To find the average power delivered to the train during its acceleration, we need to use the formula:
Power = Work / Time
First, we need to find the work done on the train during its acceleration. We can use the formula:
Work = Force x distance
The force on the train is equal to its mass times its acceleration:
Force = Mass x Acceleration
Using the given values, we get:
Force = 0.875 kg x (0.720 m/s^2) = 0.63 N
The distance the train travels during its acceleration can be found using the formula:
Distance = (1/2) x Acceleration x Time^2
Plugging in the given values, we get:
Distance = (1/2) x 0.720 m/s^2 x (22.0 x 10^-3 s)^2 = 0.17 m
So the work done on the train during its acceleration is:
Work = 0.63 N x 0.17 m = 0.1071 J
Now we can plug this value into the formula for power:
Power = Work / Time
The time given is 22.0 milliseconds, which is 0.0220 seconds:
Power = 0.1071 J / 0.0220 s = 4.87 W
Therefore, the average power delivered to the train during its acceleration is 4.87 watts.
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The driver of a car traveling at a speed of 27 m/s slams on the brakes and comes to a stop in 3 s. If we assume that the speed changed at a constant rate (constant net force), what was the average speed during this 3 s interval
Answer:
Average speed = 13.5 m/s
Explanation:
Since the car is running at a speed of 27 m/s and it stops after 3 seconds by applying the brake. Therefore, the initial speed of the 27 m/s and final speed is 0.
Use below formula to find the average speed :
Average speed = (Initial speed + final speed ) / 2
Average speed = (27 + 0 ) / 2
Average speed = 13.5 m/s
Why might the Earth's inner core have stopped and perhaps reversed course?
The Earth's inner core is thought to have stopped and perhaps reversed its rotation due to complex interactions between the inner and outer cores. The Earth's inner core is solid and surrounded by a liquid outer core.
What is the reason behind inner core's change in rotation?The exact reason for the inner core's change in rotation is not yet fully understood, but some scientists believe it could be related to changes in the Earth's magnetic field or variations in the flow of the liquid outer core.
What is the significance of inner core rotation?Some scientists believe that the inner core's rotation may play a role in the evolution of the Earth's magnetic field and the stability of the Earth's core.
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Johnny lets a 0.5kg ball roll on
the floor of the classroom. The ball gradually slows down. The coefficient
of friction between the floor and the ball is 0.18. Draw a free body diagram and calculate the acceleration
of the ball.
When Johnny lets a 0.5kg ball roll on the classroom floor, it gradually slows down due to friction. A free body diagram would include two main forces: gravitational force (Fg) acting downward and the normal force (Fn) acting upward.
Since the ball is on a horizontal surface, Fn and Fg cancel each other out. The other force acting on the ball is the frictional force (Ff), which opposes its motion. To calculate Ff, use the formula: Ff = μ * Fn, where μ is the coefficient of friction (0.18). As Fg and Fn are equal, Ff = μ * Fg = 0.18 * (0.5kg * 9.81m/s²) = 0.18 * 4.905 N = 0.8829 N. To find the acceleration of the ball (a), use Newton's second law: F = m * a. Rearrange the formula to find a: a = F / m. Since Ff is the only horizontal force acting on the ball, F = -Ff (the negative sign indicates that the force opposes motion). Therefore, a = -0.8829 N / 0.5 kg = -1.7658 m/s². In summary, the ball experiences an acceleration of -1.7658 m/s² due to friction, causing it to gradually slow down.
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A positive object touches a neutral electroscope, and the leaves separate. Then a negative object is brought near the electroscope, but does not touch it. What happens to the leaves?.
The leaves are getting closer.
An electroscope is an early scientific instrument used to detect the presence of electrical charges in a body. The charge is detected from the motion of the test object due to the Coulombic electrostatic force acting on the test object. The amount of electric charge on an object is proportional to the voltage. The electroscope consists of a metal button and he two blades. When a negatively charged object is brought close to the instrument, the blade will repel and move away. There are two types of electroscopes: the medulla electroscope and the gold foil electroscope. When a negatively charged object is brought close to the electroscope, the charge induces a positive charge on the leaves. So nothing should happen. However, induction causes the leaves to move closer together.
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what type of charge will an object have if the object contains less protons than electrons?
Answer:
Hello, I believe it would have a negative charge considering protons have a positive charge while elctrons have a negative charge
Explanation:
can someone help me for this question?
Answer:
A, 0.050 Hz
Explanation:
1) Frequency = speed divided by wavelength
time is 2* 60 = 120 seconds
distance = 6 wave lengths
speed = distance divided by time
speed = 6 wave lengths divided by 120
Hope this helps!
what is the bad side of the Integration /eclectic theory ?
The Integration/Eclectic Theory is a broad concept encompassing various fields and concepts. Without specific context, providing a comprehensive answer is challenging. Nevertheless, potential drawbacks or criticisms associated with integration or eclectic approaches .
Integration or eclectic approaches can be discussed:
Lack of coherence: Integrating different perspectives, frameworks, or methodologies from multiple disciplines may broaden understanding but can also result in a lack of coherence or consistency. The components may not seamlessly fit together, leading to a fragmented or unclear theoretical framework.
Overgeneralization: Eclectic approaches may incorporate diverse ideas without critically evaluating their compatibility or applicability in specific contexts. This can lead to overgeneralization or oversimplification of complex phenomena, disregarding important nuances or specific factors.
Inconsistencies and contradictions: Combining different theories or approaches carries the risk of encountering inconsistencies or contradictions among the components. This can create confusion and hinder drawing clear conclusions or making accurate predictions.
Lack of depth: Eclectic or integrative theories aiming to cover a wide range of perspectives may sacrifice depth. By attempting to include multiple viewpoints, the theory may not delve deeply into any one perspective, resulting in a superficial understanding of the underlying concepts.
Difficulty in application: Applying eclectic theories can be challenging due to a lack of clear guidelines or principles. The absence of a unified framework makes it difficult to translate the theory into practical applications or develop specific interventions based on its recommendations.
It is important to note that these drawbacks are not inherent to all integration or eclectic theories. Some approaches successfully integrate multiple perspectives and provide valuable insights. However, it is crucial to critically evaluate the strengths and weaknesses of any theoretical framework to ensure its suitability for a particular context or research question.
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What is the mass of a skier if they are applying a force of 500N and they are accelerating at 20m/s2?
\(▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪\)
We know that,
\(force = mass \times acceleration\)\(500 = m \times 20\)\(m = \dfrac{500}{20} \)\(m = 25\)Mass of skier is 25 kg
Q.7. For a system with a transfer function of G(s)=- co² s² +2a+w² if the natural frequency is 0.5 and the damping ratio is 1.3, which of the following statements is correct regarding the unit step response of the system?
O A) Damped
O B) Undamped
O C) Underdamped
O D) Crittically Damped
O E) Overdamped
The system described by the transfer function G(s) = -co² s² + 2a + w², with a damping ratio of 1.3 and a natural frequency of 0.5, has an overdamped unit step response. So, the correct option is (E)
The transfer function of the system is given as G(s) = -co² s² + 2a + w², where co represents the damping ratio, a represents an arbitrary constant, and w represents the natural frequency of the system. We are given that the natural frequency is 0.5 and the damping ratio is 1.3.
To determine the type of unit step response, we need to analyze the damping ratio (co) in relation to the critical damping value (co_critical).
The critical damping ratio (co_critical) is defined as the value where the system is on the threshold between being overdamped and underdamped. It is given by the formula co_critical = 2 * sqrt(a * w²).
In our case, the natural frequency (w) is 0.5, so we can calculate co_critical as follows: co_critical = 2 * sqrt(a * 0.5²).
Since the damping ratio (co) is given as 1.3, we can compare it with co_critical to determine the type of unit step response.
If co > co_critical, the system is considered overdamped (Option E).
If co = co_critical, the system is considered critically damped (Option D).
If co < co_critical, the system is considered underdamped (Option C).
Based on the given values, we can determine that the system is overdamped (Option E) because the damping ratio (1.3) is greater than the critical damping ratio.
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You are trying to push a 70kg crate out the back door. The force of friction between the crate and the floor is 275 N, and you push horizontally. How hard must you push to move the crate with a constant speed? If you push with a force of 380 N, what will be the crates acceleration? If her crates moved from rest, what will be the crate’s final velocity if you push with a force of 380 N for 6s?
(a) The acceleration of the crate is 1.5 m/s^2
(b) The crate’s final velocity is 9 m/s.
What will be the crates acceleration?
To move the crate with a constant velocity, the force you apply must equal the force of friction. So, to move the crate, you must push with a force of 275 N.
If you push with a force of 380 N, the net force on the crate will be;
F (net) 380 N - 275 N = 105 N.
The acceleration of the crate will be given by Newton's second law of motion:
a = F / m
where;
a is the acceleration, F is the net force, and m is the mass of the crate.So, substituting in the known values, we get:
a = 105 N / 70 kg = 1.5 m/s^2
Finally, if the crate started from rest, its final velocity after 6 seconds can be found using the equation:
v = at
v = 1.5 m/s^2 x 6s = 9 m/s
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a spy satellite of mass of 1000 kg is orbiting the earth at an altitude of 300 km/s
a) what is its period
b) what is its orbital speed
Answer:
a) The period of the satellite is approximately 5,425.305 seconds (1.507 hours)
b) The orbital velocity of the satellite is approximately 7,725.8565 m/s
Explanation:
The given parameters are;
The mass of the satellite, m = 1,000 kg
The altitude at which the satellite is orbiting, h = 300 km
a) The period of the satellite is given as follows;
\(T = 2 \times \pi \times \sqrt{\dfrac{(R + h)^3}{g \times R^2} }\)
Where;
R = The radius of the Earth = 6.371 × 10⁶ m
g = The acceleration due to gravity = 9.81 m/s²
h = The altitude of the orbit of the satellite = 300 km = 300,000 m
By substitution, we have;
\(T = 2 \times \pi \times \sqrt{\dfrac{((6.371 + 0.3)\times 10^6)^3}{9.81 \times (6.371 \times 10^6)^2} } \approx 5,425.305\)
T ≈ 5,425.305 seconds ≈ 1.507 hours
b) The orbital velocity of the satellite is given as follows;
\(v_0 = \sqrt{\dfrac{G \times M_{central}}{R + h} } = \sqrt{\dfrac{g \times R^2}{R + h} }\)
Where;
v₀ = The orbital velocity of the satellite
Which by substitution gives;
\(v_0 = \sqrt{\dfrac{9.81 \times (6.371 \times 10^6)^2}{(6.371 + 0.3) \times 10^6} } = 7,725.8565\)
The orbital velocity, v₀ = 7,725.8565 m/s.
It is estimated that a driver takes, on average, 1.5 seconds from seeing on obstacle to react by applying the brakes to stop or swerving. How far will a car, moving at 26 miles per hour in a residential neighborhood, travel (in feet) before a driver reacts to an obtacle? (round distance to one decimal place) feet
A possible means of space flight is to place a perfectly reflectingaluminized sheet into orbit around the Earth and then use the lightfrom the Sun to push this "solar sail." Suppose a sail of area 5.00 x 10^5 m/s^2 and mass 6300 kg is placed in orbit facing the Sun.
(a) What force is exerted on the sail?
(b) What is the sail's acceleration?
(c) What time interval is required for the sail to reach the Moon, 3.84 x 10^8 m away? Ignore all gravitational effects, assume the acceleration calculated in part (b) remains constant, and assume a solarintensity of 1370 W/m2.
The time interval required for the sail to reach the Moon is approximately 1980 seconds.
To solve this problem, we'll use the principles of radiation pressure and Newton's second law of motion.
(a) The force exerted on the sail can be calculated using the formula:
Force = Solar Intensity x Area
Given:
Solar Intensity = 1370 W/m^2
Area = 5.00 x 10^5 m^2
Plugging in the values, we get:
Force = 1370 W/m^2 x 5.00 x 10^5 m^2
Force = 6.85 x 10^8 N
Therefore, the force exerted on the sail is 6.85 x 10^8 N.
(b) The sail's acceleration can be determined using Newton's second law:
Force = Mass x Acceleration
Rearranging the equation:
Acceleration = Force / Mass
Given:
Mass = 6300 kg (mass of the sail)
Plugging in the values, we get:
Acceleration = (6.85 x 10^8 N) / (6300 kg)
Acceleration ≈ 1.09 x 10^5 m/s^2
Therefore, the sail's acceleration is approximately 1.09 x 10^5 m/s^2.
(c) To calculate the time interval required for the sail to reach the Moon, we can use the equation of motion:
Distance = (1/2) x Acceleration x Time^2
Rearranging the equation:
Time = √(2 x Distance / Acceleration)
Given:
Distance = 3.84 x 10^8 m (distance to the Moon)
Acceleration = 1.09 x 10^5 m/s^2 (from part b)
Plugging in the values, we get:
Time = √(2 x 3.84 x 10^8 m / 1.09 x 10^5 m/s^2)
Time ≈ 1980 seconds
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At what point does a rubber band have the most elastic potential energy? Explain.
Answer:
You input potential (stored) energy into the rubber band system when you stretched the rubber band back. Because it is an elastic system, this kind of potential energy is specifically called elastic potential energy. ... When the rubber band is released, the potential energy is quickly converted to kinetic (motion) energy.
Explanation:
A lamp hangs vertically from a cord in a descending elevator that decelerates at 2.9 m/s2. (a) If the tension in the cord is 52 N, what is the lamp's mass
The lamp descends with the elevator so its acceleration is also 2.9 m/s². Take downward to be the positive direction. Then the net force on the lamp is
∑ F = w - t = ma
where w = mg = weight of lamp, t = tension in the cord, m = mass of lamp, and a = acceleration. Then
mg - t = ma
mg - ma = t
m (g - a) = t
m = t / (g - a)
so that the lamp's mass is
m = (52 N) / (9.8 m/s² - 2.9 m/s²) ≈ 7.5 kg
Can someone help please
the tiny ripples in the background radiation cobe found are due to
The tiny ripples in the background radiation COBE found are due to the quantum fluctuations that occurred during cosmic inflation.
What is COBE?
The Cosmic Background Explorer (COBE) is a satellite that was launched in 1989 to study the cosmic microwave background radiation. It was the first satellite mission dedicated solely to cosmology, and it provided groundbreaking insights into the early universe.
What is the cosmic microwave background radiation?
The cosmic microwave background radiation is a faint glow of electromagnetic radiation that permeates the entire universe. It is thought to be the remnant of the Big Bang, and it has been detected in every direction of the sky.
What are quantum fluctuations?
Quantum fluctuations are tiny variations in the energy density of the early universe. They are a natural consequence of the uncertainty principle in quantum mechanics, and they played a crucial role in the formation of the large-scale structure of the universe.
What is cosmic inflation?
Cosmic inflation is a period of exponential expansion that occurred in the early universe. It is thought to have happened within the first 10^-32 seconds after the Big Bang, and it is responsible for the large-scale homogeneity and isotropy of the universe. Cosmic inflation was proposed in the early 1980s to solve some of the problems with the Big Bang model.
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the student knows that the image of the concave lens should serve as the object of the convex lens. if the concave lens has the focal length given in the problem statement, at what distance l in front of the convex lens should it be placed?
The distance "l" in front of the convex lens should be: \(f(o - f)/(f + i)\). The formula to determine the position of the image is: \(1/f = 1/o + 1/i\)
If the concave lens has the focal length given in the problem statement, then it should be placed at a distance "l" in front of the convex lens. The formula to determine the position of the image is:
\(1/f = 1/o + 1/i\) Where, f = focal length of the concave lens
o = distance of the object from the concave lens
i = distance of the image from the concave lens
First, determine the position of the image using the formula given above. This image will act as the object for the convex lens. Next, use the formula for the convex lens to determine the distance "l". The formula for the convex lens is: \(1/f = 1/i + 1/o\)
Where, f = focal length of the convex lens
\(1/o + 1/i = 1/f1/o + 1/(l + i)\)
= \(1/f1/(l + i)\)
= \(1/f - 1/o1/(l + i)\)
= \((o - f)/fo - f\)
=\(-f(l + i)l + i\)
= \(f(o - f)/fl\)
= \(f(o - f)/(f + i)\)
Therefore, the distance "l" in front of the convex lens should be:\(f(o - f)/(f + i)\).\((o - f)/fo - f\)
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How does an inclined plane increase force?
Acceleration will increase as the angle of incline does, and as a result, force will as well.
The gravitational force acting on the cart increases as the slope of the incline increases, causing it to accelerate more quickly.The ramp's steepness will cause an increase in inclination. As a result, the acceleration increases as the inclination angle increases. This acceleration causes the object to descend with greater speed.
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From this information, Jasmine concludes that "fertilizer b" is the best at increasing crop yields. Is Jasmine's conclusion scientifically valid? A. Yes, because "fertilizer b" increased her crop yield. B. No, because the different sections of her land were not equal in area. C. No, because the different sections of her land have different characteristics. D. No, because the crop yields were all equal.
Answer:
c
Explanation:
i just did this study island and the answer was wrong
An injured monkey sits perched on a tree branch 9 m above the ground, while a wildlife veterinarian is kneeling down in the bushes 90.0 m away attempting to subdue the monkey with a tranquilizer gun. The vet knows that the moment the gun fires, the monkey will be frightened and fall down from the branch. At what angle up from the ground must the veterinarian aim the gun so that the tranquilizer dart will hit the falling monkey? Given the angle, what is minimum speed at which the tranquilizer dart must leave the gun to still hit the monkey?
Answer:
The hunter should aim directly at the perched monkey because the tranquilizer dart will fall away from the line sight at the same rate that the monkey falls from its perch.
Tan theta = 9 / 90 = .1 so theta = 5.71 deg
The time for the monkey to reach the ground is
t = (2 h / g)^1/2 = (18 / 9.8)^1/2 = 1.36 sec
So the horizontal speed of the dart must be at least
Vx = 90 m / 1.36 sec = 66.4 m/s
Vx = V cos theta
V = 66.4 m/s / cos 5.71 = 66.7 m/s
The angle of projection of the tranquilizer dart is 5.7⁰
The horizontal speed of the tranquilizer dart is 66.5 m/s
The given parameters;
vertical position of the monkey, y = 9 mhorizontal position of the veterinarian, x = 90The angle of projection of the tranquilizer dart is calculated as;
\(tan(\theta) = \frac{y}{x} \\\\tan(\theta) = \frac{9}{90} \\\\tan(\theta) = 0.1\\\\\theta = tan^{-1}(0.1)\\\\\theta = 5.71 ^0\)
The speed of the tranquilizer dart is calculated as;
X = v₀ₓt
where;
t is the time to reach maximum height
X is the horizontal displacement = 90 m
The time to reach maximum height is calculated as;
\(h = v_0_yt + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = \frac{1}{2} gt^2\\\\t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 9}{9.8} } \\\\t = 1.36 \ s\)
The horizontal speed of the tranquilizer dart is calculated as;
\(X = v_0cos(\theta) \times t\\\\90 = v_0\times cos(5.71) \times 1.36\\\\90 = 1.353 v_0\\\\v_0= \frac{90}{1.353} \\\\v_0 = 66.5 \ m/s\)
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29.In which of the following pictures is the average kinetic energy of molecules the highest?Select one:a. Ab. Bc. Cd. D
We will have that the picture that shows the highest average kinetic energy is image B.
What would happen if the distance between Earth and the moon increased?
Answer:
Tide rising and falling would be different from the moon near the Earth .
Yash traveled 8 miles West and then 12 miles North, How far is he from his starting point?
A. 10 miles
B. 14.42 miles
C. 20 miles
D. 8.94 miles
Lab Report( 80 )
Energy
It’s time to complete your Lab Report. Save the lab to your computer with the correct unit number, lab name, and your name at the end of the file name (e.g., U1_ Lab_Energy_Alice_Jones.doc).
Introduction
1. What was the purpose of the experiment?
Type your answer here:
2. What were the independent, dependent, and control variables in your investigation? Describe the variables for the first part of the experiment.
Type your answer here:
Experimental Methods
1. What tools did you use to collect your data?
Type your answer here:
2. Describe the procedure that you followed to collect the data for the first part of the experiment.
Type your answer here:
Data and Observations
1. Record your observations in the data table.
Type your answer here:
Table 1. Measurements Taken from a Simulation of a [insert mass value] kg Ball Released from Various Heights on a Ramp
Mass of ball (kg) Drop height on ramp (m) Potential energy (J) Time to travel 1.0 m (s) Speed (m/s) Kinetic energy (J)
0.5
1.0
1.5
2.0
2.5
3.0
Conclusions
1. What conclusions can you draw about how the amount of potential energy stored in a system changes as a ball is placed at varying heights on a ramp? Write an evidence-based claim.
Type your answer here:
2. Develop a model (diagram) that shows how different amounts of gravitational potential energy (GPE) are stored in the earth-ball system when the ball is raised to different heights on the ramp.
Type your answer here:
3. How did you use what you learned from the first part of the experiment to design a marble run?
Type your answer here:
Pls answers all of these questions quickly
Answer:
Is this a research paper?
a metal block increases in tempreture from 15 digree to 60 digree when supplied with 13500 j of heat energy
By finding the specific heat, we can expect that the material of the block is copper or silver (or a mix).
Of which type of metal is the block made?We know that we give 13,500 joules of energy to the metal block (which we assume has a mass of 1kg) and the temperature increases from 15°C to 60°C.
Then the increase is:
60°C - 15°C = 45°C
Then this metal has a specific heat of:
H = 13,500j/(45°C*1 kg) = 300 J/°C*kg
So it could be copper, which has a specific heat of 380J/°C*kg or Silver, which has a specific heat of 240 J/°C*kg (or a mix of these two).
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A ball moving horizontally across my desk rolls off at a velocity of 3.3 m/s. Assuming my desk is a height of 0.81 m, how long will the ball be in the air?
Answer in units of seconds. Assume acceleration due to gravity is -9.81 m/s^2
Answer:
girl what- I can't answer this but I need points so I'ma just put this random lol sorry tho . ask the tutor
An object of mass m = 5 Kg is moving with a speed V = 2m/s Find the K.E of the moving body
Answer:
10 joules
Explanation:
formula for kinetic energy= 1/2mv²
mass (m) given = 5kg
velocity (v) given = 2m/s
therefore, by inputting them into the formula
= 1/2(5)(2)²
= 1/2 x 5 x 2²
= 1/2 x 5 x 4
= 1/2 x 20
= 10J
True or false, anything can turn into a black hole.
Answer:
False. Not everything can turn into a black hole. The formation of a black hole requires a massive object, typically a star, to collapse under its own gravity. This collapse causes the object to become so dense that it creates a singularity, a point of infinite density at the center of the black hole, which is surrounded by an event horizon, the point of no return beyond which nothing, not even light, can escape. So, only objects with sufficient mass and gravity can become black holes.
Explanation:
Why does reactivity decrease as you move from left to right on the periodic table?.
As we move from left to right the metalic properties decreases and non-metalic property increases hence reactivity of the elements decreases.
What happen to reactivity of Metal as they move from left to right ?It happens because there are more valence shells and less attraction between valence electrons and the nucleus. Consequently, the propensity to take electrons from other atoms declines. Atoms become more electronegative as they move through a period.
The ability to lose electrons increases generally with atom size. The capacity to lose electrons increases with increasing shielding. The most active metal is to the left and down because metallic character grows down the table and diminishes across it.
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