The difference between the roots of the equation 2x^2 -7x+c=0, what is c

Number of operations the computer can complete in one minute is 2,100,000.

If a computer can execute 35 operations per millisecond, we can calculate the number of operations it can complete in one second by multiplying 35 by the number of milliseconds in one second, which is 1,000.

35 operations/ms x 1,000 ms/s = 35,000 operations/s

Therefore, the computer can complete 35,000 operations per second.

To calculate the number of operations the computer can complete in one minute, we need to multiply the number of operations per second by the number of seconds in one minute, which is 60.

35,000 operations/s x 60 s/min = 2,100,000 operations/min

Therefore, the computer can complete 2,100,000 operations per minute.

Understanding units of time and being able to convert between them is important in many areas of computer science, including measuring the performance and efficiency of computer systems.

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Answer:

17.85

Step-by-step explanation:

it would be $5.95 per tree times that by 5 you get $17.85

The work done when lifting the 290-kg rock to a height of 6 m is 17,052 Joules.

To calculate the work done when lifting the rock, we need to use the formula:

Work = Force × Distance × cos(theta)

In this case, the force required to lift the rock is equal to its weight, which can be calculated using the formula:

Force = mass × acceleration due to gravity

Given:

mass of the rock (m) = 290 kg

acceleration due to gravity (g) = 9.8 m/s²

height (distance) lifted (h) = 6 m

theta (angle between the direction of force and the direction of motion) = 0° (since the force and displacement are in the same direction)

First, let's calculate the force:

Force = mass × acceleration due to gravity

Force = 290 kg × 9.8 m/s²

Force = 2842 N

Now, we can calculate the work done:

Work = Force × Distance × cos(theta)

Work = 2842 N × 6 m × cos(0°)

Work = 2842 N × 6 m × 1

Work = 17,052 Joules

Therefore, the work done when lifting the 290-kg rock to a height of 6 m is 17,052 Joules.

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Answer:

Step-by-step explanation:

Kites have one pair of congruent angles.

In this case it is B and D:

Find the measure of B and D:

Find the measure of angle C:

The smallest angle is C

Numerical values of,

Million: 1,000,000

Billion: 1,000,000,000

Trillion: 1,000,000,000,000

Quadrillion: 1,000,000,000,000,000

Zillion and Gazillion: These are informal and exaggerated terms that do not have specific numerical values

Million: A million is a number equal to 1,000,000 (one followed by six zeros). It is often used to express large quantities of things, such as the population of a city or the number of dollars in a large fortune.

Billion: A billion is a number equal to 1,000,000,000 (one followed by nine zeros). It is a larger quantity than a million and is often used in economic contexts, such as the value of a company or the national debt of a country.

Trillion: A trillion is a number equal to 1,000,000,000,000 (one followed by twelve zeros). It is an even larger quantity than a billion and is often used in scientific and astronomical contexts, such as the distance between stars or the number of cells in the human body.

Quadrillion: A quadrillion is a number equal to 1,000,000,000,000,000 (one followed by fifteen zeros). It is an extremely large quantity and is rarely used in everyday contexts.

Zillion and Gazillion: These are informal and exaggerated terms that do not have specific numerical values. They are often used to express an extremely large or unknown quantity in a humorous or hyperbolic way.

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Answer: 11 14/15

Step-by-step explanation:

If the test results show that the residuals are not normally distributed, Nick may need to consider transforming the data or using a different model that better fits the data. It is important to test for the normality of the residuals as it is a key assumption of regression analysis.

To test the normality of residuals in Nick's multiple regression model, he should:
1. Calculate the residuals by subtracting the predicted values from the actual values.
2. Create a histogram or a Q-Q plot of the residuals to visually inspect the distribution.
3. Perform statistical tests, such as the Shapiro-Wilk or Kolmogorov-Smirnov test, to assess normality.
If the visual inspection and statistical tests indicate that the residuals follow a normal distribution, the assumption of normality is satisfied for his regression model. To test for the normality of the residuals in a multiple regression model, Nick should conduct a normality test, such as the Shapiro-Wilk test or the Anderson-Darling test. This test will assess whether the distribution of the residuals is normal or not.

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By differentiating the second equation with respect to time, we obtain y'' = 16y, which represents a second-order differential equation in terms of y.

The given system of differential equations, x' = -4y and y' = -4x, can be converted into a second-order differential equation. To convert the system of differential equations into a second-order equation, we differentiate the second equation, y' = -4x, with respect to time. The derivative of y' with respect to time is denoted as y''.

By differentiating y' = -4x, we find y'' = -4x'. Since x' is equal to -4y according to the first equation, we substitute it into the expression for y'': y'' = 16y. This equation represents a second-order differential equation in terms of y, where the second derivative of y with respect to time is equal to 16 times y. Thus, the original system of differential equations can be equivalently described by the second-order equation y'' - 16y = 0.

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The complete triangle congruence statement are:

a) ∠A ≅ ∠Y, ∠B ≅ ∠Z, ∠C ≅ ∠X

b) AB ≅ YZ, AC ≅ XY, BC ≅ XZ

c) ΔABC ≅  ΔXYZ.

What is the congruent triangle?

The triangles are congruent regardless of how they are rotated or flipped. The symbol “≅” is frequently used to express the congruence of two items. In the diagram given, ΔABC ≅  ΔXYZ.

The corresponding angles and the sides of the triangles are also congruent with each other.

We have given,

all the corresponding congruent angles and sides. Then the triangle congruence statement.

a)

∠A ≅ ∠Y

∠B ≅ ∠Z

∠C ≅ ∠X

b)

AB ≅ YZ

AC ≅ XY

BC ≅ XZ

c)

ΔABC ≅  ΔXYZ.

Therefore, the complete triangle congruence statement are:

a) ∠A ≅ ∠Y, ∠B ≅ ∠Z, ∠C ≅ ∠X

b) AB ≅ YZ, AC ≅ XY, BC ≅ XZ

c) ΔABC ≅  ΔXYZ.

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The equation of the line which has gradient -(1/3) and passes through (6,2) in gradient-intercept form is y = (1/3)x + 4.

The gradient-intercept form is a way of representing the equation of a line. It is given by the equation

y = mx + c,

where m is the gradient of the line and c is the y-intercept.

Let us find the equation of the line which has gradient -(1/3) and passes through (6,2).

Using the point-gradient form of the equation of a straight line, we can write

y - y1 = m(x - x1)

where (x1, y1) = (6, 2) and m = -(1/3).

Substituting these values in the above equation, we get

y - 2 = -(1/3)(x - 6)

Multiplying throughout by -3, we get

-3y + 6 = x - 6

Rearranging the above equation, we get

x = 3y - 12

Adding 12 to both sides, we getx + 12 = 3y

Dividing throughout by 3, we get

y = (1/3)x + 4

Thus, the equation of the line which has gradient -(1/3) and passes through (6,2) in gradient-intercept form is y = (1/3)x + 4.

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Answer:

-10x + 4y = -53

Step-by-step explanation:

-5x+2y = -29

5x - 2y = 24

subtract both values from up to down

-5x - 5x = -10x

2y - (-2y) = 4y

-29 - 24 = -53

-10x + 4y = -53

Answer:

50

Step-by-step explanation:

because 10 × 5 is 50

- to check 50 ÷ 4 is infact equal to 10 (make sure u always double check ur answers)

The feasible set for this system of constraints is not convex, and the points (5, 5) and (3, 7) violate the convexity definition.

To determine whether the feasible set for each system of constraints is convex, we need to analyze the constraints individually and examine their intersection.

a) (x1)² + (x2)² > 9

This constraint represents points outside the circle with a radius of √9 = 3. The feasible set includes all points outside this circle.

b) x1 + x2 ≤ 10

This constraint represents points that lie on or below the line x1 + x2 = 10. The feasible set includes all points on or below this line.

c) x1, x2 > 0

This constraint represents points in the positive quadrant, where both x1 and x2 are greater than zero.

Now, let's analyze the intersection of these constraints:

Considering the first two constraints (a and b), we can see that the feasible set consists of all points outside the circle (constraint a) and below or on the line x1 + x2 = 10 (constraint b).

To determine whether the feasible set is convex, we need to check if any two points within the set create a line segment that lies entirely within the set.

If we consider the points (5, 5) and (3, 7), both points satisfy the individual constraints (a) and (b). However, the line segment connecting these two points, which is the line segment between (5, 5) and (3, 7), exits the feasible set since it passes through the circle (constraint a) and above the line x1 + x2 = 10 (constraint b).

Therefore, the feasible set for this system of constraints is not convex, and the points (5, 5) and (3, 7) violate the convexity definition.

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Answer:

-36

Step-by-step explanation:

They gave you the numerical value of h. Think of h as just a placeholder. So each time you see h, you replace it with its numerical value. This is true for all letters such as the famous x and y.

Replace h with -6

2(-6) + 4(-6) = -36

Reflect pentagon A over the y-axis, reflect it over the x-axis, and dilate it by a scale factor of two.

Reflecting pentagon A over the y-axis will change the x-coordinate from negative to positive, resulting in a point with x = 5 and the same y-coordinate.

Reflecting it over the x-axis will change the y-coordinate from positive to negative, resulting in a point with y = -5 and the same x-coordinate.

Finally, dilating it by a scale factor of two will scale both the x and y coordinates by a factor of 2, resulting in the point A' (0, -5).

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In a situation where a cast member will be picked at random from the 20 cast members who sold tickets to receive a prize, the probability of picking a cast member who sold more than 30 pocket can be calculated using the following formula.

P (X > 30) = Number of Cast Members who sold more than 30 pocket / Total Number of Cast MembersSince we have 20 Cast Members, we will need to determine the number of Cast Members who sold more than 30 pocket to calculate the probability.Let's assume that the number of Cast Members who sold more than 30 pocket is X.

We can then calculate the probability using the formula below:P (X > 30) = X/20Since we do not have the exact number of Cast Members who sold more than 30 pocket, we cannot accurately determine the probability of picking a cast member who sold more than 30 pocket.However, we can calculate the probability if we assume that the number of Cast Members who sold more than 30 pocket is 10.

We can calculate the probability as follows:P (X > 30) = Number of Cast Members who sold more than 30 pocket / Total Number of Cast MembersP (X > 30) =

10/20P (X > 30)

= 1/2Therefore, the probability of picking a cast member who sold more than 30 pocket is 1/2 or 0.5.Answer: 1/2

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The z score associated with the highest 10% is closest to: option (c) 1.28

-To find the z score associated with the highest 10%, first determine the percentage that corresponds to the lower 90%, since the z score table typically represents the area to the left of the z score.

- Look up the 0.90 (90%) in a standard normal distribution  (z score) table, which will give you the corresponding z score.

-The z score closest to 0.90 in the table is 1.28, which corresponds to the highest 10% of values.

Therefore, the z score associated with the highest 10% is closest to 1.28.

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If a finite group G has exactly one subgroup of a given order, then that subgroup is a normal subgroup of G

To show that if a finite group G has exactly one subgroup of a given order, then that subgroup is a normal subgroup of G, follow these steps:

1. Let H be the unique subgroup of G with a given order, say n.

2. Take any element g in G and consider the set gHg⁻¹, which is the conjugate of H by g. Here, g⁻¹ denotes the inverse of g.

3. We want to show that gHg⁻¹ is also a subgroup of G with the same order as H.

4. Notice that |gHg⁻¹| = |H|, since the mapping from H to gHg⁻¹ given by h ↦ ghg⁻¹ is a bijection.

5. Since there is only one subgroup of G with order n, we must have gHg⁻¹ = H.

6. As this holds for any element g in G, it means that H is a normal subgroup of G, by the definition of a normal subgroup.

So, if a finite group G has exactly one subgroup of a given order, then that subgroup is a normal subgroup of G.

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Answer:

The cost has been reduced by approximately 33%.

Step-by-step explanation:

1% of 120 is 1.2.

80 divided by 1.2 is 66.66666666...

Meaning that $80 is about 66% of the original cost. Therefore, about 33% of the cost was removed.

Hope this helps

Answer:4

Step-by-step explanation:

Answer: 3

Step-by-step explanation:

3x2 = 6

6+8=14

Step-by-step explanation:

Hello, I need the function in order to give you a exact answer.

Answer:

give me the rest of the question/ a picture or something then i can answer

Step-by-step explanation:

Answer:

I'm pretty sure It's D correct me if I'm wrong though. :)

Step-by-step explanation:

If Jamal wants to become a millionaire, then Jamal must wait for 19 years if he invests $22,108.44 at 21% today, Jamal must wait for 18 years if he invests $45,104.11 at 16% today, Jamal must wait for 22 years if he invests $152,814.56 at 8% today, and Jamal must wait for 24 years if he invests $276,434.51 at 6% today

To calculate the waiting period for Jamal, follow these steps:

Therefore, Jamal has to wait approximately 19, 18, 22, and 24 years respectively to become a millionaire by investing $22,108.44, $45,104.11, $152,814.56, and $276,434.51 respectively at 21%, 16%, 8%, and 6% interest rates.

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The dimensions of a different sector with the same area and perimeter are An alternative sector's radius is 6.42 inches. An alternative sector has an arc length of 16.52 inches.

The distance between two places along a segment of a curve is known as the arc length.

Sector radius, r = 8.26 inches

Sector arc length = 12.84 inches

Sector perimeter = 2r + length of the arc

The specified sector's perimeter is equal to 2 x 8.26 x 12.84 x 29.36 inches.

The circle's circumference is 2 + 8.26 + 16.52.

The specified circle's area is A = 8.262 * 68.2276.

Sector area, A = 53.0292 inch2

Consequently, we have;

2R plus A equals 29.36 inches

A·R = 53.0292 × 2

that provides;

R² + 53.0292 = 14.68·R

R² - 14.68·R + 53.0292 = 0

using a graphing calculator to factor yields;

(R - 6.42)·(R - 8.26) = 0

R = 6.42 or R = 8.26

R = 8.26 is the measurement for the first sector.

Due to the distinctions between the sectors, we have;

R = 6.42 inches is the radius of the other sector.

The length of the arc, A = 29.36 - 2R

∴ A = 29.36 - 2 × 6.42 = 16.52

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Hypothesis: If two angles are congruent.

Conclusion: Then they have the same measure.

The hypothesis states that if two angles are congruent, which means they are identical in shape and size, then the conclusion is that they have the same measure. In other words, when two angles are congruent, their measures are equal.

Angles are typically measured in degrees or radians. When we say that two angles are congruent, it implies that the measures of those angles are the same. This can be understood through the transitive property of congruence, which states that if two angles are congruent to a third angle, then they are congruent to each other.

For example, if angle A is congruent to angle B, and angle B is congruent to angle C, then it follows that angle A is congruent to angle C. This implies that the measures of angle A and angle C are equal, as congruent angles have the same measure.

In conclusion, the hypothesis that if two angles are congruent implies that they have the same measure is valid and supported by the principles of congruence and the transitive property.

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Option D is correct, there are 16 possibilities are in the sample space at the end of the tree diagram

It is a branch of mathematics that deals with the occurrence of a random event.

Given that Cornelio creates a tree diagram to show all possibilities for flipping a coin four times

We need to find the number of  possibilities are in the sample space at the end of the tree diagram

The number of times coin is flipped=4

We can use 2ⁿ to figure out the number of possible outcomes where n is the number of tosses.

Now n=4, so the number of possibilities are 2⁴

2×2×2×2

16

Hence, option D is correct, there are 16 possibilities are in the sample space at the end of the tree diagram

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