The dichromate ion absorbs light of wavelength close to 500 nm. Based on this information, what can you conclude? The dichromate ion absorbs within the visible region. The dichromate ion absorbs outside the visible region. Solutions of the dichromate ion are colorless.The dichromate ion absorbs in the ultraviolet region

Answer:

\(n = 243.605\)

Explanation:

Given

\(P = 200atm\) -- Pressure

\(T = 300k\) --- Temperature

\(V = 30L\) --- Volume

Required

Determine the number of moles

This question will be solved using ideal gas law which states:

\(pV = nRT\)

Make n the subject:

\(n = \frac{pV}{RT}\)

Where

\(R = 0.0821 L\ atm/(mol\ K)\)

Substitute values for p, V, R and T in:

\(n = \frac{pV}{RT}\)

\(n = \frac{200 * 30}{0.0821 * 300}\)

\(n = \frac{6000}{24.63}\)

\(n = 243.605\) -- approximated

Hence, there are 243.605 moles

354 grams of water are in 472 grams of this solution.

To determine how many grams of water are present in 472 grams of the solution, we'll need to calculate the percentage by mass of sugar in the solution and then subtract that percentage from 100 percent.

100% - 25% = 75%

By mass, the percentage of water in the solution is 75%.We can now use the following formula to calculate the grams of water in the solution.

Mass percent = (mass of solute/mass of solution) × 100 percent

For the solution given, we can say that:

Mass percent of water = 75 percent

Mass percent of sugar = 25 percent

Total mass of the solution = 472 grams

Therefore, Mass of water in the solution = (Mass percent of water / 100) x Total mass of the solution= (75 / 100) x 472= 354 grams

The solution contains 354 grams of water.

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Answer:

phenotype then genotype

Explanation:

phenotype is observable traits, genotype is heritable genes that can be passed down

Explanation:

red, blue, yellow, white, black,

these are the primary colors. when mixed together they create other colors.

The question is: Give the systematic name of \(SiF_{2}\).

Answer: The systematic name of \(SiF_{2}\) is silicon difluoride.

Explanation:

The given compound has chemical formula \(SiF_{2}\). It shows that there is one atom of silicon and two atoms of fluorine are present.

So, the number "two" will be represented by the prefix "di" while naming this compound.

Hence, systematic name of this compound is silicon difluoride.

Thus, we can conclude that systematic name of \(SiF_{2}\) is silicon difluoride.

Answer:

5.18 m x 0.77 m x 10.22 m3 = 40.763492 m^5

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Ni²⁺ is the only ion on the list that can exist as both a high-spin and a low-spin octahedral complex. The correct option is B.

An electrostatic model called the crystal field theory (CFT) assumes that the metal-ligand connection is ionic and results only from electrostatic interactions between the metal ion and the ligand. When dealing with anions, ligands are viewed as point charges, and when dealing with neutral molecules, as dipoles.

The crystal field splitting theory predicts that some transition metal ions can exist as either high-spin or low-spin octahedral complexes, depending on the magnitude of the crystal field splitting parameter (Δ) relative to the pairing energy (P).

Of the ions listed, the only one that could exist as either a high-spin or a low-spin octahedral complex is Ni²⁺ (B).

Mn²⁺ (A) is a d⁵ ion and will always form a high-spin octahedral complex due to its large number of unpaired electrons.

Sc³⁺ (C) is a d⁰ ion and does not form octahedral complexes with ligands.

Cu²⁺ (D) is a d⁹ ion and typically forms a low-spin octahedral complex due to the stability of the half-filled d⁹ configuration.

Zn²⁺ (E) is a d¹⁰ ion and does not have any unpaired electrons to undergo spin pairing, so it will always form a low-spin octahedral complex.

Therefore, the correct answer is B) Ni²⁺.

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Answer:

666.93 kJ

Explanation:

Using the formula;

Q = m × c × ∆T

Where;

Q = amount of heat absorbed (Joules)

m = mass of substance (g)

c = specific heat capacity (4.184 J/g°C)

∆T = change in temperature (°C)

Based on the information provided in the question;

Q = ?

m = 2000g

∆T = 99.7 °C - 20 °C = 79.7 °C

c = 4.184 J/g°C

Using Q = m × c × ∆T

Q = 2000 × 4.184 × 79.7

Q = 666929.6 Joules

To calculate the amount of heat absorbed (Q) in kilojoules (kJ), we say;

1 joule = 0.001 kilojoule

666929.6 Joules = 666929.6 × 0.001

= 666.9296 KJ

Approximately, Q = 666.93 kJ.

a. substituting in the expression of C(t) obtained in part a, we get,2500 = 12000/ (1 + 12000/ 5000 - 1) * e^(-2*3*t)  we get,t = 1/ (6 * log (2)) * log (5/3)≈ 0.276 h Therefore, it would take approximately 0.276 hours to reduce this concentration into C/2.

The differential equation for the indoor concentration of the given computer industry can be given as follows: dC/dt = P (0- C) - 2C²The above differential equation can be solved by the method of separating the variables as follows: dC/ (P (0- C) - 2C²) = dtIntegrating both sides, we get,-1/ [2P log (C/ (C- P0))] + (P0/ [P (C- P0)]) - (1/ (2C)) = t + c where c is the constant of integration. After simplification, the above equation can be expressed as:C(t) = P0/ (1 + (P0/ Co - 1) e^(-2Pt))The initial particle concentration Co is the value of C at t = 0. Hence, Ce = P0/ (1 + P0/ Co - 1) which can be simplified as Ce = Co/ (1 + P0/ Co - 1) = Co/P0b. Given that Co = 5000 cm³ and C/2 = 5000/2 = 2500 cm³,

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36.38 ml of a 0.167 M potassium hydroxide solution is required to neutralize 16.6 mL of a 0.366 M nitric acid solution.

Given that 16.6 mL of a 0.366 M nitric acid solution is neutralized by 0.167 M potassium hydroxide solution.

The balanced equation for the reaction is:

HNO₃ + KOH → KNO₃ + H₂O

From the equation given above,

Mole ratio of the acid, HNO₃ (nA) = 1

Mole ratio of the base, KOH (nB) = 1

From the question:

Molarity of the acid, HNO₃ (Ma) = 0.366 M

Volume of the base, KOH (Vb) =

Molarity of the base, KOH (Mb) = 0.167 M

Volume of the acid, HNO₃ (Va) = 16.6 ml

Now,

MaVa/ MbVb = nA/nB

0.366 × 16.6 / 0.167 × Vb = 1/1

6.0756 = 0.167 × Vb

Vb = 36.38 ml

Therefore, 36.38 ml of potassium hydroxide solution is required for the reaction.

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Answer:

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

\(n = \frac{N}{L} \\\)

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

\(n = \frac{5.7491 \times {10}^{25} }{6.02 \times {10}^{23} } \\ \)

We have the final answer as

Hope this helps you

Answer:

The dog ate the bone hiding under the shady tree.

Explanation:

The best observation is that the dog ate the bone hiding under the shady tree. This is because it provides the most graphic details about the position and activities of the dog.

Answer:

The dog ate the bone hiding under the shady tree.

Explanation:

It has the most detail :)

Answer:

B

Explanation:

Graphs are tools that help in performing calculations as they reduce the source of errors which is done in long mathematical calculations.

Errors in chemical analysis result when there is a difference between observed value and the true value.If the magnitude of errors is large , it results in decrease in accuracy, reproducibility, and precision.

There are three types of errors:1) random error 2) systematic error 3) human error.The cause of random errors are difficult to quantify while the human errors can be minimized by taking a range of readings to reduce the error.

Errors while measuring boiling point may be human errors while noting down the boiling temperature or instrumental or systematic error if there is a fault in the thermometer.

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Answer:

a) 72 °F= 22.22 °C

b)  213.8 °C=  416.84°F

c) 180 °C= 453.15 °K

d) 315 °K=  107.33 °F

e) 1750 °F= 1227.594 °K

f) 0 °K=  -459.67 °F

Explanation:

Para realizar el intercambio de unidades debes tener en cuenta las siguientes conversiones:

Entonces se obtiene:

a) 72 °F= \(\frac{72-32}{1.8}\)=22.22 °C

b)  213.8 °C= 213.8*1.8 + 32= 416.84°F

c) 180 °C= 180°C + 273.15= 453.15 °K

d) 315 °K= (315 -273.15)*1.8 + 32= 107.33 °F

e) 1750 °F= \(\frac{1750-32}{1.8} + 273.15\)= 1227.594 °K

f) 0 °K= (0 -273.15)*1.8 + 32= -459.67 °F

Answer:

2Ag(s) + Zn²+(aq) + 2H2O(l) → 2Ag₂O(aq) + Zn(s) + 4OH-(aq)

Explanation:

First, let's write the half-reactions for this redox reaction:

Oxidation Half-reaction: Ag(s) → Ag₂O(aq)

Reduction Half-reaction: Zn²+(aq) → Zn(s)

To balance the oxidation half-reaction, we first need to balance the number of oxygen atoms by adding H2O to the left side:

Ag(s) + H2O(l) → Ag₂O(aq)

Next, we need to balance the number of hydrogen atoms by adding OH- to the left side:

Ag(s) + H2O(l) + 2OH-(aq) → Ag₂O(aq) + 2OH-(aq)

To balance the reduction half-reaction, we first balance the zinc atoms by adding 2 electrons to the right side:

Zn²+(aq) + 2e- → Zn(s)

Now we have to balance the number of electrons between the two half-reactions. To do this, we multiply the oxidation half-reaction by 2 and the reduction half-reaction by 1 and add them together:

2Ag(s) + 2H2O(l) + 4OH-(aq) + Zn²+(aq) → 2Ag₂O(aq) + 2OH-(aq) + Zn(s)

Finally, we cancel out the OH- ions on both sides of the equation and simplify:

2Ag(s) + Zn²+(aq) + 2H2O(l) → 2Ag₂O(aq) + Zn(s) + 4OH-(aq)

Therefore, the balanced redox reaction in basic conditions is:

2Ag(s) + Zn²+(aq) + 2H2O(l) → 2Ag₂O(aq) + Zn(s) + 4OH-(aq)

The volume of the ammonia and water solution is 1.433 liters.

To calculate the volume of the solution, we first need to use the molarity and the amount of solute to calculate the total amount of solution in moles, and then use the density of the solution to convert to volume.

The molarity of a solution is defined as the number of moles of solute per liter of solution.

moles of ammonia = 34.2 g / 17.03 g/mol = 2.007 moles

Now we can use the molarity equation to solve for the volume of the solution:

Therefore, the volume of the ammonia and water solution is 1.433 liters.

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Answer:

Silver was discovered in Greece

Answer:

En 1516 Juan Díaz de Solís descubrió en Sudamérica el mar Dulce que posteriormente Sebastián Caboto denominó Río de la Plata, creyendo que allí abundaba el precioso metal, y de donde tomará el nombre la Argentina.

Explanation:

Answer:

B)

Explanation:

it has 5

The product of the reduction of ethyl 4-oxobutanoate with sodium borohydride in ethanol at room temperature for 30 minutes is Ethyl 4-hydroxybutanoate (Option A).

What is ethyl 4-oxobutanoate and what does it look like?

Ethyl 4-oxobutanoate, also known as ethyl acetoacetate, is an organic compound with the chemical formula CH₃C(O)CH₂CO₂C₂H₅. It is derived from acetoacetic acid and is an ester of acetoacetic acid.

Ethyl 4-oxobutanoate is a colorless liquid with a fruity odor.

During the reduction reaction, sodium borohydride (NaBH₄) acts as a reducing agent, donating hydride ions (H-) to the carbonyl group of the ethyl 4-oxobutanoate. This results in the conversion of the carbonyl group (C=O) to a hydroxyl group (OH) and the formation of the corresponding alcohol.

Therefore, the correct product of the reduction of ethyl 4-oxobutanoate with sodium borohydride is Ethyl 4-hydroxybutanoate (Option A).

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Multiple extractions with smaller volumes are more efficient than one extraction using the same total volume because they increase the overall effectiveness of the extraction process.

Smaller volumes allow for a greater surface area between the two phases, leading to improved partitioning of the target compound. This results in a more thorough and efficient extraction compared to a single, larger volume extraction.

Multiple extractions with small efficiency to make are preferred over one extraction using the same total volume for several reasons. Firstly, multiple extractions allow for a higher overall yield of the desired compound as the process of extraction is more thorough. Each extraction can target different components of the mixture, increasing the likelihood of extracting as much of the desired compound as possible.

Secondly, small and efficient extractions reduce the risk of contamination from impurities in the mixture. By using smaller volumes, the extraction process is more controlled and targeted, minimizing the risk of unwanted compounds being extracted along with the desired compound.

Finally, small and efficient extractions are often faster and more economical than one large extraction. By breaking the process into smaller, more manageable steps, it is possible to achieve the same overall yield with less time and fewer resources. This can be particularly important when working with limited quantities of the desired compound, or when working on a tight budget. Overall, multiple extractions with small efficient to make are a practical and effective method for extracting desired compounds from mixtures.

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         A quantum is the smallest discrete unit of a phenomenon (plural: quanta). For instance, a photon is a quantum of light, while an electron is a quantum of electricity. Quantum is a Latin word that means "quantity" or "how much?" Anything that can be measured is something that can be quantified.

             Bohr's hypothesis, often known as quantum theory, postulated that electrons move around the nucleus according to the classical principles, but with restrictions on the orbits they can take and the energy they lose as radiation when they change orbits.

        The Bohr model, also known as the Rutherford-Bohr model, was first proposed by Niels Bohr and Ernest Rutherford in 1913 and describes an atomic system with an orbiting system of electrons and a small, dense nucleus that is similar to the Solar System in structure but is attracted by electrostatic forces rather than gravity.

           A small positively charged nucleus is encircled by rotating negatively charged electrons in set orbits, according to the Bohr Atomic Model. He came to the conclusion that an electron will have more energy if it is placed far from the nucleus and less energy if it is located close to the nucleus.

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In terms of Chalk , the  reflection and assumption  is that Chalk is a soft white rock used for writing, drawing, and various industries.

Assumptions: Chalk is seen as safe for schools, yet may have impurities/allergens causing health issues in large amounts. Also believed eco-friendly due to natural sources and biodegradability.

In terms of Vinegar, the  reflection and assumption  is that is an acidic liquid used in cooking, cleaning, and medicine. It's made by fermenting ethanol with acetic acid bacteria.

Vinegar's health benefits are assumed but not fully supported by science. Vinegar is a natural cleaning agent, but may not work as well as commercial products for some stains or germs.

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Advantages:-

So hydrogen fuels are better

Answer:

The reaction of hydrogen and oxygen conveniently takes place inside a fuel cell.

Someday, it may be possible to produce hydrogen fuel using sunlight and water.

The reaction of hydrogen and oxygen doesn’t create products that negatively affect the environment.

Explanation:

PLATO

The main answer to your question is: ΔGo > 0 indicates if a reaction will proceed in reverse at any given conditions.

ΔGo (the change in Gibbs free energy) is a measure of spontaneity of a reaction.

If ΔGo is positive, it means that the reaction is not spontaneous and requires energy input to occur.

In this case, the reaction will tend to proceed in the reverse direction in order to minimize the free energy of the system.

Therefore, if ΔGo > 0, the reaction will proceed in reverse at any given conditions.

Summary: ΔGo > 0 indicates that a reaction will proceed in reverse at any given conditions.

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The mass of 0.8 cm³ of steel is 6.24 g.

mass = volume x density

Given that the density of steel is 7.8 g/cm³ and the volume of steel is 0.8 cm³, we can substitute these values into the formula and calculate the mass as follows:

mass = 0.8 cm³ x 7.8 g/cm³

mass = 6.24 g

Density is defined as the mass of a substance per unit volume. It is a physical property that can be used to identify and characterize different substances. The density of a substance is determined by dividing its mass by its volume. The unit of measurement for density is typically grams per milliliter (g/mL) or grams per cubic centimeter (g/cm³).

Density is an important property in many applications of chemistry, including material science, engineering, and environmental science. It can be used to determine the purity of a substance, to calculate the mass of a given volume of a substance, and to compare the properties of different materials. The density of a substance is affected by various factors such as temperature and pressure. For example, as the temperature of a substance increases, its density may decrease. Similarly, as the pressure on a substance increases, its density may also increase.

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Answer:2

Explanation:

Answer:

2

Explanation:

The noble-gas configurations that the elements would most likely attain in redox reactions are as follows: Lithium (Li) would achieve a helium (He) configuration, Aluminum (Al) and Potassium (K) would attain neon (Ne), Oxygen (O) would attain Ne, Phosphorus (P) would attain argon (Ar), Selenium (Se) could attain either Ar or krypton (Kr), and Strontium (Sr) would attain Kr. These configurations are determined by the tendency of each element to gain or lose electrons in order to achieve a stable electron configuration similar to that of the noble gases.

In redox reactions, elements undergo changes in their electron configurations by either gaining or losing electrons. To determine the noble-gas configuration they would most likely attain, we need to consider their valence electrons and their tendency to gain or lose electrons.

1. Lithium (Li): Lithium has one valence electron and tends to lose it to achieve a stable electron configuration. Therefore, it would most likely attain a helium (He) configuration by losing its valence electron.

2. Aluminum (Al): Aluminum has three valence electrons and tends to lose them to achieve stability. Hence, it would also attain a noble-gas configuration of neon (Ne) by losing all three valence electrons.

3. Oxygen (O): Oxygen has six valence electrons and tends to gain two electrons to achieve stability. It would attain the noble-gas configuration of neon (Ne) by gaining two electrons.

4. Phosphorus (P): Phosphorus has five valence electrons and tends to gain three electrons. Therefore, it would attain the noble-gas configuration of argon (Ar) by gaining three electrons.

5. Potassium (K): Potassium has one valence electron and tends to lose it to achieve stability. Hence, it would attain a noble-gas configuration of argon (Ar) by losing its valence electron.

6. Selenium (Se): Selenium has six valence electrons and can either gain two electrons to achieve a noble-gas configuration of krypton (Kr) or lose six electrons to attain a noble-gas configuration of argon (Ar). Both options are possible depending on the specific reaction conditions.

7. Strontium (Sr): Strontium has two valence electrons and tends to lose them to achieve stability. Therefore, it would attain a noble-gas configuration of krypton (Kr) by losing both valence electrons.

In summary, the noble-gas configurations for the elements are as follows:

Li: He

Al: Ne

O: Ne

P: Ar

K: Ar

Se: Ar or Kr

Sr: Kr

Complete Question : If the following elements were involved in redox reactions, which noble-gas configuration would they most likely attain?

Appropriate elements to their respective bins. ( He OR Ne OR Ar OR Kr ); for { Li, Al, O, P, K, Se, Sr }

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