The anti-collision lights will be on when? What is the one scenario when they won't be on?

The GPO with the highest priority in a list linked to a container is the one that was last applied.

This means that the last GPO linked to the container will take precedence over any other GPOs that have been linked to it before.This order of priority is determined by the way in which Active Directory processes Group Policy settings. When a user or computer logs on to the network, the Active Directory client uses the site, domain, and organizational unit (OU) to build a list of GPOs to apply to the user or computer.

The list is built in order of precedence, starting with the GPO at the lowest level of the Active Directory hierarchy and moving up. If multiple GPOs are linked to a container, the most recently linked GPO will be processed last, taking priority over any previous GPOs. This ensures that any settings configured in the most recent GPO will overwrite the settings in previous GPOs.

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Answer:

fgfr

cg

Explanation:

xhrrhfdfghtrfgg

This function will return the minimum value in the range of cells A2:A6.

Function is a self-contained block of code that is used to perform a particular task in a computer program. It is a set of instructions that can be called upon to perform a specific action. Functions are often used to break up a program into smaller, more manageable pieces that can be reused or combined with other functions to create more complex programs. Functions can also be used to simplify and shorten the length of a program, which makes it easier to read and debug. A function typically takes an input, performs a calculation or some type of action with that input, and then returns the result.

For finding the best manufacturing candidate based on minimum cost, we can use the MIN function. The MIN function returns the smallest numeric value in a set of values.

Syntax: =MIN(number1, [number2], ...)

Example: =MIN(A2:A6)

This function will return the minimum value in the range of cells A2:A6.

For finding the best shipping candidate based on minimum cost, we can use the MIN function in the same way. The syntax and example would be the same as above.

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The statement that evaluates to True when the `intDays` variable contains the number 5 is `If intDays = 5 Then`.In the given question, we are asked to determine the statement that evaluates to True when

the `int Days` variable contains the number 5.The different statements given are:a. If intDays = 5 Thenb. If intDays <> 0 Thence. If int Days > 1 Thind. all of the aboveOut of these, the only statement that evaluates to True when the `intDays` variable contains the number 5 is `If intDays = 5 Then`.Therefore, the answer to the given question is option a. If intDays = 5 Then.The other options are as follows:b. If intDays <> 0 Then evaluates to True for all values of `intDays`, except 0.c. If intDays > 1 Then evaluates to True for all values of `intDays` greater than 1.d. All of the above does not evaluate to True when `intDays` contains the number 5.

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A pair of helical gears are machined with a hob. The hob has a 20 degree pressure angle and machines circular pitch of 0.55 inch/tooth on a spur gear.

Calculate the pinion tangent force in Ibf.

Pressure angle, φ = 20°

Circular pitch, P = 0.55 inch/tooth

Number of teeth on pinion, N₁ = 18

Number of teeth on gear, N₂ = 36

Transverse diametral pitch on pinion, Ptd = 5 inch/tooth

Power transmitted by pinion, P = 10 hp

Speed of pinion, n₁ = 1,390 rpm

Formula used:

Diameter of gear = N × P

Diametral pitch = N / Pitch Diameter

Transverse Diametral Pitch = Diametral Pitch / cos(φ)

Tangential force = 63025 × (Power / (n₁ × Pitch Diameter))

Solution:

Pitch diameter of the pinion = N₁ × P = 18 × 0.55 = 9.9 inch

Pitch diameter of the gear = N₂ × P = 36 × 0.55 = 19.8 inch

Diametral pitch of pinion = N₁ / Pitch Diameter = 18 / 9.9 = 1.82 inch

Diametral pitch of gear = N₂ / Pitch Diameter = 36 / 19.8 = 1.82 inch

Transverse diametral pitch of pinion = Ptd / cos(φ) = 5 / cos(20°) = 5.25 inch

Transverse diametral pitch of gear = Ptd / cos(φ) = 5 / cos(20°) = 5.25 inch

Tangential force = 63025 × (Power / (n₁ × Pitch Diameter))

= 63025 × (10 / (1390 × 9.9))

= 33.5 lb

Therefore, the pinion tangent force is 33.5 lb (approximately).

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Answer:

Explanation:

Enforcing OSHA, Occupational Safety and Health Administration, standards is not a job for electricians, lawmakers or tax collectors. The right answer is safety inspectors.

The maximum torque that should be used is 30.84Nm.

d = diameter of the screw = 10mm

p = pitch of the screw = 1.25mm

\(\sigma_p\) = proof strength = 840MPa

\(c_t\) = torque coefficient = 0.2

Before we can calculate maximum torque with must know the preload but to calculate preload we need stress on the screw and shear area. All formula and calculation below,

Stress on the screw is,

σ = (tight)(\(\sigma_p\))

= (30%)(840)

= 252

Shear area is,

A = \(\frac{\pi}{4}(d-0.9382p)^2\)

= \(\frac{\pi}{4}(10-0.9382(1.25))^2\)

= 61.198

Preload is,

F = σA

= (252)(61.198)

= 15,421.896

Maximum torque is,

T =  \(c_t\)Fd

=(0.2)(15,421.896)(10)

= 30,843.79 Nmm

= 30.84 Nm

You question is incomplete, but most probably your full question was

An alloy steel metric 10x1.25 screw is used in a threaded hole and tightened to 30% of its proof strength of 840 MPa. determine the maximum torque that should be used if the torque coefficient 0.2?

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Answer:

b remains the same

Explanation:

voltage and amps have no connection

the electricity used to rin your clothes dryer is normally 220V 18-24A

the voltage in your car's battery is usually 12V 20-30A

see they are approximately the same amperage but very different voltage

Answer:

The one end of a hollow square bar whose side is (10+N/100)  in with (1+N/100)  in thickness is under a tensile stress 102,500 psi and the other end is connected with a U bracket using a double-pin system. Find the minimum diameter of pin is used according to shear strength. Take the factor of safety as 1.5 and σ_all=243 ksi for pin material.

Explanation:

Answer:

a) the mass flow rate of the steam is  \(\mathbf{m_1 =6.92 \ kg/s}\)

b) the exit velocity of the steam  is \(\mathbf{V_2 = 562.7 \ m/s}\)

c) the exit area of the nozzle is  \(A_2\) = 0.0015435 m²

Explanation:

Given that:

A steam with 5 MPa and 400° C enters a nozzle steadily

So;

Inlet:

\(P_1 =\) 5 MPa

\(T_1\) = 400° C

Velocity V = 80 m/s

Exit:

\(P_2 =\) 2 MPa

\(T_2\) = 300° C

From the properties of steam tables  at \(P_1 =\) 5 MPa and \(T_1\) = 400° C we obtain the following properties for enthalpy h and the speed v

\(h_1 = 3196.7 \ kJ/kg \\ \\ v_1 = 0.057838 \ m^3/kg\)

From the properties of steam tables  at \(P_2 =\) 2 MPa and \(T_1\) = 300° C we obtain the following properties for enthalpy h and the speed v

\(h_2 = 3024.2 \ kJ/kg \\ \\ v_2= 0.12551 \ m^3/kg\)

Inlet Area of the nozzle = 50 cm²

Heat lost Q = 120 kJ/s

We are to determine the following:

a) the mass flow rate of the steam.

From the system in a steady flow state;

\(m_1=m_2=m_3\)

Thus

\(m_1 =\dfrac{V_1 \times A_1}{v_1}\)

\(m_1 =\dfrac{80 \ m/s \times 50 \times 10 ^{-4} \ m^2}{0.057838 \ m^3/kg}\)

\(m_1 =\dfrac{0.4 }{0.057838 }\)

\(\mathbf{m_1 =6.92 \ kg/s}\)

b) the exit velocity of the steam.

Using Energy Balance equation:

\(\Delta E _{system} = E_{in}-E_{out}\)

In a steady flow process;

\(\Delta E _{system} = 0\)

\(E_{in} = E_{out}\)

\(m(h_1 + \dfrac{V_1^2}{2})\) \(= Q_{out} + m (h_2 + \dfrac{V_2^2}{2})\)

\(- Q_{out} = m (h_2 - h_1 + \dfrac{V_2^2-V^2_1}{2})\)

\(- 120 kJ/s = 6.92 \ kg/s (3024.2 -3196.7 + \dfrac{V_2^2- 80 m/s^2}{2}) \times (\dfrac{1 \ kJ/kg}{1000 \ m^2/s^2})\)

\(- 120 kJ/s = 6.92 \ kg/s (-172.5 + \dfrac{V_2^2- 80 m/s^2}{2}) \times (\dfrac{1 \ kJ/kg}{1000 \ m^2/s^2})\)

\(- 120 kJ/s = (-1193.7 \ kg/s + 6.92\ kg/s ( \dfrac{V_2^2- 80 m/s^2}{2}) \times (\dfrac{1 \ kJ/kg}{1000 \ m^2/s^2})\)

\(V_2^2 = 316631.29 \ m/s\)

\(V_2 = \sqrt{316631.29 \ m/s\)

\(\mathbf{V_2 = 562.7 \ m/s}\)

c) the exit area of the nozzle.

The exit of the nozzle can be determined by using the expression:

\(m = \dfrac{V_2A_2}{v_2}\)

making \(A_2\) the subject of the formula ; we have:

\(A_2 = \dfrac{ m \times v_2}{V_2}\)

\(A_2 = \dfrac{ 6.92 \times 0.12551}{562.7}\)

\(A_2\) = 0.0015435 m²

a. The Architectural Runway. An Enabler Epic is a type of Epic in Agile software development that is used to advance the "architectural runway" in order to support upcoming Business Epics.

What is an architectural runway?

The architectural runway refers to the technical infrastructure and systems that must be in place in order for a product or service to be developed and deployed successfully.

Enabler Epics focus on addressing technical debt, improving scalability and performance, and implementing new technologies or architectural patterns that will enable the team to deliver on the Business Epics that are planned for the future.

They are typically less visible and less customer-facing than Business Epics, but are no less important for the success of the project.

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Given:

Assuming the transition to turbulence for flow over a flat plate happens at a Reynolds number of 5x105, determine the following for air at 300 K and engine oil at 380 K. Assume the free stream velocity is 3 m/s.

To Find:

a. The distance from the leading edge at which the transition will occur.

b. Expressions for the momentum and thermal boundary layer thicknesses as a function of x for a laminar boundary layer

c. Which fluid has a higher heat transfer

Calculation:

The transition from the lamina to turbulent begins when the critical Reynolds

number reaches \(5\times 10^5\)

\((a). \;\text{Rex}_{cr}=5 \times 10^5\\\\\frac{\rho\;vx}{\mu}=5 \times 10^5\\\text{density of of air at}\;300K=1.16 \frac{kg}{m\cdot s}\\\text{viscosity of of air at}\;300K=1.846 \times 10^{-5} \frac{kg}{m\cdot s} \\v=3m/s\\\Rightarrow x=\frac{5\times 10^5 \times 1.846 \times 10^{-5} }{1.16 \times 3} =2.652 \;m \;\text{for air}\\(\text{similarly for engine oil at 380 K for given}\; \rho \;\text{and} \;\mu)\\\)

\((b).\; \text{For the lamina boundary layer momentum boundary layer thickness is given by}:\\\frac{\delta}{x} =\frac{5}{\sqrt{R_e}}\;\;\;\;\quad\text{for}\; R_e <5 \times 10^5\\\\\text{for thermal boundary layer}\\\delta _t=\frac{\delta}{{P_r}^{\frac{1}{3}}}\quad\quad \text{where} \;P_r=\frac{C_p\mu}{K}\\\Rightarrow \delta_t=\frac{5x}{\sqrt{R_e}{P_r}^{\frac{1}{3}}}\)\((c). \frac{\delta}{\delta_t}={P_r}^{\frac{r}{3}}\\\text{For air} \;P_r \;\text{equivalent 1 hence both momentum and heat dissipate with the same rate for oil}\; \\P_r >>1 \text{heat diffuse very slowly}\\\text{So heat transfer rate will be high for air.}\\\text{Convective heat transfer coefficient will be high for engine oil.}\)

Less than 80% of the maximum output is usually considered in tune.

What is Tune?
Tune is a platform that helps digital marketers, app marketers, and mobile growth professionals optimize their user acquisition and engagement efforts. Tune is designed to make it easier to measure, analyze, and optimize campaigns across a variety of mobile marketing channels, including search, social, and display ads. Tune offers powerful tools to track and analyze user engagement and performance, enabling marketers to make data-driven decisions to improve their campaigns. With Tune, marketers can quickly identify and act on user behavior, optimize campaigns for better performance, and maximize return on investment.

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Both technicians may be correct depending on the situation and the type of brake components being cleaned with either denatured alcohol or brake fluid.

Denatured alcohol is a common solvent used to clean brake components as it effectively removes brake dust, dirt, and grime. It is also less harmful to the environment and safer to use than other harsh solvents. However, it may not be effective in removing certain types of brake fluid or oil-based contaminants.

On the other hand, clean brake fluid can also be used to clean brake components as it is specifically designed to lubricate and protect brake parts. It may be more effective in removing brake fluid or oil-based contaminants, but it can be more expensive and may not be as readily available as denatured alcohol.

Ultimately, the choice of solvent for cleaning brake components depends on the specific situation and the type of contaminants that need to be removed. A knowledgeable technician will be able to determine the best solvent to use based on their experience and expertise.

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Technician A is correct when cleaning brake components in denatured alcohol.

Using denatured alcohol is an appropriate method for cleaning brake components, as it effectively removes dirt, grease, and contaminants without damaging the components.

On the other hand, Technician B is not correct, as cleaning brake components in clean brake fluid is not recommended because it may not effectively remove all contaminants and can cause issues with the braking system.

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Answer:

98 x 100=9,00

Explanation:

Answer:

The voltages of all nodes are, IE = 4.65 mA, IB =46.039μA,  IC=4.6039 mA, VB = 10v, VE =10.7, Vc =4.6039 v

Explanation:

Solution

Given that:

V+ = 20v

Re = 2kΩ

Rc = 1kΩ

Now we will amke use of the method KVL in the loop.

= - Ve + IE . Re + VEB + VB = 0

Thus

IE = V+ -VEB -VB/Re

Which gives us the following:

IE = 20-0.7 - 10/2k

= 9.3/2k

so, IE = 4.65 mA

IB = IE/β +1 = 4.65 m /101

Thus,

IB = 0.046039 mA

IB = 46.039μA

IC =βIB

Now,

IC = 100 * 0.046039

IC is 4.6039 mA

Now,

VB = 10v

VE = VB + VEB

= 10 +0.7 = 10.7 v

So,

Vc =Ic . Rc = 4.6039 * 1k

=4.6039 v

Finally, this is the table summary from calculations carried out.

Summary Table

Parameters          IE       IC           IB            VE       VB         Vc

Unit                     mA     mA          μA            V           V          V

Value                  4.65    4.6039   46.039    10.7      10     4.6039

The given exercise statement is true. MLA stands for Modern Language Association, and the Modern Language Association is responsible for developing the MLA writing style guidelines.

This particular style is used primarily in the humanities field. MLA documentation style is used to provide proper citations to the works and ideas of others.

MLA documentation is used in research papers and essays to indicate the source of a quoted or paraphrased text. MLA documentation provides accurate information about the author, the title, the date of publication, and the publisher.

The rules of MLA documentation are contained in the MLA Handbook for Writers of Research Papers and The Bedford Handbook.

The Bedford Handbook is the preferred handbook for many instructors who use the MLA documentation style.

The given exercise statement is true.

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The conflict may arise due to task interdependence.

The conflict may arise due to task interdependence.Stephen works with a group of engineers and is responsible for pricing out parts listed on the drawings for a new product. He is anxious to get the drawings so he can start his work. Conflict may arise due to Task Interdependence.Task interdependence refers to the way that different tasks or work units in an organization rely on one another. In organizations, some work units or teams depend on one another in order to complete their own work tasks. When work units depend on one another for the completion of their work, task interdependence exists.As per the given scenario, Stephen is working with a group of engineers and is responsible for pricing out parts listed on the drawings for a new product. Here, he needs to be completely dependent on the other engineers to get the drawings so he can start his work. If there is any delay or the other engineers do not deliver their part on time, then conflict can arise.

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It is to be noted that all UHRS platforms are optimized for the popular kinds of internet browser applications.

The Universal Human Relevance System (UHRS) is a crowdsourcing platform that allows for data labeling for a variety of AI application situations.

Vendor partners link people referred to as "judges" to offer data labeling at scale for us. All UHRS judges are bound by an NDA, ensuring that data is kept protected.

A browser is a software tool that allows you to see and interact with all of the knowledgeon the World Wide Web. Web sites, movies, and photos are all examples of this.

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Before joining a fitting and pipe using socket fusion, it is important to ensure that both the fitting and pipe are clean and free from any debris or contaminants. Additionally, the correct size fitting and pipe must be used to ensure a proper fit.

Socket fusion is a method of joining plastic pipes and fittings together by heating the material and then pressing the heated ends together to form a strong bond. Before the socket fusion process begins, it is important to prepare both the fitting and pipe by ensuring they are clean and free from any debris or contaminants.

This can be achieved by using a specialized cleaning tool or wiping the surfaces with a clean cloth. Additionally, it is crucial to use the correct size fitting and pipe to ensure a proper fit and prevent any leaks or issues in the future. Proper preparation of the materials is crucial to ensuring a successful socket fusion joint.

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The action that inspire Ms. Shotwell is that Her mom took her to a trip to look at the  Society of Women Engineers event, and she was said to have quickly fall in love with a mechanical engineer who was a speaker in the event.

The LES is mad up to separate the spacecraft from the Falcon 9 rocket and  move the crew away to safety in case any event of any emergency.

SpaceX was said to be successful because:

Note therefore, that  the action that inspire Ms. Shotwell is that Her mom took her to a trip to look at the  Society of Women Engineers event, and she was said to have quickly fall in love with a mechanical engineer who was a speaker in the event.

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The correct answer is a) Here is a diagram of the milling circuit with labels: The product from the SAG mill is fed to the two ball mills in parallel, with the product from the ball mills being combined and classified in cyclones. The underflow from the cyclones is recycled, and the overflow goes to the flotation circuit.

To calculate the mass rate of each size fraction in each stream, we can start with the total feed rate of 1,500 t/hr. Since 25% of the feed is below 75 microns, that means 75% of the feed is above 75 microns. Of that 75%, 50% will be broken down in the SAG mill to below 75 microns, while the remaining 50% will be broken down in the two ball mills in parallel. Therefore: Mass rate of particles above 75 microns in feed = 1,500 x 0.75 = 1,125 t/hr Mass rate of particles below 75 microns in feed = 1,500 x 0.25 = 375 t/hr Mass rate of particles above 75 microns in SAG mill product = 1,125 x 0.5 = 562.5 t/hr Mass rate of particles below 75 microns in SAG mill product = 1,125 x 0.5 + 375 = 937.5 t/hr Mass rate of particles above 75 microns in each ball mill product = 562.5 / 2 = 281.25 t/hr Mass rate of particles below 75 microns in each ball mill product = 375 / 2 = 187.5 t/hr Mass rate of particles above 75 microns in combined ball mill product = 562.5 t/hr Mass rate of particles below 75 microns in combined ball mill product = 375 t/hr + 187.5 t/hr = 562.5 t/hr Mass rate of particles above 75 microns in cyclone overflow = 562.5 t/hr x 0.95 = 534.38 t/hr (assuming a 5% bypass) Mass rate of particles below 75 microns in cyclone overflow = 562.5 t/hr x 0.05 + 375 t/hr x 0.95 = 393.75 t/hr (assuming a 5% bypass) Mass rate of particles above 75 microns in cyclone underflow/recycle = 562.5 t/hr x 0.05 = 28.13 t/hr Mass rate of particles below 75 microns in cyclone underflow/recycle = 375 t/hr x 0.05 + 187.5 t/hr = 205.63 t/hr To calculate the feed rate to each ball mill, we can use the mass rate of particles below 75 microns in the combined ball mill product, which is 562.5 t/hr. Since there are two ball mills in parallel, the feed rate to each ball mill will be: Feed rate to each ball mill = 562.5 t/hr / 2 = 281.25 t/hr Finally, to calculate the percentage passing 75 microns in the circuit product.

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Answer:

Conductors in Parallel is covered in 310.10(H). Often when working with higher ampacities, we find it to be cumbersome and expensive to keep increasing the size of the wire and conduit. The solution is often to use multiple runs that are connected to a common location on each end. Notice in the 2011 edition of the code that much of this section is highlighted gray, indicating new or revised text. The change here was that the previous code stated that you were permitted to parallel conductors 1/0 AWG and larger; however, it didn’t specifically prohibit you from paralleling smaller conductors, which was the intent and the way it was enforced in all my years of enforcement. However, that’s not what the actual language said, and ambiguous language cancause enforcement issues; therefore, in the 2011 code it was made clear that you are only allowed to parallel conductors 1/0 AWG and larger.

Answer:

just type it on a computer or a laptop

Whith regard to the life cycle assessment (LCA), the option that identifies the most likely outcome in the following scenario is: "the company will redesign the engine to lose less heat.

In this case, the most likely conclusion is that the manufacturer will alter the engine to waste less heat. This is because the life cycle assessment discovered that too much heat was lost via the engine, necessitating the consumption of huge amounts of gasoline.

Redesigning the engine to lose less heat might address this issue while also potentially resulting in more efficient fuel usage.

Conducting an impact analysis or broadening the scope of the study would not directly address the issue of engine heat loss, and developing a biodiesel engine would be a different approach to addressing the issue of fuel consumption rather than heat loss.

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Answer:

Because the shunt winding consist of a large number of turns,

Explanation:

It is nearly impossible to obtain satisfactory performance from a shunt motor connected to an ac power source because the shunt winding consist of a large number of turns, due to the high number of turns that the DC shunt motor has it develops a high impedance when connected to an ac power source. and due  to this high impedance the amount of current that flows through the field will be very low making it nearly impossible for the shunt motor to operate properly