The coefficient of performance (COP) of a refrigerator is defined as the ratio of:________
a) the difference between the heat expelled to the outside from the heat removed from the inside to the work done to remove the heat.
b) the heat expelled to the outside to the work done to remove the heat.
c) the heat removed from the inside to the heat expelled to the outside.
d) the heat removed from the inside to the work done to remove the heat.
e) the heat expelled to the outside to the heat removed from the inside.
Answers
Answer:
D
Explanation:
Solution:-
- The refrigeration cycle contains the target refrigerated place and the warm reservoir.
- The purpose of the refrigeration cycle is to exchange heat in the evaporator that consists of a cooling fluid mostly ( R - 134a ) with the air in the target refrigerated place.
- The cooling gas in the cycle is at a much lower temperature than the temperature in the target place.
- The exchange of heat is directed from the targeted refrigerated place to the working fluid in the cycle.
- This is also called the cooling load of the refrigerator / refrigeration cycle ( Ql ).
- The super-heated fluid is then taken to the condenser where heat exchanged with the surrounding which is at much lower temperature than the super-heated fluid in the cycle.
- Since, both the condenser and evaporator work at different pressures. A compressor is installed to pressurize the working fluid to the condenser pressure. Some amount of energy is required to do work on the working fluid of the cycle. This is denoted as the work input to the cycle. ( Win ).
- The performance of a refrigeration cycle is basically expressed as a ratio of desired out-put and the work-input to the cycle ( compressor ).
- The desired output of the refrigeration cycle is to remove heat from the target place via evaporator. So we express the performance of a refrigeration cycle with a parameter known as the coefficient of performance ( COP ):
\(COP_r =\frac{Q_l}{W_i_n}\)
- The ratio of cooling load to work-done on the working fluid.
Answer: The heat removed from the inside to the work done to remove the heat.
Related Questions
A person standing on a scale feels a normal force of 655 N pushing up on him. What is his mass?
Answers
Answer: 66.8 kilograms
What do you think will happen to the potential energy of the ball if the mass of the ball remains the same and placed in a higher position?
Answers
Answer:
Potential energy of the ball would increase
Explanation:
The formula for potential energy of an object is:
Potential Energy (object) = mass x gravity x height
In your question, the value for height is increased when the object (ball) is placed in a higher position. This creates a net positive change in the right-hand side of the formula and since the value of mass and gravity doesn't change because gravity is a constant (meaning it's always 9.8N/kg) and the mass is said to be kept the same, the ball's potential energy would increase.
A tourist, who weighs 705 N, is walking through the woods and crosses a small horizontal bridge. The bridge rests on two concrete supports, one at each end. He stops on the bridge. Assume that the board of the bridge has negligible weight. Where is he standing if the magnitude of the vertical force that a concrete support exerts on the bridge at the near end is 470 N?
а)one-fifth of the way along the bridge b)one-fourth of the way along the bridge c)one-third of the way along the bridge d)one-half of the way along the bridge f)one-sixth of the way along the bridge
Answers
The tourist is standing one-third of the way along the bridge (option c).
How to solveLet's denote the distance from the near end of the bridge to the point where the tourist is standing as x and the total length of the bridge as L.
According to the equilibrium condition, the sum of the forces exerted on the bridge is zero.
So, the vertical forces exerted by the two concrete supports should be equal to the weight of the tourist:
F_near + F_far = 705 N
Given that the magnitude of the vertical force exerted by the near end support is 470 N, we can calculate the force exerted by the far end support:
F_far = 705 N - 470 N = 235 N
Now, we can use the moment equilibrium condition, considering moments around the near end support:
Moment = Force × Distance
For the tourist:
Moment_tourist = 705 N × x
For the far end support:
Moment_far = 235 N × L
For equilibrium, the sum of the moments should be zero:
Moment_tourist - Moment_far = 0
Substituting the moments:
705 N × x - 235 N × L = 0
Now, we can solve for x/L, which represents the fraction of the way along the bridge where the tourist is standing:
x/L = (235 N × L) / 705 N
x/L = 235/705 = 47/141 ≈ 1/3
So, the tourist is standing one-third of the way along the bridge (option c).
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A box has a mass of 5.8 kg. the box is lifted from the garage floor and placed on a shelf. if the shelf is 2.5 m high, what is the potential energy of the box?
Answers
PE = mgh
PE = 5.8 x 9.8 x 2.5
PE = 142.1 J
the answer is 140 J and my work is on the paper, hope it helps!
A bus is moving with
a velocity of lom/s. After 2 sec its velocity
becames 20/s find the distance from travelled
by a bus at that this time of interval
Answers
Answer:
30 m
__________________________________________________________
Explanation:
We are given:
Initial velocity (u) = 10 m/s
Final velocity (v) = 20 m/s
Time interval (t) = 2 seconds
Distance travelled by the bus (s) = s meters
Solving for the distance travelled:
Solving for the acceleration:
v = u + at [first equation of motion]
20 = 10 + a(2) [replacing the given values]
2a = 10 [subtracting 10 from both sides]
a = 5 m/s² [dividing both sides by 2]
Solving for the distance:
s = ut + 1/2 (at²) [second equation of motion]
s = 10(2) + 1/2(5)(2)² [replacing the given values]
s = 20 + 10
s = 30 m
Therefore, the bus travelled 30 m in the given time interval
Assume |g| = 10 m/s^2
Answers
A free-body diagram of the block on the frictional part of the surface would show the force of friction acting in the opposite direction to the velocity of the block, and the force of gravity acting downward.
Using conservation of energy, the speed of the block at the base of the ramp can be found by setting the initial kinetic energy of the block (1/245^2) equal to the final kinetic energy of the block (1/2mv^2) and solving for v. v = sqrt((1/245^2)/(1/2*m)) where m is the mass of the block.
Using conservation of energy, the maximum vertical height H of the block on the ramp can be found by setting the initial potential energy of the block (mgH) equal to the final kinetic energy of the block (1/2mv^2) and solving for H. H = (1/2mv^2)/(m*g)
a) The total impulse given to the mass on the spring (mass A) during the brief collision is the product of the force exerted on the mass by the block and the time duration of the collision.
b) The speed of the mass on the spring (mass A) immediately after the collision can be determined using the conservation of momentum.
c) The velocity of the block immediately after the collision can also be determined using the conservation of momentum.
d) The spring constant can be determined by using the equation k = (2*F)/x, where F is the force exerted on the spring and x is the compression of the spring.
To find the horizontal range of the block from the end of the ramp, we can use the equations for horizontal and vertical motion of a projectile, with the angle of launch being 30 degrees, the initial speed being 6 m/s, and the final vertical position being 1m above the end of the ramp.
Think about a hot air balloon travelling around the world in 11 days. How can a balloon travel so far and fast without a engine or other system on board to move the balloon horizontally
Answers
Answer:
?
Explanation:
At the gym, a man pulls a bar on a machine that works the muscles of the upper back. It takes him 0.5 seconds to raise 30 kilograms of weights a vertical distance of 0.5 meters. Which of these exerts the same power output? (Estimate g as 10 m/s2.)
A) lifting 25 kilograms a distance of 2.4 meters in 2.0 seconds
B) lifting 45 kilograms a distance of 2.4 meters in 3.0 seconds
C) leg pressing 45 kilograms a distance of 0.5 meters in 0.5 seconds
D) bench pressing 30 kilograms a distance of 0.5 meter in 1.5 seconds
Answers
Answer: Lifting 25 kilograms a distance of 2.4 meters in 2.0 seconds
Explanation:
Got it wrong and that’s the answer
Lifting 25 kilograms a distance of 2.4 meters in 2.0 seconds exerts the same power output. Hence, option (A) is correct.
What is power?The quantity of energy moved or converted per unit of time is known as power in physics. The watt, or one joule per second, is the unit of power in the International System of Units.
Power is also referred to as activity in ancient writings. A scalar quantity is power.
Power required for lifting 30 kilograms of weights a vertical distance of 0.5 meters in 0.5 second = (30×9.8×0.5)/0.5 watt = 294 watt.
Power required for lifting 25 kilograms a distance of 2.4 meters in 2.0 seconds= (25×9.8×2.4)/2.0watt = 294 watt.
Power required for lifting 45 kilograms a distance of 2.4 meters in 3.0 seconds = (45×9.8×2.4)/3.0watt = 352.8 watt.
Power required for lifting 45 kilograms a distance of 0.5 meters in 0.5seconds = (45×9.8×0.5)/0.5watt = 441 watt.
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15. A vector a in the xy-plane has a length of 9 units and points in a direction that is 120° counterclockwise from the pos- itive x-axis, and a vector b in that plane has a length of 5 units and points in the positive y-direction. Find a . b.
Answers
Using the given data table, calculate the acceleration of the skateboarder. You can use either form of the
equation:
Answers
The acceleration of skateboard on road A will be 7.74 \(m/s^{2}\)
The acceleration of skateboard on road B will be 3.87 \(m/s^{2}\)
The acceleration of skateboard on road C will be 9.68 \(m/s^{2}\)
force = mass * acceleration
mass1 = 62 kg
force1 = 480 N
acceleration1 = force / mass
= 480 / 62 = 7.74 \(m/s^{2}\)
mass2 = 62 kg
force2 = 240 N
acceleration 2 = 240 / 62 = 3.87 \(m/s^{2}\)
mass 3 = 62 kg
force 3 = 600 N
acceleration 3 = 600 / 62 = 9.68 \(m/s^{2}\)
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cheese is made of cheese
Answers
Cheese is made of casein protein, which is originally made from milk and is high in protein. The texture of the cheese is determined by the quality of the milk, so cow's milk cheese differs from goat's milk cheese.
What is a dairy product?
Diary products are made from milk, such as cheese, curd, yogurt, etc., but all of them have different nutrients. The quality of these dairy products depend upon the quality of the milk, as some milking animals have a higher concentration of fats in their milk than other animals. These dairy products are used in different industrial sectors, such as for making ice cream, chocolate, and different food products.
Hence, cheese is made up of casein proteins that are present in the milk.
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. The force of gravity on the Moon is said to be one-sixth of that on the Earth. What would a mass of 12 kg weigh; (a) on the Earth
Answers
A. The weight of the mass on the earth is 117.6 N
A. The weight of the mass on the moon is 19.56 N
How do i determine the weight of the mass?Weight is defined as follow:
Weight (W) = mass (m) × Acceleration due to gravity (g)
W = mg
Now we shall determine the weight. Details below:
A. Weight on earth
Mass (m) = 12 KgAcceleration due to gravity on earth (g) = 9.8 m/s² Weight on earth (W) =?Weight (W) = mass (m) × Acceleration due to gravity (g)
Weight (W) = 12 × 9.8
Weight on earth = 117.6 N
B. Weight on moon
Mass (m) = 12 KgAcceleration due to gravity on earth (g) = 9.8 m/s² Acceleration due to gravity on moon (g) = (1/6) × 9.8 = 1.63 m/s² Weight on moon (W) =?Weight (W) = mass (m) × Acceleration due to gravity (g)
Weight (W) = 12 × 1.63
Weight on moon = 19.56 N
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Complete question:
The force of gravity on the Moon is said to be one-sixth of that on the Earth. What would a mass of 12 kg weigh; (a) on the Earth (b) on the moon
Una anciana camina 0.30 km en 10 minutos dando la vuelta un centro comercial calcule su rapidez media 
Answers
The average speed of the elderly woman walking around the shopping center is 1.80 km/h.
To calculate the average speed of the elderly woman, we can use the formula for velocity, which is equal to the distance traveled divided by the time taken. In this case, the distance traveled is 0.30 km and the time taken is 10 minutes. However, average speed is generally expressed in units of distance per unit of time, so we need to convert minutes to hours.
There are 60 minutes in one hour, so 10 minutes is equal to 10/60 = 1/6 hours.
Now we can calculate the average speed by dividing the distance traveled (0.30 km) by the time taken (1/6 hours):
Average speed = 0.30 km / (1/6 h)
= 0.30 km * (6/1 h)
= 1.80 km/h
Therefore, the average speed of the elderly woman walking around the shopping center is 1.80 km/h.
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Can you help with this ?
Answers
Answer
25 miles/hour
Explanation
Given that,
A pilot can travel with wind = 416miles
A pilot can travel against wind = 336miles
A pilot can speed without wind = 235miles/hour
let wind speed = v miles/hr
pilot's speed with the wind = 235+ v
pilot's speed against the wind = 235 - v
Time = distance / speed
416 / (235 + v) = 336 / (235 - v)
416(235 - v) = 336(235+v)
97760 - 416v = 78960 + 336v
97760 - 78960 = 416v + 336v
18800 = 752v
v = 18800/752
v = 25 miles/hour
wind speed = 25 mph
Given the functions f(x)=(1/x-3)+1 and g(x) = (1/1+4)+3
Which statement describes the transformation of the graph of function f onto the graph of function g?
O The graph shifts 2 units right and 7 units down.
O The graph shifts 7 units left and 2 units up.
O
e graph shifts 7 units right and 2 units down.
O The graph shifts 2 units left and 7 units up.
Answers
The statement that describes the transformation of the graph of function f onto the graph of function g is: The graph shifts 2 units right and 7 units down.
To determine the transformation of the graph of function f onto the graph of function g, we compare the two functions f(x) and g(x) and observe the changes in the equations.
The function f(x) = (1/x - 3) + 1 represents a reciprocal function that is shifted vertically 1 unit up and horizontally 3 units to the right. The reciprocal function is reflected about the line y = x.
The function g(x) = (1/(1 + 4)) + 3 simplifies to g(x) = 4 + 3 = 7, which is a constant function representing a horizontal line at y = 7.
By comparing the equations, we can see that the transformation from f(x) to g(x) involves the following changes:
The term 1/x in f(x) is replaced by the constant 1/(1 + 4) in g(x), resulting in a vertical shift of 7 units up.
The term -3 in f(x) is replaced by 3 in g(x), resulting in a vertical shift of 3 units up.
The +1 in f(x) is replaced by +3 in g(x), resulting in an additional vertical shift of 2 units up.
Therefore, the overall transformation is a shift of 2 units to the right and 7 units down.
Hence, the correct statement is: The graph shifts 2 units right and 7 units down.
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A canister filled with 3.5 mol of single-atom helium gas has a temperature of
300 K. What is the approximate total internal energy of the gas? (Recall that the equation for kinetic energy due to translation in a gas is: 3/2 nRT; the
equation for kinetic energy due to rotation of a molecule in a gas is: nRT, and R= 8.31 J/(mol.K).)
R= 8.31 J/(mol-K).)
A. 13,100 J
B. 5800 J
C. 15,400 J
D. 8200 J
Answers
The answer is C
Please dont get mad at me if this is not right im pretty sure it is
hope this helps!
An owl has a mass of 4 kg. It dives to catch a mouse, losing 800 J of its GPE. What was the starting height of the owl, in meters?
Answers
The owl started out at a height of about 3.2 metres.
What is gravity?Gravity is the force that draws objects toward the center of a planet or other object.
How do you determine this?Gravitational potential energy (GPE) is calculated as follows:
GPE = mass x gravity x height. Since we are aware of the owl's mass (4 kg) and the change in GPE (-800 J) in this case, we can rewrite the formula to account for the height: tallness = GPE / (mass x gravity).
On Earth, the acceleration caused by gravity is roughly 9.8 m/s2.
By entering the known numbers, we obtain the height change as follows: -800 J / (4 kg x 9.8 m/s2) = -0.408 metres.
By combining the ultimate height (which is believed to be 0 metres) with the height change, we may get the initial height as follows: 0 m + (-0.408 m) = -0.408 m = 0.408 m = 3.2m.
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A light-year (ly) is the distance light travels in one year (at speed of 2.998 × 108 m/s). An astronomical unit (AU) is the average distance from the Sun to Earth, 1.50 × 108 km. 1 year = 3.156 × 107 s.
A) How many meters are there in 1.90 ly?
B) How many AU are there in 1.90 ly?
Answers
Answer:.47 x 10 *15* meters in 1.00 ly
there are 6.31 x 10 *4* au on 1.00 ly
Explanation:
the x-component is the width and the y-compenent is the height
Answers
From the diagram we have that H is -30 km in the x-direction and 20 km in the y-direction.
We also have that F is -30 km in the x-direction and -30 km in the y-direction.
Then the resultant will be -60 km in the x-direction and -10 km in the y-direction.
Then the table woluld be:
The magnitude of the resultant is:
\(\begin{gathered} R=\sqrt[]{(-60)^2+(-10)^2} \\ R=60.83 \end{gathered}\)Therefore its resultant is 60.83 km (using two decimals).
The angle is given by:
\(\begin{gathered} \theta=\tan ^{-1}(\frac{10}{60}) \\ \theta=9.46 \end{gathered}\)Now, this is the angle in the third quadrant. Therefore the angle measuere from the x-axis CCW is 189.46°
What is the difference between an isovolumetric process and an isobaric process in terms of work?
Answers
A thermodynamic process is a chemical or physical process that takes place in a thermodynamic system, which changes the system from an initial state to a final state. There are different forms of thermodynamic processes. Isobaric and isovolumetric processes are two of these processes.
The key difference between the isobaric and isovolumetric processes is that the isobaric process occurs at constant pressure while the isovolumetric process occurs at constant volume.
It takes 85N of force to accelerate a ball at a rate of 15 m/s². What is the mass of the ball?
Answers
Explanation:
F = ma
85 N = m (15 m/s²)
m ≈ 5.7 kg
A horizontal spring with a constant of 3000 N/m is compressed 4.0 cm from equilibrium. A 2.0 kg mass is placed on front of the compressed spring and then is released. The object drags on a flat surface with a coefficient of friction equal to .23 and eventually comes to rest. How far from the spring does the mass travel?
Answers
Regarding a spring-mass system's duration, the square root of the mass and the spring constant have opposing correlations. The length of spring will be longer and vice versa as the mass grows. Therefore, the mass influences spring.
What far from the spring does the mass travel?They swing back and forth around a stationary point. Classic examples of this type of vibrating motion are a simple pendulum and a mass on a spring.
Therefore, The use of motion detectors demonstrates that the vibrations of these objects have a sinusoidal nature, even if this is not obvious from plain viewing.
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A vehicle, starting from rest, accelerates on a circular track with a 335m diameter.
Answers
The distance travelled by the vehicle around the circular track is 1,052.4 m.
What is the distance travelled by the vehicle in one complete cycle?
The distance travelled by the vehicle in one complete cycle is calculated by using the following equation as show below.
d = 2πr
d = πd
Where;
r is the radius of the circular trackd is the diameter of the circular trackIn one complete cycle, the vehicle will travel the circular track only once.
d = π(335 m)
d = 1,052.4 m
Thus, the distance travelled by the vehicle around the circular track is a function of the diameter of the circular track.
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The complete question is below:
A vehicle, starting from rest, accelerates on a circular track with a 335m diameter. What is the distance travelled by the vehicle when it makes one complete cycle?
Describe the setup of the electromagnet. Why does the wire need to be a conductive material?
Answers
An electromagnet consists of a conductive wire wrapped around a magnetic core, creating a magnetic field when an electrical current is passed through it.
An electromagnet is a type of magnet that is created by running an electrical current through a wire. The setup of an electromagnet involves a few basic components. First, there must be a wire that is conductive, meaning that it can conduct electricity. This wire is usually wrapped around a core, which is often made of iron, steel, or another magnetic material. When an electrical current is run through the wire, it creates a magnetic field around the wire. This magnetic field then magnetizes the core, creating an even stronger magnetic field. The strength of the electromagnet can be controlled by adjusting the amount of current that is run through the wire. The wire must be a conductive material because it needs to be able to carry the electrical current that creates the magnetic field. If the wire were not conductive, then the electrical current would not be able to flow through it, and the magnetic field would not be created. In summary, the setup of an electromagnet involves a conductive wire wrapped around a magnetic core, which is magnetized by the electrical current running through the wire. The wire must be conductive to carry the electrical current and create the magnetic field.For more questions on electromagnet
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A soccer player kicks a ball, applying a force of 1,000 newtons over a distance of 0.2 meter. The ball travels 50 meters down the field before another player stops the ball. How much work was done during the kick?
Answers
The total work done on the ball by the soccer player is 50,200 J.
Work done by applied forceThe work done by the applied force is the product of the applied of the applied force and the displacement of the object.
The work on the ballThe work done on the ball is calculated as follows;
W = Fd
W = 1000 x (0.2 + 50)
W = 50,200 J
Thus, the total work done on the ball by the soccer player is 50,200 J.
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A spring is compressed 1.3 cm. How far must you compress a spring with twice the spring constant to store the same amount of energy?
Answers
Answer:
Explanation:
The energy stored is E = 1/2 kx^2.
E1 = E2
1/2 k(1.3)^2 = 1/2 (2k)x^2
x^2 = 1/2 (1.3)^2
x = 1.3/sqrt(2) cm
x =0.919 cm
rate me thanks
Compression in a spring with twice the spring constant to store the same amount of energy is 0.919 cm
What is energy?Energy is the ability or capability to do tasks, such as the ability to move an item (of a certain mass) by exerting force. Energy can exist in many different forms, including electrical, mechanical, chemical, thermal, or nuclear, and it can change its form.
Given spring is compressed 1.3 cm. Compression in a spring with twice the spring constant to store the same amount of energy is,
The energy stored is E = 1/2 kx².
E1 = E2
1/2 k(1.3)² = 1/2 (2k)x²
x^2 = 1/2 (1.3)²
x = 1.3/√2 cm
x = 0.919 cm
Compression in a spring with twice the spring constant to store the same amount of energy is 0.919 cm.
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A student is using two circuits to investigate power consumption. She connects two identical light bulbs in series in one circuit and in parallel in the second circuit. What should she measure to calculate which configuration uses more power?
Responses
A The resistance of the bulbs and the potential difference of the battery.The resistance of the bulbs and the potential difference of the battery.
B The current flowing into each bulb and the potential difference across each bulb.The current flowing into each bulb and the potential difference across each bulb.
C The current flowing out of the battery and the resistance of each bulb.The current flowing out of the battery and the resistance of each bulb.
D The potential difference of the battery and the resistance of the battery.
Answers
The potential difference across the each bulb and the current entering each bulb.
What occurs if you connect two light bulbs in series?Each bulb in a straightforward parallel circuit receives the entire battery power. This is explains why the parallel circuit's lights will shine stronger than the series circuit's. The parallel circuit also has the benefit of maintaining an electricity even if one loop is disconnected.
When are two identical bulbs linked in both series and parallel?The same brightness is produced when two identical bulbs are linked in parallel as it is when they are connected in a series, which is why.
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three ballot boxes are connected by cords, one of which wraps over a pulley having negligible friction on its axle and negligible mass. The masses are mA = 34 kg, mB = 44 kg, and mC = 10 kg. When the assembly is released from rest, (a) what is the tension in the cord connecting B and C, and (b) how far does A move in the first 0.300 s (assuming it does not reach the pulley)?
Answers
(a) The tension in the cord connecting B and C=98N.
(b) A moves 544.44m in the first 0.300s.
The tension in the cord connecting B and C can be found by applying Newton's second law to the system. The forces acting on the system are the tension in the cord connecting B and C, the weight of the boxes, and the friction between the boxes and the ground.
The tension in the cord connecting B and C can be found by summing the forces in the vertical direction and setting them equal to the mass of the system times the acceleration of the system.
∑Fy = mC*a
T - mC*g = mC*a
Solving the tension gives:
T = mC*a + mC*g
The acceleration of the system can be found by summing the forces in the horizontal direction and setting them equal to the mass of the system times the acceleration of the system.
∑Fx = mA*a
T - mB*g - friction = mA*a
Solving for the acceleration gives:
a = (T - mB*g - friction)/mA
Substituting this expression for the acceleration into the equation for the tension gives:
T = mC*(T - mB*g - friction)/mA + mC*g
Solving the tension gives:
T = (mC*mB*g + mC*friction)/(mA + mC)
The distance that A moves in the first 0.300 s can be found using the equation for the position of an object undergoing constant acceleration:
x = x0 + v0*t + (1/2)*a*t²
The initial position and velocity of A are both zero, so the equation simplifies to:
x = (1/2)*a*t²
Substituting the expression for the acceleration into this equation gives:
x = (1/2)*(T - mB*g - friction)/mA*t²
Substituting the expression for the tension into this equation gives:
x = (1/2)*(mC*mB*g + mC*friction)/(mA + mC)*t²
Plugging in the values for the masses, the friction, and the time gives:
x = (1/2)*(10*44*9.8 + 10*0)/(34 + 10)*0.300²
x = 544.44 m
Therefore, when the given assembly is released from rest,
(a) the tension in the cord connecting B and C is T = (10*44*9.8 + 10*0)/(34 + 10) = 98 N
(b) the distance that A moves in the first 0.300s are x = 544.44m.
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The thermal efficiency of a power cycle operating in a reversible manner is found to be 50%. Assuming that the same 2 thermal reservoirs are now used to power a reversible refrigeration system and then a reversible heat pump, determine the Coefficient of Performance of these two systems.
Answers
Answer:
Explanation:
The thermal efficiency of a Power cycle \(\eta = \dfrac{Q_H -Q_c}{Q_H}\)
where;
\(\eta = 50\% = 0.5\)
\(Q_H = Heat \ flow \ from \ higher \ temperature\)
\(Q_c = Heat \ flow \ from \ lower \ temperature\)
\(0.5 = \dfrac{Q_H -Q_c}{Q_H}\)
\(0.5 Q_H = Q_H - Q_c\) --- (1)
\(Q_c = 0.5 Q_H\) ---- (2)
The coefficient of performance is:
\(COP_R = \dfrac{Q_c}{Q_H -Q_c}\)
let replace the value of \(Q_c = 0.5 Q_H\) in the above equation then;
\(COP_R = \dfrac{0.5Q_H}{Q_H -0.5 Q_H}\)
\(COP_R = \dfrac{0.5Q_H}{0.5 Q_H}\)
\(COP_R = 1\)
The
On the other hand, the heat pump
\(COP_{HP} = \dfrac{Q_H}{Q_H -Q_c}\)
By replacing equation (1) into the above equation; we have:
\(COP_{HP} = \dfrac{Q_H}{0.5Q_{H}}\)
\(COP_{HP} = \dfrac{1}{0.5}\)
\(COP_{HP} =2\)
t
Just as optical astronomers observe the visible light emitted by objects such as stars and galaxies, radio astronomers can also observe the radio waves emitted by these objects, as well as the radio waves emitted by gas and dust. However, radio telescopes are different from optical telescopes in important ways. In general, compared to optical telescopes, radio telescopes are larger. more curved. more expensive. smaller. This is because
Answers
Answer:
Radio telescopes are LARGER than optical telescopes and this is because radio wavelengths are much longer than optical wavelengths
Explanation:
In general radio telescopes are LARGER than optical telescopes and this is because radio wavelengths are much longer than optical wavelengths.
The main difference between radio telescopes and other telescopes especially optical telescopes is based on size and wavelength of both telescopes