the circuit she tests has a current of 5 plus j 3 amps and a resistance of 3 minus j 2 ohms. what is the voltage of the circuit?

Answer:

Sketch the situation.

b. Calculate the potential energy, the kinetic energy, and the total energy of the car as it leaves the cliff.

c. Make a graph displaying the kinetic, gravitational potential, and total energy of the car at each 10 m

increment of height as it drops

Explanation:

The potential energy of the car at that position is 10.6 x 10⁵ J.

Potential energy of an object is defined as the energy acquired by the object by virtue its position.

Here,

Mass of the car, m = 1200 kg

Speed of the car, v = 29 m/s

Height of the cliff, h = 90 m

Therefore,

Potential energy of the car, PE = mgh

PE = 1200 x 9.8 x 90

PE = 10.6 x 10⁵ J

Hence,

The potential energy of the car at that position is 10.6 x 10⁵ J.

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Ari's final vertical jump height is 5.2 m.

Ari's final vertical jump height is calculated from the law of conservation of energy as shown below.

P.E ( of Ari ) = P.E ( of Bari )

m1gh1 = m2gh2

where;

h1 = ( m2h2 ) / ( m1 )

h1 = ( 70 x 4 ) / ( 50 )

h1 = 5.6 m

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Given :

Velocity of bullet, \(v_b=300\ m/s\).

Mass of bullet, m = 0.005 kg.

Mass of rifle, M = 5 kg.

To Find :

The recoil velocity of the rifle.

Solution :

Since, their is no external force is acting.

So, momentum of the system will be conserved :

Initial momentum = Final momentum

m(0) + M(0) = m(300) + Mv

\(v=-\dfrac{300m}{M}\\\\v=-\dfrac{300\times 0.005}{5}\\\\v=-0.3 \ m/s\)

Therefore, recoil velocity of the rifle is 0.3 m/s.

Hence, this is the required solution.

Answer:

I guess the answer is c the f am not wrong

Answer:

heart rate increases during activity

Explanation:

You can work at 70 to 85 percent of your maximum heart rate during vigorous activity.

The weight of a 75 kg person on Earth is 735 N, The correct option is D.

Acceleration due to gravity is the acceleration that an object experiences due to the gravitational force exerted by a massive body, such as Earth. The acceleration due to gravity on Earth is approximately 9.8 meters per second squared (m/s^2) and is denoted by the symbol "g".

The acceleration due to gravity is a vector quantity, which means that it has both magnitude and direction. The direction of the acceleration due to gravity is always downwards, towards the center of the massive body.

The acceleration due to gravity is a constant value near the surface of the Earth, but it can vary slightly depending on altitude, latitude, and the composition of the Earth's interior. For example, at higher altitudes, the acceleration due to gravity decreases slightly, while at the equator, it is slightly greater than at the poles due to Earth's rotation.

The acceleration due to gravity plays an important role in many physical phenomena, including free fall, projectile motion, and the behavior of fluids in containers.

Here in the Question,

The weight of a 75 kg person on Earth can be calculated using the formula:

weight = mass x acceleration due to gravity

Substituting the given values, we get:

weight = 75 kg x 9.8 m/s^2

weight = 735 N

Therefore, the weight of a 75 kg person on Earth is 735 N, which is option D.

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The net force acting on the box of mass 1.75kg when it is pushed across a ground with coefficient of friction k=0.267 with a force of 8.35N, is 3.77N.

To find the answer, we have to know more about the basic forces acting on a body.

                                 \(N=mg\\F_t=ma\\F_t=F-f\)

where, N is the normal reaction, mg is the weight of the box, \(F_t\) is the net force, f is the kinetic friction.

                      \(f=kN=kmg=0.267*1.75*9.8= 4.58N\)

                        \(F_t= 8.35-4.58=3.77N\)

Thus, we can conclude that, the net force acting on the box of mass 1.75kg when it is pushed across a ground with coefficient of friction k=0.267 with a force of 8.35N, is 3.77N.

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The net force acting on the box is 3.77 N.

We need to learn more about the fundamental forces affecting a body in order to locate the solution.

                             \(N=mg\\F_n=F-f\)

where N stands for the normal reaction, mg for the box's weight, is the net force, and f for kinetic friction.

                            \(f=kN=kmg=4.58N\)

                                     \(F_n=3.77N\)

Thus, it is clear that the box with a mass of 1.75 kg will experience a net force of 3.77 N when it is pushed across a surface with a coefficient of friction of 0.264.

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Answer:

428.8 nm

Explanation:

Gravity, friction, and drag force are the forces that are acted on a car.

Gravity is defined as a force by which one body attracts other objects toward its center. Friction is the force that resists the relative motion of solid surfaces, fluid, and material that are sliding against each other. There are several types of friction force i.e. Dry friction is a type of force that opposes the relative motion of two solid surfaces that are in contact with each other.

Drag is a mechanical force that is generated by the interaction and physical contact of a solid body with a liquid or gas. It is not produced by a field force, gravitational field, or an electromagnetic field, in which one object can affect another object without any physical contact with each other.

So we can conclude that the forces acting on the car are gravity, friction and drag force.

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The resultant velocity of the parachute is 3.4 m/s.

The term resultant velocity refers to the effective velocity  with which the parachute moves. We know that velocity is a vector quantity. Recall that a vector is known to have both magnitude and direction.

Given that the magnitude of the resultant vector can only be obtained geometrically we have;

Vertical component =   3.0 m/s

Horizontal component = 1.6 m/s

Resultant velocity = √(3)^2 + (1.6)^2

= 3.4 m/s

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The figure skater increases the speed of her spin to 10 revolutions per second by drawing her arms inside.

The speed of the skater's spin drops by a factor of two as she spreads her arms out in front of her, doubling the moment of inertia. She dramatically reduces her inertia moment while folding her wrists in, resulting in a considerable increase in rotational velocity.

When does a speedskater reach a point of inertia?

During skating, the skater's mass is measured in terms of how far it extends from the axis around the direction that he or herself is spinning. This is known as the inertia moment, or moment of inertia The magnitude of its moment of inertia increases with distance from the axis. The force required to halt a moving item is measured by momentum.  

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By Newton's second law we have:

then, originally we have:

If we tripled the force and halved the mass then we have:

Therefore the new acceleration is 36 meters per second per second.

The given statement is that the temperature in degrees Fahrenheit in times square during a day in August can be predicted by the function t(x).

Hence, it can be stated that the function t(x) provides a prediction for the temperature in degrees Fahrenheit in Times Square for a given value of x. Here, x represents the input variable.

It is important to note that the input variable must be provided in the correct units and format as required by the function t(x).The content loaded refers to the data that has been previously collected and is available for analysis. In the context of predicting temperature using function t(x),

the content loaded can refer to temperature data collected in Times Square during August on previous days or years. This data can be analyzed and used to develop the function t(x) that predicts temperature for a given input variable x.

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The two resistances are calculated to be R = 6.63 ohm and r = 1.01 ohm when two situations are given.

Let the two resistances are r and R.

When they are connected in series,

V = 12 V

i = 1.57 A

When they are joined in series, the equivalent resistance is

Rs = r + R

So, By using Ohm's law

V = i × Rs

Rs = V / i = 12 / 1.57 = 7.64 ohm

R + r = 7.64 ohm  ----(1)

When they are connected in parallel:

V = 12 V

i = 10.5 A

When connected in parallel, the equivalent resistance,

Rp = (R + r)/(R r)

So, By using Ohm's law

V = i Rp

Rp = V / i = 12 / 10.5 = 1.14 ohm ----(2)

(R + r)/(R r) = 1.14

By substituting the value of R + r from equation (1) in equation (2), we get

r R = 7.64/1.14

r R = 6.70 ohm² ----(3)

R - r = √[(R+r)² -4 R r] = √[ 7.64² - 4× 6.7] = √[ 58.37 - 26.8] = √ 31.57 = 5.62 ohm

R - r = 5.62 ----(4)

(1) + (4) = 2R = 13.26

So, R = 6.63 ohm

r = 1.01 ohm

Thus, the two resistances are R = 6.63 ohm and r = 1.01 ohm.

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We are given the following information about an inelastic collision.

Mass of 1st object = 4 kg

Mass of 2nd object = 10 kg

Initial velocity of 1st object = 25 m/s

Final velocity of both objects = 14 m/s

Initial velocity of 2nd object = ?

In an inelastic collision, the momentum is conserved but the kinetic energy is not conserved.

Recall that the total momentum is conserved and given by

Let us substitute the given values and solve for initial velocity of the body (u2)

Therefore, the initial velocity of the body of mass 10 kg is 9.6 m/s

Answer:

A. stronger prevailing winds and more hurricane activity

Explanation:

edg2020

Answer:A

Explanation:

Answer:

meters per second squared or meters per second per second

Explanation:

If speed is measured in meters per second and time is measured in second, the unit of acceleration is "meters per second squared or meters per second per second."

To illustrate better, speed is measured in meters per second = m/s, while time is measured in second = s.

Hence, the unit of acceleration is m/s². This implies that acceleration is the number of meters per second the velocity changes every second.

Resitance (R)= 10 Ohm

Potential difference (V) = 9V

V= IR

I= V/R

I= 9/10

I= 0.9 Ampere

Therefore 0.9 Ampere of current is flowing through the circuit.

The current through the circuit can be calculated using Ohm's law. The  current flowing through the circuit with a resistance of 10 ohm and 9 V is 0.9 ampere.

Ohm's law states that the potential difference or voltage across a circuit is the product of the current  and resistance through the circuit. Thus  as current or resistance increases, voltage across the circuit also increases.

According to Ohm's law, V= IR.

Given  the voltage V = 9 V

Resistance R = 10 ohm

Current = voltage/ resistance (V/R)

             =  9 V/ 10 Ω.

             = 0.9 A.

Therefore, the current passing  through the circuit is 0.9 A.

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Answer:

Roots are basically hooked into the ground?

Explanation:

Maybe you could comment here the choices if it's multiple choice.

The horizontal speed of Sam in order to clear that one kid is 6.67 m/s.

The time taken for Sam to fall from the given height is calculated as follows;

h = vt + ¹/₂gt²

where;

h = 0 + ¹/₂gt²

t = √ ( 2h / g )

t = √ ( 2 x 7 / 9.8 )

t = 1.2 seconds

The horizontal speed of Sam in order to clear that one kid is calculated as;

Vx = X / t

Vx = ( 8 m ) / (1.2 s )

Vx = 6.67 m/s

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Answer:

Explanation:

The mass of the car can be found by using the formula

\(m = \frac{2k}{ {v}^{2} } \\ \)

From the question we have

\(m = \frac{2 \times 300000}{ {20}^{2} } = \frac{600000}{400} = \frac{6000}{4} \\ \)

We have the final answer as

Hope this helps you

The final velocity of rock 2 after the collision is <−31.4, 19.7, 15.6> m/s. It is known that the total momentum of a system of particles is conserved if there are no external forces acting on it. Thus, by applying the law of conservation of momentum we can find the final velocity of rock 2 after the collision.

Before the collision, the total momentum of the system is: p1 + p2where p1 and p2 are the momenta of rock 1 and rock 2 respectively. Therefore:p1 + p2 = m1v1 + m2v2where m1 and m2 are the masses of rock 1 and rock 2 respectively, v1 and v2 are their velocities just before the collision, and p1 and p2 are their momenta.In order to find the final velocity of rock 2, we can apply the law of conservation of momentum: p1 + p2 = p'1 + p'2where p'1 and p'2 are the momenta of rock 1 and rock 2 respectively just after the collision. We can solve for p'2 and then use it to find the final velocity of rock 2:p'2 = p1 + p2 - p'1.

We can calculate the momenta of rock 1 and rock 2 just before the collision: p1 = m1v1 = 10 kg <48, 45, -20> m/s = <480, 450, -200> kg·m/sp2 = m2v2 = 5 kg <-9, 5, 11> m/s = <-45, 25, 55> kg·m/s We can also calculate the momenta of rock 1 and rock 2 just after the collision:p'1 = m1v'1 = 10 kg <-10, 36, -5> m/s = <-100, 360, -50> kg·m/sp'2 = m2v'2where v'1 and v'2 are the velocities of rock 1 and rock 2 respectively just after the collision. We are asked to find the final velocity of rock 2, which is v'2. Thus, we need to solve for v'2 from the equation: p'2 = p1 + p2 - p'1 Substituting the values we have calculated:p'2 = <480, 450, -200> + <-45, 25, 55> - <-100, 360, -50>p'2 = <35, 115, -105> kg·m/s Now we can find the final velocity of rock 2:v'2 = p'2/m2 = <35, 115, -105> kg·m/s ÷ 5 kg = <7, 23, -21> m/s Therefore, the final velocity of rock 2 after the collision is <−31.4, 19.7, 15.6> m/s.

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Answer:

Respect is a feeling of admiration for someone or something elicited by their abilities, qualities or achievements.

Explanation:

Answer:

7.656 m/s

Explanation:

El sonido viaja a cierta velocidad y tiene una frecuencia y longitud de onda. La relación entre la velocidad del sonido (V), su frecuencia (f) y la longitud de onda (λ) es la misma que para todas las ondas, está dada por la ecuación:

V = fλ

pero f = 1/T

∴ V = λ/T

donde T es el período

Dado que:

período (T) es el tiempo necesario para subir y bajar = 3.2 s

La distancia entre dos crestas es la longitud de onda (λ) = 24.5 m

V =  λ/T = 24.5 / 3.2 = 7.656 m/s

V = 7.656 m/s

The force on the driver is 7629 N. The velocity of the second ball is 3.6 m/s. The combined velocity of the balls is 13.37 m/s.

We have to find the acceleration using;

v = u - at

v = final velocity = 0 m/s

u = initial velocity = 35.6m/s

a = acceleration = ?

t = time = 0.35 s

u = at

a = u/t = 35.6m/s / 0.35 s

a = 101.7 ms-2

The force on the driver =  75kg ×  101.7 ms-2 = 7629 N

Using the principle of conservation of momentum;

Momentum before collision = momentum after collision

m1u1 +m2u2 = m1v1 + m2v2

Hence

(3.2 × 4.1) + 0 = (3.2 × 1.5) + 2.3v2

13.12 = 4.8 + 2.3v2

13.12 - 4.8 = 2.3v2

v2 = 13.12 - 4.8/2.3

v2 = 3.6 m/s

Using the principle of conservation of linear momentum;

m1u1 + m2u2 = m1v1 + m2v2

(4.3 × 18.6) + (5.8 × 9.5) = (4.3 + 5.8) v

v = 79.98 + 55.1/10.1

v = 13.37 m/s

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1,012 m/s is the average velocity at an acceleration of 2.7 x 10^-3 m/s², comparable to the earth's free fall acceleration equivalent to the free fall acceleration of the Earth.

1.012 m/s is the  average speed of a moving object and 2.7 x 10^-3 m/s² is the acceleration which is

a). The average speed is-

If the orbital period of the moon is T=27.3 days=2358720s, the average velocity is

v = 2πr/T

v = 2π (3.8 x 10^8m ) / 2358720 s

v = 1.012 m/s

Much greater than the acceleration of free fall on Earth.

b). The acceleration of the Moon is -

a = v²/r

a = (1.012 m/s)²/ 3.8 x 10^8 m/s²

a = 2.7 x 10^-3 m/s²

As is much smaller than the than acceleration in free fall.

c.) The free fall acceleration on the earth is -

Attributed to the gravitational acceleration of 9.8 m/s2. Therefore, the average acceleration of the Moon is much less than the free-fall acceleration of the Earth.

Equivalent to the free fall acceleration of the Earth.

∴ 1,012 m/s is the average velocity and 2.7 x 10^-3 m/s² is the acceleration, the average acceleration of the moon is much less than that of the earth in free fall.

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The velocity (speed) of the satellite in its circular orbit is approximately 10,834.87 m/s.The velocity (speed) of the satellite in its circular orbit can be calculated using the following formula:

v = sqrt(GM/r)

where v is the velocity of the satellite, G is the gravitational constant (6.67 x 10^-11 N m^2/kg^2), M is the mass of the Earth (5.97 x 10^24 kg), and r is the radius of the orbit.

First, we need to convert the radius of the orbit from miles to meters:

r = 22,236 miles * 1609.34 m/mile = 35,786,186.4 m

Substituting the values of G, M, and r into the formula, we get:

v = sqrt((6.67 x 10^-11 N m^2/kg^2)(5.97 x 10^24 kg)/(35,786,186.4 m))

= 10,834.87 m/s

Therefore, the velocity (speed) of the satellite in its circular orbit is approximately 10,834.87 m/s. The force keeping the satellite in orbit is the centripetal force, which is given by the formula F = mv^2/r, where m is the mass of the satellite and r is the radius of the orbit. By equating this with the given force of 42.3 N.

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The speed is constant and the direction of motion changes.

Thus, the car maintains a constant speed and it does not maintain a constant velocity - the instantaneous speed varies as it goes around the corner due to the change in direction of motion.

When a car rounds a corner at a steady speed, it changes its direction of motion, and therefore, its velocity changes as well. Velocity is a vector quantity that takes into account both the speed and direction of an object's motion. Since the direction changes, the velocity changes as well. However, if the car maintains the same speed throughout the turn, then the speed remains constant. Speed is a scalar quantity that only takes into account the magnitude of an object's motion, and it is measured as the distance traveled per unit of time.

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The density of galena is 7.56 g/cm³.

We need to know about the density to solve this problem. Density can be described as how much the mass is in a volume unit. It can be written

ρ = m / V

where ρ is density, m is mass and V volume

From the question above, we know that

m = 12.4 g

V = 1.64 cm³

By substituting the given parameter, we can calculate the density

ρ = m / V

ρ = 12.4 / 1.64

ρ = 7.56 g/cm³

Hence, the density of galena is 7.56 g/cm³.

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