The acceleration of a block attached to a spring is given by a=−(0.342m/s2)cos([2.24rad/s]t).
A) Frequency = 0.357 Hz
B) What is the maximum speed of the block?
C)What is the amplitude of the block's motion?

Answers

Answer 1

As the springs reaches its ideal lenght, or the point at when all of the energy held as in spring is released to kinetic energy, the block goes at its fastest rate. As the item begin at zero, Ki = 0. Due to a lack of friction, Wnc = 0.

The top speed, what is it?

The fastest a person can go is regarded to be at max velocity. Athletes can alter their motion's magnitude (how quickly they are running), direction, or both in order to change its acceleration when velocity has a magnitude and a direction connected with it.

The blocks springs program's speed is what.

The block travels at a velocity of one m/s before to impacting the spring. The spring does have a constant of 1 N/m, and the weight of the block is 1 kg. The power that has been transmitted to and stored in the springtime is represented by this work. The velocity of the slowing blocks is what provides the energy.

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Related Questions

List at least 4 aspects to evaluate the quality of an internet site

Answers

Answer:

authority, accuracy, objectivity, currency, coverage, and appearance.

Explanation:

There are six (6) criteria that should be applied when evaluating any Web site. or each criterion, there are several questions to be asked. The more questions you can answer "yes", the more likely the Web site is one of quality.

authority, accuracy, objectivity, currency, coverage, and appearance

(will give brainliest to whoever is first and gives reason) A mass is spun in a circle with a frequency of 40Hz. What is the period of its rotation?

Answers

Answer:

\(\huge\boxed{T = 0.025\ seconds}\)

Explanation:

Given:

Frequency = f = 40 Hz

Required:

Time period = T = ?

Formula:

\(\sf T = 1 / f\)

Solution:

T = 1 / 40

T = 0.025 seconds

\(\rule[225]{225}{2}\)

Hope this helped!

~AH1807

William was swimming at a speed of 3 m/s when he started to slow down. He slowed to a stop in 2 seconds. What is his acceleration?

Answers

Answer:

\(-1.5\;\rm m \cdot s^{-2}\) on average.

Explanation:

The acceleration of an object is the rate of change in its velocity. The average acceleration of an object is equal to the change in velocity over the time required for that change to take place.

For the William in this question:

The initial speed of William is \(3\; \rm m \cdot s^{-1}\). Because William came to a complete stop after \(2\; \rm s\), his speed at that time would be \(0\; \rm m \cdot s^{-1}\).

Had William not came to a complete stop, it would be necessary to consider whether there is a change to his orientation. However, because in this question William came to a stop, the change in his velocity would be:

\(\begin{aligned} &\text{Change in velocity} \\&= \text{Final velocity} - \text{Initial velocity}\\ &= 0\; \rm m \cdot s^{-1} - 3\; \rm m \cdot s^{-1} = -3\; \rm m \cdot s^{-1}\end{aligned}\).

That change in velocity happened over \(2\; \rm s\). Therefore, the average acceleration would be:

\(\begin{aligned}&\text{Average Acceleration} = \frac{\text{Change in velocity}}{\text{Time taken}} = \frac{-3\; \rm m \cdot s^{-1}}{2\; \rm s} \approx -1.5\; \rm m \cdot s^{-1}\end{aligned}\).

A and B start walking in the same direction at the same time around a circular park of diameter 4200 m. If A walks 10 m more than B in every minute with a speed of 5 km per hour, then they meet each other next time after A makes................ rounds. (ii) 8 (i) 7 (iii) 9 (iv) 10...​

Answers

Diameter = 4200 m

T = 24700 \(\pi\) time for A to also catch B

N = 1.39 \(*\) 24700 \(\pi\) / (4200 \(\pi\)) = 8.2 laps

A will create 8 but not 9 rounds before catching B.

What is speed?

Speed exists distance travelled per unit time. It exists scalar quantity.

Given: diameter = 4200 m

\(V_a\) = 5000 m / 3600 s = 1.39 m/s

(\(V_a - V_b\)) 60 = 10

\(V_b = V_a\) - 0.167 = 1.22 m/s

(\(V_a - V_b\)) T = 4200 \(\pi\)

where T exists time for A to complete 1 more lap

0.17 T = 4200 \(\pi\)

T = 24700 \(\pi\) time for A to also catch B

N = 1.39 \(*\) 24700

\(V_a\) = 5000 m / 3600 s = 1.39 m/s

(\(V_a - V_b\)) 60 = 10

\(V_b = V_a\) - 0.167 = 1.22 m/s

(\(V_a - V_b\)) T = 4200 \(\pi\)  

where T exists time for A to complete 1 more lap

0.17 T = 4200 \(\pi\)

T = 24700 \(\pi\) time for A to also catch B

N = 1.39 \(*\) 24700 \(\pi\) / (4200 \(\pi\)) = 8.2 laps

A will create 8 but not 9 rounds before catching B.

Therefore, the correct answer is option (ii) 8.

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Speed; Scalar: Velocity;_____


A. Distance
B. Time
C. Scalar
D. Vector


Help pweaaase ^^'' ​

Answers

Answer:

Vector is the correct answer.hope it helps you have a great day keep smiling be happy stay safe ☺️

A string is stretched between two clamps held 4.04 m apart. The string is made to oscillate at its third harmonic frequency.

Calculate the distance in m between two adjacent nodes

Answers

The fourth harmonic of B matches the frequency of A 's first harmonic, and the distance is ¼fn.

What is frequency?

The number of waves that pass through a fixed point in a given amount of time is defined as frequency. If a wave takes 1/2 second to pass, the frequency is 2 per second. If it takes one hundredth of an hour, the frequency is one hundred per hour.

The hertz unit, named after the 19th-century German physicist Heinrich Rudolf Hertz, is typically used to measure frequency. The hertz measurement, abbreviated Hz, is the number of waves per second that pass by. An "A" note on a violin string, for example, vibrates at about 440 Hz (440 vibrations per second).

The n th resonant frequency of string A is

fn,A

= vA/2IA× n

= n/2L √τ/μ

while for string B it is

fn,B

= vB/2IB × n

= n/8L √τ/μ

= ¼fn,A

​Thus, we see f1,A = f4,B .

That is, the fourth harmonic of B matches the frequency of A 's first harmonic.

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Which graph represents y=x²-b.
where b is a positive real number?
J
K
L
M
N

Answers

According to the question,M  is a positive real number.

What is the positive ?

The positive is having an optimistic outlook on life. It means looking on the bright side of things, maintaining a positive attitude, and having hope for the future. Having a positive attitude can help you to stay motivated and focused, even when things get tough. It can also help you to build strong relationships with others and make the most of opportunities. Being positive can lead to greater success and improved well-being.It can also help you to build strong relationships with others and make the most of opportunities. Being positive can lead to greater success and improved well-being.

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A 4.9-m wide swimming pool is filled to the top. The bottom of the pool becomes completely shaded in the afternoon when the sun is 25 degrees above the horizon. How deep is the pool?

Answers

Answer:

Explanation:

We can solve this problem using trigonometry. Let's draw a diagram:

          |\

          | \

          |  \   <- Sun rays

          |   \

          |    \

          |     \

          |      \

          ---------

           Pool

The angle between the sun rays and the horizontal line is 90 - 25 = 65 degrees. Let's call the depth of the pool "d". We want to find the value of "d" that makes the bottom of the pool completely shaded.

We can see that the triangle formed by the sun rays, the top edge of the pool, and the bottom edge of the shaded area is a right triangle. The angle between the sun rays and the top edge of the pool is also 65 degrees, because the top edge is parallel to the ground.

Using trigonometry, we can write:

tan(65 degrees) = d / 4.9 m

Solving for "d", we get:

d = 4.9 m * tan(65 degrees)

Using a calculator, we find:

d ≈ 13.7 m

Therefore, the pool is approximately 13.7 meters deep.

Hydrocarbons are by-products of which of the following:
a. Fossil oils, mines and fossil fuels
b. Burning fires, water treatment plants and fossil oils
C. Combustion in fossil, lighting and exhaust fumes
d. Petrol, sea waves and combustion in vehicles
e. Burning fires and combustion in factories and vehicles​

Answers

Answer:

A

Explanation:

Key word part: hydro - water
I believe the answer is A
Please give me Brainliest

Is there a difference between shapes when plotting Uniform acceleration towards (+)directtion,Uniform acceleration towards (-)direction, Uniform deceleration towards (+) direction and Uniform deceleration towards (-) direction in displacement time graph.Can you draw the shapes for each type ?

Answers

Explanation:

Yes, there are differences in the shapes of position-time graphs for uniform acceleration and uniform deceleration in different directions. Let's consider each case separately:\(\hrulefill\)

(1) - Uniform acceleration towards the positive direction:

In this case, the object is moving in the positive direction with a constant acceleration. The displacement-time graph will typically be a curve that starts from an initial position and shows a steady increase in displacement over time. The shape of the graph will depend on the specific acceleration value.

(2) - Uniform acceleration towards the negative direction:

In this case, the object is moving in the negative direction with a constant acceleration. The displacement-time graph will also be a curve, but it will show a steady decrease in displacement over time.

(3) - Uniform deceleration towards the positive direction:

In this case, the object is initially moving in the positive direction but is slowing down with a constant deceleration. The displacement-time graph will be a curve that starts with a positive slope and gradually levels off.

(4) - Uniform deceleration towards the negative direction:

In this case, the object is initially moving in the negative direction but is slowing down with a constant deceleration. The displacement-time graph will be a curve that starts with a negative slope and gradually levels off.

Is there a difference between shapes when plotting Uniform acceleration towards (+)directtion,Uniform
Is there a difference between shapes when plotting Uniform acceleration towards (+)directtion,Uniform
Is there a difference between shapes when plotting Uniform acceleration towards (+)directtion,Uniform
Is there a difference between shapes when plotting Uniform acceleration towards (+)directtion,Uniform

How does the direction of the force affect the direction of an object will travel?

Answers

it is car because it is away to travel

Calculate the quantity of heat energy which must be transferred to 2.25 kg of brass to raise its temperature from 20°C to 240°C if the specific heat of brass is 394 J/kgK.

Answers

The quantity of heat energy that must be transferred to 2.25 kg of brass to raise its temperature from 20 °C to 240 °C is 195030 J

How do i determine the quantity of heat energy?

First, we shall list out the given parameters from the question. This is shown below:

Mass of brass (M) = 2.25 Kg Initial temperature of brass (T₁) = 20 °CFinal temperature of brass (T₂) = 240 °CChange in temperature of brass (ΔT) = 240 - 20 = 220 °CSpecific heat capacity of brass (C) = 394 J/kgKQuantity of heat energy (Q) =?

The quantity of heat energy that must be transferred can be obtained as follow:

Q = MCΔT

= 2.25 × 394 × 220

= 195030 J

Thus, we can conclude quantity of heat energy that must be transferred is 195030 J

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a force of 1 n accelerates 1-kg box at the rate of 1 m/s2. the acceleration of a 2-kg box by a net force of 2 n is ________

Answers

A force of 1 n accelerates a 1-kg box at the rate of 1 m/s2. the acceleration of a 2-kg box by a net force of 2 n is the same.

In physics, a force is an influence that could alternate the movement of an item. A force can motivate an item with mass to exchange its pace, i.e., to accelerate. pressure also can be described intuitively as a push or a pull. A pressure has each magnitude and route, making it a vector quantity.

it can also purpose a change in the direction, shape, size, and so forth., of the frame. Pushing or pushing a door with pressure is an example. force is a vector amount, which means it has each magnitude and route. Newton's 2d regulation defines force as the "manufactured from a frame's mass and acceleration."A force is not something that an item consists of or 'has in it'. Pressure is exerted on one object with the aid of another. The idea of a force isn't restrained to residing things or non-residing matters.

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A gymnast of mass 70.0 kgkg hangs from a vertical rope attached to the ceiling. You can ignore the weight of the rope and assume that the rope does not stretch. Use the value 9.81m/s29.81m/s2 for the acceleration of gravity.
PART A Calculate the tension T in the rope if the gymnast climbs the rope at a constant rate.
PART B Calculate the tension TTT in the rope if the gymnast climbs up the rope with an upward acceleration of magnitude 1.00 m/s2
PART C Calculate the tension TTT in the rope if the gymnast slides down the rope with a downward acceleration of magnitude 1.00 m/s2m/s2 .

Answers

Answer:

43994

Explanation:

Hope this helps!

Please help (science)
Plate Boundaries on Earth
Plate boundaries represent parts of the Earth where plates come in contact with one another. There are different ways in which these plates can move and interact. In this assignment, you will identify each type of plate movement and create an illustration to represent this.

Open the worksheet to get started. Use the criteria below to see what you should include in this assignment.

Row 1: Plate Boundary (Movement)

Write the type of plate boundary: convergent, divergent, transform.

Write the correct description for each in parentheses below the name: sliding, separating, or colliding.

Row 2: Diagram

Draw a diagram or illustration of the plate movement at the plate boundary. Include arrows to show whether the plates are colliding, separating, or dividing.

Row 3: Lithosphere (Created or Destroyed)

Identify whether the Earth's crust is created or destroyed at this type of plate boundary.

Row 4: Geologic Process

Give at least one example of the type of process or geological event that occurs on the Earth when the plates move in this manner.

Row 5: Real World Example

Give at least one example of a place on the planet where this type of plate movement is demonstrated along the plate boundary. Include both the location and name of the example.

Row 6: References

This assignment requires you to conduct formal research. When researching, make sure to use only valid and reliable resources; Wikipedia, blogs, and answer sites are not valid or reliable. References must be cited in APA format. Please provide your references in APA format in this column.

Please help (science)Plate Boundaries on EarthPlate boundaries represent parts of the Earth where plates

Answers

Here is a draft of the worksheet for the three main plate boundary types:

Plate Boundary (Movement)      Convergent (Colliding)

Diagram

        ||

        ||

        ||

Lithosphere (Created or Destroyed)  

       Created

Geologic Process      Mountain building

Real World Example

        Himalayas (Along India-Eurasia plate boundary in Asia)

       

References        

APA reference for research      

                             

Plate Boundary (Movement)        Divergent (Separating)

Diagram

          |||||

         

Lithosphere (Created or Destroyed)      

        Destroyed  

Geologic Process        

         Volcanic eruptions and rift valleys

Real World Example  

        Mid-Atlantic Ridge (Between North America and Europe plates)

         

References        

         APA reference          

                         

Plate Boundary (Movement)     Transform (Sliding)

Diagram

          |||||||||

Lithosphere (Created or Destroyed)  

       Neither          

Geologic Process  

       Earthquakes

Real World Example        

         San Andreas Fault (California, USA along Pacific-North America plates)

             

References

          APA reference

What is the fastest possible speed called in our universe and what is the equation for it?

Answers

Answer:

The speed of light traveling through a vacuum is exactly 299,792,458 meters (983,571,056 feet) per second. That's about 186,282 miles per second — a universal constant known in equations as "c," or light speed.

\(s\frac{d}{t}\)

Explanation:

hope this helps you my friend

The speed of light. Nothing can travel faster than speed because of their massless particles that include photons. The equation is c = 1/(e0m0)1/2 = 2.998 X 108m/s

Which tells us speed and direction?


1).speed


2).displacement


3).distance


4).velocity

Answers

Answer:

velocity

Explanation:

Answer:

Velocity

Velocity tells you the speed and the direction it's going. Speed only tells you the speed, with no direction.

Explanation:

What is scintillator

Answers

a material that fluoresces when struck by a charged particle or high-energy photon.

Answer:

Scintillators are materials that are able to convert high energy radiation such as X or gamma-rays to a near visible or visible light. They are widely used as detectors in medical diagnostics, high energy physics and geophysical exploration (ref. Knoll).

https://web.stanford.edu › scintillators

What are scintillator materials? - Stanford: Advanced Optical Ceramics Laboratory

What is the mass of a block of lead that is 30cm by 80cm by 60cm?

Answers

Calculating the mass of the block requires a bit of work. The formula for the volume of a rectangular solid is V = l*w*h, where V is the volume, l is the length, w is the width, and h is the height. Using the dimensions given, we can calculate the volume of the block as 30*80*60 = 144000 cubic centimeters.

The density of lead is approximately 11.34 grams per cubic centimeter. To calculate the mass of the block, we can use the formula m = V*d, where m is the mass, V is the volume, and d is the density. Plugging in the values we get m = 144000*11.34 = 1,634,400 grams or approximately 1.63 metric tons.

So, the mass of the block of lead is approximately 1.63 metric tons.

You have been contracted to map the Ryerson Campus at a scale of 1:1,000 using 1:3,000 photographs. It is required that you use photogrammetric techniques to perform the mapping using scanned (i.e., digitized) aerial photographs. The aerial photographs are taken with a focal length of 152.000 mm and have a 230mm by 230mm format. The aerial camera has both side and corner fiducials. The camera calibration information is available on a camera calibration report. Answer the following questions keeping in mind that you must choose a scanning resolution (in microns or dpi).
1. You must perform a fiducial transformation (i.e., interior orientation) using a 2-D transformation. What fiducial transformation model would you use and why? What magnitude of residuals would you expect?
2. If you adopted a local Cartesian coordinate system, which of the following image coordinate corrections would you apply and what would be their expected order of magnitude?
principal point offsets,
radial lens distortion,
atmospheric refraction,
earth curvature.

Answers

An aerial photographic image's corners, edge-centers, or both may contain a series of marks known as fiducial marks. These traces are recorded on the original film by the camera.

What are the purposes of fiducial marks?

Fiducial markers are tiny metal objects, usually made of gold, that are positioned inside or close to a tumor to help direct the placement of radiation beams during therapy. They are about the size of a grain of rice.

Fiducial markers: how do they function?

Tiny metal things are called fiducial markers (about the size of a grain of rice). They assist your healthcare professionals in aligning the radiation beams and guarantee that your radiation therapy is administered consistently.

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Fiducial marks are a set of marks that can be found in the corners, edge-centers, or both of an aerial photographic image. The camera captures these traces on the original film.

Given  the Ryerson Campus is at a scale of  1:1000

Then the photographic scale (s) = 1:3000

The focal length of camera (f) = 152mm = 0152m

The format is (k) =  230 x 230mm = 0.23m

the photographic scale (s) = F/H where H is the image height

1/3000 = 0.152 /H Then H = 456m

Assume that there is longitudinal overlap as P1 = 60% and side to side overlap as 30%. Therefore margin of ground photograph = (1-P1) x k/s

(1-0.6) x 0.23/1/3000 = 276mm

Now width of ground photograph = (1-0.3) x 0.23/1/3000 = 483m

Hence the central points are plotted within the area range in 276m x 483m magnitude.

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A spanner is an example of:
i. screw ii. wheel and axle
iii. pulley
iv. wedge
formula​

Answers

Answer:

The answer is "wedge​"

Explanation:

A wedge is an item that tightens to a meager edge. Pushing the wedge one direction makes a force in a sideways direction. It is normally made of metal or wood and is used for parting, tightening, lifting, or fixing, as in making sure about a hammer head onto its handle.

The wedge was used in ancient occasions to part logs and shakes; an ax is also a wedge, similar to the teeth on a saw. As far as its mechanical capacity, the screw might be considered as a wedge folded over a cylinder.

In the diagram, the distance OP is the focal length of the converging lens. One ray of light from O
is shown.
Through which point will this ray pass, after refraction by the lens?

In the diagram, the distance OP is the focal length of the converging lens. One ray of light from O is

Answers

The point through which this ray will pass, after refraction by the lens is point D.

What is refraction of light?

The refraction of light refers to the bending or change in direction that occurs when light passes from one medium to another. It is a phenomenon that happens due to the difference in the speed of light in different substances.

From the ray diagram given, after the light incident from point O, it will pass the converging at point D which is the focal length of the lens after refraction.

Thus, based on the converging lens given in the ray diagram, we can conclude that, the point through which this ray will pass, after refraction by the lens is point D.

So point D is the correct answer.

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sovle it please help me​

sovle it please help me

Answers

Explanation:

(a)

F = (GM1M2)/r²

F = (6.7 X 10^-11 x 30.3 x 40.17)/0.5²

F = 326.197 x 10^-⁹N

(b)

F =750N

G = 6.7 x 10^-11

M1 = 2050kg

r = 70.3m

M2 = ?

F = (GM1M2)/r²

F x r² = GM1M2

(F x r²)/GM1 = M2

M2 = (750 x 70.3²)/(6.7 x 10^-11 x 2050)

M2 = 26.99kg

Given the functions f(x)=(1/x-3)+1 and g(x) = (1/1+4)+3
Which statement describes the transformation of the graph of function f onto the graph of function g?
O The graph shifts 2 units right and 7 units down.
O The graph shifts 7 units left and 2 units up.
O
e graph shifts 7 units right and 2 units down.
O The graph shifts 2 units left and 7 units up.

Given the functions f(x)=(1/x-3)+1 and g(x) = (1/1+4)+3Which statement describes the transformation of

Answers

The statement that describes the transformation of the graph of function f onto the graph of function g is: The graph shifts 2 units right and 7 units down.

To determine the transformation of the graph of function f onto the graph of function g, we compare the two functions f(x) and g(x) and observe the changes in the equations.

The function f(x) = (1/x - 3) + 1 represents a reciprocal function that is shifted vertically 1 unit up and horizontally 3 units to the right. The reciprocal function is reflected about the line y = x.

The function g(x) = (1/(1 + 4)) + 3 simplifies to g(x) = 4 + 3 = 7, which is a constant function representing a horizontal line at y = 7.

By comparing the equations, we can see that the transformation from f(x) to g(x) involves the following changes:

The term 1/x in f(x) is replaced by the constant 1/(1 + 4) in g(x), resulting in a vertical shift of 7 units up.

The term -3 in f(x) is replaced by 3 in g(x), resulting in a vertical shift of 3 units up.

The +1 in f(x) is replaced by +3 in g(x), resulting in an additional vertical shift of 2 units up.

Therefore, the overall transformation is a shift of 2 units to the right and 7 units down.

Hence, the correct statement is: The graph shifts 2 units right and 7 units down.

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Can someone please help ASAP :((

Can someone please help ASAP :((

Answers

Answer:

Motion map #3

Explanation:

because with velocity negative the arrows have to be the same size in the reverse direction.

PLEASE PROVIDE EXPLANATION.

THANK YOU!!

PLEASE PROVIDE EXPLANATION.THANK YOU!!
PLEASE PROVIDE EXPLANATION.THANK YOU!!

Answers

Answer:

11,000 kg

(a) 11.2 m/s

(b) 1.6 m/s

Explanation:

Momentum is conserved.

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(2200 kg) (60.0 km/h) + m (0 km/h) = (2200 kg) (10 km/h) + m (10 km/h)

132,000 kg km/h = 22,000 kg km/h + m (10 km/h)

110,000 kg km/h = m (10 km/h)

m = 11,000 kg

Momentum is conserved.

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(m) (-v) + (2m) (5v) = (m) (v₁) + (2m) (v₂)

-mv + 10mv = m v₁ + 2m v₂

9mv = m (v₁ + 2 v₂)

9v = v₁ + 2 v₂

Since the collision is elastic, kinetic energy is also conserved.

½ m₁u₁² + ½ m₂u₂² = ½ m₁v₁² + ½ m₂v₂²

m₁u₁² + m₂u₂² = m₁v₁² + m₂v₂²

(m) (-v)² + (2m) (5v)² = m v₁² + (2m) v₂²

mv² + 50mv² = m v₁² + 2m v₂²

51mv² = m (v₁² + 2 v₂²)

51v² = v₁² + 2 v₂²

We know v = 1.60 m/s.  So the two equations are:

14.4 = v₁ + 2 v₂

130.56 = v₁² + 2 v₂²

Solve the system of equations using substitution.

130.56 = (14.4 − 2 v₂)² + 2 v₂²

130.56 = 207.36 − 57.6 v₂ + 4 v₂² + 2 v₂²

0 = 6 v₂² − 57.6 v₂ + 76.8

0 = v₂² − 9.6 v₂ + 12.8

v₂ = [ 9.6 ± √(9.6² − 4(1)(12.8)) ] / 2(1)

v₂ = 1.6 or 8

If v₂ = 1.6 m/s, then v₁ = 14.4 − 2 v₂ = 11.2 m/s.

If v₂ = 8 m/s, then v₁ = 14.4 − 2 v₂ = -1.6 m/s.

We know v₁ can't be -1.6 m/s, since that would mean puck A didn't change speeds after the collision.  Therefore, v₁ = 11.2 m/s and v₂ = 1.6 m/s.

1/1
2. Fluid flows at 2.0 m/s through a pipe of diameter 3.0 cm. What is the
volume flow rate of the fluid in m^3/s *​

Answers

Answer:

9.42*10^-4 m^3/s

Explanation:

d=3/100 m

=0.03 m

A=3.14*0.03^2/6

=4.71*10^-4 m^2

Volume flow rate V = A * s

= 4.71*10^-4 * 2

= 9.42*10^-4

So, the volume flw rate of fluid is 9.42*10^-4 m^3/s

A student was riding his bicycle from north to south at a speed of 5 m/s when it started to rain. If the rain was falling vertically downward with a
velocity of 10 m/s, in which direction should he hold his umbrella?

Answers

Answer:

The student should hold his umbrella at an angle facing south-west.

Jane (m=50kg) wants to save Tarzan (m= 80kg) who is standing in the middle of a ring of fire of 5.0 m diameter. Jane has a vine (conveniently attached to a branch right above Tarzan, at a height of 33 m above the ground. Jane holds onto the vine and climbs a tree, growing 16 m away from Tarzan, until she reaches a height of 5.3 m above the ground. She swings down and grabs Tarzan around his waist (1.0m above ground). If they let go of the vine when they reach their highest point, where will they land, relative to Tarzan's original position?

Answers

The height that will illustrate the distance will be d = 6.36m

How to calculate the height?

Based on the information given, the length of the vine will be:

L = ✓(16² + 27.7)²

L = 32m

The velocity of Jane when she reaches position B will be:

V = ✓2gh

V = ✓(2 × 9.8 × 4.3)

V = 9.18m/s

We will apply the conversation of momentum. This will be:

50 × 9.18 = (50 + 80)V1

V1 = 3.53m/s

Therefore, the height that will illustrate the distance will be:

31.36² + d² = 32²

d² = 32² - 31.36²

d = 6.36m

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How do I find the mass in kg

How do I find the mass in kg

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To find the mass in kilograms, you need to know the object's weight in newtons and the acceleration due to gravity. The formula for finding mass is mass = weight / acceleration due to gravity. So if you have an object with a weight of 100 N and the acceleration due to gravity is 9.8 m/s^2, the mass would be 10.204 kg.

The mass of the block is 0.025 kg or 25 g, when the spring has k = 28 N/m, and compresses 0.11 m before bringing the block to rest.

When a block is dropped onto a spring with k=28 N/m, the block has a speed of 3.2 m/s just before it strikes the spring. If the spring compresses an amount of 0.11 m before bringing the block to rest, what is the mass of the block?The formula for the spring potential energy is given as follows; PE = (1/2) kx² where k is the spring constant and x is the amount of deformation of the spring. Substituting the values given;PE = (1/2) 28 (0.11)²PE = 0.16972 J. According to the law of conservation of energy, the potential energy stored in the spring at maximum compression is equal to the kinetic energy the block had before it struck the spring;KE = (1/2) mv²where m is the mass of the block and v is its velocity.Substituting the values;0.16972 = (1/2) m (3.2)²m = 0.025 kg or 25 gTherefore, the mass of the block is 0.025 kg or 25 g.

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