The bowling ball has starts out at rest (0= speed m/s) at the top of the building (height 40 m). How much potential energy does the ball have?

How much Kinetic energy does the bowling ball have?

How much total energy (Potential energy & Kinetic) does the bowling ball have?

Of the bowling ball's total energy, is more in the form of potential or kinetic energy?

Answers

Answer 1

Answer:

it has 40 potential/ 20 kinetic energy/ do the math

Explanation:

energy


Related Questions

What length should a tube closed at one end have on a day when the air temperature is 0ºC, if its fundamental frequency is to be 96 Hz (C below middle C)?What is the frequency of its sixth over tone

Answers

The frequency of the sixth overtone would be 576 Hz.

To determine the length of a tube closed at one end, we can use the formula:

L = (v/4f) * (2n - 1)

where L is the length of the tube, v is the speed of sound in air, f is the fundamental frequency, and n is the harmonic number.

Given that the fundamental frequency is 96 Hz, we can substitute the values into the formula:

L = (v/4f) * (2n - 1)

L = (v/4*96) * (2*1 - 1)

L = v/384

To find the length at 0ºC, we need to know the speed of sound at that temperature. The speed of sound in air depends on temperature and other factors. At 0ºC, the speed of sound in dry air is approximately 331.4 m/s.

L = 331.4/384

L ≈ 0.862 m

Therefore, the tube closed at one end should have a length of approximately 0.862 meters when the air temperature is 0ºC.

To find the frequency of the sixth overtone, we multiply the fundamental frequency by six: Frequency of sixth overtone = 96 Hz * 6 = 576 Hz.

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Systems, which are the building blocks of technology, are embedded within larger:

-political, ethical, and moral systems
-mechanical, structural, and electrical systems -technological, social, and environmental systems
-optical, thermal and fluid systems

Answers

ethical, electric, and technological, thermal?

Calculate the de Broglie wavelength of a 0.56 kg ball moving with a constant velocity of 26 m/s (about 60 mi/h)

Answers

The de Broglie wavelength of a 0.56 kg ball moving with a constant velocity of 26 m/s is 4.55×10⁻³⁵ m.

De Broglie wavelength:

The wavelength that is incorporated with the moving object and it has the relation with the momentum of that object and mass of that object. It is inversely proportional to the momentum of that moving object.

λ=h/p

Where, λ is the de Broglie wavelength, h is the Plank constant, p is the momentum of the moving object.

Whereas, p=mv, m is the mass of the object and v is the velocity of the moving object.

Therefore, λ=h/(mv)

λ=(6.63×10⁻³⁴)/(0.56×26)

λ=4.55×10⁻³⁵ m.

The de Broglie wavelength associated with the object weight 0.56 kg moving with the velocity of 26 m/s is λ=4.55×10⁻³⁵ m.

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An airplane needs to reach a forward velocity of 56.4 m/s to take off. On a 2000 meter runway, what is the minimum uniform acceleration necessary for the plane to take flight if it starts from rest? NEED WORK SHOWN!! 100 PTs

What is the displacement of the airplane?

What is the initial velocity of the airplane?

What is the final velocity of the airplane?

Write the equation you will use to solve the problem.

What was your acceleration?
1.0 m/s^2
0.95 m/s^2
0.87 m/s^2
0.80 m/s^2

Answers

Displacement of the airplane (s) = 2000 m

Initial velocity of the airplane (u) = 0 m/s (Starts from rest)

Final velocity of the airplane = 56.4 m/s

Equation used to solve the problem:

\( \boxed{ \bf{ {v}^{2} = {u}^{2} + 2as}}\)

By substituting values in the equation, we get:

\( \rm \longrightarrow {56.4}^{2} = {0}^{2} + 2 \times a \times 2000 \\ \\ \rm \longrightarrow 3180.96 = 0 + 4000a \\ \\ \rm \longrightarrow 4000a = 3180.96 \\ \\ \rm \longrightarrow \dfrac{4000a}{4000} = \dfrac{3180.96}{4000} \\ \\ \rm \longrightarrow a = 0.80 \: m {s}^{ - 2} \)

\( \therefore \) Minimum uniform acceleration necessary for the plane to take flight (a) = 0.80 m/s²

Physics what is the aim of this experiment

Answers

Answer:

An experiment usually tests a hypothesis, which is an expectation about how a particular process or phenomenon works. However, an experiment may also aim to answer a "what-if" question, without a specific expectation about what the experiment reveals, or to confirm prior results.

Explanation:

calculate the upthrust aciting on a body if its
true weight is 550 N and apparent weight
lis 490 N​

Answers

Answer:

As a body moving upward

T=real weight + apparent weight

T=550+490

T=1040

hope u will get the answer:)

Explanation:

If an element has a mass number of 200 and an atomic number of 80, how many neutrons does the element have?
A. 80
B. 280
C. 120
D. 200

Answers

Answer:

If I say the correct answer is B.280

which one of the following statements concerning the electric field is false? the si unit of the electric field is the newton per meter (n/m). the magnitude of the electric field at a particular location due to a particular charged particle is inversely proportional to the square of the distance of the particle from that location. at a given point, a charged particle will experience a force, if an electric field is present at that location. if a positively charged particle is placed at a location where the electric field is directed due north, it will be accelerated due north. the electric field is a vector quantity.

Answers

The statement that is false is:

"if a positively charged particle is placed at a location where the electric field is directed due north, it will be accelerated due north."

A charged particle will experience a force in the direction of the electric field, but it may not necessarily be accelerated in the same direction. The acceleration of a charged particle depends on other factors such as the mass of the particle, the strength of the electric field, and any other forces acting on the particle. So, a positively charged particle may not be accelerated due north, even if the electric field is directed due north. The electric field is a fundamental concept in physics and is used to describe the force that a charged particle experiences in a given electric field. It is a vector quantity that represents the force per unit charge and is defined as the force that a charged particle would experience if placed at a given point in space.

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I need help. I don’t understand.

I need help. I dont understand.

Answers

The voltage drop across R3 is 34.5 volts.

Voltage, also known as electric potential difference, is a measure of the difference in electric potential energy between two points in an electrical circuit, and it is measured in volts. It is the driving force that moves electric charges through a circuit, from a higher potential to a lower potential.

To determine the voltage drop across R3 in this circuit, we need to first find the equivalent resistance of R2, R3, and R4, since they are connected in parallel. We can then find the total resistance of the circuit by adding the equivalent resistance in series with R1, and finally use Ohm's Law to calculate the voltage drop across R3.

The equivalent resistance of R2, R3, and R4 in parallel can be calculated as:

1/R_parallel = 1/R2 + 1/R3 + 1/R4

1/R_parallel = 1/20 + 1/25 + 1/10

1/R_parallel = 0.15

R_parallel = 1/0.15

R_parallel = 6.67 ohm

The total resistance of the circuit can be found by adding R1 and the equivalent resistance in series:

R_total = R1 + R_parallel

R_total = 15 + 6.67

R_total = 21.67 ohm

Now we can use Ohm's Law to calculate the current flowing through the circuit:

I = ET / R_total

I = 30 / 21.67

I = 1.38 A

Finally, we can use Ohm's Law again to calculate the voltage drop across R3:

V_R3 = I * R3

V_R3 = 1.38 * 25

V_R3 = 34.5 V

Therefore, the voltage drop across R3 is 34.5 volts.

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the lanthanides and actinides belong to the

Answers

Answer:

Inner Transition Metals

Explanation:

The lanthanides and actinides belong to the inner transition metals.

Answer:

inner transition elements

Explanation:

In the periodic table to which the lanthanides and actinides metals belong to is inner transition elements because these elements are present in between transition elements.

An empty Erlenmeyer flask weighs 246.3 g. When filled with water (density = 1.00 g/cm^3), the flask and its contents weigh 495.0 g.(a) What is the flask's volume? (b) How much does the flask weigh when filled with chloroform (d = 1.48 g/cm^3)?

Answers

The volume of the Erlenmeyer flask when filled with water is 249 cm^3.

What is volume?

Volume is a measure of the amount of three-dimensional space an object occupies. It is measured in cubic units, such as cubic centimeters (cm3) or cubic meters (m3). Volume is an important concept in many areas of science, including physics, chemistry and geology. It can also be used to describe the capacity of a container, such as a bottle, or the amount of liquid it can hold. Knowing the volume of a substance or object is important in many everyday situations, from measuring food portions to calculating the amount of paint needed to cover a wall.

This is calculated by subtracting the weight of the empty flask (246.3 g) from the weight of the flask filled with water (495.0 g) and then dividing by the density of water (1.00 g/cm^3).

When filled with chloroform, the flask and its contents weigh 581.1 g. To calculate this, we multiply the density of chloroform (1.48 g/cm^3) by the volume of the flask (249 cm^3), which gives us 371.52 g. We then add the weight of the flask (246.3 g) to the weight of the chloroform (371.52 g), which gives us a total of 617.82 g. The weight of the flask when filled with chloroform is 581.1 g.

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What are patients most likely to prepare as part of their right to make decisions about end of life care under federal legislation

Answers

Patients are most likely to prepare "advance directives" as part of their right to make decisions about end-of-life care under federal legislation.

A car is being tested on a track. The driver approaches the test section at a speed of 28 m s−1. He then accelerates at a uniform rate between two markers separated by 100 m. The car reaches a speed of 41 m s−1.

Answers

The uniform acceleration of the car is 4.485 m/s².

Acceleration of the car

The uniform acceleration of the car is calculated as follows;

v² = u² + 2as

a = (v² - u²)/2s

where;

v is final velocity = 41 m/su is initial velocity = 28 m/ss is distance = 100 ma is acceleration = ?

a = (41² - 28²)/(2 x 100)

a = 4.485 m/s²

Thus, the uniform acceleration of the car is 4.485 m/s².

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2. What is the mass of an object that was accelerated at a rate of 1 m/s with a force of 2 N

2. What is the mass of an object that was accelerated at a rate of 1 m/s with a force of 2 N

Answers

Answer:

2 kilograms

Explanation:

F = ma

2 = 1m = 2

A 66 kg driver gets into an empty taptap to start the day's work. The springs compress 2.3×10−2 m
. What is the effective spring constant of the spring system in the taptap?
Enter the spring constant numerically in newtons per meter using two significant figures

Answers

Explanation:

You want  N/m

 N = 66 * 9.81

 m = 2.3 x 10^-2 m

66* 9.81 / 2.3 x 10^-2  = 28150 =  28 000 N/m    to two S D

A ray of light is incident on a plane mirror and the angle of reflection is 50 degrees. What is the angle between the incident ray and the normal?

Answers


The angle of incidence is equal to the angle of reflection. As a result, the angle formed by the incidence and reflected rays is 100°.

please press crown next to the repot button

A solid disk with radius of 0.5 m started at rest, and is free to rotate around its center without friction. A string wrapped around the disk is pulled, as shown below, exerting a 2 N force tangent to the edge of the disk for 1 s.

A solid disk with radius of 0.5 m started at rest, and is free to rotate around its center without friction.

Answers

ANSWER:

1 N*m

STEP-BY-STEP EXPLANATION:

Given:

Force of edge (F) = 2 N

Radius (distance, d) = 0.5 m

The torque can be calculated using the following formula:

\(\begin{gathered} \tau=F\cdot d \\ \\ \tau=2\cdot0.5 \\ \\ \tau=1\text{ N*m} \end{gathered}\)

The final torque is equal to 1 N*m

Water flows at a speed of 13 m/s through a pipe that has a diameter of 1.2 m. What is the
diameter of the smaller end of the pipe that the water comes out with a speed of 30 m/s?

Answers

The diameter of the smaller end of the pipe is approximately 0.78 meters.

To determine the diameter of the smaller end of the pipe, we can use the principle of conservation of mass. According to this principle, the mass flow rate of water should remain constant throughout the pipe.

The mass flow rate is given by the equation:
Mass flow rate = density of water * cross-sectional area * velocity

Since the density of the water remains constant, we can write:
Cross-sectional area1 * velocity1 = Cross-sectional area2 * velocity2

Given that the velocity1 is 13 m/s, the diameter1 is 1.2 m, and the velocity2 is 30 m/s, we can solve for the diameter2 using the equation:
(pi * (diameter1/2)^2) * velocity1 = (pi * (diameter2/2)^2) * velocity2

Simplifying the equation:
(1.2/2)^2 * 13 = (diameter2/2)^2 * 30

Calculating the equation:
(0.6)^2 * 13 = (diameter2/2)^2 * 30

0.36 * 13 = (diameter2/2)^2 * 30

4.68 = (diameter2/2)^2 * 30

Dividing both sides by 30:
0.156 = (diameter2/2)^2

Taking the square root of both sides:
0.39 = diameter2/2

Multiplying both sides by 2:
0.78 = diameter2

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The mass on the spring in this diagram is in harmonic motion between x = -5
cm and x = 5 cm.
At which point does the mass have the most kinetic energy

The mass on the spring in this diagram is in harmonic motion between x = -5cm and x = 5 cm.At which point

Answers

Answer:

The mass will have the most KE at the midpoint of motion (velocity is a maximum)

Total Energy = KE + PE = constant

At zero displacement the potential energy equals zero and the kinetic energy is a maximum.

Answer:

I think it's point C but I'm not sure

An object weighing 10 N swings at the end of a rope that is 0.72 m long as a simple pendulum. At the bottom of the of the swing, the tension in the string is 12 N. What is the maximum height above its lowest point that the object reaches

Answers

Answer:

1.20m/s

Explanation:

We can use the formula [ m = w/g ] and [ t - w = mv^2/r ] to solve.

Use the first formula.

m = 10/9.8

m = 1.02

Use the second formula.

12 - 10 = 1.02-v^2/0.72

2 = 1.02-v^2/0.72

1.04v^2 = 1.47

v^2 = 1.41

v = √1.41

v ≈ 1.20

Best of Luck!

Seventy-one percent of the Earth is saltwater. Solve for the depth of the Pacific Ocean with pressure 3X atmospheric pressure. (Assume STP.)

Answers

The depth of the Pacific Ocean with a pressure three times the atmospheric pressure is 30.98 meters.

What is pressure?

The pressure is defined as the normal force applied on the surface. The pressure is the ratio of the normal force to the area of the applied surface.

Given that for the depth of the Pacific Ocean with pressure 3X atmospheric pressure.

The depth of water will be calculated by the formula from the concept of Hydrostatic pressure is,

P = ρ x g x h

The pressure is three times the atmospheric pressure,

P = 3 Patm

The depth will be calculated as:-

3Patm = 1000 x 9.81 x h

h = ( 3 x 101325 ) / ( 9810 )

h = 30.98 meters

The depth of the Pacific Ocean with pressure three times atmospheric pressure will be 30.98 meters.

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Shannon and Chris push on blocks with identical force. SHannon's block is twice as massive as Chris'. After pushing for 5 seconds, who did more work?

Answers

Neither because they used equal force
The amount of work done is equal to the force applied multiplied by the distance moved in the direction of the force.

Since Shannon and Chris push with identical force, the only difference between the two is the mass of the blocks.

The work done by Shannon is equal to the force she applied multiplied by the distance her block moved.

The work done by Chris is equal to the force he applied multiplied by the distance his block moved.

Since the force applied is the same, the only difference is the distance moved by each block.

Since Shannon's block is twice as massive as Chris', it will move half as far as Chris' block for the same amount of force applied.

Therefore, after pushing for 5 seconds, Chris did more work than Shannon.

Two bumper car in an amusement park ride collide elastically as on approaches the other directly from the rear. Car A has a mass of 450kg and car B 550kg, owing to differences in passenger mass. If car A approaches at 4.5m/s and car B is moving at 3.7m/s, calculate (a) their velocities after collision, and (b) the change in momentum of each.

Answers

Answer:

VA = 3.62 m/s  

VB = 4.42 m /s

Change of momentum of A = -396 kgm/s

Change of momentum of B = 396 kgm/s

Explanation:

Asuming A and B move to the right after the collision

pbefore =  pafter

4.5*450 + 3.7*550 = 450VA + 550VB

In a elastis collition, the coefficient of restitution is 1

1 = (VB - VA)/(4.5 - 3.7)

VB - VA = 0.8

VB = 4.42 m/s

VA = 3.62

Change of momentum of A = 450*(3.62-4.5) = -396 kgm/s

Change of momentum of B = 550*(4.42-3.7) = 396 kgm/s

The mass of Jupiter is 1.9 x 10 kg and that of the sun is 2 x 10 kg. If the distance between them is 78 x 10 km, find the gravitational force between them.​

Answers

Using the formula F = G * (m1 * m2) / r^2, where G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between them, we can calculate the gravitational force between Jupiter and the sun.

Plugging in the values, we get:

F = (6.674 x 10^-11 N * (m^2 / kg^2)) * ((1.9 x 10^27 kg) * (2 x 10^30 kg)) / (78 x 10^6 m)^2

Simplifying this, we get:

F = 1.98 x 10^27 N

Therefore, the gravitational force between Jupiter and the sun is approximately 1.98 x 10^27 Newtons.

The gravitational force between Jupiter and the sun, calculated using Newton's law of gravitation with their masses and distance, is \(1.95 * 10^{22} N.\)

The gravitational force between Jupiter and the sun is determined using Newton's law of gravitation, which states that two masses attract each other with a force that is directly proportional to the product of their masses and inversely proportional to the square of their distance apart. Given that the mass of Jupiter is \(1.9 * 10^{27} kg\) and that of the sun is \(2 * 10^{30} kg\), and the distance between them is \(78 * 10^6 km (which is 78 * 10^9 m)\), we can use the formula: Gravitational force = G(m1m2)/r^2where G is the universal gravitational constant, m1, and m2 are the masses of the two bodies, and r is the distance between them. Substituting the values gives Gravitational force \(= (6.67 * 10^{-11} Nm^2/kg^2) * (1.9 * 10^{27} kg) * (2 x 10^{30} kg) / (78 * 10^9 m)^2= 1.95 * 10^{22} N\)Thus, the gravitational force between Jupiter and the sun is \(1.95 * 10^{22} N.\)Summary: The gravitational force between Jupiter and the sun is found using Newton's law of gravitation, which is directly proportional to the product of their masses and inversely proportional to the square of their distance apart. Given the mass of Jupiter, the mass of the sun, and the distance between them, we can calculate the gravitational force using the formula. The gravitational force between Jupiter and the sun is \(1.95 * 10^{22} N.\)

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Is it true that electromagnetic waves do not require a material medium for propagation and travel with the speed of sound in vacuum?

Answers

Answer:

true

Explanation:

Electromagnetic waves differ from mechanical waves in that they do not require a medium to propagate. This means that electromagnetic waves can travel not only through air and solid materials, but also through the vacuum of space.

APEX PLEASE HELP
To increase the electricity supply in the country, a government needs to build
a new power plant. Which of the following is a cost associated with the use
of nuclear power that should be factored into its decision?
A. Nuclear power produces radioactive waste.
B. Nuclear power does not depend on wind.
C. Nuclear power does not contribute to climate change.
D. Nuclear power can be produced both day and night.

Answers

Answer: A. Nuclear power produces radioactive waste.

Raju completes one round of a circular track of diameter 200m in 30s. Calculate
a. The distance travelled by Raju
b. The magnitude of displacement travelled by Raju at the end of 30 s.

Answers

Explanation:

Given:

Diameter = 200 m

Radius, r = 200/2 = 100 m

Time taken, t = 30 seconds

Formula to be used:

Distance traveled, = circumference of circle = 2πr

Answer:

Putting all the values, we get

Distance traveled = 2πr

Distance traveled = 2 × 22/7 × 100 Distance traveled = 4400/7 Distance traveled = 628.57 m

So, the distance traveled by Raju is 628.57 m.

Now, magnitude of the displacement,

At the end of 30 seconds, Raju will come to starting position or initial position, so displacement is zero.

Explain why it’s much colder at the bottom of the pool than at the top. also describe what heat transfer processes is taking place

Answers

Heat transfer by radiation and convection causes the surface water of the pool to be warm which decreases with depth.

Why is it colder at the bottom of the pool than the top of the pool?

There are two heat transfer process responsible for variation in temperature of water at different depth of a pool, they include;

Heat transfer by radiationHeat transfer by convection

Heat transfer by radiation

The surface of the water absorbs heat from the air and the sun. The heat from the sun is transferred to the pool through radiation.

Heat transfer by convection

The heat from the air is transferred to the pool through convection.

Thus, these two heat transfer processes  causes the surface water of the pool to be warm which decreases with depth.

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how many taste buds do humans have 100,000, 100, 10,000 1,000​

Answers

The approximate number of taste buds that humans have is 10,000 (option C).

What are taste buds?

Tastebuds are any of the small organs on the tongue used for tasting.

Taste buds are cells on the tongue that allow one to perceive tastes, including sweet, salty, sour, bitter and umami.

Taste buds regenerate approximately every 10 days, which means injured taste buds usually repair on their own. The average adult human has between 2000 and 8000 tastebuds.

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An objects weight w is equal to the product of its mass and the acceleration due
to gravity. On Earth, this value is g = 9.8 m/s^2. If something weighs 400 N,
what is its mass?

Answers

Answer:hinwjdheiohuddwrr

87u7t

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