The electric potential difference, in volts, between the points x2 = 1.9 m and x1 = 0.75 m. is 54.70 volts.
1. Plug in the values of a, b, and n into the electric field equation: \(E = (7(6)/(c⋅m^6) - 9(6)/c)i\)
2. Integrate the electric field equation with respect to x, between x1 and x2, to find the electric potential difference (V): \(V = -∫(E dx) from x1 to x2\)
3. Replace the limits of integration and solve the integral: \(V = -∫[(7(6)/(c⋅m^6) - 9(6)/c) dx] from 0.75 to 1.9\)
The integral can be separated as follows:
V =\(-∫(7(6)/(c⋅m^6) dx) + ∫(9(6)/c dx)\) from 0.75 to 1.9
Now, solve each integral separately:
First integral:\(-∫(7(6)/(c⋅m^6) dx)\) from 0.75 to 1.9
= \(-42/c ∫(1/m^6 dx) from 0.75 to 1.9\)
\(= -42/c [(1/5)x^(-5)] from 0.75 to 1.9\)
=\(-42/c [(1/5)(1.9^(-5) - 0.75^(-5))]\)
Second integral: ∫(9(6)/c dx) from 0.75 to 1.9
= 54/c ∫(dx) from 0.75 to 1.9
= 54/c (1.9 - 0.75)
Now, add the two integrals to find the total electric potential difference:
\(V = -42/c [(1/5)(1.9^(-5) - 0.75^(-5))] + 54/c (1.9 - 0.75)\)
Since the potential difference should be in volts, we can drop the unit "c" and consider it to be incorporated into the constant terms: \(V = -42 [(1/5)(1.9^(-5) - 0.75^(-5))] + 54 (1.9 - 0.75)\)
Calculate the values:
V ≈ -42 (0.000155 - 0.00262) + 54 (1.15)
V ≈ 54.70 V
The electric potential difference between the points x2 = 1.9 m and x1 = 0.75 m is approximately 54.70 volts.
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solve the problem. select the choice that indicates the correct answer and the correct number of significant figures for each measurement. 91/2.8
Some examples of significant figures that can help you better understand them are:
104.1097 contains seven significant digits. This is because all zeros that are on the right of a decimal point and also to the left of a non-zero digit is never significant. 0.00798 contains three significant digitsFurthermore, some extra tips are:
All non-zero numbers are always significant.All zeroes before a non-zero number are insignificant. All zeroes which are simultaneously to the right of the decimal point and at the end of the number are significant.What is a Significant Figure?This refers to the digits that carry meaning contributing to its measurement resolution and each of the digits of a number that are used to express it to the required degree of accuracy, starting from the first non-zero digit.
Hence, we can see that:
All non-zero numbers are always significant.All zeroes before a non-zero number are insignificant. All zeroes which are simultaneously to the right of the decimal point and at the end of the number are significant.Read more about significant figures here:
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A 5.39 mm high firefly sits on the axis of, and 10.9 cm in front of, the thin lens A, whose focal length is 5.87 cm. Behind lens A there is another thin lens, lens B, with a focal length of 25.1 cm. The two lenses share a common axis and are 61.1 cm apart.
The image is located 52.63 cm away from lens B.
The image formed is real.
Calculation:The equation of the constructor of geometric optics is used here. it is given as,
\(\frac{1}{q} = \frac{1}{f} - \frac{1}{p}\)
where,
q = distance of image from the lens
f = focal length of the lens
q = distance of the object from the lens
Lens A
To find the distance of the image from lens A
\(\frac{1}{qa} = \frac{1}{fa} - \frac{1}{p}\)
\(\frac{1}{qa} = \frac{1}{5.87} - \frac{1}{10.9}\)
\(\frac{1}{qa} = 0.08\)
\(qa = 12.5 cm\)
Lens B
The distance between the lenses minus the distance to the image is the distance from lens B to the object,
\(pb = d - qa\)
\(= 61.1 - 12.5\)
\(pb = 48.6 cm\)
Now use the constructor's equation to find the distance of image from lens B,
\(\frac{1}{q} = \frac{1}{fb} - \frac{1}{pb}\)
\(\frac{1}{q} = \frac{1}{25.1} - \frac{1}{48.6}\)
\(\frac{1}{q} = 0.019\)
\(q = 52.63 cm\)
Hence, the image is located 52.63 cm away from lens B.
I understand the question you are looking for is this:
A 5.39 mm high firefly sits on the axis of, and 10.9 cm in front of, the thin lens A, whose focal length is 5.87 cm. Behind lens A there is another thin lens, lens B, with a focal length of 25.1 cm. The two lenses share a common axis and are 61.1 cm apart. Is the image of the firefly that lens B forms real or virtual? How far from lens B is this image located?
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At its closest approach, a moon comes within 200,000 km of the planet it orbits. At that point, the moon is 300,000 km from the other focus of its orbit, f2. The planet is focus f1 of the moon's elliptical orbit. How far is the moon from the planet when it is 260,000 km from f2?
Answer:
s₁ = 240,000 km
Explanation:
The distance between both the focuses f₁ and f₂ will be the sum of distances of the moon from each focus at a given point. Therefore,
s = s₁ + s₂
where,
s = total distance between the focuses = ?
s₁ = distance between f1 and moon = 200,000 km
s₂ = distance between f₂ and moon = 300,000 km
Therefore,
s = 200,000 km + 300,000 km
s = 500,000 km
Now, when the distance from f₂ becomes 260,000 km, then the distance from f₁(planet) will become:
s = s₁ + s₂
500,000 km = s₁ + 260,000 km
s₁ = 500,000 km - 260,000 km
s₁ = 240,000 km
An astronaut lands on another planet and wishes to determine the acceleration due to gravity.the astronaut measure a period of 0.5m pendulum as being 3.2 seconds what is the acceleration due to gravity
Answer:
1.927 m/s^2
Explanation:
period = 2 pi sqrt ( l/g)
3.2 = 2 pi sqrt (.5/g) =1.927 m/s^2
which of the following statements about subatomic particles are true? i. protons and electrons have charges of opposite signs but the same magnitude. ii. protons have twice the mass of neutrons. iii. electrons are lighter than neutrons.
Statement iii is true, while statements i and ii are false.
i. This statement is false. While protons and electrons have opposite charges, the magnitude of their charges is not the same. Protons have a positive charge while electrons have a negative charge. The magnitude of the charge of an electron is equal to the magnitude of the charge of a proton, but with opposite sign.
ii. This statement is also false. Neutrons and protons have approximately the same mass, with protons being slightly lighter. Therefore, protons do not have twice the mass of neutrons.
iii. This statement is true. Electrons are the lightest subatomic particle and have a mass approximately 1/1836 times that of a proton or neutron. Therefore, electrons are lighter than neutrons.
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The speed of individual particle diffusion is influenced by temperature and particle size, not by concentration. True or false?.
Answer:
The speed of individual particle diffusion is influenced by temperature and particle size, not by concentration
Explanation:
How fast is a skateboarder traveling if she travels 2 miles in 4 hours?
This question is asking for the speed of the skateboarder. speed= distance/time. In this question we will do 2/4 in order to get a speed of 0.5 mph.
. An ice cube is placed in a glass of water. The cube is 1.5 cm on each side and has a density of 0.933 g/cm. What is the magnitude of the buoyant force on the ice? 2. A block of wood has a density of 0.820 g/cm and dimensions of 13.0 cm, 7.0 cm, and 2.0 cm. How large a force will just submerge the block in a vat of oil with a density 0.920 g/cm"? 3. A table-tennis ball has an average density of 0.083 g/cm and a diameter of 3.8 cm. How large a force can just submerge the ball in water? (p, = 1.000 g/cm3) N
As per the details given, the force required to submerge the block of wood in oil is approximately 2.406 N. the force required to submerge the table-tennis ball in water is approximately 0.462 N.
To calculate the amount of the buoyant force on the ice cube, first establish its volume and then apply Archimedes' principle.
Volume of the ice cube = \(s^3\) = \((1.5 cm)^3\) = 3.375 \(cm^3\)
Buoyant force = Weight of the displaced water
Buoyant force = Density of water * Volume of the ice cube * Acceleration due to gravity
Density of water (ρ_water) = 1.000 \(g/cm^3\)
Acceleration due to gravity (g) = 9.8 \(m/s^2\)
So,
Buoyant force = (ρ_water * Volume of the ice cube * g) / 1000
Buoyant force = (1.000 * 3.375 * 9.8) / 1000
Buoyant force ≈ 0.033 N
The magnitude of the buoyant force on the ice cube is approximately 0.033 N.
To determine the power necessary to immerse the block of wood in oil, we must first calculate its volume and then apply Archimedes' principle.
Volume of the block = L * W * H = 13.0 cm * 7.0 cm * 2.0 cm
Force = Weight of the displaced oil
Force = Density of oil * Volume of the block * Acceleration due to gravity
Force = (ρ_oil * Volume of the block * g) / 1000
Force = (0.920 * Volume of the block * 9.8) / 1000
Force ≈ 2.406 N
The force required to submerge the block of wood in oil is approximately 2.406 N.
To determine the force necessary to sink the table tennis ball in water, first calculate the volume of the ball and then apply Archimedes' principle.
Volume of the ball = (4/3) * π * \((d/2)^3\)
Force = Weight of the displaced water
Force = Density of water * Volume of the ball * Acceleration due to gravity
Force = (ρ_water * Volume of the ball * g) / 1000
Force = (1.000 * Volume of the ball * ) / 1000
Force ≈ 0.462 N
Thus, the force required to submerge the table-tennis ball in water is 0.462 N.
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A 1.5 kg ball has a velocity of 12 m/s just before it strikes the floor. Find the impulse on the ball if the ball bounces up with a velocity of 10 m/s.
Hi there!
Recall:
Impulse = Change in momentum
I = Δp = mΔv = m(vf - vi)
Let the direction TOWARDS the floor be POSITIVE, and AWAY be NEGATIVE.
Plug in the givan values:
Δp = 1.5(-10 - 12) = -33 Ns
**OR, the magnitude: |-33| = 33 Ns
A 15 kilogram mass is traveling with a velocity of 2.7m/s. What is the object's kinetic energy?
Answer:
KE=1/2*m*v^2
KE=1/2*15*2.7^2
KE=54.675 J
Explanation:
Does anybody know the formula needed to calculate distance given the values for mass, power, and time?
Answer:
Joules/second^2=(Newton×meter)/second^2.
Solving for mass: Kg= (second^3/ meter^2).
A car battery produces 12 from electric that each produce 2.0 V. What is the minimum number of electric cells in car battery?
Answer:
6
Explanation:
From the given question, since a total of 12 V was obtained from the battery which is made up of a number of cells with each producing 2.0 V.
Assuming that the cells have a very low internal resistance, then;
minimum number of electric cells in the car battery = \(\frac{total voltage from the cells}{individual voltage of the cells}\)
= \(\frac{12}{2}\)
= 6
Thus, the minimum number of electric cells in the car battery is 6.
This implies that the addition of 6 cells which has 2.0 V supply in the battery produces a total of 12 V. Provided that the cells have a very low internal resistance.
a 90 kg fullback running east with a speed of 5.00 m/s is tackled by a 95.0 kg opponent running north with a speed of 3 m/s. if the collision is perfectly inelastic, calculate the speed and direction of the players just after the tackle and determine the mechanical energy lost as results of the collision. account of the missing energy
A 50-g stone is tied to the end of a string and whirled in a horizontal circle of radius 2 mat 20 m/s. ignoring the force of gravity, determine the tension in the string.
a. 5 N
b. 10 N
c. 100 N
d. 500 N
The tension in the string is calculated as 10 N. Therefore, the correct answer is option b. It is given that a 50-g stone is tied to the end of a string and whirled in a horizontal circle of radius 2 m at 20 m/s.
Ignoring the force of gravity, the tension in the string is given by the following equation;
Tension, T = Centripetal force
Fc = (mv²)/r
Here, m = 50 g
= 0.05 kg
v= 20 m/s
r = 2 m
Therefore, T = [(0.05 kg)(20 m/s)²]/2 m
So, T = (0.05 kg)(400 m²/s²)/2 m
Hence, T = 10 N
Thus, the tension in the string is calculated to be 10 N.
Therefore, the correct option is b.
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after a projectile is fired into the air from the ground, it is observed to have a velocity
v
=(8.6
i
^
+4.9
j
^
)m/s, where the x axis is horizontal and the y axis is positive upward. Determine the horizontal range of the projectile. Express your answer using two significant figures. Part B Determine its maximum height above the ground. Express your answer using two significant figures. Determine the speed of motion just before the projectile strikes the ground. Express your answer using two significant figures. Part D Determine the angle of motion just before the projectile strikes the ground. Express your answer using two significant figures.
Answer:
The angle of motion just before the projectile strikes the ground is approximately 50.9°.
Given,
Initial velocity, v = (8.6î + 4.9ĵ) m/s
The x-axis is horizontal and the y-axis is positive upward.
The projectile is fired from the ground.
The horizontal range of the projectile:
Horizontal component of the velocity, vx = 8.6 m/s
Time of flight, t = ?
Range, R = ?
Using the formula for range,
R = vxt∴ R = 8.6 × t ...(1)
Using the formula for time of flight,
t = 2usinθ/g = 2vy/g ...(2)
where θ is the angle of projection and
u is the magnitude of the velocity of projection.
From equation (2),
t = 2vy/g =(2 × 4.9/g) m/s ...(3)
From equations (1) and (3),
R = 8.6 × (2 × 4.9/g) m/s
= 8.6 × 2 × 4.9/9.8
≈ 8.6 m
The horizontal range of the projectile is approximately 8.6 m.
Maximum height:
Let H be the maximum height reached by the projectile.
Using the formula for maximum height,
H = u²sin²θ/2g = (v.sinθ)²/2g
Hence, H = [4.9/9.8 × (8.6/|v|)]²/2 × 9.8
≈ 1.2 m
The maximum height reached by the projectile is approximately 1.2 m.
Speed of motion just before the projectile strikes the ground:
Let the final velocity of the projectile be v′.
Vertical component of velocity at maximum height,u'y = 0
Vertical component of velocity just before striking the ground,v'y = −u'y = 0
From the formula,
v'y = uy + gt
where g is the acceleration due to gravity and
t is the time taken to fall back to the ground.(taking upward direction as positive),
0 = 4.9 − 9.8t∴ t = 4.9/9.8 s
Horizontal component of velocity just before striking the ground,
v'x = vx = 8.6 m/s
The speed of motion just before the projectile strikes the ground is 8.6 m/s.
The angle of motion just before the projectile strikes the ground:
The direction of motion just before the projectile strikes the ground can be represented by a vector v′ whose horizontal and vertical components are v′x and v′y respectively, such that
v′ = v′xî + v′yĵ ...(4)
From equations (1) and (3), the time of flight is t = 2 × 4.9/9.8 s = 1 s.
Using the formula for motion with constant acceleration for the vertical direction,
∆y = uyt + 1/2 gt²
where ∆y is the vertical displacement.
From equation (3), the vertical displacement when the projectile strikes the ground,
∆y = 4.9 × (1 s)²
= 4.9 m
Using equation (4),
v′y = − u'y + gt
= 0 + 9.8 × 1 s
= 9.8 m/s
The angle of motion just before the projectile strikes the ground,
θ′ = tan⁻¹(v′y/v′x)
≈ tan⁻¹(9.8/8.6)
≈ 50.9°
The angle of motion just before the projectile strikes the ground is approximately 50.9°.
Hence, The horizontal range of the projectile is approximately 8.6 m.
The maximum height reached by the projectile is approximately 1.2 m.
The speed of motion just before the projectile strikes the ground is 8.6 m/s.
The angle of motion just before the projectile strikes the ground is approximately 50.9°.
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It was shown in Example 21.11 (Section 21.5 ) in the textbook that the electric field due to an infinite line of charge is perpendicular to the line and has magnitude E=λ/2πϵ
0
r. Consider an imaginary cylinder with a radius of r=0.160 m and a length of l=0.415 m that has an infinite line of positive charge running along its axis. The charge per unit length on the line is λ=6.85μC/m. - Part B What is the flux through the cylinder if its radius is increased to r=0.535 m ? Express your answer in newton times meters squared per coulomb. - Part C What is the flux through the cylinder if its length is increased to l=0.865 m ? Express your answer in newton times meters squared per coulomb.
(a) The formula for the electric field due to an infinite line of charge is given as E = λ / (2πε₀r), where λ is the charge per unit length, ε₀ is the permittivity of free space, and r is the distance from the line of charge.
(b)The Electric flux through the cylinder when its radius is increased to r = 0.535 m is approximately 3.22 N·m²/C.
(c)The flux through the cylinder when its length is increased to l = 0.865 m is approximately 6.69 N·m²/C.
b) The surface area of the cylinder is given by A = 2πrh, where r is the radius and h is the height (length) of the cylinder.
Substituting the values, A = 2π(0.535)(0.415) = 1.11 m².
The flux through the cylinder is then given by Φ = EA, where E is the electric field and A is the surface area.
Φ = (λ / (2πε₀r)) * (2πrh) = λh / ε₀.
Substituting the given values, λ = 6.85 μC/m and ε₀ = 8.85 x 10^-12 C²/(N·m²), and h = 0.415 m, we can calculate the flux:
Φ = (6.85 x 10^-6 C/m)(0.415 m) / (8.85 x 10^-12 C²/(N·m²))
≈ 3.22 N·m²/C.
(c)The flux through the cylinder when its length is increased to l = 0.865 m is approximately 6.69 N·m²/C.
Φ = (6.85 x 10^-6 C/m)(0.865 m) / (8.85 x 10^-12 C²/(N·m²))
≈ 6.69 N·m²/C.
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balance the equation
P + 02 → P205
Answer:
4P + 502 → 2P205
Explanation:
Hence the above equation is balanced.
Explanation:
\( \underline{ \underline{ \large{ \text{Given \: chemical \: equation}}}} : \)
\( \tt{P \: + O _{2} \: \: \: \: ➞ \: \: P_{2} \: O_{5}}\)Here , Multiply P2O5 by 2 and O2 by 5 to equalize oxygen :
\( \tt{P+ 5O_{2} \: \: ➞\: \: 2P_{2} \:O_{5}}\)
Now , To equalize P atoms , Multiply P by 4
\( \boxed{ \large{\tt{ 4P + 5O _{2} \: ➞ \: \: \: \: 2P_{2} \: O_{5}}}}\)
Here , On the left side we have 4P and On the right side ,we have 4P. Again , On the left side , we have 10 O and On the right side , we have 10 O. And yippie , we got the balanced chemical equation !!!
Hope I helped ! ♡
Have a wonderful day / night ! ツ
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can sound wave generate heat?
Yes, sound waves can generate heat.
What are waves?A wave is a disturbance that moves through space and matter while transferring energy from one place to another.
Types of wavesElectromagnetic and Mechanical waves
Transversal and Longitudinal waves (classification by direction of the wave)
Sound waves almost always generate a little bit of heat as they travel and almost always end up also as heat when they are absorbed by any obstacle.
Sound is the ordered movement of atoms and molecules in rapid waving patterns. Heat is the disordered, random, movement of atoms and molecules.
In conclusion, all you have to do in order to turn sound into heat is transform some of the ordered movement of the atoms and molecules into disordered movement and that brings about the heat generated from sound waves.
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Why isn't all fresh water usable?
Answer:
2.5% of the earth's fresh water is unavailable: locked up in glaciers, polar ice caps, atmosphere, and soil; highly polluted; or lies too far under the earth's surface to be extracted at an affordable cost
2
Which of the following best describes temperature?
A
Number of molecules
B
Motion of molecules
C
Size of molecules
D Type of molecules
Answer:
B
Explanation:
Answer:
b the motion of molecules
Explanation:
i just took the test and it makes the most sense
an object 1.70 cm high is held 3.00 cm from a person's cornea, and its reflected image is measured to be 0.167 cm high. what is the magnification?
Do heavier bowling balls go faster than lighter ones?
Answer:
lighter ones will go faster
Explanation:
assuming you throw both bolwing ball with 10N of force. one is 3kg and the other is 5kg.
by using the equation: F = ma
a = F/m
a = 10/5 = 2m/s^2
a = 10/3 = 3.33333 m/s^2
a student thinks that the ball bearing falls through the liquid at a constant speed
explain how you could develop this experiment to determine if the ball bearing falls through the liquid at constant speed
By measuring the terminal velocity of the ball bearing and knowing the properties of the liquid and the ball bearing, the viscosity of the liquid can be calculated using Stoke's law.
What is the experiment that shows that the ball bearing falls through the liquid at constant speed?The experiment you are referring to is commonly known as the Stoke's law experiment or the falling ball viscometer experiment.
In this experiment, a ball bearing (usually made of steel or glass) is dropped into a vertical tube filled with a liquid of known viscosity. The ball bearing falls through the liquid under the influence of gravity, but also experiences a viscous drag force due to the resistance of the liquid.
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Determine time taken for temperature to fall from 65 to 55
The time taken for temperature to fall from 45°C to 35°C is 6.21 minutes when a liquid cools from 65°C to 55°C in 5 mins.
We can utilize Newton's Law of Cooling to tackle this issue. It expresses that the pace of progress of temperature of an article is corresponding to the distinction in temperature between the item and its environmental elements.
Utilizing this regulation, we can compose:
(dT/dt) = - k(T - Ts)
where dT/dt is the pace of progress of temperature, k is the cooling steady, T is the temperature of the fluid, and Ts is the temperature of the environmental elements.
To begin with, how about we track down the cooling steady. From the given data, we know that the fluid cools from 65°C to 55°C in 5 mins. Subsequently, we can compose:
-10 = - k(65 - 35)
k = 0.5
Presently, we can utilize this worth of k to make the opportunity taken for temperature to decrease from 45°C to 35°C. We want to tackle:
(dT/dt) = - 0.5(T - 35)
with introductory condition T(0) = 45.
Isolating factors and coordinating the two sides, we get:
ln|T - 35| = - 0.5t + C
Utilizing the underlying condition T(0) = 45, we get:
ln|10| = C
C = 2.303
Subbing this worth of C, we get:
ln|T - 35| = - 0.5t + 2.303
Taking dramatic on the two sides, we get:
|T - 35| = e^(- 0.5t+2.303)
Settling for T = 35°C, we get:
t = 6.21 minutes.
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The complete question is:
A liquid cools from 65°C to 55°C in 5 mins. If the surrounding temperature is 35℃, calculate the time taken for temperature to fall from 45°C to 35°C.
a toy car is given an initial velocity of 5.0 m/s and experiences a constant acceleration of 2.0m/s^, what is the distance traveled after 6.0 seconds
The distance, s, travelled by the car is 66 m.
What is the distance travelled by the toy car?The distance travelled by the toy car is calculated using the formula below:
s = ut + at²/2Where:
s is distance u is initial velocityT is time takena is accelerationDistance, s = 5.0 * 6.0 + 2.0 * 6.0²/2
Distance, s = 66 m
In conclusion, the distance travelled is calculated from the initial velocity, the time taken, as well as the acceleration.
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What amount of force would be required to lift a 10 kg dog?
Answer:
5 Kg force I think try
Explanation:
the force is equal to the weight divided by two. It will require a 5 Kg force to lift a 10Kg weight.
what is the pressure exerted by the light on a mirror located at the same distance from the source, assuming normal incidence and total reflection?
The pressure exerted by light on a mirror located at the same distance from the source, assuming normal incidence and total reflection is very small, approximately 10^-5 pascals.
When light is incident on a surface, it exerts a radiation pressure that is equal to the power of the light divided by the speed of light. This pressure is very small for everyday objects, but it can be significant for objects with very low mass, such as mirrors. In the case of a mirror that is perpendicular to the incident light, all of the light is reflected back in the opposite direction. This means that the total force on the mirror is twice the radiation pressure, but since the pressure is so small, the force is also very small. Therefore, the pressure exerted by light on a mirror located at the same distance from the source, assuming normal incidence and total reflection is approximately 10^-5 pascals.
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Fill in the blank to answer the question!
At Position D, the Sun's most direct rays are hitting the ________ on Earth.
At Position D, the Sun's most direct rays are hitting the equator on Earth.
What is the equator?The equator is a geographic coordinate that is defined as an imaginary line that stretches approximately 40,075 km or 24,901 miles across the Earth's surface. The equator is an imaginary circle that is equidistant from the North and South Poles. This circle divides the Earth into the Northern Hemisphere and the Southern Hemisphere.
In summary, the Sun's most direct rays hit the equator on Earth when it is at Position D.
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3 What is the displacement of a satellite when it makes a complete round along its circular path?
Answer:
0
Explanation:
The displacement is zero since it goes in a full circle and ends up where it started.
(a) what is the wavelength of a 2.4 ghz sine wave in inches? (b) what is the most efficient length in inches of a monopole antenna transmitting at 2.4 ghz?
In order to determine the wavelength of a 2.4 GHz sine wave in inches and the most efficient length of a monopole antenna transmitting at 2.4 GHz in inches, the answer will provide an explanation of the calculations involved.
The wavelength (λ) of a wave is calculated using the formula λ = c/f, where c represents the speed of light and f is the frequency of the wave. To find the wavelength of a 2.4 GHz sine wave in inches, we need to convert the frequency to hertz and then use the formula.
(a) Converting 2.4 GHz to hertz, we get 2.4 × 10^9 Hz. Plugging this value into the formula, along with the speed of light (approximately 3 × 10^8 meters per second or 11.8 inches per nanosecond), we can calculate the wavelength in inches as λ = 11.8 in/ns / (2.4 × 10^9 Hz).
(b) The most efficient length for a monopole antenna is typically a quarter-wavelength. To find the length of a monopole antenna that is most efficient at transmitting at 2.4 GHz, we need to calculate a quarter-wavelength.
Using the formula λ/4, where λ represents the wavelength calculated in part (a), we can determine the quarter-wavelength in inches for the monopole antenna transmitting at 2.4 GHz.
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