the earth has a mass approximately 80 times that of the moon. the distance between their centers is on average about 384000 km. how far from the center of the earth is the center of mass of the earth-moon system?

F = m × a

300N = 100kg × a

a = 300 : 100

a = 3ms-²

F = Force (N)

m = mass (kg)

a = acceleration (ms-², m/s²)

Answer:

Kinetic energy decreases as you go up hill

Potential energy increases as you go up hill

We have the next information

Answer:

I think it will brake or squashed

Answer:

F = 180 N

Explanation:

To find the required force you first calculate the angle of the ramp, by using the following relation:

\(sin\theta=\frac{2m}{5m}=0.4\\\\\theta=sin^{-1}(0.4)=23.57\°\)

Next, you use the Newton second law to know what is the x component (in a rotated coordinate system) of the gravitational force:

\(F_x=mgsin\theta\)

the required force must be, at least, the last force Fx. You know that the weight of the object is 490N = mg. Hence, you have:

\(F=F_x=(450N)sin(23.57\°)=180N\)

the required force is 180N

- - - - - - - - - - - - - - - - - - - - - - - -

TRANSLATION:

Para encontrar la fuerza requerida, primero calcule el ángulo de la rampa, utilizando la siguiente relación:

Luego, usa la segunda ley de Newton para saber cuál es el componente x (en un sistema de coordenadas girado) de la fuerza gravitacional:

la fuerza requerida debe ser, al menos, la última fuerza Fx. Sabes que el peso del objeto es 490N = mg. Por lo tanto, tienes:

"Activation energy" and "Chemical potential energy" are the types of energy are involved in a chemical reaction.

In a chemical reaction, various forms of energy are involved. The two types of energy mentioned in the question are:

These two types of energy, activation energy and chemical potential energy, play essential roles in chemical reactions. The activation energy determines the feasibility of a reaction, while the chemical potential energy is related to the energy stored within the reactants and products.

In summary, the correct answers are:

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The system described by the transfer function G(s) = -co² s² + 2a + w², with a damping ratio of 1.3 and a natural frequency of 0.5, has an overdamped unit step response. So, the correct option is (E)

The transfer function of the system is given as G(s) = -co² s² + 2a + w², where co represents the damping ratio, a represents an arbitrary constant, and w represents the natural frequency of the system. We are given that the natural frequency is 0.5 and the damping ratio is 1.3.

To determine the type of unit step response, we need to analyze the damping ratio (co) in relation to the critical damping value (co_critical).

The critical damping ratio (co_critical) is defined as the value where the system is on the threshold between being overdamped and underdamped. It is given by the formula co_critical = 2 * sqrt(a * w²).

In our case, the natural frequency (w) is 0.5, so we can calculate co_critical as follows: co_critical = 2 * sqrt(a * 0.5²).

Since the damping ratio (co) is given as 1.3, we can compare it with co_critical to determine the type of unit step response.

If co > co_critical, the system is considered overdamped (Option E).

If co = co_critical, the system is considered critically damped (Option D).

If co < co_critical, the system is considered underdamped (Option C).

Based on the given values, we can determine that the system is overdamped (Option E) because the damping ratio (1.3) is greater than the critical damping ratio.

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Answer: i think 1.666...

Produced the model is the resistance of the circuits decreased as a battery voltage increased (option-B).

Ohm's Law describes how current, voltage, and resistance are related to one another. According to this, as long as the temperature doesn't change, the current flowing through a circuit is directly proportional to the applied voltage and inversely proportional to the resistance of the circuit.

The more work a certain quantity of electrons can accomplish at a given voltage. The quantity of electrons that are presently moving through any one point in a circuit at any particular time is known as the current. At the same voltage, a larger current can perform more work. Current times voltage equals power.

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Answer:

b

Explanation:

The Force acting on the ball during collision is 25.9 N.

To calculate the magnitude of the average force, we use the formula below.

F = m(v-u)/t..........Equation 1

Where:

F = Average force acting on the ball

m = mass of the ball

v = Final velocity

u = Initial velocity

t = time.

From the question,

Given:

Substitute these given values into equation 1

F =  0.663 (12.2  -10.4 )/0.046

F = 25.9 N

Hence, The Force acting on the ball during collision is 25.9 N

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Answer:

divide work by time

Explanation:

Power=work/time.

Answer:

divid work by time

Explanation:

The time taken for the rock to reach its highest point is 1.2 seconds.

The time of motion of an object is the time taken for the object to travel from its initial position to the final position.

The time taken for the rock to reach its maximum or highest point is calculated as follows;

v = u - gt

where;

At the maximum height, the final velocity of the object is zero.

0 = u - gt

]gt = u

t = u/g

t = (11.5 m/s) / (9.8 m/s²)

t = 1.2 seconds

Thus, we can conclude that time from the initial position of the rock to the highest position of the rock is 1.2 seconds.

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Answer:

0.07

Explanation:

Huge Brain

Coefficient of friction between the car and the ground will be 0.07.    

    Given in the question,

Force applied on the car by which the car is accelerated,

F = ma

  = 3000 × 3

  = 9000 N

Force \(F_k\) to overcome the friction = 11000 - 9000

                                                         = 2000 N

Gravitational force F' on the car = mg

                                                       = 3000(9.8)

                                                       = 29400 N

Since, \(\mu_k=\frac{F_k}{F'}\)

                \(=\frac{2000}{29400}\)

                \(=0.068\)

                ≈ 0.07

   Therefore, coefficient of friction between the car and the ground will be 0.07.    

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The heliocentric model of the universe states that the sun is the center of the solar system and the planets revolve around it in elliptical orbits. This model replaced the geocentric model of the universe, which stated that the Earth is the center of the universe and all celestial bodies revolve around it.

The heliocentric model of the universe was first proposed by the ancient Greek astronomer Aristarchus of Samos in the 3rd century BCE. However, the model did not gain widespread acceptance until the work of Nicolaus Copernicus in the 16th century CE. Copernicus was the first person to provide a detailed mathematical model of the heliocentric system, which was later refined by Johannes Kepler.The model was supported by Kepler's observation that planets follow an elliptical orbit. This was a major deviation from the previous model, which assumed that all celestial bodies moved in circular orbits. The heliocentric model was further supported by Galileo Galilei's observations of the moons of Jupiter, which provided evidence that not all celestial bodies revolve around the Earth. The heliocentric model revolutionized astronomy and provided a more accurate understanding of the solar system.

The heliocentric model of the universe states that the sun is the center of the solar system and the planets revolve around it in elliptical orbits. This model replaced the geocentric model of the universe, which stated that the Earth is the center of the universe and all celestial bodies revolve around it. The model was supported by Johannes Kepler's observation that planets follow an elliptical orbit and provided a more accurate understanding of the solar system.

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The total travelled distance is • Speed, time and distance is one of the most common and important topics in the Mathematics or Quant section.

Velocity is the pace and direction of an object's movement, whereas speed is the time rate at which an object is travelling along a path. In other words, velocity is a vector, whereas speed is a scalar value.

For instance, 50 km/hr west denotes the velocity of a car whereas 50 km/hr (31 mph) denotes the speed at which it is moving down a route.

The average speed of an object is determined by dividing the distance traveled by the amount of time it takes the object to reach the distance.

Therefore, The total travelled distance is • Speed, time and distance is one of the most common and important topics in the Mathematics or Quant section.

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Answer:

false its an attraction property

Answer:

True

The attraction is a chemical property.

The west coast of the united states receives two high tides and two low tides of varying heights per day.  Tidal pattern is  mixed semidiurnal tidal cycle

Sun and moon exert force on the ocean due to tides moves through the ocean  Tide are very long period waves whose motion is directed by the effect of moon and sun .  Tides originate in the ocean and progress toward the coastlines where they appear as the regular rise and fall of the sea surface.

An area has a diurnal tidal cycle if it experiences one high and one low tide every lunar day. An area has a semidiurnal tidal cycle if it experiences two high and two low tides of approximately equal size every lunar day An area has a mixed semidiurnal tidal cycle if it experiences two high and two low tides of different size every lunar day.

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Answer:

Explanation:

The weight of the crate will e equal to its normal reaction R

Since R = mgsin theta = W

W = mgsintheta ( resolved along the vertical perpendicular to the plank

Fy = 523sin22°

Fy = 195.92N

Since the weight is acting along the negative y direction,

Fy = -195.92N

The force parallel to the plank will be the force acting in the horizontal direction.

Fx = Fcos theta

Fx = 523cos 22°

Fx = 484.9N

Answer: C. when the forces acting on the object are balanced.

Answer:

c

Explanation:

Molecules can be made up of two atoms of the same element for example oxygen gas is made up only of oxygen atoms.

Two or more atoms of the same or different element that are joined together to form a molecule are referred to as molecules. A molecule can be heteronuclear, which is a chemical compound made up of more than one element, like water, or homonuclear, which means it is made up of atoms of one chemical element, like oxygen (O2) (H2O).

When two or more atoms from the same element chemically combine, a molecule is created. A compound is created if the types of atoms differ from one another. Not all molecules are compounds because some molecules, like ozone (O3) and oxygen gas (pictured above), only contain one type of atom or element.

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Explanation:

The acceleration of an object depends directly up on the net force acting on the object and inversely upon the mass of the object. As the force acting upon an object is increased; According to Newton, an object will only accelerate if there is a net or unbalanced force acting on it, therefore the acceleration is equal to force divided by the mass

a=F/m

The photon's wavelength emitted during the transition from n = 2 to n = 3 is approximately 256 nm. The photon's wavelength emitted during the transition from n = 1 to n = 3 is about 160 nm. The width of the box is approximately 0.622 nm.

The energy levels of a particle in a one-dimensional box:

Eₙ = (n² ×h²) / (8 × m × L²)

where:

Eₙ: energy level of the particle

n: quantum number of the energy level

h: Planck's constant

m: mass of the particle

L: width of the box.

Transition from n = 2 to n = 3:

Let's assume the wavelength of the photon emitted during this transition is λ.

ΔE = E₃ - E₂

ΔE = ((3² × h²) / (8 ×m × L²)) - ((2² × h²) / (8 × m × L²))

ΔE = (h² / (8× m × L²)) ×(9 - 4)

ΔE = (h²/ (8 × m × L²)) × 5

The energy difference is proportional to the frequency of the emitted photon:

ΔE = h × c / λ

where c is the speed of light.

We can equate the two expressions for ΔE:

(h² / (8 × m × L²)) × 5 = h × c / λ

λ = (8 × m × L² ×c) / (5 × h)

Plugging in the given values:

m = mass of the electron = 9.11 x 10⁻³¹ kg

L = width of the box (to be determined)

c = speed of light = 3 x 10⁸ m/s

λ = (8 ×(9.11 x 10⁻³¹ kg) × L² × (3 x 10⁸ m/s)) / (5 ×(6.626 x 10⁻³⁴ J·s))

Solving for L

L² = (5 × (6.626 x 10⁻³⁴J·s) × λ) / (8 ×(9.11 x 10⁻³¹kg) × (3 x 10⁸ m/s))

L² = 0.00047765 m²

L ≈ 0.021847 m

The wavelength of the photon is given by:

λ = (8 × (9.11 x 10⁻³¹ kg) × (0.021847 m)² × (3 x 10⁸ m/s)) / (5 × (6.626 x 10⁻³⁴J·s))

λ ≈ 256 nm

Transition from n = 1 to n = 3:

Following the same steps,

ΔE = E₃ - E₁

ΔE = ((3² × h²) / (8 ×m ×L²)) - ((1² × h²) / (8 × m × L²))

ΔE = (h² / (m × L²))

Using ΔE = h × c / λ:

(h² / (m × L²)) = h ×c / λ

Simplifying and solving for λ:

λ = (m × L² × c) / h

Plugging in the given values:

λ = ((9.11 x 10⁻³¹ kg) × (0.021847 m)² × (3 x 10⁸ m/s)) / (6.626 x 10⁻³⁴ J·s)

λ ≈ 160 nm

Width of the box (L):

From the above equations,

L² = (5 × (6.626 x 10⁻³⁴J·s) × (426 nm)) / (8 × (9.11 x 10⁻³¹ kg) × (3 x 10⁸ m/s))

L ≈ 0.000622 m or 160 nm

Therefore, the answers are 256 nm, 160 nm, and 0.622 nm respectively.

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The wavelength of the photon released during the change from n = 2 to n = 3 is roughly 256 nm. About 160 nm is the wavelength of the photon that is released when n = 1 changes to n = 3. The box has a width of about 0.622 nm.

Given values:

m = mass of the electron = 9.11 x 10⁻³¹ kg

L = width of the box (to be determined)

c = speed of light = 3 x 10⁸ m/s

The energy levels of a particle in a one-dimensional box:

Eₙ = (n² ×h²) / (8 × m × L²)

where:

Eₙ: energy level of the particle

n: quantum number of the energy level

h: Planck's constant

m: mass of the particle

L: width of the box.

Transition from n = 2 to n = 3:

The wavelength of the photon emitted during this transition is λ.

ΔE = E₃ - E₂

ΔE = ((3² × h²) / (8 ×m × L²)) - ((2² × h²) / (8 × m × L²))

ΔE = (h²/ (8 × m × L²)) × 5

The frequency of the photon that was released directly correlates with the energy difference:

ΔE = h × c / λ

,c is the speed of light.

Evaluating the two expressions for ΔE:

(h² / (8 × m × L²)) × 5 = h × c / λ

λ = (8 × m × L² ×c) / (5 × h)

λ = (8 ×(9.11 x 10⁻³¹ kg) × L² × (3 x 10⁸ m/s)) / (5 ×(6.626 x 10⁻³⁴ J·s))

Solving for L

L² = (5 × (6.626 x 10⁻³⁴J·s) × λ) / (8 ×(9.11 x 10⁻³¹kg) × (3 x 10⁸ m/s))

L ≈ 0.021847 m

The wavelength of the photon is given by:

λ = (8 × (9.11 x 10⁻³¹ kg) × (0.021847 m)² × (3 x 10⁸ m/s)) / (5 × (6.626 x 10⁻³⁴J·s))

λ ≈ 256 nm

Transition from n = 1 to n = 3:

ΔE = E₃ - E₁

ΔE = ((3² × h²) / (8 ×m ×L²)) - ((1² × h²) / (8 × m × L²))

ΔE = (h² / (m × L²))

Using ΔE = h × c / λ:

(h² / (m × L²)) = h ×c / λ

Solving for λ:

λ = (m × L² × c) / h

λ = ((9.11 x 10⁻³¹ kg) × (0.021847 m)² × (3 x 10⁸ m/s)) / (6.626 x 10⁻³⁴ J·s)

λ ≈ 160 nm

Width of the box (L):

From the above equations,

L² = (5 × (6.626 x 10⁻³⁴J·s) × (426 nm)) / (8 × (9.11 x 10⁻³¹ kg) × (3 x 10⁸ m/s))

L ≈ 0.000622 m or 160 nm

Thus, the answers are 256 nm, 160 nm, and 0.622 nm respectively.

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Answer:

Time taken for the car to travel a distance of 4.50 m = 1.40 seconds

Explanation:

velocity of toy car = 3.21 m/s

distance travelled by toy car = 4.50 m

Time = ?

\(Velocity = \frac{Distance}{Time} \\Time =\frac{Distance}{Velocity}\)

\(Time = \frac{4.50}{3.21} \\Time = 1.40s\)

Therefore, the time taken for the car to travel a distance of 4.50 m = 1.40 seconds

The coefficient of static friction between the book and the tabletop is 0.13.

The coefficient of static friction between the book and the tabletop can be calculated using the formula:

μs = Fs / N

Where μs is the coefficient of static friction, Fs is the force of static friction, and N is the normal force.

In this case, the force of static friction is the force required to start the book sliding, which is 2.16 N. The normal force is the weight of the book, which is 1.70 kg × 9.8 m/s2 = 16.66 N.

Plugging in the values into the formula, we get:

μs = 2.16 N / 16.66 N
μs = 0.13

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Answer:

E......1,800 meters

Explanation:

distance = speed × time

convert 1 min to seconds because speed is give in meters per seconds so it's which is 60 seconds

Then...60 ×30 = 1,800

The values for the combustion heat and specific heat capacity given in the question are incomplete or possibly mistyped, making it difficult to provide an exact numerical answer. However, with the correct and complete values, you can use the above approach to calculate the mass of water that can be boiled.

To calculate the amount of water that can be boiled while lowering 8.4 kg of coal to release heat, we need to consider the heat released by the combustion of coal and the heat required to raise the temperature of the water.

First, let's calculate the heat released by the combustion of coal using the given combustion heat value of 27-10 J/kg:

Heat released = mass of coal * combustion heat

Heat released = 8.4 kg * 27-10 J/kg

Next, let's calculate the heat required to raise the temperature of the water from 0°C to its boiling point, which is 100°C:

Heat required = mass of water * specific heat capacity * temperature change

Heat required = mass of water * 4200 J/(kg·°C) * (100°C - 0°C)

To find the amount of water that can be boiled, we need to equate the heat released by the coal to the heat required to raise the temperature of the water:

Heat released = Heat required

8.4 kg * 27-10 J/kg = mass of water * 4200 J/(kg·°C) * 100°C

Now we can solve for the mass of water:

mass of water = (8.4 kg * 27-10 J/kg) / (4200 J/(kg·°C) * 100°C)

To calculate the amount of water that can be boiled while lowering 8.4 kg of coal to release heat, we need to consider the heat released by the combustion of coal and the heat required to raise the temperature of the water.

First, let's calculate the heat released by the combustion of coal using the given combustion heat value of 27-10 J/kg:

Heat released = mass of coal * combustion heat

Heat released = 8.4 kg * 27-10 J/kg

Next, let's calculate the heat required to raise the temperature of the water from 0°C to its boiling point, which is 100°C:

Heat required = mass of water * specific heat capacity * temperature change

Heat required = mass of water * 4200 J/(kg·°C) * (100°C - 0°C)

To find the amount of water that can be boiled, we need to equate the heat released by the coal to the heat required to raise the temperature of the water:

Heat released = Heat required

8.4 kg * 27-10 J/kg = mass of water * 4200 J/(kg·°C) * 100°C

Now we can solve for the mass of water:

mass of water = (8.4 kg * 27-10 J/kg) / (4200 J/(kg·°C) * 100°C)

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Answer: 1. 12,600 km/s

2. 11,700 km/s

3. 13,500 km/s

4. 42.15Mpc

5. 46.15 Mpc

6.  40 Mpc

1. To find the recessional velocity of a galaxy at a distance of 180 Mpc, we use the formula:

v = H0 × d,

where v is the recessional velocity of the galaxy, H0 is the Hubble constant, and d is the distance of the galaxy.

v = 70 × 180 = 12,600 km/s

2. If H0 = 65 km/s/Mpc, then we use the same formula to find the recessional velocity of the galaxy:

v = H0 × d,

v = 65 × 180

= 11,700 km/s

3. If H0 = 75 km/s/Mpc, then we use the same formula to find the recessional velocity of the galaxy:

v = H0 × d,

v = 75 × 180

= 13,500 km/s

4. To find the distance of a galaxy whose recessional velocity is 3000 km/s, we use the same formula: v = H0 × d,where v is the recessional velocity of the galaxy, H0 is the Hubble constant, and d is the distance of the galaxy.

Rearranging the formula to solve for distance: d = v / H0,

d = 3000 / 70

= 42.86 Mpc

5. If H0 = 65 km/s/Mpc, then we use the same formula to find the distance of the galaxy: d = v / H0,

d = 3000 / 65

= 46.15 Mpc

6. If H0 = 75 km/s/Mpc, then we use the same formula to find the distance of the galaxy: d = v / H0,

d = 3000 / 75

= 40 Mpc

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Answer:

\(resolving \: \\ (\downarrow_{ + }) \: s = ut + \frac{1}{2} g {t}^{2} \\ u = 0 ,\: g = 9.81m. {s}^{ - 2} , \: t = 5s \\ s =h= \frac{1}{2} g {t}^{2}, = \frac{1}{2} (9.81){5}^{2}\\=4.9\times25 \\ h=122.6m\)

Conduction is the transfer of heat without the actual motion of molecules and it takes place only in solids.