The earth rotates through one complete revolution every 1,440 minutes. Since the axis of rotation is perpendicular to the equator, you can think of a person standing on the equator as standing on the edge of a disc that is rotating through one complete revolution every 1440 minutes. Find the angular velocity of a person standing on the equator.
Answers
Answer:
The angular velocity of a person standing on the equator is approximately \(7.272\times 10^{-5}\) radians per second.
Explanation:
The Earth rotates at constant speed. From Rotational Physics, the angular velocity (\(\omega\)), measured in radians per second, is defined by the following formula:
\(\omega = \frac{2\pi}{T}\) (1)
Where \(T\) is the period of rotation of the Earth, measured in seconds.
If we know that \(T = 86400\,s\), then the angular velocity of a person standing on the equator is:
\(\omega = \frac{2\pi}{86400\,s}\)
\(\omega \approx 7.272\times 10^{-5}\,\frac{rad}{s}\)
The angular velocity of a person standing on the equator is approximately \(7.272\times 10^{-5}\) radians per second.
Related Questions
if you were to draw a 3rd harmonic of a tube open at both ends, what would you draw at the ends of the tube?
Answers
A 3rd harmonic of a tube open at both ends will have displacement antinodes at both ends.
In a tube of length L with two open ends, the longest standing wave has displacement antinodes (pressure nodes) at both ends. The fundamental or first harmonic is what it is known as. The second harmonic is the longest standing wave in a tube of length L with two open ends.
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How would an object need to move in order for total distance traveled and displacement to be equal?
Answers
An object need to move in a straight line in the same direction in equal intervals of time in order for total distance traveled and displacement to be equal.
Jane (m=50kg) wants to save Tarzan (m= 80kg) who is standing in the middle of a ring of fire of 5.0 m diameter. Jane has a vine (conveniently attached to a branch right above Tarzan, at a height of 33 m above the ground. Jane holds onto the vine and climbs a tree, growing 16 m away from Tarzan, until she reaches a height of 5.3 m above the ground. She swings down and grabs Tarzan around his waist (1.0m above ground). If they let go of the vine when they reach their highest point, where will they land, relative to Tarzan's original position?
Answers
The height that will illustrate the distance will be d = 6.36m
How to calculate the height?Based on the information given, the length of the vine will be:
L = ✓(16² + 27.7)²
L = 32m
The velocity of Jane when she reaches position B will be:
V = ✓2gh
V = ✓(2 × 9.8 × 4.3)
V = 9.18m/s
We will apply the conversation of momentum. This will be:
50 × 9.18 = (50 + 80)V1
V1 = 3.53m/s
Therefore, the height that will illustrate the distance will be:
31.36² + d² = 32²
d² = 32² - 31.36²
d = 6.36m
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What is the work done from X =0m to 5.0m?
Answers
If the applied force is 20 N and the displacement is from X=0m to X=5.0m, the work done is 100 Joules.
What is the work done?
To determine the work done by a force, you need to know the displacement and the component of the force parallel to the displacement.
In this case, if the force applied is 20 N and the displacement is from X=0m to X=5.0m, you need to determine if the force is parallel to the displacement.
If the force is parallel to the displacement, then the work done is simply the product of the force and the displacement, which is:
Work = Force x Displacement
Work = 20 N x (5.0 m - 0 m)
Work = 100 Joules
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The complete question is below:
What is the work done from X =0m to 5.0m? if the applied force is 20 N
9. All of the following are adaptations of herbivores EXCEPT:
special digestive systems for digesting plant cellulose
Okeen eyesight for sporting prey
O coat colors that help them blend in with the land
fut teeth for chewing tough plant matter
PLZ HURRY PLZ IMM MARK BRAINLYEST
Answers
Answer:
B.KEEN EYESIGHT thats for predators !
Explanation:
Herbivores have multiple stomachs to process tough foods, coats to blend in so they don't get eaten, and tough teeth for chewing on the plants. THEY DO NOT HAVE PREY, THEY ARE THE PREY.
Physics question and Please show work :)
Which has greater inertia, you or a skyscraper? If you push on the side of a skyscraper with a force of 100 N, how much force does the skyscraper push back on you with?
Answers
Answer:
Skyscraper
Explanation:
A human has less inertia than a skyscraper. The ability of matter to resist changes in motion is known as inertia, and it is inversely proportional to mass. A building has more inertia than a person since it has a larger mass.
According to Newton's third law of motion, if you apply a force of 100 N to the side of a skyscraper, the structure will respond by applying an equal and opposing force of 100 N to you. This is due to the fact that the force you exert on the tower is transmitted through your body, to your feet, and then into the ground. The skyscraper experiences an equal and opposite force from the earth, which is reflected back up your body through your feet.
Give me the real answer
Answers
Answer: 12,339
Explanation:
7) The coefficient of performance (COP) of a refrigerator is defined as the ratio of A) the heat removed from the inside to the heat expelled (dismissed) to the outside. B) the heat expelled (dismissed) to the outside to the heat removed from the inside. C) the heat removed from the inside to the work done to remove the heat. D) the heat expelled (dismissed) to the outside to the work done to remove the heat
Answers
Answer:
C) the heat removed from the inside to the work done to remove the heat.
Explanation:
Refrigerator is a heat engine working in reverse direction . Heat from cold source is taken out , some work is done to remove them and total heat and work energy is thrown into outside surrounding .
If q heat is taken out and W is work done to get this heat out .
coefficient of performance ( COP ) = q / W .
Hence C ) is the right choice .
The reflection in a clear window of a store
is a(n)
Answers
The reflection in a clear window of a store is a(n) image.
Why are images seen as reflection?Images are seen as reflections because of the behavior of light. When light strikes a smooth, reflective surface such as a mirror or still water, it bounces off the surface at the same angle at which it hit it. This process is called reflection. The reflected light rays then travel to our eyes, creating an image.
The angle of incidence (the angle at which the light strikes the surface) is equal to the angle of reflection (the angle at which the light bounces off the surface). This causes the reflected image to be a mirror image of the original object.
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6. In the diagram below, A is a vector of magnitude 35 cm; B is a vector of magnitude 13 cm. If tan a = 4/3 and tan ß = 5/12, a. write A and B in terms of î and ĵ b. Show that A + B makes an angle of 45° to the x-axis.
Answers
Answer:
A = 21 î + 28 ĵ
B = 12 î + 5 ĵ
Explanation:
a.
To write A and B in terms of î and ĵ, we need to use the trigonometric ratios and the vector notation
According to the diagram, we have:
tan a = 4/3 tan ß = 5/12
Using the identity tan θ = opposite/adjacent, we can find the x and y components of A and B.
For A, we have:
x component = 35 cos a y component = 35 sin a
Using tan a = 4/3, we can find cos a and sin a by using Pythagoras’ theorem:
cos a = 3/5 sin a = 4/5
Therefore, the x and y components of A are:
x component = 35 cos a = 35 (3/5) = 21 y component = 35 sin a = 35 (4/5) = 28
Using the vector notation, we can write A as:
A = 21 î + 28 ĵ
Similarly, for B, we have:
x component = 13 cos ß y component = 13 sin ß
Using tan ß = 5/12, we can find cos ß and sin ß by using Pythagoras’ theorem:
cos ß = 12/13 sin ß = 5/13
Therefore, the x and y components of B are:
x component = 13 cos ß = 13 (12/13) = 12 y component = 13 sin ß = 13 (5/13) = 5
Using the vector notation, we can write B as:
B = 12 î + 5 ĵ
b.
To show that A + B makes an angle of 45° to the x-axis, we need to find the resultant vector R and its angle θ with the x-axis.
To find R, we can use the vector addition rule :
R = A + B R = (21 î + 28 ĵ) + (12 î + 5 ĵ) R = (21 + 12) î + (28 + 5) ĵ R = 33 î + 33 ĵ
To find θ, we can use the inverse tangent function :
tan θ = y component / x component tan θ = 33 / 33 tan θ = 1
θ = tan^-1(1) θ = 45°
Therefore, A + B makes an angle of 45° to the x-axis.
A car starts from rest and accelerates at 9.54m/s2 for 6.5sec. What is the distance covered by the car?
Answers
Answer:
Explanation:
If a body starts from rest, with an acceleration of a for time t, then the distance D covered by is given by
\(D=\frac{1}{2}at^2\)Now, in our case we have a = 9.54 m/s^2 and t = 6.5 s; therefore,
\(D=\frac{1}{2}\cdot(9.54m/s^2)\cdot(6.5s)^2\)which upon simplification gives
\(\boxed{D=201.5325m}\)Hence, the distance covered by the car is about 202 meters.
How are isobars and isotherms similar? How are they different?
Answers
Answer: Brainliest?
Explanation:
Isobars and isotherms are both types of contour lines used to represent data on weather maps, specifically for atmospheric pressure and temperature, respectively.
The similarities between isobars and isotherms are:
Both are contour lines that connect points of equal value on a map.
Both are used to depict weather patterns and conditions.
Both help to identify areas of high and low values.
The differences between isobars and isotherms are:
Isobars connect points of equal atmospheric pressure, whereas isotherms connect points of equal temperature.
Isobars are measured in units of pressure such as millibars, while isotherms are measured in units of temperature such as degrees Celsius or Fahrenheit.
Isobars are typically used to show pressure patterns associated with wind, while isotherms are used to show temperature patterns.
Isobars are often used to forecast weather conditions, including the movement and intensity of storm systems. Isotherms are used to identify areas of warm and cold air masses, which can affect local weather patterns.
In summary, both isobars and isotherms are useful tools for understanding weather patterns, but they represent different types of data and are used for different purposes.
Isobars and isotherms are both concepts used in meteorology and climatology to represent important variables that help to describe atmospheric conditions. While they share some similarities, they also have several key differences.
Isobars refer to lines of equal pressure, meaning they connect points on a map or graph where the atmospheric pressure is the same. Isobars are drawn on weather maps to indicate areas of high and low pressure, and to show the general movement of air masses. When isobars are closely spaced, it indicates a steep pressure gradient, which can result in strong winds.
On the other hand, isotherms refer to lines of equal temperature, meaning they connect points on a map or graph where the temperature is the same. Isotherms are often drawn on weather maps to show the boundaries between warmer and cooler air masses, and to indicate areas where temperature changes rapidly.
One similarity between isobars and isotherms is that they are both used to describe atmospheric conditions in terms of spatial variation. They are also both used to infer information about the movement of air masses and the development of weather patterns.
However, there are also some key differences between isobars and isotherms. The most obvious difference is that isobars represent pressure while isotherms represent temperature. Additionally, while isobars are generally oriented parallel to each other and indicate the direction of winds, isotherms are typically oriented perpendicular to isobars and indicate the location of temperature gradients. Finally, while isobars are more commonly used to describe weather conditions associated with areas of high and low pressure, isotherms are often used to identify the location of fronts and other weather boundaries.
In summary, isobars and isotherms are similar in that they both describe atmospheric conditions in terms of spatial variation, and can be used to infer information about the movement of air masses and the development of weather patterns. However, isobars represent pressure and are oriented parallel to each other, while isotherms represent temperature and are oriented perpendicular to isobars.
The surface of the exit road is horizontal, not banked. (See figure.) If the static
friction between the tires and the surface of the road is us = 0.688 and the
maximum speed with which the car can exit the highway safely without sliding is
25.2 m/s, what is the radius of curvature of a highway exit, r?
Answers
The radius of curvature of the highway exit is approximately 220 km.
To find the radius of curvature of the highway exit, we can use the centripetal force equation:
F = mv^2 / r
where F is the maximum static friction force, m is the mass of the car, v is the maximum safe speed, and r is the radius of curvature.
We can solve for r by rearranging the equation:
r = mv^2 / F
Substituting the given values, we have:
r = (1000 kg)(25.2 m/s)^2 / (0.688)
r = 2.20 x 10^5 m
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How did earth change about 2.5 billion years ago when many organisms began using photosynthesis to make food
A. The amount of oxygen in the atmosphere increased
B. Mass extinctions occurred
C. The oceans became larger
D. Rainfall increased
Answers
The path of a projectile fired at an angle above the horizontal is best described as
Answers
Which water on earth is the largest,second to the largest,3rd to the largest,fourth to the largest and 5th to the largest?
Answers
Answer:
Explanation:
There are a total of 5 differen classification for the types of bodies of water that exist on Earth. These 5 would be the following: Oceans, seas, lakes, rivers, and canals. Oceans are the biggest bodies of water on Earth. If we ranked them by their size the ranking would be the following...
Pacific Ocean - being 155,556,651 sq km. in size
Atlantic Ocean - being 76,761,938 sq km. in size
Indian Ocean - being 68,555,923 sq km. in size
Antarctic / Southern Ocean - being 20,327,001 sq km. in size
Arctic Ocean - being 14,055,930 sq km. in size
There are 3 resistors in series: R1=32 Ohm, R2-51 Ohm, and R3-10 Ohm.
Determine the equivalent resistance.
Answers
Answer: 93 Ohm
Explanation: The equivalent resistance of three resistors in series can be found by adding up the individual resistances.
R_total = R1 + R2 + R3
R_total = 32 Ohm + 51 Ohm + 10 Ohm
R_total = 93 Ohm
Therefore, the equivalent resistance of the three resistors in series is 93 Ohm.
A book on a 2-meter high shelf has a mass of 0.4 kg. What is its potential energy?
Answers
Answer:
how can we get the best out with a little of my life and I think the most common reason I would n I have been having this problem for years is done in my life as the other people
Which heart rate zones are generally anaerobic in nature?
Answers
Answer:
Below
Explanation:
Not sure what numbers you have been taught to use, but heart rates (BPM) above 80% of your maximum heart rate is anaerobic
your approximate Max heart rate = ( 220 - age in years)
so if you are 20 y/o max = 220 - 20 = 200 bpm
80% of this is 160 beats per min <===above this is anaerobic
Question Completion Status:
A Moving to the next question prevents changes to this answer.
Question 5
A ball gets pushed off a 1.2m high table with a horizontal speed of 9m/s. How far does the ball travel horizontally before hitting the ground?
Answers
Answer:
The ball will travel 4.45 m horizontally before hitting the ground
Explanation:
Horizontal Motion
When an object is launched horizontally with a speed v from a height h, the maximum horizontal distance traveled by the object, also called range can be calculated as follows:
\(\displaystyle d=v\cdot\sqrt{\frac {2h}{g}}\)
The question provides us with the following data:
Initial speed of the ball: vo=9 m/s
Height: h=1.2
Proceed to calculate the range:
\(\displaystyle d=9\ m/s\cdot\sqrt{\frac {2\cdot 1.2\ m}{9.8\ m/s^2}}\)
Calculating:
\(\displaystyle d=9\ m/s\cdot\sqrt{0.2449\ s^2}\)
\(d=9\ m/s\cdot 0.4949\ s\)
d=4.45 m
The ball will travel 4.45 m horizontally before hitting the ground
calculate power disspated by the element of an electric fire (heater) of resistance 30 ohms when a
current of 10 amps flows in it. if is on for 30 hours in a week determine the energy used. determine the weekly cost of energy if eletricity costs K 13 per unit
Answers
Answer:
Weekly cost = K 8,190
Explanation:
Given the following data;
Resistance, R = 30 Ohms
Current, I = 10 Amps
Time, t = 30 hours
Cost = K13
I. To find the power dissipated;
Power = current² * resistance
Power = 10² * 30
Power = 100 * 30
Power = 3000 Watts
II. To find the energy consumption;
Energy = power * time
Energy = 3000 * 30
Energy = 90,000 Watt-hour = 90 KWh (1 Kilowatts is equal to 1000 watts).
III. To find the weekly cost;
Daily cost = Energy consumption * cost
Daily cost = 90 * 13
Daily cost = K 1170
Therefore, weekly cost = 1170 * 7
Weekly cost = K 8,190
jjhfor the following circuit, find the voltage vc across the capacitor, in phasor notation. (find both magnitude and phase). (1 point)
Answers
The voltage across the capacitor in phasor notation is VC = 53.05 ∠ 90° V.
The voltage across the capacitor in phasor notation can be found by using the equation VC = XC * IC, where VC is the voltage across the capacitor, XC is the capacitive reactance, and IC is the current through the capacitor.
To find the capacitive reactance, we use the equation XC = 1/(2πfC), where f is the frequency and C is the capacitance. In this case, we can plug in the given values to find XC:
XC = 1/(2πfC) = 1/(2π(60 Hz)(0.1 F)) = 26.525 Ω
Next, we can find the current through the capacitor by using Ohm's Law, IC = VC/XC. Since we are looking for VC, we can rearrange the equation to get VC = IC * XC:
VC = IC * XC = (2 A)(26.525 Ω) = 53.05 V
Now, we can convert this value to phasor notation by finding the magnitude and phase. The magnitude of the voltage is simply the absolute value of the voltage, or |VC| = 53.05 V.
The phase of the voltage is determined by the relationship between the voltage and current. In a capacitor, the voltage leads the current by 90 degrees, so the phase of the voltage is 90 degrees.
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An air bubble has a volume of 1.3 cm3 when it is released by a submarine 160 m below the surface of a freshwater lake. What is the volume of the bubble when it reaches the surface? Assume that the temperature and the number of air molecules in the bubble remain constant during the ascent.
Answers
Answer:
V2 = 21.44cm^3
Explanation:
Given that: the initial volume of the bubble = 1.3 cm^3
Depth = h = 160m
Where P2 is the atmospheric pressure = Patm
P1 is the pressure at depth 'h'
Density of water = ρ = 10^3kg/m^3
Patm = 1.013×10^5 Pa.
Patm = 101300Pa
g = 9.81m/s^2
P1 = P2+ρgh
P1 = Patm +ρgh
P1 = 1.013×10^5+10^3×9.81×160.
P1 = 101300+1569600
P1 = 1670900 Pa
For an ideal gas law
PV =nRT
P1V1/P2V2 = 1
V2 = ( P1/P2)V1
V2 = (P1/Patm)V1
V2 = ( 1670900 /101300 Pa) × 1.3
V2 = 1670900/101300
V2 = 16.494×1.3
V2 = 21.44cm^3
The volume of the bubble can be determined using ideal gas law. The volume of the bubble when it reaches surface is 21.44 \(\bold {cm^3}\).
The formula of the pressure of the static fluid
P1 = P2+ρgh
Where,
P1 - pressure at depth 'h'
P2 - atmospheric pressure = \(\bold {1.013x10^5 }\) = 1670900 Pa
h - Depth = 160m
ρ - Density of water = \(\bold {10^3\ kg/m^3}\)
g- gravitational acceleration = \(\bold {9.81\ m/s^2}\)
The initial volume of the bubble = \(\bold {1.3\ cm^3}\)
\(\bold {P1 = 1.013x10^5+10^3\times 9.81\times 160}\\\\\bold {P1 = 101300+1569600}\\\\\bold {P1 = 1670900\ Pa}\)
For an ideal gas,
PV =nRT
\(\bold {\dfrac {P_1V_1}{P_2V_2 }= 1}\)
\(\bold {V2 = \dfrac { P_1}{P_2V_1}}\)
So,
\(\bold {V2 = \dfrac {1670900 }{101300 }\times 1.3}\\\\\bold {V2 =21.44\ cm^3}\)
Therefore, the volume of the bubble when it reaches surface is 21.44 \(\bold {cm^3}\).
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The higher the wattage of a light bulb, the more work the light bulb does. Group of answer choices
True
False
Answers
Answer:
True.
Explanation:
The higher the wattage the brighter the light. The efficiency of the system was introduced using and coletician lamps
write down the value of
920 kg in g
Answers
Answer:
920000
Explanation:
Each kg contains 1,000 grams
What surface features does Mars have that are also common on Earth?
volcanoes, sand dunes, and large canyons
volcanoes, running rivers, and tectonic activity
volcanoes, rings, and carbon dioxide-rich atmosphere
volcanoes, sand dunes, and thick clouds
Answers
Answer:
The first one!
Explanation:
:D
De que esta hecho el sol? plisss ayuda.no necesito un texto de 100 reglones, puede ser resumido en solo 2 renglones
Answers
The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?
Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.
Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!
Answers
The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.
The p-waves travel with a constant velocity of 7 km/s
The time can be calculated by using the formula
t = d / v
where
T1 = 10:05 a.m
d is the distance they take to travel from the epicenter
v is the speed of the p-waves
On average, the speed of p-waves is
v = 7 km/s
d = 5600 km (given)
Substituting the values in the formula;
t = d / v
t = 5600 ÷ 7
t = 800 seconds
Converting into minutes,
t = 800 ÷ 60
t = 13.3
≈ 13 mins
T1 - 13 mins = T2
10:05 - 13 mins = 9.52 am
It means the earthquake occurred prior 13 minutes, that is at 9.52 am.
Therefore, the earthquake occurred at 9.52 am.
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Need help asap!!science foundations
Answers
This may be wrong, but I am 75% sure on my answer. I sincerely apologize if if it wrong.
A seems like the most reasonable option. I believe it’s A because the age, density, and thickness of oceanic crust increases with distance.
What is sound waves
Answers
Sound waves are a type of mechanical wave that propagate through a medium, typically air but also other materials such as water or solids.
Characteristics of sound wavesFrequency: the frequency of a sound wave refers to the number of cycles or vibrations it completes per second and is measured in Hertz (Hz).
Amplitude: the amplitude of a sound wave refers to the maximum displacement or intensity of the wave from its equilibrium position. It represents the loudness or volume of the sound, with larger amplitudes corresponding to louder sounds and smaller amplitudes corresponding to softer sounds.
Wavelength: the wavelength of a sound wave is the distance between two consecutive points in the wave that are in phase, such as from one peak to the next or one trough to the next. It is inversely related to the frequency of the wave.
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