The brick wall exerts a uniform distributed load of 1.35 kips / ft on the beam. If the allowable bending stress is σ_all =27.0 ksi, determine the required width b of the flange. Assume the shear stresses are small and negligible.

The interface between an application program and the DBMS is typically provided by the data access API.

The back end and front end are two important components of an application's design that are separate from one another, and each component has its own unique responsibilities.

The back end is where all of the application's logic, databases, and processing are located, whereas the front end is where the application's user interface is located.

On the front end, users are able to interact with an application's features by interacting with its user interface.

The data access API, on the other hand, is used by the application's back end to interact with the application's database management system (DBMS) in order to perform data retrieval, data updating, and other database operations.

As a result, it serves as a bridge between the front end and back end of an application.

As a result, the data access API is responsible for interfacing between an application program and a DBMS.

It can retrieve data from a database management system and interact with it, enabling an application to execute database operations that are critical to its functionality.

The interface between an application program and a DBMS is usually provided by the data access API.

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Answer:

The percentage of recycling in high socioeconomic localities is 11.02%.

Explanation:

Since in high socioeconomic localities, 10% of paper is recycled, 12% of plastic, 1.7% of fabrics, 1.2% of rubbers, 0.9% of metals, 3.5% of glass, 33% of food wastes, 35% soil and 1.9% miscellaneous, to determine the average recycling percentage the following calculation must be performed:

(10 + 12 + 1.7 + 1.2 + 0.9 + 3.5 + 33 + 35 + 1.9) / 9 = X

99.2 / 9 = X

11.02 = X

Therefore, the percentage of recycling in high socioeconomic localities is 11.02%.

A handsfree device may be used if it can be activated or deactivate with a cellphone.

Handsfree is a device which when connected to a cell device can be used in listening to audio, video and messages.

A driver can also activate or deactivate with a swipe when connect to the vehicle audio device.

Therefore,

A handsfree device may be used if it can be activated or deactivate with a cellphone.

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9514 1404 393

Answer:

  (x, y) = (5.76, 1 5/7)

Explanation:

The location of the centroid in the x-direction is the ratio of the first moment of area about the y-axis to the total area. Similarly, the y-coordinate of the centroid is the first moment of area about the x-axis, divided by the area.

For the moment about the y-axis, we can define a differential of area as ...

  dA = (y2 -y1)dx

where y2 = √(x/k2) and y1 = k1·x^3

The distance of that area from the y-axis is simply x.

So, the x-coordinate of the centroid is ...

  \(\displaystyle c_x=\frac{a_x}{a}=\frac{\int{x\cdot dA}}{\int{dA}}\\\\a_x=\int_0^{12}{x(k_2^{-1/2}\cdot x^{1/2}-k_1x^3)}\,dx=\frac{2}{5k_2^{1/2}}\cdot12^{5/2}-\frac{k_1}{5}12^5\\\\a=\int_0^{12}{(k_2^{-1/2}\cdot x^{1/2}-k_1x^3)}\,dx=\frac{2}{3k_2^{1/2}}\cdot12^{3/2}-\frac{k_1}{4}12^4\\\)

For k1 = 4/12^3 and k2=12/4^2, these evaluate to ...

  \(a_x=115.2\\a=20\\c_x=5.76\)

The y-coordinate of the centroid requires we find the distance of the differential of area from the x-axis. We can use (y2 +y1)/2 for that purpose. Then the y-coordinate is ...

  \(\displaystyle c_y=\frac{a_y}{a}\\\\a_y=\int_0^{12}{(\frac{y_2+y_1}{2}(y_2-y_1))}\,dx=\frac{1}{2}\int_0^{12}{(\frac{x}{k_2}-(k_1x^3)^2)}\,dx\\\\a_y=\frac{12^2}{4k_2}-\frac{k_1^212^7}{14}=\frac{240}{7}\\\\c_y=\frac{12}{7}\approx1.7143\)

The centroid of the shaded area is ...

  (x, y) = (5.76, 1 5/7)

The amplitude of the sinusoid is 28384 *x soít cos.

Amplitude is defined as the greatest deviation from equilibrium of a point on a vibrating body or wave in terms of displacement or distance traveled. In most cases, amplitude is calculated by looking at a wave graph and determining the height of the wave from rest. The strength or intensity of the wave is gauged by its amplitude.

Sinusoid is defined as a signal with sine wave characteristics. In the liver, spleen, and bone marrow, sinusoids and irregular tubules transport blood in place of venules and capillaries. The sine or cosine functions from trigonometry form the foundation of sinusoidal signals, which are periodic functions.

Thus the amplitude of the sinusoid is 28384 *x soít cos.

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In the radio communication system, multipath is the propagation phenomenon that causes diffusion or reflection in multiple different directions of a signal.

Multipath is a propagation mechanism that impacts the propagation of signals in radio communication. Multipath results in the transmission of data to the receiving antenna by two or more paths. Diffusion and reflection are the causes that create multiple paths for the signal to be delivered.

Diffraction occurs when a signal bends around sharp corners; while reflection occurs when a signal impinges on a smooth object. When a signal is received through more than one path because of the diffraction or reflection, it creates phase shifting and interference of the signal.

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In high-volume turboprop and turbojet engines with two-spool or split compressors, the low-pressure rotor will increase in speed as the compressor load decreases in the lower density air at high altitudes. This is due to the difference in air pressure and density at higher altitudes, which affects the engine's performance.

1)A two-spool or split compressor system features separate high-pressure and low-pressure rotors. These rotors work independently to compress air, which allows the engine to achieve higher efficiency and performance. This design also improves the engine's response to varying altitude and air density conditions.

2)At high altitudes, the air density decreases, leading to a reduction in the compressor load. As the load on the compressor decreases, the low-pressure rotor can increase in speed to maintain the desired compression ratio and engine performance. This increase in speed allows the engine to adapt to the changing conditions and continue operating efficiently.

3)In summary, high-volume turboprop and turbojet engines with two-spool or split compressors can adjust their performance at high altitudes due to the increased speed of the low-pressure rotor as the compressor load decreases in the lower density air. This design feature enhances the engine's adaptability and efficiency in various operating conditions.

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A data integrity problem will occur primarily when data are duplicated in a database.

Data integrity is the maintenance and assurance of data's accuracy and consistency over its entire lifecycle. When there is data duplication, it can lead to inconsistencies and incorrect information, which in turn negatively impacts the integrity of the database.

While having multiple administrators, a complex database, complex relationships between entities, and too many keys might pose management challenges, they are not the direct cause of data integrity problems. However, they can indirectly contribute to the issue if proper management practices are not followed.

In order to maintain data integrity, it is essential to implement measures such as data validation, normalization, and the use of primary keys to uniquely identify records. By doing so, it helps to minimize data duplication and ensures that the data remains consistent, accurate, and reliable throughout its lifecycle.

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Answer:

=$A$3*$B$1

Explanation:

Since cells involved in the formula are absolute row and column because of the $ sign on the row letter and column number for both, this formula will not changed when it is copied to any new location on the worksheet

Answer:

The velocity at section is approximately 42.2 m/s

Explanation:

For the water flowing through the pipe, we have;

The pressure at section (1), P₁ = 300 kPa

The pressure at section (2), P₂ = 100 kPa

The diameter at section (1), D₁ = 0.1 m

The height of section (1) above section (2), D₂ = 50 m

The velocity at section (1), v₁ = 20 m/s

Let 'v₂' represent the velocity at section (2)

According to Bernoulli's equation, we have;

\(z_1 + \dfrac{P_1}{\rho \cdot g} + \dfrac{v^2_1}{2 \cdot g} = z_2 + \dfrac{P_2}{\rho \cdot g} + \dfrac{v^2_2}{2 \cdot g}\)

Where;

ρ = The density of water = 997 kg/m³

g = The acceleration due to gravity = 9.8 m/s²

z₁ = 50 m

z₂ = The reference = 0 m

By plugging in the values, we have;

\(50 \, m + \dfrac{300 \ kPa}{997 \, kg/m^3 \times 9.8 \, m/s^2} + \dfrac{(20 \, m/s)^2}{2 \times 9.8 \, m/s^2} = \dfrac{100 \ kPa}{997 \, kg/m^3 \times 9.8 \, m/s^2} + \dfrac{v_2^2}{2 \times 9.8 \, m/s^2}\)50 m + 30.704358 m + 20.4081633 m = 10.234786 m + \(\dfrac{v_2^2}{2 \times 9.8 \, m/s^2}\)

50 m + 30.704358 m + 20.4081633 m - 10.234786 m = \(\dfrac{v_2^2}{2 \times 9.8 \, m/s^2}\)

90.8777353 m = \(\dfrac{v_2^2}{2 \times 9.8 \, m/s^2}\)

v₂² = 2 × 9.8 m/s² × 90.8777353 m

v₂² = 1,781.20361 m²/s²

v₂ = √(1,781.20361 m²/s²) ≈ 42.204308 m/s

The velocity at section (2), v₂ ≈ 42.2 m/s

Answer:

the total charge which crosses into the collector is 60 nC

Explanation:

Given the data in the question;

current flowing into the collector lead of the bipolar junction transistor (BJT); i = 1 nA = 10⁻⁹ A

no charge was transferred in or out of the collector lead prior to t = 0

the current flow time t = 1 min = 60 sec

Now we write the relation between current, charge, and time;

i = dq / dt

where i is current, q is charge and t is time. { d refers to change }

Now,

\(q=\int\limits^t_{t=0} {i(t)} \, dt\)

\(q=\int\limits^{t=60}_{t=0} { (10^{-9}) } \, dt\)

\(q = ( 10^{-9}) (t)_0^{60\)

\(q = ( 10^{-9}) ( 60 - 0 )\)

q = 60 × 10⁻⁹ C

q = 60 nC

Therefore, the total charge which crosses into the collector is 60 nC

Answer:

a. the rate of heat loss from the electronic device to the surrounding air

A total of 10 rectangular aluminum fins (k = 203 W/m·K) are placed on the outside flat surface of an electronic device. Each fin is 100 mm wide, 20 mm high and

4 mm thick. The fins are located parallel to each other at a center-to-center distance of 8 mm. The temperature at the outside surface of the electronic device is 72°C. The air is at 20°C, and the heat transfer coefficient is 80 W/m2·K. Determine (a) the rate of heat loss from the electronic device to the surrounding air and (b) the fin effectiveness.

Explanation:

Sorry if wrong, Hope I helped

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The gear tooth caliper should be set to a chordal height of approximately 1.89 mm during the measurement of the gear's chordal thickness.

To determine the chordal height for the measurement of the gear's chordal thickness, we can use the following steps:

1. Calculate the base circle diameter:

  The base circle diameter (Db) can be found using the formula:

  Db = Addendum Circle Diameter / cosine(pressure angle)

  Substituting the given values, we get:

  Db = 136 mm / cosine(20°)

  Db ≈ 143.07 mm

2. Calculate the circular pitch:

  The circular pitch (P) is given by the formula:

  P = π * Db / number of teeth

  Substituting the values, we have:

  P = π * 143.07 mm / 32

  P ≈ 14.17 mm

3. Calculate the chordal height:

  The chordal height (Ch) is given by the formula:

  Ch = 2 * addendum * sin(half of the circular pitch)

  The addendum can be found using the formula:

  Addendum = P / (2 * π)

  Substituting the values, we have:

  Addendum = 14.17 mm / (2 * π)

  Addendum ≈ 2.26 mm

  Now, calculating the chordal height:

  Ch = 2 * 2.26 mm * sin(0.5 * 14.17 mm)

  Ch ≈ 1.89 mm

Therefore, the gear tooth caliper should be set to a chordal height of approximately 1.89 mm during the measurement of the gear's chordal thickness.

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Proper, smooth shifting is important because shifting before your vehicle is ready will cause it to je-rk forward and your drive wheels may lock.

A proper, smooth shifting of the gears of an automobile vehicle is very important because shifting them before the vehicle is ready would cause the following:

As a good driver, proper, smooth shifting is important because shifting before your vehicle is ready will cause it to je-rk forward and your drive wheels may lock.

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Answer:

to keep the battery charged when the vehicle is running, it also helps the battery keep the electrical components in your vehicle charged

Explanation:

Answer:

19

Explanation:

i think this is the right answer

hope it helps :)

Answer:people tend to do this when they are in a different environment they lose something or just have something going on in their life

Explanation:

The type of metal would experience this type of failure is very ductile. A material's susceptibility to drawing is how the mechanical feature of ductility is most frequently defined.

A material's susceptibility to drawing is how the mechanical feature of ductility is most frequently defined (e.g. into wire). The degree to which a material can withstand plastic deformation under tensile stress before failing is referred to as ductility in the field of materials research.

In engineering and manufacturing, ductility is a crucial factor. It specifies a material's ability to withstand mechanical overload and its appropriateness for specific manufacturing processes, including cold working. Gold and copper are two examples of metals that are typically referred to as ductile.

However, not all metals are brittle, as some, like cast iron, are capable of ductile failure. Polymers can commonly be thought of as ductile materials since they frequently permit plastic deformation.

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The sections of piping immediately upstream and downstream of a primary flow measuring device are known as the "straight run."

The straight run refers to the lengths of piping that are required to be present immediately upstream and downstream of a primary flow measuring device. These sections of piping are necessary to ensure that the flow profile is fully developed and unaffected by any disturbances caused by bends, fittings, or obstructions in the pipe. The straight run allows the fluid to flow smoothly and uniformly before entering or exiting the flow measuring device, ensuring accurate and reliable measurements.

By providing sufficient straight run lengths, the flow profile becomes stable, minimizing turbulence and disturbances that could impact the accuracy of the flow measurement.

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The theoretical fracture strength of the brittle material is estimated to be approximately 165.6 MPa when a stress of 1300 MPa is applied and fracture occurs by the propagation of an elliptically shaped surface crack of length 0.29 mm and tip radius of curvature of 0.004 mm.

To estimate the theoretical fracture strength of a brittle material given the information provided, we can use Griffith's theory of brittle fracture. According to this theory, the fracture strength of a brittle material can be expressed as:

σ_f = (2Eγπa)^0.5

where σ_f is the fracture strength, E is the elastic modulus, γ is the surface energy per unit area, and a is the length of the elliptically shaped surface crack.

To calculate the fracture strength, we need to first determine the surface energy per unit area of the material. For glass, a typical value of surface energy is around 1 J/m^2.

Given the length of the elliptically shaped surface crack (a) is 0.29 mm, and the tip radius of curvature is 0.004 mm, we can calculate the crack area (A) as follows:

A = πab = π(0.29/2)(0.004)

A ≈ 5.67 x 10^-7 m^2

Next, we can calculate the elastic modulus (E) of the material. For glass, the elastic modulus is typically around 70 GPa.

Substituting these values into the equation for fracture strength, we get:

σ_f = (2Eγπa)^0.5 = [2(70 x 10^9)(1)(π)(0.29 x 10^-3)]^0.5

σ_f ≈ 165.6 MPa

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Answer:

See attachment for chart

Explanation:

The IPO chart implements he following algorithm

The expressions in bracket are typical examples

Input

Input Number (5, 4.2 or -1.2) --- This will be passed to the Processing module

Processing

Assign variable to the input number (x)

Calculate the square (x = 5 * 5)

Display the result (25) ----> This will be passed to the output module

Output

Display 25

An example of a Python application that calculates the total cost of a hospital stay based on the given inputs is given in the image attached.

The above block of code initiates a prompt for the user to input the necessary particulars comprising the duration of their stay in the hospital, medical expenses, surgical expenditures, laboratory costs, and physical therapy bills.

It subsequently employs the given techniques to determine the fundamental fees, additional costs, and overall expenses. In the event that the user inputs data that is not numeric, the try-except block will detect a ValueError and display an error message.

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Answer:

La diferencia media logarítimica de temperatura del intercambiador en paralelo es aproximadamente 75.466 ºC.

La diferencia media logarítmica de temperatura del intercambiador en contracorriente es aproximadamente 97.881 ºC.

Explanation:

De la teoría de Transferencia de Calor tenemos que un intercambiador de calor en paralelo presenta las siguientes dos características:

1) Tanto el fluido caliente como el fluido frío entran por el mismo lado.

2) Tanto el fluido caliente como el fluido frío salen por el mismo lado.

Mientras que el intercambiador de calor en contracorriente tiene que:

1) El fluido caliente y el fluido frío entran por lados opuestos.

2) El fluido caliente y el fluido frío salen por lados opuestos.

A continuación, anexamos los esquemas de perfil de cada intercambiador.

Ahora, la Diferencia Media Logarítimica de Temperatura (\(\Delta T_{lm}\)), medida en grados Celsius, queda definida como sigue:

\(\Delta T_{lm} = \frac{\Delta T_{1}-\Delta T_{2}}{\ln \frac{\Delta T_{1}}{\Delta T_{2}} }\) (Eq. 1)

Donde \(\Delta T_{1}\) y \(\Delta T_{2}\) son las diferencias de temperatura de los fluidos en cada extremo del intercambiador, medido en grados Celsius.

Procedemos a determinar esas diferencias y la Diferencia Media Logarítimica de Temperatura para cada configuración:

Intercambiador en paralelo

\(\Delta T_{1} = 180\,^{\circ}C-3\,^{\circ}C\)

\(\Delta T_{1} = 177\,^{\circ}C\)

\(\Delta T_{2} = 78\,^{\circ}C - 55\,^{\circ}C\)

\(\Delta T_{2} = 23\,^{\circ}C\)

\(\Delta T_{lm} = \frac{177\,^{\circ}C-23\,^{\circ}C}{\ln \frac{177\,^{\circ}C}{23\,^{\circ}C} }\)

\(\Delta T_{lm} \approx 75.466\,^{\circ}C\)

La diferencia media logarítimica de temperatura del intercambiador en paralelo es aproximadamente 75.466 ºC.

Intercambiador en contracorriente

\(\Delta T_{1} = 180\,^{\circ}C-55\,^{\circ}C\)

\(\Delta T_{1} = 125\,^{\circ}C\)

\(\Delta T_{2} = 78\,^{\circ}C-3\,^{\circ}C\)

\(\Delta T_{2} = 75\,^{\circ}C\)

\(\Delta T_{lm} = \frac{125\,^{\circ}C-75\,^{\circ}C}{\ln \frac{125\,^{\circ}C}{75\,^{\circ}C} }\)

\(\Delta T_{lm} \approx 97.881\,^{\circ}C\)

La diferencia media logarítmica de temperatura del intercambiador en contracorriente es aproximadamente 97.881 ºC.

Answer:

If we were to put a website here on Brainly, the moderators will delete it

Explanation:

Please trust me on this because the moderators delete a lot of things. They have been deleting people's answers for some odd reason saying it goes against their "honor code" but whatever