The assembly has the diameters and material make-up indicated. It fits securely between its fixed supports when the temperature is T1 = 70∘F.
Part A
Determine the average normal stress in the aluminum when the temperature reaches T2 = 116 ∘F.
Part B
Determine the average normal stress in the bronze when the temperature reaches T2 = 116 ∘F.
Part C
Determine the average normal stress in the stainless steel when the temperature reaches T2 = 116 ∘F.

Answer:

A Lengths

Explanation:

you make a model to show an object too large to test and too expensive to test

Answer:

a. lengths.

Explanation:

The scale can be said to be a representation of the model as regards the prototype. The prototype is the machine. Using a 1:20 scale tells us that the model is 1/20 times the magnitude of the length of this machine. So if the length of the side of the machine = 20m then we would have the length of the model as 1. (1/20x20 = 1)

Therefore the scale is the length and option a is correct

Answer:

E = 132.69 sin(ωt -11.56)

i(t) = 6.64 sin (ωt +48.44) A

Explanation:

given data

e1 = 80 sin ωt volts                       80 < 0

e2 = 60 sin (ωt + π/2) volts          60 < 90

e3 = 100 sin (ωt – π/3) volts        100 < -60

solution

resultant will be  = e2 + e2 + e3

E =  80 < 0 + 60 < 90 + 100 < -60

\(\bar E\) = 80 + j60 + 50 - j50\(\sqrt{3}\)

\(\bar E\) = 130 + (-j26.60)

\(\bar E\) = 132.69  that is less than -11.56

so

E = 132.69 sin(ωt -11.56)

and

as we have given the impedance

z = (10-j17.3)Ω

z = 19.982 < -60

and

i(t) = \(\frac{132.69}{19.982}\) sin(ωt -11.56 + 60)  

i(t) = 6.64 sin (ωt +48.44) A

A high-pass R C filter is a filter that allows signals above a certain frequency, the cutoff frequency, to pass through while rejecting signals below that frequency. In this case, the filter is connected to an AC source with a peak voltage of 9.00 V and the peak capacitor voltage is 6.4 V.

The ratio of the peak capacitor voltage to the peak source voltage is known as the voltage gain of the filter.

The voltage gain is given by the equation:

Voltage Gain = Peak Capacitor Voltage/Peak Source Voltage

Voltage Gain = 6.4 V/9.00 V Voltage Gain = 0.711 or 71.1 %

The voltage gain is less than 1, which means that the output voltage is less than the input voltage.

This is because the high-pass RC filter attenuates the low-frequency signals while allowing the high-frequency signals to pass through. The output voltage of the filter is reduced, resulting in a voltage gain of less than 1.

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The program to illustrate the list is given below:

def isSorted(lyst):

 # Check for a list of length 1

 if(len(lyst)>=0 and len(lyst)<2):

   return True

 else:        

   for i in range(len(lyst)-1):

     if(lyst[i]>lyst[i+1]):

       return False

   # Make this statement in line with the for loop    

   return True

def main():

 lyst=[]

 print(isSorted(lyst))

 lyst=[1]

 print(isSorted(lyst))

 lyst=list(range(10))

 print(isSorted(lyst))

 lyst[9]=3

 print(isSorted(lyst))

main()

A program is a specific set of ordered operations that a computer can perform. The program in the modern computer described by John von Neumann in 1945 contains a one-at-a-time sequence of instructions that the computer follows.

Typically, the program is saved in a location accessible to the computer. A computer program is a set of instructions written in a programming language that a computer can execute.

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Answer:

Explanation:

hola friend!!!!!

there is only one crankshaft in V8 engine

Hope this helps

plz mark as brainliest!!!!!!!!

Since both sides of equation P = Mgh have the same dimensions, that is kg x m²/s³, then the equation is dimensionally homogeneous.

To prove that the equation P = Mgh is dimensionally homogeneous, we need to verify that both sides of the equation have the same dimensions.

Starting with the left-hand side of the equation, we have:

P = Mgh

where P is power, which has units of watts (W) in the SI system.

Moving on to the right-hand side of the equation, we have:

Mgh

where M is mass flow rate, which has units of kg/s in the SI system, g is the gravitational constant, which has units of m/s², and h is pump head, which has units of meters (m) in the SI system.

Multiplying these units together, we get:

kg/s x m/s² x m = kg x m²/s³

Therefore, the units of the right-hand side of the equation are kg x m²/s³.

Since the units of both sides of the equation are the same (i.e., watts), we can conclude that the equation P = Mgh is dimensionally homogeneous.

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The pipe's entrance measures 17.7 feet.

The axial distance required to arrive at a value of Nu(x) that is 1.05 times the fully defines the thermal entry length Lth.

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Mechanical combustion results from all of the following, except: Electrical lighting.

Electric lighting has been a part of popular culture since Thomas Edison created a usable incandescent bulb in 1879. It was a major draw at the world's fairs in Chicago in 1894, Buffalo in 1901, and St. Louis in 1904, for instance.

Cities became more hospitable at night thanks to electric lighting; for instance, Broadway earned the nickname the Great White Way thanks to it. Moreover, it added brightness and life to homes.

Unsurprisingly, electric lighting was almost always referred to favorably in popular culture during the first half of the twentieth century. Take the 1931 film "City Lights" by Charlie Chaplin as an illustration. It celebrated indoor and outdoor electric lighting.

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Relay contacts that are defined as being normally open (n.o.) have contacts that are open only if  the relay coil is known to have de-energized.

Normally open (NO) are  known to be open if there is no measure of current that is flowing through a given coil but it often close as soon as the coil is said to be energized.

Note that  Normally closed (NO) contacts are said to be closed only if the coil is said to be de-energized and open only if the coil is said to carry current or is known to have energized.

The role of relay contact is wide. The Relays are tools that are often used in the work of  switching of control circuits and it is one that  a person cannot used for power switching that has relatively bigger ampacity.

Therefore, Relay contacts that are defined as being normally open (n.o.) have contacts that are open only if  the relay coil is known to have de-energized.

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Decomposition is the process of breaking the Work Breakdown Structure (WBS) into smaller and smaller deliverables. This process is also sometimes referred to as value engineering or detailed specifications. By decomposing the WBS into smaller pieces, it becomes easier to assign tasks, assign costs, and plan out timelines.

The decomposition process begins by taking the major deliverables of the project and breaking them down into smaller tasks. From there, each task is further broken down into even more specific tasks. This process is repeated until all tasks have been broken down into their smallest components.

The purpose of decomposition is to create a well-defined scope of the project so that it can be managed in an efficient manner. It allows managers to easily identify the resources, cost, and timeline of each task, as well as provide a way to evaluate the progress of each task. It also allows for better control of the overall project.

Decomposition is a critical part of the project management process, as it ensures the project is organized and defined. This ultimately leads to an overall better result for the customer.

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The peak runoff rate from the shopping center during a 50-year storm is approximately 0.296 m/s.

To calculate the peak runoff rate from the shopping center during a 50-year storm, use the Rational Method, which is given as

Q = (C * I * A) / 3600

where

Q is the peak runoff rate in m/s,

C is the runoff coefficient,

I is the rainfall intensity in mm/h, and

A is the total area of the shopping center in \(m^2.\)

Assuming a 50-year storm has a rainfall intensity of 152 mm/h based on the IDF curve example.

Using the runoff coefficients for the different surfaces in the shopping center, we can calculate the total area-weighted runoff coefficient as follows

C = [(0.95 * 71,000) + (0.85 * 17,000) + (0.65 * 22,000) + (0.90 * 5,000) + (0.70 * 25,000)] / (71,000 + 17,000 + 22,000 + 5,000 + 25,000)

C = 0.807

The total area of the shopping center is

A = 71,000 + 17,000 + 22,000 + 5,000 + 25,000 = 140,000 \(m^2\)

Now we can calculate the peak runoff rate

Q = (C * I * A) / 3600

Q = (0.807 * 152 * 140,000) / 3600

Q = 41.5 \(m^3/s\) or 41.5 / 140 = 0.296 m/s

Therefore, the peak runoff rate from the shopping center during a 50-year storm is approximately 0.296 m/s.

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Answer:

Following are the program to the given question:

#include <stdio.h>//header file

double square_root(double N, double initialGuess)//defining a method square_root that takes two variable in parameters

{

double NG, LG = initialGuess,diff;//defining double variable

while(1)//use loop to calculate square root value

{

NG = 0.5 * (LG + N / LG);//using given formula

diff = NG - LG;//calculating difference

if(diff < 0)//use if to check difference is less than 0

diff = -diff;//decreaing difference

if(diff < 0.005)//use if that check difference is less than 0.005

break;//using break keyword  

else//defining else block

{

LG = NG;//holding value

}

}

return NG;//return value

}

int main()//defining main method

{

double ans, n,initialguess = 1.0;//defining double variable

n = 4;//use n to hold value

ans = square_root(n, initialguess);//calculating the square root value and print its value

printf("square_root(%lf) = %lf \n", n, ans);//print calculated value with number

n = 120.5;//use n to hold value

ans = square_root(n, initialguess);//calculating the square root value and print its value

printf("square_root(%lf) = %lf \n", n, ans);//print calculated value with number

n = 36.01;//use n to hold value

ans = square_root(n, initialguess);//calculating the square root value and print its value

printf("square_root(%lf) = %lf \n", n, ans);//print calculated value with number

n = 0.25;//use n to hold value

ans = square_root(n, initialguess);//calculating the square root value and print its value

printf("square_root(%lf) = %lf \n", n, ans);//print calculated value with number

printf("\nEnter a number: ");//print message

scanf("%lf", &n);//input value

ans = square_root(n, initialguess);//calculating the square root value and print its value

printf("square_root(%lf) = %lf \n", n, ans);//print calculated value with number

}

Output:

Please find the attachment file.

Explanation:

The rate of energy loss through a 1.5 square meter window with the worst R-value (0.9) is 936.7 Btu/hour and the rate of energy loss through the best R-value (11.1) is 75.95 Btu/hour. In order to calculate how much can be saved by replacing all the windows with the highest R-value, relative to the lowest R-value windows, we need to consider the energy loss of all the windows.

We have 18 windows in the house, therefore the amount of energy lost with the lowest R-value windows will be:18 * 936.7 = 16,860.6 Btu/hourOn the other hand, the amount of energy lost with the highest R-value windows will be:18 * 75.95 = 1,367.1 Btu/hour The difference between the two will be the amount of energy that will be saved if we use the highest R-value windows:16,860.6 - 1,367.1 = 15,493.5 Btu/hourNow, we need to consider the duration of the winter, which is 4 months or 120 days, assuming that the house is heated for the entire duration of winter. Therefore, the total amount of energy that can be saved in 4 months or 120 days will be:15,493.5 * 120 = 1,859,220 Btu (rounded off to the nearest whole number).This means that we can save 1,859,220 Btu of energy if we replace all the windows with the highest R-value, relative to the lowest R-value windows over the course of a 4-month winter year.

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Answer:

The percentage of recycling in high socioeconomic localities is 11.02%.

Explanation:

Since in high socioeconomic localities, 10% of paper is recycled, 12% of plastic, 1.7% of fabrics, 1.2% of rubbers, 0.9% of metals, 3.5% of glass, 33% of food wastes, 35% soil and 1.9% miscellaneous, to determine the average recycling percentage the following calculation must be performed:

(10 + 12 + 1.7 + 1.2 + 0.9 + 3.5 + 33 + 35 + 1.9) / 9 = X

99.2 / 9 = X

11.02 = X

Therefore, the percentage of recycling in high socioeconomic localities is 11.02%.

Answer:

Not sure

Explanation:

Looking now

Answer:

  150 N

Explanation:

Moment is the product of force and distance:

  27 N·m = F·(0.180 m)

  F = 27 N·m/(0.180 m) = 150 N

The force required to produce the desired moment is 150 N.

Answer:

Explanation:

The process that Piaget called "adding another example to an existing scheme" is called assimilation. Assimilation refers to the cognitive process of incorporating new information or experiences into existing mental schemas or frameworks. In this case, Tammy assimilates the new example of a golf ball into her existing "ball" scheme, expanding her understanding of what falls under the category of a ball.

Answer:

The answer is "\(-121\ \frac{KJ}{Kg}\)".

Explanation:

Please find the correct question in the attachment file.

using formula:

\(\to W=-P_1V_1+P_2V_2 \\\\When \\\\\to W= \frac{P_1V_1-P_2V_2}{n-1}\ \ or \ \ \frac{RT_1 -RT_2}{n-1}\\\\\)

\(W =\frac{R(T_1 -T_2)}{n-1}\\\\\)

    \(=\frac{0.287(25 -237)}{1.5-1}\\\\=\frac{0.287(-212)}{0.5}\\\\=\frac{-60.844}{0.5}\\\\=-121.688 \frac{KJ}{Kg}\\\\=-121 \frac{KJ}{Kg}\\\\\)

We can see here that the element in the circuit that is possibly a resistor is Element B.

A resistor actually known to be a electrical component or device that has two terminals through which current enters and leaves. A resistor is known to limit or regulate the flow of electrical current in an electronic circuit. Resistors are known to be used in order to also provide a kind of specific voltage for a device that is active like a transistor.

Resistors are used in electrical and electronics in order to control the flow of current, reduce current, divide voltages, adjust the level of signals and terminate transmission lines. It is used for other purposes in the electronics field.

We see here that element B selected above is a resistor. The arrow on the head is pointing downward which indicates that current is entering.

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Answer:

Forces like wind and water break down rocks through the processes of weathering and erosion. ... Forces like wind and water move the rock pieces. They mix with matter like sand to become sediment. Weathering and erosion help shape Earth's surface.

Answer:

As an agent of erosion, the wind will quickly break the rock into different rock types.

Explanation:

Using a trial-and-error or diagram pattern, solve the Manning's equating for the normal wisdom (y) by:

Calculating A, P, and R for various y principles.Computing Q for each y advantage.

To decide the normal insight of a trapezoidal channel, apply Manning's equating: Q = (1/n) * A * R^(2/3) * S^(1/2)

For a trapezoidal channel: A = (b + zy) * yP = b + 2 * y * sqrt(1 + z^2)R = A / P

Using a trial-and-error or diagram pattern, solve the Manning's equating for the normal wisdom (y) by:

Calculating A, P, and R for various y principles.Computing Q for each y advantage.

Plotting the relationship 'tween y and Q.Finding the y advantage corresponding to the likely flow rate of 9.8 m³/s.

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Answer:

Explanation:

The positive (red) cable should be attached to the positive terminals on each battery. The negative (black) cable should have one end attached to the negative terminal of the dead battery, and one end grounded.

Start by connecting the positive (often red) clamps of the jumper cables to the positive terminals of your battery. These are often marked, but they can be hard to see. Be sure to look closely to ensure that you are connecting to the right portion of the battery.

Answer:

Cave-ins

Explanation:

The term excavation means any form of cuts, depression or trench by removing the surface of the earth. This process is intended primarily for the purpose of construction and maintenance or exploration. In this process there are many hurdles that pose danger to both human life and earth. The excavation workers face the great threat because of cave-ins. The collapsing of the earth's surface and random accidents prove to be very dangerous for the workers.

Answer:

1) 4.41 * 10^-4 kw

2) 2.20 * 10^-4 kw

Explanation:

Given data:

Filter = 500 m^3/min

dust velocity = 3g/m^3

bag ; length = 3 m , diameter = 0.13 m

change in pressure = 1 kPa

efficiency = 60%

1) Calculate the Fan power

First :

Calculate the total dust loading = 3 * 500 = 1500 g

To determine the Fan power we will apply the relation

\(n_{o} = \frac{\frac{p}{eg*Q*h} }{1000}\)    = \(\frac{\frac{p}{(3*10^{-3})* 981*( 500/60) *3 } }{1000}\)

fan power ( \(n_{0}\) ) = 4.41 * 10^-4 kw

2) calculate power drawn

change in P = 6 atm = 6 * 10^5 pa

efficiency compressor = 50%

hence power drawn = 4.41 * 10^-4 kw  * 50% = 2.20 * 10^-4 kw

Answer:

(a) To determine the speed v at each stand, we can use the relationship between the forward slip, rotational speed, and rolling speed:

rolling speed = rotational speed × (1 - forward slip)

At the first stand, the thickness reduction is:

thickness reduction = draft / starting thickness = 0.25 / 1.0 = 0.25

The final thickness after the first stand is:

final thickness = starting thickness - thickness reduction = 1.0 - 0.25 = 0.75

The speed at the first stand is:

v1 = (π × 10^2 × 20) / (12 × 0.75) = 139.63 ft/min

At the second stand, the thickness reduction is again 0.25, and the final thickness is 0.5. The speed at the second stand is:

v2 = (π × 10^2 × 20) / (12 × 0.5) = 209.44 ft/min

(b) To determine the forward slip, we can use the formula:

forward slip = (rotational speed - rolling speed) / rotational speed

At the first stand:

forward slip1 = (20 - 139.63) / 20 = -5.98

At the second stand:

forward slip2 = (20 - 209.44) / 20 = -9.47

Note that the negative values indicate that the rolling speed is greater than the rotational speed, which is physically impossible. This suggests that the assumption of equal forward slip at each stand is not valid.

(c) The exiting speed at each rolling stand can be determined using the same formula as in part (a), but with the entering speed at the previous stand as the rolling speed:

At the first stand, entering speed = 85 ft/min:

v1 = 85 × (1 - (-5.98)) = 541.88 ft/min

At the second stand, entering speed = v1:

v2 = v1 × (1 - (-9.47)) = 922.57 ft/min