The 0.100 kg sphere in (Figure 1) is released from rest at the position shown in the sketch, with its center 0.400 m from the center of the 5.00 kg mass. Assume that the only forces on the 0.100 kg sphere are the gravitational forces exerted by the other two spheres and that the 5.00 kg and 10.0 kg spheres are held in place at their initial positions.
Answers
Answer:
the speed of 0.10 sphere when it is moved to 0.20 kg to the left is : \(3.3337*10^{-5} \ m/s\)
Explanation:
Using the expression of the Change in Gravitational Potential Energy:
\(U= -(\frac{ Gm_1m_2 }{r_2} - \frac{ Gm_1m_2 }{r_1}) \\ \\ U=Gm_1m_2 (\frac{ 1 }{r_2} - \frac{ 1 }{r_1})\)
So when the sphere exerts just 10 kg mass; the change in the gravitational potential energy is :
\(U_1=Gm_1m_2 (\frac{ 1 }{r_2} - \frac{ 1 }{r_1})\)
\(U_1=6.67*10^{-11}*0.1 \ kg*10 \ kg(\frac{ 1 }{0.6 \ m} - \frac{ 1 }{0.8 \ m})\)
\(U_1 = 2.778*10^{-11} J\)
the change in the gravitational potential energy when the sphere exerts just 5 kg mass is ;
\(U_2=Gm_1m_2 (\frac{ 1 }{r_2} - \frac{ 1 }{r_1})\)
\(U_2=6.67*10^{-11}*0.1 \ kg*5 \ kg(\frac{ 1 }{0.4 \ m} - \frac{ 1 }{0.2 \ m})\)
\(U_2 = -8.335*10^{-11} J\)
The net total change is:
\(U_{total } = U_1 +U_2\)
\(U_{total} = 2.778*10^{-11} + (-8.335*10^{-11})\)
\(U_{total} = -5.557*10^{-11}\)
We all know that for there to be a balance ;loss of gravitational potential energy must be equal to the gain in kinetic energy .
SO;
K.E = \(5.557*10^{-11}\)
\(\frac{1}{2}mv^2 = 5.557*10^{-11}\)
\(v^2 = \frac{2*5.557*10^{-11} \ J}{m_1}\)
\(v=\sqrt{ \frac{2*5.557*10^{-11} \ J}{0. 1 \kg}\)
v = \(3.3337*10^{-5} \ m/s\)
Thus, the speed of 0.10 sphere when it is moved to 0.20 kg to the left is : \(3.3337*10^{-5} \ m/s\)
The speed of 0.10 sphere when it is moved to 0.20 kg to the left is :3.3337 *10^-5 m/s
What is speed ?The speed of any object is defined as the movement of any object with respect to the time.
By using the expression of the Change in Gravitational Potential Energy:
\(U=-Gm_1m_2(\dfrac{1}{r_2}-\dfrac{1}{r_1})\)\(U_2=-Gm_1m_2(\dfrac{1}{r_2}-\dfrac{1}{r_1})\)
So when the sphere exerts just 10 kg mass; the change in the gravitational potential energy is :
\(U_1=-Gm_1m_2(\dfrac{1}{r_2}-\dfrac{1}{r_1})\)
\(U_1=- 6.67\times 10^{-11}\times 0.1\times 10(\dfrac{1}{0.6}-\dfrac{1}{0.8})\)
\(U_1=2.778\times 10^{-11]\)
The change in the gravitational potential energy when the sphere exerts just 5 kg mass is ;
\(U_2=-Gm_1m_2(\dfrac{1}{r_2}-\dfrac{1}{r_1})\)
\(U_2=- 6.67\times 10^{-11}\times 0.1\times 5(\dfrac{1}{0.4}-\dfrac{1}{0.2})\)
\(U_2=-8.335\times 10^{-11}\ J\)
The net total change is:
\(U_{total}=U_1+U_2\)
\(U_{total}=2.778\times 10^{-11}+(-8.335\times 10^{-11})\)
\(U_{tot\leq al}=-5.557\times 10^{-11}\)
We all know that for there to be a balance ;loss of gravitational potential energy must be equal to the gain in kinetic energy .
SO;
\(\rm KE=5.557\times 10^{-11}\)
\(\dfrac{1}{2}mv^2=5.557\times 10^{-11}\)
\(v^2=\dfrac{2\times 5.557\times 10^{-11}}{m}\)
\(v=\sqrt{\dfrac{2\times 5.557\times 10^{-11}}{m}}\)
\(v=3.337\times 10^{-5}\ \frac{m}{s}\)
Thus, the speed of 0.10 sphere when it is moved to 0.20 kg to the left is : \(v=3.337\times 10^{-5}\ \frac{m}{s}\)
To know more about speed follow
https://brainly.com/question/4931057
Related Questions
Which two chemical equations show double-replacement reactions?
A. C+02 - CO2
B. 2Li + CaCl2 - 2LiCl + Ca
I C. Ca(OH)2 + H2S04 - CaSO4 + 2H20
D. Na2CO3 + H2S - H2CO3 + Na2S
Answers
The two chemical equations show double-replacement reactions are Ca(OH)2 + H2S04 - CaSO4 + 2H20 and Na2CO3 + H2S - H2CO3 + Na2S.
What is double replacement reaction?A double replacement reaction have two ionic compounds that are exchanging anions or cations.
From the given options, we can choose the following based on their exchange of anions or cations.
Ca(OH)2 + H2S04 - CaSO4 + 2H20Na2CO3 + H2S - H2CO3 + Na2SThus, the two chemical equations show double-replacement reactions are Ca(OH)2 + H2S04 - CaSO4 + 2H20 and Na2CO3 + H2S - H2CO3 + Na2S.
Learn more about double replacement reaction here: https://brainly.com/question/14281077
#SPJ2
With the maximum speed of 40 miles/hr (17.9 m/s) of your car, you can make a turn without slipping at one of the intersections near your home on a normal day. if it is raining, the road is wet and static friction is half of the normal static friction and the kinetic friction is 1/3 of normal kinetic friction. What is the maximum velocity you should have to avoid the slipping at the same intersection?
Answers
In the case of rain, the static friction is halved, meaning the new static friction coefficient is 0.5μs, while the kinetic friction is reduced to one-third, resulting in a new kinetic friction coefficient of (1/3)μk.
To determine the maximum velocity at which you can make a turn without slipping in the rain at the intersection, we need to consider the changes in friction.
Let's assume the normal static friction and normal kinetic friction are represented by μs and μk, respectively.
In the case of rain, the static friction is halved, meaning the new static friction coefficient is 0.5μs, while the kinetic friction is reduced to one-third, resulting in a new kinetic friction coefficient of (1/3)μk.
To avoid slipping during the turn, we need to ensure that the centripetal force required for the turn is less than or equal to the maximum frictional force available.
The centripetal force is given by the equation mv²/r, where m is the mass, v is the velocity, and r is the radius of the turn.
The maximum frictional force in the rain can be calculated as (0.5μs)mg, where g is the acceleration due to gravity.
Thus, to avoid slipping, we set the centripetal force equal to the maximum frictional force:
mv²/r = (0.5μs)mg
Simplifying the equation, we find:
v = √(0.5μsgr)
By plugging in the values for μs, g, and the radius of the turn, we can calculate the maximum velocity.
For more such questions on static friction
https://brainly.com/question/20595261
#SPJ8
A hypothesis is
a type of research method that involves experimentation
a statement describing the actual outcome of an experiment
the question that forms the foundation for a particular study
a statement describing what the researchers expect to find in a study
Help plz
Answers
Answer:
A hypothesis is a tentative statement about the relationship between two or more variables. It is a specific, testable prediction about what you expect to happen in a study.
A hypothesis is a tentative statement about the relationship between two or more variables. is a specific, testable prediction about what you expect to happen in a study.
Explanation:
This is answer
Answer:
hey there
hypothesis is a proposed explanation for a phenomenon. For a hypothesis to be a scientific hypothesis, the scientific method requires that one can test it. Scientists generally base scientific hypotheses on previous observations that cannot satisfactorily be explained with the available scientific theories
Explanation:
hope it helps
have a nice day : )
A weightlifter curls a 25 kg bar, raising it each time a distance of 0.50 m. How many times must he repeat this exercise to burn off the energy in one slice of pizza? Assume 25% efficiency. Energy content of one slice of pizza is 1260 kJ .
Answers
42 times must he repeat this exercise to burn off the energy in one slice of pizza.
What is energy?
Energy is the ability or capability to do tasks, such as the ability to move an item (of a certain mass) by exerting force. Energy can exist in many different forms, including electrical, mechanical, chemical, thermal, or nuclear, and it can change its form.
Energy burn by the weightlifter = potential energy
Potential energy = mgh
Potential energy = 25.(9.8)(0.50)
Potential energy = 122.5 Joule.
Assume 25% of efficiency so energy burn = 122.5*25/100
energy burn = 30.625 joule
Number of times = 1260/30.625
Number of times = 42 times.
42 times must he repeat this exercise to burn off the energy in one slice of pizza.
To learn more about energy refer to the link:
brainly.com/question/1932868
#SPJ1
A 0.1 kg tennis ball is brought from a speed of 15 m/s to a speed of 45 m/s when hit by a tennis racket. If this done over 0.05 seconds, what is the power generated by the tennis racket
Answers
Two forces are written as follows: Fap and For. H symbolizes your hand and D symbolizes a dog. Draw your hand petting a dog in the space that follows, and represent the two forces on your drawing. How would vou describe the two forces in words?
Answers
Answer:
Since the two forces are represented by Fap and For, we can assume that Fap refers to the force applied by your hand on the dog while petting it, and For refers to the equal and opposite force applied by the dog's body on your hand.
The diagram showing your hand petting a dog would look something like this:
```
____
/ \
/ \
/ D \
/ \
/____________\
H
```
In this diagram, the force Fap is represented by an arrow pointing from your hand towards the dog's body, and the force For is represented by an arrow pointing in the opposite direction, from the dog's body towards your hand.
We can describe the two forces as follows:
- Fap: The force applied by your hand on the dog's body while petting it.
- For: The equal and opposite force applied by the dog's body on your hand, according to Newton's third law of motion.
A rock weighing 6 Newton’s is lifted 2 meters. How much work is done?
Answers
Answer:
12 Joules
Explanation:
I believe a Joule is a Newton meter, and work is represented in joules, so 6 N * 2m = 12 Nm (joules)
When a species has no members left that are alive
Answers
Answer:
it means that species is extinct.
Explanation:
have a good day :)
Calculate the time required for a 6000-newton net force to stop a 1200-kilogram car initially traveling at 10 meters per second. [Show all work, including the equation and substitution with units.]
Answers
Answer:
To solve this problem, we will use the equation for the net force on an object, which is:
net force = mass x acceleration
We can rearrange this equation to solve for acceleration:
acceleration = net force / mass
Once we have the acceleration, we can use the equation for the motion of an object under constant acceleration:
final velocity^2 = initial velocity^2 + 2 x acceleration x distance
We can rearrange this equation to solve for the distance required to stop the car:
distance = initial velocity^2 / (2 x acceleration)
Finally, we can use the equation for average velocity to calculate the time required to travel this distance:
time = distance / average velocity
Substituting the given values into the equations:
net force = 6000 N
mass = 1200 kg
initial velocity = 10 m/s
Using the first equation:
acceleration = net force / mass
acceleration = 6000 N / 1200 kg
acceleration = 5 m/s^2
Using the second equation:
distance = initial velocity^2 / (2 x acceleration)
distance = 10 m/s^2 / (2 x 5 m/s^2)
distance = 10 m
Using the third equation:
average velocity = (initial velocity + final velocity) / 2
final velocity = 0 (since the car is coming to a stop)
average velocity = 10 m/s / 2
average velocity = 5 m/s
Using the fourth equation:
time = distance / average velocity
time = 10 m / 5 m/s
time = 2 seconds
Therefore, the time required for a 6000-newton net force to stop a 1200-kilogram car initially traveling at 10 meters per second is 2 seconds.
Question 10 (1 point)
A water wave in a 17 m long pool takes 3 seconds to travel to one end of the pool.
What is the speed of the wave?
Answers
Answer:
5.67 m/s
Explanation:
The speed of a wave can be calculated as the distance traveled by the wave divided by the time taken:
Speed = Distance/Time
In this case, the distance traveled by the wave is the length of the pool, which is 17 m. The time taken by the wave to travel this distance is 3 seconds.
So, the speed of the wave can be calculated as:
Speed = 17 m/3 s
Speed = 5.67 m/s
Therefore, the speed of the water wave in the 17 m long pool is 5.67 m/s.
You are designing an airplane propeller that is to turn at 2400 rpm (Fig. 9.13a). The forward airspeed of the plane is to be 75.0 m/s 75.0 m/s, and the speed of the propeller tips through the air must not exceed 270 m/s 270 m/s. (This is about 80% of the speed of sound in air. If the propeller tips moved faster, they would produce a lot of noise.) What is the maximum possible propeller radius?
Answers
Answer:
r = 1.07 m
Explanation:
The maximum radius of the propeller that can be allowed is given by the following formula:
\(v = r\omega\\\\r = \frac{v}{\omega}\)
where,
r = maximum possible radius of the propeller = ?
v = maximum possible linear speed of the propeller = 270 m/s
ω = angular speed of the propeller = (2400 rpm)(2π rad/1 rev)(1 min/60 s)
ω = 251.33 rad/s
Therefore,
\(r = \frac{270\ m/s}{251.33\ rad/s}\)
r = 1.07 m
what is the equation for Kepler's 3rd law
Answers
A monk is sitting atop a mountain in complete rest in meditation. What is the Kinetic
Energy of the monk? (assume mass of 65 kg and the mountain's height was 1000 m)
4,225,000
No Kinetic Energy - because there is no movement
637,000
65.000
Answers
Answer:
No kinetic energy-because there is no movement
Explanation:
It states that the monk is at complete rest so there is no movement.
What is the answer to this question number 2?
Answers
Answer:
1⁺ ion
Explanation:
Metals in the first group on the periodic table will prefer to form 1⁺ ion. This is because the 1 valence electron in their orbital.
Most metals are electropositive and would prefer to lose electrons than to gain it.
Like all metals, the group 1 elements called the alkali metals would prefer to lose and electron.
On losing an electron the number of protons is then greater than the number of electrons. This leaves a net positive charge.
Part C Now, grab Tracker’s protractor tool (the green angle in the video frame) and measure the angle of incidence and the angle of refraction for the frame numbers specified in the table below. Hints: To advance the video a frame at a time, use the step buttons on the right. Position the vertex of the protractor exactly at the origin of the coordinate axis. Move the arms of the protractor so that one arm is on the vertical axis (above or below, as appropriate) and the other on the light ray.
Answers
In order to measure the angle of incidence and the angle of refraction using Tracker's protractor tool (the green angle in the video frame), the following steps should be followed:
Step 1: Open the video in Tracker software.
Step 2: Click on the "Measure" button on the toolbar at the top of the software.
Step 3: From the dropdown menu, select "Angle".
Step 4: Click on the "protractor tool" icon (the green angle in the video frame).
Step 5: Position the vertex of the protractor exactly at the origin of the coordinate axis and move the arms of the protractor so that one arm is on the vertical axis (above or below, as appropriate) and the other on the light ray.
Step 6: Measure the angle of incidence and the angle of refraction for the frame numbers specified in the table below by using the step buttons on the right to advance the video a frame at a time.
Step 7: Record the measured angles in the table below. Note that the angle of incidence should be measured on the incident ray (the ray that is coming from the left), and the angle of refraction should be measured on the refracted ray (the ray that is coming from the right).In conclusion, by following these steps, one can measure the angle of incidence and the angle of refraction using Tracker's protractor tool.
For more question Tracker’s protractor tool.
https://brainly.com/question/16772121
#SPJ8
What can result if. An earthquake cause sudden vertical change in the sea floor?
Answers
Answer:
A Tsunami would occur.
Heather and Jerry are standing on a bridge 46 m
above a river. Heather throws a rock straight down with a speed of 14 m/s
. Jerry, at exactly the same instant of time, throws a rock straight up with the same speed. Ignore air resistance. How much time elapses between the first splash and the second splash?
Answers
The time elapsed between the first splash and the second splash is approximately 0.69 seconds.
To calculate this, we consider the motion of two rocks thrown simultaneously from a bridge. Heather throws a rock straight down with a speed of 14 m/s, while Jerry throws a rock straight up with the same speed.
We use the equation for displacement in uniformly accelerated motion: s = ut + (1/2)at^2.
For Heather's rock, which is thrown downwards, the initial velocity (u) is positive and the acceleration (a) due to gravity is negative (-9.8 m/s^2). The displacement (s) is the height of the bridge (46 m).
Solving the equation, we find two possible values for the time (t): t ≈ -4.91 s and t ≈ 1.91 s.
Since time cannot be negative in this context, we discard the negative value and consider t ≈ 1.91 s as the time it takes for Heather's rock to hit the water.
For Jerry's rock, thrown upwards, we use the same equation with the same initial velocity and acceleration. The displacement is also the height of the bridge, but negative.
Solving the equation, we find t ≈ -5.68 s and t ≈ 1.22 s. Again, we discard the negative value and consider t ≈ 1.22 s as the time it takes for Jerry's rock to reach its maximum height before falling back down.
To find the time difference between the first and second splash, we subtract t ≈ 1.91 s (Heather's rock) from t ≈ 1.22 s (Jerry's rock). This gives us a time difference of approximately 0.69 seconds.
Therefore, the time elapsed between the first splash and the second splash is approximately 0.69 seconds.
For more such questions on time elapsed, click on:
https://brainly.com/question/31287589
#SPJ8
An atom with four protons and four electrons is in equilibrium. An electron is added. What is the overall charge of the atom?
Answers
The overall charge of the atom after an electron is added is -1.
An ion is an atom or molecule that has an unequal number of protons and electrons, resulting in a net electrical charge. Atoms are normally electrically neutral because the number of protons, which carry a positive charge, is equal to the number of electrons, which carry a negative charge. However, when an atom gains or loses one or more electrons, it becomes an ion with a net electrical charge.
When an atom loses one or more electrons, it becomes a positively charged ion, or cation, since the number of positively charged protons is greater than the number of negatively charged electrons. On the other hand, when an atom gains one or more electrons, it becomes a negatively charged ion, or anion, since the number of negatively charged electrons is greater than the number of positively charged protons.
An atom with four protons and four electrons is electrically neutral since the number of positively charged protons equals the number of negatively charged electrons. When an electron is added to the atom, the number of electrons becomes five, while the number of protons remains at four. This results in a net negative charge on the atom, since the extra electron carries a negative charge.
Therefore, the overall charge of the atom after an electron is added is -1.
To learn more about electronic configuration for lead click:
https://brainly.com/question/29184975
#SPJ1
The trajectory of a ball can be computed with
y = (tan 0)x
9
2v cos² 0.
-x² + Yo
where y the height (m), 0o = the initial angle (radians), vo = the initial velocity (m/s), g = the gravitational constant = 9.81 m/s²,
and yo the initial height (m). Use the golden-section search to determine the maximum height given yo = 2 m, vo = 20 m/s,
and 80=45°. Iterate until the approximate error falls below &s=10% using initial guesses of x/= 10 m and xu = 30 m. (Round
the final answer to three decimal places.)
The maximum height is
m.
Answers
We must define a function that accepts an input parameter x and returns the associated height y in order to use the golden-section search. By entering the specified numbers for yo, vo, 0o, g, and x into the formula.
How much learning error must be set?The golden-section search algorithm can now be used to identify the value of x that maximises y. We begin by setting the error tolerance to 10% and starting with the basic hypotheses .
How can we determine the value of x that optimises y using the golden-section search algorithm?Calculate the values of x2 and x3 using the golden ratio:Evaluate the function at x2 and x3:If y2 > y3, the maximum is between x1 and x3, so we set x4 = x3 and repeat from step 1. Otherwise, the maximum is between x2 and x4, so we set x1 = x2 and repeat from step.
To know more about Trajectories visit:-
brainly.com/question/28874076
#SPJ1
Ball B is hanging from an inextensible cord. An identical ball A is released from rest when it is just touching the cord and drops through the vertical distance hA = 8 in. before striking ball B. Assuming e = 0.9 and no friction, determine the resulting maximum vertical displacement hB of ball B.
Answers
The image of the ball hanging from the chord is missing, so i have attached it.
Answer:
hb = 0.1016 m
Explanation:
We are given;
Height from which block A is dropped;hA = 8 in = 0.2032 m
Coefficient of restitution;e = 0.9
Now, let us make v_a and v_b the velocities of balls A and B respectively after collision.
If we assume that both balls have the same masses, then from conservation of momentum, v_a = -v_b
Thus;
½m(v_a)² + ½m(v_b)² = m•g•hA
m will cancel out, also, putting -v_b for v_a, we have;
½(-v_b)² + ½(v_b)² = g•hA
½(v_b² + v_b²) = g•hA
½(2v_b²) = g•hA
v_b² = g•hA
v_b = √g•hA
v_b = √(9.81 × 0.2032)
v_b = 1.412 m/s
Now, using conservation of total mechanical energy, we have;
m•g•hb = ½mv_b²
Making hb the subject, we have;
hb = ½v_b²/g
hb = 1.412²/(2 × 9.81)
hb = 0.1016 m
Each tire on a car has a radius of 0.330 m and is rotating with an angular speed of 15.6 revolutions/s. Find the linear speed v of the car, assuming that the tires are not slipping against the ground.
Answers
Answer:
v = 32.345 m/s
Explanation:
given data
radius r = 0.330 m
angular speed = 15.6 revolutions/s
solution
we will get here linear speed v, that is express as
v = r × w .....................1
here w = 17.5 × 2 × π radians
so now put value in eq1
v = 0.330 × 15.6× 2 × π
v = 32.345 m/s
The gas exchange in humans occurs in the alveoli where oxygen enters the blood stream and carbon dioxide enters the lungs for
exhalation. What major organ are alveoli located in?
O the heart
O the lungs
O the bronchi
O the brain
Answers
Answer: the lungs
Explanation: During gas exchange oxygen moves from the lungs to the bloodstream. At the same time carbon dioxide passes from the blood to the lungs. This happens in the lungs between the alveoli and a network of tiny blood vessels called capillaries, which are located in the walls of the alveoli.
Two blocks, 1 and 2, are connected by a massless string that passes over a massless pulley. 1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. 2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105
. The figure illustrates the configuration.
A system of two blocks connected by a rope passing over a pulley. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle. Box M subscript 1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M sub 1 and the surface is mu subscript 1. Box M subscript 2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle. The coefficient of friction between box M sub 2 and the surface is mu subscript 2.
Answers
The force acting on the system of two blocks connected by a rope passing over a pulley is -13.26 N.
The system of two blocks connected by a rope passing over a pulley are M1 and M2, where M1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M1 and the surface is mu subscript 1. M2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle.
The coefficient of friction between box M2 and the surface is mu subscript 2. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle.M1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. M2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.The free-body diagram of M1 shows that the weight of M1 acts straight downwards (vertically) and the normal force acts perpendicular to the slope.
The force of friction opposes the motion and acts opposite to the direction of motion.M1 = 2.25 kgTheta subscript 1 = 42.5 degreesMu subscript 1 = 0.205g = 9.81 m/s²In the free-body diagram of M2, the normal force acts perpendicular to the incline of the slope, the weight of the object acts vertically downwards and parallel to the incline, and the force of friction opposes the motion and acts opposite to the direction of motion.M2 = 5.55 kgTheta subscript 2 = 33.5 degreesMu subscript 2 = 0.105g = 9.81 m/s²The tension in the string is the same throughout the rope. Since the masses are being pulled by the same rope, the acceleration of the objects is the same as the acceleration of the rope.
The tension in the string is directly proportional to the acceleration of the objects and the rope.A system of two blocks connected by a rope passing over a pulley has a total mass of M. The acceleration of the system is given by the formula below:a = [(m1-m2)gsin(θ1) - μ1(m1+m2)gcos(θ1)] / (m1 + m2)Where, μ1 = 0.205 is the coefficient of friction of block M1θ1 = 42.5 degrees is the angle of the incline of block M1M1 = 2.25 kg is the mass of block M1M2 = 5.55 kg is the mass of block M2g = 9.81 m/s² is the acceleration due to gravitysinθ1 = sin 42.5 = 0.67cosθ1 = cos 42.5 = 0.75The acceleration of the system is:a = [(2.25-5.55)(9.81)(0.67) - (0.205)(2.25+5.55)(9.81)(0.75)] / (2.25 + 5.55)a = -1.7 m/s² (the negative sign indicates that the system is accelerating in the opposite direction).
The force acting on the system is given by:F = MaWhere M is the total mass of the system and a is the acceleration of the system. The total mass of the system is:M = m1 + m2M = 2.25 + 5.55M = 7.8 kgThe force acting on the system is:F = 7.8(-1.7)F = -13.26 N (the negative sign indicates that the force is acting in the opposite direction).
for more question on force
https://brainly.com/question/12785175
#SPJ8
In the figure, a red car and a green car, identical except for the colour, move toward each other in adjacent lanes and parallel to the xâaxis. At time t=0, the red car is at x r =0, and the green car is at x g =220m. If the red car has a constant velocity of 20km/h, the cars pass each other at x=44.5m, and if it has a constant velocity of 40km/h, they pass each other at x=76.6m. What is the constant acceleration of the green car?
Answers
The constant acceleration of the green car which passes red color car is 2.81 m/s^2.
In this problem, the initial positions of the red and green cars are xr = 0 and xg = 220 m, respectively, and their initial velocities are vr = 20 km/h and vg = 0. When the red car has a velocity of 20 km/h, the cars pass each other at x = 44.5 m, and when the red car has a velocity of 40 km/h, they pass each other at x = 76.6 m.
We can use these two equations to solve for the acceleration of the green car. First, we convert the velocities from kilometers per hour to meters per second by dividing by 3.6. This gives us vr = 5.56 m/s and vg = 0 m/s.
Then, we can substitute these values into the equation for position and solve for the acceleration. When the red car has a velocity of 20 km/h, the equation becomes:
x = 0 + 5.56t + 1/2at^2
x = 44.5
Solving for a, we find that the acceleration of the green car is a = 2.61 m/s^2.
When the red car has a velocity of 40 km/h, the equation becomes:
x = 220 + 11.11t + 1/2at^2
x = 76.6
Solving for a, we find that the acceleration of the green car is a = 2.61 m/s^2.
When the red car has a velocity of 40 km/h, the equation becomes:
x = 220 + 11.11t + 1/2at^2
x = 76.6
Solving for a, we find that the acceleration of the green car is a = 3.02 m/s^2.
Since the acceleration is the same in both cases, we can take the average of these two values to find the constant acceleration of the green car. The average of 2.61 m/s^2 and 3.02 m/s^2 is 2.81 m/s^2.
To know more about speed
https://brainly.com/question/28224010
#SPJ4
Explain how you would make a cast of a shoeprint in left in the mud
Answers
Answer:
Put some melted plastic over the print and let it harden
Explanation:
I think that's how the police do it
Which term is the product of force and distance? power work net force acceleration please help
Answers
Answer: WORK
Explanation:
Answer:
work
Explanation:
got it right on edge:p
Need help on number 5. Super complex have had tutors that can’t solve
Answers
Given
Mass of the particles,
\(\begin{gathered} m_1=10.3\text{ kg} \\ m_2=2.5\text{ kg} \\ m_3=2.7\text{ kg} \end{gathered}\)Their respective coordinates are
\(\begin{gathered} (x_1,y_1)=(-12,-5) \\ (x_2,y_2)=(4,3) \\ (x_3,y_3)=(14,1) \end{gathered}\)The angular velocity is
\(\omega=15\text{ rad/s}\)To find
Rotational kinetic energy of the system
Explanation
The moment of inertia about the y axis is
\(\begin{gathered} I=m_1x_1^2+m_2x_2^2+m_3x_3^2 \\ \Rightarrow I=10.3\times12^2+2.5\times4^2+2.7\times^14^2 \\ \Rightarrow I=2052.4\text{ kgm}^2 \end{gathered}\)The rotational kinetic energy is
\(\begin{gathered} K=\frac{1}{2}I\omega^2 \\ \Rightarrow K=\frac{1}{2}\times2052.4\times15^2 \\ \Rightarrow K=230895J \end{gathered}\)Conclusion
The rotational kinetic energy is A.230895 J
Simpson drives his car with an average velocity of 24 m/s toward the east. how long will it take him to drive 560 km on a perfectly straight highway?
Answers
Answer:
The time taken to drive on this high way is 6.48 hours
Explanation:
Given;
average velocity, v = 24 m/s
distance of travel, d = 560 km = 560,000 m
The distance traveled is given by;
\(d = (\frac{v+u}{2} )t\\\\d =( 24 \ m/s)t\\\\t = \frac{d}{24} \\\\t = \frac{560,000}{24}\\\\t = 2333.33 \ s = 6.48 \ hrs\)
Therefore, the time taken to drive on this high way is 6.48 hours
Please help me with this question.
Answers
With 20 windings, the generator will produce a higher EMF and, consequently, a larger current. This increased current will provide more power to the light bulb, resulting in a brighter illumination compared to the dim illumination observed with only 5 windings.
When you increase the number of wire windings in the generator from 5 to 20, the effect on the light bulb will be a brighter illumination. The brightness of the light bulb is directly proportional to the number of windings in the generator.
By increasing the number of windings, you are increasing the amount of wire wrapped around the magnet. This results in a higher number of turns per unit length, leading to an increased magnetic flux passing through the wire coils.
According to Faraday's law of electromagnetic induction, a change in magnetic flux induces an electromotive force (EMF) in a conductor, which in this case is the copper wire. The induced EMF causes electric current to flow through the wire, creating a flow of electrons.
The 30-W light bulb requires a certain amount of electrical power to produce its specified brightness. With 20 windings, the generator will produce a higher EMF and, consequently, a larger current. This increased current will provide more power to the light bulb, resulting in a brighter illumination compared to the dim illumination observed with only 5 windings.
For more such questions on current
https://brainly.com/question/1100341
#SPJ8
Projeche Problems
1.
A ball is kicked from the top of one building towards another building that is 15.24 m away. The
initial velocity of the ball is 6.1 m/s 40° above the horizontal. How far above or below its original
level will the ball strike the opposite wall?
Answers
the ball will strike the opposite wall 6.22 m below its original level.
To solve this problem, we need to use the equations of motion for a projectile. The horizontal and vertical components of the initial velocity are:
V₀x = V₀ cosθ = 6.1 cos(40°) = 4.65 m/s
V₀y = V₀ sinθ = 6.1 sin(40°) = 3.91 m/s
The time it takes for the ball to reach the opposite wall can be found using the horizontal distance and the horizontal component of velocity:
d = V₀x t
t = d / V₀x = 15.24 m / 4.65 m/s = 3.28 s
The vertical distance traveled by the ball can be found using the equation:
y = V₀y t - 1/2 g t²
where g is the acceleration due to gravity, which is -9.81 m/s² (negative because it acts downward). Substituting the known values, we get:
y = 3.91 m/s × 3.28 s - 1/2 × 9.81 m/s² × (3.28 s)² = 6.22 m
Therefore, the ball will strike the opposite wall 6.22 m below its original level.
learn more about equation here
https://brainly.com/question/29657983
#SPJ9