T/F: if the range of feasibility indicates that the original amount of a resource, which was 20, can increase by 5, then the amount of the resource can increase to 25.

The work function of the photosensitive material is 0.82 eV.

The minimal energy needed to remove an electron from a photosensitive

material is represented by the work function (Φ)  of the substance. In the photoelectric effect, electrons can be released from a substance when light with a high enough energy (higher than or equal to the work function) strikes it.

We must deduct the energy of the released electrons from the energy of the incident light in order to get the material's work function.

Work function (Φ) = Energy of incident light - Energy of emitted electrons

Given:

Energy of incident light = 2.53 eV

Energy of emitted electrons = 1.71 eV

Work function (Φ) = 2.53 eV - 1.71 eV

Work function (Φ) = 0.82 eV

Therefore, the work function of the photosensitive material is 0.82 eV.

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Answer:

I believe its A

Step-by-step explanation:

The adjusted cost of the dealer financing package is 5.00%. Therefore, you should accept the rebate and finance your new vehicle using your credit union loan as its cost (8.8%) is less than the adjusted cost of the dealer-arranged financing (5.00%).

To compare the dealer financing package with the credit union loan, you need to determine the adjusted cost of the dealer financing package using the given equation.

Using the given information: D = $27,690, APR = 3.5%, Y = 12 (monthly payments), P = 48 (4 years of payments), and F = $1,038.

Plugging the values into the equation:

APR = (12 * ((95 * 48) + 9) * 1038) / (12 * 48 * (48 + 1) * (4 * 27690 - 1038))
APR = (12 * (4560 + 9) * 1038) / (12 * 48 * 49 * (110760 - 1038))
APR = (12 * 4569 * 1038) / (12 * 48 * 49 * 109722)
APR = 56830384 / 257289792
APR ≈ 0.2208

To convert this to percentage, multiply by 100: 0.2208 * 100 ≈ 22.08%

Since the adjusted cost of the dealer-arranged financing package (22.08%) is higher than the credit union loan's cost (8.8%), you should accept the rebate and finance your new vehicle using your credit union loan.

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The solution set to the inequality (4x-3)(2x-1)20 is x ≤ 1/2 or x ≥ 3/4. Option C

An inequality, is a statement of an order relationship—greater than, greater than or equal to, less than, or less than or equal to—between two numbers or algebraic expressions.

(4x-3)(2x-1) ≥ 0

expanding the brackets

8x^2 - 4x - 6x + 3

8x^2 -10x +3

(8x^2 -6x) -(4x+3)

Factoring the common factors

2x(4x-3)-1(4x-3)

(2x-1)(4x-3) ≥ 0

2x-1 ≥ 0

dividing both sides by 2

x≤-1/2

4x-3≥0

Dividing both sides by 4

x≤3/4

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Answer:

1

Step-by-step explanation:

i think

Answer:

-6a -5

Step-by-step explanation:

\(-6a+3-8\)

Subtract ; +3-8 =-5

\(-6a-5\)

Answer:

\(\boxed {\tt -6a-5}\)

Step-by-step explanation:

We are given the expression:

\(-6a+3-8\)

We want to simplify the expression. Combine like terms.

In this expression, there are 2 constants, or terms without variables. The constants, 3 and -8, can be combined.

\(-6a+(3-8)\)

\(-6a+(-5)\)

\(-6a-5\)

The simplified expression is -6a-5

Answer:

x = 3

Step-by-step explanation:

y = 5x

x + y = 12

x + 5x = 12 (substitute 5x in the place of y)

6x = 12

x = 12/6

x = 3

Answer:

Step-by-step explanation:

y=5x

+5(y)=(12-x)+5  which distributing is +5y= +60-5x

y=5x

+5y=+60-5x

6y=60

y=10

10=5x

x=2

Step-by-step explanation:

The problem bothers on fractions, here we are being presented with mixed fractions.

what we are going to do bascially is to subtract the sum of all the uloaded

peat moss in sites 1 and 2 to get from the peat moss to get the remaining for the third site

therefore

\(10\frac{2}{5}-(2\frac{2}{3}+ 2\frac{1}{4})\)

we then have to convert the mixed fraction to further simplify the problem we have

\(\frac{52}{5}-(\frac{8}{3}+ \frac{9}{4})\)

we then solve the fraction to the right of the negative symbol first

\(=\frac{52}{5}-(\frac{8}{3}+ \frac{9}{4})\\\\=\frac{52}{5}-\frac{32+27}{12} \\\\=\frac{52}{5}-\frac{59}{12} \\\\\=\frac{624-295}{60} \\\\=\frac{329}{60}\)

We can now convert to mixed fraction

\(=\frac{329}{60}\\\\ =5\frac{12}{25}\)

For the third site the remainder is 5 12/25

For the given standard deviation the minimum value we would assign is 22.the maximum value we would assign is 88.

To calculate the minimum and maximum values based on the given information, we need to consider the standard deviation and the respective interest rates for the 3-year and 10-year periods.

Given:

S = 26.32 (Initial value)

E = 55 (Expected value)

t = 3 (Years)

Standard deviation = 60% (of the expected value)

3-year interest rate = 2.4%

10-year interest rate = 3.1%

To find the minimum value, we will calculate the value at the end of the 3-year period using the lowest possible growth rate.

Minimum value calculation:

Minimum value = E - (Standard deviation * E) = 55 - (0.6 * 55) = 55 - 33 = 22

Therefore, the minimum value we would assign is 22.

To find the maximum value, we will calculate the value at the end of the 10-year period using the highest possible growth rate.

Maximum value calculation:

Maximum value = E + (Standard deviation * E) = 55 + (0.6 * 55) = 55 + 33 = 88

Therefore, the maximum value we would assign is 88.

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Answer: 26

Explanation:

Answer:

\( = \sqrt{ {5}^{2} + {6}^{2} + {7}^{2} } = \sqrt{25 + 36 + 49} = \sqrt{110} = 10.48\)

Answer:

720

Step-by-step explanation:

10x9x8

Since they are picking 3 different instruments

please mark me brainliest :)

Answer:

x0.4

Step-by-step explanation:

Answer:

its c 48.08 im pretty sure

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

use a calculator next time

\($\mathbb{Q}(\sqrt{2})$\) is isomorphic to \($\mathbb{Q}[x] /(x^2-2)$\), as desired.

What is the equivalent expression?

Equivalent expressions are expressions that perform the same function despite their appearance. If two algebraic expressions are equivalent, they have the same value when we use the same variable value.

Show that \($\mathbb{Q}(\sqrt{2})$\) is isomorphic to \($\mathbb{Q}[x] /(x^2-2)$\) :

We define a function \($\phi\) : \(\mathbb{Q}[x] \to \mathbb{Q}(\sqrt{2})$\)  by \($\phi(f(x)) = f(\sqrt{2})$\).

This function is clearly a homomorphism since it preserves addition and multiplication.

Furthermore, we see that \($\phi(x^2-2) = (\sqrt{2})^2-2 = 0$\),

so the kernel of \($\phi\) contains the ideal generated by \($x^2-2$\).

By the first isomorphism theorem, there exists an isomorphism \($\operator{deg}(r) < \operator{deg}(x^2-2) = 2$\)\($\tilde{\phi} : \mathbb{Q}[x] /(x^2-2) \to\)\(\operator{im}(\phi)$.\)

It remains to show that \($\tilde{\phi}$\)  is surjective. Let \($a+b\sqrt{2} \in \mathbb{Q}(\sqrt{2})$\) be an arbitrary element. Since \($\mathbb{Q}[x]$\) is a polynomial ring, we can apply the division algorithm to find \($q(x),r(x) \in \mathbb{Q}[x]$\) such that \($a+b\sqrt{2} = q(\sqrt{2}) + r(\sqrt{2})$\)  where \($\operator{deg}(r) < \operator{deg}(x^2-2) = 2\).

But then \($r(\sqrt{2}) = a+b\sqrt{2} - q(\sqrt{2}) \in \operator{im}(\phi)\), so \($\tilde{\phi}$\) is surjective.

Therefore, \($\mathbb{Q}(\sqrt{2})$\) is isomorphic to \($\mathbb{Q}[x] /(x^2-2)$\), as desired.

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Answer

the third side can measure 2 in, 3 in, or 4 in

Explanation

inequality theorem

a + b > c

a + c > b

b + c > a

2 = a

b = 3

c = x

a + b > c

2 + 3 > x

5 > x

x= 4, 3, 2, or 1 in

a + c > b

2 + x > 3

x = 4, 3, or 2

b + c > a

3 + x > 2

x = 4, 3, or 2

Answer:

1 ,2,3,4,5,6,7,9,10,11,12 is the union

Answer:

A U B = {1,2,3,4,5,6,7,9,10,11,12}

Step-by-step explanation:

Union of sets is a set containing all elements that are in A or  B.

A = {1,3,4,5,9,10,11}

B= {2,4,6,7,11,12}

A U B = {1,2,3,4,5,6,7,9,10,11,12}

The last two digits of $9^{8^7}$ are 21.

To find the last two digits of $9^{8^7}$, we need to evaluate the exponent power from the top down. Let's start by finding $8^7$.

To find the last two digits of $8^7$, we can look for a pattern.

$8^1 = 08$
$8^2 = 64$
$8^3 = 52$
$8^4 = 16$
$8^5 = 28$
$8^6 = 24$
$8^7 = 92$

Now, we have $9^{8^7}$.

To find the last two digits of $9^{8^7}$, we can again look for a pattern.

$9^1 = 09$
$9^2 = 81$
$9^3 = 29$
$9^4 = 61$
$9^5 = 49$
$9^6 = 41$
$9^7 = 69$
$9^8 = 21$
$9^9 = 89$
$9^{10} = 01$

As we can see, the last two digits of the powers of 9 repeat in a cycle of 10. Since $8^7$ is a multiple of 4, the last two digits of $9^{8^7}$ will be the same as $9^8$, which is 21.

Therefore, the last two digits of $9^{8^7}$ are 21.

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The toy cars Anna must sell for her revenue to equal her expense is 4 toy cars. The result is obtained by using the concept of calculating algebra.

To calculate the algebra with one variable, sum up all the same variable and count the value.

Anna want to sell toy car at a craft fair. Each car is sold at a price of $ 12. The material for each car cost $ 3.50 and the table rental at the fair is 34 dollar for the day.

Find the toy cars must Anna sell for her revenue to equal her expense!

We have

Let's say

Revenue = Expense

a × $12 = (a × $3.5) + $34

12a = 3.5a + 34

12a - 3.5a = 34

8.5a = 34

a = 4 toy cars

Hence, Anna must sell 4 toy cars so that her revenue is equal to expense.

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The approximate percentage discount is equal to 25%.

Given the following data:

To calculate the approximate discount on the calculator:

First of all, we would determine the discount on the calculator by using the following mathematical expression:

\(Discount = Original\;price -Sales\;price\)

\(Discount = 89.99 -68.25\)

Discount = $21.74

Now, we can calculate the approximate percentage discount:

\(Percent\;discount = \frac{21.74}{89.99} \times 100\\\\Percent\;discount = \frac{2174}{89.99}\\\\Percent\;discount = 24.16\)

Percent discount = 25%

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Answer:

3

Step-by-step explanation:

Selina gave 2 stickers to each of her friends.

Robert bought 4 bottles of paint.

A numerical expression is a mathematical statement written in the form of numbers and unknown variables. We can form numerical expressions from statements.

Given, Selina had 21 stickers. She gave the same amount of stickers to each of her 9 friends and had 3 stickers left over.

This can be represented as,

9x + 3 = 21.

9x = 18.

x = 2.

So, she gave 2 stickers to each of her friends.

Robert went to an art supply store.

He got a pack of paintbrushes for $9 and some bottles of paint for $3 each.

His total came out to $21, before tax.

3x + 9 = 21.

3x = 12.

x = 4.

Robert bought 4 bottles of paint.

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Elements in set A is 7.

Consider the following example: If set A includes the elements, A = a, b, then the correct subset of the provided subset is, a, and b. The set has two components in this case. The formula for calculating the number of appropriate subsets is 2n – 1.

RECALL: The number of proper subsets of a set with nn elements is 2^n-12

N

−1.

Let n = number of elements of the set.$

Then,Then, 2^n-1 = 127

2^n = 127+1

2^n=128

2^n = 2^7

N=7

$The set has 7 elements.

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According to the given information in the question the element in set A is  7.

Consider the following example: If set A includes the elements, A = a, b, then the correct subset of the provided subset is, a, and b. The set has two components in this case. The formula for calculating the number of appropriate subsets is 2n – 1.

RECALL: The number of proper subsets of a set with nn elements is 2^n-12

N

−1.

Let n = number of elements of the set.$

Then, Then, 2^n-1 = 127

2^n = 127+1

2^n=128

2^n = 2^7

N=7

$The set has 7 elements.

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Answer:

Option 2 is the answer

Step-by-step explanation:

BTW not to intrude on your life, but  

I strongly suggest that kids between years old shouldn't have FF ecause it's not suitable. 

children with lack of life experience and there brain aren't fully mature yet.

Answer:

Step-by-step explanation:

Given circle:

Convert the equation into the standard form of (x - k)² + (y - h)² = r²:

As per above:

Correct choice is A

A.2

Answer:

Solution given:

equation of a circle is:

x²+y²+4x-2y=-1

x²+y²+4x-2y+1=0

Comparing above equation with

ax²+by²+2gx+2fy+c=0

we get

a=1

b=1

g=2

f=-1

c=1

now

radius of a circle (r)=\(\sqrt{g²+f²-c}\)

substituting value

r=\(\sqrt{2²+(-1)²-1}=2\)

therefore radius of a circle is 2 units

Answer:

1,980.25cm^2

Step-by-step explanation:

445mm=44.5cm
44.5^2=1,980.25

18. An infant weighs 11 pounds which is equivalent to 4.98 kg. Using the 100/50/20 Rule, the required amount of fluid per day for an infant between 11-20 kg is 50 ml/kg/day. So, the required amount of fluid per day in ml is 4.98 kg x 50 ml/kg/day = 249 ml/day.

19. A child weighs 31lbs and 8 ozs which is equivalent to 14.21 kg. Using the 100/50/24 Rule, the required amount of fluid per day for a child over 20 kg is 20 ml/kg/day. So, the required amount of fluid per day in ml is 14.21 kg x 20 ml/kg/day = 284.2 ml/day.

If no oral fluids are consumed, the hourly IV flow rate to maintain proper hydration would be: 284.2 ml/day / 24 hours/day = 11.8 ml/hour.

The question is about fluid requirements for infants and children, and it is using the 100/50/20 Rule for Daily Fluid Requirements (DFR) to calculate the required amount of fluid per day for different weight ranges. The 100/50/20 Rule is a guideline used to determine the appropriate amount of fluid that infants and children should receive on a daily basis based on their weight. The rule states that for infants and children up to 10 kg, the recommended fluid intake is 100 ml/kg/day, for those between 11-20 kg it is 50 ml/kg/day, and for those over 20 kg it is 20 ml/kg/day.

The question also asking about the hourly IV flow rate to maintain proper hydration if no oral fluids are consumed.

This subject is part of pediatrics, more specifically in the field of fluid and electrolyte balance and management.

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The measures of the corresponding inscribed angles, and then add those angles together to find the measure of angle L. Therefore, the measure of angle L is 64 degrees.

The Inscribed Angle Theorem states that the measure of an inscribed angle is half the measure of its intercepted arc. In other words, if we have an angle whose vertex is on the circumference of a circle, and whose sides intersect two points on the circumference, then the measure of the angle is half the measure of the arc between those two points.

In this problem, we are given the measures of two arcs, DR and SV, and we want to find the measure of angle L. We can start by using the Inscribed Angle Theorem to find the measures of the corresponding inscribed angles. Let's call these angles A and B, where A is the inscribed angle that intercepts arc DR, and B is the inscribed angle that intercepts arc SV.

Using the Inscribed Angle Theorem, we can find that m∠A=12m⌢DR=12(34∘)=17∘m∠B=12m⌢SV=12(94∘)=47∘

To find the measure of angle L, we simply add angles A and B together: m∠L=m∠A+m∠B=17∘+47∘=64∘

Therefore, the measure of angle L is 64 degrees.

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