The Burj Khalifa is the tallest building in the world at 828 m. How much work would a man with a weight of 700 N do if he climbed to the top of the building

it would help if work was shown :,)

Answer:

Option D

Explanation:

11,890

Hope this helps

Answer:

just multiply the frequency and wavelength

200× 2

400

Answer:

B,C,D

Explanation:

Ap3X

Answer:

A

Explanation:

Answer:

2m/s

Explanation:

If X stops Y takes momentum and it has the same velocity

Answer

I Think Its 150

D  because it uses meters                                                                                              

Answer:

Touch

Explanation:

We have that the total pipe drip of \(X=155 mL/min.\) expressed in gallons/day is

\(X=58.96gal/day\)

From the Question we are told that

Pipe Drip\(=155 mL/min.\)

Generally

We have that for mL to gallons conversion

\(1mL=0.000264172\)

And

A minute to day con version is

\(1min=0.000694444\)

Therefore

\(X=155 mL/min.\)

\(X=155(\frac{0.000264172}{0.000694444})\)

\(X=58.96gal/day\)

In conclusion

The total pipe drip of \(X=155 mL/min.\) expressed in gallons/day is \(X=58.96gal/day\)

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At 20 years old, the boy would require eyeglasses with lenses of approximately -1.49 diopters power in order to read a book at 25 cm.

1/f1 = 1/v - 1/u1

1/f1 = 1/∞ - 1/0.25 (converting 25 cm to meters)

1/f1 = 0 - 4

1/f1 = -4

f1 = -1/4

f1 = -0.25 meters

The initial lens power (P1) is the reciprocal of the focal length:

P1 = 1/f1

P1 = 1/-0.25

P1 = -4 diopters

Now let's calculate the final focal length (f2) using the final distance (v2) of 40 cm:

1/f2 = 1/v2 - 1/u1

1/f2 = 1/0.40 - 1/0.25

1/f2 = 2.5 - 4

1/f2 = -1.5

f2 = -1/1.5

f2 = -0.67 meters

The final lens power (P2) is the reciprocal of the focal length:

P2 = 1/f2

P2 = 1/-0.67

P2 ≈ -1.49 diopters

Therefore, at 20 years old, the boy would require eyeglasses with lenses of approximately -1.49 diopters power in order to read a book at 25 cm.

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A. The velocity of car A with respect to car B is 20 km/h

The velocity of an object A relative to another object B is the velocity that object A would appear to have to an observer moving with B.

The velocity of car A with respect to car B is calculated as follows;

Va/b = Va - Vb

where;

Substitute the given parameters and solve for the  the velocity of car A with respect to car B.

Va/b = 50 km/h - 30 km/h

Va/b = 20 km/h

Thus, we can conclude that the velocity of car A with respect to car B will appear to decrease since they are moving in the same direction.

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The Big Bang theory is the most widely accepted explanation for the origins of the universe, but it does not necessarily imply that the universe emerged from nothing.

It is possible that new discoveries or insights may shed light on this fundamental question in the future. The universe may have arisen from a pre-existing state or through some other natural process that we do not yet understand.

Instead, the theory describes how the universe underwent a rapid expansion from a very dense and hot state. The conditions and laws of physics that applied during the earliest moments of the universe may not necessarily be the same as those we observe today, and there are many unknowns and uncertainties in our understanding of these early stages.

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Explanation:

Some standard unit conversion are 1 mile = 1.609344 km, 1 ft.= 30.48 cm,

1 km= 1000 m or 1 m = 0.001 km and 1 m= 100 cm or 1 cm=0.01 m.

Now, use these values to convert the given lengths.

A. length of cave = 5 miles (given)

From standard value 1 mile = 1.609344 km

\(\Rightarrow\) 5 miles = \(\times\) 1.609344 km= 8.04672 km,

\(\Rightarrow\) 5 miles =8.04672 \(\times\) 1000 m= 8046.72 m [ as 1 km = 1000 m]

\(\Rightarrow\) 5 miles = 8046.72 \(\times\) 100 cm=804672 cm

B. Height of the waterfall = 1235 ft. (given)

1 ft.= 30.48 cm [ from standard value]

\(\Rightarrow\) 1235.2 ft.= 1235.2\(\times\) 30.48 cm=37648.896 cm,

\(\Rightarrow\) 1235.2 ft.=37648.896 \(\times\) 0.01 m =376.48896 m [ as 1 cm = 0.01 m]

\(\Rightarrow\) 1235.2 ft.=376.48896 \(\times\) 0.001 km =0.37648896 km [ as 1 m = 0.001 km]

C. Height of the mountain= 21320 ft. (given)

From standard value: 1 ft.= 30.48 cm

\(\Rightarrow\) 21320 ft.= 21320 \(\times\) 30.48 cm=649833.6 cm,

\(\Rightarrow\) 21320 ft.=649833.6 \(\times\) 0.01 m =6498.336 m [ as 1 cm = 0.01 m]

\(\Rightarrow\) 21320 ft.=6498.336 \(\times\) 0.001 km =6.498336 km [ as 1 m = 0.001 km].

D. Depth of canyon =6630 ft.

From standard value: 1 ft.= 30.48 cm

\(\Rightarrow\) 6630 ft.= 6630 \(\times\) 30.48 cm=202082.4 cm,

\(\Rightarrow\) 6630 ft.=202082.4  \(\times\) 0.01 m =2020.824  m [ as 1 cm = 0.01 m]

\(\Rightarrow\) 6630 ft.=2020.824  \(\times\) 0.001 km =2.020824  km [ as 1 m = 0.001 km].

Weight is best defined as C) the force of gravity on an object.

Answer:

F = 37.8 × 10^(6) N

Explanation:

The charges are 0.06 C and 0.07 C.

Thus;

Charge 1; q1 = 0.06 C

Charge 2; q2 = 0.07 C

Distance between them; r = 3 m

Formula for the force in between them is;

F = kq1•q2/r²

Where k is a constant = 9 × 10^(9) N.m²/C²

Thus;

F = (9 × 10^(9) × 0.06 × 0.07)/3²

F = 37.8 × 10^(6) N

Conduction is a process through which energy is transferred from the branding iron to the handle.

When two objects with different surface temperatures come into close touch with one another, conduction happens. Up until they reach thermal equilibrium, or the point at which they are at the same temperature, the heat energy moves from the hotter to the cooler object.

The metal tip of the branding iron, which makes contact with the branded surface, becomes extremely hot when it is placed in the fire because of the high fire temperature.

Hence, conduction is a process through which energy is transferred from the branding iron to the handle.

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The distance over which the force was applied would be 10 meters.

The work done on an object is given by the product of the force applied and the distance over which it is applied. Therefore, we can use the formula:

Work = Force x Distance

We know that the force applied is 50 newtons, and the work done is 5.0 x 10^2 joules. We can rearrange the formula to solve for distance:

Distance = Work / Force

Substituting the values we know, we get:

Distance = (5.0 x 10^2 J) / 50 N

Distance = 10 meters

Therefore, the force of 50 newtons was applied over a distance of 10 meters to do 5.0 x 10^2 joules of work on the object.

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Answer:

B

Explanation:

Answer:

B

Explanation:

The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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The angle of the free surface relative to the horizontal direction after deceleration is approximately 20.2 degrees.

Let's assume that the tank has a mass of m, the angle of the inclined surface is θ, and the height of the inclined surface is h. The initial kinetic energy of the tank is given by:

KE = (1/2)mv²

where v is the initial velocity of the tank. When the tank reaches the top of the inclined surface, its potential energy is given by:

PE = mgh

where g is the acceleration due to gravity (9.81 m/s²). Since there is no change in the total energy of the system (tank + water), we can equate the initial kinetic energy to the final potential energy:

(1/2)mv² = mgh

Solving for v, we get:

v = √(2gh)

When the tank decelerates with an acceleration of a, its velocity decreases at a rate of a m/s². The time taken for the tank to come to a complete stop is given by:

t = v/a

The distance traveled by the tank during this time is:

s = (1/2)at²

\(=\dfrac{1}{2} (\dfrac{v}{a})^2a = \dfrac{v^2}{2a}\)

The angle of the free surface relative to the horizontal direction after deceleration is given by:

\(\theta' = tan^{-1}\dfrac{s}{h}\)

Substituting the values of v and s, we get:

\(\theta' = tan^{-1}\dfrac{\sqrt{2gh}^2}{2ah}\\\\ = tan^{-1}\dfrac{2h}{3a}\)

Substituting the given values of h and a, we get:

\(\theta' = tan^{-1}\dfrac{2(9.81)sin(15)}{3.83}\\ = 20.2\)

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The statement that what matters in an experiment is asking the right questions and not necessarily finding the right answer potryas the importance of the scientific process and inquiry-based approach.

The aim of scientific study is to learn about and comprehend the natural world. This is accomplished through developing hypotheses, posing questions, carrying out experiments, and evaluating the outcomes. While getting the right response is critical, it's just as important to ask the right questions in the first place.

Asking the right questions helps to define the scope and objectives of the experiment and also  guides the researcher to focus on specific variables, design appropriate experiments, and gather relevant data.

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Answer: the last one

Explanation: it pushes the lid off in a upward motion

Answer:

the last one

Explanation:

Can you mark me as BRAINLLIEST, PLEASE!!!!!!!!!!!!

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Answer: Similarity

By.

Answer:

s = 14.3 ft

Explanation:

First we need to calculate the distances traveled by both the cars. We use third equation of motion for that:

2as = Vf² - Vi²

where,

a = acceleration

s = distance

Vf = Final Velocity

Vi = Initial velocity

FOR CAR A:

Vi = Va = (40 mph)(5280 ft/1 mile)(1 h/3600 s) = 58.66 ft/s

Vf = 0 ft/s

a = aA = - 22 ft/s²

s = sa = ?

Therefore,

2(- 22 ft/s²)(sa) = (58.66 ft/s)² - (0 ft/s)²

sa = 78.2 ft

FOR CAR B:

Vi = Vb = (45 mph)(5280 ft/1 mile)(1 h/3600 s) = 66 ft/s

Vf = 0 ft/s

a = aB = - 20 ft/s²

s = sb = ?

Therefore,

2(- 20 ft/s²)(sb) = (66 ft/s)² - (0 ft/s)²

sb = 108.9 ft

Since, the car A was initially 45 ft ahead of car B. Therefore,

sa = 45 ft + 78.2 ft = 123.2 ft

Now, the distance between the cars will be:

s = sa - sb

s = 123.2 ft - 108.9 ft

s = 14.3 ft

Each of the five friends needs to pay £12 to cover the cost of their own meals and contribute towards the birthday person's meal. Using mean allows us to distribute the cost equally among the friends, ensuring a fair division of expenses for the meal.

To determine how much each of the five friends needs to pay, we can use the concept of averages (mean) and divide the total cost by the number of people paying.

In this scenario, the total cost of the meal for 6 people is £12 per person. Since the other 5 friends have decided to pay for the birthday person's meal, they will collectively cover the cost of their own meals plus the birthday person's meal.

To calculate the total cost covered by the five friends, we can subtract the cost of one person's meal (since the birthday person's meal is being paid by the group) from the total cost. The cost of one person's meal is £12.

Total cost covered by the five friends = Total cost - Cost of one person's meal

= (£12 x 6) - £12

= £72 - £12

= £60

Now, to find out how much each of the five friends needs to pay, we divide the total cost covered by the five friends (£60) by the number of friends (5).

Amount each friend needs to pay = Total cost covered by the five friends / Number of friends

= £60 / 5

= £12

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Answer:

Distance from sun, orbit and rotation. Presence of interior oceans, and elements that forms compressed water.

Explanation:

Answer:

So the answer is C: 2 Ω.

Explanation:

The equivalent resistance of a parallel circuit is given by the formula:

1/R_equiv = 1/R1 + 1/R2 + ... + 1/Rn

In this case, there are 5 resistors each with a resistance of 10 ohms, so:

1/R_equiv = 1/10 + 1/10 + 1/10 + 1/10 + 1/10 = 5/10 = 0.5

And the equivalent resistance is:

R_equiv = 1 / 0.5 = 2 ohms

So the answer is C: 2 Ω.

Louis Armstrong's average velocity in the time trial was approximately 1.078 km/min.

To calculate the average velocity, divide the total displacement by the total time taken. In this case, Louis Armstrong rode his bike 55 km to the east in a time trial lasting 51 minutes.

Average Velocity = Displacement / Time

Displacement = 55 km (since he rode 55 km to the east)

Time = 51 minutes

Average Velocity = 55 km / 51 min

To express the average velocity in km/min, convert the time from minutes to minutes.

1 hour = 60 minutes

Average Velocity = 55 km / 51 min × (1 hour / 60 min)

Average Velocity = 55 km / 51 min × (1/60) hour

Simplifying the expression:

Average Velocity = 1.078 km/min

Therefore, Louis Armstrong's average velocity in the time trial was approximately 1.078 km/min.

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The angular velocity to nearest degree per second, gives:

A) 21584°/s

B) 79217°/s

C) 215848°/s

D) 551180°/s

The formula to convert frequency (f) in Hertz (Hz) to angular velocity (ω) in radians per second is:

ω = 2πf

To convert the result to degrees per second, we can multiply by 180/π, which is the conversion factor between radians and degrees.

Using this formula, we get:

A) ω = 2π × 60 = 376.99 rad/s ≈ 21584°/s

B) ω = 2π × 220 = 1382.94 rad/s ≈ 79217°/s

C) ω = 2π × 600 = 3769.91 rad/s ≈ 215848°/s

D) ω = 2π × 1.53 × 10^3 = 9621.89 rad/s ≈ 551180°/s

Rounding these results to the nearest degree per second, we get:

A) 21584°/s

B) 79217°/s

C) 215848°/s

D) 551180°/s

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Answer:

The correct answer is A) It is upright and 1.5m behind the mirror

Explanation:

Your reflection must be upright, meaning vertical/erect, and the distance will be the exact same. Also, the reflected ray appears as if it had traveled from an object located behind the mirror.