Answer: 592.37m
Explanation:
Person D is the blue line.
The total displacement is equal to the difference between the final position and the initial position, if the initial position is (0,0) we have that he first goes down two blocks, then right 6 blocks. then up 4 blocks, then left 1 block.
Now i will considerate that the positive x-axis is to the right and the positive y-axis is upwards.
Then the new position will be, if B is a block:
P =(6*B - 1*B, -2*B + 4*B) = (5*B, 2*B)
And we know that B = 110m
P = (550m, 220m)
Now, then the displacement will be equal to the magnitude of our vector, (because the difference between P and the initial position is equal to P, as the initial position is (0,0)) this is:
P = √(550^2 + 220^2) = 592.37m
Step 7: Explore the Effect of Adding More Mass to the String.
Calculate the average time it took the car to travel 0.25 and 0.50 meters with the three washers attached to the pulley. Record the averages, rounded to two decimal places, in Table C of your Student Guide.
What is the average time it took the car to travel 0.25 meters? _____ seconds.
What is the average time it took the car to travel 0.50 meters? _____ seconds.
Answer:
1.92
2.61
Explanation:
The average time taken by the car to cover a distance of 0.25 meters and 0.50 meters which is based on the three trial times are :
Distance of 0.25 meters = 2.23 seconds
Distance of 0.50 meters = 3.13 seconds
What is Distance?Distance is defined as a numerical or sometimes a qualitative measure of how far objects or points are. Distance can be described as a physical length or as an approximation based on other criteria.
It can be calculated by:
Distance= Speed x time
Where, Distance is in Meter or kilometer
Speed is in meter per second or km/min
Time is in seconds or minutes
From the above formula, we can also calculate the time like for above given information,
Average travel time to cover 0.25 meters :
(Trial 1 time + Trial 2 time + Trial 3 time) ÷ 3
(2.24 + 2.21 + 2.23) ÷ 3
(6.68 ÷ 3) = 2.226667 = 2.23 seconds
Average travel time to cover 0.50 meters :
(Trial 1 time + Trial 2 time + Trial 3 time) ÷ 3
(3.16 + 3.08 + 3.15) ÷ 3
9.39 ÷ 3 = 3.13 seconds
Thus, the average time taken to cover 0.25 and 0.50 meters are 2.23 and 3.13 seconds respectively
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A projectile is launched at ground level with an initial speed of 49.5 m/s at an angle of 40.0° above the horizontal. It
strikes a target above the ground 3.50 seconds later. What are the x and y distances from where the projectile was
launched to where it lands?
x distance
m
y distance
m
Answer:
x = 132.7 m
y = 51.34 m
Explanation:
Given :
Initial speed, u = 49.5 m/s²
Angle of projection, θ = 40°
Time, t = 3.50 seconds
The distance, x = horizontal component ;
Distance = speed * time
Distance = uCosθ * 3.50
Distance = 49.5 * Cos40° * 3.50
Distance = 49.5 * Cos40° * 3.50
Horizontal distance = 132.7 m
Vertical distance, y :
Sy = ut + 1/2gt²
Sy = Vertical distance ; g = 9.8 m/s²
Sy = 49.5 * sin40 * 3.5 - (0.5 * 9.8 * 3.5²)
Sy = 111.36295 - 60.025
Sy = 51.33795 m
x = 132.7 m
y = 51.34 m
What is the wavelength of this wave
\(\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}\)
Actually Welcome to the Concept of the Waves.
Wavelength is the distance between two consecutive crest or trough.
hence, here the distance is 10cm
So the wavelength is 10cm
===> 10 cm
consider the combination of two capacitor c1 and c2 with c2>c1,when connected in parallel,the equivalent capacitance is 8 times the equivalent capacitance of the same connected in series. calculate the ratio of capacitor c2/c1?
Explanation:
Current flowing through the circuit, I = 2A Applying Kirchoff’s Ist law at junction P, I = I1 + I2 I2 = I – I1 …(1) Applying Kirchoff’s Ind law at junction PQSP 5 I1 + 10 Ig – 15 I2 = 0 5 I1 + 10 Ig -15(I – I1) = 0 20 I1 + 10 Ig = 15 I 20 I1 + 10 Ig = 15 x 2 ÷ by 10 21 I1 + Ig = 3 … (2) Applying Kirchoff’s II law at junction QRSQ 10(I1 – Ig ) – 20(I – I1 – Ig ) – 10 Ig = 0 10 I1 – 10g – 20(I – I1 – Ig ) – 10 Ig = 0 10 I1 – 10 – 20 I + 20 I1 -20Ig – 10 Ig = 0 30 I1 – 40 Ig = 20 I ÷ by 10 ⇒ 3 I1 – 4 Ig = 20 I 3 I1 – 4 Ig = 2 I 3 I1 – 4 Ig = 2 x 2
hope this helps :)
A 15 g bullet is fired horizontally into a 3.000 kg block of wood suspended by a long cord. The bullet comes to a rest in the block. Determine the velocity of the bullet if the impact causes the block to swing 10 cm above its initial level
The velocity of the bullet if the impact causes the block to swing 10cm above its initial level is 281m/s.
What is law of conservation of momentum?The law of conservation of momentum determines that the momentum of a system remains conserved after a collision. The initial momentum of a system of two bodies is equal to the final momentum of the system.
After collision, initial K.E. (Kinetic energy) of combined mass = 3 × 10 × 0.1 = 3J
1/2 × 3 × v² = 3
v = √2m/s
Conservation of momentum,
15 × v = 3000 × √2
v = 281m/s
Therefore, the velocity of the bullet is 281m/s.
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In the 4.6 billion year history of the Earth, how many times have continents of our planet gone through major shifts if these shifts happen on average every 395 million years?
Continents have undergone major shifts around 12 times.
To calculate the number of times continents have gone through major shifts in the 4.6 billion year history of the Earth, we can divide the total time span by the average duration between shifts.
Total time span = 4.6 billion years
Average duration between shifts = 395 million years
To convert the total time span to years, we multiply 4.6 billion by 1 billion (1 billion = 1,000 million).
Total time span in years = 4.6 billion years × 1 billion = 4.6 × 10^9 years
Now we can calculate the number of shifts by dividing the total time span by the average duration between shifts:
Number of shifts = Total time span / Average duration between shifts
= (4.6 × 10^9 years) / (395 million years)
≈ 11.65
Therefore, continents of our planet have gone through major shifts approximately 11.65 times in the 4.6 billion year history of the Earth. Since we cannot have a fraction of a shift, we can round the result to the nearest whole number. Thus, continents have undergone major shifts around 12 times.
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List the 6 questions you may apply to formulating a logical, reasonable perspective to any situation.
Steps to formulate a logical, reasonable perspective to any situation are: gather information, identify problem, analyze the situation, consider assumptions, generate solutions, evaluate options, consider your values, make decision and monitor and adjust
What are the 6 questions that may be applied to formulate logical, reasonable perspective to any situation?Here are the six questions that you can apply to formulating a logical, reasonable perspective to any situation:
What are the issues that should be addressed?
What are the relevant facts and data related to this problem or issue?
What assumptions am I making about the problem or issue?
What are the possible solutions or outcomes, and what are the pros and cons of each?
What are my values and priorities related to this problem or issue?
What additional information do I need to make an informed decision or come to a reasonable conclusion?
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Three 7Ω resistors are connected in series across a 10 V battery. What is the equivalent resistance of the circuit?
ANSWER:
21Ω
STEP-BY-STEP EXPLANATION:
Given:
R1 = R2 = R3 = 7Ω
The resistance in a series circuit has the following equation
\(R_{eq}=R_1+R_2\ldots+R_n\)We replacing in this case:
\(\begin{gathered} R_{eq}=R_1+R_2+R_3 \\ R_{eq}=7+7+7 \\ R_{eq}=21\Omega \end{gathered}\)The equivalent resistance of the circuit is 21Ω
Explain how we could test for the accuracy of the period you calculated (and don't mean by using a calculator). How could you experimentally find it?
Answer:
Here are the steps to perform the experiment:
1. Set up a pendulum by suspending a weight from a fixed point using a string or a rod. Ensure that the length of the string or the rod is constant.
2. Displace the weight by a small angle and release it to allow it to oscillate back and forth.
3. Use a stopwatch or a timer to measure the time it takes for the pendulum to complete one full oscillation (i.e., from one extreme position to the other and back to the original position).
4. Repeat the measurement several times to get an average value for the time period.
5. Compare the measured time period to the calculated value using the formula T = 2π√(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity.
If the measured value is close to the calculated value, then the calculated period can be considered accurate. However, if the measured value is significantly different from the calculated value, then the calculated period may need to be revised or further experiments may need to be performed to determine the source of the error.
It is important to note that experimental errors such as human error in measuring the time or the length of the pendulum can affect the accuracy of the measurement. Therefore, it is recommended to repeat the experiment several times to minimize these errors and obtain a more accurate value.
Q2 (2-33): Determine the magnitude of the resultant force and its direction measured counterclockwise from the positive x axis. Given: F1 = 50N F2 = 35N α = 120° B = 25°
The magnitude of the resultant force is 29.29 N. direction is + x- axis.
A resultant force is a single force and related torque received by using combining a system of forces and torques acting on an inflexible frame via vector addition.
A resultant pressure is a general pressure that acts on the object. understand that forces are vectors. when you calculate the consequent force you want to additionally say the course its miles appear in.
Given;
F₁ = 50 N
F₂ = 35 N
α = 120°
B = 25°
Net force along X-axis
Fx = F₁cos30° - F₂sin25°
= 50cos30° - 35sin25°
= 28.509 N
Net force along y axis,
Fy = F₁sin30° - F₂cos25°
=50sin 30° - 35cos25°
= - 6.72 N
Resultant force R = \(\sqrt{Fx^{2} - Fy^{2} }\)
= \(\sqrt{28.509^{2} - 6.72^{2} }\)
= 29.29 N
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What is the perimeter of the entire tessellation
The perimeter of a geometry is na where a is the side and n be the number of sides of the figure. Here, the each sides of the triangle is 5 cm, there are 10 such sides. Therefore, the perimeter is 50 cm.
What is perimeter ?Perimeter of geometry measures the sum of its out side lengths. For example, the perimeter of an equilateral triangle is 3a, where 3 is the number of sides in triangle and a be the measure of its side.
Tessellation is the repeating pattern of same or different shapes. It can be of regular, semi-regular or irregular types. The given tessellation is a regular repeating pattern.
Here, the side of one triangle = 5 cm
It is clear from the figure that, there are 10 such sides for the whole figure.
hence, perimeter = 5 cm × 10 = 50 cm.
Therefore, the perimeter of the entire tessellation is 50 cm.
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What is sound waves
Sound waves are a type of mechanical wave that propagate through a medium, typically air but also other materials such as water or solids.
Characteristics of sound wavesFrequency: the frequency of a sound wave refers to the number of cycles or vibrations it completes per second and is measured in Hertz (Hz).
Amplitude: the amplitude of a sound wave refers to the maximum displacement or intensity of the wave from its equilibrium position. It represents the loudness or volume of the sound, with larger amplitudes corresponding to louder sounds and smaller amplitudes corresponding to softer sounds.
Wavelength: the wavelength of a sound wave is the distance between two consecutive points in the wave that are in phase, such as from one peak to the next or one trough to the next. It is inversely related to the frequency of the wave.
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ចំនុចរូបធាតុមួយចរពាក់កណ្តាលដំបូងនៃចម្ងាយចររបស់វាដោយល្បឿនប, = 2 m/s ហើយកំណាត់ផ្លូវ
ដែលនៅសល់ វាចរដោយល្បឿន I = 3 m/s ដោយប្រើពាក់កណ្តាលដំបូងនៃរយៈពេលសរុបលើកំណាត់ផ្លូវ
និងពាក់កណ្តាលចុងក្រោយដោយល្បឿន 4 = 5 m/s ។
នេះ:
Answer:
Explanation:
??????????
Can someone explain how to do the algebra for this question? I know everything else, I just don’t know how to rearrange the question to solve for v.
Answer:
Refer to the step-by-step Explanation.
Step-by-step Explanation:
Simplify the equation with given substitutions,
Given Equation:
\(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2\)
Given Substitutions:
\(\omega=v/R\\\\ \omega_{_{0}}=v_{_{0}}/R\\\\\ I=(2/5)mR^2\)\(\hrulefill\)
Start by substituting in the appropriate values: \(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2 \\\\\\\\\Longrightarrow mgh+(1/2)mv^2+(1/2)\bold{[(2/5)mR^2]} \bold{[v/R]}^2=(1/2)mv_{_{0}}^2+(1/2)\bold{[(2/5)mR^2]}\bold{[v_{_{0}}/R]}^2\)
Adjusting the equation so it easier to work with.\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)
\(\hrulefill\)
Simplifying the left-hand side of the equation:
\(mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)
Simplifying the third term.
\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2}\cdot \dfrac{2}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)
\(\\ \boxed{\left\begin{array}{ccc}\text{\Underline{Power of a Fraction Rule:}}\\\\\Big(\dfrac{a}{b}\Big)^2=\dfrac{a^2}{b^2} \end{array}\right }\)
\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2 \cdot\dfrac{v^2}{R^2} \Big]\)
"R²'s" cancel, we are left with:
\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5}mv^2\)
We have like terms, combine them.
\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{7}{10} mv^2\)
Each term has an "m" in common, factor it out.
\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)\)
Now we have the following equation:
\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)
\(\hrulefill\)
Simplifying the right-hand side of the equation:
\(\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac12\cdot\dfrac25\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\cdot\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15mv_{_{0}}^2\Big\\\\\\\\\)
\(\Longrightarrow \dfrac{7}{10}mv_{_{0}}^2\)
Now we have the equation:
\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)
\(\hrulefill\)
Now solving the equation for the variable "v":
\(m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)
Dividing each side by "m," this will cancel the "m" variable on each side.
\(\Longrightarrow gh+\dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2\)
Subtract the term "gh" from either side of the equation.
\(\Longrightarrow \dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2-gh\)
Multiply each side of the equation by "10/7."
\(\Longrightarrow v^2=\dfrac{10}{7}\cdot\dfrac{7}{10}v_{_{0}}^2-\dfrac{10}{7}gh\\\\\\\\\Longrightarrow v^2=v_{_{0}}^2-\dfrac{10}{7}gh\)
Now squaring both sides.
\(\Longrightarrow \boxed{\boxed{v=\sqrt{v_{_{0}}^2-\dfrac{10}{7}gh}}}\)
Thus, the simplified equation above matches the simplified equation that was given.
The steps in the heating of the handle of a pan held over a flame are listed below:
Step 1: Heat from the flame travels to the base of the pan
Step 2: Heat from the base of the pan travels through the pan to the part where the handle touches the pan
Step 3: Heat from one end of the handle travels to the other end
By which method is heat transferred in the three steps?
Radiation in Step 1 and conduction in Steps 2 and 3
Conduction in Step 1 and radiation in Steps 2 and 3
Conduction in Step 1 and convection in Steps 2 and 3
Convection in Step 1 and conduction in Steps 2 and 3
Heat transferred in the three steps is Conduction in Step 1 and radiation in Steps 2 and 3.
Which kind of heat transfer can occur in metals?Conduction. The substance itself does not flow when heat is transported through conduction; instead, heat is internally transferred by the vibrations of atoms and molecules. Metals are typically excellent heat conductors because they can also carry electrons, which can carry heat.
The ability of metal to transfer heatIn contrast to atoms, unbound electrons exist in metals. These electrons are free to roam the metal, interacting with the metal atoms and effectively transferring heat to them through collisions. Due of this, metals are generally superior heat conductors than other types of materials.
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A 66.1-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. He then drops through a height of 1.59 m, and ends with a speed of 8.51 m/s. How much nonconservative work (in kJ) was done on the boy?
A 66.1-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. He then drops through a height of 1.59 m, and ends with a speed of 8.51 m/s. The nonconservative work done on the boy is approximately -42.7 kilojoules.
To find the nonconservative work done on the boy, we need to consider the change in the boy's mechanical energy during the process. Mechanical energy is the sum of the boy's kinetic energy (KE) and gravitational potential energy (PE).
The initial mechanical energy of the boy is given by the sum of his kinetic energy and potential energy when he catches the wave:
E_initial = KE_initial + PE_initial
The final mechanical energy of the boy is given by the sum of his kinetic energy and potential energy after he drops through the height:
E_final = KE_final + PE_final
The nonconservative work done on the boy is equal to the change in mechanical energy:
Work_nonconservative = E_final - E_initial
Let's calculate each term:
KE_initial = (1/2) * m * v_initial^2
= (1/2) * 66.1 kg * (1.60 m/s)^2
PE_initial = m * g * h_initial
= 66.1 kg * 9.8 m/s^2 * 1.59 m
KE_final = (1/2) * m * v_final^2
= (1/2) * 66.1 kg * (8.51 m/s)^2
PE_final = m * g * h_final
= 66.1 kg * 9.8 m/s^2 * 0
Since the boy ends at ground level, the final potential energy is zero.
Substituting the values into the equation for nonconservative work:
Work_nonconservative = (KE_final + PE_final) - (KE_initial + PE_initial)
Simplifying:
Work_nonconservative = KE_final - KE_initial - PE_initial
Calculating the values:
KE_initial = (1/2) * 66.1 kg * (1.60 m/s)^2
PE_initial = 66.1 kg * 9.8 m/s^2 * 1.59 m
KE_final = (1/2) * 66.1 kg * (8.51 m/s)^2
Substituting the values:
Work_nonconservative = [(1/2) * 66.1 kg * (8.51 m/s)^2] - [(1/2) * 66.1 kg * (1.60 m/s)^2 - 66.1 kg * 9.8 m/s^2 * 1.59 m]
Calculating the result:
Work_nonconservative ≈ -42.7 kJ
Therefore, the nonconservative work done on the boy is approximately -42.7 kilojoules. The negative sign indicates that work is done on the boy, meaning that energy is transferred away from the boy during the process.
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Verify that the quantity (k/N)Inr, where In,) is equal to the (mean) entropy of the given system. Show that this leads to essentially the same result for In T if we take, in the foregoing summation, only the largest term of the sum, namely the term Wint) that corresponds to the most probable distribution set. ISurprised? Well, note the following example: For all N, the summation over the binomial coefficients N!/Ir! (N-r!)l gives CNG, 2 r-0 therefore nCNIn2. Now, the largest term in this sum corresponds to r N/2; so, for large N, the logarithm of the largest term is very nearly equal to In(N!)-2In((N/2)!) N, N which agrees with (a).J
Because one mole of H X 2 is typically lighter than N e, it stands to reason that it would have a higher entropy than N e. Ne, on the other hand, is thought to have a higher entropy due to its lower molar mass.
A chemical equation can be examined for changes in physical states and the number of moles of product and reactant particles to predict relative changes in entropy using the same factors on a macroscopic level.
The species with the greater molar mass between two monoatomic ones will have a greater standard entropy. The more mobile of two allotropic forms of an element will have a higher standard entropy value. The entropies of these substances are not zero, despite the fact that their conventional internal energies and enthalpies would be. The "energies of formation" of elements in their normal states are typically set to zero because there is no absolute scale of energy.
Entropy, on the other hand, gauges the distribution of energy among the numerous quantum states that can accept it; they exist even in pure substances.
Evidently, entropies often rise with molecule weight. This is, of course, a direct reflection of the fact that translational quantum states are more densely packed in heavier molecules, making them more occupiable, for the noble gases.
The additional impacts of rotational quantum levels are visible in the entropies of the diatomic and polyatomic molecules.
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What is a true statement about models in science? A. Models change to accommodate new discoveries. B. Models are only used by scientists. C. Models never change. D. Models are only used by engineers.
Answer:
Models change to accommodate new discoveries
Explanation:
Owing to the dynamism of science, scientific models also change to accommodate new ideas and discoveries. Science is not a static body of knowledge. Research consistently brings new information to the fore. This propels a change in certain scientific models to accommodate the new discoveries and present a more accurate representation of phenomena in nature.
Hence, scientific models change to accommodate new discoveries.
Answer: Models change to accommodate new discoveries.
Explanation: I took the test
An object of mass 2kg moves in circles at radius 8m at uniform speed of 30m/s calculate. A_angular velocity B_ceritripetal force
The angular velocity is 3.75 m/s and the centripetal force is 225 N respectively.
The angular velocity of an object with respect to some extent is a degree of the way rapid that item actions through the point's view, within the feel of the way speedy the angular function of the item modifications. An instance of angular pace is a ceiling fan. One blade will whole a complete round in a certain amount of time T, so its angular speed with respect to the middle of the ceiling fan is twoπ/T.
Calculation:-
A. angular velocity ω = v/r
= 30 /8
= 3.75 m/s
B. Centripetal force = mv²/r
= 2×30²/8
= 225 N
There are 3 formulations we will use to find the angular velocity. the primary comes instantly from the definition. The angular pace is the rate of alternate of the position attitude of an object with respect to time, so w = theta / t, in which w = angular pace, theta = position attitude, and t = time.
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5. An automobile with a mass of 1000 kilograms accelerates when the traffic light turns green. If the
net force on the car is 4000 Newtons, what is the car's acceleration?
Answer:
Therefore, the acceleration of the car will be 4 (ms2).
If a ball leaves the ground with a velocity of 4.67 m/s,
how high does the ball travel?
Answer:
\(Vf^2=Vo^2+2aS\\(0m/s)^2=(4.67m/s)^2+(2*-10m/s^2)S\\-(4.67)^2 m^2/s^2=-20m/s^2*S\\S=(21.8089/20) m\\S=1.090445 m\\\)
Which of the following explains why the Earth orbits the sun rather than the sun orbiting the Earth?
A. Earth has much smaller mass, so the gravitational force accelerates the Earth much more than it accelerates the sun.
B. The force of Earths gravity pulling on the sun has a smaller magnitude than the force of the sun pulling on Earth.
C. While the Earth is pulled toward the sun with a gravitational force, the sun is not pulled toward the Earth be a gravitational force.
D. Even though the sun is pulled toward the Earth, the force is opposed by forces from the gravity of the planets.
Answer:
A
Explanation:
because like people and earth,the forces acting on earth by people is negligible .
Read the scenario below and answer the question that follows. Randall is hiring cooks for his restaurant. The first applicant is a handsome man with an average resumé and average job experience. The second applicant is a far less attractive man with a slightly above average resumé and above average job experience. Randall decides to hire the first applicant. Based on this information and on Randall’s decision, what might a psychologist conclude about Randall’s social perception? Randall has an unconscious assumption that attractive people are more competent. Randall has a unconscious assumption that unattractive people are bad cooks. Randall has a conscious assumption that attractive people make better cooks. Randall has a conscious assumption that unattractive people are more competent.
Randall has an unconscious assumption that attractive people are more competent.
What is meant by assumption ?The term assumption can be described as an unspoken premise that underlies the conclusion.
Here,
The capacity to accurately evaluate and draw conclusions about other individuals based on their overall physical appearance, verbal behaviour, and nonverbal attitudes is referred to as social perception.
Given that, for his restaurant, Randall is employing chefs. The first applicant is a dashing man with an average resume and career history. The second candidate is a far less appealing man with an average to slightly above average resume and work experience. Randall chooses to hire the first candidate.
This shows the social perception of Randall and his unconscious assumptions against unattractive people.
Hence,
Randall has an unconscious assumption that attractive people are more competent.
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A 10,000 kg freight car is rolling along a track at 3.00m.s.Calculate the time needed for a force of 1000N for stop the car
It takes 0.3 seconds for a force of 1000 N to halt a 10,000 kg goods car moving at 3.00 m/s along a track.
Calculate the time needed for a force of 1000N for stop the carWe must first establish the car's starting kinetic energy in order to calculate the time required to stop the vehicle:
Kinetic Energy (KE) is equal to half of mass times speed, or 10,000 kg times 3.00 m/s.
KE = 45,000 J
Then, we may use the designed with the intent, which asserts that an object's change in kinetic energy equals the jobs performed by an external force: Work equals Force x Distance x Change in KE.
The gain in kinetic energy is equal to the starting kinetic energy because the car is coming to a stop: KE Change = -45,000 J
As a result, the external force's work is: Work equals force times distance, or -45,000 J.
When we solve for distance, we obtain: Work / Force = -45,000 J / 1000 N Distance
Location = -45 m
Because the force is against the direction of the car's motion, you'll see that the range is negative.
Finally, we can calculate the travel time using the kine model for uniformly accelerated motion: Distance is equal to 1/2*acceleration*time2. Time is calculated as sqrt(2 * Distance / Acceleration) as well as sqrt(2 * 45 m / (1000 N / 10,000 kg)).
time equals sqrt(0.09 s2/kg).
time = 0.3 s
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9. When air or water is cools it...
A.) Sinks
B.) Becomes less dense
Answer:
when air or water cools it sinks
Explain/Describe how atoms in domains determine whether a material is magnetic or not. (Please help this is due today)
Answer:
In a material, the magnetic behavior depends on the alignment of magnetic moments of the atoms. Magnetic moments are generated by the motion of the electrons in the atoms. When the magnetic moments of atoms in a material are aligned in a specific pattern, it creates a magnetic field which results in the material being magnetic.
In many materials, the magnetic behavior arises due to the alignment of magnetic domains, which are regions of atoms with magnetic moments aligned in the same direction. When many domains with aligned magnetic moments are present in a material, the material becomes magnetic.
The magnetic behavior of a material depends on the number of electrons and the arrangement of those electrons in the atoms. In particular, for an atom to have a magnetic moment, it must have unpaired electrons, meaning electrons that are not paired with another electron with the opposite spin. When these unpaired electrons in the atoms are aligned, they generate a magnetic moment. If all electrons are paired, there will not be a net magnetic moment, so the material will not be magnetic.
So, in summary, the magnetic behavior of a material is determined by the alignment of magnetic moments of atoms. When the magnetic moments of many atoms in a material align in the same direction, it creates a magnetic field, leading to a material being magnetic. This alignment is usually present in magnetic domains consisting of atoms with unpaired electrons.
two physical quantities that change with temperature
Answer:
i think this is wat u want
if you sit on the edge of a very light table, it is likely the table will topple over. explain?
Answer:
This question heavily relies on the weight of the table and the weight of the person sitting on it, if a 90 pound person sits on the side of a 40 pound table, it will topple over.
Explanation: Tables are generally have a 50/50 weight distribution ratio so that they are even on the ground and can stay upright, but if a table is too light and the person or object sitting on it is heavier than the side they/it is placed on, it will fall.
Who serves as the presiding officer of the Senate?
Who serves as the presiding officer of the Senate?
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The \(\sf\purple{Vice\:President}\) of the United States serves as the presiding officer of the Senate.
At present, \(\sf\red{Kamala\:Harris}\) is the president of the Senate.
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If the total _______ on an object is not zero, its motion will change. A Speed B Gravity C Force D None of the above
Answer:
The correct answer is C) Force. If the total force on an object is not zero, its motion will change according to the second law of motion by Isaac Newton.