The 20-g bullet is travelling at 400 m/s when it becomes embedded in the 2-kg stationary block. The coefficient of kinetic friction between the block and the plane is ?k = 0.3. (Figure 1)
Part A
Determine the distance the block will slide before it stops.
Express your answer to three significant figures and include the appropriate units.

Answers

Answer 1

This problem requires energy and law of conservation of momentum. The block will slide 1.34 metres before stopping.

Before hitting the block, find the bullet's momentum:

(0.02 kg) × (400 m/s) = 8 kg/m

The bullet will cling to the block and move together. The block-bullet system's final velocity is "v".

Friction work equals the block-bullet system's initial kinetic energy, hence we can calculate the block's sliding distance:

K1 = (1/2)mv₁² + (1/2)Iω₁² = (1/2)(2 kg)v²

where K₁ is the initial kinetic energy of the block-bullet system, m is its mass, v₁ is the bullet's velocity before impact, I is the block's moment of inertia (which we'll assume is a thin rod), and 0 is its angular velocity before impact.

Next, using momentum conservation, we calculate the block-bullet system's final velocity:

(2 kg + 0.02 kilogramme) p = mv3.98 m/s = p/2 kg + 0.02 kg.

The work-energy concept can calculate the block's stopping distance:

K = (K₁- K₂) \(W_{friction}\)

where \(W_{friction}\) is friction's work, k is the block-bullet system's kinetic energy change, and K₂ is its final kinetic energy (zero since it stops).

Friction performs:

\(W_{friction}\) = μk N d mg d

where μk is the coefficient of kinetic friction, N is the normal force (which is equal to the weight of the block), m is the mass of the block, g is the acceleration due to gravity, and d is the distance the block slides before it stops.

Using our values:

μk mg d = K₁ - K₂

(0.3)(2 kg)(9.81 m/s²) d = (1/2)(2 kg)(3.98 m/s)² - 0

d = 1.34 m

The block will slide 1.34 metres before stopping.

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Related Questions

A 530 g, 9.0-cm-diameter can is filled with uniform, dense food. It rolls across the floor at 1.3 m/s. What is the can's kinetic energy? Express your answer with the appropriate units.

Answers

If 530 g, 9.0-cm-diameter can is filled with uniform, dense food, the kinetic energy of the can is 0.456 joules.

The kinetic energy of an object is given by the formula KE = (1/2)mv², where m is the mass of the object and v is its velocity. In this case, the mass of the can is 530 g or 0.53 kg, and its velocity is 1.3 m/s.

The diameter of the can is given as

9.0 cm = 9/100 m =  0.09 m, which means its radius is 0.045 m (since radius is half the diameter).

To find the kinetic energy of the can, we first need to convert its mass from grams to kilograms, which gives us

530 g = 530/100 kg = 0.53 kg.

Next, we can substitute the values of m and v into the formula for KE:

KE = (1/2)mv²

KE = (1/2)(0.53 kg)(1.3 m/s)²

KE = 0.456 J

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what is the speed in km/hr of a car traveling 144 km in 90 minutes?

Answers

Answer

  96mph

Explanation:

You are given "144 miles in 90 minutes" and what you need to figure out is "144 km in X hours." To go from 90 min to hours, you can do 90 min * 1hr/60min = 1.5 hrs or 144 km in 1.5 hrs or 144 km per 1.5 hours. 144/1.5 = 96.

why is thouching the live wire of an appliane when it is connecfed to the mains dangerous

Answers

Answer: The live wire is the most dangerous one, since it is at 230 V. it should never touch the earth wire (unless the insulation is between them, of course!), because this would make a complete circuit from your mains supply to the ground (earth). A shock or fire would be highly likely.

Explanation:

(b) You have 50.0 m3
of an ideal gas at 1000.0 Pa and heat the gas until it expands to a volume of 300.0 m3
. How
much work did the gas do? [4]

Answers

The amount of work done by the ideal gas is 2475J.

How to calculate work done?

The magnitude of the work done when a gas expands is therefore equal to the product of the pressure of the gas times the change in the volume of the gas.

w=−PΔV

The negative sign associated with the above equation indicates that the system loses energy. If the volume increases at constant pressure (ΔV > 0), the work done by the system is negative, indicating that a system has lost energy by performing work on its surroundings.

According to this question, an ideal gas initially at 50.0m³ at 1000.0 Pa expands to a volume of 300.0 m³ after heating. The work done can be calculated as follows:

W = -P∆V

W = - (0.0099 × {300000L - 50000L)

W = - (0.0099 × 250000)

W = 2475J

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A chocolate bar has nutritional energy content of 100KJ. If an 50kg mountain climber eats this chocolate bar and converts it all to potential energy. What altitude(height) can she climb on a mountain using this energy? Consider g=10m/s^2

Answers

Answer:

h = 200 m

Explanation:

The energy content of the chocolate is completely converted to the potential energy of the climber. Therefore:

\(Energy\ of\ Chocolate = Potential\ Energy\\Energy\ of\ Chocolate = mgh\)

where,

m = mass of climber = 50 kg

Energy of Chocolate = 100 KJ = 100000 J

g = acceleration due to gravity = 10 m/s²

h = height = ?

Therefore,

\(100000\ J = (50\ kg)(10\ m/s^2)h\\\\h = \frac{100000\ J}{500\ N}\)

h = 200 m

A 5 Kg mass is suspended from a spring. The spring is stretched 8 cm from equilibrium. What is the spring constant? Use g=9.8 m/s^2 to calculate the force of the load

Answers

The spring constant is:

                                             \(\Large\displaystyle\text{$\begin{aligned}k &= 612.5\ \dfrac{\text{N}}{\text{m}}\end{aligned}$}\)

To calculate the spring constant we must remember the law for it, the Hooke's Law:

                                            \(\Large\displaystyle\text{$\begin{aligned}\vec{F} = -k\Delta \vec{x} \end{aligned}$}\)

Where k is the spring constant [N/m].

So if the mass is suspended it means that its weight is equal to the elastic force (values), then we can write:

                                           \(\Large\displaystyle\text{$\begin{aligned}\vec{W} = k\Delta \vec{x} \end{aligned}$}\)

Therefore:

                                          \(\Large\displaystyle\text{$\begin{aligned}mg &= k\Delta x \\ \\k &= \dfrac{mg}{\Delta x} \\ \\\end{aligned}$}\)

Now we just have to put the values and calculate:

                                              \(\Large\displaystyle\text{$\begin{aligned}k &= \dfrac{mg}{\Delta x} \\ \\k &= \dfrac{5\cdot 9.8}{0.08} \\ \\k &= 612.5\ \dfrac{\text{N}}{\text{m}}\end{aligned}$}\)

I hope you liked it

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A 5 Kg mass is suspended from a spring. The spring is stretched 8 cm from equilibrium. What is the spring

in general, populations living between 0° and 20°N latitude have the darkest skin color. true or false?

Answers

True, populations living between 0° and 20°N latitude generally have the darkest skin color. This observation is primarily due to the intensity of ultraviolet (UV) radiation that these regions receive from the sun.

Darker skin provides more protection from UV radiation, thanks to higher levels of melanin, which is a pigment that absorbs and dissipates UV radiation.
Living close to the equator (0° latitude) exposes populations to more direct sunlight, leading to stronger UV radiation. This necessitates increased melanin production for protection against the potential damaging effects of UV radiation, such as skin cancer and DNA damage.
As a result, populations native to areas between 0° and 20°N latitude, including regions in Africa, Central America, and parts of Asia, tend to have darker skin. Conversely, populations living farther from the equator have lighter skin due to less exposure to UV radiation, which makes it easier for their bodies to produce vitamin D.
In conclusion, it is true that populations living between 0° and 20°N latitude generally have the darkest skin color, primarily because of the increased melanin production needed to protect against the higher levels of UV radiation they experience.

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An automobile crankshaft is 3.175 cm in diameter. A bearing on the shaft is 3.183 cm in diameter and 2.8 cm long. The bearing is lubricated with SAE 30 oil at a temperature of 365 K. Assuming that the shaft is centrally located in the bearing, determine how much heat must be removed to maintain the bearing at constant temperature. The shaft is rotating at 1700 rpm, and the viscosity of the oil is 0.01 Pa.s.

Answers

In the case, the heat must be removed to maintain the bearing at constant temperature 0.8 W

The formula used to determine how much heat must be removed to maintain the bearing at constant temperature is as follows:

Q = 3πμrv/(D1 - D2),

where

Q is the amount of heat removed,

μ is the viscosity of the oil,

r is the radius of the shaft,

v is the velocity of the shaft,

D1 is the diameter of the shaft,

D2 is the diameter of the bearing,

v = (2πnr)/60,

where n is the rotation rate in revolutions per minute (rpm). Given that the crankshaft is 3.175 cm in diameter, D1 = 3.175 cm. Also, the bearing is 3.183 cm in diameter, and the length is 2.8 cm. The radius of the bearing is

r = (3.183 - 3.175)/2

r = 0.004 cm.

The shaft rotates at 1700 rpm, sov = (2π × 1700 × 3.175)/60 = 56.06 cm/s.

μ = 0.01 Pa.s.

Using these values,

Q = 3π(0.01)(0.004)(56.06)/(3.183 - 3.175)

Q ≈ 0.8 W, which is the amount of heat that must be removed to maintain the bearing at constant temperature.

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41 m/s is struck by a baseball bat of mass m and speed 37 m/s (in the opposite direction of the ball's motion). After the collision, the ball has initial speed u(m)=77m−6.87/m+0.11m/s Show that u' 
(m)>0 and interpret this in baseball terms. Compare u'(0.9) and u'(1.5). Round your final answer to two decimal places. u'(0.9)≈ and u'(1.5)≈ The rate at which this speed is increasing is

Answers

The velocity of the ball before and after collision as V₁ = 41m/s and V₂ = 37m/s respectively, and the mass of the ball as m.The velocity of the bat = 37m/s (opposite direction to the ball). Therefore, the relative velocity of the ball with respect to the bat, V = V₁ - V₂= 41 - 37 = 4 m/s.The coefficient of restitution (e) is defined as the ratio of the relative velocity of separation to the relative velocity of approach.e = V₂’ - V₁’ / V₁ - V₂, where V₂’ and V₁’ are the velocities of the ball and bat after collision.e = V₂’ / V₁ = (77 - 0.11m) / 37, V₂’ = (77 - 0.11m)  37 / 37 = 77 - 0.11m.

The velocity of the ball is u(m) = 77 - 6.87/m + 0.11m/s.Understanding:

To show that u’ (m) > 0, we need to find the derivative of u(m) with respect to m. That is, u’(m) > 0 if and only if du(m) / dm > 0.

Calculation:

u(m) = 77 - 6.87/m + 0.11m/s∴ u’(m) = 6.87/m² + 0.11From the above equation, it is evident that u’(m) > 0 because m² > 0. Therefore, the velocity of the ball increases with increasing mass m.

Interpretation:

In baseball terms, when the mass of the ball increases, the velocity of the ball also increases.

A ball with higher velocity can travel farther when hit with a bat. Therefore, it is always an advantage to use a heavier ball.u’(0.9) = 8.81 m⁻²/s, u’(1.5) = 5.60 m⁻²/sRate of increase of speed is u’(m).Answer:u’(0.9) ≈ 8.81 m⁻²/s, u’(1.5) ≈ 5.60 m⁻²/s.The rate at which this speed is increasing is u’(m).

About Velocity

Velocity is a foreign term that means speed. Speed ​​is the locking of an object every single unit of time. Acceleration or acceleration is the change in velocity in a certain unit of time. The acceleration of an object is caused by a force acting on the object, as explained in Newton's second law. The SI unit for acceleration is meters per second squared (m s−2). What is the difference between speed and pace? Velocity or speed is the quotient between the distance traveled and the time interval. Velocity or speed is a scalar quantity. Speed ​​​​or speed is the result of separation with an interval. Speed ​​or velocity is a vector quantity.

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pls help Demarius is at the bottom of a hill. The hill has an upward slope of 13.5above horizontal. When Demarius has walked 955 meters along this slope, how much elevation has he gained?

a.255 m
b.955 m
c.929 m
d.223 m

Answers

Demarius has gained an elevation of 233 m. Option D.

Elevation calculation

To solve this problem, we can use trigonometry. Let's call the elevation Demarius has gained "h". Then, we can use the following trigonometric relationship:

tan θ = h / d

where θ is the angle of the slope (13.5°), and d is the distance Demarius has walked along the slope (955 m).

Rearranging this equation to solve for h, we get:

h = d * tan θ

Substituting the values we know, we get:

h = 955 m * tan 13.5°

h ≈ 223 m

Therefore, Demarius has gained approximately 223 meters in elevation.

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rearrange the equation d=vt-1/2at^2 to find v

Answers

Explanation:

This is the formula for the change in distance (δx) of an object moving with constant acceleration (a) and initial velocity (v), one of the standard Equations of motion. To solve for t first rearrange

12at2+vt−δx=0

then apply the formula for solving a Quadratic equation if our equation is At2+Bt+C=0 then the solution is

t=−B±B2−4AC√2A,

here A=12a, B=v, C=−δx so plugging these in the formula gives

t=−v±✓v2−4(12a)(−δx)√2(12a) (Apply quandriatic equation)

simplifying

t=−v±v2+2aδx√a.

Note how there are two possible solutions one corresponding to the + and one to the -. Sometimes one of these will give a negative time, so you may want to eliminate that. Indeed if δx>0, v>0 and a>0 we only want the positive solution. In other cases you may want to consider both solutions, for instance if we thow a ball up in the air the initial velocity is positive and the acceleration is negative, it will pass a fixed height above your head twice, once on the way up and once on the way down.

terms used to measure motion

Answers

Answer:

velocity term

Explanation:

Answer:velocity term

Explanation:

True or False: A chemical reaction always happens when two substances are combined. (please help fast this is a test)

Answers

Answer:

no not always sometimes they react at all so false I hope I helped :)

Answer:probably false

Explanation:

Every time you mix two substances it doesn’t mean it’s going to have a reaction, they have to be two substances that don’t combine. I really hope this helps

. ASSERTION: WHEN ASTRONAUTS THROW SOMETHING IN SPACE, THAT OBJECT WOULD CONTINUE MOVING IN THE SAME DIRECTION AND WITH THE SAME SPEED. REASON: THE ACCELERATION OF AN OBJECT PRODUCED BY A NET APPLIED FORCE IS DIRECTLY RELATED TO THE MAGNITUDE OF THE FORCE, AND INVERSELY RELATED TO THE MASS OF THE OBJECT.

Answers

Both the assertion and the reason given are true.If the mass of the object is less, the acceleration produced by the force will be more. Hence, the acceleration produced by the force is directly proportional to the magnitude of the force and inversely proportional to the mass of the object.

The given assertion: When astronauts throw something in space, that object would continue moving in the same direction and with the same speed; and the given reason: The acceleration of an object produced by a net applied force is directly related to the magnitude of the force, and inversely related to the mass of the object are both correct.Astronauts are capable of throwing objects in space because they are beyond Earth's gravity and do not have to deal with any significant air resistance. In the absence of other forces like friction or air resistance, the initial velocity will be conserved, and the object will continue to move with the same speed and direction. The object would continue to move in a straight line with the same speed because no external force acts on it to change the object's state of motion.Newton's second law states that the force of an object is directly proportional to its acceleration, but inversely proportional to its mass. F=ma, where F is force, m is mass, and a is acceleration. Therefore, if the mass of the object is less, the acceleration produced by the force will be more. Hence, the acceleration produced by the force is directly proportional to the magnitude of the force and inversely proportional to the mass of the object.

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Analyze the formula FG = mg to explain how an object's weight can change even when its 'mass remains constant.

Analyze the formula FG = mg to explain how an object's weight can change even when its 'mass remains

Answers

Weight is the gravitational attraction that an object experiences. The mass of an item remains constant, but its weight might vary based on the amount of gravity acts on it.

The mass of the item has a direct relationship with the gravitational force (FG) and may be determined by applying the formula FG=mg.

The weight, mass, and gravitational force that are applied to an object are represented in the formula FG=mg by the letters FG, m, and g. FG varies if gravity changes, even though the mass remains constant.

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a car of mass 1850 kg is traveling at 22.5 m/s in a straight line. a truck of mass 3170 kg has the same momentum as the car. the speed of the truck is

Answers

A car of mass 1850 kg is traveling at 22.5 m/s in a straight line. A truck of mass 3170 kg has the same momentum as a car. The speed of the truck is 13.43 m/s.

How to solve momentum and speed-related problems?

Momentum and speed-related problems can be solved by using the formula, p= mv. The momentum of an object is defined as the product of its mass and velocity.

The formula for the speed of an object is given by,

speed = distance/time.

To solve this problem, we will equate the momentum of the car with the momentum of the truck.

the momentum of car = momentum of truck

                            m₁v₁ = m₂v₂

where m₁ = 1850 kg, v₁ = 22.5 m/s, m₂ = 3170 kg and v₂ = speed of truck

Substituting the given values in the above equation, we get

1850 × 22.5 = 3170 × v₂

v₂ = 41250/3170

v₂ = 13.43 m/s

Therefore, the speed of the truck is 13.43 m/s.

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Why is an object’s mass, rather than its weight, used to indicate the amount of matter it contains?.

Answers

The mass of an object indicate the amount of matter it contains, and the weight is a force that results from the action of gravity on the mass of the object.

When we are referring to the amount of matter that a body or an object contain we should use the magnitude of the mass and not the weight that is because the weight is a force.

What is weight?

It is the physical magnitude that expresses the force exerted by gravity on the mass of a body, this is expressed in units of the international system in Newton.

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Why is an objects mass, rather than its weight, used to indicate the amount of matter it contains?.

what is the acceleration ar(t) of the rod? take m to be the mass of the rod. express your answer as a function of v , b , the velocity of the rod vr(t) , l , r , and the mass of the rod m .

Answers

Let's consider the forces acting on the rod. The gravitational force acting on the center of mass of the rod is mg, where g is the acceleration due to gravity. The force due to air resistance is bv, where b is the air resistance coefficient and v is the velocity of the rod. The force acting on the rod is given by F = ma, where a is the acceleration of the rod.

Since the rod is rotating about its pivot, there is also a torque acting on the rod. The torque τ is given by τ = Iα, where I is the moment of inertia of the rod about its pivot and α is the angular acceleration of the rod. For a thin rod rotating about its center of mass, I = (1/12)ml^2, where m is the mass of the rod and l is its length.

The torque τ is also given by τ = r × F, where r is the distance from the pivot to the point where the force is applied. Since the force F is acting at the center of mass of the rod, r = (1/2)l.

Equating the two expressions for τ, we get:

Iα = r × F

Substituting the values of I and r, we get:

(1/12)ml^2α = (1/2)(l/2) × F

Simplifying, we get:

α = (6F)/(ml)

The angular acceleration α is related to the linear acceleration a by a = rα, where r is the distance from the pivot to the point where the force is applied. Since the force is acting at the center of mass of the rod, r = (1/2)l.

Therefore, we have:

a = (1/2)lα

Substituting the value of α, we get:

a = (3F)/(ml)

The net force acting on the rod is given by:

Fnet = F - bv - mg

Substituting the value of F from the expression for τ, we get:

Fnet = (τ/(l/2)) - bv - mg

Substituting the value of α, we get:

Fnet = (6mla/(l^2)) - bv - mg

Simplifying, we get:

Fnet = (6a/l) - bv - mg

Therefore, the acceleration of the rod is given by:

a = (1/m)((6/l)Fnet + bv + mg)

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why is the roof of the hearst tower designed to collect rainwater? check all that apply.

Answers

The roof of the Hearst Tower is designed to collect rainwater for several reasons, including sustainability and environmental considerations.

Here's an explanation of why rainwater collection is incorporated into the design:
1. To reduce stormwater runoff: By collecting rainwater, the roof helps prevent excess water from overwhelming the city's sewer system and contributing to flooding.
2. To conserve water resources: The collected rainwater can be used for various purposes within the building, such as irrigation, flushing toilets, or cooling systems, reducing the demand for freshwater resources.
3. To promote sustainable architecture: The Hearst Tower is designed with environmental sustainability in mind, and rainwater collection is one of the many green features incorporated into its design.

In summary, the roof of the Hearst Tower is designed to collect rainwater to reduce stormwater runoff, conserve water resources, and promote sustainable architecture.

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Which statement BEST describes the relationship between our Solar System and the Milky Way galaxy?
A)Our Solar System is located in the center of the Milky Way galaxy.
B)The Milky Way galaxy is located in the center of our Solar System.
C)The Milky Way galaxy is located in the outer area of one of the orbits in our Solar System.
D)Our Solar System is located in the outer area of one of the spiral arms of the Milky Way galaxy.

Answers

Answer:

D)Our Solar System is located in the outer area of one of the spiral arms of the Milky Way galaxy.

Explanation:

Our solar system is one of millions of solar systems found in our galaxy, the Milky Way.

Hope that helps!

Have a great day! :D

The relationship between our Solar System and the Milky Way galaxy is option d. Our Solar System is located in the outer area.

Relationship between our Solar System and the Milky Way galaxy:

The earth orbited the sun, so the solar system that orbited the center of the milky way.

Also, it does have solar system nearest to the 250 million for finishing the single revolution.

Hence, the option d is correct.

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The wavelength of light visible to the human eye is on the order of 5 × 10?7 m.Find the frequency of the lightwave if the speed of light in air is 2.99792 × 108 m/s.

Answers

The speed of light (c) in air is 2.99792 × 10^8 m/s, and the wavelength of visible light (λ) is 5 × 10^-7 m.

We can use the formula for the speed of light, which is:

c = λν

where ν is the frequency of the light wave.

Solving for ν, we get:

ν = c / λ

Substituting the values we have:

ν = (2.99792 × 10^8 m/s) / (5 × 10^-7 m)

ν = 5.99584 × 10^14 Hz

Therefore, the frequency of the light wave is approximately 5.99584 × 10^14 Hz.

what type of force can never do any work on an object

Answers

Hay muchos ejemplos importantes de fuerzas que no funcionan porque actúan perpendiculares al movimiento. Para el movimiento circular, la fuerza centrípeta siempre actúa en ángulo recto con el movimiento. Cambia la dirección del movimiento, pero no funciona en el objeto.

A humpback whale dove beneath the ocean's surface, and 310 seconds later it sang to
another whale that was 1,800 meters away. The song's sound wave traveled at a constant
velocity of 1,500 meters per second toward the other whale. How much time did it take the
sound wave to travel from one whale to the other?

Answers

The sound wave took 1.2 seconds to travel from one whale to the other.

Velocity is a physical quantity that describes the rate of change of an object's position with respect to time and includes both the speed and direction of motion. It is a vector quantity, meaning it has both magnitude and direction and is typically measured in meters per second (m/s) or other appropriate units.

The time it took for the sound wave to travel from one whale to the other can be calculated using the formula:

time = distance/velocity

In this case, the distance between the whales is 1,800 meters and the velocity of sound in water is 1,500 meters per second. Therefore:

time = 1,800 meters / 1,500 meters per second

time = 1.2 seconds

Hence, The distance between the two whales was covered by the sound wave in 1.2 seconds.

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A simple 15.2 cm reflecting telescope can achieve 1 second of arc resolution for visible light. Many radio telescopes study a particular radio wavelength of 21 cm. Complete parts a −d using the above information. a. Use the Raleigh criteron to determine how large a radio telescope aperature must be to achieve this resolution at 21 cm. b. Why must the aperture of a radio telescope be much larger than that of an optical telescope? c. Why is it possible to resolve two predominantly blue stars when the same telescope can not resolve two simarily separated red stars? d. In the galaxy pictures of 5 b, which photograph corresponds to the largest aperture?

Answers

a)The aperture size of the radio telescope needs to be approximately 0.27 meters b)The aperture of a radio telescope needs to be much larger than that of an optical telescope because radio waves have much longer wavelengths compared to visible light. c)the resolving power of a telescope depends on the ratio of the wavelength of light.

a. To determine the aperture size of a radio telescope to achieve a resolution at 21 cm, we can use the Rayleigh criterion, which states that the minimum resolvable separation (δθ) is given by:

δθ = 1.22 * (λ / D)

Where λ is the wavelength of the radiation and D is the diameter of the telescope's aperture.

Given that the radio wavelength is 21 cm (or 0.21 m), and we want to achieve the same resolution as the optical telescope (1 second of arc), we can rearrange the formula to solve for D:

D = 1.22 * (λ / δθ)

D = 1.22 * (0.21 m / 1 second of arc)

Calculating the result:

D ≈ 0.27 m

Therefore, the aperture size of the radio telescope needs to be approximately 0.27 meters to achieve a resolution of 1 second of arc at a wavelength of 21 cm.

b. The Rayleigh criterion tells us that the resolution of an instrument is inversely proportional to the wavelength.

Since radio waves have longer wavelengths, the telescope's aperture needs to be larger to achieve the same resolution as an optical telescope. This is because a larger aperture collects more incoming waves and allows for finer spatial detail to be resolved.

c. The ability to resolve two objects using a telescope depends on the size of the aperture relative to the wavelength of the radiation. When it comes to resolving stars, the resolving power of a telescope depends on the ratio of the wavelength of light to the size of the telescope's aperture (λ/D).

Blue light has a shorter wavelength compared to red light. Since the resolving power is directly proportional to the wavelength, a shorter wavelength of blue light allows for better resolution.

Therefore, two predominantly blue stars can be resolved because their shorter wavelength allows for finer detail to be distinguished, while the same separation between two predominantly red stars cannot be resolved due to the longer wavelength.

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how many kinds of matter are there in the universe

Answers

There are four types of matter in the universe. The four types of matter are solid, liquid, gas, and plasma.

There are several forms of matter in the universe, and all of them may be divided into four categories: solids, liquids, gases, and plasmas. The matter's composition is what distinguishes one from the other. A solid is a material that is firm and unyielding. The particles in a solid are packed together and have little movement, which gives the material its rigidity. A liquid is a material that flows and assumes the shape of its container.

The particles in a liquid are more spread out than those in a solid, but they are still close enough together to be affected by their neighbors' movements. A gas is a substance that is not solid or liquid. The particles in a gas are scattered and have little attraction to one another. As a result, a gas will spread out as much as possible to fill any container it is in. Plasma is a unique form of matter that is composed of charged particles. It is thought to be the most common form of matter in the universe, accounting for more than 99 percent of all matter in the universe.

In summary, the universe contains four distinct types of matter: solid, liquid, gas, and plasma. These categories are distinguished by the particles' composition and their interactions with one another.

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who is the richest artist in the Gambia 2020​

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Answer:

Jaliba Kuyateh is the most famous and wealthiest Gambian musician.

Which of these would have the greatest pressure?
Group of answer choices

A large balloon with few gas molecules at a high temperature

A small balloon with many gas molecules at a low temperature

A small balloon with many gas molecules at a high temperature

A large balloon with few gas molecules at a low temperature

Answers

The third one because it is a small one and it had high and high temp so it has the most modecules.

Hope this helps

Using Ohm's law, what is the current passing through a wire when the 10 V is placed across a wire with 50 Ohms? (3pts) If voltage is slowly increased, what will happen to current flow? What will the current be if that initial voltage (10 V) is used but now a longer the wire is 10x longer?

Answers

Ohm's Law is V = IR, where V is voltage, I is current, and R is resistance. To find the current passing through a wire when the 10 V is placed across a wire with 50 Ohms, we need to use the formula I = V/R.

So, I = 10 V / 50 Ω = 0.2 A. Therefore, the current passing through a wire when the 10 V is placed across a wire with 50 Ohms is 0.2 A.If voltage is slowly increased, the current flow will also increase, as per Ohm's law I = V/R. The current will increase proportionally as long as the resistance remains constant.

If the resistance changes with respect to the voltage, then the current flow will change differently. For example, if the voltage increases and the resistance also increases proportionally, then the current flow will remain the same.

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Find the change in gravitational potential energy of the following a) A box of mass 10kg which is raised 1.6 meters vertically

Answers

We are asked to determine the change in gravitational potential energy. To do that we will use the following formula:

\(\Delta U=mg\Delta h\)

Where:

\(\begin{gathered} \Delta U=\text{ change in potential energy} \\ m=\text{ mass} \\ g=\text{ acceleration of gravity} \\ \Delta h=\text{ change in height} \end{gathered}\)

The change in height is the distance that the object is raised. Therefore, plugging in the values we get:

\(\Delta U=(10kg)(9.8\frac{m}{s^2})(1.6m)\)

Solving the operations:

\(\Delta U=156.8J\)

Therefore, the change in gravitational potential energy is 156.8 Joules.

opacity of the lens of the eye that impairs vision and can cause blindness is called

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The opacity of the lens of the eye that impairs vision and can cause blindness is called cataract. Cataract refers to the clouding or opacification of the natural lens of the eye, which leads to a progressive decline in vision.

Cataracts commonly develop as a result of aging, but they can also be caused by factors such as trauma, certain medications, systemic diseases (e.g., diabetes), or genetic predisposition. Cataract surgery, which involves the removal of the cloudy lens and replacement with an artificial intraocular lens, is an effective treatment for cataracts, restoring clear vision for many individuals. It occurs when proteins in the lens clump together, causing the lens to become less transparent. This clouding obstructs the passage of light, resulting in blurred or distorted vision. If left untreated, cataracts can eventually lead to severe vision loss and even blindness.

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