The crocodile which can remain underwater without breathing for up to an hour, drowns it air-breathing prey and then dines on them at its leisure. An adaptation that aids the crocodile in doing so is that it can utilize virtually 100% of the O2 in its blood whereas humans, for example, can extract only -65% of the O2 in their blood. (a) Draw an O2 binding curve comparing crocodile hemoglobin to that of normal hemoglobin. humne ih (b) Experiments have demonstrated that 2,3 bis-phosphoglycerate has no effect on the O2 binding of crocodile hemoglobin. However, it has been shown that 2 molecules of bicarbonate bind to deoxyhemoglobin tetramers but not to oxyhemoglobin tetramers of crocodile hemoglobin. Describe how bicarbonate might effect the O2 affinity of crocodile hemoglobin. Make sure to detail what regions of the hemoglobin tetramek might be bound by bicarbonate and how this would influence structural changes in the crocodile hemoglobin that would, in turn, affect O2 affinity. (c) Sketch the biochemical reactions in red blood cells that result in bicarbonate formation in venous blood. Write balanced equations and identify any enzymes that might be involved. If an enzyme is required, indicate which reaction is enzyme-catalyzed.

Answers

Answer 1

Answer:

Answer is explained in the explanation section below.

Explanation:

Note: Please refer to the attachment for the O2 binding curve comparing crocodile hemoglobin to that of normal hemoglobin.

so as we know that crocodile can remain under water without breathing for an hour using certain important factor it includes the process :

 Hb(4O2) :↔: (4O2) + deoxyHB → deoxyHB-CO3 -

At the tissues, there is an equilibrium between oxygenated and deoxygenated Hb, depending upon the oxygen concentration in the tissues. Utilization of oxygen by the crocodile tissues will remove the oxygen from the right of the first equilibrium expression, causing the dissociation of oxygen from oxyhemoglobin.

At the same time, the crocodile tissues are generating carbon dioxide from metabolism. This binds to deoxyHb, generating the carboxylated form. This reaction depletes the deoxyHb from the center of the above equilibrium, causing further incentive for oxyHb to give away its oxygen.

When the crocodile has its prey underwater and is using lots of energy to keep its jaws clamped on the prey, O2 is consumed and CO2 is produced. CO2 is converted to protons and bicarbonate ions as follows: CO2 + H2O ↔ H2CO3 ↔ H+ + HCO3 - H+ is an allosteric inhibitor that specifically binds the deoxy or T state of hemoglobin, shifting the equilibrium from the R state to the T state. This is the pH Bohr Effect.

In addition, the problem states that HCO3 - also specifically binds the deoxy or T state of crocodile hemoglobin. The shift to the deoxy or T state by H+ and HCO3 - lowers Hb affinity for O2, allowing for nearly complete O2 unloading and utilization in the crocodile’s blood .

The Crocodile Which Can Remain Underwater Without Breathing For Up To An Hour, Drowns It Air-breathing

Related Questions

If 5.10 grams Kr occupies volume of 25.7 mL how many grams occupies volume of 42.6 mL

Answers

The molarity is an important method which is used to determine the concentration of a solution. So the term molarity is also known as the concentration. Here the grams of Kr which occupies a volume of 42.6 mL is

The molarity of a solution is defined as the number of moles of the solute present per litre of the solution. Its unit is mol L⁻¹ and it is essential to calculate the concentration of a binary solution.

Here M₁V₁ = M₂V₂

M₂ = M₁V₁ /  V₂

25.7 mL = 0.0257 L

42.6 mL = 0.0426 L

M₂ =  5.10 × 0.0257 / 0.0426  = 3.076 g

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The Sun has been shining on this swimming pool all day. The water is much warmer than it was in the morning. Describe what is happening to the water in terms of temperature, particle speed, and kinetic energy.

Answers

Answer:

The waters' temp increased

Explanation:

The temperature of the water in the swimming pool has increased due to the heat from the Sun. As a result, the particles in the water are moving faster and have a higher kinetic energy than in the morning.

The enthalpy of fusion of aluminum is 10.7 kJ/mol. How many grams of aluminum can be melted by adding 81.4 kJ of energy to the metal at its melting point

Answers

Answer:

The correct answer is  205.4 g Al

Explanation:

Given the enthalpy of fusion (ΔHf) of aluminum (Al), the amount of heat required to melt the substance is calculated as follows:

heat = ΔHf x moles Al

We have the following data:

ΔHf = 10.7 kJ/mol

heat= 81.4 kJ

So, we calculate the moles of Al we can melt:

moles =heat/ΔHf= 81.4 kJ/(10.7 kJ/mol)= 7.61 moles

The relation between moles and grams of Al is given by the molar mass of Al (27 g/mol). Thus, we multiply the moles of Al by the molar mass to calculate the grams of Al we can melt:

grams = 7.61 moles x 27 g/mol = 205.4 g

Whats the answer giving brainliest have a good day lol help

Whats the answer giving brainliest have a good day lol help

Answers

Answer: i would say north pole because the sunlight has to change directions to reach it if that makes since

Explanation: sorry if im wrong

12. 5.6g of solid copper was heated with 476.2 J at room temperature (25°C). Given that
copper has a C of 0.38 J/g°C, what would its final temperature be?

Answers

Answer:

The final temperature of the copper would be 311.3°C.

I hope this helps you

Suppose 215 g of NO3- flows into a swamp each day. What volume of CO2 would be produced each day at 17.0°C and 1.00 atm?

Answers

Answer:

The answer is "\(41.23 \ L\ N_2\)"

Explanation:

\(2 NO_3^{-} + 10 e^{-} + 12 H^{+} \longrightarrow N_2 + 6 H_2O\\\\= \frac{( 215 \ g \ NO_3^{-})}{(62.0049 \frac{\ g NO_3^{-}}{mol})} \times \frac{(1 \ mol \ N_2}{ 2 \ mol \ NO_3^{-})}\\\\\)

\(=3.46746789 \times 0.5\\\\= 1.733 \ mol \ N_2 \\\\\to V = \frac{nRT}{P} \\\\= (1.733 \ mol) \times (0.08205746 \frac{L\ atm}{Kmol}) \times \frac{ (17 + 273) K}{(1.00 atm)}\\\\= 41.23\)

The volume of CO2 is 206.27 L

The ideal gas equation is used to determine the volume, pressure, temperature, or number of moles. It can be mathematically expressed as:

PV = nRT

From the given information:

The equation for the reaction can be expressed as:

\(\mathbf{2NO_3^-_{(aq)} + 5CO_{(g)} + 2H^+_{(aq)} \to N_2{(g)} + 5CO_2_{(g)} + H_2O_{(l)}}\)

The mass of NO₃⁻ = 215 gThe temperature = 17.0°C = (273 + 17) = 290 KPressure = 1.00 atm

The number of moles of CO2 from the reaction is;

\(\mathbf{= \dfrac{215 \ g}{62.0049} \times \dfrac{5 \ mol \ of \ CO_2}{2 \ mol \ of \ NO_3^-} }\)

\(\mathbf{= 8.669 \ moles \ of \ CO_2 }\)

From ideal gas, by making the volume the subject of the, we have:

The volume of CO₂ \(\mathbf{V= \dfrac{nRT}{P}}\)

\(\mathbf{V= \dfrac{8.669 \ moles \times 0.08205 L atm/ kmol \times 290\ K}{1 \ atm }}\)

\(\mathbf{V= 206.27 \ L \ of \ CO_2 \ gas}\)

Learn more about the volume of CO2 gas here 206.27 L

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Mara and Ivy are asked to identify two minerals in science class. To do this, they decide to study the physical properties of the minerals in the following ways.
1. Examine how they freeze.
2. Determine how they break.
3. Rub them on a white tile plate. What is the best method (or methods) for the girls to study the physical properties and
identity the two minerals?
1 only
2 only
1 and 2
2 and 3

Answers

Answer:  determine how they break

Explanation:

hope this helps!

Answer: 2  

Explanation:

Strontium hydroxide reacts with hydrobromic acid to produce Strontium bromide and
water.
Write and balance the chemical reaction above, use it for problems 1-4 below:
1. If 5.50 moles of strontium hydroxide were consumed, how much moles of water are
produced?
2. Find the mass of hydrobromic acid used to produce 7.50 moles water.
3. If 10.8 g of strontium hydroxide were used, how much moles of strontium bromide are
produced?
4. If 13.3 g of hydrobromic acid were consumed, find the mass of the water produced.

Answers

The chemical reaction for the reaction of strontium hydroxide with hydrobromic acid is:

Sr(OH)2 + 2 HCl --> SrCl2 + 2 H2O

To find the moles of water produced when 5.50 moles of strontium hydroxide are consumed, we need to apply the law of conservation of mass. The mass of water produced is equal to the mass of strontium hydroxide consumed. Since strontium hydroxide has a molar mass of 142 g/mol and water has a molar mass of 18 g/mol, 1 mol of strontium hydroxide can produce 9 mol of water. Therefore, 5.50 moles of strontium hydroxide can produce 49.5 mol of water.

Similarly, 7.50 moles of water can be produced by reacting 18 moles of hydrobromic acid with strontium hydroxide. Hydrobromic acid has a molar mass of 79.9 g/mol, so 18 moles of hydrobromic acid would have a mass of 79.9 * 18 = 1435.2 g.

To find the moles of strontium bromide produced when 10.8 g of strontium hydroxide is used, we need to apply the law of conservation of mass again. The mass of the strontium bromide produced is equal to the mass of strontium hydroxide consumed. Since strontium bromide has a molar mass of 410 g/mol and strontium hydroxide has a molar mass of 142 g/mol, 1 mol of strontium bromide can consume 3.23 moles of strontium hydroxide. Therefore, 10.8 g of strontium hydroxide can produce 10.8 / 3.23 = 3.34 moles of strontium bromide.

Finally, to find the mass of water produced when 13.3 g of hydrobromic acid is consumed, we need to apply the law of conservation of mass yet again. The mass of the water produced is equal to the mass of hydrobromic acid consumed. Since hydrobromic acid has a molar mass of 79.9 g/mol, 13.3 g of hydrobromic acid would produce 13.3 / 79.9 = 0.166 moles of water.

If d represents the density of a gas and k is a constant. The relationship between the rate of diffusion r, and d is ____?

Answers

The relationship between the rate of diffusion r, and d is r ∝ 1/√d.

The relationship between the rate of diffusion (r) and the density of a gas (d) can be explained using Graham's law of diffusion. According to this law, the rate of diffusion of a gas is inversely proportional to the square root of its density. Mathematically, it can be expressed as:

r ∝ 1/√d

where the symbol '∝' represents 'proportional to'. The constant of proportionality (k) can be introduced to this equation as:

r = k/√d

This equation shows that as the density of a gas increases, its rate of diffusion decreases. This is because denser gases have more molecules per unit volume and thus, they experience greater intermolecular collisions that hinder their movement. Therefore, it requires more energy for them to diffuse through a medium compared to less dense gases.

The relationship between the rate of diffusion and density is particularly important in understanding the behavior of gases in different environments. For instance, in a gas chromatography column, the rate of diffusion of a gas determines how quickly it moves through the column and separates from other components. Similarly, in the Earth's atmosphere, the rate of diffusion of greenhouse gases such as carbon dioxide affects their concentration and hence, their impact on climate change.

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1. What volume in milliliters of 0.100 M HClO₃ is required to neutralize 40.0 mL of 0.140 M KOH? 2. A 25.0 mL solution of HNO₃ is neutralized with 15.7 mL of 0.250 M Ba(OH)₂. What is the concentration of the original HNO₃ solution?

Answers

Answer:

The correct answer is 1) 56 ml and 2) 0.314 M

Explanation:

1. The reaction taking place in the given case is,  

HClO₃ + KOH ⇒ KClO₃ + H2O, the molarity of HClO₃ given is 0.100 M, the molarity of KOH given is 0.140 M and the volume of KOH given is 40 ml, there is a need to find the volume of HClO₃.  

Therefore, the mole of HClO₃ = mole of KOH

= MHClO₃ × VHClO₃ = MKOH × VKOH

= 0.100 M × VHClO₃ = 0.140 M × 40 ml

VHClO₃ = 0.140 M × 40 ml/0.100 M

VHClO₃ = 56 ml.  

2. The reaction taking place is,  

2HNO₃ + Ba(OH)₂ ⇒ Ba(NO₃)₂ + 2H₂O

The volume of HNO₃ given is 25 ml, the molarity of Ba(OH)2 is 0.250 M, the volume of Ba(OH)2 is 15.7 ml, the n or the number of moles of HNO₃ is 2, and the n of Ba(OH)2 is 1, the concentration or M of HNO₃ is,  

M₁V₁/n₁ = M₂V₂/n₂

M₁ × 25/ 2 = 0.25 × 15.7/1

M₁ or molarity of HNO₃ = 0.314 M

1. The volume of HClO₃ required to neutralize the KOH is 56.0 mL

2. The concentration of the original HNO₃ solution is 0.314 M

1.

First, we will write a balanced chemical equation for the reaction

The balanced chemical equation for the reaction is

HClO₃ + KOH → KClO₃ + H₂O

This means,

1 mole of HClO₃ is required to neutralize 1 mole of KOH

From the titration formula

\(\frac{C_{A}V_{A} }{C_{B}V_{B}} = \frac{n_{A}}{n_{B}}\)

Where

\(C_{A}\) is the concentration of acid

\(C_{B}\) is the concentration of base

\(V_{A}\) is the volume of acid

\(V_{B}\) is the volume of base

\(n_{A}\) is the mole ratio of acid

\(n_{B}\) is the mole ratio of base

From the given information,

\(C_{A} = 0.100 \ M\)

\(C_{B} = 0.140 \ M\)

\(V_{B} = 40.0 \ mL\)

From the balanced chemical equation

\(n_{A} = 1\)

\(n_{B} =1\)

Putting the values into the formula, we get

\(\frac{0.100 \times V_{A} }{0.140 \times 40.0} = \frac{1}{1}\)

∴ \(0.100 \times V_{A} = 0.140 \times 40.0\)

\(V_{A}=\frac{0.140\times 40.0}{0.100}\)

\(V_{A}=\frac{5.60}{0.100}\)

\(V_{A}=56.0 \ mL\)

Hence, the volume of HClO₃ required to neutralize the KOH is 56.0 mL

2.

First, we will write the balanced chemical equation for the reaction

The balanced chemical equation for the reaction is

2HNO₃ + Ba(OH)₂ → Ba(NO₃)₂ + 2H₂O

This means, 2 mole of HNO₃ is required to neutralize 1 mole Ba(OH)₂  

From the given information,

\(V_{A} = 25.0\ mL\)

\(C_{B} = 0.250 \ M\)

\(V_{B} = 15.7 \ mL\)

From the balanced chemical equation

\(n_{A} = 2\)

\(n_{B} =1\)

Also, Using the titration formula

\(\frac{C_{A}V_{A} }{C_{B}V_{B}} = \frac{n_{A}}{n_{B}}\)

We get

\(\frac{C_{A} \times 25.0 }{0.250 \times 15.7} = \frac{2}{1}\)

Then,

\(C_{A} = \frac{2\times 0.250 \times 15.7} {1 \times 25.0}\)

\(C_{A} =\frac{7.85}{25.0}\)

\(C_{A} =0.314 \ M\)

Hence, the concentration of the original HNO₃ solution is 0.314 M

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The picture shows a model of the internal structure of Earth.

Which evidence best supports the different characteristics of each layer in this model?

evaluations of seismic data

direct observations of the layers

explanations of the rock cycle

samples of rocks from the layers

Answers

Answer:evaluations of seismic data

Explanation:

what is a kinetic molecular

Answers

Kinetic Molecular Theory states that gas particles are in constant motion and exhibit perfectly elastic collisions.

kinetic molecular is constant elastic collisions

What is the binding energy of 1 mole of 23 Pu if the mass defect is 0.001896 kg/mol?

Answers

Answer:

1.7 * 10^14 J

Explanation:

Recall that binding energy = Δmc^2

Δm= mass defect

c = speed of light

Given that;

Δm = 0.001896 kg/mol/1 mol = 0.001896 kg

c=3 * 10^8 m/s

Binding energy = 0.001896 kg (3 * 10^8 m/s)^2

Binding energy = 1.7 * 10^14 J

This is for science! I really need help.

This is for science! I really need help.

Answers

Answer

Solid

liquid

Gas

Explanation:


the three states of matter are solid, liquid, and gas

Which of these is a ball and stick model?

C subscript 2 H subscript 4.

2 overlapping large black spheres each with 2 small blue spheres overlapping it.

2 medium sized black spheres connected by 2 grey sticks. Each black sphere has 2 small blue spheres connected to it by 1 grey stick.

2 C's connected by 2 black lines. Each C has 2 H's connected to it each by 1 black line.

Answers

The ball and stick model of C subscript 2 H subscript 4 is described as Option C: Each C has 2 H's connected to it each by 1 black.

This means the same as the 3D structure image of ethylene (C2H4) and means 2 C's connected by 2 black lines.

line.

The structure of ethylene is made up of 2 carbon atoms and 4 hydrogen atoms.

The carbon atoms are located at the middle position and the hydrogen atom surrounding the carbon atoms with two hydrogen atoms connected to each carbon atom. The two black lines connecting the carbons are the double bonds.

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Which of these is a ball and stick model?C subscript 2 H subscript 4.2 overlapping large black spheres

Answer:

C

Explanation:

Bohr's Model of the atom
If an element has 7 electrons in its valence shell (outermost ring), which chemical family would you expect it to belong to?​

Answers

Answer:

group 17 the halogen.as it has 7 electron in its outermost ring

In distillation,separation is achieved by difference in---​

Answers

Answer:

relative volatility.

mark me brainliestt :))

Answer: in temperature

Which of the following are true about an atom? Choose all that apply.

Answers

Answer:

Explanation:

Atoms are the building blocks of matter.

They are the smallest particles of an element that still have the element's properties.

All atoms are very small, but atoms of different elements vary in size.

Three main types of particles that make up all atoms are protons, neutrons, and electrons.

The fluorine-17 nuclide radioactively decays by electron capture.

Answers

Answer: daughter nucleus is Oxygen-17

Explanation: electron and proton form a neutron in nucleus.

Mass number remains same and number of proton decreases.

Fluorine -17 isotope undergoes nuclear decay by electron capture results in the formation of the oxygen-17 nuclei and one neutron as written below:

\(\rm _{9}^{17}F + _{-1}^{0}e \rightarrow _{9}^{1 7}O + _{0}^{1}n\)

What is nuclear decay?

Unstable radioactive isotopes of some elements undergoes breaking their nuclei by emitting or absorbing some charged particles such as alpha or beta.

Alpha decay result in the emission of one helium  nuclei where, the mass number reduces by 4 units and atomic number by 2. In beta decay mass umber does not change but atomic number increases by one.

The process of electron capture, is the bombardment of an electron into the unstable nucelli result where the atomic number reduces by one. Therefore, fluorine converts to oxygen -17 by electron capture where the latter isotope is stable one.

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Your question is incomplete. But your complete question probably was:

Fluorine-17 nuclide radioactively decays by electron capture. Write a balanced nuclear chemical equation that describes this process.

Waves that can travel through empty space are called

Answers

Answer:

Hello, Otaku Kun Here! >:3

Explanation:

Electromagnetic waves? This is also called light!

hope this helps!

from: Otaku Kun! ^^

Photoelectric effect will occur only if frequency of light striking an electron in a metal is above a certain threshold frequenci

Answers

The statement is correct. The photoelectric effect refers to the phenomenon where electrons are ejected from the surface of a material when it is exposed to light. The frequency of light striking an electron in a metal must be above the threshold frequency in order for the photoelectric effect to occur.

The statement is correct. The photoelectric effect refers to the phenomenon where electrons are ejected from the surface of a material when it is exposed to light. However, for the photoelectric effect to occur, the frequency of the incident light must be above a certain threshold frequency.

The threshold frequency is the minimum frequency of light required to dislodge electrons from the material. Below this threshold frequency, regardless of the intensity or duration of the light, no electrons will be emitted.

This behavior can be explained by the particle-like nature of light, where light is composed of discrete packets of energy called photons. The energy of a photon is directly proportional to its frequency. Only photons with energy greater than or equal to the binding energy of the electrons in the material can dislodge them.

Therefore, the frequency of light striking an electron in a metal must be above the threshold frequency in order for the photoelectric effect to occur.

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When a metal is put into an acidic solution, what happens

Answers

Answer:

The acid will react with the metal, causing hydrogen gas and salt to form from it.

In what type of reaction is water always a product

Answers

when hydrogen and oxygen combine then they form water as product

also in neutralization reaction water form as product

hope it helps

Water is always a product in a type of chemical reaction called a neutralization reaction.

A reaction is a process that involves the transformation of one or more substances into one or more different substances.

Neutralization reaction is type of reaction occurs when an acid and a base react together to form a salt and water. The general equation for a neutralization reaction is:

\(\rm acid + base \rightarrow salt + water\)

In this type of reaction, the hydrogen ions (\(\rm H^+\)) from the acid combine with the hydroxide ions (\(\rm OH^-\)) from the base to form water (\(\rm H_2O\)). The remaining ions from the acid and the base combine to form a salt.

Therefore, water is always a product in a neutralization reaction, which occurs when an acid and a base react together to form a salt and water.

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100 POINTS & BRAINLIEST !!!! PLEASE HELP

100 POINTS & BRAINLIEST !!!! PLEASE HELP

Answers

Answer:

The more you get closer to a substance in the periodic table things that are included into the substance start to get bigger

Explanation:

Answer:The more you get closer to a substance in the periodic table things that are included into the substance start to get biggerplz mark me as brainiest

Does anyone know these answers?

Does anyone know these answers?

Answers

Answer:

Explanation:

Na & I -> NaI (Sodium iodide)Be & Br -> BeBr2 (beryllium bromide)Ca & S -> CaS (Calcium sulfide)Ca & N -> Ca3N2 (Calcium Nitride)Al & P -> AlP (Aluminum phosphide)Al & Te -> AlTe (Aluminum telluride)K & O -> KO (Potassium oxide)Na & S -> Na2S (Sodium sulfide)Sr & Cl -> SrCl2 (Strontium chloride)Sr & S -> SrS (Strontium sulfide)Al & F -> AlF3 (Aluminum fluoride)Mg & S -> MgS (Magnesium sulfide)Rb & Se -> RbSe (Rubidium selenide)Al & O -> Al2O3 (Aluminum oxide)Ba & P -> Ba3P2 (Barium phosphide)It is important to note that these compounds are formed by ionic bonding where the metal atom loses electrons to form a positive ion ( cation) and the non-metal atom gains electrons to form a negative ion (anion). The cation and anion combine to form a neutral compound.Also, the nomenclature of these compounds follow the IUPAC rules, which have a set of conventions to name compounds based on the elements present and their oxidation states, and the number of atoms of each element in the compound.

Based on the Law of Conservation of Mass,
what mass of products form when baking
soda decomposes?
NaHCO3 → Na₂CO3 + H₂O + CO₂
25.00 g
Give your answer to the correct number of
significant figures.
(g) Sodium Chloride
?g
Enter

Answers

Based on the Law of Conservation of Mass, the mass of products form when baking soda decomposes is 168 g/mole.

What is law of conservation of mass?

Law of conservation of mass is defined as chemical reactions and physical changes cannot build or remove mass in an isolated system. The mass of the reactants and products in a chemical reaction must equal each other according to the law of conservation of mass.

\(\rm 2NaHCO_3 \rightarrow Na_2CO_3 + H_2O + CO_2\)

Mass of baking soda = 2 x molar mass

Molar mass of NaHCO₃ = 84.007 g/mole

Mass of baking soda = 2 x 84.007 g/mole

Mass of baking soda =  168.014 g/mole ≅ 168 g/mole

Thus, based on the Law of Conservation of Mass, the mass of products form when baking soda decomposes is 168 g/mole.

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Write the complete equation for neutralization reactions for LiOh + HNO2

Answers

The complete equation for the neutralization reactions for the LiOH + HNO₂ is as :

LiOH  +  HNO₂ ---->  LiNO₂  +  H₂O

The Neutralization reaction is the reaction as in the chemical reaction in which the acid will reacts with the base and to produce the salt and the water molecule. The general equation of the chemical reaction is as :

HX  +  BOH  -->  BX  + H₂O

The reaction with the LiOH and the HNO₂ is :

LiOH  +  HNO₂ ---->  LiNO₂  +  H₂O

There is the combination of the H⁺ ions and OH⁻ ions that will form the water.

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At 40 °C, the solubility of KNO3 is 65 g/100 g of H2O. In the laboratory, a student mixes 110 g of KCl with 200. g of H2O at a temperature of 40 °C. How much of the KNO3 will dissolve?

Answers

At 40°C, the maximum amount of KNO₃ that can dissolve in 200 g of water is 130 g, but since only 110 g of KCl was added, all the KCl will dissolve, and 71.5 g of KNO₃ will dissolve.

To determine how much KNO₃ will dissolve, we need to compare the amount of KCl that was added to the maximum amount of KNO₃ that can dissolve at the same temperature.

First, we can find the maximum amount of KNO₃ that can dissolve in 200 g of water at 40°C, which is given as 65 g/100 g of water

Maximum amount of KNO₃ that can dissolve

= 65 g/100 g x 200 g

= 130 g

This means that at most, 130 g of KNO₃ can dissolve in 200 g of water at 40°C.

Next, we need to compare the amount of KCl added to the maximum amount of KNO₃ that can dissolve.

The amount of KCl added is 110 g, which is less than the maximum amount of KNO₃ that can dissolve (130 g). Therefore, all of the KCl will dissolve and some of the KNO₃ will dissolve.

To find the amount of KNO₃ that will dissolve, we need to calculate how much KNO₃ would be in 110 g of the solvent (water) if it were saturated with KNO₃

Amount of KNO₃ in 110 g of water

= 65 g/100 g x 110 g

= 71.5 g

This means that 71.5 g of KNO₃ will dissolve in 110 g of water at 40°C.

Therefore, the amount of KNO₃ that will dissolve in the 200 g of water containing 110 g of KCl is 71.5 g.

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The addition of 0.275 L of 1.62 M KCl to a solution containing Ag+ and Pb2+ ions is just enough to precipitate all of the ions
as AgCl and PbCl2. The total mass of the resulting precipitate is 62.37 g. Find the mass of PbCl, and AgCl in the precipitate.

Answers

Answer:

The mass of PbCl₂ is 45.88 grams and the mass of AgCl is 16.48 grams.

Explanation:

As mentioned in the given question, the addition of 0.275 L of 1.62 M KCl is done in a solution that comprise Ag⁺ and Pb²⁺ ions so that all the ions get precipitated. Therefore, the moles of KCl present is,  

Moles of KCl = 0.275 L × 1.62 M = 0.445 moles

Now the reaction will be,  

Ag⁺ + Pb²⁺ + KCl ⇒ AgCl + PbCl₂ + 3K⁺

Now let us assume that the formation of x moles of AgCl and y moles of PbCl₂ is taking place.  

Therefore, mass of AgCl will be x × molecular mass, which will be equal to x × 143.32 grams = 143.32 x grams

Now the mass of PbCl2 formed will be,  

y × molecular mass = y × 278.1 grams = 278.1 y grams

Now the total precipitate will be,  

62.37 grams = 143.32 x + 278.1 y -----------(i)

Now as AgCl and PbCl₂ requires 1:2 ratio of KCl, this shows that x moles of AgCl will require x moles of KCl and y mol of PbCl₂ will require 2*y moles of PbCl₂. Therefore,  

x + 2y = total mass of KCl

x + 2y = 0.445 moles ------ (ii)

On solving equation (i) and (ii) we get,  

x as 0.115 and y as 0.165

Now the mass of AgCl will be,  

143.32 × 0.115 = 16.48 grams

The mass of PbCl₂ will be,  

278.1 × 0.165 = 45.88 grams.  

What happens when an acid reacts with a metal such as sodium?

The temperature decreases.

The acid is converted to a base.

A chemical reaction occurs.

The metal becomes polished and shiny.

Answers

Answer:

a chemical reaction occurs

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