The distribution of 4 in the following expression (5+s)4

The true statements about the random variable is:

1. P(X > 17) - P(X < 17)

2. P(X < 21) - P(Z < 1)

1. P(X > 17) - P(X < 17): Since X follows a normal distribution with a mean (µ) of 17 and a standard deviation (σ) of 4, the probability of X being greater than 17 is equal to the probability of X being less than 17 (i.e., P(X > 17) = P(X < 17)). Therefore, the difference between these probabilities is zero.

2. P(X < 21) - P(Z < 1):

To compute P(X < 21), we need to calculate the area under the normal distribution curve to the left of 21. Similarly, to compute P(Z < 1), we need to calculate the area under the standard normal distribution curve to the left of 1.

As X follows a normal distribution with mean 17 and standard deviation 4, we can convert X to a standard normal random variable Z using the formula Z = (X - µ) / σ. So, Z = (21 - 17) / 4 = 1. P(Z < 1) represents the probability of Z being less than 1, which is approximately 0.8413. Thus, P(X < 21) - P(Z < 1) is equal to the probability of X being less than 21 minus 0.8413.

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the complete question is:

consider a random variable, x, where x~n(17, 4). which of the following statements are true? select all that apply.

P(X>17)-P(X <17)

P(X<21)-P(Z<1)

P(X<11) = P(X<3)

P(X<21) P(Z<2)

The percentage of the sheets with no air bubbles is given as follows:

13.53%.

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following mass probability function:

\(P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}\)

The parameters are listed and explained as follows:

The mean for this problem is given as follows:

\(\mu = 2\)

The proportion of these sheets with no air bubbles is P(X = 0), hence it is given as follows:

P(X = 0) = e^-2 = 0.1353 = 13.53%.

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The amounts that she has to spend are of $2000 in Country A and $500 in Country B, using a system of equations.

The first step in building the system of equations is identifying the variables, as follows:

Considering the total amount of $3400 that she has to spend, and the rates of each country, the following equation is established:

1.3x + 1.6y = 3400.

She wants to have four times as much of currency A as she wants of currency B, hence the second equation of the system is presented as follows:

x = 4y.

Then the amount that she will have to spend in Country B is calculated replacing x = 4y on the first equation as follows:

1.3(4y) + 1.6y = 3400

6.8y = 3400

y = 3400/6.8

y = $500.

The amount that she has to spend in Country A is given as follows:

x = 4y = 4 x 500 = $2000.

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Answer: 1701

Step-by-step explanation:

It’s the simple math

243

    7=

1701

Answer:

949

Step-by-step explanation:

Answer:

-3

Step-by-step explanation:

first you’d do the things in parentheses

In the parentheses you would simplify the exponent first because PEMDAS

(-3)^2 = 9

-4 + 9 - 6 = -1

Then you would do 15 / 3 which equals 5

5 x -1 = -5

-5 + 2 = -3

Answer:

Answer: HC, HT, CT

Step-by-step explanation:

2 !DIFFERENT! DRINKS so it can’t be HH, CC, TT

Step-by-step explanation:

.....

Answer:

24 meters

Step-by-step explanation:

I hope this helps!

Answer:

24 meters

Step-by-step explanation:

you do 6 times 4

Answer:

5x + 25

Step-by-step explanation:

The values of p for which the series ∑(n=1)^(∞) ((-1)^n / (n^p)) converges conditionally are p > 0.

To determine the values of p for which the series ∑(n=1)^(∞) ((-1)^n / (n^p)) converges conditionally, we can apply the alternating series test.

According to the alternating series test, a series of the form ∑((-1)^n * b_n) converges conditionally if:

1. The terms b_n are positive and decreasing (|b_n+1| ≤ |b_n|), and

2. The limit of b_n as n approaches infinity is 0 (lim(n→∞) b_n = 0).

In this case, our terms are b_n = 1 / (n^p). Let's check these conditions:

1. The terms are positive and decreasing:

  To satisfy this condition, we need to show that |(1 / ((n+1)^p))| ≤ |(1 / (n^p))| for all n.

  Taking the ratio of consecutive terms:

  |(1 / ((n+1)^p)) / (1 / (n^p))| = (n^p) / ((n+1)^p) = (n / (n+1))^p.

Since (n / (n+1)) is less than 1 for all n, raising it to the power p will still be less than 1 for p > 0. Therefore, the terms are positive and decreasing.

2. The limit of the terms as n approaches infinity is 0:

  lim(n→∞) (1 / (n^p)) = 0 for p > 0.

Based on the conditions of the alternating series test, the series converges conditionally for p > 0.

Therefore, the values of p for which the series ∑(n=1)^(∞) ((-1)^n / (n^p)) converges conditionally are p > 0.

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The system of linear equations that match with its graph and the solution is

Making a graph of a system of linear equations is done by substituting the value x = 0 and the value y = 0 in an equation. After getting two points, draw a line through the two coordinates. But if the equation goes past the point (0 , 0) then take another value of x at random to get another point. Graph and solution

3. - x + y = 1

x - y = 1

Graph F matches the system.

The two lines are parallel.

No solution.

4. 2x - 2y = 4

- x + y = - 2

Graph E matches the system.

The two lines coincide.

Infinitely many solutions.

5. 2x + y = 4

- 4x - 2y = - 8

Graph B matches the system.

The two lines coincide.

Infinitely many solutions.

6.  x - y = 0

5x - 2y = 6

Graph C matches the system.

The two lines intersect.

One solution.

7. - 2x + 4y = 1

3x - 6y = 9

Graph D matches the system.

The two lines are parallel.

No solution.

8. 5x + 3y = 17

x - 3y = - 2

Graph A matches the system.

The two lines intersect.

One solution.

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Answer:

#7:  x = 7

#8:  AC = 52

Step-by-step explanation:

We know that part + part = whole.

Thus, AB + BC = AC

Using this fact, we can solve for x:

\(6x-3+2x-1=10x-18\\8x-4=10x-18\\8x=10x-14\\-2x=-14\\x=7\)

We can simply plug in x in 10x-18 to find the length of AC:

\(10(7)-18=AC\\70-18=AC\\52=AC\)

You can also check that AB + BC = AC by plugging in x for 6x -3 and 2x -1 and finding the sum of the two parts of the line:

\(6(7)-3+2(7)-1=52\\42-3+14-1=52\\39+13=52\\52=52\)

The population parameter is the average amount of time for all students to complete the standardized test. The 90% confidence interval [108.6, 143.4] means that we are 90% assured that the true population means lies within this range.

The population parameter in this case is the average amount of time, in minutes, for all students to complete the standardized test.

The interpretation of the 90% confidence interval [108.6, 143.4] is that we are 90% confident that the true population means that it falls within this interval. It means that if we were to repeat the sampling process multiple times and construct 90% confidence intervals, approximately 90% of these intervals would capture the true population mean. In this specific case, we can be 90% assured that the average time for all students taken to complete the standardized test must be between 108.6 and 143.4 minutes.

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Answer:

40

Step-by-step explanation:

40 because 39 will round up to 40 by 1

The probability in percentage that the next customer will pay with a debit card will be 68.42%.

Its fundamental concept is that someone will nearly surely occur. The proportion of positive events in comparison to the total of occurrences. Then the probability is given as,

P = (Favorable event) / (Total event)

She knows that in the last week, 13 customers paid cash, 39 customers used a debit card, and 5 customers used a credit card.

The probability that the next customer that will pay with a debit card will be given as,

P = 39 / (13 + 39 + 5)

P = 39 / 57

P = 0.6842 or 68.42%

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The corresponding CDF is:F(x) = 1 - cos(x) for 0 < x < π/2F(x) = 1 for x ≥ π/2c. The expected value or mean of the given random variable X is 2. d. The variance of the given random variable X is π²/4 + 2π - 6.

The value of the constant A can be obtained by using the normalization condition that the integral of the PDF function over the entire possible range of X must be equal to 1. So, we can write the following integral to solve for

A:(∫f(x) dx) from 0 to π/2=∫A sin(x) dx= A [-cos(x)] evaluated at π/2 and 0= -A(cos(π/2) - cos(0))= A (1 - 0) =1. Therefore, the value of the constant A is 1. b. The CDF of the given random variable X is given as follows:

F(x)=∫f(x)dx from 0 to x, for 0 < x < π/2=∫sin(x) dx from 0 to x= [-cos(x)] evaluated at x and 0= -cos(x) - (-cos(0))= 1 - cos(x) for 0 < x < π/2=1 for x ≥ π/2. So, the corresponding CDF is as follows:

F(x) = 1 - cos(x) for 0 < x < π/2F(x) = 1 for x ≥ π/2c. The expected value or mean of the given random variable X can be obtained using the following formula:

E(X) = ∫xf(x)dx from 0 to π/2=∫x sin(x) dx from 0 to π/2= [-x cos(x)] evaluated at π/2 and 0 - ∫-cos(x) dx from 0 to π/2= -0 + cos(0) - ([-cos(x)] evaluated at π/2 and 0)= 0 + 1 - (-1)= 2. So, the expected value of the given random variable X is 2.

d. The variance of the given random variable X can be obtained using the following formula:

Var(X) = E(X²) - [E(X)]²=∫x² f(x)dx from 0 to π/2 - [E(X)]²=∫x² sin(x)dx from 0 to π/2 - (2)²= [-x² cos(x)] evaluated at π/2 and 0 + ∫2x cos(x)dx from 0 to π/2 - 4= -0 + π²/4 - 4 + (2 sin(x) + 2x cos(x)) evaluated at π/2 and 0= π²/4 - 2 - 4 + 2 + 2π= π²/4 + 2π - 6. So, the variance of the given random variable X is π²/4 + 2π - 6

Hence, the answer is: a. The value of the constant A is 1.b. The corresponding CDF is : F(x) = 1 - cos(x) for 0 < x < π/2F(x) = 1 for x ≥ π/2c. The expected value or mean of the given random variable X is 2. d. The variance of the given random variable X is π²/4 + 2π - 6

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f(x) = x is a simple linear function with a slope of 1, f(x) = 3 5 6 is a constant function, f(x) = 3-x is a linear function with a negative slope of -1,  f(x) = 1 is a constant function, f(x) = 2 is a constant function

A constant function is a mathematical function whose output value is the same for every input value

From the given parameters, f(x) = x is a simple linear function with a slope of 1, this implies  that for every unit increase in x, the value of y increases by 1.

Also,  f(x) = 3 5 6 is a constant function, where the value of y is always 3 5 6, regardless of the value of x.

In the same way,  f(x) = 3-x is a linear function with a negative slope of -1, which means that for every unit increase in x, the value of y decreases by 1. The fourth function f(x) = 1 is a constant function, where the value of y is always 1, regardless of the value of x.

The domain of the fifth function is 3 0, which means that x can take any value between 3 and 0.

The sixth function f(x) = 2 is a constant function, where the value of y is always 2, regardless of the value of x.

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Answer: 2.5

\(\frac{p}{a}=\frac{1}{2} => a=2p\\\\\frac{a}{b}=\frac{2}{3}=> b=\frac{3}{2}a=3p\\\\\frac{b}{c}=\frac{5}{1}=>c=\frac{1}{5} b=\frac{3p}{5}\\\\\frac{c}{r}=\frac{3}{2}=>\frac{3p}{5r}=\frac{3}{2}=>\frac{p}{r}=\frac{3}{2}:\frac{3}{5}=2.5\)

Step-by-step explanation:

Answer:

= -8

Step-by-step explanation:

2(-2)+3(-3)+5

first solve the brackets

-4 -9 +5

-13 + 5

= -8

According to the given statement , the domain and range of a relation describe the possible inputs and outputs, respectively.

In the first relation, the domain is all real numbers and the range is also all real numbers.

In the second relation, the domain is x ≤ 0, which means x is less than or equal to 0. The range is all real numbers.

In the third relation, the domain is x ≤ 0 and the range is y ≤ 0.

In the fourth relation, the domain is all real numbers and the range is y ≤ 0.

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Answer:

i dont see it-

Step-by-step explanation:

Step-by-step explanation:

ok but what's the question

The figure that ∠ 1 and ∠ 2 are a pair of alternate exterior angles is Figure A.

Alternate exterior angles are a pair of angles that are formed by two parallel lines and a transversal line intersecting them. Alternate exterior angles are located on opposite sides of the transversal line and outside of the two parallel lines.

When two parallel lines are intersected by a transversal line, eight angles are formed. These angles can be divided into pairs based on their location and relationship to each other.

In Figure 1, ∠ 1 and ∠ 2 are a pair of alternate exterior angles as they form due to two parallel lines.

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Step-by-step explanation:

I did the Iready.

Answer:

-4 4/5 = - 24/5

1 1/3 = 4/3        

-(24/5) / (4/3) = -72 / 20 = -3 12/20 = -3 3/5

Using a calculator -(4 4/5) / (1 1/3) = -3 3/5

Answer:

266 Miles / 3.5 Hours = # Mph

just plug that into your calc

Step-by-step explanation

think we measure in Miles Per Hour

266 Miles / 3.5 Hours = # Mph

just plug that into your calc

Given:

The vertices of the rectangle ABCD are A(-3,4), B(-1,4), C(-1,-1) and D(-3,-1).

It is reflected over the line x=2.

To find:

The vertices of the image A'B'C'D'.

Solution:

If a figure is reflected over the line x=a, then

\((x,y)\to (-(x-a)+a,y)\)

\((x,y)\to (-x+a+a,y)\)

\((x,y)\to (-x+2a,y)\)

The rectangle ABCD is reflected over the line x=2. So, the rule of reflection is

\((x,y)\to (-x+2(2),y)\)

\((x,y)\to (-x+4,y)\)

Using this rule, we get

\(A(-3,4)\to A'(-(-3)+4,4)\)

\(A(-3,4)\to A'(3+4,4)\)

\(A(-3,4)\to A'(7,4)\)

Similarly,

\(B(-1,4)\to B'(5,4)\)

\(C(-1,-1)\to C'(5,-1)\)

\(D(-3,-1)\to D'(7,-1)\)

The vertices of image are A'(7,4), B'(5,4), C'(5,-1) and D'(7,-1).

Note: All options are incorrect or not in proper format.

The $1314^\text{th}$ digit past the decimal point is 2.

To find the $1314^\text{th}$ digit past the decimal point in the decimal expansion of $\frac{5}{14}$, we can use long division to compute the decimal expansion of the fraction.

The long division of $\frac{5}{14}$ is as follows:

```

0.35    <-- Quotient

-----

14 | 5.00

   4.2    <-- Subtract: 5 - (14 * 0.3)

   -----

     80   <-- Bring down the 0

     70    <-- Subtract: 80 - (14 * 5)

     -----

     100   <-- Bring down the 0

      98    <-- Subtract: 100 - (14 * 7)

      -----

       20   <-- Bring down the 0

       14    <-- Subtract: 20 - (14 * 1)

       -----

        60   <-- Bring down the 0

        56    <-- Subtract: 60 - (14 * 4)

        -----

         40   <-- Bring down the 0

         28    <-- Subtract: 40 - (14 * 2)

         -----

         120   <-- Bring down the 0

         112    <-- Subtract: 120 - (14 * 8)

         -----

           80   <-- Bring down the 0

           70    <-- Subtract: 80 - (14 * 5)

           -----

           ...

```

We can see that the decimal expansion of $\frac{5}{14}$ is a repeating decimal pattern with a repeating block of digits 285714. Therefore, the $1314^\text{th}$ digit past the decimal point is the same as the $1314 \mod 6 = 0^\text{th}$ digit in the repeating block.

Since $1314 \mod 6 = 0$, the $1314^\text{th}$ digit past the decimal point in the decimal expansion of $\frac{5}{14}$ is the first digit of the repeating block, which is 2.

So, the $1314^\text{th}$ digit past the decimal point is 2.

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Answer:

5%

Step-by-step explanation:

100 - 95 = 5