Temperature is not a direct measure of the thermal energy of a system. The total thermal energy of a system depends on its temperature and what other factors?


The temperature of the system’s environment and its location in that environment The number of atoms in the system and their molecular weights

The boiling points and freezing points of the elements that make up the substances in the system

The number of atoms in the system and conductivity of the material

Answer: There are \(12.71 \times 10^{-9}\) moles present in \(2.11 \times 10^{14}\) molecules of LiBr.

Explanation:

According to the mole concept, there are \(6.022 \times 10^{23}\) molecules present in 1 mole of a substance.

Hence, moles in \(2.11 \times 10^{14}\) molecules of LiBr are calculated as follows.

\(Moles = \frac{2.11 \times 10^{14}}{6.022 \times 10^{23}}\\= 12.71 \times 10^{-9}\)

Thus, we can conclude that there are \(12.71 \times 10^{-9}\) moles present in \(2.11 \times 10^{14}\) molecules of LiBr.

J. None of the above.

The total amount of energy in a closed system is conserved, meaning that it cannot be created or destroyed, only transformed from one form to another.

What is Energy?

Energy is a physical quantity that measures the ability of a system to perform work. It is an abstract concept that comes in many forms, such as mechanical, thermal, electrical, chemical, and nuclear energy. Energy can be transferred between different objects or systems, and it can be converted from one form to another.

Option H is an example of how thermal energy moves in a predictable pattern. When water is left on a table at a low temperature for a long period of time, its temperature drops below the freezing point of water, and the water molecules start to form ice crystals. This is an example of a predictable pattern in which thermal energy is transferred from the water to the surrounding air, causing the water to freeze.

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Answer:

C

Explanation:

The student is incorrect.

The atmosphere weighs very little compared to the material the earth is made of. Gravity is effected by mass. The more mass, the more gravity. The only correct (and it is totally correct) answer is C

Answer: During a chemical reaction, reactants are transformed into products through a process known as chemical transformation. This process involves the breaking of chemical bonds between atoms in the reactants and the formation of new bonds between atoms to form the products. The key to this transformation is the rearrangement of the electrons in the atoms involved.

In a chemical reaction, the atoms in the reactants are rearranged to form new chemical compounds, the products. This rearrangement is often accompanied by the release or absorption of energy, leading to the formation of new chemical bonds between atoms. The energy changes that occur during a chemical reaction are closely linked to the chemical changes, and are often responsible for driving the reaction forward.

A chemical reaction can occur through several different mechanisms, but all involve the breaking of existing bonds between atoms and the formation of new bonds to form the products.

Explanation:

The number of moles of hydrogen is equal to the number of moles of nitrogen.

According to the ideal gas equation

PV = nRT

where

In the problems there are two identical cylinders means, V₁ = V₂

The pressure inside each of two identical cylinders is equal to atmospheric pressure means, P₁ = P₂

Both gases are at the same temperature, means T₁ = T₂

\(\frac{P_1 V_1}{P_2 V_2} \:=\: \frac{n_1 RT_1}{n_2 RT_2}\)

\(\frac{P_1 V_1}{P_2 V_2} \:=\: \frac{n_1 T_1}{n_2 T_2}\)

n₁ = n₂

So the total amount of hydrogen gas is equal to total amount of ideal nitrogen gas.

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Now, solving this equation will give us the percentage of the RR enantiomer (x) in the mixture. The percentage of the other enantiomer can be calculated as (100 - x).

Percentage of each isomer in the mixture:

The observed specific rotation of the mixture (+14.3°) is a combination of the specific rotations of the individual enantiomers. Let's assume x represents the percentage of the RR enantiomer and (100 - x) represents the percentage of the other enantiomer in the mixture.

The specific rotation of the RR enantiomer is -33.4°, and the specific rotation of the other enantiomer can be calculated using the observed specific rotation and the percentage composition:

(+14.3°) = (x% * -33.4°) + ((100 - x)% * Specific Rotation of the other enantiomer)

Simplifying the equation:

14.3 = -33.4x/100 + (100 - x) * Specific Rotation of the other enantiomer

Now, we can solve for x by rearranging the equation and substituting the specific rotation value of the other enantiomer:

14.3 = -33.4x/100 + (100 - x) * Specific Rotation of the other enantiomer

Substituting the specific rotation of the other enantiomer:

14.3 = -33.4x/100 + (100 - x) * Specific Rotation of the other enantiomer

Note: Since the specific rotation of the other enantiomer is not provided in the question, I am unable to provide the exact percentage composition of each isomer in the mixture.

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The volume of pure gold has a mass of 65.4g and a density of 9.3g/cm3 is   3.3886 cm3.

Solution :

∵ density = mass ÷ volume

⇒ volume = mass ÷ density

∴ volume of pure gold = (mass of gold) ÷ (density of gold)

                                      = 65.4 ÷ 19.3

  The volume of pure gold = 3.3886 cm3

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Answer: 3510 J

Explanation:

q = m x Cs x delta T

m = 28.0 g

Cs = 4.18 J/g x ⁰C

delta T = Final temperature - Initial temperature = 60.0⁰C - 30.0⁰C = 30.0⁰C

q = m x Cs x delta T

q = 28.0 g x (4.18 J/g x ⁰C) x 30.0⁰C = 3511.2 J

3510 J for the correct number of significant figures.

Grams and ⁰C cancel and you are left with Joules.

Answer:

the same is what is this question like what did u exame

1. The amount of OH¯ present in the solution is 0.1 mol/L

2. The amount of H⁺ present in the solution is 0.0000000000001 mol/L

3. The pH of the solution with H⁺ concentration of 1×10⁻⁴ mol/L is 4

We'll begin by obtaining the pOH of the solution

pH + pOH = 14

13 + pOH = 14

Collect like terms

pOH = 14 - 13

pOH = 1

Finally, we can determine the OH¯

pOH = –Log [OH¯]

1 = –Log [OH¯]

Multiply through by –1

–1 = Log [OH¯]

Take the anti-log of –1

[OH¯] = anti-log of (–1)

[OH¯] = 0.1 mol/L

pH = –Log [H⁺]

13 = –Log [OH¯]

Multiply through by –1

–13 = Log [H⁺]

Take the anti-log of –13

[H⁺] = anti-log of (–13)

[H⁺] = 0.0000000000001 mol/L

pH = –Log [H⁺]

pH = –Log 1×10⁻⁴

pH = 4

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In the reaction

2Mg(s)+CO₂(g)→2MgO(s)+C(s)

The reactant which is going to oxidised is Mg(s) and the reactant which is going to reduce is CO₂(g).

Oxidation is defined as the loss of electron from the element, whereas reduction is defined as the gain of electron done by the element. When any element is present in solid form, its oxidation state is zero. Hence, the oxidation state of Mg(s) and C(s) is zero. The oxidation state of O is -2. On product side, the oxidation state of Mg is

x+(-2)=0

x-2=0

x=+2

The oxidation state of Mg is increased from zero(0) to 2. Hence, Mg(s) is oxidised.

The oxidation state of C in CO₂(g) is

x+2(-2)=0

x+(-4)=0

x-4=0

x=4

The oxidation state of C is decreased from +4 to 0. Hence, C in CO₂ is reduced in the reaction.

Therefore, the reactant which is going to oxidised is Mg(s) and the reactant which is going to reduced is CO₂(g).

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Answer:

6 carbon atoms

Explanation:

For instance, we can say that one molecule of glucose has 6 carbon atoms, or we can say, equivalently, that one mole of glucose has 6 moles of carbon atoms

Answer:

The loosening of soil and they bind the soil with the help of the roots

Explanation:

Here, we want to know how plants prevent erosion by wind or water.

The way they do this is by binding the soil with their roots such that it will not be easy for the erosion agent to erode the surface.

How they do this is by making sure that the soil

particles are binded together with their roots which helps to keep the particles of the soil intact and not eroded

Answer:

c

Explanation:

An atomic orbital is a three-dimensional representation of the position of an electron relative to an atom's nucleus. In other words, there is a maximal likelihood of discovering an electron in an atomic orbital.

A molecular orbital diagram, also referred to as a MO diagram, is a qualitative descriptive tool used in conjunction with the linear combination of atomic orbitals (LCAO) approach and general molecular orbital theory to describe chemical bonding in molecules. These ideas are founded on the fundamental assumption that as atoms unite to form molecules, a certain number of atomic orbitals combine to produce the same number of molecular orbitals, even though the electron distribution of the orbitals may differ. This approach becomes more difficult when talking about even very straightforward polyatomic molecules, like methane. For straightforward diatomic compounds like carbon monoxide, oxygen, and dihydrogen, it performs admirably. The existence of some molecules and the absence of others can be explained via MO diagrams. They are able to forecast bond strength as well.

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Answer:

Rutherfords

Explanation:

The model of the atom supported by Bohr's hydrogen experiment is the Rutherford's model of the atom.

Rutherford through his experiment on gold foil suggested the atomic model of the atom. The model posits that an atom has a small positively charged center(nucleus) where nearly all the mass is concentrated.

Answer:

Explanation:

The density of a substance can be found by using the formula

\(Density = \frac{mass}{volume} \)

From the question

volume = 15 mL

mass of object = 8.7 g

We have

\(Density = \frac{8.7}{15} \)

We have the final answer as

Hope this helps you

Answer:

125280

Explanation:

86400 seconds are in a day so just multiply 86400 by 1.45 to get your answer

Answer:

cellular respiration

Explanation:

Living animals release carbon back into the carbon cycle through the process of respiration. During respiration, animals take in oxygen and release carbon dioxide as a waste product. This carbon dioxide can be taken up by plants during photosynthesis and used to build organic compounds, which can then be consumed by other animals, continuing the carbon cycle. Additionally, when animals defecate or when their bodies naturally decompose after death, the organic matter can be broken down by decomposers, such as bacteria and fungi, which release carbon back into the cycle as well.

I just finished my biology class in high school with an A. Trust me lol

Hope you have a nice day

Answer:

One process that returns carbon from living animals to the cycle is cellular respiration. Cellular respiration converts the organic carbon in the food molecules into carbon dioxide gas, which is released into the atmosphere or water. Another process that returns carbon from living animals to the cycle is excretion1. Excretion removes waste products that contain carbon, such as urea and uric acid, from the body of animals. These waste products can be decomposed by bacteria and fungi, releasing carbon dioxide back into the environment.

Explanation:

Answer:

Options B and C are the two criteria that are most essential

Explanation:

When trying to develop a novel process, it is important that the new process involves the use of equipment that can be operated safely by workers so as to prevent death or injury in the cause of handling this equipment. If this equipment is seen not to be safe or cannot be handled safely by workers, it can/will force workers to previous or alternative methods that require more safe equipment.

Also, the process must be able to maximize the most of the reactants, i.e the process must be able to convert a good percentage of the reactants into the desired product (phosphorus pentachloride) since that is the focus. This will also lead to reduction of byproducts produced which could be useful or otherwise (a loss).

Answer:

It is B and C.

Explanation:

I just got them right on  A p E x

The third quantum number of a 2s² electron in phosphorus, m = 0.

The correct option is D.

Quantum numbers are the set of numbers used to express the location and energy of an electron in an atom.

There are four types of quantum numbers;

The electronic configuration of phosphorus is 1s²2s²2p63s²3p³.

The third quantum number m has values of -l to +l.

For phosphorus, l is 0. Hence, m is also 0.

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qwertyuiopanshdncjjcjdjwis

Answer:

False

Explanation:

The air masses are not responsible for weather , it is cause by the Earth evolution

When 7.58 moles of Mg3N2 react, 7.58 moles of H2O will also react. The stoichiometric ratio in the balanced equation is 1:1, determining the equal number of moles for both substances.

To determine the number of moles of H2O that react when 7.58 moles of Mg3N2 are allowed to react, we need to examine the balanced chemical equation for the reaction.

The balanced equation for the reaction between Mg3N2 and H2O is:

3 Mg3N2 + 6 H2O → 2 NH3 + 3 Mg(OH)2

From the balanced equation, we can see that the stoichiometric ratio between Mg3N2 and H2O is 6:6, or simply 1:1. This means that for every mole of Mg3N2 that reacts, one mole of H2O also reacts.

Therefore, if 7.58 moles of Mg3N2 react, an equal number of moles of H2O will also react. The number of moles of H2O is the same as the number of moles of Mg3N2, which is 7.58 moles.

In summary, when 7.58 moles of Mg3N2 are allowed to react, an equal number of moles, which is 7.58 moles, of H2O will also react. The stoichiometric ratio between the two substances in the balanced chemical equation determines this 1:1 relationship.

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When the force become stronger, the acceleration becomes larger and the velocity changes by a wider margin.

We know that the force is that which makes motion to occur. In other words, an object would continue in its state of rest or uniform motion unless it is acted upon by an external force.

We know that the stronger the force the greater the acceleration since force is directly proportional to the acceleration of a body. Given this statement, it is important to also know that acceleration is the change of velocity with time.

When the force become stronger, the acceleration becomes larger and the velocity changes by a wider margin.

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Ultraviolet and infrared rays are harmful rays emitted during arc welding.

During arc welding, an intense electric arc is generated, producing various types of radiation. Ultraviolet (UV) rays are one form of harmful radiation emitted during the welding process. UV rays have a shorter wavelength than visible light and can cause damage to the skin and eyes, leading to sunburn, skin aging, and even long-term health risks such as skin cancer.

In addition to UV rays, infrared (IR) rays are also emitted during arc welding. IR rays have longer wavelengths than visible light and can generate heat. Prolonged exposure to IR rays can cause thermal burns and skin damage.

To protect against the harmful effects of UV and IR radiation during arc welding, welders typically use personal protective equipment (PPE) such as welding helmets with shaded lenses or filters. These lenses are designed to block or reduce the transmission of harmful UV and IR rays while allowing safe levels of visible light to pass through, ensuring the welder's safety.

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Answer:

1. V2.

2. 299K.

3. 451K

4. 0.25 x 451 = V2 x 299

Explanation:

1. The data obtained from the question include:

Initial volume (V1) = 0.25mL

Initial temperature (T1) = 26°C

Final temperature (T2) = 178°C

Final volume (V2) =.?

2. Conversion from celsius to Kelvin temperature.

T(K) = T (°C) + 273

Initial temperature (T1) = 26°C

Initial temperature (T1) = 26°C + 273 = 299K

3. Conversion from celsius to Kelvin temperature.

T(K) = T (°C) + 273

Final temperature (T2) = 178°C

Final temperature (T1) = 178°C + 273 = 451K

4. Initial volume (V1) = 0.25mL

Initial temperature (T1) = 299K

Final temperature (T2) = 451K

Final volume (V2) =.?

V1 x T2 = V2 x T1

0.25 x 451 = V2 x 299

Answer:

271

Explanation:

1+10+15+20+25+30+35+40=45+50=

The statement that is true of the solubility of a gas in a liquid is that "the solubility of the gas in the liquid usually increases as pressure increases".

The solubility of a gas in a liquid is the amount of gas that dissolves in a given volume of a liquid at a particular temperature and pressure. The solubility of a gas in a liquid is affected by changes in temperature, pressure, and the nature of the solvent and the solute. The solubility of a gas in a liquid is directly proportional to the partial pressure of the gas over the liquid.

Therefore, if the partial pressure of the gas above the liquid is increased, the solubility of the gas in the liquid also increases. If the partial pressure of the gas above the liquid is decreased, the solubility of the gas in the liquid also decreases. This phenomenon is known as Henry's law.

According to Henry's law, the solubility of a gas in a liquid is directly proportional to the pressure of the system. Therefore, as the pressure of the system increases, the solubility of the gas in the liquid decreases. Conversely, as the pressure of the system decreases, the solubility of the gas in the liquid increases.

To summarize, the solubility of a gas in a liquid usually increases as pressure increases. This is because the solubility of a gas in a liquid is directly proportional to the partial pressure of the gas over the liquid.

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The ΔH for the desired reaction is -906 kJ.

The ΔH for the reaction X(s) + 1/2 O2(g) + CO2(g) ⟶ XCO3(s) can be found by manipulating the given reactions and then summing their ΔH values.

First, reverse the second reaction:
XO(s) + CO2(g) ⟶ XCO3(s), ΔH = -374.7 kJ

Now, add the two reactions:
X(s) + 1/2 O2(g) ⟶ XO(s), ΔH = -531.3 kJ
XO(s) + CO2(g) ⟶ XCO3(s), ΔH = -374.7 kJ
------------------------------------------
X(s) + 1/2 O2(g) + CO2(g) ⟶ XCO3(s), ΔH = (-531.3 + (-374.7)) kJ

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The ΔH for the reaction:

X(s) + 1/2 O2(g) + CO2(g) ⟶ XCO3(s)

is -1437.3 kJ.

To find the ΔH for the reaction:

X(s) + 1/2 O2(g) + CO2(g) ⟶ XCO3(s)

We can use Hess's Law, which states that the enthalpy change of a reaction is independent of the pathway between the initial and final states. We can use the given equations and their enthalpy changes to calculate the overall enthalpy change for the reaction of interest.

First, we need to reverse the second equation and change the sign of its enthalpy change:

XO(s) + CO2(g) ⟶ XCO3(s) ΔH = -374.7 kJ

Next, we need to balance the equations by multiplying the first equation by 2:

2X(s) + 6O2(g) ⟶ 2XO(s) ΔH = -1062.6 kJ

Now we can add the equations together, canceling out the intermediate XOs:

2X(s) + 6O2(g) + 2CO2(g) ⟶ 2XCO3(s) ΔH = (-1062.6 kJ) + (-374.7 kJ) = -1437.3 kJ

The ΔH for the reaction:

X(s) + 1/2 O2(g) + CO2(g) ⟶ XCO3(s)

is -1437.3 kJ.

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