The difference of a number and - 11/12 is the same as the difference of three times the number and 1/6

Answer:

6-16y

Step-by-step explanation:

Multiply 2 by the numbers inside the parentheses.

There is no significant evidence to conclude that the proportion of all pet owners who speak to their pets on an answering machine or telephone is lower than 45%.

x =63

n =150

P =0.45

\(\hat{p} & =\frac{x}{n} \\\) = 63/150 = 0.42

Null and alternative hypothesis:

\($$\begin{aligned}& H_0: P=0.45 \\& H_a: P < 0.45 \quad \text { (Left tailed test) }\end{aligned}$$\)

Significance level: \($\alpha=0.05$\)

Test statistic:

Under the null hypothesis, the test statistic for one sample proportion will be

\($$\begin{aligned}z_0 & =\frac{\hat{p}-P}{\sqrt{\frac{P(1-P)}{n}}} \\& =\frac{0.42-0.45}{\sqrt{\frac{0.45(1-0.45)}{150}}} \\& =-0.74\end{aligned}$$\)

P-value:

\(p & =P+( z_0) \\& =P+(z_0) \\& =P+(-0.74) \quad \quad \text { (Standard normal tables) } \\& =-0.29\)

Decision rule:

Reject H_0, if \($p \leq \alpha$\) otherwise do not reject H_0.

Since the p-value is greater than the level of significance, so we fail to reject the null hypothesis at 5% significance level.

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The slope of (0,-3) and (9,0) is 1/3

The slope of line q is 3/7

The equation of line p is y=3/7x+9

The standard form of equation of a line is

y = mx + c

where m represents the slope of the line

Upon comparing the standard form with the given equation

y = 3/7 x + 9

we get that the slope of this line is 3/7

and the y intercept c is 9

When two lines are parallel to each other, then the slope of both the lines are same.

the slope of line q is same as the slope of line p as line q is parallel to line p

the slope of line q is 3/7

Therefore,  the slope of line q is 3/7

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The logical statement that defines the relation (⊂) in terms of (∈) is:

A ⊂ B if every element of A is an element of B.

To prove that (A-B) ∩ (B-A) = ∅,

follow the steps below:

Step 1: To begin, assume that x ∈ (A-B) ∩ (B-A)

Step 2: This means that x is an element of both A-B and B-A.

Step 3: Since x ∈ A-B, x ∈ A, but x ∉ B.

Step 4: Since x ∈ B-A, x ∈ B, but x ∉ A.

Step 5: Since x ∈ A and x ∉ B, it is impossible for x to be in both A and B.

Step 6: Therefore, x cannot be in (A-B) ∩ (B-A).

Step 7: This means that (A-B) ∩ (B-A) is an empty set, or ∅.

Step 8: Thus, (A-B) ∩ (B-A) = ∅.

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Answer:

5×2x +5×1=25

10x+5=25

10x=25-5

10x=20

x=2

•D X =2

The y-intercept of a line in the xy-plane is (0,1) as shown in attached graph given int the question.

To find the y-intercept of a line in the xy-plane, we need to find the point where the line intersects the y-axis. The y-axis is the vertical axis that runs through the origin and is perpendicular to the x-axis. This means that the y-intercept is the value of y when x is equal to zero. Therefore, we can read off the y-intercept directly from the equation of the line. To find the y-intercept of a line in the xy-plane, we need to find the point where the line intersects the y-axis. The y-axis is the vertical axis that runs through the origin and is perpendicular to the x-axis.

In the given graph we can see that the line intersects the point 1 on y axis.

Therefore, y-intercept of a line in the xy-plane is (0,1).

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Answer:

is it like exponets

Step-by-step explanation:

A sine wave is also known as a sinusoid. The sine function that has an amplitude of 5, a midline of 2 and a period of 3/7​ is 5Sin(16πx/3)+2.

A sine wave, also known as a sinusoid, is the graph of the sine function. Any curve that can be expressed in the form is referred to as a sinusoid. (A and B are both positive.) Sinusoids are the most generic version of the sine function.

Given the amplitude of the function is 5, the vertical shift is 3, and the period of 3/7. Therefore, the values of constants can be written as,

a = 5

b = (2π)/(3/7) = 14π/3

d = 2

Substituting the values in the sine function,

a sin b (x-c) + d

= 5 Sin(16π/3)(x-0) + 2

= 5 Sin(16πx/3) + 2

Hence, the sine function that has an amplitude of 5, a midline of 2 and a period of 3/7​ is 5Sin(16πx/3)+2.

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Answer:

x = 8

y = 4 sqrt(3)

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

sin theta = opp / hyp

sin 30 = 4/x

x sin 30 = 4

x = 4 / sin 30

x = 4 / ( 1/2)

x = 8

tan theta = opp /adj

tan 30 = 4/y

y tan 30 =4

y = 4 / tan 30

y = 4 / ( 1/ sqrt(3))

y = 4 sqrt(3)

Answer and Step-by-step explanation:

To solve, we need to use Trigonometric Functions.

These functions include Sine, Cosine, and Tangent.

- Each one has its own rule to follow when solving.

θ = Angle

sin(θ) = \(\frac{Opposite.Side}{Hypotenuse}\)

cos(θ) = \(\frac{Adjacent.Side}{Hypotenuse}\)

tan(θ) = \(\frac{Opposite.Side}{Adjacent.Side}\)

For this problem, we will only be using the trigonometric functions of Sine and Tangent.

Start by finding x.

sin(30) = \(\frac{4}{x}\)

Multiply x to both sides.

x × sin(30) = \(\frac{4}{x}\) × x

x(sin(30)) = 4

Divide both sides of the equation by sin(30).

x(sin(30)) ÷ (sin(30)) = 4 ÷ (sin(30))

x = \(\frac{4}{sin(30)}\)

Simplify in calculator.

x = 8

Now find the value of y.

tan(30) = \(\frac{4}{y}\)

Multiply y to both sides.

y × tan(30) = \(\frac{4}{y}\) × y

y(tan(30)) = 4

Divide both sides of the equation by tan(30).

y(tan(30)) ÷ (tan(30)) = 4 ÷ (tan(30))

y = \(\frac{4}{tan(30)}\)

Simplify in calculator.

y = \(4\sqrt{3}\)

x = 8

y = \(4\sqrt{3}\)

^ These are the answers.

I hope this helps!

#teamtrees #PAW (Plant And Water)

Adding and subtracting polynomials worksheets assist pupils in becoming acquainted with the idea of polynomial addition and subtraction.

Adding and subtracting polynomial worksheets provide pupils with a platform to access a variety of well-structured problems. Because these worksheets progress in complexity, they are simple to use and allow pupils to reinforce their concepts.

Children must study in accordance with their learning curve, and these worksheets are designed to allow young brains to work at their own speed. These math worksheets also address the logical and reasoning aspects of arithmetic, assisting pupils in real-life situations.

Students may have a better grasp and explore these worksheets more quickly with the aid of pictures. These worksheets' step-by-step approach helps pupils better comprehend ideas and reinforce their comprehension.

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Answer:

I think it's 15

Step-by-step explanation:

Volume is basically just adding length, width, and height

A total of 14 additives were included here in a study of the effects of various health additives on various top runners.

One-Way ANOVA Test :;Uses one-way analysis of variance (ANOVA) to determine whether there are statistically significant differences between the means of three or more independent (unrelated) groups.

Need of One way ANOVA :

When working with individuals, this situation can be encountered using two different types of study designs group. Then have each group perform a different task and measure the outcome/response to the same dependent variable. In the given problem, the term "Between" in the source table refers to processing. The term "within" refers to the error term. The inner term represents the variability that exists between runners. The total number of

additives is one more than his total number of

degrees of freedom (df). Total degrees of freedom for = N – 1. Total degrees of freedom = 18,so N= 19

Hence, total additives for given study is 19.

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Complete Question:

study was made on the effects of several health additives for a number of elite

runners. The results of a One-Way ANOVA are presented in the following table.

how many additives were in the study?

Source। Df Sum of Squares MS

Between 3 55.00

Within 15 450.00

Total 18 505.50

A. 18

B. 19

C. 7

D. 8

The student is getting enough sleep because the student is sleeping for 7 hours 30 minutes. The inequality for the number of hours of sleep is x ≥ 7 hours.

For the student to be getting enough sleep, the student has to sleep for greater than 7 hours. The first step is to determine the number of hours slept.

In order to determine the time the student spent sleeping, subtract the time he slept from the time he woke up. Subtraction is the process that is sued to determine the difference between two or more numbers.

The sign that represents subtraction is -. In this case, 6 : 30am - 11 : 00pm = 7 hours 30 minutes. The sign to use is ≥ because the student can sleep for 7 hours or greater.

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The student is getting enough sleep.

The inequality that represents the number of hours a student should sleep each night is s ≥ 7 hours.

In order to determine if the student is getting enough sleep, we have to determine the total hours between 11:00pm and 6:30am. The total hours between 11:00pm and 6:30am is 7 hours 30 minutes.  7 hours 30 minutes is greater than 7 hours. Thus, the student is getting enough sleep.

Here are inequality signs and what they mean:

> means greater than

< means less than

≥ means greater than or equal to

≤ less than or equal to

The sign that would be used is, ≥ , the greater than or equal to sign

The total hours slept ≥ 7 hours

s ≥  7 hours

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Answer:

B= 25°

A=138° /139°

...

...

....

....

.....

...

The local maximum and minimum values of the function are as follows: maximum at (smaller x value), minimum at (larger x value), and there are no saddle points.

To find the local maximum and minimum values of the function, we need to analyze its critical points, which occur where the partial derivatives are equal to zero or do not exist.

Let's denote the function as f(x, y) = -8 - 2x + 4y - x^2 - 4y^2. Taking the partial derivatives with respect to x and y, we have:

∂f/∂x = -2 - 2x

∂f/∂y = 4 - 8y

To find critical points, we set both partial derivatives to zero and solve the resulting system of equations. From ∂f/∂x = -2 - 2x = 0, we obtain x = -1. From ∂f/∂y = 4 - 8y = 0, we find y = 1/2.

Substituting these values back into the function, we get f(-1, 1/2) = -9/2. Thus, we have a local minimum at (x, y) = (-1, 1/2).

There are no other critical points, which means there are no local maximums or saddle points. Therefore, the function has a local minimum at (x, y) = (-1, 1/2) but does not have any local maximums or saddle points.

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Answer:

6^4

Step-by-step explanation:

6^2*6^9/6^7

6^(2+9)/6^7

6^(11-7)

6^4 or 1296

Answer:

17

Step-by-step explanation:

What is the value of s?

17 units

Answer:

Step-by-step explanation:

Let's start by looking at the graph of the two equations.

Since you are not looking for where the lines cross, I have chosen any 3 points for each equation almost randomly. I have not used either the x or y intercepts except once.

As a sample for the method of calculation

Let x -2y = 4

Let x = -2.             Find y and put it in the table

-2 - 2y = 4             Add 2 to both sides

-2+2-2y = 4 + 2    Combine

-2y = 6                  Divide by -2

y = 6/-2

y = - 3

Put that in the table under the first equation.

The other 5 points are done the same way.

Answer:

r = 10 , centre = (6, - 2 )

Step-by-step explanation:

the equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k ) are the coordinates of the centre and r is the radius

given

x² - 12x - 60 = - y² - 4y ( add y² + 4y to both sides )

x² - 12x + y² + 4y - 60 = 0 ( add 60 to both sides )

x² - 12x + y² + 4y = 60

using the method of completing the square

add ( half the coefficient of the x and y terms )² to both sides

x² + 2(- 6)x + 36 + y² + 2(2)y + 4 = 60 + 36 + 4

(x - 6)² + (y + 2)² = 100 ← in standard form

with centre = (6, - 2 ) and r = \(\sqrt{100}\) = 10

The Playfair cipher is a polygraphic substitution cipher that encrypts pairs of letters rather than individual letters, making it significantly more difficult to break than simpler substitution ciphers.

The Playfair cipher works by dividing the plaintext into pairs of letters (bigrams), encrypting the bigrams one at a time using a series of key tables or matrices, and then concatenating the resulting ciphertext. As a result, if a plaintext message has an odd number of letters, the sender adds an additional letter to the end of the message to make it even before encrypting it. To decode using the Playfair cipher, one must use the reverse method of encryption, which involves locating each pair of letters in the ciphertext in the key matrix, finding the corresponding plaintext letters, and rejoining the pairs to reveal the original message. The Playfair cipher is a fascinating encryption technique that operates by replacing pairs of letters. It's significantly more difficult to crack than simple substitution ciphers since it works by dividing the plaintext into pairs of letters. As a result, the Playfair cipher was widely employed throughout the 19th century. Although its usefulness has been undermined by modern computing systems, the Playfair cipher remains one of the most intriguing historical encryption techniques. Because the Playfair cipher encrypts bigrams, which are two-letter chunks, the original message must contain an even number of letters. To create the ciphertext, the Playfair cipher employs a series of key tables or matrices to encrypt the plaintext message in a straightforward step-by-step procedure. As a result, when the ciphertext is received, one can easily decrypt it by using the reverse encryption method. The Playfair cipher is fascinating because of its simplicity. The basic algorithm for encrypting and decrypting the cipher is straightforward, and it can be quickly executed by hand. As a result, if you're looking to encrypt your messages securely, it's a good option to use.Cryptanalysis, or the act of breaking ciphers, is the practice of breaking Playfair ciphers. Cryptanalysis is now made easier by modern computing systems.

To decode a Playfair cipher, use the reverse technique of encryption, which involves finding the ciphertext's pairs of letters in the key matrix, locating the corresponding plaintext letters, and rejoining the pairs to reveal the original message. The Playfair cipher is a fascinating encryption technique that operates by replacing pairs of letters. It's significantly more difficult to crack than simple substitution ciphers since it works by dividing the plaintext into pairs of letters. As a result, the Playfair cipher was widely employed throughout the 19th century. Because it encrypts bigrams, which are two-letter chunks, the original message must contain an even number of letters.

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The names of 0 employees are written on 0 cards. the cards are placed in a​ bag, and three names are picked from the bag - here simple random sampling technique was used.

Basic irregular testing can provide you with an extremely precise image of how your motto performs with the typical individual, yet it won't give you nitty gritty data about unambiguous gatherings. Utilizing straightforward irregular testing permits scientists to make speculations about a particular populace and leave out any inclination. This can assist with deciding how to settle on future choices. It has been expressed that "the rationale behind straightforward arbitrary examining is that it eliminates predisposition from the choice method and ought to bring about delegate tests".

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An inequality that can be written in the form ax + by < c (where a and b are not both zero) is called a linear inequality in two variables.

An inequality that represents a line in a two-dimensional coordinate system is referred to as a linear inequality. The set of points that satisfies the inequality is a half-plane bounded by a line that may be dashed or solid.

In contrast to a linear equation, which represents a line, a linear inequality represents a half-plane. The points on one side of the line, rather than the points on the line, are solutions to the inequality.

The method of shading is used to graph a linear inequality in two variables. First, graph the boundary line, which is usually represented by a solid or dashed line, and then select a test point on one side of the line. Shaded regions of the half-plane containing the test point satisfy the inequality.

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According to the question For a) This statement is correct. For b) statement is incorrect. For c) statement is correct. For d) statement is incorrect and For e) This statement is correct.

a. A linear transformation is a special type of function.

This statement is correct. A linear transformation is a function between vector spaces that preserves the vector addition and scalar multiplication operations. In other words, it satisfies two properties: preservation of addition

\(\[T(u + v) = T(u) + T(v)\]\)

and preservation of scalar multiplication

\(\[T(cu) = cT(u)\]\)

where \(\(T\)\) is the linear transformation, \(\(u\)\) and \(\(v\)\) are vectors, and \(\(c\)\) is a scalar.

b. If \(\(A\)\) is a \(\(3 \times 5\)\) matrix and \(\(T\)\) is a transformation defined by  \(\(T(x) = Ax\),\) then the domain of \(\(T\)\) is \(\(\mathbb{R}^5\).\)

This statement is incorrect. The domain of the transformation \(\(T\)\) is determined by the size of the input vectors, which in this case is determined by the number of columns of matrix \(\(A\)\). Since \(\(A\)\) is a \(\(3 \times 5\)\) matrix, the domain of \(\(T\)\) is \(\(\mathbb{R}^5\), not \(\mathbb{R}\).\)

c. If \(\(A\)\) is an \(\(m \times n\)\) matrix, then the range of the transformation \(\(x \rightarrow Ax\)\) is \(\(\mathbb{R}^m\).\)

This statement is correct. The range of the transformation \(\(x \rightarrow Ax\)\) is the set of all possible outputs obtained by multiplying the matrix \(A\)\) with the input vectors \(\(x\).\) Since \(\(A\)\) is an \(\(m \times n\)\) matrix, the resulting vectors will have \(\(m\)\) dimensions. Therefore, the range of the transformation is \(\(\mathbb{R}^m\).\)

d. Every linear transformation is a matrix transformation.

This statement is incorrect. While every matrix transformation is a linear transformation (since matrix multiplication satisfies the properties of linearity), not every linear transformation can be represented by a matrix. Linear transformations can have various forms and may not always be expressible as matrix multiplication.

e. A transformation \(\(T\)\) is linear if and only if \(\(T(cv + c_2v_2) = cT(v_1) + c_2T(v_2)\)\) for all \(\(v_1\)\) and \(\(v_2\)\) in the domain of \(\(T\)\) and for all scalars \(\(c\)\) and \(\(c_2\).\)

This statement is correct. This equation represents the linearity property of a transformation. A transformation \(\(T\)\) is linear if and only if it satisfies this equation, which states that the transformation of a linear combination of two vectors is equal to the linear combination of the transformed vectors.

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Answer:

-32p+56

Step-by-step explanation:

-8*4p=-32p

-7*-8=56(negative times negative =positive)

-32p+56

Answer:

hi

Step-by-step explanation:

-8(4p-7)= -8×4p -7×(-8) = -32p-56

Answer:

A, C, D, E

Step-by-step explanation:

Input your equations and tables into Desmos graphing to get your answers.

Answer:

D.

Step-by-step explanation:

3 1/4 = 3.25

3 2/7 = 3.29

3.29>3.25

3.31>3.29

3.36>3.31

so the answer is D.