The curved movement of air or water is the result of which action?.
Answers
The curved movement of air or water is the result of the Coriolis effect.
The Coriolis effect is an apparent deflection of moving objects caused by the rotation of the Earth. As the Earth rotates on its axis, objects in motion, such as air or water, are influenced by this rotation and appear to be deflected to the right in the Northern Hemisphere and to the left in the Southern Hemisphere.
In the case of air movement, this deflection is responsible for the rotation of large-scale weather systems, such as cyclones and anticyclones. The Coriolis effect also influences the direction of winds and ocean currents, causing them to follow curved paths rather than moving in straight lines.
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Related Questions
which two technologies use waves to determine the location and velocity of objects
Lenses
X Rays
Sonar
Radar
Answers
Answer: sonar and radar
Explanation:
Picture
Can some help me, please?
Answers
Answer:
1. Transform Boundary
2. Continental-continental convergent boundary
3. Oceanic-Oceanic Divergent boundary
Explanation:
Two 4 kg blocks hang from a rope that passes over two frictionless pulleys
Answers
The tension in the horizontal part of the rope is 39.24 N when the blocks are stationary and the rope has no mass.
What is tension force?The tension force is described as the force transferred through a rope, string, or wire as it is pulled by opposing forces.
The tension force is applied along the whole length of the wire, pulling energy equally on both ends.
The force in the rope is found as;
Tension = mass × acceleration due to gravity
T=mg
T = 4kg × 9.81 m/s²
T = 39.24 N
Hence,the tension in the horizontal part of the rope is 39.24 N
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Liquid ammonia flows through a pipe at a mass flow rate of 100
kg/s .
If the cross-sectional area of the pipe is 0.01
m^2, determine the flow rate of momentum through the
pipe.
Answers
The momentum flow rate through the pipe carrying liquid ammonia is 1 × \(10^6\) kg·m/s.
The flow rate of momentum (Ṁ) through the pipe can be calculated by multiplying the mass flow rate (ṁ) by the velocity (v). The speed can be determined using the equation v = ṁ / (ρA), where ρ is the density of the liquid ammonia and A is the pipe's cross-sectional area.
Given:
ṁ = 100 kg/s
A = 0.01 m²
Assuming the density (ρ) of liquid ammonia is 700 kg/m³, we can calculate the velocity (v):
v = ṁ / (ρA)
v = 100 kg/s / (700 kg/m³ × 0.01 m²)
v = 10000 m/s
Now, we can calculate the flow rate of momentum (Ṁ):
Ṁ = ṁv
Ṁ = 100 kg/s × 10000 m/s
Ṁ = 1 × \(10^6\) kg·m/s
Therefore, the momentum flow rate through the pipe is 1 × \(10^6\) kg·m/s.
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Lizette works in her school’s vegetable garden. Every Tuesday, she pulls weeds for 15 minutes. Weeding seems like a never-ending task. Each time Lizette goes to the garden, there are just as many weeds as the week before!
Lizette’s teacher suggests that she use a strong solution of vinegar to kill the weeds. Vinegar is acidic and prevents plants from maintaining homeostasis. Lizette sets up a controlled experiment to test her hypothesis that the solution will kill the weeds without harming nearby vegetables. She plans to spray one group of weeds with the solution and another group of weeds with water as a control.
What variables should Lizette keep the same between the control group of weeds and the sprayed weeds?
Answers
The variables that Lizette should keep the same between the control group of weeds and the sprayed weeds include : type of weed, age and size of the weeds, amount of sunlight and water , location of the weeds and amount and frequency of spraying.
What variables should Lizette keep the same between control group of weeds and sprayed weeds?The variables that Lizette should keep the same between the control group of weeds and the sprayed weeds include:
The type of weed: To ensure that the control group of weeds and the sprayed weeds are comparable, Lizette should use the same type of weed in both groups.
The age and size of the weeds: Lizette should select weeds of similar age and size for both groups, as larger or older weeds may be more resistant to the vinegar solution.
The amount of sunlight and water: The amount of sunlight and water that the control group of weeds and sprayed weeds receive should be same, as these factors can affect plant growth and health.
The location of the weeds: The control group of weeds and the sprayed weeds should be located in same area of the garden, as differences in soil composition or other environmental factors could affect the results.
The amount and frequency of spraying: Lizette should apply the same amount of water to the control group of weeds as she applies vinegar solution to the sprayed weeds, and frequency of spraying should also be same.
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Justify your answer!! Please explain steps Does the sequence: {4- (3)*}** n=0 If yes, what does it converge to?
Answers
The given sequence does converge. It converges to 4. To determine if the given sequence converges, we need to analyze its pattern.
The sequence is defined as {4- (3)}** n=0, where n represents the index of the term in the sequence. The expression within the braces, 4- (3), suggests that each term is obtained by subtracting 3 multiplied by the previous term from 4.
Let's calculate a few terms to observe the pattern:
Term 0: 4 - (3)* = 4 - 0 = 4
Term 1: 4 - (3)4 = 4 - 12 = -8
Term 2: 4 - (3)(-8) = 4 + 24 = 28
Term 3: 4 - (3)*28 = 4 - 84 = -80
From the calculations, it is clear that the sequence does not converge to a specific value. Instead, it oscillates between positive and negative values, never settling down to a single value. Therefore, the given sequence does not converge.
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5. A book is placed on a table. If the book exerts a force of 15 N'on the table,
how much force does the table exert on the book?
A. ON
C. 9.8 N
B. 3 N
D. 15 N
Answers
Answer:
D
Explanation:
The table is NOT in motion, so it will remain still. Newton's second law states that for every action, there's an equal and opposite reaction. Therefore, the table must push back the opposite direction(up) with the same force(15N)
Which factor increases as a result of increasing altitude?
Answers
Help me to answer this pls
Answers
here is the answers, hope this helps you.
if the car rolls down the hill ( with engine off) with negligible friction and air resistance what will its kinetic energy be
Answers
Answer:
falling iirc
Explanation:
What types of human and animal behavior are "complex, unlearned, and rigidly patterned"?
Answers
Answer:
Instincts
Explanation:
instincts are complex, unlearned behaviors that are present throughout a species and genetically transmitted.
The rate of increase of the Earth's gravity field at latitudes 30° and 60° are in the ratio
Answers
Answer:
1 : 2 (30 : 60)
Explanation:
The rate of increase of the Earth's gravity field at latitudes 30° and 60° are in the ratio 1 : 2 because 30 : 60 simplified is 1 : 2.
If the answer does not ask for the ratio to be simplified leave its as 30 : 60.
if we could have turned a receiver toward the heavens in hopes of observing the cosmic microwave radiation four and a half billion years ago, at the time the solar nebula was forming, what would we have found?
Answers
In order to observe the cosmic microwave radiation four and a half billion years ago, we would have seen a blackbody curve with the same shape as we see now but with a peak intensity at a wavelength shorter than 1 mm.
blackbody Curves Planck's Law can be used to apply a curve to represent the intensity of blackbody emission over a variety of wavelengths on the light spectrum.
The green region of the spectrum, close to the human eye's maximal sensitivity, has a peak emission per nanometer (of wavelength) at a wavelength of about 500 nm, according to Wien's equation.
In physics, the wavelength is the length over which a periodic wave repeats, or its spatial period.
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What happens to hotter air in the atmosphere?
A.Warmer air molecules move faster and get farther apart. As they get farther apart, they become more dense and sink.
B.Warmer air molecules move faster and get farther apart. As they get farther apart, they become less dense and rise.
C.Warmer air molecules move slower and spread out. As they spread out, they sink below cooler air molecules.
Answers
B.Warmer air molecules move faster and get farther apart. As they get farther apart, they become less dense and rise.
10 points
A 2.5 kg ball moving at 5 m/s collides with a 2.5 kg stationary ball in a perfectly elastic collision. What is the velocity of the second ball after the
collision?
7.5 m/s
10 m/s
2.5 m/s
5 m/s
Next
Answers
The velocity of the second ball that was hit by a ball of mass 2.5 kg moving with an initial velocity of 5 m/s is 5 m/s.
What is velocity?Velocity can be defined as the rate of change of displacement.
To calculate the velocity of the second ball after collision, we use the formula below.
Formula:
mu+MU = mv+MV............ Equation 1Where:
m = Mass of the first ballM = Mass of the second ballu = Initial velocity of the first ballU = Initial velocity of the second ballv = Final velocity of the first ballV = Final velocity of the secomnd ballFrom the question,
Given:
m = 2.5 kgM = 2.5 kgu = 5 m/sU = 0 m/s (at rest)v = - 5 m/s (rebound)Substitute these values into equation 1 and solve for V
(2.5×5)+(2.5×0) = 2.5(-5)+2.5V2.5V = 12.5+12.52.5V = 25V = 25/5V = 5 m/sHence, the velocity of the second ball is 5 m/s.
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the net electric flux crossing an open surface is never zero. true or false?
Answers
The given statement that net electric flux crossing an open surface is never zero, is false.
The net electric flux of an electric field through a closed surface is equal to the enclosed charge, divided by the permittivity of the free space. Where charge is taken in the unit of coulombs.
The net electric flux cross an open surface can also be zero if the is perpendicular to the direction of the field. In other word if the field lines are parallel to the surface. Electric flux is a scaler quantity. The SI unit of electric flux is N-m²/C.
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Prompt
First aid can be a critical step in saving someone's life and facilitating quick healing in case of an emergency. Having a well
stocked first aid kit is crucial in administering proper first aid. What items would you include in a first aid kit?
Answers
Answer:
1.bandages
2.cottons
3.scissor
4.medicines
a force of 10 newtons pushes a box a distance of 1.86 m. how much work did the force do? do not include units in the answer.
Answers
When a force of 10 newtons pushes a box, then the work done is 18.6 joules.
Work done :
Work done is defined as the amount of energy used by a force to move an object.
W = Fd Its unit is joule.Force :
The push and pull of an object.Its unit is newton.A force pushes a box = 10 Newtons
Distance covered = 1.86m
work done is calculated as :
W = F x d
where
W = work done
F = force applied
d = distance covered by a box
W = 10 x 1.86
W = 18.6 joule.
so, the work done is 18.6 j.
When a force of 10 newtons pushes a box, then the work done is 18.6 joules.
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4.) A car with mass 1352 kg is being towed across the parking lot by a tow truck using a horizontal cable with a force of 7820 N. The coefficient of kinetic friction between the car tires and pavement is 0.56. Determine whether a net force is acting on the car and if so, at what rate is the car accelerating across the parking lot?
Answers
From the calculation, there is a net force that acts on the car and then the acceleration that is produced by the net force is 0.296 m/s^2.
What is the net force?The term net force refers to the force that is acting on an object that makes it to move. We have to recall that the force of friction is the force the limits the motion of an object. In other words, it is the force of friction that makes a body not to be able to move and this must be overcome by the forward force when it is greater than the friction force.
Now;
Mass of the car = 1352 kg
Forward force = 7820 N
Coefficient of friction = 0.56
Frictional force = μmg
= 0.56 * 1352 kg * 9.8 m/s^2
= 7419.8 N
Net force = Forward force - Frictional force
= 7820 N - 7419.8 N
= 400.2 N
Then;
Net force = ma
m = mass
a = acceleration
a = Net force/m
a = 400.2 N/ 1352 kg
a = 0.296 m/s^2
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A ball is projected at an angle of elevation of 60 ° with an initial velocity of 120m/s.calculate
1) The time taken to get to the maximum height
ii) the time of flight
Answers
Explanation:
It is given that,
The angle of projection is 60 degrees
Initial velocity of the ball is 120 m/s
We need to find the time taken to get to the maximum height and the time of flight.
Time taken to reach the maximum height is given by :
\(T=\dfrac{u^2\sin^2\theta}{2g}\)
g is acceleration due to gravity
\(T=\dfrac{(120)^2\times \sin^2(60)}{2\times 10}\\\\T=540\ s\)
(ii) Time of flight,
\(t=\dfrac{2u\sin\theta}{g}\)
So,
\(t=\dfrac{2\times 120\times \sin(60)}{10}\\\\t=20.78\ s\)
Hence, this is the required solution.
A 20μC point charge is placed 10cm from a 5μC point charge.
1. Calculate the force experienced by the 5μC charge.
2. What is the force on the 20μC charge?
3. What is the electric field strength located at 15cm from the 20μC charge?
4. Draw the direction of the electric field line at the 15cm mark from the 20μC charge
Answers
1. The force experienced by the 5μC charge is 0.45 N.
2. The force on the 20μC charge is -0.45 N.
3. The electric field strength located at 15cm from the 20μC charge is 12 N/C.
4. The electric field lines will point away from the 20μC charge, radially outward.
1. To calculate the force experienced by the 5μC charge, we can use Coulomb's law. Coulomb's law states that the force between two point charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. Mathematically, the formula is given by:
\(F = k * (q1 * q2) / r^2\)
Where F is the force, k is the electrostatic constant (9 x 10^9 Nm²/C²), q1 and q2 are the charges, and r is the distance between them.
Plugging in the values:
\(F = (9 x 10^9 Nm^2/C^2) * ((5 x 10^-6 C) * (20 x 10^-6 C)) / (0.1 m)^2\)
= 0.45 N
Therefore, the force experienced by the 5μC charge is 0.45 N.
2. By Newton's third law of motion, the force on the 20μC charge is equal in magnitude but opposite in direction to the force experienced by the 5μC charge. Hence, the force on the 20μC charge is -0.45 N.
3. To calculate the electric field strength at a point, we can use the formula:
\(E = k * (q / r^2)\)
Where E is the electric field strength, k is the electrostatic constant, q is the charge, and r is the distance from the charge.
Plugging in the values:
\(E = (9 x 10^9 Nm^2/C^2) * (20 x 10^-6 C) / (0.15 m)^2\)
= 12 N/C
Therefore, the electric field strength located at 15cm from the 20μC charge is 12 N/C.
4. Electric field lines depict the direction of the electric field. Since the charge is positive (20μC), the electric field lines will point away from it, radially outward. Hence, at the 15cm mark from the 20μC charge, the electric field lines will extend outward from the charge in all directions.
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Calculate the magnitude of the gravitational force between Goku with a mass of 62 kg and King Kai’s planet with a mass of 1.458x1015 kg if the distance between their centers of mass is 31 m.
Answers
Answer:
6227.866 N
Explanation:
F = G . m(goku) . m(planet) / d²
F = 6.674 x 10-¹¹ x 62 x 1.458 . 10¹⁵ / 31²
F = 6227.866 N
Climate is the sum of _____ in a given area, averaged over a long period of time.
a. ocean currents
b. atmospheric circulation
c. wind speeds
d. weather conditions
e. cloud patterns
Answers
Answer:
d.weather conditions
Explanation:
Climate is the sum of weather conditions in a given area,averaged over a long period of time.
will give correct answer brainliest
5 kg m/s
8kg m/s
80 kg m/s
200 kg m/s
Answers
Answer: Here this will help you..
Explanation:
1 kg-m/s to kilogram-force meter/second = 1 kilogram-force meter/second
5 kg-m/s to kilogram-force meter/second = 5 kilogram-force meter/second
10 kg-m/s to kilogram-force meter/second = 10 kilogram-force meter/second
20 kg-m/s to kilogram-force meter/second = 20 kilogram-force meter/second
30 kg-m/s to kilogram-force meter/second = 30 kilogram-force meter/second
40 kg-m/s to kilogram-force meter/second = 40 kilogram-force meter/second
50 kg-m/s to kilogram-force meter/second = 50 kilogram-force meter/second
75 kg-m/s to kilogram-force meter/second = 75 kilogram-force meter/second
100 kg-m/s to kilogram-force meter/second = 100 kilogram-force meter/second
What are two ways fusion is used in the real world.
Answers
Answer:
The main application for fusion is in making electricity. Most fusion reactors make less radiation than the natural background radiation we live with in our daily lives. ... Clean - No combustion occurs in nuclear power (fission or fusion), so there is no air pollution.
sketch a velocity -time graph for a body thrown vertically upward to a maximum height
Answers
The velocity time graph for a body thrown vertically upward to a maximum height is given below:
What is velocity?
The pace at which an object's position changes as perceived from a particular point of view and as measured by a particular unit of time (for example, 60 km/h northbound) is defined as its velocity. Velocity is a fundamental concept in kinematics, the branch of classical mechanics that deals with the motion of bodies.
In order to be defined, the physical vector quantity known as velocity needs to have both a magnitude and a direction. Speed is a coherent derived unit whose quantity is measured in metres per second (m/s or m/s1) in the SI. Speed is the scalar absolute value (magnitude) of velocity (metric system). "5 metres per second," for example, is a scalar as opposed to "5 metres per second east," which is a vector.
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A 1000-kg sports car of mass accelerates from rest to 20 m/s in 6.6 s. What is the frictional force exerted by the road on the car?
Answers
Acceleration
a=v-u/ta=20-0)6.6a=20/6.6a=3.03m/s²Now
Apply Newtons second law
F=maF=1000(3.03)F=3030NTo find frictional force we need coefficient of friction which is not given .
generally for car case the value of coefficient is 0.6-0.8 .
Putting max 0.8
f=$\mu$ Nf=0.8(3030)f=2424NNote:
Last part is assumption not accurate
The force acting on the sports car is the product of its mass and acceleration. The force on the car is 3300 N.
What is force?Force is an external agent acting on a body to deform it or to change it from the state of rest or motion. There are different kinds of forces such as frictional force, gravitational force, nuclear force, magnetic force etc.
Frictional force is acting as a hindrance to the motion of an object. The frictional force is the product of normal force and coefficient of friction.
According to second law of motion, force is the product of mass and acceleration.
Given mass m = 1000 Kg
change in velocity = 20 - 0 m/s
Acceleration = 20 m/s / 6.6 s
= 3.3 m/s².
Force = m a
= 3.3 m/s² × 1000 Kg
= 3300 N.
Now, product of this normal force and coefficient of static friction.
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please help me!!!!!!
Answers
Answer:
3.a. 6m away
b. 3m away
Explanation:
a)
Effort = 10000N
Load=5000 N
effort distance=3 m
load distance=?
We can use the following equation to calculate the distance of the load from the fulcrum:
\(\boxed{\bold{\tt{Load * Load \:Distance = Effort * Effort \:Distance}}}\)
Plugging in the known values, we get:
\(\bold{\tt{5000 N * Load Distance = 10000 N * 3 m}}\)
dividing both side by 5000 N
\(\bold{\tt{Load\: Distance =\frac{ 10000 N * 3 m }{5000 N}}}\)
Load Distance = 6 m
Therefore, the load must be 6 meters away from the fulcrum in order for the crane to be balanced.
b)
If the load is increased to 10,000N, the effort and effort distance do not change.
Effort = 10000N
Load=10,000 N
effort distance=3 m
load distance=?
This is because the moment of the load will increase, and the moment of the effort will remain the same.
The moment of the load is calculated as follows:
\(\boxed{\bold{\tt{Load * Load \:Distance = Effort * Effort \:Distance}}}\)
Plugging value
\(\bold{\tt{10,000 N * Load Distance = 10,000 N * 3 m}}\)
dividing both side by 10,000 N
\(\bold{\tt{Load\: Distance =\frac{ 10,000 N * 3 m }{10,000 N}}}\)
New Load Distance = 3 m
Therefore, if the load is increased to 10,000N, it should be placed 3 meters away from the pivot point to balance the crane.
Please help it’s due soon!!!
Do you think it is possible for two neutral objects to both become positively charged after they are rubbed together? Justify your answer
Answers
Answer:
It is possible for neutral objects to become charged by rubbing them together due to friction. Electrons of one object transfer to the other resulting to more electrons in the object than its protons therefore leaving it as charged
Explanation:
I all ready said it 0>0
Answer:
no
Explanation:
because one itoms becomes positive and the other negative due to the transfer
Based on what you know about the intrinsic brightness of stars, select all of the correct statements from the following list.
Answers
The intrinsic brightness of a star can vary greatly from star to star, depending on factors such as its size, temperature, and age. These variations in intrinsic brightness are used to classify stars into different types or spectral classes, such as supergiants and dwarfs.
Based on what you know about the intrinsic brightness of stars, select all of the correct statements from the following list:
1. The intrinsic brightness of a star is also known as its absolute magnitude. This magnitude measures the actual amount of light that a star emits.
2. The intrinsic brightness of a star is independent of its distance from Earth. This means that even if a star is far away, its intrinsic brightness remains the same.
3. The intrinsic brightness of a star can be determined by measuring its apparent magnitude and knowing its distance from Earth. The apparent magnitude is how bright a star appears to us from Earth, while the distance is the actual physical distance between the star and Earth.
4. The intrinsic brightness of a star can be used to classify stars into different types or spectral classes. For example, stars with high intrinsic brightness are classified as "supergiants," while stars with low intrinsic brightness are classified as "dwarfs."
5. The intrinsic brightness of a star can vary greatly from star to star. Some stars are much brighter than others due to factors like their size, temperature, and age.
6. The intrinsic brightness of a star can be calculated using the formula: Intrinsic Brightness = (Apparent Brightness * 4π * (Distance)²) / (Luminosity Constant)
The intrinsic brightness of a star, also known as its absolute magnitude, is a measure of the actual amount of light that a star emits. It is important to note that the intrinsic brightness of a star is independent of its distance from Earth. This means that even if a star is far away, its intrinsic brightness remains the same.
However, in order to determine the intrinsic brightness of a star, we need to measure its apparent magnitude (how bright it appears to us from Earth) and know its distance from Earth. The apparent magnitude is measured on a logarithmic scale, with smaller numbers indicating brighter stars. By comparing the apparent magnitude and distance of a star, we can calculate its intrinsic brightness using the formula: Intrinsic Brightness = (Apparent Brightness * 4π * (Distance)²) / (Luminosity Constant).
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