The big ben clock tower in london has clocks on all four sides. If each clock has a minute hand that is 11.5 feed in length, how far does the tip of each hand travel in 52 minutes?

Answer:

SECTION LEARNING OBJECTIVES

By the end of this section, you will be able to do the following:

Distinguish between static friction and kinetic friction

Solve problems involving inclined planes

Section Key Terms

kinetic friction static friction

Static Friction and Kinetic Friction

Recall from the previous chapter that friction is a force that opposes motion, and is around us all the time. Friction allows us to move, which you have discovered if you have ever tried to walk on ice.

There are different types of friction—kinetic and static. Kinetic friction acts on an object in motion, while static friction acts on an object or system at rest. The maximum static friction is usually greater than the kinetic friction between the objects.

Imagine, for example, trying to slide a heavy crate across a concrete floor. You may push harder and harder on the crate and not move it at all. This means that the static friction responds to what you do—it increases to be equal to and in the opposite direction of your push. But if you finally push hard enough, the crate seems to slip suddenly and starts to move. Once in motion, it is easier to keep it in motion than it was to get it started because the kinetic friction force is less than the static friction force. If you were to add mass to the crate, (for example, by placing a box on top of it) you would need to push even harder to get it started and also to keep it moving. If, on the other hand, you oiled the concrete you would find it easier to get the crate started and keep it going.

Figure 5.33 shows how friction occurs at the interface between two objects. Magnifying these surfaces shows that they are rough on the microscopic level. So when you push to get an object moving (in this case, a crate), you must raise the object until it can skip along with just the tips of the surface hitting, break off the points, or do both. The harder the surfaces are pushed together (such as if another box is placed on the crate), the more force is needed to move them.

The rooftop solar is a form of solar energy that can be installed on the roof of a home or business. It is cost-effective, environmentally friendly, and provides many benefits to homeowners and businesses.

The rooftop solar has many advantages over other forms of solar energy. One of the main advantages is that it provides 100% clean electricity from renewable sources. In addition, it can be combined with other sources such as wind power and geothermal power for even more benefits.

There are also many uses for rooftop solar panels in homes and businesses. One example is using it to heat water for hot water systems or heating swimming pools.

For me Bluebird Solar Private Limited is the best website in India for rooftop solar panels in India.

Bank tellers, bookkeepers, tax examiners, auditing clerks, cashiers, and bill collectors are among the occupations that demand a high school graduation or prior job experience. Thus option A,D is correct.

Depending on your field of study, degree type, and experience, you can obtain a number of entry-level positions with a finance degree. Some entry-level options include junior tax accountant, stockbroker, financial analyst, personal finance advisor, and banking assistant.

For entry-level positions in many financial careers, a bachelor's degree is necessary, and for management-level positions, a master's degree.

Therefore, Tax Preparer and Teller are included in Finance jobs can someone pursue with only a high school diploma.

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A three-prong 110-volt electric plug is an example of option d. Poka-Yoke permitting the only proper plug insertion.

Poka-Yoke is a Japanese term that means "mistake-proofing". It is a technique used in lean manufacturing to prevent defects by designing the process in such a way that errors are not possible. In the case of the three-prong 110-volt electric plug, the plug is designed in such a way that it can only be inserted in one way. This design feature prevents the user from inserting the plug incorrectly, thereby reducing the risk of electric shock or damage to the device.

Poka-Yoke is an important aspect of lean manufacturing because it helps to eliminate waste by reducing the need for rework or repair. By designing processes and products that are error-proof, companies can save time and money while improving product quality. It is a simple yet effective way to improve efficiency and productivity. In conclusion, the three-prong 110-volt electric plug is an example of Poka-Yoke because it is designed to permit only proper plug insertion.

This design feature reduces the risk of electric shock or damage to the device and helps to eliminate waste by preventing the need for rework or repair. Poka-Yoke is an important aspect of lean manufacturing and can be used to improve efficiency and productivity in any industry. Therefore, the correct answer is option d.

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The relationship between line voltage and phase voltage in a delta-connected load is line voltage = phase voltage.

What is Line Voltage?

In a three-phase system, line voltage, also known as Vline or VL-L, is the potential difference between any two lines or phases that are present in the system. The phases that are present here are coil windings or conductors.

If R, Y, and B are the three phases, the voltage difference between R and Y, Y and B, or B and R is the line voltage (red, yellow, and blue). Phase voltage is the potential difference between one phase (R, Y, or B) and the neutral junction point, and it is represented by the formula Vphase = VR (voltage of Red phase) = VY (voltage of Yellow phase) = VB.

Line voltage and Phase voltage Relation:

Line voltage and phase voltage are proportional to one another.

That means-

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1) the source voltage Vs referred to the low voltage side is Vs = 480 V

2) the transmission line current iTL is 26.67 - j20 A

3) the load current il is  0.00833 + j0.00625 A

4) the voltage drop across the transmission line Vdrop is 4.8006 + j5.3248 V

5) the load voltage VL is 48 V

To solve the given problem, we'll use the given information and apply relevant formulas. Let's go through each step:

1) Finding the source voltage Vs referred to the low voltage side:

We know that the turns ratio of the transformer is 10:1. Therefore, the voltage transformation ratio is also 10:1. So, we can write:

Vs/V2 = Ns/N2 = 10

Vs/4800 = 10

Vs = 4800/10

Vs = 480 V

2) Finding the transmission line current iTL:

The transmission line current can be calculated using Ohm's Law:

iTL = V2 / Zline

iTL = 4800 / (0.18 + j0.24)

iTL = (4800 / 0.18) - j(4800 / 0.24)

iTL = 26.67 - j20

3) Finding the load current il:

To find the load current, we can use the apparent power formula:

S = V * I*

Where S is the complex power, V is the voltage, and I* is the conjugate of the current.

Given that the apparent power S is 4 + j3 VA, and the voltage V is 480 V, we can solve for the load current il:

4 + j3 = 480 * il*

il = (4 + j3) / 480

il = (4/480) + (j3/480)

il = 0.00833 + j0.00625

4) Finding the voltage drop across the transmission line:

The voltage drop across the transmission line can be calculated using Ohm's Law:

Vdrop = iTL * Zline

Vdrop = (26.67 - j20) * (0.18 + j0.24)

Vdrop = (26.67 * 0.18) + j(26.67 * 0.24) - j(20 * 0.18) - 0.24 * 20

Vdrop = 4.8006 + j5.3248

5) Finding the load voltage VL:

The load voltage can be calculated using the voltage transformation ratio:

VL/Vs = N2/N1 = 1/10

VL/480 = 1/10

VL = 480/10

VL = 48 V

So, the answers to the given questions are as follows:

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The question is incomplete. Here is the complete question.

Two kg of a two phase liquid vapor mixture of carbon dioxide (CO₂) exists at -40°C in a 0.05m³ tank. Determine the quality of the mixture, if the values of specific volume for saturated liquid and saturated vapor CO₂ at -40°C are \(v_{f}\) = 0.896 x 10⁻³m³/kg and \(v_{g}=\) 3.824 x 10⁻²m³/kg, respectively.

Answer: x = 1

Explanation: In a phase change of a pure substance, at determined pressure and temperature, the substance exists in two different phases: saturated liquid and saturated vapor.

Quality (x) is the ratio of saturated vapor in the mixture and can be written as:

\(x=\frac{m_{vapor}}{m_{liquid}+m_{vapor}}\)

It has value between 0 and 1: x = 0 for saturated liquid and x = 1 for saturated vapor.

When related with volumes, quality is rearranged as:

\(x=\frac{v-v_{f}}{v_{g}-v_{f}}\)

Solving for x:

\(x=\frac{0.05-0.896.10^{-3}}{3.824.10^{-2}-0.896.10^{-3}}\)

\(x=\frac{0.049104}{0.037344}\)

x = 1.3

Quality of mixture of carbon dioxide is x = 1, which means it's for saturated vapor.

Answer:

the material's toughness, in terms of energy absorbed until fracture, is 98 kJ.

Explanation:

Step 1: Calculate the strain at the yield point:

Given that the cross-sectional area of the specimen is 0.004 m², and it yielded at a load of 280 kN (280,000 N), we can calculate the stress at the yield point:

Stress = Load / Cross-sectional area

Stress = 280,000 N / 0.004 m²

Stress = 70,000,000 N/m² (or Pa)

Using Hooke's Law, we know that stress is equal to the modulus of elasticity (E) multiplied by the strain (ε) at the yield point:

Stress = E * Strain

70,000,000 N/m² = 200,000,000,000 N/m² * Strain (converting E from GPa to N/m²)

Strain = 70,000,000 / 200,000,000,000

Strain = 0.00035

Step 2: Calculate the strain energy up to the yield point:

Strain energy (U) = (1/2) * Stress * Strain * Volume

We can assume that the volume remains constant during the test, so:

Strain energy (U) = (1/2) * Stress * Strain * Cross-sectional area * Length

For simplicity, let's assume the length of the specimen is 1 meter (this assumption won't affect the toughness calculation since it is based on energy per unit volume). Substituting the values:

Strain energy (U) = (1/2) * 70,000,000 N/m² * 0.00035 * 0.004 m² * 1 m

Strain energy (U) = 98,000 J (Joules)

Step 3: Convert the strain energy to kilojoules (kJ):

Toughness = Strain energy / 1000

Toughness = 98,000 J / 1000

Toughness = 98 kJ

Using the formula of comfort condition it is possible to determine the safe operating speed on the highway.

In physics, we define angular deviation as the angle resulting from the deflection of light when reflected from a prism. A prism has the ability to separate white light into several other colors, which are reflected by the object.

The comfort condition formula is given by: \(L=2(\frac{NV^{3} }{C} )^{\frac{1}{2} }\)

Where, L is the length of the vertical curve, N is the grade, V is the safe speed operation and assuming the standart value for C (0,6 m/s3) it is possible to calculate:

\(C = 0,6 m/s^{3} = 1,968 ft/s^{3}\\ N= N1 - N2 = 7,5-0 = 7,5% = 0,075\)

Changing the values in the formula:

\(L=2(\frac{NV^{3} }{C}){\frac{1}{2} } \\300 = 2(\frac{0,075.V^{3} }{1,968})^{\frac{1}{2} } \\V = 83,89 ft/s\)

So, the safe operating speed on the highway is 83,89 ft/s.

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Answer:

5

Explanation:

Given:-

- The power dissipated by a transistor, q = 6 W

- The dimensions of the plate:  ( 25 x 25 ) cm

- The forced velocity of air, V = 4 m/s

- The temperature of the air, T∞ = 35°C

- The temperature of the surface, Ts = 65°C

Declare Variables/Symbols:

- The number of transistors used = n

- Thermal conductivity = k

- Prandlt Number = Pr

- Nusselt Number ( averaged ) = Nu*

- Heat transfer coefficient ( averaged ) = h*

- Reynold's Number = Re

- Critical Reynold's Number ( Re,c ) = 5*10^5

- Density = ρ ( kg/m^3 )

- Dynamic Viscosity = μ ( kg/m.s )

Find:-

Assuming the heat transfer from the back side of the plate to be negligible and disregarding radiation, determine the number of transistors that can be placed on this plate

Solution:-

- We will perform the heat balance on the system ( aluminium plate integrated with transistors ). We will ignore the radiation effects and only consider the forced convective cooling of the transistors subjected to a stream of air forced at V = 4 m/s over the plate.

- From heat balance the rate at which heat is dissipated from the circuit -board is:

                                   \(n*q = h^*.A_s.( T_s - T_i_n_f )\)

Where,

            h*: The average heat transfer coefficient over the edge of the plate

            As: The area exposed to convective current

- We need to determine the average heat transfer coefficient ( h* ) over the flat plate for the given conditions. We know that the heat transfer coefficient is a function of a dimensionless quantity ( Nu* ), thermal conductivity ( k ) of convection fluid and edge length of the plate ( L ).

- We will first determine the thermo-physical properties of the convective fluid ( air ). Its a standard practise to evaluate these properties at the film temperature ( T ) , i.e the average of surface temperature ( Ts ) and the free stream temperature ( T∞ ). Thus,

                         \(T_f = \frac{T_s + T_i_n_f}{2} = \frac{65 + 35}{2}\\\\T_f = 50\)

- Use thermo-physical tables ( A - 4 ) and evaluate properties at T = 50°C:

                         k = 0.02735 W /m.K

                         Pr = 0.7228

                         ρ = 1.092 kg/m^3

                         μ = 1.963*10^-5 kg/m.s

- The average Nusselt Number ( Nu* ) is a function of flow properties of the convective fluid namely: ( Re , Pr ). We will determine the Reynold's number over the edge of the aluminium plate as follows:

                       \(Re_L = \frac{p*V*L}{u} = \frac{1.092*4*0.25}{1.963*10^-^5} = 55629.1391\)

- The Reynold's number define the flow conditions of the fluid. We see that Reynold number calculated above is within the critical Reynold's number ( Re,c ). Therefore,

                       Re = 5.6 * 10^5 ≤ Re,c ( 5*10^5 )

-  For flows with Re < Re,c, we take the assumption of "Laminar Boundary Layer".

- The corresponding (averaged) Nusselt Number empirical relation for Laminar flow regime and constant surface temperature ( Ts = 65°C ) over flat plate ( forced convection) we have:

                     \(Nu^* = 0.664. Re_L^\frac{1}{2}. Pr^\frac{1}{3}\\\\Nu^* = 0.664. (55629.13907)^\frac{1}{2}. (0.7228)^\frac{1}{3}\\\\Nu^* = 140.5482\)

- From above relation we can evaluate the average heat transfer coefficient ( h* ) as follows:

                     \(h^* = \frac{Nu_L^*. k}{L} = \frac{140.5482. 0.02735}{0.25}\\\\h^* = 15.376 \frac{W}{m^2.K}\)

- Now we can use the energy balance applied to the system initially developed and solve for ( n ):

                     \(n = \frac{h^*. A_s. ( Ts - T_i_n_f)}{q} \\\\n = \frac{15.376. ( 0.25)^2 . ( 65 - 35)}{6} \\\\n = 4.8\)

Answer: The number of transistors that can be placed are 5.

Note: In the above evaluation we have made an assumption that the exposed area ( As ) is equivalent to the surface area of the aluminium plate. This neglects the area associated with the thickness of the transistors. Moreover, we have assumed that the back-side of plate is thermally insulated. Also the surface temperature ( Ts ) of the plate base and the top of the transistor is assumed to be similar (if not then, we would have applied extended fin analysis ).  

Answer:

14 km/hour

Explanation:

Answer:

1) The bending moment diagram of the shaft is shown in Figure 1. The weakest cross section A is located at the point where the bending moment is maximum.

2) The weakest point on cross section A is located at the point where the bending moment is maximum.

3) The von-Mises stress at the weakest point is given by:

σ = M/I

where M is the bending moment and I is the moment of inertia of the cross section.

4) The factor of safety n is given by:

n = Sy/σ

where Sy is the yield strength of the shaft and σ is the von-Mises stress at the weakest point.

Explanation:

Hope this helps!

Answer:

y = 0.834X - 1.58015

Slope = 0.8340 ; Intercept = - 1.5802

y = 40.9539

19.93

0.9765

Explanation:

X: Rainfall volume

6

12

14

16

23

30

40

52

55

67

72

81

96

112

127

Y : Runoff

4

10

13

14

15

25

27

48

38

46

53

72

82

99

100

The scatterplot shows a reasonable linear trend between the Rainfall volume and run off.

The estimated regression equation obtained using a linear regression calculator is :

y = 0.834X - 1.58015

y = Runoff ; x = Rainfall volume

Slope = 0.8340 ; Intercept = - 1.5802

Point estimate for Runoff, when, x = 51

y = 0.834X - 1.58015

y = 0.834(51) - 1.58015

y = 40.95385

y = 40.9539

d.)

Point estimate for standard deviation :

s = 5.145

σ = s * √n

σ = √15 * 5.145

= 19.93

e.)

r² = Coefficient of determination gives the proportion of explained variance in Runoff due to the regression line. From the model output, the r² value = 0.9765. Which means That about 97.65% Runoff is due to Rainfall volume.

Answer:

The timing light is connected to the ignition circuit and used to illuminate the timing marks on the engine's crankshaft pulley or flywheel, with the engine running. The apparent position of the marks, frozen by the stroboscopic effect, indicates the current timing of the spark in relation to piston position.

Explanation:

:)

Answer:

Most technicians install rebuilt or new power steering pumps rather than overhauling the defective unit in the shop.

True

Explanation:

It has been established that most technicians, instead of overhauling the defective power steering pumps, prefer to install rebuilt or revamped pumps or even new pumps when they could have overhauled the unit themselves.  Some are afraid that leakage could occur again.  They are not confident enough to do the overhauling in-house or some claim that they do not have the time and other tools to carry out the overhauling.  Acknowledgedly, overhauling a power steering pump is not a job for the novice.  They require experienced and skilled hands to do the hard work.

The Rankine cycle is a thermodynamic cycle used in power plants to generate electricity. It is a simple cycle that consists of four components, a boiler, a turbine, a condenser, and a pump. The cycle operates between two pressure limits, the high-pressure limit, and the low-pressure limit.

The cycle efficiency is a measure of the amount of work produced by the cycle compared to the amount of energy supplied to the cycle. In this case, the Rankine cycle operates between the pressure limits of 20 kPa and 3 MPa, with a turbine inlet temperature of 500?C. Disregarding the pump work, we can use the Carnot cycle efficiency formula to find the cycle efficiency. The Carnot cycle efficiency is the maximum possible efficiency of any heat engine operating between two temperatures, and it is given by the formula:

Efficiency = (1 - Tlow/Thigh) * 100% Where Tlow is the absolute temperature of the low-pressure limit, and Thigh is the absolute temperature of the high-pressure limit. In this case, the low-pressure limit is 20 kPa, which is 0.02 MPa, and the high-pressure limit is 3 MPa. We can convert the turbine inlet temperature of 500?C to absolute temperature by adding 273.15, which gives us 773.15 K. So, Tlow = 293.15 K and Thigh = 773.15 K. Substituting these values into the efficiency formula gives us: Efficiency = (1 - 293.15/773.15) * 100% Efficiency = 62.11% Therefore, the cycle efficiency is approximately 62.11%. This means that for every 100 units of energy supplied to the cycle, 62.11 units are converted into useful work.

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Answer:

end products

Explanation:

end products are results of completion of the process of manufacturing. there are various categories under these. but the ones that got used by consumers are called end products

To make an alloy circle C, you need to first prepare the material by combining two or more metals together. This can be done by heating the metals until they liquify and then mixing them together. Once the alloy is formed, it can be shaped into a circle by using a die-casting machine or other casting methods. After the circle is shaped, it can be further processed to create the desired finish.

To make an alloy circle C, you will need to follow the steps below:
1. Gather the metals you want to use to make the alloy. Commonly used metals include copper, zinc, and tin.
2. Melt the metals together in a crucible or furnace at a high temperature.
3. Once the metals are melted and combined, pour the molten alloy into a mold in the shape of a circle.
4. Allow the alloy to cool and solidify in the mold.
5. Once the alloy is solid, remove it from the mold and you will have an alloy circle C.

It is important to note that different metals have different melting points and will require different temperatures to melt and combine. Additionally, the proportions of each metal used will affect the properties of the final alloy.

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The order in which reagents are added during the preparation of a UV/Vis sample is crucial to the experiment because it can affect the accuracy and precision of the measurements.

When preparing the UV/Vis sample, the order in which reagents are added is crucial to the experiment because it ensures proper reaction sequence, accurate measurements, and minimizes experimental errors. By adding reagents in a specific order, you allow each component to react and equilibrate appropriately, ultimately leading to accurate and consistent results.

Additionally, following the correct order helps avoid contamination and maintain the integrity of the sample throughout the experiment.

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The maximum spacing (L_max) of the supports to avoid fracture of the glass due to its own weight is 0.015 m.

Step 1: Calculate the bending moment (M) at the crack.

M = F x L = (0.5 x 2600) x 0.004 = 4.2 Nm

Step 2: Calculate the maximum stress (σ_max) at the crack.

σ_max = M / I = 4.2 / (0.5 x 0.018^3) = 18.3 MPa

Step 3: Calculate the maximum spacing (L_max) of the supports to avoid fracture.

L_max = (K_IC / σ_max)^2 = (0.3 / 18.3)^2 = 0.015 m

Therefore, the maximum spacing (L_max) of the supports to avoid fracture of the glass due to its own weight is 0.015 m.

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The statement "In a regular pyramid, the slant height is always longer than a lateral edge of the pyramid" is false.

In a regular pyramid, the slant height refers to the distance from the apex (top) of the pyramid to any point on the lateral face, measured along the slanted surface. A lateral edge, on the other hand, refers to the length of an edge that connects the apex to a vertex of the base.

In a regular pyramid, the slant height and the lateral edge are typically not equal to each other. The slant height is generally longer than a lateral edge. This can be understood by considering the shape of a regular pyramid, where the slant height forms a diagonal along the lateral face, while the lateral edge is a straight line connecting the apex and a vertex of the base.

However, it is important to note that the specific lengths of the slant height and lateral edge depend on the dimensions of the pyramid, such as the base size and the height. The relationship between the slant height and lateral edge can vary depending on the specific measurements of the regular pyramid.

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Answer:

I think it's 23 ohms.

Explanation:

Not entirely sure about it.

hope this helps

Answer:

a) 0.033024 GPa

b)  482.6 MPa

Explanation:

Gauge length = 50 mm

Tensile load = 1032 N

extension of gauge length = 0.625 mm

Extent of load sustainable by sample = 2063 N

Assuming a cross section area = 2500 mm^2 = 0.0025 m^2

a) Determine the Elastic modulus of the Polymer

Elastic modulus = stress / strain  --------  ( 1 )

  = ( f/A / strain )

f/A = force / area = 1032 / 0.0025 m^2  = 4.128 * 10^5 N/m^2

strain = Δl / original l  = 0.625 / 50 = 0.0125

Back to equation 1 = 4.128 * 10^5 / 0.0125 = 3.3024 * 10^7 N/m^2

= 0.033024 GPa

b) determine yield strength of Polymer

бy = 482.6 MPa

attached below is the detailed solution

Answer:

Explanation:

1. Inspect regularly

Regularly inspect your tools to make sure that they are in good condition.

2. Wear gloves

Always wear appropriate personal protective equipment.

3. Carry with care

Never carry tools up a ladder.

If you need to take tools up to a height use a bag or hoist them up in a bucket.

4. Don't pocket sharp objects

Never carry sharp or pointed tools in your pocket.

Instead, carry them in a toolbox.

5. Be aware of your surroundings

Always be aware of the people around you when using tools.

6. Use the right tools

Always use the right tools for the job.

Never use a tool for a different purpose than it was intended.

You risk damaging the tools and injuring yourself.

7. Follow instructions

Only operate tools according to manufacturers' instructions.

8. Clean and return

After using a tool, clean it and return it to it's proper storage place.

9. Oily hands are dangerous

Don't work with greasy or oily hands.

10. Protect your eyes

Always wear eye protection.

Answer:

D. 539,000 J

Explanation:

The formula for potential energy(P.E) =mgh where m is mass of object, g is gravity acceleration 9.8 m/s² and h is height in meters.

From the question ;

m=500 kg

g= 9.8 m/s²

h= 110 m

P.E = mgh

     = 500*9.8*110

     =539,000 J

 Answer option D

The other options are incorrect because the calculated values for the potential energy of the train are not equal to 539,000 J.