The specific work and reaction are given by Ws= (Vx^2/2) [(tan a2)-(tan a3)] and R= 1- [(Vx^2/V1^2) [(cos a2)/(cos a3)]].
Where Vx is the airflow leaving the rotor of an axial flow turbine, a2 is the inlet flow angle to the rotor and a3 is the angle of the flow leaving the rotor. The formula for specific work in terms of the flow angles a2 and a3, and the axial velocity Vx of the flow is Ws = (Vx^2/2) [(tan a2)-(tan a3)]. The formula for the reaction in terms of flow angles a2, a3, axial velocity Vx, and velocity V1 of the incoming fluid is R= 1- [(Vx^2/V1^2) [(cos a2)/(cos a3)]].Given that Vx = 140 m/s and a2 = 60°. The axial velocity is constant and equal to the blade speed. So, a3 = 0°.Thus, the specific work is given by Ws = (Vx^2/2) [(tan a2)-(tan a3)] = (140^2/2) [(tan 60°)-(tan 0°)] = (9800/2) [1.732] = 8474 J/kg The reaction is given by R = 1- [(Vx^2/V1^2) [(cos a2)/(cos a3)]] = 1- [(Vx^2/V1^2) [(cos 60°)/(cos 0°)]] = 1- [(140^2/V1^2) (0.5/1)] = 1- [0.5 (19600/V1^2)] = 1- 9800/V1^2
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A 1.5 kg ball is kicked with an initial velocity of 26 m/s at an angle of 30 degrees above the horizontal. How far did the ball go before returning to the ground? Answer in meters.
ANSWER ASAP!!! I AM GIVING EXTRA POINTS!!!! PLEASSEEE HELP!!!
The maximum height travelled by the ball before returning to the ground is 8.62 m.
What is the maximum height travelled by the ball?The maximum height travelled by the ball before returning to the ground is calculated by applying the following kinematic equation as shown below.
H = (u²sin²θ) / 2g
where;
u is the initial velocity of the ballθ is the angle of projection of the ballg is acceleration due to gravityH = (26² (sin 30)²) / (2 x 9.8)
H = 8.62 m
Thus, the maximum height travelled by a projectile depends on the initial velocity and angle of projection.
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A football player threw a football with a velocity of (3.0 m/s x + 5.0m/s y). How far did it travel horizontally?
The horizontal distance travelled by the football is 3.1 m.
What is the angle of projection of the ball?
The angle of projection of the football is calculated as follows;
tan ( θ ) = Vy / Vx
where;
Vy is the velocity of the ball in the vertical directionVx is the velocity of the ball in the horizontal directiontan ( θ ) = 5 / 3
tan ( θ ) = 1.667
θ = arc tan (1.667)
θ = 59⁰
The resultant velocity of the ball is calculated as follows;
v = √ (Vx² + Vy²)
v = √ (3² + 5²)
v = 5.83 m/s
The horizontal distance travelled by the football is calculated as follows;
x = v² sin(2θ) /g
where;
v is the resultant velocityg is acceleration due to gravityθ is the angle of projection of the ballx = [ (5.83)² sin(2 x 59) /9.8 ]
x = 3.1 m
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For the electrical system shown in the circuit below: L₂ oo R L₁ Moo V, V, H(s) = - IF R=270, find the value of the inductance, L1 (in Henry) so that the transfer function is 0.1s $+1.5
The value of the inductance, L1 is 255 Henry.
The transfer function of a circuit is a function of complex frequency, expressed as a ratio of two complex polynomial functions of the same frequency. It is generally represented as H(s).
Given,
Transfer Function, H(s) = -IF R = 270Now, 0.1s + 1.5 = -IF= -1.5/0.1=-15As per the question, we have to find out the value of the inductance, L1(in Henry).The impedance of the inductor L1 is L1s.
Thus, the overall impedance of the circuit is given by:
Z = R + L1s + L2s
From the circuit diagram, we can write the following equation:
H(s) = - L2s / (R + L1s + L2s)
Put the values of R, F and H(s) in the above equation to get the value of
L1: 0.1s + 1.5 = - L2s / (270 + L1s + L2s)
By taking inverse Laplace, we get:
Solve for L1: 2700 + 10L1 = 225L1 - L1²10L1 + 2700
= - 225L1 + L1²
Therefore,
L1² - 235L1 - 2700 = 0L1² - 255L1 + 20L1 - 2700
= 0L1(L1 - 255) + 20(L1 - 255)
= 0(L1 - 255)(L1 + 20)
= 0L1
= -20, 255
Since, L1 can not be negative, therefore L1 = 255
Hence, the value of the inductance, L1 is 255 Henry.
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Jessica decides to explore her understanding of momentum and energy conservation in collisions by making and testing a hypothesis. She says, " the two trains have equal mass and initial speeds, then the total initial momentum of the system of two trains will be zero. The net momentum of the system will be conserved, and the final momentum will also be zero. So, in this case, the two trains will come to rest independent of the degree of elasticity of the collision." She runs the simulation with the masses and initial speeds of the two trains set equal for different levels of elasticity of the collision to test her hypothesis. From these simulations, Josh concludes that - Jessicas incorrect. The two trains will only be at rest for any degree of inelasticity. In the case of an elastic collision kinetic energy conservation will not hold if the two trains are at rest after the collision. - Jessica Is incorrect. Although the net momentum of the system is zero before and after the collision the two trains will only be at rest under the conditions of a completely inelastic collision - Jessica is correct. Both trains must have zero velocity after the collision in order to make the final net momentum be zero.
- Jessica is incorrect. The two trains are at rest after the collision only for the elastic case. In the inelastic case kinetic energy is lost meaning that at least one of the trains will be moving after the collision.
From the given hypothesis, Jessica assumes that the two trains have equal mass and initial speeds, and therefore the total initial momentum of the system will be zero.
She also assumes that the net momentum of the system will be conserved, and the final momentum will also be zero, making the two trains come to rest independent of the degree.
However, Josh concludes that Jessica's hypothesis is incorrect. In the case of an inelastic collision, the two trains will be at rest, but not for any degree of inelasticity. In an elastic collision, kinetic energy conservation will not hold if the two trains are at rest after the collision. In this case, Jessica's hypothesis would be incorrect.
Therefore, Jessica's hypothesis is incorrect. The two trains are at rest after the collision only for the completely inelastic case. In the inelastic case, kinetic energy is lost, meaning that at least one of the trains will be moving after the collision. Both trains must have zero velocity after the collision in order to make the final net momentum be zero.
So, Jessica's assumption that the degree of elasticity of the collision does not matter for the final velocity of the trains is not correct.
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what does a resistor in an electrical dp
Answer:
A resistor is a passive two-terminal electrical component that implements electrical resistance as a circuit element. In electronic circuits, resistors are used to reduce current flow, adjust signal levels, to divide voltages, bias active elements, and terminate transmission lines, among other uses.
Explanation:
Resistors are common elements of electrical networks and electronic circuits and are ubiquitous in electronic equipment. Practical resistors as discrete components can be composed of various compounds and forms. Resistors are also implemented within integrated circuits.
The electrical function of a resistor is specified by its resistance: common commercial resistors are manufactured over a range of more than nine orders of magnitude. The nominal value of the resistance falls within the manufacturing tolerance, indicated on the component.
Explain why white light splits up into the different colours when it goes through a prism
Answer:
Light splits up into different colors because of the electromagnetic spectrum which makes the light bend, wavelength, and it makes different colors by it :3
Explanation:
:3
Un niño juega con un conejo en el parque, en un momento el conejo se aleja del niño en línea recta una distancia de 200 m en 15 s y luego regresa recorriendo dos tercios de la distancia en 10 s. Calcular: la velocidad media y rapidez media detodo elrecorrido.
Answer:
26.6m/s
Explanation:
Speed = distance/time
When the distance = 200m
Time = 15s
Speed = 200/15
Speed = 13.33m/s
If it returns travelling 2/3rd of the distance, then the new distance will be:
2/3 × 200
New Distance = 400/3 m
Time taken = 10s
Speed during this period = 400/3 × 1/10
= 400/30
= 40/3
= 13.3m/s
Average speed during the entire trip = 13.3+13.3 = 26.6m/s
The minimum requirements for the design, materials, fabrication, erection, testing, and inspection of various types of piping systems are covered by:________
The minimum requirements for the design, materials, fabrication, erection, testing, and inspection of various types of piping systems are covered by ASME B31.3 Code.
The ASME B31.3 Code, which specifies the minimal standards for design, materials, fabrication, inspection, testing, and commissioning, is the construction code for process pipe. Your inspection and test plan (ITP) for process piping must adhere to ASME B31.3 Code as a result of the aforementioned rationale.Several organizations publish the norms and standards that are connected to piping systems and pipe components. Representatives from industry associations, manufacturers, professional associations, user groups, governmental organizations, insurance providers, and other interest groups serve on committees for these organizations. The committees are in charge of maintaining, updating, and rewriting the referred codes, standards, specifications, and regulations in light of technology advancements, research, user input, issues, and modifications. Periodically, updates to various codes and standards are published. The most recent versions, addenda, or modifications of the codes and standards that are relevant to engineers, designers, and other professional and technical staff should be kept up to date as a result.To know more about fabrication
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( WILL GIVE BRAINLIEST TO WHOEVER ANSWERS FIRST AND SHOWS WORK) A car weighs 15300 N. What is its mass?
why is the sun considered the ultimate source of energy
The sun is considered the ultimate source of energy because it is the primary driver of almost all forms of energy on Earth. Through the process of nuclear fusion, the sun converts hydrogen atoms into helium, releasing an enormous amount of energy in the form of light and heat. This energy radiates out into space and reaches Earth as sunlight.
Sunlight is the basis for several key energy sources. It drives photosynthesis in plants, which converts solar energy into chemical energy stored in organic compounds. This process forms the foundation of the food chain, providing energy for all living organisms.
Additionally, sunlight plays a crucial role in the generation of other renewable energy sources. Solar panels directly convert sunlight into electricity, while wind power relies on solar heating to create air movements. Even hydroelectric power is indirectly powered by the sun, as solar radiation drives the water cycle that produces rainfall and fills reservoirs.
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5.Projectile motion is free fall with an initial horizontal velocity. True or false
Explanation:
One of the interesting things about projectile motion is that the horizontal motion is independent of the vertical motion. Recall that in freefall, an object continually experiences a downward acceleration of 9.80ms2 but has no horizontal acceleration.
What is the length of AC ?
A van slows down uniformly from 17 m/s to 0 m/s in 5 s. How far does it travel before stopping?
Procedure is required.
Answer:
Before stopping, the van travels 42.5 m
Explanation:
Constant Acceleration Motion
It's a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.
Being a the constant acceleration, vo the initial speed, vf the final speed, and t the time, the following relation applies:
\(v_f=v_o+at\qquad\qquad [1]\)
The distance traveled by the object is given by:
\(\displaystyle x=v_o.t+\frac{a.t^2}{2}\qquad\qquad [2]\)
The van slows down uniformly from v0=17 m/s to vf=0 m/s in t=5 s. The acceleration can be calculated by solving [1] for a:
\(\displaystyle a=\frac{v_f-v_o}{t}\)
\(\displaystyle a=\frac{0-17}{5}=-3.4\ m/s^2\)
The distance covered is:
\(\displaystyle x=17\cdot 5+\frac{(-3.4)\cdot 5^2}{2}\)
\(\displaystyle x=85-42.5=42.5\)
Before stopping, the van travels 42.5 m
George weighs 200 lb. what is his weight in Newtons (think metric, ha ha 1 kg=2.2 lb)
Answer:
889.644 newton
Explanation:
multiply the pound value by 4.448
Find the center of mass of the region bounded by y=9-x^2 y=5/2x , and the z-axis. Center of Mass = __?
Note: You can earn partial credit on this problem.
The centre of mass of the region is bounded by y=9-x^2 y=5/2x, and the z-axis is (3.5, 33/8). Formulae used to find the centre of mass are as follows:x bar = (1/M)*∫∫∫x*dV, where M is the total mass of the system y bar = (1/M)*∫∫∫y*dVwhere M is the total mass of the system z bar = (1/M)*∫∫∫z*dV, where M is the total mass of the systemThe region bounded by y=9-x^2 and y=5/2x, and the z-axis is shown in the attached figure.
The two curves intersect at (-3, 15/2) and (3, 15/2). Thus, the total mass of the region is given by M = ∫∫ρ*dA, where ρ = density. We can assume ρ = 1 since no density is given.M = ∫[5/2x, 9-x^2]∫[0, x^2+5/2x]dAy bar = (1/M)*∫∫∫y*dVTherefore,y bar = (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]y*dA= (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]ydA...[1].
The limits of integration in the above equation are from 5/2x to 9-x^2 for x and from 0 to x^2+5/2x for y.To evaluate the above integral, we need to swap the order of integration. Therefore,y bar = (1/M)*∫[0, 3]∫[5/2, (9-y)^0.5]y*dxdy...[2].
The limits of integration in the above equation are from 0 to 3 for y and from 5/2 to (9-y)^0.5 for x.Substituting the values and evaluating the integral, we get y bar = (1/M)*[(9-5/2)^2/2 - (9-(15/2))^2/2]= (1/M)*(25/2)...[3].
Also, the x coordinate of the center of mass is given by,x bar = (1/M)*∫∫∫x*dVTherefore,x bar = (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]x*dA= (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]xdA...[4].
The limits of integration in the above equation are from 5/2x to 9-x^2 for x and from 0 to x^2+5/2x for y.To evaluate the above integral, we need to swap the order of integration. Therefore, x bar = (1/M)*∫[0, 3]∫[5/2, (9-y)^0.5]xy*dxdy...[5].
The limits of integration in the above equation are from 0 to 3 for y and from 5/2 to (9-y)^0.5 for x.
Substituting the values and evaluating the integral, we get x bar = (1/M)*[63/8]= (1/M)*(63/8)...[6]Thus, the centre of mass of the region is bounded by y=9-x^2 y=5/2x, and the z-axis is (3.5, 33/8).
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A block of mass m = 3.7 kg slides from left to right across a frictionless surface withra speed v; - 7.4 m/s. It collides in a perfectly elastic collision with a second block of
mass M that is at rest. After the collision, the 3.7-kg block reverses direction, and its new speed is vf 2.2 m/s. What is M?
8.9 kg
6.8 kg
5.2 kg
7.5 kg
Answer:
5.2 kgExplanation:
#CARRY ON LEARNING #MARK BRAINLITSIf we rub a rubber rod against a piece of fur the rod gains a negative change. Why does the rod have a negative charge?
Answer:
because the rod takes electrons from the fur when rubbed across it
A stone is dropped from the
top of a tower 500m high into a pond of water at the base of the tower When is the splash heard at the top? (Given, g = 10m/s-² and speed of sound = 340 m/s¹)
Now
\(\\ \sf\longmapsto h=ut+\dfrac{1}{2}gt^2\)
\(\\ \sf\longmapsto h=0t+\dfrac{1}{2}10t^2\)
\(\\ \sf\longmapsto 500=5t^2\)
\(\\ \sf\longmapsto t^2=100\)
\(\\ \sf\longmapsto t=10s\)
Now
\(\\ \sf\longmapsto h=cT\)
\(\\ \sf\longmapsto T=\dfrac{h}{c}\)
\(\\ \sf\longmapsto T=\dfrac{500}{340}\)
\(\\ \sf\longmapsto T=1.47\approx 1.5s\)
Total time:-
\(\\ \sf\longmapsto T_{net}=t+T=10+1.5=11.5s\)
The total time of motion of the stone is 11.47 seconds.
Time of motion from the given height
The time taken for the stone to drop from the given height is calculated as follows;
\(h = v_0t + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 500}{10} } \\\\t = 10 \ s\)
Time it travels through the waterThe time it takes the stone to travel through the water is calculated as follows;
\(t = \frac{500}{340} \\\\t = 1.47 \ s\)
Thus, the total time of motion of the stone is 1.47 + 10 = 11.47 seconds.
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The energy of the electron of hydrogen atom in its nth orbit is given by E n =− n 2 13.6
electron volt(eV). Based on this formula.
(i) Draw different energy levels corresponding to n=1,2,3,4,5,6 and [infinity].
(ii) Show Lyman and Baler series of emission spectrum of hydrogen atom by drawing various electronic transitions.
(iii) Find the ionisation energy of hydrogen atom.
Answer:
i) E1 = -13.6/1² = -13.6eV
E2 = -13.6/2² = -3.4 eV
E3 = -13.6/3² = -1.51 eV
E4 = -13.6/4² = -0.85 eV
E5 = -13.6/5² = -0.544 eV
E6 = -13.6/6² = -0.377 eV
E∞ = 0
ii) Lyman series obtained when there is electron transition from n = 2,3,4,5,6... to n1=1
Baler series obtained when there is a transition from n = 3,4,5,6.. to n1 = 2
iii) E ( ionisation) = E∞ - E1 = 0 - (- 13.6) = 13.6 eV
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When a chainsaw is in operation, the chain moves with a linear speed of v=5. 3 m/s. At the end of the saw, the chain follows a semicircular path with a radius of r=0. 040 m. Part A What is the angular speed of the chain as it goes around the end of the saw? Express your answer to two significant figures and include appropriate units. Part B What is the centripetal acceleration of the chain at the end of the saw? Express your answer to two significant figures and include appropriate units
The centripetal acceleration of a chain link at the end of a chainsaw's saw blade when chain is moving with a linear speed of 5.3 m/s and follows semicircular path with radius of 0.040 m is 702.625 m/s^2
The centripetal acceleration is given by the formula:
a = v^2 / r
where v is the linear speed of the chain link and r is the radius of the semicircular path.
Substituting the given values, we get:
a = (5.3 m/s)^2 / 0.040 m
a = 702.625 m/s^2
Therefore, the centripetal acceleration of a chain link at the end of a chainsaw's saw blade when the chain is moving with a linear speed of 5.3 m/s is 702.625 m/s^2.
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--The complete Question is, What is the centripetal acceleration of a chain link at the end of a chainsaw's saw blade when the chain is moving with a linear speed of 5.3 m/s and follows a semicircular path with a radius of 0.040 m?--
Increasing the temperature of object by 20K = C *
A. 20 C
B. 293.15 C
C. -253.15 C
D. None of the above
Answer:
B
Explanation:
A cannonball is shot from the top of
a 47.8 m high hill at a speed of
53.7 m/s. At its highest point, it is
moving at 31.5 m/s.
How high is it then?
A cannonball is shot from the top of a 47.8 m high hill at a speed of 53.7 m/s. The height then is 61.81 m/s.
What are kinematic equations?The motion of an object with constant acceleration is described by a set of equations known as kinematic equations. Integrals, derivatives, and rates of change must all be understood in order to solve kinematics equations.
Velocity is the rate and direction of an object's movement, whereas speed is the time rate at which an object is moving along a path. In other words, velocity is a vector, whereas speed is a scalar value.
The kinematic equation is:
v² = u² + 2gs (a = g)
Where u is the initial velocity, a is the acceleration, and v is the velocity after the time period t.
(53.7)² + 2 x 9.8 x 47.8 m
Therefore, the height is 61.81 m/s.
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it’s 144.2 I have it in my notes from when I was in school!!!!
What is the name of the shuttle with 134 successful launches
International space station is the mission of NASA. It has launched 134 successful space missions.
What is International Space Station ?International space station is a huge place in the space but in the close orbit with all possible facilities for astronauts , scientists and others
What is NASA ?The National Aeronautics and Space Administration (NASA) is an acronym for the National Aeronautics as well as Space Administration. NASA was established as a division of the United States government on October 1, 1958. NASA is just in charge of all research and technology related to aviation and space in the United States.
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How many oxygen (O) atoms are in a molecule of Cg H,O3?
A. 1
B. 3
C. 10
D. 4
Answer:
B. 3
Explanation:
A kid drives 4 miles to the mall. If the speed limit is 45 miles/hr and the kid makes the trip in .03 hours. Is the kid breaking the speed limit? a. No, he is going 1 mile/hr. b. Yes, he is going 133 miles/hr, C. No, he is going 40 miles/hr. d. Yes, he is going 150 miles/hr.
Answer:B
Explanation:
.03 of an hr is 2 mins and if it takes 2 mins to drive 4 miles enter it in pace calulator you are going 120mph so the closest to 120 is 133mph
The kid is breaking the speed limit of 45 miles/hr since he is going at 133.3 miles/hr.
Speed is the ratio of distance travelled to time taken. It is given by:
Speed = distance / time
Since the distance to the mall is 4 miles, the time taken is 0.03 hours, hence the speed is:
Speed = distance / time
Speed = 4 miles / 0.03 hours
Speed = 133.3 miles/hr
Hence the kid is breaking the speed limit of 45 miles/hr since he is going at 133.3 miles/hr.
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The body process in which an adequate supply of oxygen converts glucose into energy is called:________
Aerobic metabolism can occur both aerobically (using oxygen), or anaerobically (without oxygen). During aerobic cellular respiration, glucose reacts with oxygen, forming ATP that can be used by the cell.
What is Cellular respiration ?Through the process of cellular respiration, organisms mix oxygen with food molecules, directing the chemical energy contained in these substances toward life-sustaining processes while excreting carbon dioxide and water as waste.
Glycolysis, also known as the citric acid cycle, is the first stage of cellular respiration. The Krebs cycle, also known as the electron transport chain, is the second stage Anaerobic and aerobic respiration are the two basic forms of cellular respiration. It need oxygen (O2) to make ATP during an exclusive type of cellular respiration known as aerobic respiration.Learn more about Cellular respiration here:
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I’m on earth.I have an object with a mass of 15 kg. When I put it on a scale, what will the scale read?
The scale will read 147N
Explanation:The mass of the object, m = 15 kg
Since I am on the earth, the acceleration due to gravity on the earth is:
g = 9.8 m/s²
The scale will read the weight of the object, and is calculated below
The weight, W = mg
W = 15(9.8)
W = 147 N
Therefore, the scale will read 147N
Braking studies have shown that a tractor-trailer traveling at 55 mph needs ____ the distance to stop as an automobile.
Braking studies have shown that a tractor-trailer traveling at 55 mph needs two times the distance to stop as an automobile.
There are four parts that make up a vehicle's overall stopping distance i.e., Vehicle reaction time and distance, human perception time and distance, human reaction time and distance Vehicle Braking Distance and Time
The maximum distance your car will travel while braking under perfect circumstances. It may require 216 feet at 55 mph on dry pavement with decent brakes. The brakes must use more force to stop a bigger car, which increases heat absorption. On the other hand, large vehicles' brakes, tires, springs, and shock absorbers are made to function optimally when fully loaded. Trucks that are empty need longer stopping distances because they have less traction. It can lock up and bounce, providing substantially worse braking.
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Please help me. I have to submit this today.
explain the difference between mass and weight and how these concepts relate to gravity
Answer:
Your mass is the same no matter where you go in the universe; your weight, on the other hand, changes from place to place. Mass is measured in kilograms; even though we usually talk about weight in kilograms, strictly speaking it should be measured in newtons, the units of force
In summary, mass is a measure of how much matter an object contains, and weight is a measure of the force of gravity acting on the object. ... The amount of gravity is directly proportional to the amount of mass of the objects and inversely proportional to the square of the distance between the objects.
Explanation: