\( \binom{lim}{x -> 0} \frac{ \sin^{2} (x) }{x} \)
I looked up how to do this, but I just dont understand how the internet explains it, I need a step by step simple explanation on how to do it.​

Answer:

He needs 132

Step-by-step explanation:

hope it helps

Using a linear function, it is found that the costs are given as follows:

A linear function is modeled by:

y = mx + b

In which:

Considering the price of admission and the price per ride, the y-intercept is of 20 and the slope is of 4, the cost for r rides is given by:

C(r) = 20 + 4r.

Hence, for 6 rides, the cost is given by:

C(6) = 20 + 4 x 6 = $44.

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The height of the tower in Alex's drawing is 20.7 centimeters.

A unit of measurement is a definite magnitude of a quantity, defined and adopted by convention or by law, that is used as a standard for measurement of the same kind of quantity.

We need to find the height of the tower in Alex's drawing.

Let us multiply the actual height of the tower by the scale factor.

Scale factor = 1 : 4000

Height of the actual tower = 828 meters

Height of the tower in Alex's drawing = 828 meters x (1/4000) = 0.207 meters or 20.7 centimeters.

Therefore, the height of the tower in Alex's drawing is 20.7 centimeters.

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Are wee getting the outline size? or what?

Answer:

The answer is C

Step-by-step explanation:

it is C because parallel lines don't intercept the go up or across but they don't touch, just imagine it isn't graphed.

here's two, I used mathday but day with a w

Step-by-step explanation:

good website for it and it gives good explanation! Gl

The correct answer is b) unchanged. Cutting a chocolate bar in half does not affect its density.

When a chocolate bar is cut in half, its density remains unchanged. Density is a physical property of a substance that is determined by its mass per unit volume. When the chocolate bar is cut in half, the mass is also divided into two equal parts, resulting in a reduction of the volume by half as well. Since both the numerator and denominator in the density formula change proportionally, the density remains the same.

For example, if the density of a chocolate bar is 1 gram per cubic centimeter, cutting it in half would result in two smaller bars, each with half the volume and half the mass. The density of each of the new bars would still be 1 gram per cubic centimeter, even though they are smaller in size.

Therefore, the correct answer is b) unchanged. Cutting a chocolate bar in half does not affect its density.

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Step-by-step explanation:

The sides of triangle are 5,12 and 13

Here, the greatest side is 13

Therefore,

Hence, these sides will form a right angled triangle.

\(\qquad \qquad\huge \underline{\boxed{\sf Answer}}\)

To check if the triangle is congruent or not, we have to see if they form Pythagorean triplet, that is :

sum of squares of smaller sides should be equal to square of the longest side.

let's check it out ~

\(\qquad \sf  \dashrightarrow \: {5}^{2} + 12 {}^{2} = {13}^{2} \)

\(\qquad \sf  \dashrightarrow \: {25}^{} + 144 = 169\)

\(\qquad \sf  \dashrightarrow \: 169= 169\)

Therefore, the sides 5, 12 and 13 forms a right angle.

The no. of schnauzers in the annual dog show are 20.

Assume that there are x Schnauzers at the annual dog show.

Scotties entered in the yearly dog show: x + 3

There are 2x - 5 Wirehaired Terriers entered in the annual dog show.

There are 78 dogs in all competing in the yearly dog show.

Consequently, the equation becomes

x + x + 3 + 2x - 5 = 78.

4x - 2 = 78

4x = 78 + 2

4x = 80

x = 80/4

  = 20

In the yearly dog show, there are 20 Schnauzers. I hope you can understand the process without too much trouble. It is crucial to thoroughly study the equation so that you can easily solve the issue.

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If the series starts at 13, ends at 46, and has 10 more integers in between them. The sum of these 10 integers will be 295.

It is defined as the systematic way of representing the data that follows a certain rule of arithmetic.

Divergent sequences are those in which the terms never stabilize; instead, they constantly increase or decrease as n approaches infinity, approaching either infinity or -infinity.

It is given that, the series starts at 13, ends at 46, and has 10 more integers in between them.

a = 13

L=46

n=10

The sum of the series is,

S = n/2 (a+L)

S= 10/2(13+46)

S=295

Thus, if the series starts at 13, ends at 46, and has 10 more integers in between them. The sum of these 10 integers will be 295.

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The forecast for the next period using the following weights: 0.3, 2, 0.5 is Option d. 421.

To compute the forecast for the next period, we'll use the weighted moving average (WMA) formula.WMA formula:

WMA = W1Yt-1 + W2Yt-2 + ... + WnYt-n

Where, WMA is the weighted moving average

W1, W2, ..., Wn are the weights (must sum to 1)

Yt-n is the demand in the n-th period before the current period

As we know Month 1 – 381, Month 2-366, and Month 3 - 348.

Weights: 0.3, 2, 0.5

We'll compute the forecast for the next period (month 4) using the data:

WMA = W1Yt-1 + W2Yt-2 + W3Yt-3WMA

= 0.3(381) + 2(366) + 0.5(348)WMA

= 114.3 + 732 + 174WMA

= 1020.3

Therefore, the forecast for the next period is 1020.3, which rounds to 421. Hence, option d is correct.

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The sum of the random variables T(X) = X1 + X2 + ... + Xn is a two-dimensional sufficient statistic for the parameters θ = (α, β) in the gamma distribution.

To find a two-dimensional sufficient statistic for the parameters θ = (α, β) in a gamma distribution, we can use the factorization theorem of sufficient statistics.

The factorization theorem states that a statistic T(X) is a sufficient statistic for a parameter θ if and only if the joint probability density function (pdf) or probability mass function (pmf) of the random variables X1, X2, ..., Xn can be factorized into two functions, one depending only on the data and the statistic T(X), and the other depending only on the parameter θ.

In the case of the gamma distribution, the joint pdf of the random sample X1, X2, ..., Xn is given by:

f(x1, x2, ..., xn | α, β) = (β^α * Γ(α)^n) * exp(-(x1 + x2 + ... + xn)/β) * (x1 * x2 * ... * xn)^(α - 1)

To find a two-dimensional sufficient statistic, we need to factorize this joint pdf into two functions, one involving the data and the statistic, and the other involving the parameters θ = (α, β).

Let's define the statistic T(X) as the sum of the random variables:

T(X) = X1 + X2 + ... + Xn

Now, let's rewrite the joint pdf using the statistic T(X):

f(x1, x2, ..., xn | α, β) = (β^α * Γ(α)^n) * exp(-T(X)/β) * (x1 * x2 * ... * xn)^(α - 1)

We can see that the joint pdf can be factorized into two functions as follows:

g(x1, x2, ..., xn | T(X)) = (x1 * x2 * ... * xn)^(α - 1)

h(T(X) | α, β) = (β^α * Γ(α)^n) * exp(-T(X)/β)

Now, we have successfully factorized the joint pdf, where the first function g(x1, x2, ..., xn | T(X)) depends only on the data and the statistic T(X), and the second function h(T(X) | α, β) depends only on the parameters θ = (α, β).

Therefore, the sum of the random variables T(X) = X1 + X2 + ... + Xn is a two-dimensional sufficient statistic for the parameters θ = (α, β) in the gamma distribution.

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Answer:

The mean life time of the bulbs is approximately 739 hours

Step-by-step explanation:

Here, we want to calculate the mean life time

From the question, 95% of the bulbs die before 920 hours

What this mean is that the probability that a bulb will die before 920 hours is 95% = 95/100 = 0.95

Now, we need the z-score that is exactly equal to this value

Using the standard normal distribution table, the z-score corresponding to this probability value is 1.645

Mathematically;

z-score = (x-mean)/SD

In this case, x is 920, SD is standard deviation which is 920 hours

thus, we have it that;

1.645 = (920-mean)/110

110(1.645) = 920 - mean

180.95 = 920 - mean

mean = 920- 180.95

mean = 739.05

The third side of the triangle whose two sides are 11 cm and 19 cm can be between 9 and 29.

A triangle is a geometric figure with three edges, three angles and three vertices. It is a basic figure in geometry.

The sum of the angles of a triangle is always 180°

Given that,

The sides of triangles are 11 cm and 19 cm,

Let the third side of the triangle is x,

Since, a side of a triangle is greater than the difference of two sides and less than the sum of two sides,

implies that,

19-11<x<19+11

8 < x < 30

The possible range of third side is (9,29).  

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Answer:

8cm < x < 30cm

Step-by-step explanation:

To find the range of lengths for the third side of a triangle when two side lengths are known, first, assign a variable for the length of the third side.

Let x be the length of the unknown side.

Use the Triangle Inequality Theorem to write the three inequalities.

x + 11x > 19

x + 19 > 11

11 + 19 > x

Solve each inequality.

x > 8

x > -8

30 > x

Now find the range of values that satisfies all three inequalities.

The range between 8 and 30 satisfies all 3 inequalities. Therefore, this triangle's third side lengths range is 8cm < x < 30cm.

a. Null hypothesis: H₀: µ ≤ 74

b. A t-test is appropriate here because the population standard deviation is not known, and the sample size is less than 30.

c. The value of Test statistic is -6.325

d. At a 0.05 significance level, the critical value for a right-tailed test is  -1.664.

e. The test statistic (-4.38) is less than the critical value (1.645). Hence we can reject the null hypothesis.

a. Null hypothesis, H0: µ = 74, alternative hypothesis, H1: µ > 74  (there is no significant difference in the mean job satisfaction scores of employees after the telecommuting policy is adopted).

b. A t-test is appropriate here because the population standard deviation is not known, and the sample size is less than 30. This is a one-tailed test because the alternative hypothesis is directional (i.e., it states that the mean level of satisfaction will increase with telecommuting).

c. The test statistic is calculated using the formula: t = (X - µ) / (s / √n), where X is the sample mean, µ is the population mean, s is the sample standard deviation, and n is the sample size.  Substituting the values given in the question: t = (56 - 74) / (8 / √80) = -6.325

d. The critical value for a one-tailed t-test with 79 degrees of freedom at the 0.05 level of significance is -1.664. Since the calculated t-value of -6.325 is less than the critical value of -1.664, we reject the null hypothesis.

e. Based on the calculated t-value and critical value, we reject the null hypothesis that the mean level of satisfaction is the same before and after telecommuting and accept the alternative hypothesis that telecommuting increases the mean level of satisfaction among employees.

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Step-by-step explanation:

\( = (x + y)(x + 6y)\)

\( = x \times x + x \times 6y + y \times x + y \times 6y\)

\( = {x}^{2} + 6xy + xy + 6 {y}^{2} \)

\( = {x}^{2} + 7xy + 6 {y}^{2} \)

Truncation error for s4 = Sum of the infinite series - s4 = 3 - 0.2187 ≈ 2.7813

The value of s4, which represents the sum of the series with the given expression, is approximately 0.2187. To calculate this, we substitute n = 4 into the expression and perform the necessary calculations.

On the other hand, if the sum of the infinite series is given as 3, we can determine the truncation error for s4. The truncation error is the difference between the sum of the infinite series and the partial sum s4. In this case, the truncation error is approximately 2.7813.

The truncation error indicates the discrepancy between the partial sum and the actual sum of the series. A smaller truncation error suggests that the partial sum is a better approximation of the actual sum. In this scenario, the truncation error is relatively large, indicating that the partial sum s4 deviates significantly from the actual sum of the infinite series.

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Answer:

A.

Because it has it two sides equal

Answer:

-9

Step-by-step explanation:

-7x = 63

Divide both sides by -7.

-7x/-7 = 63/-7

Simplify.

x = -9

Follow directions and input only the -9

\(-7x=63\)

1. Divide both sides by -7.

\(\frac{-7x}{-7} = \frac{63}{-7}\)

\(x=-9\)

-9 would be your answer.

Option b. encourage pet owners to appreciate their unique relationship with their pets.

In approaching minor animal behavior problems in a veterinary practice, it is important for a veterinary technician to first consider the relationship between the pet and the owner. Encouraging pet owners to appreciate their unique bond with their pets can help them understand the behavior problem and work towards correcting it. Formal training classes and pharmaceutical therapies may not always be necessary for minor behavior problems and examining the animal for signs of abuse or neglect should be done regardless of the behavior issue.

In veterinary practice, behavior problems in animals can range from minor issues to severe behavioral disorders. When it comes to minor behavior problems, veterinary technicians can play an important role in helping pet owners address the issue and improve their pet's behavior. One approach to addressing minor behavior problems is to encourage pet owners to appreciate their unique relationship with their pets. Pets are often considered as part of the family and have unique personalities and preferences just like their human counterparts. Encouraging pet owners to appreciate this bond can help them understand their pet's behavior better and work towards correcting any problematic behaviors. By doing so, veterinary technicians can empower pet owners to take an active role in their pet's health and wellbeing.

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The values of Q(C1), Q(C2), and Q(C3) are 4, 4, and π, respectively.

The concept of the integral is a fundamental part of calculus and it is used to calculate the area under a curve or the volume of a 3-dimensional object. In this context, we will be exploring the integral of a two-dimensional set in the R^2 plane.

For every two-dimensional set C contained in R^2 for which the integral exists, the function Q(C) is defined as the double integral of the function (x^2 + y^2) over the set C. The double integral is a mathematical tool for finding the total volume under a surface.

Let's consider the three sets C1, C2, and C3 and find Q(C1), Q(C2), and Q(C3).

C1={(x,y) : −1 ≤ x ≤ 1, −1 ≤ y ≤ 1}

Q(C1) = ∬C1 (x^2 + y^2) dxdy = ∫^1_{-1}∫^1_{-1} (x^2 + y^2) dxdy = ∫^1_{-1} [(x^2 + y^2)/2]^1_{-1} dx = 4.

C2 ={(x,y):−1≤x≤1,−1≤y≤1}

Q(C2) = Q(C1) = 4.

C3 = {(x,y):x^2 + y^2 ≤1}

Q(C3) = ∬C3 (x^2 + y^2) dxdy = π.

In conclusion, the values of Q(C1), Q(C2), and Q(C3) are 4, 4, and π, respectively.

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The solution to the linear system is unique solution which is  x₁ = 1/6, x₂ = 3/2, and x₃ = 17/6.

The correct answer is option  A.

To solve the given system of linear equations using elementary row operations and back substitution, let's start by representing the augmented coefficient matrix:

[1  -4  5  |  23]

[2   1   1  |  10]

[-3  2  -3 |  -23]

We'll apply row operations to transform this matrix into echelon form:

1. Multiply Row 2 by -2 and add it to Row 1:

[1  -4   5   |  23]

[0   9   -9  |  -6]

[-3  2  -3  |  -23]

2. Multiply Row 3 by 3 and add it to Row 1:

[1  -4  5   |  23]

[0   9  -9  |  -6]

[0   -10 6  |  -68]

3. Multiply Row 2 by 10/9:

[1  -4  5    |  23]

[0   1   -1   |  -2/3]

[0   -10 6  |  -68]

4. Multiply Row 2 by 4 and add it to Row 1:

[1  0   1   |  5/3]

[0  1   -1  |  -2/3]

[0  -10 6  |  -68]

5. Multiply Row 2 by 10 and add it to Row 3:

[1  0   1   |  5/3]

[0  1   -1  |  -2/3]

[0  0   -4  |  -34/3]

Now, we have the augmented coefficient matrix in echelon form. Let's solve the system using back substitution:

From Row 3, we can deduce that -4x₃ = -34/3, which simplifies to x₃ = 34/12 = 17/6.

From Row 2, we can substitute the value of x₃ and find that x₂ - x₃ = -2/3, which becomes x₂ - (17/6) = -2/3. Simplifying, we get x₂ = 17/6 - 2/3 = 9/6 = 3/2.

From Row 1, we can substitute the values of x₂ and x₃ and find that x₁ + x₂ = 5/3, which becomes x₁ + 3/2 = 5/3. Simplifying, we get x₁ = 5/3 - 3/2 = 10/6 - 9/6 = 1/6.

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Answer:

Step-by-step explanation:

x² + 6x = 8

Coefficient of the x term: 6

Divide it in half: 3

Square it: 3²

Add 3² to both sides of the equation to complete the square and keep the equation balanced:

x² + 6x + 3² = 8 + 3²

(x+3)² = 17

Answer:

52 adults and 42 children attended the concert

Step-by-step explanation:

Given:

Total attendees=94 people

Adults tickets=$2.5

Children tickets=$1.75

Total receipts=$203.5

Let adults=a

Children=c

a+c=94 (1)

2.5a + 1.75c=203.5 (2)

From (1)

a+c=94

a=94-c

Substitute a=94-c into (2)

2.5a + 1.75c=203.5

2.5(94-c) + 1.75c=203.5

235-2.5c+1.75c=203.5

-0.75c=203.5-235

-0.75c=-31.5

Divide both sides by -0.75

-0.75c/-0.75=-31.5/-0.75

c=42

Substitute c=42 into (1)

a+c=94

a+42=94

a=94-42

=52

a=52

Therefore,

52 adults and 42 children attended the concert

The correct 4-bit combination for the decimal number 9 is 1001. To explain it in a long answer, we need to understand binary representation. In binary, each digit can either be 0 or 1, and the value of the digit depends on its position.

The rightmost digit represents the value 2^0 (which is 1), the next digit to the left represents the value 2^1 (which is 2), the next represents 2^2 (which is 4), and so on. To convert decimal number 9 to binary, we can start by finding the highest power of 2 that is less than or equal to 9, which is 2^3 (which is 8). We can subtract 8 from 9, and the remainder is 1. This means the leftmost digit in the binary representation is 1.

We repeat the same process with the remainder, which is 1, and find the highest power of 2 that is less than or equal to 1, which is 2^0 (which is 1). We subtract 1 from 1, and the remainder is 0. This means the rightmost digit in the binary representation is 0. Thus, the binary representation of decimal number 9 is 1001, which is the correct 4-bit combination.

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Answer:

Angle 2

Step-by-step explanation:

They are 90 degrees when added together

Answer:

<2

Step-by-step explanation:

Complementary angles add to 90 degrees ( form right angles)

<1 and <2 add to 90 degrees so they are complementary angles

Answer:

x(x-3)(x+1)

Step-by-step explanation:

Answer: you end up at (2,2)

Step-by-step explanation:

Answer:

2,2

Step-by-step explanation:

go down to the bottom right corner (5,-5)

move over left 3 boxes

and then up 7 boxes

hope this helps :P

Answer:

\(v=400,000 \times (2)^d\)

Step-by-step explanation:

Given that,

The value of a house is 400,000 in 2015 and it doubles every decade.

Let v be the value of the house.

We need to find an equation for v in terms of d (the number of decades since 2015).

It shows that the function is exponential. So,

\(v=ab^d\)

Where

a = Initial Value = 400000

b = rate = 2

d = number of decades

v = the current value of the home

So,

\(v=400,000 \times (2)^d\)

The critical points of the given autonomous system are (0, 0) and (3/5, 3/5).

The given autonomous system is x′ = 5x² − 3y,

y′ = x − y.

We have to find all critical points of the system.

The critical points are the points at which the solutions of the differential equations of the system either converge to or diverge from. So, we need to find out the points (x, y) at which x′ = y′ = 0.

To find the critical points, we equate x′ and y′ to zero, and solve the equations:

5x² − 3y = 0   ...(1)

x − y = 0         ...(2)

Solving equation (2), we get: x = y

Putting this value of y in equation (1), we get:

5x² − 3x = 0

⇒ x(5x − 3) = 0

⇒ x = 0, 3/5

Thus, the critical points are (0, 0) and (3/5, 3/5).

Hence, the answer is: (0, 0), (3/5, 3/5).

Conclusion: The critical points of the given autonomous system are (0, 0) and (3/5, 3/5).

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