The bus travelled at velocity 15 ms-l for 5 minutes before it came to a stop. By using suitable linear equation, calculate the distance the bus has travelled.​

Answer:

money is not rare. you can find it everywhere. what exactly is the question? whether it is bad or not is an opinion.

Explanation:

The characteristics of the scalar product allows to find the angle between the two vectors is:

The scalar product is the product between two vectors whose result is a scalar.

            A . B = |A|  |B| cos θ

Where A and B are the vectors, |A| and |B| are the modules of the vectors and θ at the angle between them.

The vector is given in Cartesian coordinates and the unit vectors in these coordinates are perpendicular.

            i.i = j.j = 1

            i.j = 0

            A . B = (4 i - 4j). * -5 i + 7j)

            A . B = - 4 5 - 4 7

            A. B = -48

We look for the modulus of each vector.

           |A| = \(\sqrt{x^2 +y^2 }\)

           |A| = \(\sqrt{4^2 + 4^2}\)  

           |A| = 4 √2

          |B| = \(\sqrt{5^2 +7^2}\)

          |B| = 8.60

We substitute.

            -48 = 4√2  8.60  cos θ

            -48 = 48.66 cos θ

            θ = cos⁻¹   \(\frac{-48}{48.664}\)  

            θ = 170º

In conclusion using the dot product we can find the angle between the two vectors is:

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Answer:

endothermic

Explanation:

An endothermic is any process with an increase in the enthalpy H (or internal energy U) of the system. In such a process, a closed system usually absorbs thermal energy from its surroundings, which is heat transfer into the system.

Answer:

Height of cliff = 147.43 m

Explanation:

We have equation of motion s = ut + 0.5 at²

Consider the vertical motion of stone and up as positive,

Initial velocity, u = 15sin30=7.5m/s

Time taken, t = 6.30 s

Acceleration, a = -9.81 m/s²

Substituting

            s = ut + 0.5 at²      

            s = 7.5 x 6.30 + 0.5 x (-9.81) x 6.30²

            s = -147.43 m

So the stone goes below 147.43 m below the initial postilion

Height of cliff = 147.43 m      

1) The force acting on the object during the time interval 0-3 seconds is 1/3 N.

2) The force acting on the object during the time interval 6-10 seconds is -0.5 N.

3) There is no time interval in which no force acts on the object.

(i) Force acting on the object in time interval 0-3 seconds. Force acting on the object is equal to the product of its mass and acceleration, i.e.,F = ma.

In the given velocity-time graph, the acceleration of the object can be determined by determining the slope of the velocity-time graph from 0 to 3 seconds.

Slope = (change in velocity) / (change in time)= (20-0) / (3-0) = 20/3 m/s^2

Acceleration, a = slope= 20/3 m/s^2

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × 20/3= 1/3 N.

Therefore, the force acting on the object during the time interval 0-3 seconds is 1/3 N.

(ii) Force acting on the object in time interval 6-10 seconds. Similar to the first question, the force acting on the object in time interval 6-10 seconds can be determined by determining the acceleration of the object during this time interval.

The slope of the velocity-time graph from 6 seconds to 10 seconds can be determined as follows:

Slope = (change in velocity) / (change in time)= (-20-20) / (10-6) = -40/4= -10 m/s^2 (negative sign indicates that the object is decelerating)

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × (-10)= -0.5 N.

Therefore, the force acting on the object during the time interval 6-10 seconds is -0.5 N.

(iii) Time interval in which no force acts on the object. There is no time interval in which no force acts on the object. This is because, as per Newton's first law of motion, an object will continue to remain in a state of rest or uniform motion along a straight line unless acted upon by an external unbalanced force.In other words, if the object is moving with a constant velocity, there must be a force acting on the object to maintain its motion.

Therefore, there is no time interval in which no force acts on the object.

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Answer:

2.405 m/s

Explanation:

Given that,

Mass of a women, m₁ = 60 kg

Mass of a ball, m₂ = 3.9 kg

Velocity of the ball, v₂ = 37 m/s

We need to find the velocity of the woman. It is a concept based on the conservation of linear momentum. Let v₁ is the velocity of the woman. So,

\(m_1v_1=m_2v_2\\\\v_1=\dfrac{m_2v_2}{m_1}\\\\v_1=\dfrac{3.9\times 37}{60}\\\\v_1=2.405\ m/s\)

So, the velocity of the woman is 2.405 m/s.

Answer:

Condenses on dust

Explanation:

Pls brainiest

Answer:

condenses on dust

Explanation:

An object with an initial velocity of 5m/s has a constant acceleration of \(2m/s^2\) .The object has traveled a distance of 50 meters when it is speed is 15m/s how far has us travelled​

To find the distance traveled by the object, we can use the equation:

\(v^2 = u^2 + 2as\)

where v is the final velocity, u is the initial velocity, a is the acceleration, and s is the distance traveled.

Given:

Initial velocity (u) = 5 m/s

Acceleration (a) = 2\(m/s^2\)

Final velocity (v) = 15 m/s

We need to solve for s.

Rearranging the equation, we have:

s =\((v^2 - u^2)\) / (2a)

Substituting the given values, we get:

s = \((15^2 - 5^2)\)/ (2 * 2)

s = (225 - 25) / 4

s = 200 / 4

s = 50 m

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If a piece of metal at the bottom of a beaker is 0.50m below the eye, and water is poured into the cylinder to a depth of 0.24m, Then the metal appears closer by 0.38m.

To calculate how much closer the metal appears, we can use the lens maker's formula, which relates the object distance, image distance, and focal length of a lens or in this case, the refractive index of water.

The formula is:

1/f = (n - 1) x (1/R1 - 1/R2)

where f is the focal length, n is the refractive index of the medium (water in this case), R1 is the radius of curvature of the first surface of the medium (in this case, the bottom surface of the beaker), and R2 is the radius of curvature of the second surface of the medium (in this case, the air-water interface at the top of the water level).

Assuming the radius of curvature of both surfaces is large and the surfaces are nearly flat, we can approximate R1 and R2 as infinity, so the formula simplifies to:

1/f = (n - 1) x (1/R2)

Since the piece of metal is at the bottom of the beaker, it acts as the object, and the eye acts as the observer. Initially, the object distance is the distance from the bottom of the beaker to the eye, which is 0.50m.

When water is poured into the beaker to a depth of 0.24m, the new object distance is the distance from the bottom of the beaker to the water level, which is 0.50m - 0.24m = 0.26m.

To calculate the image distance, we can use the thin lens equation:

1/f = 1/o + 1/i

where o is the object distance, and i is the image distance.

Solving for i, we get:

i = (1/f - 1/o)^-1

Since we know that the object distance o is 0.26m, we just need to calculate the focal length f using the lens maker's formula.

1/f = (n - 1) x (1/R2) = (4/3 - 1) x (1/0.24m) = 1/0.72m

f = 0.72m

Plugging in the values, we get:

i = (1/0.72m - 1/0.26m)^-1 = 0.12m

Therefore, the metal appears closer by 0.50m - 0.12m = 0.38m.

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Answer:

128 Kelvin = 128 - 273.15 = -145.15 Celsius. Temperature conversion chart Sample temperature conversions 103.55 Kelvin to degrees Fahrenheit 39.82 degrees Fahrenheit to Kelvin

Explanation:

hope this helps have a good day

The volume of the ark is 11163 cubic feet.

The term volume of a box refers to the product of the length, width and height of the box. We have been told that the ark of Noah could be likened to a box and we have been asked to obtain its volume.

Hence;

width = 3.5  * 50 = 175 inches or 14.58 feet

length = 300 * 3.5 = 1050 inches or 87.5 feet

height = 30  * 3.5 = 105 inches or 8.75 feet

Volume of the ark = 14.58 feet * 87.5 feet *  8.75 feet

Volume of the ark = 11163 cubic feet

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Answer:

9

Explanation:

The velocity of the car is 5.5 m/s. Then the centripetal acceleration of the car will be 0.6 m/s².

Acceleration is a physical quantity measuring the rate of change in velocity. It has both magnitude and direction.

Centripetal acceleration is the acceleration of an  object moving through a circular path. Thus its measures the rate of change in velocity of the body moving in the curvature path.

The centripetal acceleration = V²/R.

Where R is the radius of the curvature path.

The car moves 50 m in 9 seconds. Its velocity is 50/9 = 5.5 m/s.

Thus, centripetal acceleration = (5.5 × 5.5) m/s/ 50 m = 0.6 m/s².

Therefore, the centripetal acceleration of the car moving at a speed of 9 m/s through curvature path is 0.6 m/s².

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Answer:

\(a=2.8\ m/s^2\)

Explanation:

Given that,

Initial velocity of an object, u = 22 m/s

Final velocity of an object, v = 36 m/s

Time, t = 5 s

It can be assumed to find the average acceleration of the object instead of average velocity.

The change in velocity per unit time is equal to average acceleration of an object. It can be given by :

\(a=\dfrac{v-u}{t}\\\\a=\dfrac{36\ m/s-22\ m/s}{5}\\\\\a=\dfrac{14}{5}\ m/s^2\\\\a=2.8\ m/s^2\)

So, the acceleration of the object is \(2.8\ m/s^2\).

The acceleration of the block is 9N/kg.

Acceleration is the rate at which an object's velocity changes over time. It is typically measured in meters per second squared (m/s2) and is a vector quantity, meaning that it has both a magnitude and a direction. Acceleration can be either positive or negative, depending on the direction of the object's velocity. Positive acceleration occurs when an object's velocity is increasing, and negative acceleration occurs when the velocity is decreasing. Acceleration can also be described as the rate of change of an object's velocity over time. In the simplest terms, acceleration is the rate at which an object speeds up or slows down.

This means that the block will accelerate to the right due to the net force (12N - 3N = 9N) acting on it.

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Answer:

The first scenario!

Explanation:

W=F*d

a) 55*8= 440J

b) 60*6= 360J

c) 50*5= 250J

d) 40*10= 400J

The scenario with the greatest amount of work done on a wagon is "A force of 55 N moves it 8 m" and the Work done is 440N.m.

Work done is simply defined as the energy transfer that takes place when an object is either pushed or pulled over a certain distance by an external force. It is expressed as;

W = F × d

Where F is force applied and d is distance travelled.

From the question;

A force of 55 N moves it 8 m

W = 55N×8m = 440N.m

A force of 60 N moves it 6 m.

W = 60N×6m = 360N.m

A force of 50 N moves it 5 m.

W = 50N×5m = 250N

A force of 40 N moves it 10 m.

W = 40N×10m = 400N.m

Therefore, the scenario with the greatest amount of work done on a wagon is "A force of 55 N moves it 8 m" and the Work done is 440N.m.

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Answer:The correct statement about electric charges is:

"An object with a negative charge and an object with a positive charge will attract each other."

Explanation:

*an object with a negative charge and an object with a positive charge will attract each other" this statement is true.

Electric charge is the physical property of matter that experiences force when it is placed in electric field. F = qE where q is amount of charge, E = electric field and F = is force experienced by the charge. there are two types of charges, positive charge and negative charge which are generally carried by proton and electron resp. like charges repel each other and unlike charges attract each other. the flow charges is called as current. Elementary charge is amount of charge a electron is having, whose value is 1.602 x 10⁻¹⁹ C.

Hence option B is correct.

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Answer:

Approximately \(3.967\; {\rm kg\cdot m\cdot s^{-1}}\).

Explanation:

Convert velocity to the standard units (meters per second):

\(\begin{aligned}v &= 246.2 \; {\rm km \cdot h^{-1}} \\ &= 246.2 \; {\rm km \cdot h^{-1}}\times \frac{1\; {\rm h}}{3600\; {\rm s}} \times \frac{1000\; {\rm m}}{1\; {\rm km}} \\ &\approx 68.389\; {\rm m\cdot s^{-1}}\end{aligned}\).

Convert mass to standard units (kilograms):

\(\begin{aligned} m &= 58\; {\rm g} \\ &= 58\; {\rm g} \times\frac{1\; {\rm kg}}{1000\; {\rm g}}\\ &= 0.058\; {\rm kg}\end{aligned}\).

When an object of mass \(m\) travels at a velocity of \(v\), momentum of that object would be \(p = m\, v\). In standard units, the momentum of this tennis ball would be:

\(\begin{aligned}p &= m\, v \\ &\approx (0.058\; {\rm kg})\, (68.389\; {\rm m\cdot s^{-1}}) \\ &\approx 3.967\; {\rm kg \cdot m\cdot s^{-1}}\end{aligned}\).

Answer:

\(150\ N\)

Explanation:

\(We\ are\ given:\\Acceleration\ of\ the\ elevator= 3\ m/s^2\\Assumed\ mass\ of\ the\ man\ standing\ on\ it=50\ kg\\We\ know\ that,\\Force=Mass*Acceleration\\Or,\\F=ma\\Hence,\\Substituting\ m=50, a=3\ m/s^2,\\Force\ acting\ on\ the\ floor\ of\ the\ elevator=3*50=150\ Newtons\)

The lowest height at which speaker B can be placed above speaker A to produce the lowest sound to the person standing in front of A by superposition and wave interference is ∆y ≈ 2.41 m.

The superposition principle states that the magnitude of the resulting wave when two waves overlap is the sum of the disturbance of the individual waves.

The given parameters are;

Height of speaker B above speaker A = ∆y

Wavelength of the wave = 0.880 meters

Distance between the person standing directly in front of speaker A and speaker A, ∆x = 6.38 meters

Required;

The minimum height of speaker B above speaker A that produces the minimum sound to the person in front of speaker A

Solution;

The minimum sound is given when there is destructive interference of the waves produced by the speakers

When there is destructive interference, the peak of the wave from speaker A coincides with the through of the wave from speaker B which gives;

Distance between a peak and the through of a wave = 0.5 × The wavelength

Therefore, for minimum sound, we have;

Distance from the person to speaker B = 6.38 m + 0.5 × (The wavelength)

Which gives;

Distance from the person to speaker B = 6.38 m + 0.5 × 0.88 m = 6.82 m

Pythagorean theorem is used to find the height of speaker B above speaker A as; ∆y = √(6.82² - 6.38²) ≈ 2.41

The height of speaker B above A is approximately 2.41 meters

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The lowest height that Speaker B can be placed above Speaker A to produce a minimum of sound heard by a person standing Δx=6.38 meters directly in front of Speaker A is

\(\Delta y=1.62m\)

This is further explained below.

Generally, For a person, to hear sound minimum, sound waves from speakers A and B should meet at point P, in opposite phases, so path diff. should be

\(x=(2 n+1) \frac{\lambda}{2},\)

\(\lambda\)= wavelength

\(for $\Delta y$ to be minimum $\Rightarrow x=\frac{\lambda}{2}$ \\\\from figure, in $\triangle A B P$$$\Delta x^2+\Delta y^2=\Delta x^{\prime 2}=\text { (2) }$$\)

Path diff. will be x=B P-A P

\(\begin{aligned}& \quad x=\Delta x^{\prime}-\Delta x \\\\&\Delta x^{\prime}-\Delta x=\frac{\lambda}{2} \quad x=\frac{\lambda}{2} \quad \text { from eq (1) } \\\\&\left.\Delta x^2+\Delta y^2-3.01=0.41 \quad \quad \quad \quad \lambda=0.820 \mathrm{~m}\right] \\\\&\Delta x^2+\Delta y^2=3.42 \\\\&\Delta y^2=(3.42)^2-(3.01)^2 \quad \Delta x=3.01 \mathrm{~m} \\\\&\Delta y=1.62 \mathrm{~m}\end{aligned}\)

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The powder takes the shape of a magnetic field.

Powder morphology is connected to the shape and size of powder particles and is strongly dependent on the manufacturing methods. For example, mechanical alloying/mechanical milling leads to unevenly shaped powder particles, while gas dissipation leads to spherically shaped particles.

Atomized metal powder particles come in two basic particle shapes: those that are almost superbly round called spherical, and those that have lopsided, rounded shapes, called spheroidal.

So we can conclude that Powders are a group of particles of different sizes.

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The coefficient of kinetic friction between the skis and the snow covering the slope is 0.7.

The coefficient of kinetic friction is the ratio of the kinetic friction force of contacting surfaces to the normal force.

The coefficient of kinetic friction between the skis and the snow covering the slope is calculated by applying the following formula.

μ = Ff/N

μ = mgsinθ/mg cosθ

μ = tanθ

where;

μ = tan(35)

μ = 0.7

Thus, the coefficient of friction is determined from the ratio of kinetic friction and normal force.

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Answer:

C

Explanation:

C

The relationship is , the square of the period of an orbit is proportional to the cube of its Orbital Radius.

The relationship between orbital radius and period is described by Kepler's Third Law of Planetary Motion, which states that the square of the period of an orbit is proportional to the cube of its semi-major axis.

In other words, if we denote the orbital radius (semi-major axis) by "a" in units of astronomical units (AU) and the period by "T" in years, then:

a³ = (T²)k

where;

For objects orbiting the sun, k is approximately equal to 1.

So, if you know the orbital radius of an object around the sun, you can use Kepler's Third Law to calculate its period, or vice versa.

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The electron configuration of an element with atomic number 15 is 3s² 3p⁵.

The electron configuration of an element with atomic number 15 (which corresponds to the element phosphorus) can be determined by following the Aufbau principle and the Pauli exclusion principle. The Aufbau principle states that electrons occupy the lowest energy levels available, while the Pauli exclusion principle states that each orbital can hold at most two electrons with opposite spins.

Starting with the first energy level, we fill in the electrons for each subsequent energy level until we reach the 15 electrons of phosphorus: 1s² 2s² 2p⁶ 3s² 3p⁵

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Answer:

The acceleration of the mass is 2 meters per square second.

Explanation:

By Newton's second law, we know that force (\(F\)), measured in newtons, is the product of mass (\(m\)), measured in kilograms, and net acceleration (\(a\)), measured in meters per square second. That is:

\(F = m\cdot a\) (1)

The initial force applied in the mass is:

\(F = (10\,kg)\cdot \left(2.5\,\frac{m}{s^{2}} \right)\)

\(F = 25\,N\)

In addition, we know that force is directly proportional to acceleration. If the smaller force is removed, then the initial force is reduced to \(\frac{4}{5}\) of the initial force. The acceleration of the mass is:

\(\frac{25\,N}{20\,N} = \frac{2.5\,\frac{m}{s^{2}} }{a}\)

\(a = 2\,\frac{m}{s^{2}}\)

The acceleration of the mass is 2 meters per square second.

a) The value of t u = 140/t`b.

b) The y position of the cannonball at the time t is  55.5 mc.

c) The initial speed of the projectile is 52.4 m/s.

Given that a cannonball is fired horizontally from the top of a cliff. The cannon is at height H = 55.5 m above ground level, and the ball is fired with initial horizontal speed u. The projectile lands at a distance D = 140 m from the cliff. Assume that the cannon is fired at time t = 0 and that the cannonball hits the ground at time t.Now,We have to find the value of t, y position of the cannonball at the time t and the initial speed of the projectile.

a. To find the value of t:Here, we have to use the formula of distance

i.e.,S = ut + (1/2)gt², Where S = 140 m, u = u and g = 9.8 m/s².Hence,140 = u×t ………..(1)We know that, time taken by the cannonball to hit the ground can be calculated as,`(2H)/g`

Since the height of the cannon from the ground is 55.5m, the total height of the cannonball from the ground is

(2H) = 2 × 55.5

= 111 m`2H/g

= 111/9.8`

= 11.32653 s

From equation (1),u×t = 140u = 140/t

Therefore, `u = 140/t`b.

b)To find the y position of the cannonball at the time t:

Here, we have to use the formula of height i.e.,y = u×t – (1/2)gt²,

Where, y = height of the cannonball at time t, u = 140/t, t = time taken by the cannonball to hit the ground and g = 9.8 m/s².

We have already calculated the time taken by the cannonball to hit the ground in the previous step.`

y = 140 - (1/2) × 9.8 × t²`

On substituting the value of t as `t = 11.32653`,

we get,y = 140 - (1/2) × 9.8 × (11.32653)²= 55.5 mc.

c)  To find the initial speed of the projectile:

To calculate the initial speed of the projectile, we need to use the formula of range of projectile

.i.e.,R = u²sin2θ/g

Where R = 140 m, g = 9.8 m/s², θ = 0° (horizontal)

u² = R × g/sin2θ

   = 140 × 9.8/sin0°  

   = 2744m²/s²u  

   = \(\sqrt(2744m^2/s^2)\)

   = 52.4 m/s

Hence, the initial speed of the projectile is 52.4 m/s.

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Answer:

Component

Explanation:

All circuits have some basic parts, called components. One component is the power source, also called a voltage source. The power source is what pushes the electricity through the circuit.

If you pull with a constant force of 400 N for 0.2 meters, then the work done will be equal to 80 J.

In physics, the word "work" involves the measurement of energy transfer that takes place when an item is moved over a range by an externally applied, at least a portion of which is applied within the direction of the displacement.

The length of the path is multiplied by the element of a force acting all along the path to calculate work if the force is constant. The work W is theoretically equivalent towards the force f times the length d, or W = fd, to portray this concept.

As per the given information in the question,

Force, f = 400 N

Displacement, d = 0.2 meters

\(Work done(W)=Force(f)*Displacement(d)\)

W = 400 × 0.2

W = 80 J.

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Answer:

4.65.3 heehiwijwjwwjwhh

Explanation:

behsjjejejnndjjje

Answer:

D

Explanation: