The coulombic force between two ions is reduced to ______ of its original strength when the distance between them is quadrupled.

Answer:

The displacement of the pendulum from equilibrium position is 0.855 of the length of the pendulum.

Explanation:

A pendulum's motion can be modelled as a simple harmonic motion and the differential equation describing simple harmonic motion is given as

(d²x/dt²) + (k/m)x = 0

(d²x/dt²) = acceleration of the pendulum

x = displacement of the pendulum from equilibrium position

k = spring constant of the pendulum = (mg/L) = (0.006×9.8/L) = (0.0588/L)

L = length of the pendulum

m = mass of the pendulum = 6 g = 0.006 kg

(k/m) = (g/L) = (9.8/L)

To calculate the pendulum's acceleration

Initial velocity of the car = 0 mph = 0 m/s

Final velocity of the car = 60 mph = 26.822 m/s

Time taken for velocity change = 3.2 s

Acceleration = (Δv/Δt) = (26.822/3.2) = 8.382 m/s²

(d²x/dt²) + (k/m)x = 0

Becomes

8.383 + (9.8/L)x = 0

(9.8x/L) = -8.382

9.8x = -8.382L

x = -(8.382/9.8) = -0.855 L (the minus sign shows the direction of movement of the pendulum)

Ignoring the sign and only focusing on the magnitude of the pendulum's displacement from equilibrium position, the displacement of the pendulum from equilibrium position is 0.855 of the length of the pendulum.

Hope this Helps!!!

The net force on q1 is 9.94 N.

From Coulomb's Law, the force between two point charges is given by:

where;

All the charges have the same charge and magnitude and are separated by the same distance.

The force between q1 and q2 is:

F12 = (9 * 10⁹ N * m²/C²) * (-2.35 x 10⁻⁶ C)² / (0.100 m)²

F12 = 4.97 N

The positive sign indicates that the force is repulsive

Similarly, the force between q2 and q3 is:

(9 * 10⁹ N * m²/C²) * (-2.35 x 10⁻⁶ C)² / (0.100 m)²

F12 = 4.97 N

The positive sign indicates that the force is repulsive

The net force on q1 will be:

Fnet = F12 + F23

Fnet = 4.97 N + (4.97)

Fnet = 9.94 N

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The truck has a velocity of 10 m/s, then its momentum would be: 1,000,000 kgm/s.

What is velocity?
Velocity is indeed the direction at which an object is moving and serves as a measure of the rate at which its position is changing as seen from a specific point of view and as measured by a specific unit of time (for example, 60 km/h northbound). In kinematics, the area of classical mechanics that deals with the motion of bodies, velocity is a fundamental idea. A physical vector quantity called velocity must have both a magnitude and a direction in order to be defined. Speed is the scalar exact number (magnitude) of velocity; it is a coherent derived unit for whom the quantity is measured in metres per second (m/s or m/s1) in the SI (metric system). In contrast to "5 metres per second east," which is a vector, "5 metres per second," for instance, is a scalar.

The momentum of the 100000 kg truck is equal to the product of its mass and velocity. Therefore, if the velocity of the truck is given, the momentum can be calculated using the following equation:

Momentum = Mass x Velocity

For example, if the truck has a velocity of 10 m/s, then its momentum would be 100000 kg x 10 m/s = 1,000,000 kgm/s.

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Dense because food do be dense tho

The direction in which the 25 kg mass will move is to the Left. The correct option is A.

This is because the force pulling to the left is greater than that to the right.

The velocity of the mass after 1 second will be 0.4 m/s

The velocity of the mass after 2 seconds will be 0.8 m/s

The net force o the mass of 25 kg is given below:

Net force = 20 N - 10 N

Net force = 10 N

The velocity of the mass is given by the formula below:

Velocity = net force * time / mass

velocity after 1 second = 10 * 1 / 25

velocity after 1 second = 0.4 m/s

velocity after 2 seconds = 10 * 2 / 25

velocity after 2 seconds = 0.8 m/s

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Given that,

Number of turns, N = 25

Magnetic field, B = 1.5 T

The coil has a crosssectional area of 0.80 m2

The coil exits the field in 1.0 s.

To find,

Induced emf in the coil.

Solution,

The induced emf in the coil is given by :

\(\epsilon=\dfrac{-d\phi}{dt}\\\\=\dfrac{dB}{dt}\\\\=\dfrac{NBA}{t}\\\\=\dfrac{25\times 1.5\times 0.8}{1}\\\\=30\ V\)

So, the induced emf in the coil is 30 V.

Answer:

B) The lighter gases boiled off of the protoplanets closest to the sun, leaving dust and metals behind to form the inner planets.

Explanation:

Inner planets are smaller and rockier than outer gas planets,outer planets are larger,because of their lower gravity they don't attract extreme amounts of gas in their planets.The four outer planets were so far from the Sun that its winds could not blow away their ice and gases

Answer:  1)Scientists seek to acquire: scientific hypothesis

2)A scale measures the weight of a light object: 0.240 lbs

3)What does the process of scientific inquiry: It starts with a problem to solve or a question to answer

4)A mouse in a maze scurries 41 cm south: 76 cm southwest

5)When might an object's average velocity be equal to its average speed in two dimensions:

If the object moves in a straight line in one direction represented as positive, then the magnitude of average velocity will be equal to the average speed.

6)Using the velocity versus time graph, calculate the acceleration of Object A: 3 m/s^2

7)What is the range of a bullet fired horizontally at a height of 1.5m: 66.4m

8)What two vertical forces act on a falling leaf: weight, friction

9)What is equal and opposite to the applied force: spring force

10)Using the free-body diagram, calculate the net force: 12N, right

11)How does the force of impact during a collision change: it increases

12)The threads of a screw used to fasten two pieces of wood: by increasing the normal force exerted by the wood on the screw thread

13)A 60 kg skier with an initial velocity of 12 m/s coasts up a hill: 2.5m

14)A 1,500 kg car’s speed changes from 30 m/s to 15 m/s: -506,250 (negative 506,250| NOT POSITIVE)

15)What is true about weather: The weather depends on so many conditions that it is not possible to account for them all in any model.

16)A student records the mass of objects A, B, C, and D:  A

17)Newton’s cradle is a contraption where metal balls: friction force

18)In a closed system, an object with a mass of 10 kg: 12kgm/s

19)Given the data, what is the kinetic energy of the: 3J

20)A wedge is a simple machine that is essentially two: A length of 12 in. and a thickness of 2 in.

21)Object A and Object B are at equal distances on opposite: 3/4

22)A geosynchronous satellite has an orbital period of 24: 35,900 km

23)Calculate the eccentricity for the planet if the: 0.0167

24)A planet travels in its orbit close to apogee : the same amount of time

25)If astronomers discovered a new planet and found its: 22.3 AU

Explanation:

Hope this helps you guys!!! <3 (this is for 'A Semester Exam')

Answer:

So it floats

Explanation:

m =3893.40 /10 = 389.340kg (if i use g= 10 not 9.81 -use 9.81 if your syllabus says so)

v = 4.60 m cube

389.340/4.60 =84.64

as density less than that of water 90

so it floats

The ​Projectile Motion Lab​ is focused on a different type of projectile motion - that of a non-horizontally launched projectile.

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Answer:

7.5 m/s².

Explanation:

From the question given above, the following data were:

Mass (m) of object = 0.6 Kg

Force of friction (Fբ) = 1.5 N

Acceleration (a) =?

Next, we shall determine the force of gravity on the object. This can be obtained as follow:

Mass (m) of object = 0.6 Kg

Acceleration due to gravity (g) = 10 m/s²

Force of gravity (F₉) =?

F₉ = mg

F₉ = 0.6 × 10

F₉ = 6 N

Next, we shall determine the net force acting on the object. This can be obtained as follow:

Force of friction (Fբ) = 1.5 N

Force of gravity (F₉) = 6 N

Net force (Fₙ) =?

Fₙ = F₉ – Fբ

Fₙ = 6 – 1.5

Fₙ = 4.5 N

Finally, we shall determine the acceleration of the object. This can be obtained as follow:

Mass (m) of object = 0.6 Kg

Net force (Fₙ) = 4.5 N

Acceleration (a) of object =?

Fₙ = ma

4.5 = 0.6 × a

Divide both side by 0.6

a = 4.5 / 0.6

a = 7.5 m/s²

Therefore, the acceleration of the object is 7.5 m/s²

Answer:

C. the force applied must cause the movement of the object in the same direction as the force

Explanation:

looked it up

The power used, given that a force of 20 N is used to push the shopping cart 3.5 m in 2 seconds is 35 W

First, we shall determine the work done in pushing the cart. Details below:

Wd = Fd

Wd = 20 × 3.5

Wd = 70 J

Finally, we shall determine the power used in pushing the cart. Details below:

P = Wd / t

P = 70 / 2

P = 35 W

Thus, we can conclude that the power used is 35 W

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Meat-eating desert reptiles depend on small animals in their habitat on which they feed.

Meat-eating desert reptiles depend on small animals that lives to their surrounding. On these animals, these meat eating desert reptiles feed and fulfill their requirements of food so we can conclude that meat eating reptiles needs small animals present in the desert for feeding.

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Correct answer:- Class 1

Class 1 aircraft are those whose weight or center-of-gravity limits can sometimes be exceeded by loading arrangements normally used in tactical operations. Therefore, limited loading control is needed.

The aircraft's airframe and powerplant (A&P) technician or repairman keeps accurate weight and balance records, noting any adjustments made as a result of repairs or modifications.

Similar to an airplane, if its center of gravity is too far off the range, it will be heavier on one side than the other and the pilot may lose control of it. The aircraft's longitudinal imbalance is what causes the nose and/or tail to be heavy.

An aircraft's center of gravity (CG) center of gravity (CG) of an aircraft is the point at which, if suspended at that location, the aircraft would balance. The center of gravity must stay within predetermined boundaries set by the aircraft manufacturer since it impacts the stability of the airplane.

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Class 1 aircraft are those whose centre of gravity or weight constraints may occasionally be exceeded by loading configurations typically used in tactical missions. As a result, restricted loading control is required.

A&P technician or repairman for the aircraft maintains accurate weight and balance records, noting any alterations made as a result of repairs or modifications. Like an aeroplane, if it has a centre of gravity that is too far off the range, it will be heavier on one side than the other and the pilot may lose control. The nose and/or tail of the aircraft are disproportionately heavy due to the longitudinal imbalance. The point at which, if held at that location, an aircraft would be in balance is called the centre of gravity (CG).

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Answer:

Wavelength is the distance between successive crests of wave, especially points in a sound wave or electromagnetic

wave.

Explanation:

Answer:

With the same force

Explanation:

Their is always the same reaction when you have a force. In this case it would be the force pairs. If you throw a ball at the wall, it bounces back right? It uses the same force that you did on the ball.

Hope this helps!

Answer:

v = 17.71 m / s

Explanation:

We can work this exercise with the kinematics equations. In general the body is released so that its initial velocity is zero, the acceleration of the acceleration of gravity

                v² = v₀² - 2 g (y -y₀)

                v² = 0 - 2g (y -y₀)

when it hits the stone the height is zero and part of the height of the seagull I

              v² = 2g y₀

              v = Ra (2g i)

let's calculate

              v =√ (2 9.8 16)

              v = 17.71 m / s

Given that the density of heptane is

The mass of heptane is

The density of water is

The mass of water is

The volume of heptane will be

The volume of water will be

Thus, the volume of heptane is 45.32 mL and the volume of water is 37 mL.

The total volume of liquid in the cylinder will be

The total volume of liquid in the cylinder will be 82.32 mL.

When the jumper moves from the cliff then the horizontal component of velocity remains constant as the acceleration in horizontal direction is zero.

But for the vertical velocity the acceleration changes as the accel

5 kg of liquid oxygen at -220°C will have the most thermal energy due to its higher mass and temperature.

Thermal energy is the total heat required to raise the entire mass of a given substance.

Q = mcΔθ

where;

Thus, 5 kg of liquid oxygen at -220°C will have the most thermal energy due to its higher mass and temperature.

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(a) When m₂ is released, its acceleration will be approximately -3.27 m/s².

(b) The tension in the string is approximately -13.08 N.

To determine the acceleration of m₂ when it is released and the tension in the string, we need to consider the forces acting on the system.

(a) Acceleration of m₂:

Since the pulley is assumed to be frictionless, the tension in the string is the same on both sides of the pulley. We can consider the system consisting of m₁ and m₂ as one body. The net force acting on this system is the difference between the weight of m₁ and the weight of m₂:

Net force = m₁g - m₂g

Applying Newton's second law, F = ma, where F is the net force and a is the acceleration, we have:

m₁g - m₂g = (m₁ + m₂)a

Rearranging the equation to solve for the acceleration, we get:

a = (m₁g - m₂g) / (m₁ + m₂)

Substituting the given values, m₁ = 2.00 kg and m₂ = 4.00 kg, and the acceleration due to gravity, g = 9.8 m/s², we can calculate the acceleration:

a = ((2.00 kg)(9.8 m/s²) - (4.00 kg)(9.8 m/s²)) / (2.00 kg + 4.00 kg)

a = (19.6 N - 39.2 N) / 6.00 kg

a = -19.6 N / 6.00 kg

a = -3.27 m/s²

Therefore, when m₂ is released, its acceleration will be approximately -3.27 m/s². The negative sign indicates that the acceleration is in the opposite direction of the gravitational force.

(b) Tension in the string:

The tension in the string can be determined by considering the forces acting on m₂. The net force on m₂ is equal to its mass multiplied by its acceleration:

Net force = m₂a

Substituting the given values, m₂ = 4.00 kg and a = -3.27 m/s², we can calculate the tension:

Tension = (4.00 kg)(-3.27 m/s²)

Tension = -13.08 N

Therefore, the tension in the string is approximately -13.08 N. The negative sign indicates that the tension acts in the opposite direction of the weight of m₂.

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Answer:

\(v=\sqrt{26}~m/s\)

Explanation:

Parametric Equation of the Velocity

Given the position of the particle at any time t as

\(r(t) = (x(t),y(t))\)

The instantaneous velocity is the first derivative of the position:

\(v(t)=(v_x(t),v_y(t))=(x'(t),y'(t))\)

The speed can be calculated as the magnitude of the velocity:

\(v=\sqrt{v_x^2+v_y^2}\)

We are given the coordinates of the position of a particle as:

\(x=5t-3t^2\)

\(y=5t\)

The coordinates of the velocity are:

\(v_x(t)=(5t-3t^2)'=5-6t\)

\(v_y(t)=(5t)'=5\)

Evaluating at t=1 s:

\(v_x(1)=5-6(1)=-1\)

\(v_y(1)=5\)

The velocity is:

\(v=\sqrt{(-1)^2+5^2}\)

\(v=\sqrt{1+25}\)

\(\mathbf{v=\sqrt{26}~m/s}\)

(a) The induced current in the circuit is clockwise.

b. To find the power (P) using P = Fd/t or P = Fv (since d/t = v). Here, F = ILB (from the Lorentz force), so P = (ILB)v.

(a) The induced current in the circuit is clockwise.

This can be determined using the right-hand rule.

As the metal bar moves to the left through the magnetic field directed out of the plane, the generated force on the electrons (Lorentz force) will push them toward the top rail, creating a clockwise current.

(b) To find the rate at which the applied force is doing work on the bar, first calculate the induced EMF (ε) using Faraday's law:

induced EMF (ε) using Faraday's law:

ε = BLv

= (0.65 T) * (0.36 m) * (5.9 m/s)

= 1.389 Tm²/s

= 1.389 V (since 1 Tm²/s = 1 V)

induced current (I) using Ohm's law:

I = ε/R

= 1.389 V / 45 Ω

= 0.03086 A

force (F) from the Lorentz force law, where F = ILB:

F = ILB

= (0.03086 A) * (0.36 m) * (0.65 T)

= 0.00723 N

Finally, we find the power (P) using P = Fv:

P = Fv

= (0.00723 N) * (5.9 m/s)

= 0.04266 W

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      The rate at which an object's velocity with respect to time changes is referred to as acceleration in mechanics. It is a vector quantity to accelerate (in that they have magnitude and direction). The direction of the net force applied on the item determines the object's acceleration.

        The definition of acceleration (symbol: a) in physics or physical science is the rate of change (or derivative with respect to time) of velocity.

       The equation a = v/t denotes acceleration (a), which is the change in velocity (v) over the change in time (t).

     The displacement that an object or particle experiences with respect to time is expressed vectorially as velocity. The meter per second (m/s) is the accepted unit of velocity magnitude (also known as speed).

         When an item is travelling at a constant speed, its acceleration can be zero. There won't be any acceleration because the speed is constant, hence there won't be any change in speed. Zero acceleration is shown by the graph above.

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The resultant of the displacement is 336.5m

The process of splitting a vector into its components is called resolution of the vector. The vectors are splitted into vertical and horizontal component.

For the first displacement;

The vertical component = - 150 sin45 = -106.1 m

The horizontal component = - 150 cos 45° = -106.1 m

For the second displacement;

The vertical displacement = - 85sin90 = -85

The horizontal component = 0

For the third displacement;

The vertical displacement = 550 sin55 = 450.5

The horizontal displacement = 550 cos 55 = 315.5

Sum of vertical component = 450.5-85-106.1 = 263.4

sum of horizontal component = 315.5 -106.1 = 209.4

Using Pythagorean theorem

R = √ 263.4² + 209.4²

R = √113227.92

R = 336.5m

The resultant angle = tan^-1( 263.4/209.4)

= tan^-1(1.26)

= 51.56°

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