1/(1 + 4) in g(x), resulting in a vertical shift of 7 units up.

The term -3 in f(x) is replaced by 3 in g(x), resulting in a vertical shift of 3 units up.

The +1 in f(x) is replaced by +3 in g(x), resulting in an additional vertical shift of 2 units up.

Therefore, the overall transformation is a shift of 2 units to the right and 7 units down.

Hence, the correct statement is: The graph shifts 2 units right and 7 units down.

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Answer:

Explanation:

a = gsinθ

a = 9.8sin30

a = 4.9 m/s²

v² = u² + 2as

v² = 0² + 2(4.9)(10)

v² = 98

v = √98 = 9.8994949...

v = 9.9 m/s

Answer:

A. length, diameter, material, temperature

a. There are two main types of pluralism: cultural and political

b. Yes, the United States is becoming more pluralistic

c. Ethnic enclaves can be both a positive and negative aspect of pluralism in the US.

a. Pluralism refers to the coexistence of multiple cultures, religions, and ethnicities within a society. There are two main types of pluralism: cultural and political. Cultural pluralism emphasizes the preservation of distinct cultural traditions, while political pluralism emphasizes the equal representation of different groups within the political system.

Cultural pluralism is often associated with the idea of multiculturalism, which recognizes and celebrates the diversity of different cultures. This type of pluralism acknowledges the importance of cultural differences and encourages individuals to maintain and express their cultural identities. In contrast, political pluralism emphasizes the importance of equal representation of different groups within the political system. This can take the form of proportional representation in government or equal access to political power for different groups.

b. The United States is becoming more pluralistic, as the population becomes more diverse and the importance of multiculturalism and political pluralism is increasingly recognized. The country is home to many different ethnic and cultural groups, and these groups are increasingly visible in politics and society. This is evident in the increasing number of ethnic and cultural enclaves, which are areas where different ethnic groups live in close proximity to one another.

c. Ethnic enclaves can be both a positive and negative aspect of pluralism in the US. On the one hand, they allow individuals to maintain their cultural traditions and create supportive communities. On the other hand, they can also lead to segregation and exclusion, as different groups may be reluctant to interact with one another. In order to promote a positive form of pluralism, it is important to encourage interaction and understanding between different groups, while also respecting and celebrating their distinct cultural identities.

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Answer:

electric field in the wide wire is

E₂ =\(\frac{E}{4}\)

Explanation:

given

length of the copper wire = L

radius of the copper wire r₁ = b

length of the second copper wire = L

radius of the second copper wire r₂ = 2b

electric field in the narrow wire = E₁=E

recall

resistance R = ρL/A

where ρ is resistivity of the copper wire, L is the length, and A is the cross sectional area.

Resistance of narrow wire, R₁

R₁ = ρL/A

where A  = πb²

R₁ = ρL/πb²---------- eqn 1

Resistance of wide wire, R₂

R₂ = ρL/A

where A = π(2b)²

R₂ = ρL/π(2b)²

R₂ = ρL/4πb²-------------- eqn 2

R₂ = ¹/₄(ρL/πb²)

comparing eqn 1 and 2

R₁ = 4R₂

calculating the current in the wire,

I = E/(R₁ + R₂)

recall

R₁ = 4R₂

∴ I = E/(4R₂ + R₂)

I = E/5R₂

calculating the potential difference across R₁ & R₂

V₁ = IR₁

I = E/5R₂

∴ V₁ = ER₁/5R₂

R₁ = 4R₂

V₁ = 4ER₂/5R₂

∴V₁  = ⁴/₅E

potential difference for R₂

V₂= IR₂

I = E/5R₂

∴ V₂ = ER₂/5R₂

V₂ = ER₂/5R₂

∴V₂  = ¹/₅E

so, electric field E = V/L

for narrow wire E₁ = V₁/L ----------- eqn 3

for wide wire, E₂ = V₂/L------------ eqn 4

compare eqn 3 and 4

E₂/E₁ = V₂/V₁( L is constant)

E₂/E₁ = ¹/₅E/⁴/₅E

E₂ = E₁/4

note E₁ = E

∴E₂ =\(\frac{E}{4}\)

In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.

This relationship is described by the equation for the generated emf in a DC generator:

Emf = Φ * N * A * Z / 60

Where:

Emf is the generated electromotive force (in volts),

Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),

N is the number of turns in the armature winding,

A is the effective area of the armature coil (in square meters),

Z is the total number of armature conductors, and

60 is a constant representing the conversion from seconds to minutes.

From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.

The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.

The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.

Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.

By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.

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The magnitude of normal force (N) on motorcycle is 704.537 N

In this type of scenario, we have been told that the mass, denoted by "m," is 350 kilograms, that the speed of the motorcycle, denoted by "v," is 29 meters per second, and that the radius of curvature, denoted by "R," is 105 meters. We can utilize the second law of motion that Newton proposed to compute the magnitude of the normal force, which is as follows:

\(m . g - N = \frac{mv^{2} }{R}\)

By applying the formula above we have:

\(350 x 9.8 - N= \frac{350x29^{2} }{108}\)

3430 - N = 2725.46296

N = 3430 - 2725.46296

N = 704.537 N

Thus, the magnitude of normal force on motorcycle would be 704.537 N

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The minimum horizontal velocity required for an object to orbit the earth just above the surface is 5.04 x 10¹⁰ m/s.

The orbital speed of Earth or a natural satellite is the speed at which it orbits around the center of the system.

The minimum horizontal velocity required for an object to orbit the earth just above the surface is calculated as follows;

V(min) = √GMR

where;

Substitute the given parameters and solve for the minimum orbital speed of the earth.

V(min) = √(6.67 x 10⁻¹¹ x 5.97 x 10²⁴ x 6.38 x 10⁶)

V(min) = 5.04 x 10¹⁰ m/s

Thus, the minimum horizontal velocity required for an object to orbit the earth just above the surface is 5.04 x 10¹⁰ m/s.

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Answer:

Personality or share the same interest similar in age or hobby

Explanation:

Answer:

Explanation:

People will form relationships with others who are similar in background, attitude and lifestyle.

Answer:

Explanation:

speed (velocity) = distance / time

                          = 0.2 km (1000 m/km)

                                     95 secs.

                          = 2.10 meters per second

The force acting on the system of two blocks connected by a rope passing over a pulley is -13.26 N.

The system of two blocks connected by a rope passing over a pulley are M1 and M2, where M1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M1 and the surface is mu subscript 1. M2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle.

The coefficient of friction between box M2 and the surface is mu subscript 2. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle.M1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. M2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.The free-body diagram of M1 shows that the weight of M1 acts straight downwards (vertically) and the normal force acts perpendicular to the slope.

The force of friction opposes the motion and acts opposite to the direction of motion.M1 = 2.25 kgTheta subscript 1 = 42.5 degreesMu subscript 1 = 0.205g = 9.81 m/s²In the free-body diagram of M2, the normal force acts perpendicular to the incline of the slope, the weight of the object acts vertically downwards and parallel to the incline, and the force of friction opposes the motion and acts opposite to the direction of motion.M2 = 5.55 kgTheta subscript 2 = 33.5 degreesMu subscript 2 = 0.105g = 9.81 m/s²The tension in the string is the same throughout the rope. Since the masses are being pulled by the same rope, the acceleration of the objects is the same as the acceleration of the rope.

The tension in the string is directly proportional to the acceleration of the objects and the rope.A system of two blocks connected by a rope passing over a pulley has a total mass of M. The acceleration of the system is given by the formula below:a = [(m1-m2)gsin(θ1) - μ1(m1+m2)gcos(θ1)] / (m1 + m2)Where, μ1 = 0.205 is the coefficient of friction of block M1θ1 = 42.5 degrees is the angle of the incline of block M1M1 = 2.25 kg is the mass of block M1M2 = 5.55 kg is the mass of block M2g = 9.81 m/s² is the acceleration due to gravitysinθ1 = sin 42.5 = 0.67cosθ1 = cos 42.5 = 0.75The acceleration of the system is:a = [(2.25-5.55)(9.81)(0.67) - (0.205)(2.25+5.55)(9.81)(0.75)] / (2.25 + 5.55)a = -1.7 m/s² (the negative sign indicates that the system is accelerating in the opposite direction).

The force acting on the system is given by:F = MaWhere M is the total mass of the system and a is the acceleration of the system. The total mass of the system is:M = m1 + m2M = 2.25 + 5.55M = 7.8 kgThe force acting on the system is:F = 7.8(-1.7)F = -13.26 N (the negative sign indicates that the force is acting in the opposite direction).

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Answer:

The speed of m2 is 0.6 m/s and its direction is to the right.

Explanation:

This numerical can be solved easily by applying law of conservation of momentum to it. According to law of conservation of momentum:

Total Momentum Before Collision = Total Momentum After Collision

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

where,

m₁ = Mass of 1st air glider = 0.25 kg

m₂ = Mass of 2nd air glider = 0.5 kg

u₁ =  Speed of 1st air glider before collision = 0.9 m/s

u₂ = Speed of 2nd air glider before collision = 0 m/s (at rest)

v₁ =  Speed of 1st air glider after collision = - 0.3 m/s (negative sign due to change in direction of velocity)

v₂ = Speed of 2nd air glider after collision = ?

Therefore,

(0.25 kg)(0.9 m/s) + (0.5 kg)(0 m/s) = (0.25 kg)(-0.3 m/s) + (0.5 kg)v₂

0.225 kg.m/s + 0.075 kg.m/s = (0.5 kg)v₂

v₂ = (0.3 kg.m/s)/(0.5 kg)

v₂ = 0.6 m/s

Positive sign indicates that v₂ is directed towards right