The acceleration of the tanker aircraft will remain the same, since the thrust of the engine is kept constant.
option C is the correct answer.
What is the thrust of an engine?
Thrust is the power or force that is required to make a vehicle or aircraft move in a particular direction.
According to Newton's second law of motion, the force applied on an object is directly proportional to the product of mass and acceleration of the object.
Mathematically, Newton's second law of motion is given as;
F = ma
where;
F is the force applied on the objectm is the mass of the object'a is the acceleration of the objecta = F/m
When the thrust of the engine is kept constant, then the force applied by the engine is constant.
a = F1/m = F2/m
F1 = F2, since the thrust of the engine kept constant.
Hence, the acceleration of the tanker aircraft will be constant.
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The concrete sections of a certain superhighway are designed to have a length of 25.0m . The sections are poured and cured at 10.0°C . What minimum spacing should the engineer leave between the sections to eliminate buckling if the concrete is to reach a temperature of 50.0°C ?
The minimum spacing the engineer should leave between the sections to eliminate buckling is 0.011 m.
To calculate the minimum space the engineer must leave in other to eliminate bulking, we use the coefficient of linear expansivity of steel.
What is coefficient of linear expansivity?This can be defined as the increase in length, per unit length, per degree rise in temperature.
To calculate the minimum space, we use the fomula below
Formula:
α = ΔL/L₁(t₂-t₁)........... Equation 1
Make L₂ the subject of the equation
ΔL = αL₁(t₂-t₁)........... Equation 2From the question,
Given:
L₁ = 25 mt₁ = 10°Ct₂ = 50°Cα = 11×10⁻⁶ /K ( Cofficient of Linear expansion of steel)Substitute these values into equation 2
ΔL = [11×10⁻⁶×25×(50-10)]ΔL = 0.011 mHence, the minimum spacing the engineer should leave between the sections to eliminate buckling is 0.011 m.
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suppose a telescope has two eyepieces: eyepiece a with focal length 10 mm and b with 20 mm. suppose the magnifying power with eyepiece a is 200. what is the magnifying power with eyepiece b? hint: it is an inverse (opposite) relationship between power and focal length.
With eyepiece b, the magnification is 100.
What distinguishes a telescope's 10 mm and 20 mm lenses?Simply dividing the focal length of the telescope by the focal length of the eyepiece yields the magnification. This implies that a higher magnification is provided by a smaller number on an eyepiece. The magnification offered by a 10mm eyepiece would be twice that of a 20mm eyepiece.
What is magnifying and how is it calculated?The ratio of the image's height to the object's height is represented by the formula for magnification. Additionally, the letter "m" stands for the object's magnification. Additionally, its formula is Magnification (m) is equal to h/h. Here, h is the object's height and h' is its the item's height.
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A hypothetical hard-sphere gas that has a collision frequency per unit volume, Z1 of 1.09 GHz/L at a Temperature of 228.8 K. The gas is heated at isochorically (constant volume) to a Temperature of 478.4 K. What is the new collision frequency, in GHz/L wi this new parameters?
The new collision frequency of the hypothetical hard-sphere gas, after being heated isochorically from 228.8 K to 478.4 K, is X GHz/L.
The collision frequency of a gas is related to its temperature and is a measure of how frequently gas particles collide with each other. In this scenario, the initial collision frequency per unit volume (Z₁) is given as 1.09 GHz/L at a temperature of 228.8 K. To determine the new collision frequency after heating the gas to 478.4 K, we can use the relationship between collision frequency and temperature.
The collision frequency (Z₂) is directly proportional to the square root of the absolute temperature. Therefore, we can calculate the ratio of the square roots of the temperatures (T₂/T₁) to find the change in collision frequency. By multiplying this ratio with the initial collision frequency (Z₁), we can determine the new collision frequency (Z₂).
Plugging in the given temperatures and the initial collision frequency into the equation and solving for Z₂ will give us the desired new collision frequency in GHz/L.
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A 40.0-kilogram child exerts a 100.-newton force on a 50.0-kilogram object. The magnitude of the force that the object exerts on the child is
answer choices
- 0.0 N
- 80.0 N
- 100. N
- 125 N
The magnitude of the force that the object exerts on the child is 100 N.
option C is the correct answer.
What is Newton's third law of motion?
Newton's third law of motion states that for every action there is an equal and opposite reaction. In other words, action and reaction are equal and opposite.
Mathematically, Newton's third is given as;
Fa = Fb
where;
Fa is the applied forceFb is the reaction experienced by the objectIf the child exerts 100 N force on the object, the reaction of the object or the upward force exerted on the child by the object is 100 N in opposite direction.
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How to test the effect of the water throughout the experiment (independent variable) on the cleanliness of water (dependent variable).
Answer Questions below
Answer:
When several resistors are connected in series, the total resistance equals the sum of the individual resistors. In series combination, the current is same through each resistor.
1) V= 60 volt
Total resistance R = R₁ + R₂
= 20 + 10
= 30 Ω
2) Ohms law states that,
\(\sf I =\dfrac{V}{R}\\\\\\I = \dfrac{60}{30}\\\\I = 2 \ A\)
3) Voltage around 10 Ω resistor,
V₂ = I R₂
= 2 * 10
= 20 volt
___________________________________________________
4) Total current = 1 A
5) Total voltage = 8 volt
6) Voltage around R₁ is V₁
R₁ = 2 Ω ; I = 1 A
V₁ = IR₁
= 1 * 2
= 2 volt
7) Resistance 2:
Total resistance = R
Total voltage = V = 8 volt
Total current = I = 1 A
\(\sf R = \dfrac{V}{I}\\\\\\ R = \dfrac{8}{1}\\\\\)
R = 8 Ω
R₁ + R₂ = 8 Ω
2 + R₂ = 8
R₂ = 8 - 2
R₂ = 6 Ω
8)Voltage around R₂:
\(\sf V_2 = IR_2\\\\V_2 = 1*6\\\\\)
V₂ = 6 volt
9) Total R = 8 Ω
_________________________________________________
10) Total V = 12 volt
11) Total R = 8 + 8
= 16 Ω
12) Total current I,
\(\sf I = \dfrac{V}{R}\\\\I = \dfrac{12}{16}\\\\I = 0.75 \ A\)
13) Voltage at each resistor:
V₁ = I*R₁
= 0.75 * 8
= 6 volt
V₂ = I*R₂
= 0.75 * 8
= 6 volt
_______________________________________________________
14) Total R = 40 + 20
= 60 Ω
15) To find V₁, first find total voltage.
I = 2 A ; R = 60 Ω
V = IR
= 2 * 60
= 120 V
V₁ + V₂ =V
V₁ + 80 = 120
V₁ = 120 - 80
V₁ = 40 volt
How much speed of light in m/s?
Answer:
below
Explanation:
Most folks use 3 x 10^8 m/s in calculations , but more accurately it is
299 792 458 m / s
PLZ HELP ASAP THX
If scientists is designing a device to create high energy electromagnetic waves which type of wave would the device most likely create?
Microwaves
Infrared waves
Ultraviolet waves
Gamma ray waves
Answer:
Gamma ray waves
Explanation:
Gamma ray waves carry the most energy electromagnetic waves.
Hope this helps, thank you !!
Convert the following into radians 90°, 30°, 45°, 180°
Answer:
90 degress -> radians= π/2
30 degress -> radians= π/6
45 degrees -> radians= π/4
180 degress -> radians= π
Explanation:
To convert degrees to radians, multiply the degree by π/180 and simplify.
a vector has an x component of -309m and a y component of 187m find the direction of the vector
The direction of the vector is approximately 330.06 degrees.
To find the direction of a vector given its components, we can use trigonometry. The direction of a vector is typically represented by an angle measured counterclockwise from the positive x-axis.
Let's denote the x-component as x = -309 m and the y-component as y = 187 m. To find the direction, we can calculate the tangent of the angle using the formula:
θ = arctan(y/x)
Substituting the given values, we have:
θ = arctan(187/-309)
Using a scientific calculator or trigonometric tables, we find that the arctan of this ratio is approximately -30.06 degrees.
Since the direction is measured counterclockwise from the positive x-axis, we can express the direction as 360 degrees minus the calculated angle. In this case, the direction is approximately 330.06 degrees.
Therefore, the direction of the vector is approximately 330.06 degrees.
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2. A squirrel runs 15 m to the north and finds an acorn. The squirrel then turns back to the south
and runs 8 m, at that point he decides to change direction and runs 24 m to the east to bury his
acorn.
Answer:
24 m to the right/ to the east
A car starts to move from point A to B such that its displacement becomes 150m. This
motion was provided by a driving force of 66MN, calculate the Kinetic energy of the
body at B.??
Answer:
sorry I cannot give the answer I know only little bit about it
To calculate the kinetic energy of the car at point B, we first need to determine its velocity at that point. We can use the work-energy principle to relate the work done by the driving force to the change in kinetic energy of the car:
Work done by driving force = Change in kinetic energy
The work done by the driving force is equal to the product of the force and the displacement:
Work done = Force x Displacement = 66 MN x 150 m = 9.9 GJ
The change in kinetic energy is equal to the final kinetic energy minus the initial kinetic energy. Assuming the car starts from rest at point A, its initial kinetic energy is zero. Therefore, the final kinetic energy at point B is equal to the work done by the driving force:
Final kinetic energy = Work done = 9.9 GJ
Note that we converted the force to MN (meganewtons) and the energy to GJ (gigajoules) to match the SI unit system commonly used in physics calculations.
The following data was taken during a student's experiment with an object moving at a relatively constant velocity. Use the data to create a position-time graph (on the accompanying graph paper). Be sure to include a best-fit line. After the graph is completed, use your best-fit line to calculate the average speed of the object. Show speed calculations below.
Based on the best-fit line, the average speed of the object is equal to 6.15 m/s.
What is a scatter plot?A scatter plot is also referred to as scatter chart, scatter diagram or scattergram and it can be defined as a type of graph which is used for the graphical representation of the values of two (2) variables, with the resulting points showing any association (correlation) between the data set.
What is a position vs time graph?A position vs time graph can be defined as a type of graph that is used to graphically represent the distance traveled (covered) by an object from its starting position with respect to the time when it is started moving.
By critically observing the graph (see attachment) which models the data in the given table, we can infer and logically deduce that the linear function from the best-fit line is given by:
y = 6.35x + 0.86
What is a slope?In Mathematics, the slope of a straight line on a position vs time graph simply refers to the ratio of displacement to time interval and it represents the average speed.
For the average speed, we have:
Average speed, ΔV = Δd/Δt
Average speed, ΔV = (40 - 8)/(6.2 - 1.0)
Average speed, ΔV = 32/5.2
Average speed, ΔV = 6.15 m/s.
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The time period of a wave T is the the time taken to produce one complete wave. If the frequency of a wave is 2 Hz, what is it’s time period?
Answer:
0.5s
Explanation:
if the frequency is 2Hz that means it makes 2 complet cycles in one second. The time period for one cycle would be 0.5s
10. What is the acceleration due to gravity at a location
where a 15.0-kilogram mass weighs 45.0 newtons?
1) 675 m/s2
2) 9.81 m/s2
3) 3.00 m/s2
4) 0.333 m/s2
does an object in motion stay in motion
for bone density scores that are normally distributed with a mean of 0 and a standard deviation find the percentage of scores
Approximately 50% of scores are above 0 and 50% are below 0 in a normally distributed variable with a mean of 0 and standard deviation of 1.
For a normally distributed variable with a mean of 0 and standard deviation of 1, approximately 68% of scores fall within 1 standard deviation of the mean, which is between -1 and 1. This means that approximately 34% of scores are above 1 and 34% are below -1. Similarly, approximately 95% of scores fall within 2 standard deviations of the mean, which is between -2 and 2. This means that approximately 2.5% of scores are above 2 and 2.5% are below -2. Finally, approximately 99.7% of scores fall within 3 standard deviations of the mean, which is between -3 and 3. This means that approximately 0.15% of scores are above 3 and 0.15% are below -3. Since the mean is 0, we know that approximately 50% of scores are above 0 and 50% are below 0.
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What type of protein secondary structure does the structure shown here (Fiqure 1) represent? O a-helix O a-sheet
O B- helix O B-sheet O y turn
The correct option is C. β-sheet type of protein secondary structure does the structure shown here (Figure 1) represent.
A shape is an arrangement and organization of interrelated elements in a fabric item or gadget, or the item or system so prepared. material systems encompass guy-made items consisting of homes and machines and natural items which include organic organisms, minerals, and chemical compounds. abstract structures consist of statistics structures in pc science and musical shape.
Sorts of the shape include a hierarchy (a cascade of one-to-many relationships), a network providing many-to-many links, or a lattice presenting connections among additives that can be pals in space.
Built structures are widely divided by using their various design approaches and requirements, into classes together with constructing systems, architectural structures, civil engineering structures, and mechanical structures.
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Complete Question:
What type of protein secondary structure does the structure is shown here (Figure 1) represent?
A). α-helix
B). α-sheet
C). β- helix
D). β-sheet
E). γ turn
A form of energy is stored in the bonds between atoms. What is the name for this stored energy?
A. kenetic energy
B. chemical energy
C. electrical energy
D. electromagnetic energy
Answer:
chemical energy
Explanation:
A form of energy is stored in the bonds between atoms is known as chemical energy.
Answer:
Chemical energy
Explanation:
Chemical energy because
it's energy stored in the bonds of
the atoms & molecules.
Why is communication an important part of the scientific process
Answer:
Communication is a vital component to the scientific process. It helps the scientist, if he/she was making an invention, tell people or get advice about the project, which couldn't be done without communication. Scientists need to communicate to learn, get advice, and collaborate with one another.
what is the meaning of life?
Answer:
Life means to exist' in general
PLEASE HELP: A planet has an average distance to the sun of 3.36AU. In two or more complete sentances, explain how to calculate the orbital peroid of the planet and calculate it.
Answer:
Use the AU formula
Explanation:
1 astronomical unit = 149597871 kilometer
identify the limiting reactant and determine the mass of the excess reactant remaining when 7.00 g of chlorine gas reacts with 5.00 g of potassium to form potassium chloride.
The amount of excess potassium is: 0.070 mol K. The negative value indicates that there is no excess potassium remaining. All of the potassium reacted to form potassium chloride.
To identify the limiting reactant, we need to compare the mole ratio of the two reactants in the balanced chemical equation. The balanced equation for the reaction is:
2K + Cl2 → 2KCl
From the equation, we see that 2 moles of potassium react with 1 mole of chlorine gas to form 2 moles of potassium chloride. Therefore, we need to convert the given masses of each reactant into moles.
Moles of chlorine gas = 7.00 g / 70.9 g/mol = 0.099 mol
Moles of potassium = 5.00 g / 39.1 g/mol = 0.128 mol
Since the mole ratio of K to Cl2 is 2:1, we can see that chlorine gas is the limiting reactant. This means that all of the chlorine gas will be consumed, leaving some excess potassium.
To determine the mass of the excess potassium, we need to calculate the amount of potassium that reacted. Using the mole ratio from the balanced equation, we can see that for every mole of Cl2 consumed, 2 moles of K are consumed. Therefore, the amount of potassium that reacted is:
0.099 mol Cl2 x (2 mol K / 1 mol Cl2) = 0.198 mol K
The amount of excess potassium is:
0.128 mol K - 0.198 mol K = -0.070 mol K
The negative value indicates that there is no excess potassium remaining. All of the potassium reacted to form potassium chloride.
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Susie rolls a bowling ball down the alley and knocks over most of the pins. Explain why fewer pins were knocked over when her little brother rolled a basketball, at the same velocity, down the alley.
Answer:
The force used
Explanation:
This has to be because of the force used. Both Susie and her younger brother might have hit the ball with the same velocity, but they surely couldn't have hit it with the same force. The force with which Susie hurts it is heavier than that with which her younger brother hits it, and as such, Susie gets to fall down more pins than her brother will be able to. The ball has to have a lot of force in it for it to be able to knock off all the pins there. So basically, the more the force, the higher it's chances of hitting all the pins
a 220 mwmw laser pulse is focused with a lens to a diameter of 1.7 μmμm . part a part complete what is the laser beam's electric field amplitude at the focal point?
The laser beam's electric field amplitude at the focal point is 5.16 x 10^8 V/m.
To find the electric field amplitude at the focal point, we can use the formula:
E = √(2P/(pi * r^2 * c * n))
where:
P = power of the laser pulse = 220 mW = 220 x 10^-3 W
r = radius of the focused beam = 0.85 μm = 0.85 x 10^-6 m (since diameter is given as 1.7 μm)
c = speed of light in vacuum = 3 x 10^8 m/s
n = refractive index of the medium (assuming air) = 1
Plugging in these values, we get:
E = √(2(220 x 10^-3)/(pi*(0.85 x 10^-6)^2*3 x 10^8*1)) = 5.16 x 10^8 V/m
Therefore, the laser beam's electric field amplitude at the focal point is 5.16 x 10^8 V/m.
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1. If a cart with a mass of 5 kg is accelerated at a rate of 12 m/s/s, then what is theNUMERICAL value for the force?
*The mass of the cart is
m=5 kg
*The acceleration is
\(undefined\)
9. What voltage is applied to a 20 ohm fixed resistor if the current through the resistor is 1.5 amps?
Question :-
What Voltage is applied to a 20 Ohm fixed Resistor, if the Current through the Resistor is 1.5 Ampere ?Answer :-
Voltage of the Device is 30 Volt's .Explanation :-
As per the provided information in the given question, The Resistance is given as 20 Ohm's . Current is given as 1.5 Amperes . And, we have been asked to calculate the Voltage .
For calculating the Voltage , we will use the Formula :-
\( \bigstar \: \: \: \boxed {\sf { \: Voltage \: = \: Current \: \times \: Resistance \: }} \)
Therefore , by Substituting the given values in the above Formula :-
\( \Longrightarrow \: \: \: \sf { Voltage \: = \: Current \: \times \: Resistance } \)
\( \Longrightarrow \: \: \: \sf { Voltage \: = \: 1.5 \: \times \: 20 } \)
\( \Longrightarrow \: \: \: \bf { Voltage \: = \: 30 } \)
Hence :-
Voltage of Device = 30 Volt's .\( \underline {\rule {180pt}{4pt}} \)
Additional Information :-
\(\Longrightarrow \: \: \: \sf {Voltage \: = \: Current \: \times \: Resistance} \)
\( \Longrightarrow \: \: \: \sf {Current \: = \: \dfrac {Voltage}{Resistance}} \)
\( \Longrightarrow \: \: \: \sf {Resistance \: = \: \dfrac {Voltage}{Current} } \)
Answer:
30 VoltsExplanation:
Given:
Resistance = 20 ohmCurrent = 1.5 AmperesTo Find:
VoltageSolution:
Using formula:
Voltage = Current × ResistanceBy Substituting the required values,
⇢ Voltage = 1.5 × 20
⇢ Voltage = 30 Volts.
Hence,
The required Voltage is 30 voltsWhen an ambulance drives towards you, the pitch of the siren is higher. After itdrives past, the pitch of the siren is lower.The reason it is lower is that the frequency of the wavelengthA. increasesB. decreasesC. Stays the same
Doppler's effect:
The Doppler effect states that the frequency of sound increases as it source approaches you and it decreases as the source turns away from you.
When the ambulance drives past you, the pitch of the siren is lower. This is due to the fact that the frequency of the wavelength decreases.
A higher pitch means frequency increases and a lower pitch means frequency decreases.
Therefore, the correct answer is option B. decreases
A rocket of mass m is launched straight up with a thrust Fthrust.
A. Find an expression for the rocket's speed at height h if air resistance is neglected.
B. The motor of a 360 g model rocket generates 10 N thrust. If air resistance can be neglected, what will be the rocket's speed as it reaches a height of 87 meters?
The rocket's speed as it reaches a height of 87 meters, neglecting air resistance, will be approximately 93.7 m/s.
A. The expression for the rocket's speed at height h, neglecting air resistance, is v = sqrt((2 * Fthrust * h) / m), where v is the speed, Fthrust is the thrust, h is the height, and m is the mass of the rocket.
B. To calculate the rocket's speed as it reaches a height of 87 meters, we substitute the given values into the expression: v = sqrt((2 * Fthrust * h) / m). Considering the motor generates 10 N of thrust (Fthrust = 10 N), and the mass of the rocket is 360 g (m = 0.36 kg), and the height is 87 meters (h = 87 m), we can calculate the speed:
v = sqrt((2 * 10 N * 87 m) / 0.36 kg) ≈ 93.7 m/s
A. When neglecting air resistance, the only force acting on the rocket is the thrust force provided by the engine. Therefore, using the principles of work and energy, we can derive the expression for the rocket's speed at height h. The work done on the rocket is given by the change in kinetic energy, which is equal to (1/2) * m * v^2, where m is the mass of the rocket and v is its speed. The work done is also equal to the force applied (thrust) multiplied by the distance traveled (height h). Equating these two expressions, we have:
(1/2) * m * v^2 = Fthrust * h
Simplifying and solving for v, we get:
v = sqrt((2 * Fthrust * h) / m)
B. Given that the motor generates 10 N of thrust (Fthrust = 10 N), the mass of the rocket is 360 g (m = 0.36 kg), and the height is 87 meters (h = 87 m), we substitute these values into the expression:
v = sqrt((2 * 10 N * 87 m) / 0.36 kg) ≈ 93.7 m/s
The rocket's speed as it reaches a height of 87 meters, neglecting air resistance, will be approximately 93.7 m/s.
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La punta de la aguja de una máquina de coser se mueve en MAS, sobre el eje x con una frecuencia de 2,5 [Hz]. En t = 0, sus componentes de posición y velocidad son, respectivamente, +1,1 [cm] y -15 [cm/s]. A) Calcule la componente de aceleración de la aguja en t = 0. B) Escriba ecuaciones para las componentes de posición, velocidad y aceleración de la punta en función del tiempo. (15 puntos)
Answer:
A) El componente de aceleración de la aguja en \(t = 0\,s\) es -236,206 centímetros por segundo al cuadrado.
B) Las ecuaciones para la componentes de posición, velocidad y aceleración de la punta en función del tiempo son, respectivamente:
\(x(t) = 1,458\cdot \cos (15,708\cdot t +0,228\pi)\)
\(v(t) = -22,902\cdot \sin (15,708\cdot t + 0,228\pi)\)
\(a(t) = -359,749\cdot \sin (15,708\cdot t + 0,228\pi)\)
Explanation:
El movimiento armónico simple es un movimiento periódico de carácter sinusoidal que está descrito por la siguiente ecuación cinemática:
\(x(t) = A\cdot \cos (\omega\cdot t + \phi )\) (1)
Donde:
\(x(t)\) - Posición actual de la aguja con respecto a la posición de equilibrio, en centímetros.
\(A\) - Amplitud, en centímetros.
\(\omega\) - Frecuencia angular, en radianes por segundo.
\(\phi\) - Ángulo de fase, en radianes.
Por Cálculo Diferencial, obtenemos las fórmulas cinemáticas para la velocidad (\(v(t)\)), en metros por segundo, y la aceleración (\(a(t)\)), en metros por segundo cuadrado, de la aguja:
\(v(t) = -\omega\cdot A \cdot \sin (\omega\cdot t + \phi)\) (2)
\(a(t) = -\omega^{2}\cdot A \cdot \cos (\omega\cdot t + \phi)\) (3)
Por otra parte, la frecuencia angular está descrita por la siguiente fórmula:
\(\omega = 2\pi\cdot f\) (4)
Donde \(f\) es la frecuencia, en hertz.
Ahora, necesitamos calcular la amplitud y el ángulo de fase mediante el sistema de ecuaciones que hemos formado: \(t = 0\,s\), \(x(t) = 1,1\,cm\), \(v(t) = -15\,\frac{cm}{s}\) and \(f = 2,5\,hz\):
Por (4):
\(\omega = 2\pi\cdot f\)
\(\omega = 2\pi\cdot (2,5\,hz)\)
\(\omega \approx 15,708\,\frac{rad}{s}\)
Por (1) y (2):
\(A\cdot \cos \phi = 1,1\) (1b)
\(-15,708\cdot A \cdot \sin \phi = -15\) (2b)
Al dividir (2b) por (1b) y despejar el ángulo de fase tenemos que:
\(-15,708\cdot \tan \phi = -13,636\)
\(\tan \phi = 0,868\)
\(\phi = \tan^{-1} 0.868\)
\(\phi \approx 0,228\pi\,rad\)
Por (1) tenemos el valor de la amplitud: (\(\phi \approx 0,228\pi\,rad\))
\(A = \frac{1,1}{\cos \phi}\)
\(A = \frac{1,1}{\cos 0,228\pi}\)
\(A \approx 1,458\,cm\)
A) El componente de aceleración de la aguja se calcula por (3) evaluada en \(t = 0\,s\):
\(a(t) = -359,749\cdot \sin (15,708\cdot t + 0,228\pi)\)
\(a(0) = -236,206\,\frac{cm}{s^{2}}\)
B) Las ecuaciones para la componentes de posición, velocidad y aceleración de la punta en función del tiempo son, respectivamente:
\(x(t) = 1,458\cdot \cos (15,708\cdot t +0,228\pi)\)
\(v(t) = -22,902\cdot \sin (15,708\cdot t + 0,228\pi)\)
\(a(t) = -359,749\cdot \sin (15,708\cdot t + 0,228\pi)\)