The amount of money raised for 75 attendees will be $1875. The correct option is B.
What is an expression?The mathematical expression is the combination of numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.
Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also be used to denote the logical syntax's operation order and other properties.
Given that the money raised for 12 attendees is $300. The money raised for 75 attendees will be calculated as below:-
12 attendees = $300
1 attendees = $300 / 12
75 attendees = $300 x 75 / 12
75 attendees = $1875
Therefore, the amount of money raised for 75 attendees will be $1875. The correct option is B.
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Dontina is ordering uniforms for her employees. The company Dontina is ordering from charges $18 per uniform and a shipping fee
of 57
Based on this information, which function can be used to represent the relationship between the total cost, c, and the number of
uniforms Dontina orders, n?
c= 7n + 18
c=7n - 18
c=18n - 7
c = 18 + 7
Answer: D. 18 + 7
Step-by-step explanation:
If we get 18$ and want to find the TOTAL cost it would be the last one
.
The linear function that represents the relationship is:
\(c = 18n + 7\)
A linear function is modeled by:
\(y(n) = an + b\)
In which:
a is the slope, which is the rate of change per unit n.b is the y-intercept, which is the "fixed" value.In this problem:
Charge of $18 per uniform, hence \(a = 18\).Shipping fee of $7, hence \(b = 7\)Thus, the relationship is modeled by:
\(c = 18n + 7\)
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is the equation 2x+y=4 and 2x^2+y=6 linear.. if so, how do i graph them?
Answer:
No, but you can graph them by converting to mx+b form
Step-by-step explanation:
The procedure for solving simultaneous linear equations now called Gaussian elimination appears in the ancient Chinese mathematical text Chapter Eight: Rectangular Arrays of The Nine Chapters on the Mathematical Art. Its use is illustrated in eighteen problems, with two to five equations.[4]
Systems of linear equations arose in Europe with the introduction in 1637 by René Descartes of coordinates in geometry. In fact, in this new geometry, now called Cartesian geometry, lines and planes are represented by linear equations, and computing their intersections amounts to solving systems of linear equations.
The first systematic methods for solving linear systems used determinants, first considered by Leibniz in 1693. In 1750, Gabriel Cramer used them for giving explicit solutions of linear systems, now called Cramer's rule. Later, Gauss further described the method of elimination, which was initially listed as an advancement in geodesy.[5]
In 1844 Hermann Grassmann published his "Theory of Extension" which included foundational new topics of what is today called linear algebra. In 1848, James Joseph Sylvester introduced the term matrix, which is Latin for womb.
Linear algebra grew with ideas noted in the complex plane. For instance, two numbers w and z in {\displaystyle \mathbb {C} }\mathbb {C} have a difference w – z, and the line segments {\displaystyle {\overline {wz}}}{\displaystyle {\overline {wz}}} and {\displaystyle {\overline {0(w-z)}}}{\displaystyle {\overline {0(w-z)}}} are of the same length and direction. The segments are equipollent. The four-dimensional system {\displaystyle \mathbb {H} }\mathbb {H} of quaternions was started in 1843. The term vector was introduced as v = x i + y j + z k representing a point in space. The quaternion difference p – q also produces a segment equipollent to {\displaystyle {\overline {pq}}.}{\displaystyle {\overline {pq}}.} Other hypercomplex number systems also used the idea of a linear space with a basis.
Arthur Cayley introduced matrix multiplication and the inverse matrix in 1856, making possible the general linear group. The mechanism of group representation became available for describing complex and hypercomplex numbers. Crucially, Cayley used a single letter to denote a matrix, thus treating a matrix as an aggregate object. He also realized the connection between matrices and determinants, and wrote "There would be many things to say about this theory of matrices which should, it seems to me, precede the theory of determinants".[5]
Benjamin Peirce published his Linear Associative Algebra (1872), and his son Charles Sanders Peirce extended the work later.[6]
The telegraph required an explanatory system, and the 1873 publication of A Treatise on Electricity and Magnetism instituted a field theory of forces and required differential geometry for expression. Linear algebra is flat differential geometry and serves in tangent spaces to manifolds. Electromagnetic symmetries of spacetime are expressed by the Lorentz transformations, and much of the history of linear algebra is the history of Lorentz transformations.
The first modern and more precise definition of a vector space was introduced by Peano in 1888;[5] by 1900, a theory of linear transformations of finite-dimensional vector spaces had emerged. Linear algebra took its modern form in the first half of the twentieth century, when many ideas and methods of previous centuries were generalized as abstract algebra. The development of computers led to increased research in efficient algorithms for Gaussian elimination and matrix decompositions, and linear algebra became an essential tool for modelling and simulations.[5]
Vector spaces
Main article: Vector space
Until the 19th century, linear algebra was introduced through systems of linear equations and matrices. In modern mathematics, the presentation through vector spaces is generally preferred, since it is more synthetic, more general (not limited to the finite-dimensional case), and conceptually simpler, although more abstract.
A vector space over a field F (often the field of the real numbers) is a set V equipped with two binary operations satisfying the following axioms. Elements of V are called vectors, and elements of F are called scalars. The first operation, vector addition, takes any two vectors v and w and outputs a third vector v + w. The second operation, scalar multiplication, takes any scalar a and any vector v and outputs a new vector av. The axioms that addition and scalar multiplication must satisfy are the following. (In the list below, u, v and w are arbitrary elements of V, and a and b are arbitrary scalars in the field F.)[7]
9. Which unit of measure would be appropriate for the volume of a cube with sides of 2 meters.
Answer:
The unit of measure appropriate is cubic metre or cubic meter (m³)
Step-by-step Explanation:
we know that
The volume of a cube is equal to
V = b^3
where b is the length side of the cube
In this problem we have
b = 2m
substitute in the formula of volume
V = 2^3
V = 8 m^3
therefore
The unit of measure appropriate is cubic metre (m³)
The blank is the number that tell how many times a base number is used as a factor
Answer:
exponent
Step-by-step explanation:
a summary description of a given variable in a survey sample is called a: a. statistic. b. parameter. c. confidence interval. d. confidence level. e. variable.
A summary description of a given variable in a survey sample is called a statistic.
What is statistic?
Any quantity calculated from sample values and taken into consideration for statistical purposes is known as a statistic (singular) or sample statistic. A population parameter estimate, a sample description, or a hypothesis evaluation are examples of statistical aims. A statistic is the average (or mean) of sample values. Both the function and the result of the function on a particular sample are referred to as statistics. A statistic may be referred to by a term that indicates its purpose when it is being utilized for that reason only.
Therefore, Option a is correct answer, a summary description of a given variable in a survey sample is called a statistic.
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Which of the following is a like radical to 3x5?
5y
3(5x)
y5
Answer:
y\(\sqrt{5}\)
Step-by-step explanation:
Like radicals are radicals that have the same radical (the number into the square root) and the same radicand (the number above the root)
Here, only the last expression \(\sqrt{5}\) can be chosen.
Which is NOT a function?
A. y = x + 3^2
B. x + y = 3^2
C. x + 3 = y^2
D. y = x^2 - 3
Answer:
All are functions
Step-by-step explanation:
A. y = x + 9 A graph of a line. There are no x-values that are the same on the graph. The graph passes the vertical line test.
B. x + y = 9
y = -x + 9 A graph of a line. There are no x values that are the same number on the graph. The graph passes the vertical line test
C. x + 3 = y²
\(\sqrt{x + 3} = y\) The graph passes the vertical line test. On the graph, there are no x-values that are the same number.
D. y = x² - 3 The graph is a parabola. The graph passes the vertical line test (there are no x- values are the same number on the graph).
the amounts of time per workout an athlete uses a stairclimber are normally distributed, with a mean of 22 minutes and a standard deviation of 6 minutes. find the probability that a randomly selected athlete uses a stairclimber for (a) less than 18 minutes, (b) between 22 and 31 minutes, and (c) more than 30 minutes.
The probability that a randomly selected athlete uses a stair climber for,
(a) P(X < 18) = 0.2514
(b) P(22 < X < 31) = 0.4332
(c) P(X > 30) = 0.0918
Let X be the amount of time an athlete uses a stair climber. Then, X ~ N(22, 6^2) represents a normal distribution with mean 22 and standard deviation 6.
(a) To find the probability that a randomly selected athlete uses a stair climber for less than 18 minutes, we need to calculate P(X < 18).
Z-score for 18 minutes = (18 - 22) / 6 = -0.67
Using a standard normal table or calculator, we find that P(Z < -0.67) = 0.2514.
Therefore, P(X < 18) = P(Z < -0.67) = 0.2514.
(b) To find the probability that a randomly selected athlete uses a stair climber for between 22 and 31 minutes, we need to calculate P(22 < X < 31).
Z-score for 22 minutes = (22 - 22) / 6 = 0
Z-score for 31 minutes = (31 - 22) / 6 = 1.5
Using a standard normal table or calculator, we find that P(0 < Z < 1.5) = 0.4332.
Therefore, P(22 < X < 31) = P(0 < Z < 1.5) = 0.4332.
(c) To find the probability that a randomly selected athlete uses a stair climber for more than 30 minutes, we need to calculate P(X > 30).
Z-score for 30 minutes = (30 - 22) / 6 = 1.33
Using a standard normal table or calculator, we find that P(Z > 1.33) = 0.0918.
Therefore, P(X > 30) = P(Z > 1.33) = 0.0918.
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Marty is spending money at the average rate of $3 per day. After 14 days he has $68 left. The amount left depends on the number of d days that have passed. A. Write an equation for the situation.B. Find the a amount of money he began with.C. How much money does Marty have after 9 days?
Given:
Amount Marty spent per day = $3
Number of days = 14
Remaining amount = $68
Since the amount left depends on the number
3. Determine the intervals where f is concave up/down and find the inflection point(s). (a) f(x) = x2 – 2x – 8 = — (b) f(x) = -x + 6x2 – 5 (c) f(x) = x(x – 4)3
To determine the intervals where f is concave up/down and find the inflection point(s), we need to follow these steps:
1. Find the second derivative of f(x).
2. Solve for the critical points by setting the second derivative equal to 0.
3. Analyze the concavity of the function using the critical points.
Let's apply these steps to each function:
(a) f(x) = x^2 - 2x - 8
1. First derivative: f'(x) = 2x - 2
Second derivative: f''(x) = 2
Since the second derivative is a constant (2) and is positive, the function is concave up for all values of x. There is no inflection point.
(b) f(x) = -x + 6x^2 - 5
1. First derivative: f'(x) = -1 + 12x
Second derivative: f''(x) = 12
Similarly to the first function, the second derivative is a constant (12) and is positive, so the function is concave up for all values of x. There is no inflection point.
(c) f(x) = x(x - 4)^3
1. First derivative: f'(x) = (x - 4)^3 + 3x(x - 4)^2
Second derivative: f''(x) = 6(x - 4)(x - 2)
2. Set f''(x) = 0 to find critical points: 6(x - 4)(x - 2) = 0 => x = 2, 4
3. Analyze concavity:
- For x < 2, f''(x) > 0, so f is concave up.
- For 2 < x < 4, f''(x) < 0, so f is concave down.
- For x > 4, f''(x) > 0, so f is concave up.
Inflection points: x = 2, 4
In summary:
(a) f(x) is concave up for all x, with no inflection points.
(b) f(x) is concave up for all x, with no inflection points.
(c) f(x) is concave up for x < 2 and x > 4, and concave down for 2 < x < 4, with inflection points at x = 2 and x = 4.
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Given that limx→2f(x)=−5 and limx→2g(x)=2, find the following limit.
limx→2 2-f(x)/x+g(x)
The limit of (2 - f(x))/(x + g(x)) as x approaches 2 is 7/4. To find the limit of (2 - f(x))/(x + g(x)) as x approaches 2, we substitute the given limit values into the expression and evaluate it.
lim(x→2) f(x) = -5
lim(x→2) g(x) = 2
We substitute these values into the expression:
lim(x→2) (2 - f(x))/(x + g(x))
Plugging in the limit values:
= (2 - (-5))/(2 + 2)
= (2 + 5)/(4)
= 7/4
Therefore, the limit of (2 - f(x))/(x + g(x)) as x approaches 2 is 7/4.
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a machine that is programmed to package 1.60 pounds of cereal is being tested for its accuracy in a sample of 40 cereal boxes, the sample mean filling weight is calculated as 1.62 pounds. the population standard deviation is known to be 0.06 pounds. find the 95% confidence interval for the mean.
The 95% confidence interval for the mean is (1.6048, 1.6352).Hence, option (d) is the correct answer.
As given, a machine that is programmed to package 1.60 pounds of cereal is being tested for its accuracy in a sample of 40 cereal boxes, the sample mean filling weight is calculated as 1.62 pounds. The population standard deviation is known to be 0.06 pounds. We are required to find the 95% confidence interval for the mean. Here are the steps to solve this problem:
The formula to find the confidence interval is as follows;
Lower limit = x - zα/2 (σ/√n)
Upper limit = x + zα/2 (σ/√n)
Where,
x= sample mean
zα/2 = z-value of the level of significance
σ = population standard deviation
n = sample size
We are given;
x = 1.62 pounds
σ = 0.06 pounds
n = 40
We need to find the z-value of the level of significance, which can be found using the z-table or by using the calculator.Using the z-table, we get the z-value at 95% confidence interval as zα/2 = 1.96
Substituting the values, we get
Lower limit = 1.62 - 1.96(0.06/√40)
Upper limit = 1.62 + 1.96(0.06/√40)
Lower limit = 1.6048, Upper limit = 1.6352
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Sketch the graph of a function f having the following properties: Label points of inflection, if any, on the graph.
The domain of f (x) is (−[infinity], 5) ∪ (5, [infinity]) and f is continuous on its domain. f(−6)=−3;f(2)=4. x = 5 is a vertical asymptote. lim f(x)=−[infinity]and lim f(x)=0 x→−[infinity] x→[infinity] f′(2) = 0; f′(x) > 0 on (−[infinity],2) and on (5,[infinity]); f′(x) < 0 on (2,5) f′′(x) < 0 on (−[infinity],3) and on (5,[infinity]);f′′(x) > 0 on (3,5)
The function f has a vertical asymptote at x = 5 and is continuous on its domain of (-∞, 5) ∪ (5, ∞). It has a point of inflection at x = 3 and is increasing on (-∞, 2) and (5, ∞), while decreasing on (2, 5).
The given information provides us with various characteristics of the function f. We start by observing that the function is not defined at x = 5, as it has a vertical asymptote there. The limits of f as x approaches -∞ and ∞ indicate that the function decreases to -∞ as x approaches -∞ and approaches 0 as x approaches ∞.
The first derivative of f provides information about the function's increasing and decreasing behavior. We know that f′(x) > 0 on (-∞, 2) and (5, ∞), which means that f is increasing on these intervals. On the interval (2, 5), f′(x) < 0, which implies that f is decreasing on this interval.
The second derivative of f tells us about the concavity of the graph. We know that f′′(x) < 0 on (-∞, 3) and (5, ∞), which means that the graph is concave down on these intervals. On the interval (3, 5), f′′(x) > 0, which implies that the graph is concave up on this interval. Therefore, we can conclude that f has a point of inflection at x = 3.
Using the given information, we can sketch a rough graph of the function f. We start by drawing a vertical asymptote at x = 5 and marking the point (2, 4) and (-6, -3) on the graph. We can then draw the function increasing on (-∞, 2) and (5, ∞), and decreasing on (2, 5). The point of inflection at x = 3 can be marked on the graph. Finally, we can draw the graph concave down on (-∞, 3) and (5, ∞), and concave up on (3, 5).
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(7x²+2x-1)-(2x²-5x+3)
Answer:
5x²+7x-4
Step-by-step explanation:
Given: (7x²+2x-1)-(2x²-5x+3)
Distribute: 7x²+2x-1-2x²+5x-3
Rearrange: 7x²-2x²+5x+2x-3-1
Combine like terms: 5x²+7x-4
Your final answer is thus 5x²+7x-4
Can someone please tell me what to put in question number 3 plz?
Answer:
It's 70, big man
Step-by-step explanation:
It's a forth of 280
Which expression could represent this phrase?
three times the difference of 8 and a number
Answer:
3(8-x) I think
Step-by-step explanation:
Answer:
3(8-x)
Step-by-step explanation:
PLEASE HELP
The slope of the line that represents the data Nicholas collected is -63, and the y-intercept is 825. Explain what these represent in the context of the situation. Remember that x is the number of days, and y is the number of canned goods. explain the answer
Answer:
sorry i coldent find the anser
Step-by-step explanation:
ello
+v+
Answer:
The slope indicates that the soup kitchen uses 63 cans per day. The y-intercept shows that there were initially 825 cans at the soup kitchen.
Step-by-step explanation:
(a) How many ways are there to pick a sequence of two different letters of the alphabet that appear in the word CRAB? In STATISTICS?
(b) How many ways are there to pick first a vowel and then a consonant from CRAB? From STATISTICS?
There are 12 ways to pick a sequence of two different letters of the alphabet that appear in the word CRAB? In STATISTICS?
and There are 6 ways to pick first a vowel and then a consonant from CRAB? From STATISTICS?
A) There are 12 ways to pick a sequence of two different letters of the alphabet that appear in the word CRAB, and 20 ways to pick a sequence of two different letters of the alphabet that appear in the word STATISTICS.
B) There are 6 ways to pick first a vowel and then a consonant from CRAB, and 10 ways to pick first a vowel and then a consonant from STATISTICS.
Sequence and series are the basic topics in Arithmetic. An itemized collection of elements in which repetitions of any sort are allowed is known as a sequence, whereas a series is the sum of all elements
The fundamentals could be better understood by solving problems based on the formulas. They are very similar to sets but the primary difference is that in a sequence, individual terms can occur repeatedly in various positions.
The length of a sequence is equal to the number of terms and it can be either finite or infinite.
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A cola-dispensing machine is set to dispense 8 ounces of cola per cup, with a standard deviation of 1.0 ounce. The manufacturer of the machine would like to set the control limit in such a way that, for samples of 47, 5% of the sample means will be greater than the upper control limit, and 5% of the sample means will be less than the lower control limit.
If the population mean shifts to 7.8, what is the probability that the change will be detected? (Round your intermediate calculations to 2 decimal places and final answer to 4 decimal places.)
If the population mean shifts to 8.6, what is the probability that the change will be detected? (Round your intermediate calculations to 2 decimal places and final answer to 4 decimal places.)
1. When the population mean shifts to 7.8, the probability of detecting the change is approximately 0.0495 (or 4.95%).
2. The probability of detecting the change is 0.0495 or 4.95%.
To solve this problem, we'll use the concept of control limits and the sampling distribution of the sample means.
When the population mean shifts to 7.8: First, let's calculate the standard deviation of the sampling distribution, also known as the standard error (SE). The formula for SE is given by SE = σ / sqrt(n), where σ is the standard deviation of the population (1.0 ounce) and n is the sample size (47).
SE = 1.0 / sqrt(47) ≈ 0.145
Next, we need to determine the z-score corresponding to the lower and upper tails of the sampling distribution that capture 5% each. Since the total probability in both tails is 10%, each tail will have a probability of 5%. We can find the z-scores using a standard normal distribution table or calculator.
The z-score corresponding to the lower tail of 5% is approximately -1.645.
The z-score corresponding to the upper tail of 5% is approximately 1.645.
Now, let's calculate the lower and upper control limits:
Lower Control Limit (LCL) = Population Mean - (z * SE)
Upper Control Limit (UCL) = Population Mean + (z * SE)
LCL = 7.8 - (-1.645 * 0.145) ≈ 8.026
UCL = 7.8 + (1.645 * 0.145) ≈ 9.574
To find the probability of detecting the change, we need to calculate the area under the sampling distribution curve that falls beyond the control limits. In this case, we're interested in the area above the upper control limit.
Since the distribution is assumed to be normal, we can use the standard normal distribution's cumulative distribution function (CDF) to calculate this probability.
Probability of detecting the change = 1 - CDF(z-score for UCL)
Using the z-score for the upper control limit (UCL), we can calculate the probability.
Probability of detecting the change ≈ 1 - CDF(1.645) ≈ 0.0495
Therefore, when the population mean shifts to 7.8, the probability of detecting the change is approximately 0.0495 (or 4.95%).
When the population mean shifts to 8.6: We'll follow the same steps as before.
SE = 1.0 / sqrt(47) ≈ 0.145
The z-score corresponding to the lower tail of 5% is still approximately -1.645.
The z-score corresponding to the upper tail of 5% is still approximately 1.645.
LCL = 8.6 - (-1.645 * 0.145) ≈ 8.926
UCL = 8.6 + (1.645 * 0.145) ≈ 10.274
Probability of detecting the change = 1 - CDF(z-score for UCL)
Probability of detecting the change ≈ 1 - CDF(1.645) ≈ 0.0495
Therefore, when the population mean shifts to 8.6, the probability of detecting the change is also approximately 0.0495 (or 4.95%).
In both cases, the probability of detecting the change is 0.0495 or 4.95%.
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IQ scores are normally distributed with a
mean of 100 and a standard deviation of
15. What percentage of people have an IQ
score less than 117, to the nearest tenth?
Answer: To find the percentage of people with an IQ score less than 117, we need to calculate the z-score first. The z-score measures how many standard deviations an individual score is from the mean in a normal distribution.
The z-score formula is given by:
z = (x - μ) / σ
Where:
x = IQ score (117 in this case)μ = mean IQ score (100)σ = standard deviation (15)
Let's calculate the z-score:
z = (117 - 100) / 15z = 17 / 15z ≈ 1.1333
Now, we need to find the percentage of people with a z-score less than 1.1333. We can look up this value in the standard normal distribution table (also known as the Z-table) or use statistical software/tools.
Using the Z-table, we find that the percentage of people with a z-score less than 1.1333 is approximately 0.8708, or 87.08% (rounded to the nearest hundredth).
Therefore, approximately 87.1% of people have an IQ score less than 117.
What is the square root of 18 plus the square root of 2? And is it rational or irrational?
pls help :( :) i’m a little lost
Answer:
B
Step-by-step explanation:
On a graph you go rise over run (or Y divided by X) which in this equation is 1 divided by 2 which equals 1/2. You also need to look at what number is being crossed on the y axis, which in this case is 1. Slope intercept form is y=mx+b with m being the slope (1/2) and b being the y intercept (1)
Answer:
B. y = 1/2x + 1
Step-by-step explanation:
I went ahead and graphed each of the answer options for you and when I graphed for B it gave me:
If the frequency of a radio station is 88. 1 MHz (8. 81 × 107 Hz), what is the wavelength of the wave used by this radio station for its broadcast? The answer should have three significant figures. Meters.
To calculate the wavelength of a radio wave, we can use the formula: wavelength = speed of light / frequency the wavelength of the radio wave used by this radio station is approximately 3.41 meters.
The speed of light is a constant value, approximately 3.00 × 10^8 meters per second.
Given that the frequency of the radio station is 8.81 × 10^7 Hz, we can substitute these values into the formula:
wavelength = (3.00 × 10^8 m/s) / (8.81 × 10^7 Hz)
Performing the calculation, the wavelength of the radio wave used by this radio station is approximately 3.41 meters.Therefore, the wavelength of the wave used by this radio station for its broadcast is approximately 3.41 meters, with three significant figures.
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What type of polynomial is this
Answer:
trinomial..............
Park visitors
100
150
200
250
300
350
1) What was the range of the number of park visitors each day?
visitors
Submit
Answer:
The answer is 225
Step-by-step explanation:
Because you first need to subtract 350-125 and you get 225
What is the mode, mean, median for these numbers?
{18,18,63,63,84}
Answer:
Mean= the average of the number set= 18+18+63+63+84=246/5=49.2
Median- the number in the middle of the set= 63
Mode- the number(s) that repeat=1 8, 63
Range- the amount between the highest and lowest numbers= 84-18=66
Step-by-step explanation:
The mode, mean, and median of the data will be 18 or 63, 49.2, and 63, respectively.
What are statistics?Statistics is the study of collection, analysis, interpretation, and presentation of data or discipline to collect and summarise the data.
The data set is given below.
18, 18, 63, 63, 84
The mode of the data is given as,
Mode = Frequency of the repeated number
Mode = 18 and 63
The mean of the data is given as,
Mean = (Sum of observations) / (Number of observations)
Mean = (18 + 18 + 63 + 63 + 84) / 5
Mean = 246 / 5
Mean = 49.2
The median of the data is given as,
Median = (n + 1)th / 2
Median = (5 + 1)th / 2
Median = 6th / 2
Median = 3th
Median = 63
The mode, mean, and median of the data will be 18 or 63, 49.2, and 63, respectively.
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2. Describe the graph of the line y = 15. .
Answer:
it is a horizontal line resting at 15 on the y axis
Step-by-step explanation:
because there is no x on the left side of the equation, it must be flat. it is 15, so that is where it lies
The graph of the function y=15 is the horizontal line resting at 15 on the y-axis
What is a graph?A graph is the representation of the data on the vertical and horizontal coordinates so we can see the trend of the data.
The graph of the function y=15 is the horizontal line resting at 15 on the y-axis because there is no x on the left side of the equation, it must be flat. it is 15, so that is where it lies.
Therefore the graph of the function y=15 is the horizontal line resting at 15 on the y-axis. The graph is attached with the answer below.
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a number increased by 7 given 20
Answer:
13
Step-by-step explanation:
True or false? (-x)^4 = -x^4 Explain your answer.
Answer:
true, theres nothing inside the parenthesis meaning that you remove it as a first step
Step-by-step explanation:
Every other weekend, Bronwyn’s brother Daniel mows the lawn. He can mow 15,000 ft2 in 3/4 fourths hour. Who mows the lawn in less time? Explain. PLEASE HELP ME
The person who mows the lawn in less time is given as follows:
Daniel.
How to decide who mows the lawn in less time?To obtain who mows the lawn in less time, we calculate the hourly rates for each person, applying the proportion, which is the division of the amount of area mowed by the time needed.
Daniel can mow 15,000 ft³ in 3/4 = 0.75 hours, hence his hourly rate is calculated as follows:
Daniel hourly rate = 15000/0.75 = 15000 x 4/3 = 20,000 ft² per hour.
Bronwyn can mow 12,000 ft² in hour, hence her rate is of:
12,000 ft² per hour.
20,000 > 12,000, hence Daniel can mow the law in less time, as he has a higher rate.
Missing InformationThe missing sentence is of:
"Bronwyn can mow 12,000 ft² in hour".
More can be learned about proportions at https://brainly.com/question/24372153
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