The ballistic pendulum is a device used to measure the speed of a fast - moving projectile such as a bullet. The bullet is fired into a large block of wood suspended from some light wires. The bullet embeds in the block, and the entire system swings up to a height h. A Walther PPK, the gun used by James Bond, has an average muzzle velocity of 950 m/s. In a ballistic pendulum, how high would we expect the block to travel when shot by a Walther PPK, given the mass of a 0.32 ACP is 5 grams, a the mass of the block is 2kg

Answer:

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Explanation:

Answer:

Freud's importance to psychology and psychiatry remains in the foundational aspects of the science of human behavior and the mind. Outside of Freudian psychoanalysis, Freud is no longer applicable or important to practical applications of psychological theory.

Answer: All organisms generate waste and dead material that is recycled by decomposers.

Explanation: Give me brainiest!

Answer:

V(c)' = 0.325 m/s

V(a)' = 2.19375 m/s

V(b)'' = 0.73125

Explanation:

See attachment for explanation.

Answer:

The mass in grams of a red blood cell is about 7.85 ×  10⁻¹¹ grams

Explanation:

To find the mass in grams of a red blood cell,

From,

\(Density = \frac{Mass}{Volume}\)

Then,

\(Mass = Density \times Volume\)

From the question,

Density of a red blood cell is similar to that of water

Density of water = 1 g/mL = 1 g/ cm³

Then, Density of a red blood cell = 1 g/cm³

Now, we will find the volume a red blood cell.

From the question,  

Since the shape is like that of a thick disc, we can determine the volume by using the formula for volume of a cylinder.

Hence,

Volume of a red blood cell = \(\pi r^{2}h\)

Where \(\pi\) Is a constant (Take \(\pi\) = 3.14)

\(r\) is the radius

and \(h\) is the thickness

Diameter of a red blood cell = 10 micrometers

Then, radius of a red blood cell = 10/2 micrometers = 5 micrometers

\(r\) = 5 micrometers = 5 × 10⁻⁶ meters

and \(h\) = 1 micrometer = 1 × 10⁻⁶ meters

Hence,

Volume of a red blood cell = 3.14 × (5 × 10⁻⁶)² × 1 × 10⁻⁶

∴ Volume of a red blood cell = 7.85 × 10⁻¹⁷ cubic meter (m³)

Convert this to cubic centimeter

(NOTE: 1 cubic meter = 1000000 cubic centimeter)

Hence,

Volume of a red blood cell = 7.85 ×  10⁻¹¹ cubic centimeter (cm³)

Now, for the mass

\(Mass = Density \times Volume\)

Density of a red blood cell = 1 g/cm³

Volume of a red blood cell = 7.85 ×  10⁻¹¹ cubic centimeter (cm³)

Then,

Mass = 1 g/cm³ ×  7.85 ×  10⁻¹¹ cm³

Mass = 7.85 ×  10⁻¹¹ g

Hence, the mass in grams of a red blood cell is about 7.85 ×  10⁻¹¹ grams

The electric charge and the electric force  on each sphere in terms of q is 2

Two metallic spheres, a and b, with a charge of half and a force of two tens of five

F1=k(1/2)(1/2)/r2

Equation F1=k/4r

A and C are two metallic spheres, respectively, so

Equation F2=k/2rsquare

equ1/equ2

2×10^-5/F2=k/4r^2×2r^2/k

F2=4×10^-5

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To calculate the net force on particle q2, we need to calculate the individual forces exerted by q1 and q3 on q2, considering their charges and separation distances.

Using Coulomb's Law, the force between two charged particles can be calculated as:

\(F = (k * |q1 * q2|) / r^2\)

where F is the force, k is Coulomb's constant (8.99 x 10^9 N m²/C²), q1 and q2 are the charges of the particles, and r is the separation distance between them.

For q1 and q2:

F1 = (8.99 x 10^9 N m²/C²) * (|-66.3 x 10^-6 C * 108 x 10^-6 C|) / (0.550 m)²

For q2 and q3:

F2 = (8.99 x 10^9 N m²/C²) * (|108 x 10^-6 C * -43.2 x 10^-6 C|) / (0.550 m)²

The net force on q2 is the vector sum of F1 and F2:

Net Force = F1 + F2

By calculating these values and performing the addition, we can determine the net force acting on particle q2.

Therefore, To calculate the net force on particle q2, we need to calculate the individual forces exerted by q1 and q3 on q2, considering their charges and separation distances.

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The normal force on the car when it is at the bottom of the track is 8.84 N.

At the top of the track (point B), the normal force (N) acting on the car is equal to the weight of the car (mg) plus the centrifugal force (mv²/r) acting outwards:

N = mg + mv²/r

where m is the mass of the car, g is the acceleration due to gravity, v is the speed of the car, and r is the radius of the track.

Since the car is traveling at constant speed, its acceleration is zero, so the centrifugal force is balanced by the force of gravity, and we have:

N = mg

Substituting the given values, we get:

6.00 N = (0.610 kg)(9.81 m/s²)

Solving for g, we get:

g = 9.68 m/s²

At the bottom of the track (point A), the normal force acting on the car is equal to the weight of the car minus the centrifugal force acting downwards:

N = mg - mv²/r

Substituting the known values, we get:

N = (0.610 kg)(9.81 m/s²) - (0.610 kg)(v²/5.00 m)

Since the car is traveling at constant speed, we can use the fact that its kinetic energy is equal to its gravitational potential energy to solve for v:

mg(2r) = (1/2)mv²

where 2r is the total distance traveled by the car (i.e., the circumference of the circle), so 2r = 2πr = 31.4 m. Solving for v, we get:

v = sqrt(2gr)

Substituting the known values, we get:

v = sqrt(2(9.68 m/s²)(5.00 m)) = 6.19 m/s

Substituting this value of v into the equation for N, we get:

N = (0.610 kg)(9.81 m/s²) - (0.610 kg)((6.19 m/s)²/5.00 m) = 8.84 N

Therefore, the normal force on the car when it is at the bottom of the track is 8.84 N.

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The velocity, measured in the Earth reference frame, of an inertial reference frame in which the cat's kinetic energy does not change is equal to the velocity of the skier before the collision. The velocity of the skier before the collision is 15 m/s.

According to the law of conservation of momentum, the total momentum before the collision must be equal to the total momentum after the collision. This can be expressed as m1*v1 + m2*v2 = (m1 + m2)*vf, where m1 and m2 are the masses of the skier and the cat respectively, v1 is the velocity of the skier, and vf is the velocity of the skier and the cat after the collision.

The kinetic energy converted to internal energy in the Earth reference frame can be determined by applying the law of conservation of momentum.

The amount of kinetic energy converted to internal energy can be calculated as follows:

m1*v1 = (m1 + m2)*vf

vf = (m1*v1)/(m1 + m2)

KE = (1/2)*m2*v2²

KE converted = KE initial - KE final

KE converted = (1/2)*m2*v2² - (1/2)*m2*((m1*v1)/(m1 + m2))²

KE converted = (1/2)*m2*v2² - (1/2)*m2*((60*15)/(60 + 5))²

KE converted = (1/2)*5*3.8² - (1/2)*5*(15²/65)

KE converted = 28.8 - 22.15

KE converted = 6.65 J

The velocity, measured in the Earth reference frame, of an inertial reference frame in which the cat's kinetic energy does not change is equal to the velocity of the skier before the collision.

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The nature of the image formed by the convex lens is virtual, the position of the image is 30 cm away from the lens on the same side as the object, and the size of the image is twice the size of the object. The magnification is 2, meaning the image is magnified.

Given:

Object height (h) = 5 cm

Focal length of the convex lens (f) = 10 cm

Object distance (u) = 15 cm (positive since it's on the same side as the incident light)

To determine the nature, position, and size of the image, we can use the lens formula:

1/f = 1/v - 1/u

Substituting the given values:

1/10 = 1/v - 1/15

To simplify the equation, we find the common denominator:

3v - 2v = 2v/3

Simplifying further:

v = 30 cm

The image distance (v) is 30 cm. Since the image distance is positive, the image is formed on the opposite side of the lens from the object.

To find the magnification (M), we use the formula:

M = -v/u

Substituting the values:

M = -30 / 15 = -2

The magnification is -2, indicating that the image is inverted and twice the size of the object.

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Answer:

B. 1,170,000 J

Explanation:

Given;

mass of lead block, m = 40 kg

initial temperature, t₁ = -25 ⁰C

final temperature, t₂ = 200 ⁰C

The heat absorbed the lead block is calculated as;

H = mcΔt

where;

c is the specific heat capacity of lead =  130 J/kg⁰C

H = 40 x 130 x (200 - (-25))

H = 40 x 130 x (200 + 25)

H = 40 x 130 x 225

H = 1,170,000 J

Therefore, the heat absorbed the lead block is 1,170,000 J

Answer:

c

Explanation:

because a drop of water is falling and that is gravitational potential energy into motion energy

The coefficient of kinetic friction is equal to μ = F/N.

The coefficient of kinetic friction (fr), which is a numerical value, is obtained by dividing the resistive force of friction (Fr) by the normal or perpendicular force (N) pushing the objects together.

Static friction prevents the box from moving on its own; this friction must be overcome by an opposing force powerful enough to cause the box to move. Kinetic friction, sometimes referred to as dynamic friction, is a force that resists the relative movement of surfaces when they are in motion.

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The pressure of the gas in the deodorant can when it is heated to 900 K is 9 atm.

Gay-Lussac's law states that the pressure exerted by a given quantity of gas varies directly with the absolute temperature of the gas.

It is expressed as;

P₁/T₁ = P₂/T₂

From the data:

We substitute our values into the expression above and solve for final pressure.

P₁/T₁ = P₂/T₂

P₁T₂ = P₂T₁

P₂ = P₁T₂  / T₁

P₂ = ( 3 atm × 900 K ) / 300 K

P₂ = 9.0 atm

Therefore, the final pressure is 9.0 atm.

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The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)

The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.

This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.

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Answer:

Explanation:

We can use the kinematic equation v^2 = u^2 + 2as to solve for the length of the driveway. Here, u = 0 (since the car starts from rest), v = 3.8 m/s, a = F/m = 4.0 x 10^3 N / 2.1 x 10^3 kg = 1.9 m/s^2. Solving for s, we get:

s = (v^2 - u^2) / 2a = (3.8^2) / (2 x 1.9) = 3.8 m

So the length of the driveway is 3.8 meters.

The pipe will be 40.1 meter  if the barrel is not to rupture.

The pressure exerted by a fluid at equilibrium at any point due to the force of gravity is known as fluid pressure.

Given that: fluid pressure is: p = 350 kPa = 350 * 1000 Pa = 350000 Pa.

Density of fluid is: ρ = 890 kg/m^3.

Let the height of the pipe is h.

Hence, from the formula of  P = hρg we get: the height of the pipe is:

h = P/ρg

= 350000/(890×9.8) m

= 40.1 meter.

So, the pipe is 40.1 m long.

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Answer:

Weight, W = 400 N

Explanation:

Give that,

Mass of a girl, m = 40 kg

We need to find the weight of a girl.

Weight of an object is given by :

W = mg

g is the acceleration due to gravity

Putting all the values,

W = 40 kg × 10 m/s²

= 400 N

Hence, the weight of a girl is 400 N.

Answer:

all of those are pisitions

Explanation:

Answer:

Theory

Explanation:

Conservation of energy is explained as a scientific law and not a theory because it does not explain why energy is conserved.

A law is a the statement of a scientific fact. It is a product of repeated experiment and observation through time. Most laws do not explain the reason for the logic behind their premise.

A theory on the other hand provides an explanation for an observed phenomenon. Most theories are no immutable. They are often changed when new finds are reported or made.

Laws are immutable and they stand still.

Press Alt and 0176 on your keyboard. Please take note that this technique only functions on keyboard shortcut with a 10-key numeric pad.

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The average angular acceleration of the second hand is zero because the angular speed is constant. The angular speed is 360 degrees/hour.

The angular acceleration of a clock's minute hand on a clock is π1800rad/s

Angular acceleration means the time rate of change of angular velocity. The second hand of a clock involves an angular displacement of 2π per minute. Its angular speed is w = 2p/60s = 0.105/s. The direction of w is perpendicular to the face of the clock, directing to the face of the clock. The average angular acceleration of the second hand is zero.

Therefore, the correct answer is as given above

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The horizontal velocity of the projectile as it leaves the launcher is 35 m/s.

The time of motion of the projectile is calculated by applying the following kinematic equation as shown below.

h = vt + ¹/₂gt²

where;

h = 0 + ¹/₂gt²

h = ¹/₂gt²

t = √(2h/g)

t = √(2 x 0.4 / 9.8)

t = 0.286 s

The horizontal velocity of the projectile as it leaves the launcher is calculated as follows;

v = x/t

where;

v = 10 m / 0.286 s

v = 35 m/s

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Answer:

a. 10.5 s b. 6.6 s

Explanation:

a. The driver's perception/reaction time before drinking.

To find the driver's perception time before drinking, we first find his deceleration from

v² = u² + 2as where u = initial speed of driver = 50 mi/h = 50 × 1609 m/3600 s = 22.35 m/s, v = final speed of driver = 0 m/s (since he stops), a = deceleration of driver and s = distance moved by driver = 385 ft = 385 × 0.3048 m = 117.35 m

So, a = v² - u²/2s

substituting the values of the variables into the equation, we have

a = v² - u²/2s

a = (0 m/s)² - (22.35 m/s)²/2(117.35 m)

a =  - 499.52 m²/s²/234.7 m

a = -2.13 m/s²

Using a = (v - u)/t where u = initial speed of driver = 50 mi/h = 50 × 1609 m/3600 s = 22.35 m/s, v = final speed of driver = 0 m/s (since he stops), a = deceleration of driver = -2.13 m/s² and t = reaction time

So, t = (v - u)/a

Substituting the values of the variables into the equation, we have

t = (0 m/s - 22.35 m/s)/-2.13 m/s²

t = - 22.35 m/s/-2.13 m/s²

t = 10.5 s

b. The driver's perception/reaction time after drinking.

To find the driver's perception time after drinking, we first find his deceleration from

v² = u² + 2as where u = initial speed of driver = 50 mi/h = 50 × 1609 m/3600 s = 22.35 m/s, v = final speed of driver = 30 mi/h = 30 × 1609 m/3600 s = 13.41 m/s, a = deceleration of driver and s = distance moved by driver = 385 ft = 385 × 0.3048 m = 117.35 m

So, a = v² - u²/2s

substituting the values of the variables into the equation, we have

a = v² - u²/2s

a = (13.41 m/s)² - (22.35 m/s)²/2(117.35 m)

a = 179.83 m²/s² - 499.52 m²/s²/234.7 m

a = -319.69 m²/s² ÷ 234.7 m

a = -1.36 m/s²

Using a = (v - u)/t where u = initial speed of driver = 50 mi/h = 50 × 1609 m/3600 s = 22.35 m/s, v = final speed of driver = 30 mi/h = 30 × 1609 m/3600 s = 13.41 m/s, a = deceleration of driver = -1.36 m/s² and t = reaction time

So, t = (v - u)/a

Substituting the values of the variables into the equation, we have

t = (13.41 m/s - 22.35 m/s)/-1.36 m/s²

t = - 8.94 m/s/-1.36 m/s²

t = 6.6 s

The best way of presenting the information on density graphically would be to use a D, bar graph.

A bar graph is a type of chart that uses rectangular bars to represent data. The bars are typically arranged in columns, with the independent variable (in this case, the type of wood) on the x-axis and the dependent variable (in this case, the density) on the y-axis.

A bar graph is the best choice for this data because it allows for easy comparison of density of different types of wood. We can see at a glance which type of wood is the densest and which type of wood is the least dense.

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The correct statement for the skier has the most potential energy is when the skier is at the top of the ski slope. Hence, option (a) is correct.

Potential energy is a form of energy that is stored but is dependent on the size positions of different system components. Extending or contracting a spring increases its potential energy.

A specimen has much more potential energy when it is raised above the surface of the earth than when it is brought to Earth. It can conduct more work in the raised position. Potential energy is a system property, not a feature of a single entity or particle. For example, the system made up of Earth and the raised ball has greater potential energy as they are far apart.

The potential energy at the top of the ski slope will be maximum, while the kinetic energy at the top of the ski slope will be equal to zero.

Therefore, when he was at the top of the ski slope, the potential energy will be maximum.

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