Answer: 27 m/s
Explanation:
vo = 15 m/s
a = 2 m/s^2
t = 6s
v = vo + at
v = 15 + 2(6)
v = 15 + 12
v = 27 m/s
35. A daredevil is launched out of a
cannon with an initial horizontal
velocity of 30 m/s. If it took a total
of 13 s for the daredevil to land in
the safety net, how far was the fall
during the flight?
Answer:
845 m
Explanation:
Given in the y direction:
v₀ = 0 m/s
a = 10 m/s²
t = 13 s
Find: Δy
Δy = v₀ t + ½ at²
Δy = (0 m/s) (13 s) + ½ (10 m/s²) (13 s)²
Δy = 845 m
Quantum numbers are interrelated values that indicate a specific orbital - the principal quantum number, n; the angular momentum quantum number, l; and the magnetic quantum number, ml.
Which one of the following is an allowed set of quantum numbers?
a) n = 3, l = 1, ml = -2
b) n = 2, l = 0, ml = 1
c) n = 2, l = 2, ml = - 1
d) n = 3, l = 2, ml = - 1
Due to the fact that they go against one or more of the aforementioned restrictions, options a), b), and c) are not permitted groups of quantum numbers.
An allowed set of quantum numbers must follow certain rules that govern the behavior of electrons in atoms. The principal quantum number (n) indicates the energy level of the electron, the angular momentum quantum number (l) indicates the shape of the orbital, and the magnetic quantum number (ml) indicates the orientation of the orbital in space. The values of n, l, and ml must all be integers, and they must also satisfy certain constraints.
Of the options given, only option d) n = 3, l = 2, ml = -1 is an allowed set of quantum numbers. This is because n = 3 indicates the electron is in the third energy level, l = 2 indicates that it is in a d orbital (since l = 0 corresponds to an s orbital, l = 1 corresponds to a p orbital, and so on), and ml = -1 indicates that the orbital is oriented in a specific direction in space.
Options a), b), and c) are not allowed sets of quantum numbers because they violate one or more of the constraints mentioned above.
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Carlos is driving home after getting some Whataburger for lunch. The Whataburger bag is full of food, and is sitting in the front seat. He is driving east with a speed of 35 m/s. There is another car driving towards him, with a velocity of -25 m/s. Relative to Carlos, how fast is the Whataburger bag moving?
Answer:
Relative to Carlos the Whataburger is moving at 0 speed.
Explanation:
Carlos speed, \(V_A\) = 35 m/s
speed of another car, \(V_B\) = -25 m/s
The speed of the Whataburger, \(V_w\) = 35 m/s since it is in the same car as Carlos.
The relative of the Whataburger to Carlos is given as;
\(V = V_A - W_w\\\\V = 35 \ m/s - 35 \ m/s\\V = 0\)
Therefore, Relative to Carlos the Whataburger is moving at 0 speed.
What scientist was responsible for the modern periodic table we study today?
The scientist responsible for the modern periodic table that we study today is Dmitri Mendeleev. Mendeleev was a Russian chemist who lived in the 19th century. He is often credited as the creator of the periodic table because of his significant contributions to its development.
In the mid-1860s, Mendeleev was working on organizing the known elements based on their chemical properties. He noticed that there was a recurring pattern in the properties of the elements when they were arranged in order of increasing atomic mass. Mendeleev proposed that these elements could be arranged in a table format, where elements with similar properties would fall into the same groups or columns.
Mendeleev's breakthrough came when he realized that there were some gaps or missing elements in his proposed table. Instead of discarding these gaps, he made a bold move and predicted the existence and properties of the yet-to-be-discovered elements. He left spaces for these elements, specifying their properties based on the patterns he observed.
What made Mendeleev's periodic table significant was that it not only organized the elements based on their atomic masses but also successfully predicted the properties of the missing elements. Over time, his predictions were proven correct when the missing elements were discovered and found to match Mendeleev's descriptions.
Mendeleev's periodic table formed the foundation for the modern periodic table that we use today. Although there have been some modifications and improvements to the table since Mendeleev's time, his work laid the groundwork for understanding the periodicity and organizing the elements based on their properties. His contributions to the field of chemistry and the development of the periodic table have had a lasting impact on our understanding of the elements and their relationships.
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A rectangular vessel has a volume of 400cm3.the vessel has a square cross-sectional area of length 10cm.if the vessel is filled with water.calculate(g=1000kg/m3)
The mass of water in the rectangular vessel can be calculated by multiplying the volume (400 cm³) by the density of water (1000 kg/m³), resulting in a mass of 0.4 kg.
To calculate the mass of the water in the rectangular vessel, we can use the formula:
Mass = Density × Volume
Given that the density of water is 1000 kg/m³ and the volume of the vessel is 400 cm³, we need to convert the volume to cubic meters before calculating the mass.
1 cm³ = 1 × 10^(-6) m³
Volume = 400 cm³ × (1 × 10^(-6) m³/cm³)
= 0.0004 m³
Now we can calculate the mass:
Mass = 1000 kg/m³ × 0.0004 m³
= 0.4 kg
Therefore, the mass of the water in the rectangular vessel is 0.4 kg.
It's important to note that the given information about the square cross-sectional area of length 10 cm is not directly used in this calculation since the volume is already provided. The square cross-sectional area is relevant to determine the volume if it was not given, but in this case, the volume is explicitly given as 400 cm³.
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who was the first president of the united states
Answer:
George Washington
Explanation:
Answer:
well for me
Explanation:
It was George Washington
Newton's law of cooling states that the temperature of an object T, in surrounding air with temperature T, will behave according to the formula: T() = Aekt +Ts where t is time in minutes, A is the difference between the temperature of the object and the temperature of its surroundings and k is a constant A turkey is taken out of the oven with an internal temperature of 165°F and is allowed to cool in a a 75°Froom. After half an hour, the internal temperature of the turkey is 145°F. a. Find the formula that models this situation we need A, Ts and k. Here is a little help: Internal temperature of the turkey when it came out of the oven The Temperature of the room the Turkey in in after leaving the oven = A= (The difference in the two temperatures above) (this is Ts) Replace A and Tg in the equation T(t) = Aekt +Ts. To find k, use the information that when t = 30, T(30) = 145, and solve for k. b. To the nearest degree what will the temperature of the turkey be 50 minutes after it leaves the oven? c. To the nearest minute, how long will it take the turkey to cool to 110 °F?
According to Newton's law of cooling, The formula that models the cooling of the turkey is T(t) = (165 - 75) * e^(k * t) + 75. The temperature of the turkey 50 minutes after it leaves the oven will be approximately 118°F.
(a) The formula that models the cooling of the turkey is T(t) = (165 - 75) * e^(k * t) + 75.
In this case, the temperature difference between the turkey and the room, when it came out of the oven, is A = 165 - 75 = 90°F, and Ts (the temperature of the room) is 75°F. By substituting these values into the equation T(t) = A * e^(k * t) + Ts, we get T(t) = 90 * e^(k * t) + 75.
To find the value of k, we can use the information that when t = 30 minutes, T(30) = 145°F. Substituting these values into the equation and solving for k, we have 145 = 90 * e^(k * 30) + 75. Rearranging and solving, we find k ≈ -0.0207.
(b) The temperature of the turkey 50 minutes after it leaves the oven will be approximately 118°F.
To calculate the temperature at t = 50 minutes, we can use the formula T(t) = 90 * e^(-0.0207 * t) + 75. Substituting t = 50, we have T(50) = 90 * e^(-0.0207 * 50) + 75. Evaluating this expression, we find T(50) ≈ 118°F.
(c) It will take approximately 145 minutes for the turkey to cool to 110°F.
To determine the time it takes for the turkey to reach a temperature of 110°F, we can rearrange the equation T(t) = 90 * e^(-0.0207 * t) + 75 and solve for t. So, 110 = 90 * e^(-0.0207 * t) + 75. Solving this equation, we find t ≈ 145 minutes.
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How fast is a cat that runs 50 meters in 10 seconds?
Answer:
50 m in 10 sec….divide 50 by 10 to convert to metres per second = 5 m/s. Then multiply by 3.6 (3600 seconds in an hour divided by 1000) to convert to kilometres per hour =18 m/s. To convert to mph divide by 1.609 =11.18 mph.
Explanation:
Answer:
5 meters per second
Explanation:
1) Set up a proportion.
\(\frac{50}{10}\) = \(\frac{x}{1}\)
2) Solve the proportion.
x = 5 because 50 ÷ 10 is 5.
electrons are accelerated through a potential difference of 890 kv, so that their kinetic energy is 8.90×105 ev.
When electrons are accelerated through a potential difference, they gain kinetic energy. In this case, the electrons are accelerated through a potential difference of 890 kV, resulting in a kinetic energy of \(8.90 × 10^5 eV.\)To understand this concept, let's break it down step-by-step:
1. Potential difference: This refers to the voltage applied across the acceleration region. In this case, it is 890 kV, where "kV" stands for kilovolts.
2. Kinetic energy: This is the energy associated with the motion of an object. In this case, the electrons gain a kinetic energy of\(8.90 × 10^5 eV\), where "eV" stands for electron volts.
3. Conversion: To convert the potential difference from kilovolts to electron volts, we multiply by the elementary charge of an electron, which is approximately\(1.6 × 10^-19 C\) (coulombs). So, \(890 kV * (1.6 × 10^-19 C/eV) = 1.424 × 10^-14 eV.\)
4. Conclusion: The electrons gain a kinetic energy of \(1.424 × 10^-14 eV\)when accelerated through a potential difference of 890 kV.
In summary, the potential difference of 890 kV accelerates electrons, resulting in a kinetic energy of\(8.90 × 10^5 eV.\)
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when entering traffic after being parked at a curb you
When entering traffic after being parked at a curb, you should proceed with caution, yield to oncoming traffic, and merge smoothly into the flow of vehicles.
When entering traffic from a parked position at a curb, it is important to follow certain steps to ensure a safe and smooth transition. Here is a step-by-step explanation:
1. Check for traffic: Before entering the flow of traffic, look in both directions to ensure there is a safe gap in the traffic.
2. Signal your intention: Activate your vehicle's turn signal to indicate your intention to merge into the traffic.
3. Yield to oncoming traffic: If there are vehicles approaching, yield the right of way and wait for a safe gap to merge into the traffic. It is important to give way to vehicles already on the road.
4. Accelerate smoothly: Once you have found a suitable gap, accelerate smoothly and merge into the flow of traffic. Be mindful of the speed and spacing of the vehicles around you.
5. Adjust your speed: Gradually adjust your speed to match the flow of traffic, ensuring that you are not impeding the normal movement of vehicles.
By following these steps, you can safely enter traffic after being parked at a curb, allowing for a seamless transition into the flow of vehicles.
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if a system has 46.5 j of heat added to it, and the system does 75.5 j of work on its surroundings, what is the change in the internal energy of the system, in j?
If a system has 46.5 j of heat added to it, and the system does 75.5 j of work on its surroundings. 29 j is the change in the internal energy of the system.
Internal energy refers to the energy that exists within the system. It is represented by the letter "U" in English.
Thermal energy is another name for internal energy. It is the energy of a substance as a result of the kinetic and potential energies connected to the ad hoc motion of all the constituent particles.
Internal energy, which is measured in KJ or Joule, is the energy attributed to the chaotic arrangement or random motion of particles within the system. Using the formula for internal energy, we can calculate the same.
The difference between the heat flow in a system and the work done by or on the system (PV) equals the change in internal energy, and the change in internal energy formula aids in calculating the same.
Energy Equation within the energy of the universe is constant, in accordance with the basic law of thermodynamics.
Additionally, the sum of the work done and the heat transported is equal to the change in a system's internal energy.
Additionally, the sum of the change in the system's internal energy and the work performed by the PV system equals the heat added or flown.
The Change in Internal Energy Formula is:
ΔU = Q + W
Here,
U = the total change in internal energy within the system
Q = the heat exchanged between a system and its surroundings (outside the system)
W = work done by or on the system
= 46.5 - 75.5
= 29j
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A dentist wants a small mirror that when placed 2cm from a tooth, will produce 3× upright image. What kind of mirror must be used and what must its focal length be?
A. concave mirror, 3.0cm
B. concave mirror, 1.5cm
C. convex mirror, 3.0cm
D. convex mirror, 1.5cm
A dentist wants a small mirror that when placed 2cm from a tooth, will produce 3× upright image. What kind of mirror must be used and what must its focal length be the correct answer is B. concave mirror, 1.5cm
To determine the type of mirror and its focal length needed to produce a 3× upright image when placed 2 cm from a tooth, we can use the mirror equation:
1/f = 1/di + 1/do
Where f is the focal length of the mirror, di is the image distance, and do is the object distance.
In this case, the object distance (do) is given as 2 cm, and the magnification (M) is 3×, which means the image distance (di) will be three times the object distance.
Using the magnification formula:
M = -di/do
We can find that di = -3 × do.
Substituting these values into the mirror equation, we have:
1/f = 1/(-3 × do) + 1/do
Simplifying this equation, we get:
1/f = -2/do
To obtain a positive focal length (indicating a concave mirror), the object distance (do) must be negative. Therefore, a concave mirror must be used.
Among the given options, the only concave mirror with a focal length that satisfies the equation is option B: concave mirror, 1.5 cm. Therefore, the correct answer is B.
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Baseball pitcher throws a 250g baseball to make it accelerate 250m/s the instant that it leaves his hand. How much energy (in joules) is expended (how much work is done) if the same baseball travels a distance and 30 meters?
The energy expended by the pitcher on the baseball for the acceleration is 7812 J.
Step by step explanationTo find the work done on the baseball, we need to use the work-energy principle, which states that the work done on an object is equal to the change in its kinetic energy. In this case, we can assume that the initial kinetic energy of the baseball is zero, since it is at rest before the pitcher throws it. The final kinetic energy of the baseball can be calculated using the formula:
KE = (1/2)mv^2
where m is the mass of the baseball (0.25 kg), and v is its final velocity (250 m/s). Substituting these values, we get:
KE = (1/2)(0.25 kg)(250 m/s)^2
= 7812.5 J
So the final kinetic energy of the baseball is 7812.5 J. To find the work done in stopping the baseball after it has traveled 30 meters, we need to use the work-energy principle again. Since the final velocity of the baseball is zero, its final kinetic energy is also zero. Therefore, the work done on the baseball to bring it to a stop is equal to its initial kinetic energy of 7812.5 J.
We can use the work formula:
W = Fd
where W is the work done, F is the force applied, and d is the distance over which the force is applied. In this case, the force that stops the baseball is the force of friction between the baseball and the air. We can assume that this force is constant over the 30-meter distance, so we can calculate the work done as:
W = Fd = KE = 7812.5 J
Rearranging the formula, we get:
F = W/d
= 7812.5 J / 30 m
= 260.4 N
So the force of friction on the baseball is 260.4 N. Now we can use the formula for work again to find the energy expended by the pitcher:
W = Fd
= (260.4 N)(30 m)
= 7812 J
So the energy expended by the pitcher is 7812 J.
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Please answer the following question
Answer:
Where is the resistance value?
Question is incomplete
True or False: The variables in the equation 4x-(5y)2=64x-(5y)2=6 are 4, 5, and 6
Answer:
true
Explanation:
Answer:
true
Explanation:
A elastic spring is compressed by an amount x. Show that its P.E. is 1/2 kx2
where k is the spring constant.
Answer:
The potential energy (P.E.) stored in an elastic spring is equal to the work done in compressing or stretching the spring.
When a spring is compressed or stretched, the force required to do so is given by Hooke's law, which states that the force F required to compress or stretch a spring by an amount x is given by
F = kx, where k is the spring constant.
The work done in compressing or stretching a spring is equal to the force required to do so multiplied by the distance over which the force is applied.
In the case of a spring, this distance is equal to the amount x by which the spring is compressed or stretched.
Therefore, the work done in compressing or stretching a spring is given by
W = Fd = kx * x = kx^2.
The potential energy stored in the spring is equal to the work done to compress or stretch it.
Therefore, the potential energy of a spring that is compressed by an amount x is given by P.E. = W = kx^2.
Substituting kx^2 = 1/2 kx^2, we find that
P.E. = 1/2 kx^2.
This shows that the potential energy stored in an elastic spring is equal to 1/2 times the spring constant multiplied by the amount x by which the spring is compressed or stretched.
Explanation:
Suppose a rollerblade racer finnished a 132 meter race in 18 seconds. What is the average speed of the rollerblade racer
Answer:
As = 7.33 [m/s]
Explanation:
To solve this problem we must use the definition of the average speed, which is equal to the relationship between the distance over time.
As = x/t
where:
As = average speed [m/s]
x = distance = 132 [m]
t = time = 18 [s]
As = 132/18
As = 7.33 [m/s]
. Which of these clients is the most likely candidate for Aaron Beck's form of cognitive therapy?
a) Albert, who suffers from mania
b) Barbara, who suffers from depression
c) Robert, who suffers from schizophrenia
d) Virginia, who has been diagnosed with dissociative identity disorder
Virginia, who has been diagnosed with dissociative identity disorder, is not a likely candidate for Aaron Beck's form of cognitive therapy.
This type of therapy is typically used for individuals with depression, anxiety, and other mood disorders, rather than dissociative disorders. Dissociative identity disorder requires a specialized approach, such as cognitive-behavioral therapy or trauma-focused therapy, that focuses on addressing the underlying trauma and helping the individual integrate their different identities. It is important for therapists to assess each client's unique needs and tailor their approach accordingly to provide the most effective treatment.
Aaron Beck's cognitive therapy is most effective for individuals dealing with depression, anxiety, and other mood disorders. While Virginia's diagnosis of dissociative identity disorder is a serious mental health issue, it is not the most likely candidate for cognitive therapy. Dissociative identity disorder requires a different therapeutic approach, often involving trauma-focused therapy and the integration of multiple identities. Cognitive therapy would be more suitable for a client dealing with a mood disorder, such as depression or anxiety.
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Which would most likely contain this same type of current? the air above a wildfire a carton of milk in a refrigerator a snowdrift on a shady mountainside a boulder in a hot desert
Answer: the air above a wildfire
Explanation:
First part of question is: The diagram shows currents that form as water is heated.
When water is being heated from below, convection currents are used. This happens when the molecules at the bottom are heated thus giving them energy and enabling them rise to the surface. The colder water at the surface will therefore sink to the bottom where is is heated making it rise as well and the process is repeated.
When a wildfire is ignited, the concept is the same. The air above the wildfire is the water in this scenario. It is heated at the bottom and rises thereby forcing the air above to come down and be heated as well. Both situations uses convectional currents.
Answer:
The air above a wildfire
Explanation:
A small child has a wagon with a mass of 10 kilograms. The child pulls on the wagon with a force of 2 newtons. What is the acceleration of the wagon?
Answer:
0.2 m/s²Explanation:
Given,
Mass ( m ) = 10 kg
Force ( f ) = 2 Newtons
Acceleration ( a ) = ?
Now, let's find the acceleration :
We know that,
\(f = ma\)
Plug the values
\(2 = 10a\)
Swap the sides of the equation
\(10a = 2\)
Divide both sides of the equation by 10
\( \frac{10a}{10} = \frac{2}{10} \)
Calculate
\(a = 0.2 \: {metre \: per \: second \: }^{2} \)
Hope this helps...
Best regards!!
Calculate the total charge Q of a thin plate with the charge density distribution p(x,y) = x²y mC/m². The plate shape is restricted by the lines: y=2-x² and y=2x-1, where x and y are measured in metres. a) Sketch the plate shape. [10 marks] [4 marks] b) Present the total charge through the double integral. c) Reduce the double integral to the repeated integrals and show limits of integration. [6 marks] d) Calculate the integral and present your answer with five significant figures. [20 marks]
a) Sketch the plate shape: we get a shape that resembles a trapezoid.
The plate shape is determined by the lines y = 2 - x² and y = 2x - 1. To sketch the plate shape, we can plot these two lines and shade the region in between them. The intersection points of the lines are found by solving the equations simultaneously:
2 - x² = 2x - 1
Simplifying, we get:
x² + 2x - 3 = 0
Factoring, we have:
(x - 1)(x + 3) = 0
So, x = 1 and x = -3. Plugging these values into the equations of the lines, we find the corresponding y-values:
For x = 1:
y = 2 - (1)² = 1
For x = -3:
y = 2(-3) - 1 = -7
Plotting these points and connecting them with the lines, we get a shape that resembles a trapezoid.
b) Total charge through the double integral:
To find the total charge Q, we need to integrate the charge density p(x, y) over the entire plate. We can express this as a double integral:
Q = ∬ p(x, y) dA
c) Reducing the double integral to repeated integrals: The limits of integration for x are the values of x that define the boundaries of the plate shape, which are -3 to 1.
Since the plate shape is described by the lines y = 2 - x² and y = 2x - 1, we can rewrite the double integral as a repeated integral by integrating with respect to x and y separately:
Q = ∫∫ p(x, y) dy dx
The limits of integration for y are from the lower curve y = 2 - x² to the upper curve y = 2x - 1. The limits of integration for x are the values of x that define the boundaries of the plate shape, which are -3 to 1.
d) Calculating the integral: The total charge Q of the thin plate is approximately 12.4 mC.
Now, we can evaluate the double integral to find the total charge Q:
Q = ∫(-3 to 1) ∫(2 - x² to 2x - 1) x²y dy dx
Performing the inner integral with respect to y first, we get:
Q = ∫(-3 to 1) [x²(y²/2 - y)] from 2 - x² to 2x - 1 dx
Simplifying the inner integral, we have:
Q = ∫(-3 to 1) [(x²/2)(2 - x²) - x²(2x - 1)] dx
Expanding and simplifying further, we get:
Q = ∫(-3 to 1) (x² - x⁴/2 - 4x³ + 2x²) dx
Integrating term by term, we have:
Q = [x³/3 - x⁵/10 - x⁴ + 2x³/3] from -3 to 1
Evaluating the integral at the limits, we get:
Q ≈ 12.4 mC (rounded to five significant figures)
Therefore, the total charge Q of the thin plate is approximately 12.4 mC.
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A 3,000kg car rests on rough horizontal ground. A rope is
attached to the car and is pulled with a force of 11,000N to the
left. As a result, the car accelerates at 3 m/s2. The coefficient of
sliding friction (1) between the car and the ground is?
Answer:
0.07
Explanation:
Huge Brain
Coefficient of friction between the car and the ground will be 0.07.
Given in the question,
Mass of the car 'm' = 3000 kgForce 'F' by which the car is pulled = 11000 NAcceleration 'a' by which the car gets accelerated = 3 meters per second²Force applied on the car by which the car is accelerated,
F = ma
= 3000 × 3
= 9000 N
Force \(F_k\) to overcome the friction = 11000 - 9000
= 2000 N
Gravitational force F' on the car = mg
= 3000(9.8)
= 29400 N
Since, \(\mu_k=\frac{F_k}{F'}\)
\(=\frac{2000}{29400}\)
\(=0.068\)
≈ 0.07
Therefore, coefficient of friction between the car and the ground will be 0.07.
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How can you decrease the amount of energy an object has?
Answer: Hello There!...............
You decrease the kinetic energy by either stopping the object and let it rest (which would give it potential energy) or changeing the slope.
Explanation:
Mark me brainest please. Hope this helps. Anna ♥
Depending on the sort of energy involved, you can use a variety of techniques to reduce the quantity of energy an object contains. To slow motion in mechanical systems, you can add friction or resistance, which turns kinetic energy into heat.
When dealing with thermal energy, you can place the object in a cooler environment, which will enable it to transmit heat and cool down. It is possible to lessen an object's potential energy by changing its height or location within a gravitational field. Reactions that release energy can dissipate chemical energy. These strategies essentially entail aiding energy transfer or conversion to a less energetic state, hence lowering the object's overall energy content.
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What process is used to make food safer for consumption by killing bacteria within the food ? A. freezing B. fermentation C.antibiotic treatment D. pasteurization
A sonar echo returns to a submarine 2.30 s after being emitted. What is the distance to the object creating the echo?
A sonar echo returns to a submarine 2.30 s after being emitted. The distance to the object creating the echo is 1702m
Let's understand the solution in detail,
The speed of sound in water is equal to 1480m/s
The time the waves take to hit the object and return back to the receiver is 2.30s
As we already know distance = speed x time
So the distance of the object = (speed x time)/2
We are dividing the distance by two because sound travels the same distance while reaching the object from the emitter and reaching back to the receiver after getting reflected by the object.
Therefore the distance comes out as \(\frac{1480 x 2.30}{2}\)
which is equal to 1702 meters
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new york, Vermont, Massachusetts are specifically what region of the united states? and what two wind directions do you combine? (north, south, west, east)
Answer:
if you mean the regions during slavery, North, but if in general, East. (think East Coast)
Part C
Just like in the diagram, when Earth was primarily liquid, it separated into layers. What prediction can you make about the
densities of Earth's different layers?
When the Earth was primarily liquid, it separated into layers. The density of Earth's different layers may be predicted. For instance, it is assumed that the outermost layer, or crust, is less dense than the inner layers.
The Earth's crust is mostly composed of silicates (such as quartz, feldspar, and mica) and rocks, which are less dense than the mantle, core, or outer core.
The mantle is composed of solid rock, which is denser than the Earth's crust.
The core is the most dense layer, and it is composed of a liquid outer core and a solid inner core.
Most of the Earth's layers are composed of different types of rock and minerals.
The layers were formed from the molten material that cooled and solidified.
The Earth's layers are divided into four groups, or spheres, that represent different levels of density.
The lithosphere is the outermost layer, which includes the crust and upper mantle.
The asthenosphere is the soft layer beneath the lithosphere.
The mantle is a solid layer that surrounds the core.
The core is the Earth's central layer, consisting of a liquid outer core and a solid inner core.
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find the fundamental unit involved in following derived unit a Newton Pascal cubic meter watt
Answer:
HAHAHAH
Explanation:
A 45 kg wagon is being pulled with a rope that makes an angle of 380 with the horizontal. The applied force is 410 N and the coefficient of kinetic friction between the wagon and the ground is 0. 18.
b) What are the x and y components of the applied force?
c) What is the normal force acting on the wagon? Is this greater than or less than the wagon’s weight? What impact does this have on the kinetic friction force?
d) Find the acceleration of the wagon in the x direction
a) The weight of the wagon can be -249.6 N (negative because the force is acting downwards)
b) The x component of the applied force is 410cos(38°) ≈ 318.7 N and the y component is 410sin(38°) ≈ 252.6 N.
c) The normal force acting on the wagon is 436.5 N, which is greater than the wagon's weight. This means there is a net upward force on the wagon, reducing the force of friction.
d), The acceleration of the wagon in the x direction is\(6.505 m/s^2.\)
a) The weight of the wagon can be calculated as:
Weight = mass x gravity
= 45 kg x 9.8 \(m/s^2\)
= 441 N
The angle of the applied force with the horizontal is 380, so the x and y components of the applied force can be calculated as:
F_x = F_applied * cos(380)
= 410 N * cos(380)
= 327.2 N
F_y = F_applied * sin(380)
= 410 N * sin(380)
= -249.6 N (negative because the force is acting downwards)
b) The normal force, N, acting on the wagon can be calculated as:
N = Weight + F_y
= 441 N - 249.6 N
= 191.4 N
The normal force is less than the wagon's weight, which means that the wagon is experiencing a net force downwards. This impacts the kinetic friction force, which will act in the opposite direction to the wagon's motion to resist this downward force.
c) The coefficient of kinetic friction, μ_k, is given as 0.18. The force of kinetic friction, F_k, can be calculated as:
F_k = μ_k * N
= 0.18 * 191.4 N
= 34.452 N
The acceleration of the wagon in the x direction, a_x, can be calculated using Newton's second law, which states that:
ΣF_x = m*a_x
d) The only force in the x direction is the applied force, so we have:
F_x - F_k = m*a_x
Substituting the values, we get:
327.2 N - 34.452 N = 45 kg * a_x
Simplifying:
292.748 N = 45 kg * a_x
a_x = \(6.505 m/s^2\)
Therefore, the acceleration of the wagon in the x direction is\(6.505 m/s^2.\)
Learn more about Newton's second law
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how much force is needed to accelerate a 20 kg mass at a rate of 4 m/s to the second power?
Answer:
So 55 Newtons are needed.
Answer:
80 N
Explanation:
mass (m) = 20kg
acceleration (a) = 4m/s^2
Force (F) = ?
.°. F = ma
= 20 × 4 = 80
.°. F = 80 N
Thus, The Force is needed to accelerate a 20 kg mass at a rate of 4 m/s^2 is 80 N
-TheUnknownScientist