The diameter of a circle is 6 cm. Find the circumference
to

the

nearest

tenth
to the nearest tenth.

Answer:

5(x+2)

Step-by-step explanation:

When factoring, always use the greatest common factor (GCF) method first. 5x and 10 have a GCF of 5, so this is applicable. Divide each factor by 5:

(5x)/5=x

10/5=2

Now, factor 5 out of 5x+10:

5(x+2)

Answer:

20-(4+2)

Step-by-step explanation:

So since they are eating, they are taking away, or subtracting.

Answer:

20 - (4 + 2)

Step-by-step explanation:

The original amount is 20.

The number of cookies left is the original amount minus the amount that was eaten.

Amy ate 4 cookies.

Her brother ate 2 cookies.

Amount that was eaten: 4 + 2

Amount left = original amount - amount that was eaten

amount left = 20 - (4 + 2)

Answer:

Y= -1/3 |x+3| +5

Step-by-step explanation:

An absolute value will always make a V line.

In your particular problem it wants you to reflect it over the x axis, and to do this you simply need to place a negative.

A negative in the beginning of the problem is only there to say whether you flip your line or not, and this means you don't have to worry about it any more.

What it looks like so far: Y= -

Next it wants you to compress the line vertically by 1/3

A number that causes your line to compress is always less than one

A number that stretches your line would be 1 or more

This number is always placed right next to the left of the parenthesis or absolute value.

What it looks like so far: Y= - 1/3

Now we want the line to move left 3 units.

We are now inside of the absolute value because this is where we move the line left or right. This can get a little confusing, but once you get it then you don't forget it.

Inside the line.. a -# moves right and a +# moves left.

This number should be placed inside the absolute value and to the right of the x.

What it should look like: Y= - 1/3 |x + 3|

Now they want us to move the line up by 5 points.

To the outer right side of the absolute value is where we move things up or down.

To move a number up you need to place a + sign with however many places it wants you to move to the right of the sign, but to move the line down you need to place a - sign with however many places it wants you to move to the right of the sign.

To move this up you simply need to place a +5 to the outer right side of the absolute value.

What you should end up with: Y= - 1/3 |x+3| +5

Step b is wrong. The slope is the change in y over the change in x.

Step b should be (18- 8)/( 10-6)

= 10/4

= 5/2

To convert tablespoon to grams, you need to know the density of the substance and use a conversion factor to multiply the number of tablespoons by the density in grams per tablespoon.

To convert tablespoon (tbsp) to grams (g), you need to know the density of the substance you are measuring.

For example, 1 tablespoon of water weighs approximately 15 grams. However, the weight of 1 tablespoon of a different substance, such as flour or sugar, would be different because their densities are different.

Therefore, you need to look up the density of the substance you are measuring and use a conversion factor to convert tablespoons to grams. The conversion factor will be the density of the substance measured in grams per tablespoon.

Then, to convert tablespoons to grams, multiply the number of tablespoons by the conversion factor. The result will be the weight of the substance in grams.

Here's an example of how to convert tablespoons to grams using a conversion factor:

Suppose you need to convert 3 tablespoons of sugar to grams. The density of sugar is approximately 12.5 grams per tablespoon. To convert tablespoons to grams, you would multiply the number of tablespoons by the conversion factor (density in grams per tablespoon):

3 tbsp * 12.5 g/tbsp = 37.5 grams

Therefore, 3 tablespoons of sugar is equivalent to 37.5 grams of sugar.

It's important to note that the density of a substance can vary depending on various factors such as temperature, pressure, and moisture content. Therefore, it's important to use a reliable source for the density of the substance you are measuring.

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Answer:

  ∠3 and ∠4

Step-by-step explanation:

In this diagram, angles 3 and 4 are the only pair whose sum is 90°.

In this given figure, \(\angle{3}\) and \(\angle{4}\) are the only pairs of angles that have the measure of 90°.

So,\(\angle{3}\) & \(\angle{4}\) are the pair of angles.

Answer:

1st

Step-by-step explanation: i think

After approximately 12.13 years, the revenue of this firm is going to drop to $1 million.

The value of shares t years after their floatation on the stock market, is modelled by V = 10e0.09t

The initial value of shares = V when t = 0. So, putting t = 0 in V = 10e0.09t,

we get

V = 10e0.09 × 0= 10e0 = 10 × 1 = 10 million dollars.

The values after 5 years, 10 years and 12 years, respectively are:

For t = 5, V = 10e0.09 × 5 ≈ 19.65 million dollarsFor t = 10, V = 10e0.09 × 10 ≈ 38.43 million dollarsFor t = 12, V = 10e0.09 × 12 ≈ 47.43 million dollars

The total revenue (TR) in t years' time is modelled as TR = 10e−0.19t (in million dollars)

The current revenue is the total revenue when t = 0.

So, putting t = 0 in TR = 10e−0.19t, we get

TR = 10e−0.19 × 0= 10e0= 10 million dollars

Revenue in 5 years' time is TR when t = 5.

So, putting t = 5 in TR = 10e−0.19t, we get

TR = 10e−0.19 × 5≈ 4.35 million dollars

To find when the revenue of this firm is going to drop to $1 million, we need to solve the equation TR = 1.

Substituting TR = 1 in TR = 10e−0.19t, we get1 = 10e−0.19t⟹ e−0.19t= 0.1

Taking natural logarithm on both sides, we get−0.19t = ln 0.1 = −2.303

Therefore, t = 2.303 ÷ 0.19 ≈ 12.13 years.

So, after approximately 12.13 years, the revenue of this firm is going to drop to $1 million.

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a. The interest rate earned on borrowing $650 and promising to pay back $780 at the end of 1 year is 20%.

b. The interest rate earned on lending $650 and having the borrower promise to pay back $780 at the end of 1 year is 20%.

c. The interest rate earned on borrowing $55,000 and promising to pay back $73,706 at the end of 6 years is approximately 3.5%.

d. The interest rate earned on borrowing $18,000 and promising to make payments of $4,390.00 at the end of each year for 5 years is approximately 7.1%.

To calculate the interest rate earned in each scenario, we use the simple interest formula:

Interest rate = (interest / principal) x 100

For scenario a, the interest earned is $780 - $650 = $130. The interest rate is then (130 / 650) x 100 = 20%.

For scenario b, the interest earned is $780 - $650 = $130. The interest rate is then (130 / 650) x 100 = 20%.

For scenario c, we can use the formula for compound interest:

A = P(1 + r/n)^(nt)

Where A is the amount paid back, P is the principal, r is the annual interest rate, n is the number of times interest is compounded per year, and t is the number of years. Solving for r, we get:

r = n[(A/P)^(1/nt) - 1]

Plugging in the numbers, we get r = 2[(73706/55000)^(1/(6*2)) - 1] x 100, which simplifies to approximately 3.5%.

For scenario d, we can use the same formula as in scenario c, but with a slightly different calculation. The total payments made over the 5 years is $4,390 x 5 = $21,950. The interest earned is then $21,950 - $18,000 = $3,950. Plugging in the numbers, we get r = 1[(3950/18000)^(1/(5*1)) - 1] x 100, which simplifies to approximately 7.1%.

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Answer:

B and E

Step-by-step explanation:

trust me its correct

The focus of the parabola y=5x²+5 would be (0 , 5.05)

Since All points in a plane that are equally spaced out from a given point and a given line make up a parabola. The line is the directrix, and the point is the parabola's focus.

The stanard form of the parabola is y = 1/4p ( x - h)²+ k

Where, (h,k) is the vertex of parabola

(h , k + p) is the focus of the parabola

Given equation to the standard form;

y=5x²+5

y = 5 (x - 0)² + 5

Therefore, we have h = 0

1/4p = 5

p = 1/20

k = 5

Now, the focus = (h , k + p)

= (0 , 5 + 1/20)

(0 , 5.05)

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Answer:

Step-by-step explanation:

Sorry I can't explain how it is done. It is very difficult to explain on paper.

Answer:

Below in bold.

Step-by-step explanation:

Slope = difference in y values / difference is x values

= (1 - (-3)) / (0 - (-1)

= 4 / 1

= 4.

The y-intercept is the y value when x = 0, so it is

= 1.

So, the equation is

y = 4x + 1.

Answer:

porportional

Step-by-step explanation:

Answer:

x = 2

Step-by-step explanation:

8x + 7x + 5 + 4 = 39

15x + 9 = 39

15x = 30

x = 2

Brainly plz :))

a. The probability of 3 accidents is P(X=3) = 0.15.

b. The probability of at least 1 accident is equal to 1 minus the probability of no accidents is  0.90.

c. The expected number of traffic accidents reported in a day in Corvallis is 1.95.

d. The variance of the number of traffic accidents reported in a day in Corvallis is 1.6525.

e. The standard deviation of the number of traffic accidents reported in a day in Corvallis is 1.284.

a. The probability of 3 accidents is P(X=3) = 0.15.

b. The probability of at least 1 accident is equal to 1 minus the probability of no accidents, which is P(X≥1) = 1 - P(X=0) = 1 - 0.10 = 0.90.

c. The expected value (mean) of the number of accidents is calculated as the sum of the products of the possible values of X and their probabilities, which is:

E(X) = 0(0.10) + 1(0.20) + 2(0.45) + 3(0.15) + 4(0.05) + 5(0.05) = 1.95.

Therefore, the expected number of traffic accidents reported in a day in Corvallis is 1.95.

d. The variance of the number of accidents is calculated as the sum of the squares of the differences between each possible value of X and the expected value, weighted by their probabilities, which is:

Var(X) = [ (0-1.95)²(0.10) + (1-1.95)²(0.20) + (2-1.95)²(0.45) + (3-1.95)²(0.15) + (4-1.95)²(0.05) + (5-1.95)²(0.05) ]

= 1.6525.

Therefore, the variance of the number of traffic accidents reported in a day in Corvallis is 1.6525.

e. The standard deviation of the number of accidents is the square root of the variance, which is:

SD(X) = √(1.6525) = 1.284.

Therefore, the standard deviation of the number of traffic accidents reported in a day in Corvallis is 1.284.

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After making equal monthly deposits of $453 for 11 years into a savings account earning 7.29 percent interest compounded monthly, Marc will have approximately $89,909.92 in his account.

To calculate the total amount of money in Marc's account at the end of 11 years, we can use the formula for compound interest:

A = P(1 + r/n)^(nt)

Where:

A is the final amount in the account,

P is the monthly deposit amount,

r is the annual interest rate (expressed as a decimal),

n is the number of times the interest is compounded per year, and

t is the number of years.

In this case, Marc makes monthly deposits of $453, the annual interest rate is 7.29 percent (0.0729 as a decimal), and the interest is compounded monthly (n = 12). The number of years is 11.

Using the formula, we can calculate the final amount:

A = 453(1 + 0.0729/12)^(12*11)

A ≈ 89,909.92

Therefore, at the end of 11 years, Marc will have approximately $89,909.92 in his savings account.

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Answer:

(3×6)÷5

Step-by-step explanation:

We are given the following expression:

(3/5)*6

The 6 can also be written as a fraction(6/1).

So we have a multiplication of fractions, is which we multiply the numerators and denominators.

So

(3*6)/5

The fraction sign means division

So the answer is:

(3×6)÷5

1. False

2. False

3. True

4. True

5. True

1. CLD does not clear the zero flag (ZF). It is used to clear the direction flag (DF), which determines the direction of string operations.

2. REPNE (or REPNZ) will repeat as long as the zero flag (ZF) is not set. It checks the value of ZF before each iteration and continues until ZF becomes 0.

3. When repeating, the counter is decremented before the string instruction is executed. The counter is usually stored in the CX register and decremented automatically by the string instruction.

4. When repeating CMPS (compare strings), REPNZ (or REPNE) is used to continue repeating while the characters are not equal. It checks the ZF after each iteration and continues until ZF becomes 1.

5. STOS (store string) will initialize an array with whatever value is in the appropriate accumulator register. It stores the value from the accumulator into the destination memory location pointed to by the destination index register.

# Question: Assembly programming and computer architecture for software engineers answers
True/False 1. CLD clears the zero flag (ZF). 2. REPNE will repeat as long as ZF is set. 3. When repeating, the counter is decremented before the string instruction is executed. 4. When repeating CMPS, use REPNZ to continue repeating while the characters are equal. 5. STOS will initialize an array with whatever value is in the appropriate accumulator register.

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On the interval [0, 2π], the minimum values of f(x) = 12cos^2(x) - 1 are -1, and the maximum values are 11.

To find the minimum and maximum values of the function f(x) = 12cos^2(x) - 1 on the interval [0, 2π], we need to determine the critical points and endpoints within that interval.

First, let's differentiate the function f(x) with respect to x to find the critical points. The derivative of f(x) is f'(x) = -24cos(x)sin(x).

Next, we set f'(x) equal to zero and solve for x:

-24cos(x)sin(x) = 0

This equation is satisfied when cos(x) = 0 or sin(x) = 0.

For cos(x) = 0, we have x = π/2 and x = 3π/2 as critical points.

For sin(x) = 0, we have x = 0 and x = π as critical points.

Now, we evaluate the function f(x) at these critical points and the endpoints of the interval [0, 2π]:

f(0) = 12cos^2(0) - 1 = 11

f(π/2) = 12cos^2(π/2) - 1 = -1

f(π) = 12cos^2(π) - 1 = 11

f(3π/2) = 12cos^2(3π/2) - 1 = -1

f(2π) = 12cos^2(2π) - 1 = 11

From the evaluations, we see that the minimum values of f(x) are -1, occurring at x = π/2 and x = 3π/2, while the maximum values are 11, occurring at x = 0, x = π, and x = 2π.

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The answer is quite simply x=4

Answer:

Step-by-step explanation:

To evaluate the given expression, we need to substitute the given values for x, y, and z. The expression becomes:

yz + x²

Substituting the given values, we get:

(6.1 * 0.2) + (3.2^2)

This simplifies to:

1.22 + 10.24

Therefore, the value of the expression is approximately 11.46.

11.46

gimme brainlyest gang

The equation y = (13 / 4) · x - 19 / 2 represents the perpendicular bisector of the line segment.

In this problem we need to determine the equation of the line perpendicular to a line segment whose endpoints are known. The equation of the line is represented by a first grade polynomial of the form:

y = m · x + b

Where:

And the relationship between the slopes of two perpendicular lines:

m · m' = - 1

Where:

And the slope of the original line can be found by the secant line formula:

m = Δy / Δx

And the midpoint of a line segment between two endpoints is defined below, necessary for the location of the bisector:

M(x, y) = 0.5 · A(x, y) + B(x, y)

Where:

First, find the slope of the line segment by secant line formula:

m = [- 1 - (- 5)] / (- 5 - 9)

m = - 4 / 13

Second, find the slope of the perpendicular bisector by the slope relationship between two perpendicular lines:

m' = - 1 / m

m' = - 1 / (- 4 / 13)

m' = 13 / 4

Third, determine the midpoint of the line segment by the midpoint formula:

M(x, y) = 0.5 · (9, - 5) + 0.5 · (- 5, - 1)

M(x, y) = (4.5, - 2.5) + (- 2.5, - 0.5)

M(x, y) = (2, - 3)

Fourth, find the intercept of the perpendicular bisector by means of the equation of the line:

b = y - m' · x

b = - 3 - (13 / 4) · 2

b = - 3 - 26 / 4

b = - 3 - 13 / 2

b = - 19 / 2

The equation for the perpendicular bisector is y = (13 / 4) · x - 19 / 2.

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Answer:

Step-by-step explanation:

The roots of equation A are  2 and 0.25.

The roots of equation B are 3.14 and -0.64.

To solve for the roots of a quadratic equation using the Quadratic Formula, we can use the formula:

x = (-b ± √(b² - 4ac)) / (2a)

Where a, b, and c are the coefficients of the equation.

For equation A, a = 4, b = -9, and c = 2. Plugging these values into the Quadratic Formula, we get:

x = (-(-9) ± √((-9)² - 4(4)(2))) / (2(4))
x = (9 ± √(81 - 32)) / 8
x = (9 ± √49) / 8
x = (9 ± 7) / 8

This gives us two possible values for x:

x = (9 + 7) / 8 = 2
x = (9 - 7) / 8 = 0.25

Therefore, the roots of equation A are 2 and 0.25.

For equation B, a = 2, b = -7, and c = -1. Plugging these values into the Quadratic Formula, we get:

x = (-(-7) ± √((-7)² - 4(2)(-1))) / (2(2))
x = (7 ± √(49 + 8)) / 4
x = (7 ± √57) / 4

This gives us two possible values for x:

x = (7 + √57) / 4 ≈ 3.14
x = (7 - √57) / 4 ≈ -0.64

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Using the spring's force we know that 48.4 lb-ft work is done in stretching the spring from its natural length to 1.1 feet beyond its natural length.

So, F is the 4 lb force required to maintain the spring's stretched position.

The labor of extending a spring is denoted by the formula:

So, calculate:

Therefore, 48.4 lb-ft work is done in stretching the spring from its natural length to 1.1 feet beyond its natural length.

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According to the information, the numbers are classified as follows: Greater than 8.2 x 104 = None; between 8.2 x 10⁴ and 8.2 x 10⁻⁶ : 2.1 x 10⁻⁴, 9.2 x 10⁻⁴, 3.4 x 10⁻⁵, 2.1 x 10⁻³, 8.3 x 10⁻⁵, 7.2 x 10⁻⁵; and less than 8.2 x 10⁻⁵: 2.8 x 10⁻⁷.

To find the classification of numbers we must know how scientific notation works and know how to classify these numbers. According to its scientific notation, if we want to classify numbers greater than 8.2 x 10⁴ we must take the following into account:

All numbers with a power greater than 10⁴ would be greater than 8.2. Therefore, none of the options would be greater than this number.

In the second case, to find the numbers that are between 8.2 x 10⁴ and 8.2 x 10⁻⁶ we must look at the same element, that is, the numbers that have a power less than 10⁴ and greater than 10⁶ would be in the range of this exercise. So the numbers in this range would be:

In the third case, to identify the numbers that are less than 8.2 x 10⁻⁵ we must take into account the same element. If power is less than 10⁻⁵, they would classify in this interval. So the values that classify are:

Note: This question is incomplete because there is some information missing. Here is the complete information:

Greater than 8.2 x 104

Between 8.2 x 104

and 8.2 x 10-6

Less than 8.2 x 10-5

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Answer:

  (c)  y -2 = 6/5(x -1)

Step-by-step explanation:

The equations are all in point-slope form with a slope of 6/5. The points used are (-1, -2), (-2, -1), and (1, 2). It seems point (1, 2) best matches a point on the graphed line. Choice C is the best. (In the attached graph, choice C is the red line.)

_____

Additional comment

The point-slope form of the equation for a line is ...

  y -k = m(x -h) . . . . . . . line with slope m through point (h, k)

__

The equation might be easier to see if the point chosen were one at a grid intersection, such as (-4, -4) or (6, 8).

The exact solutions of the given equation on the given interval are x = π, 2π/3 and 4π/3, for the given equation 2 cos²x + 3 cos x: {-1, 0 ≤ x ≤ 3}

We need to find all the exact solutions for the equation on the given interval (0 ≤ x ≤ 3).

The given equation is a quadratic equation in cos x.

Let's substitute cos x as y and then solve for y.

2 cos²x + 3 cos x + 1 = 0

Multiplying both sides by 2:

4 cos²x + 6 cos x + 2 = 0

Dividing both sides by 2:

2 cos²x + 3 cos x + 1 = 0

Now ,let's substitute y = cos x

2 y² + 3 y + 1 = 0

Factorizing the quadratic equation:

(2 y + 1)(y + 1) = 0

Therefore, the exact solutions are:

cos x = y = -1 or y = -1/2

When y = -1, cos x = -1.

This occurs at x = π

When y = -1/2, cos x = -1/2.

This occurs at x = 2π/3 and x = 4π/3.

Thus, the exact solutions of the given equation on the given interval are x = π, 2π/3 and 4π/3.

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