The electric flux is 300 n m2/c through two opposing faces of a 2.0cm x 2.0cm x 2.0cm box. the flux through each of the other faces is 100 n m2/c. how much charge is inside the box?

Answers

Answer 1

The electric flux is 300 n m²/C through two opposing faces of a 2.0cm x 2.0cm x 2.0cm box. the flux through each of the other faces is 100 n m²/C. The charge present inside the box is  8.85 x 10⁻⁹ Coulombs.

To determine the charge inside the box, we can use Gauss's law, which states that the electric flux passing through a closed surface is proportional to the charge enclosed by that surface.

Given:

Electric flux through two opposing faces = 300 n m²/C

Electric flux through each of the other faces = 100 n m²/C

Let's consider the two opposing faces as face A and face B, and the other four faces as face C, face D, face E, and face F.

The total flux passing through the box is the sum of the flux through each face:

Total flux = Flux through face A + Flux through face B + Flux through face C + Flux through face D + Flux through face E + Flux through face F

From the given information, we know that:

Flux through face A = Flux through face B = 300 n m²/C

Flux through each of the other faces (C, D, E, F) = 100 n m²/C

Substituting the values:

Total flux = (300 n m²/C) + (300 n m²/C) + (100 n m²/C) + (100 n m²/C) + (100 n m²/C) + (100 n m²/C)

          = 1000 n m²/C

According to Gauss's law, the total flux passing through the box is equal to the charge enclosed by the box divided by the permittivity of free space (ε₀).

Total flux = (Charge enclosed) / ε₀

We can rearrange the equation to solve for the charge enclosed:

Charge enclosed = Total flux × ε₀

The permittivity of free space (ε₀) is approximately 8.85 x 10⁻¹² C²/(N m²).

Now we can calculate the charge enclosed:

Charge enclosed = (1000 n m²/C) × (8.85 x 10⁻¹² C²/(N m²)

= 8.85 x 10⁻⁹ C

Therefore, the charge enclosed inside the box is approximately 8.85 x 10⁻⁹ Coulombs.

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Related Questions

A Projectile is launched horizontally from a height of 120m. If it lands 300 ft away from where it was launched, how fast was it launched?

Answers

The initial speed of the projectile is 18.5m/s

What is a projectile ?

Projectile motion is the motion of an object thrown into the air under gravity. Examples of projectiles include a fired bullet, a thrown javelin e t.c

When a projectile is launched horizontal, it's horizontal range is given as R = u(√2h/g)

R = 300ft = 91.44meters

h= 120m

therefore 91.44= u( √ 2×120/9.8)

91.44 = u ( √24.49)

91.44 = 4.95 u

divide both sides by 4.95

u = 91.44/4.95

u = 18.5m/s

therefore the speed of the projectile is 18.5m/s

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• ¿Qué rapidez tendrá un sonido de 150 Hz con una longitud de onda de 2 metros?

Answers

Answer:

Speed = 300 m/s

Explanation:

Given the following data;

Frequency = 150 Hz

Wavelength = 2 meters

To find the speed of the wave;

Mathematically, the speed of a wave is given by the formula:

\( Speed = wavelength * frequency \)

Substituting into the formula, we have;

\( Speed = 2 * 150\)

Speed = 300 m/s

NEPTUNE

•Number of days to orbit the sun:
•Distance around the sun:​

Answers

Answer:

1. 165 years

2. 2.781 billion mi

Explanation:

Find a unit vector perpendicular to the vectors given A=4i+2j+2k and B=4i-4j+8k.

Answers

The cross product of A and B is perpendicular to both A and B.

A × B = (4i + 2j + 2k) × (4i - 4j + 8k)

A × B = 16 (i × i) - 16 (i × j) + 32 (i × k) + 8 (j × i) - 8 (j × j) + 16 (j × k) + 8 (k × i) - 8 (k × j) + 16 (k × k)

A × B = -16 (i × j) - 32 (k × i) - 8 (i × j) + 16 (j × k) + 8 (k × i) + 8 (j × k)

A × B = -16k - 32j - 8k + 16i + 8j + 8i

A × B = 24i - 24j - 24k

The magnitude of A × B is

||A × B|| = 24 ||i - j - k|| = 24√3

Dividing A × B by its magnitude gives a unit vector,

(A × B)/||A × B|| = 1/√3 (i - j - k)

you are sliding a sofa across a horizontal floor to rearrange your living room. assume you are pushing with a horizontal force of 486.99 n, the sofa weighs 83.47 kg, and the coefficient of kinetic friction is 0.23 . calculate the magnitude of the acceleration of the sofa in units of m/s2, and round it to two decimal places.

Answers

To calculate the magnitude of the acceleration of the sofa in units of m/s2, we need to use Newton's Second Law of Motion, which states that the force acting on an object is equal to the mass of the object times its acceleration, F = ma.

We also need to account for the force of friction, which opposes the motion of the sofa and is equal to the coefficient of kinetic friction times the normal force, or Ff = μkFN.

Since the sofa is sliding across a horizontal floor, the normal force is equal to the weight of the sofa, or FN = mg. Therefore, the force of friction is Ff = μkmg.

Now we can plug in the given values and solve for the acceleration of the sofa:

F - Ff = ma

486.99 N - (0.23)(83.47 kg)(9.8 m/s2) = (83.47 kg)a

Solving for a, we get:

a = (486.99 N - (0.23)(83.47 kg)(9.8 m/s2))/(83.47 kg)

a = 3.82 m/s2

Rounding to two decimal places, the magnitude of the acceleration of the sofa is 3.82 m/s2.

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How does Physics connect to the Greenhouse Effect?

Answers

Answer: The greenhouse effect is caused by certain gases in the Earth's atmosphere trapping heat from the sun, which leads to climate change. Physics plays a role in understanding this phenomenon and developing solutions to mitigate its effects.

Explanation:

Which of these actions would increase heat transfer between two objects?A. establishing their thermal equilibriumiB. ncreasing the area of their contactC. using objects with similar specific heatsD. reducing the time of their contact

Answers

B. Increasing the area of their contact would increase heat transfer between two objects.

Heat transfer occurs due to a temperature difference between two objects in contact with each other.

The rate of heat transfer is proportional to the temperature difference, the thermal conductivity of the materials, and the surface area in contact between the objects.

Therefore, increasing the area of contact between two objects will increase the rate of heat transfer between them.

Establishing thermal equilibrium, using objects with similar specific heats, and reducing the time of contact will not necessarily increase heat transfer between the two objects.

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A force of 540 N is exerted on a 8 kg mass through 11 m. How much work was done?
• 4320 J
• 5940
• 742.5 J
• 47520 J

HELP PLEASE

Answers

The work formula is W = F * d * costheta

Theta is the angle between the force and the distance. Since they are going in the same direction, the angle is 0. Cos 0 is 1, so we can ignore that part.

The rest of the equation is force times distance.

540 * 11 = 5940 J.

Newtons laws!!! Help due midnight of June 13 !! 50 points!



Students in science class conducted an investigation of Newton's Second Law of Motion. The
students rolled two different mass balls down a ramp. All other variables, including the length
and incline of the ramp, and its distance from the force sensor, were the same for every trial.
Using the collected data, they calculated the velocity, acceleration, and force of each of the balls.
They also measured the distance the ball rolled after it bounced back off of the force sensor. The
final data, after all calculations, was entered in the data table below.
When the final results were displayed, a student exclaimed, "Hey, that data also provides
evidence that supports Newton's Third Law of Motion."
(This would be the chart, view photo)


Mass
Acceleration
Force
Distance
Ball A
1.5 m
5 kg
5 m/s/s
25 N
Ball B
10 kg
5 m/s/s
50 N
3 ml

How do the results of the investigation support Newton's Second and Third Laws of
Motion?

In your response, be sure to include
statements of Newton's Second and Third Laws of Motion
data supporting the claims that the investigation demonstrates Newton's Second and
Third Laws of Motion

Newtons laws!!! Help due midnight of June 13 !! 50 points!Students in science class conducted an investigation

Answers

Newton's second law

It states that force applied on a object is the product of mass and accelerationF=ma

Newton's third law

It states that every action has an equal and opposite reaction

Now

On coming

Here the word bounce back is used

That's enough to say the third law is applied as the reaction force helped in bounce.

And then

Check F=ma

25=5(5)50=10(5)

Yes verified

How do you find the molar mass of an unknown compound?.

Answers

The molar mass of a compound can be found by adding the molar masses of all of the atoms in the compound.

The molar mass of an atom can be found on the periodic table by looking at the atomic mass listed for that element.

For example, to find the molar mass of water (H2O), we would add the molar masses of two hydrogen atoms (2 x 1.01 g/mol) and one oxygen atom (16.00 g/mol) to get a total molar mass of 18.02 g/mol.

Another way is by finding the molecular formula of the compound, it can be done by analyzing the compound's chemical and physical properties and then using the mass spectrometer to determine the molecular weight.

In conclusion, the molar mass of a compound can be found by adding the molar masses of the atoms in the compound using the atomic masses listed on the periodic table, or by determining the molecular formula of the compound and using a mass spectrometer to find the molecular weight.

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why is it important for the input voltage of a transformer to be ac?

Answers

The input voltage of a transformer must be AC (alternating current) because transformers rely on the property of AC for effective electromagnetic induction, which is essential for their operation.

Electromagnetic induction occurs when a varying magnetic field induces an electric voltage in a conductor. In the case of a transformer, an alternating current passing through the primary coil generates a changing magnetic field, which, in turn, induces a voltage in the secondary coil.

AC is particularly well-suited for this process due to its constant change in direction, resulting in a continuously fluctuating magnetic field. This dynamic magnetic field induces a voltage in the secondary coil, facilitating efficient energy transfer from the primary coil to the secondary coil.

Conversely, if a transformer were to be powered by DC (direct current), the magnetic field produced by the unidirectional current would remain constant. As a result, there would be no continuous alteration in the magnetic field to induce a voltage in the secondary coil, severely limiting the transformer's functionality.

Hence, the utilization of AC input voltage is critical for transformers as it enables efficient energy transfer and voltage transformation between various circuits or power systems.

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carbon-14 is used to date a palm fossil that originally contained 0.24 grams of carbon-14. The half life is 5700 years. If the fossil is found to be 17,000 years old, how much Carbon-14 does it contain now?

Answers

Answer:

Exactly 0.03042 carbon-14 is remaining.

Roughly 0.03 Carbon-14 is remaining. (When/If Multiple Choice)

Explanation:

Not a physics question, this is chemistry, but I'll answer.

First, divide 17,000/5700 to find the t, or time.

t = 2.98245614 or 2.98.

If it originally contained .24 grams, and a half life means x/2,

you would use the formula x/2^p, with p being the number of half lives

(these variables are made up, you can use any you would like)

In 17,000 years, the palm fossil experienced 2.98 half lives.

Thus meaning, using our equation, we would find (.24)/2^2.98

This equals 0.030418784 carbon-14 remaining to be exact.

(For Multiple Choice, it may be required to round to For Multiple Choice, it may be required to round to 3, so .24/2/2/2 or .24/2=.12 then .06 then it equals :  .03 Carbon-14)

SWOT analysis, PESTEL analysis, Porter's Five
Forces Analysis, and Value Chain Analysis on the
company of a company (excluding netflix india, and amazon)

Answers

SWOT Analysis: Apple Inc. has a strong brand image and innovative product portfolio, but faces challenges such as high product prices and intense competition.

PESTEL Analysis: Apple Inc. is influenced by global political stability, economic conditions, changing consumer preferences, rapid technological advancements, environmental sustainability practices, and legal regulations.

Porter's Five Forces Analysis: Apple Inc. faces moderate threats of new entrants and supplier bargaining power, high buyer bargaining power and threats of substitute products, and intense competitive rivalry.

Value Chain Analysis: Apple Inc.'s value chain includes primary activities like logistics, operations, marketing, and support activities such as procurement, technology development, and human resource management.

SWOT Analysis of Apple Inc.:

Strengths: Strong brand image, innovative product portfolio, loyal customer base.Weaknesses: High product prices, dependence on a few key products, and limited customization options.Opportunities: Emerging markets, expansion into new product categories (e.g., wearables), growing demand for smart devices.Threats: Intense competition, rapidly changing technology landscape, legal and regulatory challenges.

PESTEL Analysis of Apple Inc.:

Political: Global political stability, taxation policies, intellectual property rights.Economic: Global economic conditions, exchange rates, consumer spending patterns.Sociocultural: Changing consumer preferences, lifestyle trends, environmental consciousness.Technological: Rapid technological advancements, cybersecurity risks, automation.Environmental: Environmental sustainability practices, renewable energy usage.Legal: Intellectual property laws, privacy regulations, antitrust regulations.

Porter's Five Forces Analysis of Apple Inc.:

The threat of new entrants: Moderate due to high barriers to entry, and strong brand loyalty.Bargaining power of suppliers: Moderate due to Apple's size and brand power.Bargaining power of buyers: High due to numerous alternative products available.The threat of substitute products: High due to intense competition in the tech industry.Competitive rivalry: Intense competition from companies like Samsung, and Microsoft.

Value Chain Analysis of Apple Inc.:

Primary activities: Inbound logistics, operations, outbound logistics, marketing, sales, and after-sales service.Support activities: Procurement, technology development, human resource management, firm infrastructure.

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Newton's 3rd Law of Motion
For every__________ (or force), there is an ____________ and __________ action (or force).

Answers

Answer:

Explanation:

For every action (or force), there is an equal and opposite action (or force).

Elliot is going to start strength training at home. He does not have any weights and is
brand new to strength training but is young and healthy. What would be a good
household object to use to for strength training? (1 point)
O a can of soup
O a box of tissues
O a gallon of water
O a paperback book

Answers

Answer:

A gallon of water would be a good household object to use for strength training.

Explanation:

Gallon jugs of water typically weigh around 8.3 lbs, which can provide a good amount of resistance for strength training exercises such as bicep curls, shoulder presses, and tricep dips. Additionally, the handle on the jug of water makes it easy to grip and use for various exercises. Cans of soup and boxes of tissues are generally too light to provide enough resistance for strength training, and a paperback book may not be sturdy enough to use for certain exercises.

1. List a similarity between magnetic force and electrical force.

Answers

Answer:

Both are attractive as well as repulsive.

Explanation:

(Like poles repel, like charges repel; unlike poles attract, unlike charges attract).

There are two types of charges that form electric fields: positive and negative charges. Magnetic fields are formed by charges and are related with two magnetic poles, north and south (but moving charges).

The attraction and repulsion of electric charges produce both electric and magnetic fields.

The force released by magnets when they attract or repel each other is known as magnetism. An electric force is the attracting or repulsive interaction between any two charged things.

Similarities are as follows:

There are two types of charges that form electric fields: positive and negative charges. Magnetic fields are formed by charges and are related with two magnetic poles, north and south (but moving charges).The attraction and repulsion of electric charges produce both electric and magnetic fields.

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PLZZ ANSWER THE QUESTION ​

PLZZ ANSWER THE QUESTION

Answers

D. a poster on the train- it makes sense for this to be the answer because everything else would appear to be moving away from the train.

A poster on the train.

Which force would result in a balanced force for the
game?
O 45N
O -20 N
O 20 N
O 45 N

Answers

Answer:

F= 45 N

Explanation:

Assume the outer ear is a cylindrical tube, open at one end and closed at the other, with a length of 3 cm. Calculate the lowest resonance frequency (the fundamental frequency) of this tube.

Answers

The lowest resonance frequency of the outer ear tube is 1220 Hz.

The lowest resonance frequency of a cylindrical tube, such as the outer ear, can be calculated using the formula:

f = (c/2π) x (1/L)

where:

f is the frequency (in hertz)

c is the speed of sound in air (approximately 343 m/s at room temperature and normal atmospheric pressure)

L is the length of the tube (in meters)

In this case, the length of the outer ear tube is given as 3 cm, or 0.03 meters. The tube is closed at one end and open at the other, so we must take into account that the closed end is a node of the standing wave, and the open end is an antinode.

This means that the lowest resonance frequency, or fundamental frequency, of the tube will be the frequency at which a half-wavelength fits into the length of the tube. Therefore, the wavelength of the sound wave that will resonate in the tube is twice the length of the tube (since it has a closed end), or 0.06 meters.

Using the formula above, we can calculate the fundamental frequency as:

f = (343/2π) x (1/0.03) ≈ 1220 Hz

Therefore, the lowest resonance frequency of the outer ear tube is approximately 1220 Hz.

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A 2.0-N force acts horizontally on a 10-N block that is initially at rest on a horizontal surface. The coefficient of static friction between the block and the surface is 0.50.56. What is the magnitude of the frictional force that acts on the block?A) 0 NB) 2 NC) 5 ND) 8 NE) 10 N

Answers

The magnitude of the frictional force acting on the block is 2 N since  the frictional force will exactly oppose the applied force. Answer is  B) 2 N

To determine the magnitude of the frictional force acting on the block, we need to use the coefficient of static friction (μs) and the normal force (N). The formula for calculating the maximum static frictional force (F_friction) is:

F_friction = μs * N

First, let's find the normal force. In this case, the normal force (N) is equal to the weight of the block, which is given as 10 N.

Now, let's use the given coefficient of static friction, which is 0.56. Plug the values into the formula:

F_friction = 0.56 * 10 N
F_friction = 5.6 N

Since the applied force (2.0 N) is less than the maximum static frictional force (5.6 N), the block will not move, and the frictional force will exactly oppose the applied force. Therefore, the magnitude of the frictional force acting on the block is: B) 2 N

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Replace the force and couple system with a single equivalent force. If placed along the y-axis, what would be the y-coordinate (in units of meters) where it is located

Answers

The equivalent force of magnitude 20 N, when placed along the y-axis, has a direction of 30 degrees with respect to the positive y-axis.

The component along the x-axis can be found using the cosine of the angle:

Fx = 20 N * cos(30 degrees)

≈ 17.32 N

The component along the y-axis can be found using the sine of the angle:

Fy = 20 N * sin(30 degrees)

≈ 10 N

Now, we have the horizontal force (17.32 N) and the vertical force (10 N). To find the single equivalent force, we need to combine these forces into a resultant vector.

Using the Pythagorean theorem, we can find the magnitude of the resultant force:

Resultant force (F) =\(\sqrt{(Fx^2 + Fy^2)\)

= \(\sqrt{((17.32 N)^2 + (10 N)^2)\)

≈ \(\sqrt{(300 N^2 + 100 N^2) \\\)

≈ \(\sqrt{(400 N^2)\)

= 20 N

So, the magnitude of the equivalent force is 20 N.

To determine the direction of the equivalent force, we can use trigonometry. The direction can be found as the angle between the equivalent force and the positive y-axis.

Using the tangent of the angle, we can calculate:

tan(angle) = Fy / Fx

= 10 N / 17.32 N

≈ 0.577

angle ≈ arctan(0.577)

≈ 30 degrees

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--The complete Question is, A rectangular object experiences two forces: a 10 N force applied horizontally in the positive x-axis direction and a 20 N force applied at a 30-degree angle from the positive x-axis. These forces are applied at the same point on the object. Replace the force and couple system with a single equivalent force. If this equivalent force is placed along the y-axis, what is its magnitude and direction?--

how do i get the correct answer for 0.429m to mm

Answers

the answer for 0.429m to mm is 429

Answer:

0.429m=429 mm

Explanation:

Since there are 1,000 millimeters per meter, you need to multiply by 1,000 to convert from meters to millimeters.

as time passes, water transfers through the water cycle again and again. what happens to the total amount of water on earth?

Answers

The total amount of water vapor in the atmosphere remains approximately the same over time.

What is the Water Cycle?

The water cycle shows the continuous movement of water within the Earth and atmosphere. It is a complex system that includes many different processes. Liquid water evaporates into water vapor, condenses to form clouds, and precipitates back to earth in the form of rain and snow. Water in different phases moves through the atmosphere (transportation). Liquid water flows across land (runoff), into the ground (infiltration and percolation), and through the ground (groundwater). Groundwater moves into plants (plant uptake) and evaporates from plants into the atmosphere (transpiration). Solid ice and snow can turn directly into gas (sublimation). The opposite can also take place when water vapor becomes solid (deposition).

In conclusion, water continually evaporates, condenses, and precipitates, and on a global basis, evaporation approximately equals precipitation. Because of this equality, the total amount of water vapor in the atmosphere remains approximately the same over time.

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Explain how the pressure of the ice cube on the ground changes when it melts

Answers

Answer:

Explanation: Andre Ampere

How can you describe the path of the projectile motion?

Answers

Projectile motion is when an object moves in a bilaterally symmetrical, parabolic path. The path that the object follows is called its trajectory. Projectile motion only occurs when there is one force applied at the beginning, after which the only influence on the trajectory is that of gravity.

Projectile motion is  a motion where an object moves in a bilaterally symmetrical path

What is a Projectile motion ?

Projectile motion is a form of motion experienced by an object or particle that is projected near Earth's surface and moves along a curved path under the action of gravity only.

If an object is thrown up by making a certain angle with respect to  ground ( let say theta) up in the sky , it will reach a maximum height after which it follows a symmetrical path as it comes down due to  the action of gravity . The path followed from the beginning till end will be a parabolic in this case .

It is a motion where an object moves in a bilaterally symmetrical path .

Projectile motion only occurs when there is only one force applied at the beginning of the trajectory, after been released object comes in the action of gravity .

General form of equation of trajectory  of Projectile motion   can be written as :

y = x tan(theta ) - g(x^2)/(2(u^2)cos^2(theta))

where y = horizontal component

           x = vertical component

           g = gravity

           u = initial velocity

           theta = angle of inclination of the initial velocity from horizontal axis

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The electric field due to an isolated electron will Select one: a. be stronger at greater distance from the electron b. form concentric circles around the electron c. extend radially away from the electron d. extend radially toward the electron

Answers

The correct answer is c. The electric field due to an isolated electron extends radially away from the electron.

This means that the electric field lines originating from the electron will radiate outward in all directions, forming a spherical pattern around the electron. The strength of the electric field decreases as the distance from the electron increases, following an inverse-square law. The behavior of electric field lines surrounding an electron can be described as a spherical pattern radiating outward in all directions. These field lines represent the direction and strength of the electric field. As the distance from the electron increases, the strength of the electric field decreases. This relationship follows an inverse-square law, which means that the electric field strength decreases proportionally to the square of the distance from the electron. In simpler terms, the electric field becomes weaker as you move farther away from the electron. This understanding of the electric field helps in visualizing its distribution and its impact on nearby charged particles or objects.

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The main reproductive cells are produced in the testes, which are contained in the what

Answers

The testes, contained in the scrotum, produce the main reproductive cells (sperm cells) through spermatogenesis. Additionally, the testes also produce testosterone, which is important for male sexual development.

The main reproductive cells, known as sperm cells, are produced in the testes. The testes are part of the male reproductive system and are contained in a sac-like structure called the scrotum. The scrotum hangs outside the body to maintain a slightly lower temperature, which is necessary for proper sperm development.
Within the testes, there are numerous tiny tubules called seminiferous tubules. These tubules are where the production of sperm cells takes place through a process called spermatogenesis. Spermatogenesis involves the division and maturation of germ cells, resulting in the formation of sperm cells.
It's important to note that the testes also produce male sex hormones, specifically testosterone. Testosterone is responsible for the development of secondary sexual characteristics in males, such as deepening of the voice, growth of facial and body hair, and muscle development.
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Question L
What is the weight of a 2.2 kg book on Mars
(gravity on Mars = 3.7 m/s²)

Answers

ans.  8.14

weight = mg

m=mass

g= gravity

putting values

2.2x3.7

= 8.14 ans.

If a body of mass 4 kg moves at a velocity of 25 m/s and has a completely inelastic collision with a body of mass 10 kg, the final velocities of both the bodies is 14 m/s. Calculate the initial velocity of the body of mass 10 kg.

Answers

We are given the following information about an inelastic collision.

Mass of 1st object = 4 kg

Mass of 2nd object = 10 kg

Initial velocity of 1st object = 25 m/s

Final velocity of both objects = 14 m/s

Initial velocity of 2nd object = ?

In an inelastic collision, the momentum is conserved but the kinetic energy is not conserved.

Recall that the total momentum is conserved and given by

\(m_1u_1+m_2u_2=(m_1+m_2)v_2\)

Let us substitute the given values and solve for initial velocity of the body (u2)

\(\begin{gathered} m_1u_1+m_2u_2=(m_1+m_2)v_2 \\ 4\cdot25+10\cdot u_2=(4+10)\cdot14 \\ 100+10\cdot u_2=196 \\ 10\cdot u_2=196-100 \\ 10\cdot u_2=96 \\ u_2=\frac{96}{10} \\ u_2=9.6\; \frac{m}{s} \end{gathered}\)

Therefore, the initial velocity of the body of mass 10 kg is 9.6 m/s

130 An object, initially at rest, is dropped from a height of 12.0m. The change in gravitational potential
energy when it falls to the ground is 565J.
The frictional forces are negligible
mgh
What is its speed when it hits the ground?
A
4.71 m/s
B
15.5m/s
C 47.1 m/s
D 240 m/s

Answers

The  speed when it hits the ground is option (B) 15.5 m/s.

To determine the speed of the object when it hits the ground, we can use the principle of conservation of energy. The initial potential energy of the object is converted into kinetic energy as it falls.

The change in gravitational potential energy is given as ΔPE = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height.

We know that ΔPE = 565 J, and the height h = 12.0 m.

Since the object is initially at rest, its initial kinetic energy is zero.

The total mechanical energy (sum of potential and kinetic energy) is conserved, so:

ΔPE = ΔKE

mgh = (1/2)mv^2

Here, m cancels out, giving:

gh = (1/2)v^2

Substituting the known values:

(9.8 m/s^2)(12.0 m) = (1/2)v^2

117.6 = (1/2)v^2

Dividing both sides by (1/2):

235.2 = v^2

Taking the square root of both sides:

v ≈ 15.33 m/s

Therefore, the speed of the object when it hits the ground is approximately 15.33 m/s.

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