Temperature is a measure of

Answer:

the bigger stars tend to be hotter and burn through their fuel more quickly than smaller stars they also tend to ether be turned into a black hole or a huge nebula with a neutron star the smaller stars have a tendency to go through their fuel slower and don't get as hot as big stars until the red giant stage.

Explanation:

Answer:

Volume of Sand = 0.4 m³

Radius of Sand Sphere = 0.46 m

Explanation:

First we need to find the volume of gold sphere:

Vg = (4/3)πr³

where,

Vg = Volume of gold sphere = ?

r = radius of gold sphere = 2 cm = 0.02 m

Therefore,

Vg = (4/3)π(0.2 m)³

Vg = 0.0335 m³

Now, we find mass of the gold:

ρg = mg/Vg

where,

ρg = density of gold = 19300 kg/m³

mg = mass of gold = ?

Vg = Volume of gold sphere = 0.0335 m³

Therefore,

mg = (19300 kg/m³)(0.0335 m³)

mg = 646.75 kg

Now, the volume of sand required for equivalent mass of gold, will be given by:

ρs = mg/Vs

where,

ρs = density of sand = 1602 kg/m³

mg = mass of gold = 646.75 kg

Vs = Volume of sand = ?

Therefore,

1602 kg/m³ = 646.75 kg/Vs

Vs = (646.75 kg)/(1602 kg/m³)

Vs = 0.4 m³

Now, for the radius of sand sphere to give a volume of 0.4 m³, can be determined from the formula:

Vs = (4/3)πr³

0.4 m³ = (4/3)πr³

r³ = 3(0.4 m³)/4π

r³ = 0.095 m³

r = ∛(0.095 m³)

r = 0.46 m

The resultant force while pushing the car would be 20 N.

Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.

As given in the problem Mary and Carl's car broke down so they are pushing the car. Mary is pushing the car at 9N and Carl is pushing the car at 11N.

As both Mary and Carl apply the force in the same direction while pushing the broke car

Resultant force= 9 N + 11 N

                          = 20 N

Thus, the resultant force comes out to be 20N.

Learn more about Newton's second law, here

brainly.com/question/13447525

#SPJ1

The question seems incomplete, the complete question is,

Mary and Carl's car broke down so they are pushing the car. Mary is pushing the car at 9N and Carl is pushing the car at 11N. Find out the resultant force while pushing the car

Answer:

Explanation:

The kinetic energy of an object can be found by using the formula

\(k = \frac{1}{2} m {v}^{2} \\ \)

m is the mass

v is the velocity

From the question we have

\(k = \frac{1}{2} \times 74 \times {11}^{2} \\ = 37 \times 121\)

We have the final answer as

Hope this helps you

Answer:

A, Passive Solar.

Explanation:

The magnitude of the initial acceleration of the object is 4.2 m/s².

The tension in the string once the object starts moving is 13.65 N.

The magnitude of the initial acceleration of the object is calculated by applying Newton's second law of motion as follows;

F(net) = ma

m₂g - μm₁g cosθ = a(m₁ + m₂)

where;

(4.75 x 9.8) - (0.535 x 3.25 x 9.8 x cos40) = a(3.25 + 4.75)

33.5 = 8a

a = 33.5/8

a = 4.2 m/s²

The tension in the string once the object starts moving is calculated as;

T = m₁a

T = 3.25 x 4.2

T = 13.65 N

Learn more about acceleration here: https://brainly.com/question/14344386

#SPJ1

In general, option c - warming it up on the stove - is often an effective method to increase the reaction rate.

Increasing the temperature of a reaction generally leads to faster reaction rates. This is because higher temperatures provide more thermal energy to the reactant particles, causing them to move faster and collide more frequently. The increased collision frequency and energy lead to more successful collisions and a higher likelihood of effective molecular interactions, which speeds up the reaction. On the other hand, options a and b - putting it in the fridge where it is cold or covering it with a blanket to make it dark - are unlikely to have a significant effect on the reaction rate. While temperature can influence reaction rates, cooling the reaction or making it dark typically reduces the kinetic energy of the particles, resulting in slower reaction rates. Option d - there is nothing you can do to change the speed of the reaction - is not accurate. The reaction rate can be influenced by various factors such as temperature, concentration, catalysts, and surface area, among others. By manipulating these factors, it is often possible to control and change the speed of a reaction. Hence option c, is correct

for more questions on reaction
https://brainly.com/question/4431224
#SPJ8

Answer:

The discrimination which is based on affirmative action, inherent requirement of a particular job, productivity and compulsory discrimination by law are termed as fair discrimination.

hope it helps :)

Explanation:

Answer:

ok

Explanation:

Answer:

shooting

Explanation:

i hope you're joking

A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm, the electromotive force (emf) of the cell is approximately 14.5 volts.

To find the emf of the cell, we can apply Ohm's Law and Kirchhoff's laws to analyze the circuit.

Given:

Resistance of the coil, R1 = 4 ohm

Resistance of the other resistor, R2 = 8 ohm

Current passing through the 8-ohm resistor, I = 2A

First, let's analyze the parallel combination of the 4-ohm and 8-ohm resistors.

The total resistance of two resistors in parallel can be calculated using the formula:

1/Rp = 1/R1 + 1/R2

Substituting the given values, we have:

1/Rp = 1/4 + 1/8

1/Rp = 2/8 + 1/8

1/Rp = 3/8

Rp = 8/3 ohm

Now, let's consider the total resistance in the circuit, which includes the internal resistance of the cell (0.5 ohm) and the parallel combination of the resistors (8/3 ohm).

R_total = R_internal + Rp

R_total = 0.5 + 8/3

R_total = 1.833 ohm

Now, we can find the emf of the cell using Ohm's Law:

emf = I * R_total

emf = 2 * 1.833

emf ≈ 3.667 volts

Therefore, the emf of the cell is approximately 3.667 volts.

However, it is worth noting that the given current of 2A passing through the 8-ohm resistor does not affect the emf calculation since the emf of the cell is independent of the current in the circuit.

For more such questions on emf, click on:

https://brainly.com/question/13744192

#SPJ8

The kinetic energy of the cat is 2 joules (J).

The kinetic energy of an object can be calculated using the formula KE = 1/2 * mass * velocity^2.

The kinetic energy of an object can be calculated using the formula:

Kinetic Energy (KE) = 0.5 * mass * velocity^2

In this case, the mass of the cat is 4 kilograms, and its velocity is 1 m/s. Plugging these values into the formula:

KE = 0.5 * 4 kg * (1 m/s)^2

Simplifying the equation:

KE = 0.5 * 4 kg * 1 m^2/s^2

KE = 0.5 * 4 kg * 1

KE = 2 kg

Therefore, the kinetic energy of the cat is 2 joules (J).

Kinetic energy is the energy possessed by an object due to its motion. In this case, the cat's kinetic energy is determined by its mass and velocity. The formula for kinetic energy demonstrates that it is directly proportional to the mass and square of the velocity. As the mass increases, the kinetic energy also increases. Similarly, as the velocity increases, the kinetic energy increases exponentially.

In this example, the cat's kinetic energy is relatively low due to its mass and velocity values. If the cat were moving at a higher velocity or had a greater mass, the kinetic energy would be significantly higher. Kinetic energy is an important concept in understanding the energy associated with moving objects and is utilized in various fields such as physics, engineering, and sports science.

for more such questions on kinetic

https://brainly.com/question/8101588

#SPJ8

The amount of force applied to the 7kg object that caused it to accelerate at 8m/s² is 56 newtons.

A force is simply a push or a pull of an object resulting from the object's interaction with another object.

From newton's second law;

Force = mass × acceleration

Given the data in the question;

Plug the given values into the formula to determine the applied force.

Force = mass × acceleration

Force = 7kg × 8m/s²

Force = 56kgm/s²

Force = 56 N

Therefore, the applied force is 56 newtons.

Learn more about force here: brainly.com/question/27196358

#SPJ1

If the engine of a boat on a river is turned off while the boat is moving with a steady speed, several things would happen Loss of propulsion,Drifting,Loss of steering control and Potential hazards.

Loss of propulsion: Without the engine running, the boat would lose its power source for propulsion. The boat would gradually slow down and eventually come to a stop unless other external forces, such as currents or wind, continue to move it.

Drifting: Once the boat comes to a stop, it would start to drift with the current of the river or be affected by wind forces. The direction and speed of the drift would depend on the strength and direction of the current or wind.

Loss of steering control: When the engine is turned off, the boat's steering mechanism, such as a rudder, would also lose power. Without the ability to steer, the boat would follow the course determined by the river's current or the wind direction.

Potential hazards: Depending on the surroundings and the current conditions, there could be potential hazards for a boat that is no longer under power. These hazards might include other vessels, obstacles, shallow areas, or strong currents. The boat's crew would need to take appropriate actions to ensure the safety of the boat and its occupants.

It's important to note that the specific behavior of the boat after the engine is turned off can vary depending on factors such as the size and design of the boat, the strength and direction of the current, and the presence of wind or other external forces.
For more such questions on Loss of propulsion,click on:

https://brainly.com/question/17083942

#SPJ11

Answer: the final velocity and final velocity velocity can also be written as we It went to one route A. V. Of X. Care plus movie. Why is here? This is a vision number two. And this is a revision number one food equation and one into to get we want to and wrote. We now takes scared plus we not scared away helpless to And by and the horizontal and the vertical component which are we know scare X is equal to we not cost it and we're not scared by going to we not scientific putting these value. Immigration number three. We get we will too. Are we not scared? I got scared to to less. We not scare Science square theater plus two. Why? So this we equal to he went to work and rude. We're not scared people to got scared he to less science security theater Last two. A. Y. Sure we get we s we're not scared into I. Plus to A Y. So we is able to. And road we now scared. Plus two. Am I. So this is a vision number four. And we are given me an artist 14 m purse again. And why he has given us. Uh huh. three m. So we can we find out by putting this value innovation number for the disk 14 scared. Uh huh. Plus To into -9.8 into three. We get to be It will do 11.7. Me did last

Explanation:

Argon

as it is an inert elemnt

a. To determine the maximum height the car can go up, we need to use conservation of energy. At ground level, the car has kinetic energy equal to 1/2 mv^2, where m is the mass of the car and v is its velocity.

As the car moves up, its kinetic energy will be converted into potential energy, which is equal to mgh, where h is the height above ground level and g is the acceleration due to gravity (9.8 m/s^2). At the maximum height, all of the car's kinetic energy will have been converted into potential energy, so we can set these two expressions equal to each other and solve for h:
1/2 mv^2 = mgh
h = (1/2 v^2)/g
h = (1/2) (15 m/s)^2 / 9.8 m/s^2
h = 11.5 meters
Therefore, the maximum height the car can go up is 11.5 meters.
b. To determine the velocity of the car if it goes up a hill 3 meters high, we can use conservation of energy again. This time, the car will have both potential energy (due to its height above ground level) and kinetic energy. At the bottom of the hill, the car has kinetic energy equal to 1/2 mv^2, where m is the mass of the car and v is its velocity. As the car goes up the hill, its kinetic energy will be converted into potential energy, which is equal to mgh, where h is the height of the hill (3 meters) and g is the acceleration due to gravity (9.8 m/s^2). At the top of the hill, all of the car's kinetic energy will have been converted into potential energy, so we can set these two expressions equal to each other and solve for v:
1/2 mv^2 = mgh
v = sqrt(2gh)
v = sqrt(2 * 9.8 m/s^2 * 3 meters)
v = 7.7 m/s
Therefore, the velocity of the car if it goes up a hill 3 meters high is 7.7 m/s.

a. To find the maximum height the car can go up, we'll use the conservation of mechanical energy principle. At the maximum height, the car's kinetic energy (KE) will be converted to gravitational potential energy (PE). The formula for KE is (1/2)mv^2 and for PE is mgh.
At ground level, KE = (1/2)(1200 kg)(15 m/s)^2 = 135000 J, and PE = 0.
At the maximum height, KE = 0 and PE = mgh. So, we can set up the equation:
135000 J = (1200 kg)(9.81 m/s^2)(h)
Solving for h, we get:
h = 135000 J / (1200 kg * 9.81 m/s^2) ≈ 11.48 m
So, the maximum height the car can go up is approximately 11.48 meters.
b. To find the velocity of the car when it goes up a hill 3 meters high, we can use the conservation of mechanical energy principle again:
Initial KE + Initial PE = Final KE + Final PE
(1/2)mv^2_initial + 0 = (1/2)mv^2_final + mgh
(1/2)(1200 kg)(15 m/s)^2 = (1/2)(1200 kg)v^2_final + (1200 kg)(9.81 m/s^2)(3 m)
Solving for v_final, we get:
v_final ≈ 13.43 m/s
So, the velocity of the car when it goes up a hill 3 meters high is approximately 13.43 m/s.

For more question on kinetic energy

https://brainly.com/question/25959744

#SPJ11

Answer:

the inertia would be the force equal mass times the acceleration

10 thieworhet

Explanation:

1) The force acting on the object during the time interval 0-3 seconds is 1/3 N.

2) The force acting on the object during the time interval 6-10 seconds is -0.5 N.

3) There is no time interval in which no force acts on the object.

(i) Force acting on the object in time interval 0-3 seconds. Force acting on the object is equal to the product of its mass and acceleration, i.e.,F = ma.

In the given velocity-time graph, the acceleration of the object can be determined by determining the slope of the velocity-time graph from 0 to 3 seconds.

Slope = (change in velocity) / (change in time)= (20-0) / (3-0) = 20/3 m/s^2

Acceleration, a = slope= 20/3 m/s^2

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × 20/3= 1/3 N.

Therefore, the force acting on the object during the time interval 0-3 seconds is 1/3 N.

(ii) Force acting on the object in time interval 6-10 seconds. Similar to the first question, the force acting on the object in time interval 6-10 seconds can be determined by determining the acceleration of the object during this time interval.

The slope of the velocity-time graph from 6 seconds to 10 seconds can be determined as follows:

Slope = (change in velocity) / (change in time)= (-20-20) / (10-6) = -40/4= -10 m/s^2 (negative sign indicates that the object is decelerating)

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × (-10)= -0.5 N.

Therefore, the force acting on the object during the time interval 6-10 seconds is -0.5 N.

(iii) Time interval in which no force acts on the object. There is no time interval in which no force acts on the object. This is because, as per Newton's first law of motion, an object will continue to remain in a state of rest or uniform motion along a straight line unless acted upon by an external unbalanced force.In other words, if the object is moving with a constant velocity, there must be a force acting on the object to maintain its motion.

Therefore, there is no time interval in which no force acts on the object.

For more such questions on force, click on:

https://brainly.com/question/12785175

#SPJ8

The minimum deceleration required to stop the car in 35 meters is 40000 m/s^2.

Deceleration is defined as  the decrease in speed as the body moves away from the starting point.

The minimum deceleration required can be calculated using the equation of motion:

d = v^2 / (2 * a)

where d is the distance, v is the initial velocity, and a is the acceleration.

Rearranging the equation to solve for a:

a = v^2 / (2 * d) = (3500 m/s)^2 / (2 * 35 m) = 40000 m/s^2

In conclusion, , the minimum deceleration required to stop the car in 35 meters is 40000 m/s^2.

learn more about deceleration at: https://brainly.com/question/25311290

#SPJ1

Drawing the vectors, we have:

Now, calculating the components of each vector:

Answer:

Explanation:

Your numbers seem wonky, so I'll just assume that the initial displacement is a distance A (Amplitude) from the equilibrium position. Spring constant = k

Initial potential energy is

PE = ½kA²

As potential energy and kinetic energy are constantly exchanging in SHM,

the position x where half of the original spring potential exists is found where

½kx² = ½(½kA²)

    x² = ½A²

    x = (√0.5)A

    x ≈ 0.707A

just plug in your actual starting position A

With A = 5.2 cm

x = 3.67695... 3.7 cm

On research on animals they must given proper care and housing. And the purpose of the research must have a scientific reason. Thus option B  is  correct.

Animal research includes various scientific investigation on animals such as testing various doses of some drugs, effect of various chemicals, level of toxicity of some compounds etc.

According to the research ethics, no animals can be used to conduct any unscientific works. There must be a scientific purpose which is very important to conduct any animal research.

If any animals irrespective of its nature,it must be provided proper care, food and housing. No harmful things must be there which make them more suffering. Hence, option B is correct.

To find more on animal research, refer here:

https://brainly.com/question/6140246

#SPJ1

Answer:

when air or water cools it sinks

Answer:

SA = 18.6 * t + 186    total distance traveled by A in time t

SB = 24.4 t                total distance car B must travel to catch car A

SA - SB = 0 = 18.6 t + 186 = 24.4 t

(24.4 - 18.6) t = 186

t = 186 m / 5.8 m/s = 32 s

Check 18.6 * 32 + 186 = 781 m

24.4 * 32 = 781 m

Let F be the magnitude of the force needed to keep the box sliding at constant speed, and f the magnitude of kinetic friction. Then by Newton's second law, the net horizontal force on the crate is

F - f = 0

so that

F = f

f is proportional to the magnitude of the normal force n,

f = 0.38n

The net vertical force is

n - mg = 0

which tells us that

n = mg = (29 kg) (9.8 m/s²) ≈ 284 N

Then the required force must have magnitude

F = f = 0.38 (284 N) ≈ 110 N

The value of the spring constant is 8704 N/m.

The spring constant (k) can be found using Hooke's law, which states that the force required to stretch or compress a spring is proportional to the distance it is stretched or compressed.

Mathematically, it can be expressed as:

F = -kx

where F is the force applied to the spring,

k is the spring constant, and

x is the distance the spring is stretched or compressed.

Since the force applied to the spring is equal to the weight of the book, we can write:

F = mg = -kx

where m is the mass of the book and

g is the acceleration due to gravity.

Substituting the given values, we get:

560 g * 9.8 m/s^2 = -k * 0.25 m

Dividing both sides by -0.25 m and solving for k,

we will get it as:

k = (560 g * 9.8 m/s^2) / 0.25 m

k= 8704 N/m

For more questions on Spring Constant

https://brainly.com/question/23885190

#SPJ4

The force in each cable depends on the orientation of the cable relative

to the force of the balloon and to each other.

Responses:

a) The position vectors are;

Position vector, DA, \(r_{DA}\) = -20·i - 30·j + 0·k

DB, \(r_{DB}\) = 30·i - 30·j + 20·k

DC, \(r_{DC}\) = 0·i - 30·j + 20·k

\(b) \hspace{0.15 cm} Unit \ vectors \ are, u_{DA} = \underline{ \dfrac{-2 \cdot \sqrt{13} \cdot i}{13} - \dfrac{ 3 \cdot \sqrt{13} \cdot j }{13 }}\)

c) The approximate values of the force in each cable are;

a) The position vector is a vector that locates a point relative to another point.

The position vector,

\(r_{DA} = \mathbf{ r_A - r_D}\)

Whereby the coordinate of the point D is taken as (0, 30, 0), we have;

Similarly, we have;

\(r_{DB}\) = 30·i + 0·j + 20·k - (0·i + 30·j + 0·k) = 30·i - 30·j + 20·k

\(r_{DC}\) = 0·i + 0·j + 20·k - (0·i + 30·j + 0·k) = 0·i - 30·j + 20·k

b) The unit vectors are  therefore;

\(u_{DA} = \mathbf{ \dfrac{r_{DA}}{|r_{DA} |}}\)

Which gives;

\(u_{DA} = \dfrac{-20 \cdot i - 30 \cdot j + 0 \cdot k}{\sqrt{(-20)^2 + (-30)^2 + 0} } = \dfrac{-2 \cdot i - 3 \cdot j }{\sqrt{13} } = \dfrac{\left(-2 \cdot i - 3 \cdot j \right) \times \sqrt{13} }{13 }\)

\(u_{DA} = \mathbf{ \dfrac{-20 \cdot i - 30 \cdot j + 0 \cdot k}{\sqrt{(-20)^2 + (-30)^2 + 0} }}} = \dfrac{-2 \cdot i - 3 \cdot j }{\sqrt{13} } = \underline{\dfrac{-2 \cdot \sqrt{13} \cdot i}{13} - \dfrac{ 3 \cdot \sqrt{13} \cdot j }{13 }}\)

\(u_{DB} = \dfrac{30 \cdot i + 0 \cdot j + 20 \cdot k}{\sqrt{(30)^2 + (20)^2 + 0} } = \mathbf{\dfrac{3 \cdot i +2 \cdot k }{\sqrt{13} } } = \underline{\dfrac{3 \cdot \sqrt{13} }{13} \cdot i + \dfrac{2 \cdot \sqrt{13} }{13} \cdot k}\)

\(u_{DC} = \mathbf{\dfrac{-30 \cdot j + 20 \cdot k}{\sqrt{(30)^2 + (20)^2 } } }= \underline{-\dfrac{3 \cdot \sqrt{13} }{13} \cdot j + \dfrac{2 \cdot \sqrt{13} }{13} \cdot k}\)

c) The force in each cable are found as follows;

\(\vec F_{DA} = \mathbf{ \dfrac{-2 \cdot \sqrt{13} }{13}\cdot i \cdot F_{DA}- \dfrac{ 3 \cdot \sqrt{13} }{13 } \cdot j\cdot F_{DA}}\)

\(\vec F_{DB} = \mathbf{ \dfrac{3 \cdot \sqrt{13} }{13} \cdot i \cdot F_{DB}+ \dfrac{2 \cdot \sqrt{13} }{13} \cdot k\cdot F_{DB}}\)

\(\vec F_{DC} = \mathbf{ -\dfrac{3 \cdot \sqrt{13} }{13} \cdot j \cdot F_{DC}+ \dfrac{2 \cdot \sqrt{13} }{13} \cdot k\cdot F_{DC}}\)

Sum of forces, ∑F = 0, gives;

\(\mathbf{ \dfrac{-2 \cdot \sqrt{13} }{13}\cdot i \cdot F_{DA} +\dfrac{3 \cdot \sqrt{13} }{13} \cdot i \cdot F_{DB}} = 0\)

\(\mathbf{ - \dfrac{ 3 \cdot \sqrt{13} }{13 } \cdot j\cdot F_{DA} -\dfrac{3 \cdot \sqrt{13} }{13} \cdot j \cdot F_{DC} + 900} = 0\)

\(\mathbf{ \dfrac{2 \cdot \sqrt{13} }{13} \cdot k\cdot F_{DB} + \dfrac{2 \cdot \sqrt{13} }{13} \cdot k\cdot F_{DC}} = 0\)

Solving the above simultaneous equation with a graphing calculator gives;

Learn more about vectors here:

https://brainly.com/question/2263823

Answer:

Newton's first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force. This tendency to resist changes in a state of motion is inertia.

Explanation:

Increased driving can lead to higher vehicle maintenance and repair expenses, increased fuel costs, potential increases in auto insurance premiums, and additional parking fees, all of which should be considered when estimating the overall impact on your expenses.

The expenses that are likely to change based on how much you drive can be broadly categorized into two main areas: vehicle-related expenses and fuel-related expenses.

1. Vehicle-related expenses: The more you drive, the more wear and tear your vehicle will experience, leading to increased maintenance and repair costs. Regular oil changes, tire replacements, brake pad replacements, and other routine maintenance tasks will be required more frequently.

2. Fuel-related expenses: It's intuitive that the more you drive, the more fuel you'll consume, resulting in higher fuel expenses. Fuel prices can vary, but regardless of fluctuations, increased mileage will directly impact your fuel budget. Fuel-efficient vehicles may mitigate some of these costs, but the overall impact on your expenses will still be noticeable.

For more such questions on driving,click on

https://brainly.com/question/32438244

#SPJ8