The Code generally requires receptacles installed in an unfinished basement to be GFCI protected. The exception(s) to the general rule includes a single receptacle installed to serve a permanently installed alarm system (true or false)

Answers

Answer 1

The given statement, The Code generally requires receptacles installed in an unfinished basement to be GFCI protected. The exception(s) to the general rule includes a single receptacle installed to serve a permanently installed alarm system, is true because unfinished basements are considered to be damp and potentially hazardous environments.

The National Electrical Code (NEC) generally requires that all receptacles installed in unfinished basements be protected by ground-fault circuit interrupters (GFCIs) to prevent electrical shock hazards. However, there are some exceptions to this rule.

One of the exceptions is for a single receptacle that is installed to serve a permanently installed alarm system in the unfinished basement. Such a receptacle does not need to be GFCI protected, as long as it is designated as a dedicated branch circuit for the alarm system and meets other applicable code requirements.

It's worth noting that local electrical codes may have additional requirements or exceptions, so it's always a good idea to consult with a licensed electrician or local code authority for specific information related to your installation.

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Related Questions

HELP PLEASE AND HURRRRRY
How far a projectile moved horizontally from its starting point is its...
A. trajectory
B. Elipse
C. Range
D. Projectile

Answers

Answer:

the path the object follows is called its trajectory so A. trajectory

when developing an experemental design, which action could a scientist take to improve thye quality of results

Answers

Answer:

i dont know i want points tho

Explanation:

The mass of the earth is 6x10^24 kg and that of the moon is 7.4x10^22 kg. If the radius of the moon is 1740 km, then find the value of g if the earth is compressed into the size of moon.​

Answers

Answer:

In the surface of the moon, gravitational acceleration is 1.63 m/s*2.

Explanation:

An object of mass M will accelerate gravitationally at a distance R if it is at the following distance:

g = G*M/R^2

Where the gravitational constant is G.

G = 6.67*10^(-11) m^3/(kg*s^2)

At the surface of a moon, the distance between its surface and its center will be equal to its radius, since a moon's mass is concentrated at its center, thus:

R = 1740 km

It's important to remember that we need meters in order to work:

1 km = 1000 m

so:

1740 km = (1740)*1000 m = 1740000 m

R =  1740000 m

Basically, the mass consists of:

M = 7.4x10^22 kg

Incorporating all that into the gravitational acceleration equation, we get:

g = (6.67*10^(-11) m^3 / (kg*s^2))*(7.4x10^22 kg) / ( 1740000 m)^2

g = 1.63 m / s^2

In the surface of the moon, gravitational acceleration is 1.63 m / s*2.

What is the equation for burning a fossil fuel

Answers

Answer:

Fuel + O2 → CO2 + H2O

Explanation:

A force of 5 n and a force of 15 n acting on an object can produce the following net forces except.

Answers

The net force that it would produce here is 20N

How to calculate the net force?

F(net)= F1 + F2

F1=15N

F2=5N

therefore

15+5 = 20N

The vector sum of the forces exerted on a particle or object is known as the net force.

The net force is a single force that cancels out the original forces' influence on the motion of the particle.

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Why would a person who weights 100 lbs. on earth weight significantly More on Jupiter?

A. Jupiter has more gravitational force then earth

B.Jupiter is farther away from sun

C.Jupiter has no atmosphere

Answers

Im pretty sure the answer is A)

The correct answer would be A

Because Jupiter's radius balloons to roughly 11 times as large as Earth's, its gravitational force drops off by a factor of 1/112 at its surface (assuming you could find a way to stand on gas clouds).

Hope this helps!!

c) What is the time interval in which the average velocity is


Zero?


Negative?



Positive?

a) Find the displacement (value and direction) between t = 0 and t = 5 s.

Answers

Answer:

Is always negative answer for you

A sound signal traveling underwater has a frequency of 230 hertz. The speed of sound under water is 1. 45 × 103 meters/second. What is the wavelength of the sound signal? A. 6. 3 meters B. 2. 3 meters C. 3. 0 meters D. 1. 2 meters E. 9. 3 meters.

Answers

Answer:

A.6.3

Explanation:

What is the average velocity of a man who runs forward at 8 m/s for 9 s and back again at 5 m/s for 3 s after an 8 s break?What is the average velocity of a man who runs forward at 8 m/s for 9 s and back again at 5 m/s for 3 s after an 8 s break?

Answers

The average velocity of a man who runs forward at 8 m/s for 9 s and back again at 5 m/s for 3 s after an 8 s break is 7.25 m/s.

The average velocity of the man in this scenario can be found by dividing the total distance traveled by the total time spent moving.

The total distance traveled while running forward is 8 m/s * 9 s = 72 m, and the total distance traveled while running back is 5 m/s * 3 s = 15 m.

The total distance traveled is 72 m + 15 m = 87 m. The total time spent moving is 9 s + 3 s = 12 s.

Therefore, the average velocity is 87 m / 12 s = 7.25 m/s.

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what are the consequences of how the earth is heated by the sun?

Answers

Strong storms and hurricanes are the consequences of how the Earth is heated by the sun.

The upper troposphere becomes warmer as the lower stratosphere warms. When the troposphere and the planet's surface are at opposite temperatures, significant updrafts result, which intensifies storms and hurricanes. Updrafts and storm power are diminished during the height of the 11-year solar cycle.

Troposphere, stratosphere, mesosphere, and thermosphere are the layers of the atmosphere. The stratosphere, which contains the ozone layer, is the part of the Earth's atmosphere that is most affected by the sun. The stratosphere, which is where weather happens, is followed by the troposphere.

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what happens to the molecules when carbon dioxide is heated

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When the molecules of carbon dioxide is heated, it is disintegrated into molecules of carbon monoxide and oxygen atoms.

CO2 → CO + O

This is the basic reaction expected to happen by carbon dioxide molecules are heated. However it may also disintegrate into C2, O2, C, etc.

Since heat is absorbed in this reaction, it is an example of endothermic reaction. In an exothermic reaction heat is released. These are the basic two types of chemical reactions on basis of heat.

Therefore, when the molecules of carbon dioxide is heated, it is disintegrated into molecules of carbon monoxide and oxygen atoms.

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an object is thrown with an initial horizontal velocity of 10 meters per second and take approximately 9 seconds to reach the ground.considering air resistance to be negligible. what horizontal distance did the object travel​

Answers

The horizontal velocity was constant, so:

\(s = vt\)

\(s = 10\cdot9\)

\(s = 90\)

it traveled 90meters

what do you understand by domestic wiring or what are household electric circuits ??


please answer quick !!!​

Answers

Explanation:

Domestic wiring is house wiring were phase/live wire,neutral wire,earth wire is used that functions in giving the electricity to our home except in case of neutral wire

A droplet of ink in an industrial ink-jet printer carries a charge of 2.1×10?10C and is deflected onto paper by a force of 3.2×10?4N. Find the strength of the electric field (E=F/q) required to produce this force. Express your answer to two significant figures and include the appropriate units.

Answers

The electric field strength needed to generate this force is roughly 1.5 x 106 N/C

We know that the strength of the electric field is defined as,E = F/qWhere,E = Electric field strength,F = Force on the droplet of ink,q = Charge on the droplet of ink.Therefore, putting the given values, we get: E = (3.2 × 10⁻4 ) / (2.1 ×10-4 ) = 1.5 × 10⁶ N/C.

Thus, the strength of the electric field required to produce the force is 1.5 ×10⁶ N/C (two significant figures). Therefore, the final answer is 1.5 × 10⁶ N/C.

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The velocity of an object is it’s speed and __ of motion .

Answers

Answer:

direction should be the answer

velocity i’m pretty sure

All of the following statements concerning drugs and supplements are true EXCEPT: A. Many drugs and supplements are ineffective and expensive. B. Many supplements and drugs are frequently used to improve performance and appearance. C. Supplements and drugs both undergo stringent government testing. D. Supplements and drugs can both cause unwanted side effects. Please select the best answer from the choices provided. A B C D

Answers

Answer: C, supplements and drugs both undergo stringent government testing.

Explanation: took the unit test.

hope this helps :)

Answer:

C

Explanation:

A 0.43T magnetic field is perpendicular to a circular loop of wire with 56 turns and a radius of 16cm .
If the magnetic field is reduced to zero in 0.14s , what is the magnitude of the induced emf?

Answers

The value of the magnitude of the induced emf is 98.74 V.

From the question, Magnetic field strength, B = 0.43T

Number of turns, N = 56

Radius, r = 16 cm

Time taken, t = 0.14s

Formula to calculate the induced emf, ε = -NdΦ/dt

Where,N = Number of turns

dΦ = Change in magnetic flux

dt = Change in time

1: Calculation of magnetic flux, Φ

Φ = B.A = B(πr²) [Area of the circular loop]

Φ = (0.43T)(π × 0.16m × 0.16m)

Φ = 0.03456 WbS

2: Calculation of induced emf, ε

ε = -NdΦ/dtε = -(56)(0.03456 Wb)/0.14s

ε = -13.824/0.14 V

ε = -98.74 V (negative sign indicates the direction of induced current)

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I NEED HELP PLEASE! :)
A train is moving at 23 m/s due east when it sounds a blast on its horn, frequency = 164 Hz. What frequency is heard by the driver of a car moving due east at 15 m/s along a road parallel to the tracks? Use 343 m/s for the speed of sound. Please show all work.

Answers

Answer:

168 Hz

Explanation:

The Doppler equation describes how sound frequency depends on relative velocities:

fr = fs (c + vr) / (c + vs),

where fr is the frequency heard by the receiver,

fs is the frequency emitted at the source,

c is the speed of sound,

vr is the velocity of the receiver,

and vs is the velocity of the source.

Note: vr is positive if the receiver is moving towards the source, negative if away.

Conversely, vs is positive if the receiver is moving away from the source, and negative if towards.

Given:

fs = 164 Hz

c = 343 m/s

vr = -15 m/s

vs = -23 m/s

fr = fs (c + vr) / (c + vs)

fr = 164 Hz (343 m/s − 15 m/s) / (343 m/s − 23 m/s)

fr = 168 Hz

As CO2 increases, the length of days increases. *
O True
O False

Answers

Answer: false

Explanation:

CO2 decreases during the day because of photosynthesis. The plants absorb the carbon di oxide present in the air to generate oxygen. When CO2 increases, the lengths of the nights are much affected than day. The lengths of days are not much changed. Hence, False.

Ten children measured and recorded how high they could jump. The results they recorded, in inches, were as follows:
8, 9, 8, 6, 8, 12, 9, 10, 11, 16
What is the median of these measures?

Answers

the median is 9.

i hope this helps you!

A projectile is shot directly away from Earth's surface. Neglect the rotation of Earth.
(a) As a multiple of Earth's radius RE, what is the radial distance a projectile reaches if its initial speed is one-fifth of the escape speed from Earth?
multiplied by RE
(b) As a multiple of Earth's radius RE, what is the radial distance a projectile reaches if its initial kinetic energy is one-fifth of the kinetic energy required to escape Earth?
multiplied by RE
(c) What is the least initial mechanical energy required at launch if the projectile is to escape Earth?

Answers

(a) The radial distance a projectile reaches, as a multiple of Earth's radius (RE), if its initial speed is one-fifth of the escape speed from Earth can be calculated as follows:

The escape speed from Earth can be given by the formula:

Ve = √(2GM/R)

Where:

Ve = Escape speed from Earth

G = Gravitational constant

M = Mass of Earth

R = Radius of Earth

Let's denote the initial speed of the projectile as Vp. According to the problem, Vp = (1/5)Ve.

The distance reached by the projectile can be determined using the equation for the motion of an object under constant acceleration:

d = Vp² / (2g)

Where:

d = Distance reached

Vp = Initial speed of the projectile

g = Acceleration due to gravity

The acceleration due to gravity at the surface of Earth is given by:

g = GM / R²

Substituting the values and rearranging the equations, we get:

d = (Vp² * R²) / (2GM)

To express the result as a multiple of Earth's radius (RE), we divide the distance reached (d) by the radius of Earth (R).

d/RE = [(Vp² * R²) / (2GM)] / R

Simplifying the expression, we have:

d/RE = Vp² / (2GM)

Substituting Vp = (1/5)Ve, we get:

d/RE = [(1/5)Ve]² / (2GM)

Now, let's substitute the values and calculate the result:

G ≈ 6.67430 × 10^(-11) m³/kg/s² (gravitational constant)

M ≈ 5.972 × 10^24 kg (mass of Earth)

R ≈ 6.371 × 10^6 m (radius of Earth)

Ve = √(2 * G * M / R)

= √(2 * 6.67430 × 10^(-11) * 5.972 × 10^24 / 6.371 × 10^6)

≈ 1.118 × 10^4 m/s

Vp = (1/5)Ve

= (1/5) * 1.118 × 10^4

≈ 2.236 × 10^3 m/s

d/RE = [(2.236 × 10^3)² / (2 * 6.67430 × 10^(-11) * 5.972 × 10^24)]

/ (6.371 × 10^6)

Calculating the result:

d/RE ≈ 0.063

Therefore, the radial distance the projectile reaches, as a multiple of Earth's radius (RE), is approximately 0.063.

(b) The radial distance a projectile reaches, as a multiple of Earth's radius (RE), if its initial kinetic energy is one-fifth of the kinetic energy required to escape Earth can be calculated as follows:

The kinetic energy required to escape Earth can be given by the formula:

KEe = (1/2)MVe²

Where:

KEe = Kinetic energy required to escape Earth

M = Mass of Earth

Ve = Escape speed from Earth

Let's denote the initial kinetic energy of the projectile as KEp. According to the problem, KEp = (1/5)KEe.

The kinetic energy of an object can be calculated using the formula:

KE = (1/2)MV²

Where:

KE = Kinetic energy

M = Mass of the object

V = Velocity of the object

The velocity of the projectile can be expressed as:

Vp = √(2KEp / M)

The distance reached by the projectile can be calculated using the equation for the motion of an object under constant acceleration:

d = Vp² / (2g)

To express the result as a multiple of Earth's radius (RE), we divide the distance reached (d) by the radius of Earth (R).

Substituting the values and calculating, we have:

Vp = √(2 * (1/5)KEe / M)

= √((2/5) * (1/2)MVe² / M)

= √((1/5)Ve²)

= (1/√5)Ve

d/RE = [(Vp)² / (2g)] / R

Substituting Vp = (1/√5)Ve, we get:

d/RE = [(1/√5)Ve]² / (2GM) / R

Now, let's substitute the values and calculate the result:

d/RE = [(1/√5) * 1.118 × 10^4]² / (2 * 6.67430 × 10^(-11) * 5.972 × 10^24) / (6.371 × 10^6)

Calculating the result:

d/RE ≈ 0.063

Therefore, the radial distance the projectile reaches, as a multiple of Earth's radius (RE), is approximately 0.063.

(c) The least initial mechanical energy required at launch for the projectile to escape Earth can be determined by considering the conservation of mechanical energy.

The total mechanical energy of an object is given by the sum of its kinetic energy and potential energy:

E = KE + PE

Where:

E = Mechanical energy

KE = Kinetic energy

PE = Potential energy

To escape Earth, the projectile's mechanical energy at launch should be zero, meaning its kinetic energy and potential energy should cancel each other out.

KE + PE = 0

KE = -PE

The kinetic energy can be expressed as:

KE = (1/2)MV²

The potential energy can be calculated using the formula for gravitational potential energy:

PE = -GMm/R

Where:

PE = Potential energy

G = Gravitational constant

M = Mass of Earth

m = Mass of the projectile

R = Radius of Earth

Substituting the expressions for KE and PE into the equation KE + PE = 0, we have:

(1/2)MV² - GMm/R = 0

Simplifying and rearranging the equation, we get:

V² = 2GM/R

V = √(2GM/R)

This equation gives us the escape speed from Earth, which we calculated earlier in part (a).

Therefore, the least initial mechanical energy required at launch for the projectile to escape Earth is zero, as the kinetic energy and potential energy cancel each other out.

(a) The radial distance the projectile reaches, as a multiple of Earth's radius (RE), is approximately 0.063.

(b) The radial distance the projectile reaches, as a multiple of Earth's radius (RE), is approximately 0.063.

(c) The least initial mechanical energy required at launch for the projectile to escape Earth is zero.

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what is the force on a -50 μc charge in an electric field of 3000 n/c pointing due east?

Answers

The force on a -50 μc charge in an electric field of 3000 n/c pointing due east is -150 N.

F=qE, where F is the force, q is the charge, and E is the electric field.

The electric field has a magnitude of 3000 n/c, which means there is a force of 3000 N acting in the direction of the electric field.

For the -50 μc charge, the force is equal to -50 μc multiplied by 3000 n/c, or -150 N. This force acts in the opposite direction of the electric field, meaning the -50 μc charge would experience a force of -150 N due east.

This is due to the fact that like charges repel each other. The electric field is providing a force to the charge, so the charge is repelling the electric field in order to maintain equilibrium.

The force on a -50 μc charge in an electric field of 3000 n/c pointing due east is -150 N.

This force acts in the opposite direction of the electric field, meaning the charge experiences a force of -150 N due east. This is due to the fact that like charges repel each other.

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a star 10 light-years away explodes and produces gravitational waves. how long will it take these waves to reach earth?

Answers

Gravitational waves travel at the speed of light, so it would take approximately 10 years for the gravitational waves produced by the star's explosion to reach Earth.

Since the star is located 10 light-years away, it means that the light emitted by the explosion takes 10 years to travel from the star to Earth. Gravitational waves, like light, also travel at the speed of light in a vacuum.

Therefore, the gravitational waves produced by the star's explosion would also take approximately 10 years to propagate through space and reach Earth. This is because both light and gravitational waves travel at the same finite speed, and in this scenario, they would arrive at Earth at approximately the same time, 10 years after the star's explosion.

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Galois drove 60.0 kilometers due west in 5.00 hours and then drove 43.0 kilometers due north in 3.00 hours.
(a) How far did he travel?
(b) What was his average speed?
(c) What was his displacement?
(d) What was his average velocity?

Answers

Answer:

Explanation:

See the attachment for the details.  A right triangle is formed to find the hypotenuse of the two legs consisting of the actual driving distances and times.  The hypotenuse gives the vector information for the displacement at the end of 8 hours of driving.  

The individual driving times and distances are summed to provide:

(a) How far did he travel?

103 km

(b) What was his average speed?

12.88 km/h

(c) What was his displacement?

73.82 km

(d) What was his average velocity?

9.228 km/h

Galois drove 60.0 kilometers due west in 5.00 hours and then drove 43.0 kilometers due north in 3.00

a skater moved from position 14 m to 179 m and then ultimately moved to position -23 m. the total time of travel is 94 s. find the average speed of the skater over the time of motion

Answers

Answer:

V = ((179 - 14) + (179 - (-23))) / 94 = 367 / 4 = 3.9 m/s

Question asks for total distance not net distance traveled

A wave with a frequency of 17 Hz ha a wavelength of 5 meter. At what peed will thi wave travel?

Answers

The wave's speed is 85 m/s if its wavelength is 5 meters and its frequency is 17 Hz.

What is a wave length?

A waveform signal that is propagated in space or down a wire does have a wavelength, that is the separation between two equal places (adjacent crests) in the consecutive cycles. This length is typically specified in wireless systems in metres (m), centimetres (cm), or millimeters (mm) (mm).

given data,

frequency of the wave v = 17 Hz

Wavelength of the wave = 5m

speed of the wave s = ?

Calculating the speed of wave

We know that,

Speed= frequency × wavelength

Thus,

s= 17 × 5 m/s

s= 85 m/s

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One fitness magazine suggested that the food that you eat is like a battery because it has energy. Do you think that the banana that Mila ate had energy? Explain why you think this.

Answers

When food is kept in storage, it has chemical energy as potential. Chemical energy in food is transformed into fuel for our bodies when a person eats it.

Thermal energy, which keeps us warm, is the fuel for our bodies. \

When a human moves, the chemical energy is also transformed into motion. Kinetic energy is the movement.

Because food gives the human body the chemical energy it needs to carry out its daily tasks, the fitness magazine made the comparison between food and a battery in this instance.

The banana is a fruit that contains a lot of carbohydrates and fructose. Because of this, it is a great food to eat before exercise because it gives the muscles the chemical energy they need to perform better both before and after exercise.

The banana is also high in potassium, magnesium, phosphorus, and vitamins a and c, which gives it more strength and energy.

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how does temperature affect chemical reaction​

Answers

When its temperature increases, the reactants have more kinetic energy so the frequency of effective collision increases, resulting in a faster rate of chemical reaction.

Roberto has twice the mass his sister Mary has (see above) but runs at the same velocity as Mary. Will his kinetic energy be twice as much? Show your work. What happens to Roberto’s kinetic energy when he runs twice as fast?

Answers

Answer:

yes Robert's kinetic energy will be twice as much

if Robert runs twice as fast, then his KE will be 8 times Mary's KE

Explanation:

Kinetic energy KE = \(\frac{1}{2}\)m\(v^{2}\)

for Robert KE =  \(\frac{1}{2}\)(2m)\(v^{2}\) =  m\(v^{2}\)

for Mary KE = \(\frac{1}{2}\)m\(v^{2}\)

If you divide Robert KE by Mary KE = m\(v^{2}\) /  \(\frac{1}{2}\)m\(v^{2}\) = 2; yes Robert's kinetic energy will be twice as much

if Robert v is equal to 2v

for Robert KE =  \(\frac{1}{2}\)(2m)\((2v)^{2}\) =  4m\(v^{2}\)

for Mary KE = \(\frac{1}{2}\)m\(v^{2}\)

If you divide Robert new KE by Mary's KE = 4m\(v^{2}\) /  \(\frac{1}{2}\)m\(v^{2}\) = 8, if Robert runs twice as fast, then his KE will be 8 times Mary's KE

Roberto has twice the mass his sister Mary has (see above) but runs at the same velocity as Mary, then his kinetic energy would be twice that of Mary, and the kinetic energy of Roberto would be 8 times when he runs twice as fast Mary.

What is mechanical energy?

Mechanical energy is the combination of all the energy in motion represented by total kinetic energy and the total stored energy in the system which is represented by total potential energy.

The kinetic energy is the body depends on the mass as well as the speed of the object and is given by the mathematical expression as follows

K.E = 1/2 × m × v²

When Roberto runs at the same speed as his sister Mary but has twice Mary's mass (see above), Roberto's kinetic energy is twice Mary's, and it is eight times higher when Roberto runs twice as quickly as Mary.

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What is the radius of a circular space station that spins with a linear speed of 90.0 m/s I’m order for its walls to supply a centripetal acceleration equal to the acceleration provided by gravity on the surface of the earth?

Answers

Answer:

a = v^2 / R      centripetal acceleration

R = v^2 / a     a at the surface of earth is 9.8 m/s^2

R = (90 m/s)^2 / 9.8 m/s^2 = 827 m

Other Questions
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