The equation below represents a chemical reaction. Zn (s) + 2HCl (aq) → ZnCl2 (aq) + H2 (g) A 5.00-g sample of zinc is added to hydrochloric acid. The amount of hydrochloric acid is sufficient to allow the zinc to react completely. What mass of hydrogen gas does this reaction produce? A. 0.0308 g B. 0.0771 g C. 0.121 g D. 0.154 g

In the preceding equation, 6.67 moles of boric acid (\(H_3BO_3\)) will react to generate 10 moles of water (\(H_2O\)).

To determine the number of moles of boric acid that react in the equation to produce 10 moles of water, we need to examine the balanced chemical equation and use stoichiometry.

1. Begin by examining the balanced chemical equation for the reaction involving boric acid and water. Let's assume the equation is:

  \(3H_2O\) + \(3H_2O\) -> \(B_2O_3\) + \(6H_2O\)

2. From the balanced equation, we can see that 2 moles of boric acid (H3BO3) react with 3 moles of water (\(H_2O\)) to produce 6 moles of water (\(H_2O\)).

3. Use the given information that 10 moles of water (\(H_2O\)) are produced. Since the stoichiometric ratio between boric acid and water is 2:3, we can set up a proportion to find the number of moles of boric acid:

  2 moles \(H_3BO_3\) / 3 moles \(H_2O\) = x moles \(H_3BO_3\) / 10 moles \(H_2O\)

4. Cross-multiply and solve for x:

  (2 moles \(H_3BO_3\))(10 moles \(H_2O\)) = (3 moles \(H_2O\))(x moles \(H_3BO_3\))

  20 moles \(H_2O\) = 3x moles \(H_3BO_3\)

5. Divide both sides of the equation by 3 to isolate x:

  x moles \(H_3BO_3\) = (20 moles \(H_2O\)) / 3

6. Calculate the value of x:

  x moles \(H_3BO_3\) ≈ 6.67 moles \(H_3BO_3\)

Therefore, approximately 6.67 moles of boric acid (\(H_3BO_3\)) will react to produce 10 moles of water (\(H_2O\)) in the given equation.

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Answer:

c.10 m/s²

Explanation:

By the newton's second law

Food fats and oils decay through a process known as rancidity, which affects the taste, texture, and flavour of the meal as well as the odour and smell. Unsaturated fatty acid oxidation is what triggers this process.

Rancidity is known to be influenced by time, temperature, light, air, exposed surface, moisture, nitrogenous organic material, and traces of metals.

Unsaturated fatty acids that contain double bonds in their molecules are peroxidation-prone. Lipids can undergo this peroxidation, often known as "oxidative degradation," in one of two ways. Autoxidation is one method, and it's by far the most significant one. A less significant alternative is an enzymatic oxidation. A fatty acid molecule undergoes oxidation when an oxygen ion replaces a hydrogen ion, and the likelihood of autoxidation rises as the number of double bonds increases inside the fatty acid.

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The atomic theory have been developed over the years by the works of many scientists.

The atomic theory is the series of postulations that sought to explain the behavior of the atom. The study of the atom started as far back as the time of Democritus and Aristotle.

The first empirical study of the nature of the atom started with the work of John Dalton when he proposed the famous Dalton's theory. Further empirical work was carried out by J.J Thompson which gave rise to the plum pudding model of the atoms.

The work of Ernest Rutherford introduced the planetary model of the atom which was latter replaced by the Bohr model based on energy levels. Today, the work of Erwin Schrödinger has led us to the appreciation of the wave mechanical model of the atoms which is the mot accepted model for the atom today.

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Answer: a solid transforms into a gas phase without first melting to form a liquid phase.

Explanation:

The mass number of the daughter atom formed from the alpha decay of a certain radioactive atom that has 90 protons and 142 neutrons is 228.

Alpha decay of a radioactive material is the release of an alpha particle that posseses mass number of 4 and atomic number of 2.

According to this question, a certain radioactive atom that has 90 protons and 142 neutron undergoes alpha decay. This means that the mass number of the daughter atom will be as follows:

Mass number of radioactive atom = 142 + 90 = 232

Mass number of daughter atom = 232 - 4 = 228

Therefore, the mass number of the daughter atom formed from the alpha decay of a certain radioactive atom that has 90 protons and 142 neutrons is 228.

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Given data:H2O vapor content: 13 gramsH2O vapor capacity: 52 grams at 25 degrees Celsius 13 grams at 10∘C52 grams at 30∘CFormula used to find the dew point:$$\dfrac{13}{52}=\dfrac{(A*3\pi)/(ln100)}{(17.27-A)}$$$$\frac{1}{4}=\dfrac{(A*3\pi)/(ln100)}{(17.27-A)}$$

Where A is the constantDew Point:It is the temperature at which air becomes saturated with water vapor when the temperature drops to a point where dew, frost or ice forms. To solve this question, substitute the given data into the formula.$$13/52=\dfrac{(A*3\pi)/(ln100)}{(17.27-A)}$$$$13(17.27-A)=3\pi A(ln100)$$By simplifying the above expression, we get$$A^2-17.27A+64.78=0$$Using the quadratic formula, we get$$A=9.9,7.4$$

The dew point is 7.4 since it is less than 10°C.More than 100:The term "More than 100" has not been used in the question provided.

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A zinc bromide solution containing 75.0 ccs of solid sodium carbonate is gradually added until the carbonate ion concentration reaches 0.0636 m. The maximum amount of zinc ions that can remain in the solution is 5.30 x 10^-14 moles.

The addition of solid sodium carbonate to the zinc bromide solution will result in the precipitation of zinc carbonate according to the following balanced chemical equation:

Na2CO3 + ZnBr2 -> ZnCO3 + 2NaBr

The stoichiometry of the reaction shows that one mole of zinc bromide reacts with one mole of sodium carbonate to produce one mole of zinc carbonate. Therefore, the number of moles of zinc carbonate produced will be equal to the number of moles of carbonate ion in the solution, which is given as 0.0636 moles.

The initial concentration of zinc bromide is not given, so we cannot directly calculate the number of zinc ions remaining in the solution. However, we can use the solubility product constant (Ksp) of zinc carbonate to determine the maximum amount of zinc ions that can remain in the solution before precipitation occurs.

The Ksp of zinc carbonate is given as 4.5 x 10^-11. Using the balanced chemical equation, we can write the expression for the Ksp as follows:

Ksp = [Zn2+][CO32-]

Since the concentration of carbonate ion is given as 0.0636 M, we can rearrange the above equation to solve for the maximum concentration of zinc ion that can remain in the solution:

[Zn2+] = Ksp / [CO32-] = (4.5 x 10^-11) / (0.0636)

= 7.07 x 10^-13 M

Therefore, the maximum amount of zinc ion that can remain in the solution is given by multiplying the maximum concentration by the final volume of the solution:

[Zn2+] x Vfinal = (7.07 x 10^-13 M) x (75.0 mL / 1000 mL/mL)

= 5.30 x 10^-14 moles

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Answer:

I would guess that a polar air mask would be freezing, high winds type weather. I think that's right.

Answer:

Cool and dry

Explanation:

Exactly what it is on Edge

I know I am late to answer but for the points and for the people that need it

Coordination numbers are defined for the crystalline structures that tell about the numbers of atoms bonded to the central atom. The coordination number of a diamond is 4.

A coordination number has been defining the number of the ions, atoms, and molecules that are bonded to the central atom of the crystalline compound or a complex.

The diamond has 8 carbon atoms in its one unit and its coordination number is 4 as its lattice type is face-centered cubic that has carbons at the corners and face center of the structure. One carbon contributes 1/8 hence and the faces center contributes 1/2.

Therefore, the diamond has a coordination number of 4.

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Answer:

Hypertension, also known as high blood pressure, is a long-term medical condition in which the blood pressure in the arteries is persistently elevated. High blood pressure usually does not cause symptoms. Long-term high blood pressure, however, is a major risk factor for stroke, coronary artery disease, heart failure

Answer:

a) The temperature of the water will rise by maximum 100 K, steam by 143.9 K

b) The temperature of the water will rise by maximum 100 K, steam by 1077.45 K

c) The temperature of the water will rise by maximum 100 K, steam by 972.75 K

d) The temperature of the water will rise by maximum 100 K, steam by 1027.86 K

e) The temperature of the water will rise by maximum 100 K, steam by 902.6 K

Explanation:

a) ΔH for ethanol = 29.65 kJ/g therefore, burning 100 g will produce;

29.65 × 100 = 2965 kJ

The specific heat capacity of water = 4.184 J/(g·K)

Therefore, 2965000= 1000 × 4.184 × ΔT

ΔT = 2965000 ÷ (1000 × 4.184) = 708.65 K

Latent heat of water = 2260 kJ/kg will be absorbed when the temperature reaches the boiling point of water hence we have

2965 - 2260 = 705 kJ to heat the water of which a maximum of 418.4 will boil the water and the steam temperature will rise by (705-418.4)/1.996 = 143.59 K

b) For Hexane: ΔH = 48.29 kJ/g

100 g will produce 4829 kJ

∴ Temperature change for the 1 kg water is given as follows

ΔT = 4829000 ÷ (1000 × 4.184) = 1154.16 K

However

4829 - 2260 = 2569

2569 - 418.4 = 2150.6

2150.6 / 1.996 = 1077.45 K

The final steam temperature will rise by 1077.45 K

c) For Kerosene(C₁₂H₂₆): ΔH = 46.2 kJ/g

100 g will produce 4620 kJ

∴ Hypothetically the temperature change for the 1 kg water is given as follows

ΔT = 4620000 ÷ (1000 × 4.184) = 1104.21 K

However

4620 - 2260 = 2360

2360 - 418.4 = 1941.6

1941.6 / 1.996 = 972.75 K

The final steam temperature will rise by 972.75 K

d) For Car Fuel(90% octane): ΔH = 47.3 kJ/g

100 g will produce 4730 kJ

∴ Temperature change for the 1 kg water is given as follows

ΔT = 4730000 ÷ 4184 = 1130.5 K

However

4730 - 2260 = 2470

2470 - 418.4 = 2051.6

2051.6 / 1.996 = 1027.86 K

The final steam temperature will rise by 1027.86 K

e) For Diesel (C₁₂H₂₃): ΔH = 44.8 kJ/g

100 g will produce 4480 kJ

∴ Temperature change for the 1 kg water is given as follows

ΔT = 4480000 ÷ 4184 = 1070.75 K.

However

4480 - 2260 = 2220

2220 - 418.4 = 1801.6

1801.6 / 1.996 = 902.6 K

The final steam temperature will rise by 902.6 K.

The Molarity of hydrochloric acid is 5.708 M  containing mass of 19.0% and the density of the solution is 1.095 g/ml .

Molarity of the solution is defined as the amount of solute in moles divided by the volume of solution in liters.

               M = moles of solute/liters of solution.

we can calculate the molarity by dividing the number of moles of solute by the total volume of liters of solution.

let's assume 100g solution. the mass percentage of hydrochloric acid within the solution is 19.0%. and the density of the solution that is give is 1.095g/mole. substituting all these values we can calculate the molarity of the solution.

mass Hydrochloric acid,

100g solution x (19.00g / 100g solution) = 19.00g Hcl

moles of hydrochloric acid is ,

19.00g HCl x (1 mole Hcl / 36.45g HCl) = 0.52126

then the solution is,

100g solution x (1mL solution / 1.095g solution) x (1L / 1000mL) = 0.091324L

molarity HCl = 0.52126 mole / 0.091324L = 5.708M.

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Independent: Gasoline with different amounts of lead Dependent: Amount of pollution produced

Answer:

a chemical bond in which two pairs of electrons are shared by two atoms and a molecule. Examples of compounds with double bonds include oxygen gas, carbon dioxide, acetone, and ozone

a chemical bond in which two pairs of electrons are shared between two atoms.

Answer:

941 K (668°C)

Explanation:

We have the following data:

Initial pressure : P1 = 1.45 atm

Initial temperature: T1 = 52°C + 273 = 325 K

Final pressure: P2 = 4.2 atm

Final temperature: T2 = ?

The relation between pressure and temperature for a gas at constant volume is given by Gay-Lussac's law:

P1/T1 = P2/T2

That means that the pressure is directly proportional to the absolute temperature (in K). So, we calculate T2 from the equation:

T2 = P2 x T1/P1 = 4.2 atm x (325 K/1.45 atm) = 941 K

Therefore, the final temperature would be 941 K (668°C). This is consistent with the law, that states that if the pressure increase, the temperature will be increased.  

The pH of the aqueous solution made by dissolving 50mg of H₂SO₄ and 60 mg of NaOH to a final volume of 500 ml at 25°C is  11.10.

Step 1: Convert the mass of H₂SO₄ and NaOH to moles.

Therefore, the number of moles of H₂SO₄ present in the solution = (50 mg)/(98.08 g/mol) = 0.00051 mol.

The number of moles of NaOH present in the solution = (60 mg)/(40.00 g/mol) = 0.0015 mol

Step 2: Use the number of moles of H₂SO₄ and NaOH to calculate the limiting reactant.The limiting reactant is the chemical that's present in the solution in the smallest amount. It is the chemical that will react completely with the other chemical. The limiting reactant will, therefore, determine the number of moles of any other chemical that will react completely and the products that will be formed. H₂SO₄ is the limiting reactant since it is present in a smaller amount.

Step 3: Calculate the number of moles of H⁺ ions that will be formed when H₂SO₄ reacts completely with water.

H₂SO₄ is an acid and will react with water to form H⁺ ions and HSO₄⁻ ions. HSO4⁻ ions will also react with water to form H⁺ ions and SO4²⁻ ions.

H₂SO₄ + H₂O ⟶ H⁺ + HSO₄⁻  HSO₄⁻ + H2O ⟶ H⁺ + HSO₄²⁻

The number of moles of H⁺ ions that will be formed from 0.00051 mol of H₂SO₄ is 0.00051 mol.

Step 4: Calculate the number of moles of OH⁻ ions that will be formed when NaOH reacts completely with water.NaOH is a base and will react with water to form OH⁻ ions and Na⁺ ions.NaOH + H2O ⟶ OH⁻ + Na⁺

The number of moles of OH⁻ ions that will be formed from 0.0015 mol of NaOH is 0.0015 mol.

Step 5: Calculate the concentration of H⁺ ions and OH⁻ ions in the solution.

The concentration of H⁺ ions in the solution = (number of moles of H⁺ ions)/(volume of solution)= (0.00051 mol)/(0.5 L) = 0.00102 M

The concentration of OH⁻ ions in the solution = (number of moles of OH⁻ ions)/(volume of solution)= (0.0015 mol)/(0.5 L) = 0.003 M

Step 6: Use the equation for the ion product of water to calculate the pH of the solution.

The ion product of water is given as follows: Kw = [H⁺][OH⁻] where Kw is the ion product of water (1.0 x 10-14 at 25°C).

Hence, [H⁺][OH⁻] = Kw = 1.0 x 10-14

If [H⁺][OH⁻] = 1.0 x 10-14, then [H⁺]/[OH⁻] = 1.0 x 10-14/[OH⁻] = [H3O⁺] and pH = -log[H3O⁺].

Therefore, pH = -log[H3O⁺] = -log(1.0 x 10-14/0.003) = 11.10

The pH of the aqueous solution is 11.10.

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The empirical formula of the compound is K2CrO4, which indicates that there are two potassium atoms, one chromium atom, and four oxygen atoms in the compound.

To find the empirical formula of the given compound, we need to determine the ratio of atoms in the compound. First, we need to convert the given masses of K, Cr, and O into moles by dividing them by their respective atomic masses (39.10 g/mol for K, 52.00 g/mol for Cr, and 16.00 g/mol for O). This gives us 0.0266 moles of K, 0.0135 moles of Cr, and 0.0538 moles of O.

Next, we need to find the smallest whole number ratio of atoms in the compound. We can do this by dividing each of the mole values by the smallest mole value, which is 0.0135 moles for Cr. This gives us a ratio of approximately 2:1:4 for K:Cr:O, respectively.

Therefore, the empirical formula of the compound is K2CrO4.

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Answer:

a) Vmax= 964,320,000,000,000 molecules/m3·sec

b) Vo=0.089 mol/L·sec

c) catalytic efficiency of fumarase=1.6 × 10^8 M-1 s-1

Explanation:

(a) To calculate the Vmax, we use the following formula:

Vmax = kcat × [ET] ,Where [ET] is the total enzyme concentration.

The given fumarase enzyme concentration = 2nM = 2 × 10^9 molecules/m3

[ET] = 2nM × 6.02 × 10^23 molecules/mole× 1mole/10^9nM = 1.2044 × 10^15 molecules/m3

Vmax = kcat × [ET]Vmax = 800/sec × 1.2044 × 10^15 molecules/m3= 964,320,000,000,000 molecules/m3·sec

(b) To calculate the Vo when fumarate is 47.5 μM, we use the following formula:

Vo = Vmax × [S]Km + [S]

Where [S] is the concentration of the substrate, fumarate.

Vmax = 964,320,000,000,000 molecules/m3·sec[S] = 47.5μM = 47.5 × 10^-6 mol/L

Km = 5uM = 5 × 10^-6 mol/L

Vo = Vmax × [S]Km + [S]Vo = (964,320,000,000,000 molecules/m3·sec × 47.5 × 10^-6 mol/L

)5 × 10^-6 mol/L + 47.5 × 10^-6 mol/L

Vo = 0.089 mol/L·sec

(c) The catalytic efficiency of fumarase is given by the ratio of kcat to the Km of the substrate catalyzed by an enzyme.

Catalytic efficiency = kcatKm= 800/sec5uM= 1.6 × 10^8 M-1 s-1

Therefore, the catalytic efficiency of fumarase is 1.6 × 10^8 M-1 s-1.An enzyme with a high catalytic efficiency has a high turnover number (kcat) and low substrate concentration (Km).

The enzyme fumarase has a very high catalytic efficiency of 1.6 × 10^8 M-1 s-1, indicating that it can catalyze the reaction with a high rate even at a low concentration of the substrate.

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Answer:

The three-point test

Explanation:

The three-point test refers to a ground test utilizing an auxiliary current electrode and an auxiliary potential electrode.

True. Injured individuals can rely on the common law to obtain damages and injunctions against business polluters.

The common law refers to the body of law that is developed through court decisions rather than legislation. In the context of environmental pollution caused by businesses, individuals who have suffered harm or injury due to such pollution may seek remedies under the common law.

Under the common law, individuals have the right to bring lawsuits against polluting businesses and seek damages for the harm caused. Damages can include compensation for medical expenses, property damage, loss of income, and other relevant losses resulting from the pollution. If the court finds the polluting business liable for the harm, it may order the payment of damages to the injured individuals.

Additionally, injunctions can also be sought under the common law. An injunction is a court order that requires the polluting business to stop or limit its harmful activities. In cases where ongoing pollution poses a threat to public health or the environment, injured individuals can seek injunctive relief to prevent further harm.

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Answer:

Neon, Argon, Krypton, Xenon and Radon

Explanation:

The other elements that would be expected to have similar properties as the Helium from the periodic table are the noble gases.

The noble gases are a special group of elements belonging to the last group of the periodic table.

They are called the O group or inert group because elements in this group do not combine with other atoms due to their completely filled outermost shell.

This makes them unreactive and do not readily combine with other atoms.

Answer:

scientist never ignore the missing -parts of body

Explanation:

they take the missing bones as an opportunity to look into them as practical for pre medical student ,they are very costly sealed

Answer:

2.71*10^24  formula units in 4.5 moles NaCl

Explanation:

Remark

Make sure you know what a formula unit it. In this case, what it consists of is 1 ion of Na+ Combined with 1 ion of Cl- Together they combine to make NaCl which is ordinary table salt.

1 mole contains 6.02 * 10 ^23 formula units of any chemical -- in this case NaCl.

Therefore 4.50 moles have 4.5 * 6.02*10^23 formula units.

Answer:2.71*10^24

159.77kJ

Given the balanced chemical reaction between carbon C(s) and SO2(g) expressed as:

First, we need to get the number of moles of Carbon present using the formula;

According to the reaction, 5 moles of carbon reacts to produce 239.9 kJ of heat.

To determine how much heat will be produced by 3.33 moles of Carbon, this will be expressed as:

Hence the amount of heat absorbed when 40.00 g of C( s) reacts in the presence of excess SO 2( g) to produce CS 2( l) and CO(g) is 159.77kJ

The number of grams of the original sample remaining is b. 10 g

This is the process by which unstable atomic nucleus decay into smaller atoms and also lose energy

Since the Calcium-49, a radioactive isotope, has a half-life of 9 minutes an d 80-gram sample of the isotope decays for 27 minutes, we need to find the number of half lives it takes for the radioactive decay to occur in 27 minutes

So, number of half-lives, n = time/half life

= 27 min/9 min

= 3.

Since we have 3 half-lives in 27 minutes, the number of grams remaining after 27 minutes is x = (1/2)³ × mass of sample

=  (1/2)³ × 80 g

= 1/8 × 80

= 10 g

So, the number of grams of the original sample remaining is b. 10 g

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The movement of positively charged sodium ions across the membrane of a neuron can produce an action potential. An action potential is an electrical impulse that travels down the length of the neuron, allowing for communication between neurons.

When a neuron is at rest, there is a higher concentration of sodium ions outside of the cell and a higher concentration of potassium ions inside of the cell. However, when the neuron receives a signal, channels on the cell membrane open, allowing for the influx of sodium ions.

This sudden increase in positive charge triggers the neuron to fire an action potential, which travels down the length of the neuron. Once the impulse reaches the end of the neuron, it triggers the release of neurotransmitters, which carry the signal to the next neuron in the circuit.

Overall, the movement of positively charged sodium ions plays a crucial role in the communication between neurons and the functioning of the nervous system.

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