Answer:
56.52/3.14 = 18 feet
Step-by-step explanation:
The equation for finding the diameter of a circle when given the circumference is D = circumference/pi. In this case, the equation is D = 56.52/3.14, which is equal to 18 feet.
Answer:
Step-by-step explanation:
Using the equation C=2\(\pi\)r
56.54=2\(\pi\)*r
where
r= .5*diameter
D=diameter
56.54=2\(\pi\)*(1/2)D
56.25/2\(\pi\)=1/2 D
88.3572933822= 1/2 D
*2
176.714586764=D
If a = -1, b = 2 and c = -3 determine the value of a² – 2b³+ c²
Answer:
-26
Step-by-step explanation:
-1^2-2(2)^3 -3^2
-1-2(8)-1(9)
-1-16-9
-26
*please don’t answer if you aren’t going to be serious or answer everything *
-I will make you the brainliest-
Answer:
I'm sorry i only know (A)
Step-by-step explanation:
Horizontal
Multiply and express in the form of a complex number a + b i.
(-5 + 3i)(- 4 + 8i)
Answer:
-4 - 52 i
Step-by-step explanation:
Hope this helps :)
SOMEONE HELP ME HURRY ASAP PLEASE ILL CASHAPP PLEASE HELP
Answer:
48 il take brainliest instead lol
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
76 * 2 = 152
p = 152
152 + 76 + 38 + 94 = 360
Lesson question: How does adding the two equations in a system allow you to solve it?
ANSWER FAST PLEASE
Answer:
Step-by-step explanation:
y-terms cancel out and are eliminated as a result of adding the two equations.
write 17598 correct to 2 significant figures
Answer:
180000
Step-by-step explanation:
2 significant figures means you see the digit next 2 second number. here next number is 5, then you round off second number to the next one. in the case 17 rounded to 18. rest all become 0000
hope it helps!
How do you find the asymptote?
To find the asymptotes of a graph, first determine the type of asymptote (horizontal, vertical, or slant) and identify the conditions that must be satisfied. Then, set the numerator or denominator equal to zero and solve for y or x, or divide the numerator by the denominator and find the equation of the line that the graph approaches as x approaches infinity.
To find the asymptotes of a graph, you can follow these steps:
Determine the type of asymptote: There are three types of asymptotes: horizontal, vertical, and slant.Identify the conditions for the asymptote: For a horizontal asymptote, the degree of the numerator must be less than the degree of the denominator. For a vertical asymptote, the denominator must be equal to zero. For a slant asymptote, the degree of the numerator must be one more than the degree of the denominator, and the leading coefficients of the numerator and denominator must not be equal.Solve for the asymptote: Once you have identified the type of asymptote and the conditions that must be satisfied, you can solve for the asymptote by setting the numerator or denominator equal to zero and solving for y or x, or by dividing the numerator by the denominator and finding the equation of the line that the graph approaches as x approaches infinity.Learn more about the asymptote at
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can someone check if this is correct please
Answer:
it is correct you are right
Please I don’t know how to do this
Answer: x = \(\sqrt{320}, or 17.8885438\)
Step-by-step explanation:
According to the pythagorean theorem, a^2 + b^2 = c^2.
As such, 4^2 + x^2 = (4sqrt5)^2
16 + x^2 = 80
x^2 = 64
x = 8.
Thus, the dashed line in the center is 8.
Simply plug this into the pythagorean theorem as well.
8^2+16^2=p^2
p^2 = 320
p = 17.8885438, or sqrt 320
Which angles of the triangle measure 90 degrees?
I just need clarification
Answer:
Step-by-step explanation:
Suppose r(140°, P)(A) = B and (Rnotation: Line PD∘Rnotation: Line PC)(A) = B, what is m∠CPD?
The measure of angle formed from the angle bisector PC- ∠CPD is 70°.
Here the question says that here we have an angle, ∠RPD. Now, there os a line PC from point P that bisects the angle, ∠RPD. Now, the given information states that ∠RPD measures 140°. We need to find the measure of ∠CPD.
According to the question,
the angle ∠RPD is bisected by the line PC.
An angle bisector is that line, line segment or ray, that divides an angle equally into 2 halves.
We know that ∠RPD = 140°
Now, since PC bisects ∠RPD, the angle ∠CPD resulted from it would be half of that of ∠RPD
Hence ∠CPD = 70°.
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Complete Question
Image Attached
help neeed it right if not ill get beat
Dave is making cookies for his niece. He wants to
make 1/2 batches. If the recipe calls for 2 1/4 cups of
flour for one batch, how much flour will he need to
use for 1 1/2 batches?
Answer:2.25 + 4.5 = 6.75 cups of flour
2.25
Step-by-step explanation: 1 batch is already 2.25 in decimal form so just infer from there.. divide 2.25 from .5 and get 4.5 then add to the one batch you've already received .. 4.5 + 2.25 = 6.75 and just convert into a fraction 6 3/4
if a parametric surface given by and , has surface area equal to 1, what is the surface area of the parametric surface given by with ?
Let's start by finding the surface area of the parametric surface given by
To find the surface area, we need to evaluate the integral:
where
The surface area can be expressed in terms of a double integral over the parameter domain of the surface, which is the square [0,1] × [0,1]:
First, we need to compute the partial derivatives:
Then, we can compute the cross product:
Finally, we can compute the magnitude of the cross product:
Thus, the surface area of the parametric surface given by
is
Now, to find the surface area of the parametric surface given by
we can use the same method. The partial derivatives are:
The cross product is:
And the magnitude of the cross product is:
Thus, the surface area of the parametric surface given by
is
Therefore, the surface area of the second parametric surface is 2 times the surface area of the first parametric surface, which is 2.
The given parametric surface has a surface area given by 2π.
To find the surface area of the parametric surface given by with , we need to use the formula for the surface area of a parametric surface:
A = ∫∫ ||(∂f/∂u) x (∂f/∂v)|| dudv
where ||(∂f/∂u) x (∂f/∂v)|| is the magnitude of the cross product of the partial derivatives of the parametric equations, and dudv is the area element in the u-v plane.
For the given parametric surface, we have:
x = u
y = v
z = uv
So, the partial derivatives are:
∂f/∂u = i + vj
∂f/∂v = ui + uk
Taking the cross product, we get:
(∂f/∂u) x (∂f/∂v) = -vj + uuk - vk
Taking the magnitude, we get:
||(∂f/∂u) x (∂f/∂v)|| = √(1 + u² + v²)
So, the surface area is:
A = ∫∫ √(1 + u² + v²) dudv
To evaluate this integral, we can use a change of variables:
x = u
y = v
z = √(1 + u² + v²)
which gives us a surface that is a hemisphere of radius 1. The surface area of a hemisphere is given by:
A = 2πr²
So, in this case, the surface area is:
A = 2π(1)² = 2π
Therefore, the surface area of the parametric surface given by with is 2π.
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19. machine tools a) cut a metal b) provide surface finish c) cut a metal and provide surface finish d) none of the above
Option b.) to provide a surface finish is correct answer. For the metal removal process, the metal removal is more (not negligible), and for surface finishing the metal removal is negligible.
Surfacing removes a small amount of material from the surface compared to other metal cutting processes. However, a small amount of material is removed during surface preparation compared to this method. Although there is definitely a removal of material from the surface.
Why surface finishing is required :- Surface finish can affect a part's resistance to wear and fatigue. Promotes or destroys effective lubrication. Increase or decrease friction and/or wear with mating parts. and resist corrosion.
Surface Finishing Work Methods :-
⇒Finishing is the process of modifying the surface of a manufactured part to achieve a desired appearance, facilitate bonding, or increase durability.
⇒ All finishing processes applied to manufactured parts depend on the material of the part (plastic or metal).
⇒Surface finish charts are usually measured in microns or microinches. The surface finish measurement describes the overall texture of a surface, characterized by surface waviness, position, and surface roughness.
Here is the full question:-
Which machining process causes negligible metal removal?
a) surface finish b) metal removal c) both surface finish and metal removal d) none of the above
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Can u please help me with this. I’ll make brainliest
Answer:
number
Step-by-step explanation:
number than number lol sorry i dont know i wish i could help you
Calculate the average rate of change forf(x) = 8x + 2from x to x + h.
\(slope = m = \cfrac{rise}{run} \implies \cfrac{ f(x_2) - f(x_1)}{ x_2 - x_1}\impliedby \begin{array}{llll} average~rate\\ of~change \end{array}\\\\[-0.35em] \rule{34em}{0.25pt}\\\\ f(x)=8x+2 \qquad \begin{cases} x_1=x\\ x_2=x+h \end{cases}\implies \cfrac{f(x+h)-f(x)}{(x+h)-x} \\\\\\ \cfrac{[8(x+h)+2]~~ -~~[8x+2]}{h}\implies \cfrac{[8x+8h+2]-8x-2}{h} \implies \cfrac{8h}{h}\implies 8\)
Potassium-42 has a half-life of 12.4 hours. How much of a 746-gram sample will be left after 62 hours?
the amount of potassium-42 remaining after 62 hours is approximately 23.31 grams (option B)
Explanation:half life = 12.4 hours
initial amount = 746g
time elapsed = 62 hours
Using the half-life formula:
\(\begin{gathered} N(t)=N_0(\frac{1}{2})^{\frac{t}{t_{_{\frac{1}{2}}}}} \\ N(t)\text{ = amount remaining} \\ N_0\text{ = initial amount = 746g} \\ t\text{ = 62 hours} \\ t_{\frac{1}{2}\text{ }}\text{ = 12.4 hours} \end{gathered}\)Substitute for the values:
\(\begin{gathered} N(t)=N_0(\frac{1}{2})^{\frac{t}{t_{_{\frac{1}{2}}}}} \\ N(t)\text{ = }746(\frac{1}{2})^{\frac{62}{12.5}} \\ N(t)\text{ = }746(\frac{1}{2})^5 \\ N(t)\text{ = }746(\frac{1}{2^5}) \end{gathered}\)\(\begin{gathered} N(t)\text{ = }(\frac{746}{32})^{} \\ N(t)\text{ = }23.3125 \end{gathered}\)Hence, the amount of potassium-42 remaining after 62 hours is approximately 23.31 grams (option B)
-x + 3y = -23
-8x - 3y = -22
using elimination
A painter spends 3 hours working on a painting. A sculptor spends 23 as long working on a sculpture. How long does the sculptor work?
Answer:
69 hours
Step-by-step explanation:
The painter spends 3 hours working on a painting.
The sculptor spends 23 times as long as the painter.
The amount of time the sculptor spent is:
23 * 3 = 69 hours
The sculptor works for 69 hours.
个
Factoring When a > 1
Algebra 1 B (SP23) 1/ Quadratic Functions
1. For what values of x will the function f(x) = 3x² + 13x - 10 equal zero?
== -5 or 2
Oz=-3 or 5
Oz=5 or-2
Oz=or-5
The solution of equation f(x) = 3x² + 13x - 10 will be -5 and 2/3.
Given that:
Equation, f(x) = 3x² + 13x - 10
In other words, the collection of all feasible values for the parameters that satisfy the specified mathematical equation is the convenient storage of the bunch of equations.
The solution of the equation is given as,
f(x) = 0
3x² + 13x - 10 = 0
3x² + 15x - 2x - 10 = 0
3x(x + 5) - 2(x + 5) = 0
(3x - 2)(x + 5) = 0
x = -5, 2/3
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In an aquarium, there are large fish and small fish. Half of the large fish are red. One fish is selected at random. Find the probability that it is a large, red fish.
The probability that a randomly selected fish is a large, red fish is 0.25 or 25%.
To find the probability that a randomly selected fish is a large, red fish, we need to consider both the probability of selecting a large fish and the probability of selecting a red fish among the large fish.
Assuming an equal number of large and small fish, the probability of selecting a large fish is 0.5 (or 1/2).
Among the large fish, the probability of selecting a red fish is also 0.5 (or 1/2).
To find the overall probability, we multiply the probabilities of the individual events:
Probability of selecting a large, red fish = Probability of selecting a large fish × Probability of selecting a red fish among the large fish
Probability of selecting a large, red fish = 0.5 × 0.5
Probability of selecting a large, red fish = 0.25
Therefore, the probability that a randomly selected fish is a large, red fish is 0.25 or 25%.
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Need help filling out the chart for #3
Answer:
Slope intercept equation= y2-y1 over x2-x1
When to use= You know the slope and any point
Dado f(x)=14(5−x)2 cual es el valor de F(11)?
What is the simplest form of 12/54
Answer:
2/9
Step-by-step explanation:
Answer:
reduce it
six goes into both evenly
2/9
Using an integrating factor, solve y-y-5 CD- in the method for solving a first-order linear differential equation, the first step is to put the equation in the standard form y alty bit). is the given equation in the standard form? No Yes Identify a(t) and bit)
The value of a(t) is -1 and b(t) is 55 + \(e^t\)
No, the given equation y' - y = 55 + \(e^t\) is not in the standard form of a first-order linear differential equation.
In the method for solving a first-order linear differential equation, an integrating factor is a function used to transform the equation into a form that can be easily solved.
For an equation in the standard form y' + a(t)y = b(t), the integrating factor is defined as:
μ(t) = e^∫a(t)dt
To solve the equation, you multiply both sides of the equation by the integrating factor μ(t) and then simplify. This multiplication helps to make the left side of the equation integrable and simplifies the process of finding the solution.
To put it in standard form, we need to rewrite it as y' + a(t)y = b(t).
Comparing the given equation with the standard form, we can identify:
a(t) = -1
b(t) = 55 + \(e^t\)
Therefore, The value of a(t) is -1 and b(t) is 55 + \(e^t\)
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If X = 3t4 + 7 and y = 2t - t2, find the following derivatives as functions of t. dy/dx = d^2y/dx^2 =
The derivative function is dy/dx = (1 - t) / (\(6t^3\)) and \(d^2y/dx^2\) = \((-1 / (6t^3))\)- (3 / \((2t^4)\)
To find dy/dx, we need to differentiate y with respect to t and x with respect to t, and then divide the two derivatives.
Given:
\(x = 3t^4 + 7\)
\(y = 2t - t^2\)
Differentiating y with respect to t:
dy/dt = 2 - 2t
Differentiating x with respect to t:
\(dx/dt = 12t^3\)
Now, to find dy/dx, we divide dy/dt by dx/dt:
\(dy/dx = (2 - 2t) / (12t^3)\)
To simplify this expression further, we can divide both the numerator and denominator by 2:
\(dy/dx = (1 - t) / (6t^3)\)
The second derivative \(d^2y/dx^2\)represents the rate of change of the derivative dy/dx with respect to x. To find \(d^2y/dx^2\), we differentiate dy/dx with respect to t and then divide by dx/dt.
Differentiating dy/dx with respect to t:
\(d^2y/dx^2 = d/dt((1 - t) / (6t^3))\)
To simplify further, we can expand the differentiation:
\(d^2y/dx^2 = (-1 / (6t^3)) - (3 / (2t^4))\)
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a case bottle water contains 24 bottles . each case contains a total of 405.6 ounces of water wich equation represents the relationship between ounces of water , y,and number of bottles,x
Answer:
y = 16.9x
where y is the ounces of water
and x is the number of bottles
Step-by-step explanation:
Here, we want to find the relationship between ounces of water y and number of bottles x
From the question, we can find the amount of liquid in each bottle
Mathematically, that will be 405.6/24 = 16.9 ounces
There is 16.9 ounces of water per bottle
So the relationship we want to write is that;
y = 16.9x
In client-server architecture, the client is responsible for ______; the server is responsible for ______; and the location of _______ varies.
In "client-server" architecture, client is responsible for presentation-logic; "server" is responsible for data-access logic; and location of data-storage varies.
In a client-server architecture, we think of the client as a person using a computer to access a website or an app. The client is responsible for how things are presented to the user. It takes care of things like displaying information, handling user input, and making the interface look good and easy to use.
The server is like a powerful computer that stores and manages the data needed for the client. It's responsible for things like storing and retrieving information from a database. The server also handles tasks like processing requests from the client and sending back the requested data.
The location of the data storage can vary. Sometimes the data is stored directly on the server itself, while in other cases, it may be stored in a separate database or file system.
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Find all the local maxima, local minima, and saddle points of the function. 4xy-x^2-6y^2 5x 5
The function \(\(f(x, y) = 4xy - x^2 - 6y^2 + 5x + 5\)\) has a local maximum at \(\(\left(\frac{15}{2}, \frac{5}{2}\right)\)\).
To find the local maxima, local minima, and saddle points of the function \(\(f(x, y) = 4xy - x^2 - 6y^2 + 5x + 5\)\), we need to calculate its partial derivatives and analyze their critical points.
Step 1: Calculate the partial derivatives:
\(\(\frac{{\partial f}}{{\partial x}} = 4y - 2x + 5\)\)
\(\(\frac{{\partial f}}{{\partial y}} = 4x - 12y\)\)
Step 2: Set the partial derivatives equal to zero and solve for x and y to find the critical points:
For \(\(\frac{{\partial f}}{{\partial x}} = 0\)\):
4y - 2x + 5 = 0
For \(\(\frac{{\partial f}}{{\partial y}} = 0\)\):
4x - 12y = 0
Solving these two equations simultaneously, we get:
4y - 2x + 5 = 0
4x - 12y = 0
From the second equation, we have (x = 3y). Substituting this into the first equation:
\(\(4y - 2(3y) + 5 = 0\)\)
\(\(4y - 6y + 5 = 0\)\)
\(\(-2y + 5 = 0\)\)
\(\(2y = 5\)\)
\(\(y = \frac{5}{2}\)\)
Substituting the value of (y) back into (x = 3y):
\(\(x = 3 \left(\frac{5}{2}\right)\)\)
\(\(x = \frac{15}{2}\)\)
So, the critical point is \(\(\left(\frac{15}{2}, \frac{5}{2}\right)\)\).
Step 3: Analyze the critical points to determine if they are local maxima, local minima, or saddle points.
To classify the critical points, we need to calculate the second-order partial derivatives and evaluate the determinant and the discriminant of the Hessian matrix.
The Hessian matrix is given by:
\(\(H(x, y) = \begin{bmatrix} \frac{{\partial^2 f}}{{\partial x^2}} & \frac{{\partial^2 f}}{{\partial x \partial y}} \\ \frac{{\partial^2 f}}{{\partial y \partial x}} & \frac{{\partial^2 f}}{{\partial y^2}} \end{bmatrix}\)\)
Calculating the second-order partial derivatives:
\(\(\frac{{\partial^2 f}}{{\partial x^2}} = -2\)\)
\(\(\frac{{\partial^2 f}}{{\partial x \partial y}} = 4\)\)
\(\(\frac{{\partial^2 f}}{{\partial y \partial x}} = 4\)\)
\(\(\frac{{\partial^2 f}}{{\partial y^2}} = -12\)\)
Evaluating the Hessian matrix at the critical point \(\(\left(\frac{15}{2}, \frac{5}{2}\right)\)\):
\(\(H\left(\frac{15}{2}, \frac{5}{2}\right) = \begin{bmatrix} -2 & 4 \\ 4 & -12 \end{bmatrix}\)\)
The determinant of the Hessian matrix is:
\(\(\Delta = \frac{{\partial^2 f}}{{\partial x^2}} \cdot \frac{{\partial^2 f}}{{\partial y^2}} - \left(\frac{{\partial^2 f}}{{\partial x \partial y}}\right)^2 = (-2) \cdot (-12) - (4)^2 = 24 - 16 = 8\)\)
The discriminant of the Hessian matrix is:
\(\(D = \frac{{\partial^2 f}}{{\partial x^2}} = -2\)\)
Based on the determinant and discriminant, we can determine the nature of the critical point:
1. If \(\(\Delta > 0\)\) and \(\(D > 0\)\), then the critical point is a local minimum.
2. If \(\(\Delta > 0\)\) and \(\(D < 0\)\), then the critical point is a local maximum.
3. If \(\(\Delta < 0\)\), then the critical point is a saddle point.
4. If \(\(\Delta = 0\)\), further analysis is required (such as higher-order derivatives or other methods).
In this case, we have \(\(\Delta = 8\)\) and \(\(D = -2\)\).
Since \(\(\Delta > 0\)\) and \(\(D < 0\)\), we conclude that the critical point \(\(\left(\frac{15}{2}, \frac{5}{2}\right)\)\) is a local maximum.
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