Technician a says that since north american clutch manufacturers no longer use asbestos there is no need to be concerned by clutch dust. technician b says that compressed air is the best way to clean the clutch housing when performing a clutch replacement. who is correct?

Answer:

Used to recall the direction a standard screw

Answer:

Steampunk Mechanical

Explanation:

Your welcome

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

In the given circuit, V(t)=12cos(2000t+45)V, R1=R2=2Ω, L1=L2=L3=3mH and C1=250μF. You are required to find the Thevenin equivalent of this circuit using phasors.

a. If you write the Thevenin voltage, Vth, in phasor form, what is the magnitude of this phasor? Put your answer in the box below without units.

b. What is the value of the angle associated with the phasor Vth, in degrees?

c. Now, calculate the Thevenin impedance, Zth. What is the magnitude of this phasor?

d. What is the angle associated with the phasor Zth, in degrees?

Answer:

Vth = 6 < 45° V

Zth = 1.414 < 45°

a. The magnitude of the Thevenin voltage is 6 V

b. The phase angle of the Thevenin voltage is 45°

c. The magnitude of the Thevenin impedance is 1.414 V

d. The phase angle of the Thevenin impedance is 45°

Explanation:

The given voltage is

V(t)=12cos(2000t+45)

In phasor form,

V(t) = 12 < 45° V

So the magnitude of voltage is 12 V and the phase angle is 45°

Also the frequency ω = 2000

then the inductance is

L₁ = L₂ = L₃ = jωL = j×2000×0.003 = j6 Ω

and the capacitance is

C₁ = 1/jωC = 1/(j×2000×250x10⁻⁶) = -j2 Ω

and the resistance is

R₁ = R₂ = 2 Ω

Thevenin voltage:

The Thevenin voltage is the voltage that appears across the open-circuited terminals a-b (after removing L₃)

The Thevenin voltage is given by

Vth = V(t) × [ (R₂ + L₂) / (R₁ + L₁) + (R₂ + L₂) ]

Please note that there is no current flow in the capacitor due to open-circuited terminal a-b

Vth = 12 < 45°  × [ (2 + j6) / (2 + j6) + (2 + j6) ]

Vth = 12 < 45°  × [ (2 + j6) / (4 + j12) ]

Vth = 4.24264 + j4.24264 V

In phasor form,

Vth = 6 < 45° V

a. The magnitude of the Thevenin voltage is 6 V

b. The phase angle of the Thevenin voltage is 45°

Thevenin Impedance:

The Thevenin Impedance is the impedance of the circuit calculated when looking from the terminal a-b

Zth = [ (R₁ + L₁) × (R₂ + L₂) / (R₁ + L₁) + (R₂ + L₂) ] + (-j2)

Zth = [ (2 + j6) × (2 + j6) / (2 + j6) + (2 + j6) ] - j2

Zth = [ (2 + j6) × (2 + j6) / (2 + j6) + (2 + j6) ] - j2

Zth = [ (-32 + j24) / (4 + j12) ] -j2

Zth = [ (1 +j3) ] - j2

Zth = 1 + j Ω

In phasor form,

Zth = 1.414 < 45°

c. The magnitude of the Thevenin impedance is 1.414 V

d. The phase angle of the Thevenin impedance is 45°

(a) The probability of drawing a black fuse from the second toolbox is 4/7.

(b) The probability of drawing a white fuse from the second toolbox is 3/7.

(c) The probability that one fuse is white is 27/49.

To calculate the probabilities, we need to consider the number of white and black fuses in each toolbox.

First, let's determine the total number of fuses in each toolbox:

First Toolbox:

Total fuses = 4 white fuses + 3 black fuses = 7 fuses

Second Toolbox:

Total fuses = 3 white fuses + 5 black fuses = 8 fuses

(a) The probability that the fuse drawn from the second toolbox is black:

The probability of drawing a black fuse from the second toolbox depends on the fuse selected from the first toolbox. There are two scenarios to consider:

Scenario 1: The fuse selected from the first toolbox is black.

In this case, the second toolbox will have 3 black fuses remaining out of the total 7 fuses.

Probability = (Number of black fuses in the second toolbox)/(Total number of fuses in the second toolbox)

Probability = 3/7

Scenario 2: The fuse selected from the first toolbox is white.

In this case, the second toolbox will have 5 black fuses out of the total 7 fuses.

Probability = (Number of black fuses in the second toolbox)/(Total number of fuses in the second toolbox)

Probability = 5/7

To calculate the overall probability, we need to consider the probability of each scenario and weigh it by the probability of selecting a fuse of that color from the first toolbox. Since the fuse from the first toolbox has an equal chance of being white or black, we need to take an average of the probabilities in both scenarios.

Probability of drawing a black fuse from the second toolbox = (Probability of scenario 1 + Probability of scenario 2)/2

Probability of drawing a black fuse from the second toolbox = (3/7 + 5/7)/2

Probability of drawing a black fuse from the second toolbox = 8/14

Probability of drawing a black fuse from the second toolbox = 4/7

Therefore, the probability of drawing a black fuse from the second toolbox is 4/7.

(b) The probability that the fuse drawn from the second toolbox is white:

Similarly, we can calculate the probability of drawing a white fuse from the second toolbox. It will be the complement of the probability of drawing a black fuse.

Probability of drawing a white fuse from the second toolbox = 1 - Probability of drawing a black fuse from the second toolbox

Probability of drawing a white fuse from the second toolbox = 1 - 4/7

Probability of drawing a white fuse from the second toolbox = 3/7

Therefore, the probability of drawing a white fuse from the second toolbox is 3/7.

(c) The probability that one is white:

To calculate the probability that one fuse is white, we need to consider both scenarios: either the fuse drawn from the first toolbox is white and the fuse drawn from the second toolbox is black, or the fuse drawn from the first toolbox is black and the fuse drawn from the second toolbox is white.

Scenario 1: Fuse drawn from the first toolbox is white, and the second toolbox has a black fuse:

Probability = (Probability of drawing a white fuse from the first toolbox) * (Probability of drawing a black fuse from the second toolbox)

Probability = (3/7) * (5/7)

Scenario 2: Fuse drawn from the first toolbox is black, and the second toolbox has a white fuse:

Probability = (Probability of drawing a black fuse from the first toolbox) * (Probability of drawing a white fuse from the second toolbox)

Probability = (4/7) * (3/7)

To calculate the overall probability, we need to sum up the probabilities of both scenarios:

Probability that one fuse is white = Probability

of scenario 1 + Probability of scenario 2

Probability that one fuse is white = (3/7) * (5/7) + (4/7) * (3/7)

Probability that one fuse is white = 15/49 + 12/49

Probability that one fuse is white = 27/49

Therefore, the probability that one fuse is white is 27/49.

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Answer:

Explanation:

heat

Answer:

0.2 x 100

Explanation:

Engineering strain is the original crossection/original crossection

cold work percentage is

original crossection/original crossection x 100

Explanation:

for 40hz

since they are in series they will have the same amper

so R=30ohm

C=30F

for 50Hz

R=25

C=25

To prove the relationship between the mean coefficient of friction (μ) and the shear angle (x), given that the frictional force (F) on the tool rake face is equal to KtA, where K is a constant, A is the area of the cross-section of the chip, and a is the rake angle, we can follow these steps:

Step 1: Express the frictional force in terms of the mean coefficient of friction:

The frictional force, F, is equal to the product of the mean coefficient of friction (μ) and the normal force (N), which is equal to KtA:

F = μN = μKtA.

Step 2: Calculate the normal force, N:

The normal force can be determined using trigonometry. Since a is the rake angle, the component of the normal force in the direction of the shear force is N cos(x - a).

Step 3: Equate the frictional force with the calculated normal force:

Setting F = N cos(x - a), we get:

μKtA = N cos(x - a).

Step 4: Substitute the expression for the normal force:

μKtA = (N cos(x - a)).

Step 5: Rearrange the equation to solve for μ:

Divide both sides by N cos(x - a):

μ = KtA / (N cos(x - a)).

Step 6: Express N in terms of K and A:

Using trigonometry, we find that N = K sin(x - a).

Step 7: Substitute N into the equation:

μ = KtA / ((K sin(x - a)) cos(x - a)).

Step 8: Simplify the expression:

μ = K cos^2(x - a) / (K sin(x - a) cos(x - a) + 1).

Therefore, we have derived the relationship between the mean coefficient of friction (μ) and the shear angle (x) as μ = K cos^2(x - a) / (K sin(x - a) cos(x - a) + 1), where K is a constant, A is the area of the cross-section of the chip, and a is the rake angle.

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Answer: its A

Explanation:

Using the Newton's second law of motion we will see that the acceleration is  0.0875 m/s^2.

The acceleration of a vehicle is determined by the force acting on it and its mass, as described by Newton's second law of motion:

F = m * a

where F is the force acting on the object, m is the mass of the object, and a is the resulting acceleration.

In this case, the force acting on the vehicle is 0.07 N, and the mass of the vehicle is 0.8 kg. Substituting these values into the equation above, we get:

0.07 N = 0.8 kg * a

Solving for a, we get:

a = 0.07 N / 0.8 kg

a = 0.0875 m/s^2

Therefore, the acceleration of the 0.8 kg vehicle powered by 0.07 N of force is 0.0875 m/s^2.

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Answer:

  your answer is correct

Explanation:

You have the correct mapping from inputs to outputs. The only thing your teacher may disagree with is the ordering of your inputs. They might be written more conventionally as ...

 A B Y

 0 0 1

 0 1 0

 1 0 0

 1 1 1

That is, your teacher may be looking for the pattern 1001 in the last column without paying attention to what you have written in column B.

Explanation:

The term refrigeration means cooling a space, substance or system to lower and/or maintain its temperature below the ambient one (while the removed heat is rejected at a higher temperature). In other words, refrigeration is artificial (human-made) cooling.

Refrigeration, is the act of removing undesirable heat from one thing, substance, or space and transferring it to another object, substance, or space.

Refrigeration refers to the process of chilling an area, material, or system in order to decrease and or keep its temperature below that of the surrounding environment.

Refrigeration, sometimes known as chilling, is the act of removing undesired heat from one item, substance, or area and transferring it to another.

The temperature can be lowered by using ice, snow, cooled water, or mechanical refrigeration to remove heat.

Hence,refrigeration, is the act of removing undesirable heat.

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The correct sequence for proper usage and maintenance of knives is as follows:

1. Purchase the required knives. 2. Select the proper knife for the job. 3. Clean the knife after use. 4. Store the clean knife in the knife block.

Purchasing the required knives is the first step in the proper usage and maintenance of knives. It is important to select the right knives for the job, as different knives are designed for different tasks. After use, it is important to clean the knife to prevent the spread of bacteria and to keep the knife in good condition. Finally, the clean knife should be stored in a knife block to protect it from damage and to keep it organized.

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Answer:

Make sure both cars are in park or neutral with the parking brake engaged. This makes sure that all electrical functions (headlights, radios, etc.) are turned off.

When jump starting a car, make sure it is in the right distance of the cables to reach battery.

Thus, when jump-starting a car, always remember the cables are in the right position.

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Answer:

Weight Percentage of Ash = 3.4

Explanation:

Given - Coal containing 21% ash is completely combusted, and the ash is 100% removed in a water contact scrubber. If 10,000 kg of coal is burned per hour with a scrubber flow rate of 1.0 m3/min.

To find - the weight percentage of the ash in the water/ash stream leaving the scrubber is most nearly ?

Solution -

Given that,

Coal Burned Rate = 10,000 kg/hr

                              = \(\frac{10,000}{60 min} * 1 hr *\frac{kg}{hr}\)

                              = 166.6666 kg/min

⇒Coal Burned Rate = 166.6666 kg/min

Now,

Given that,

Ash content in coal = 21 %

⇒Ash in (coal that burned) = 166.6666 × \(\frac{21}{100}\) kg/min

                                             = 34.9999 ≈ 35 kg/min

⇒Ash in (coal that burned) = 35 kg/min

Now,

We know,

Density of water = 1000 kg/m³

Now,

Water flow Rate = \(1\frac{m^{3} }{min} * density\)

                           = 1000 kg/min

⇒Water flow Rate = 1000 kg/min

Now,

Total Mass flow Rate of (Water + Ash stream) = ( 1000 + 35) kg/min

                                                                           = 1035 kg/min

⇒Total Mass flow Rate of (Water + Ash stream) = 1035 kg/min

So,

Weight Percentage of Ash = (Weight of Ash ÷ Total weight of Stream) × 100

                                            = (35 ÷ 1035) × 100

                                            = 3.38 ≈ 3.4

∴ we get

Weight Percentage of Ash = 3.4

The statement It is similar to sleep-walking Option(b) is the one that best describes "sleep-driving".

Driving while fatigued or drowsy is known as sleep driving. This typically occurs when a driver hasn't had enough sleep, but it can also occur as a result of untreated sleep disorders, drug use, alcohol consumption, or shift employment.

According to the Division of Sleep Medicine at Harvard Medical School, there are 250,000 drivers who consistently fall asleep behind the wheel in the United States. In a public survey conducted by the National Sleep Foundation, 54% of adult drivers admitted to driving while drowsy in the previous year, with 28% admitting to actually falling asleep behind the wheel.

The National Highway Traffic Safety Administration estimates that tired driving causes more than 100,000 accidents, resulting in around 6,550 fatalities.

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The assertion It is comparable to sleepwalking. Option (b) best describes "sleep-driving"

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To solve this problem, we need to use the formula for the volume of a pyramid: V = (1/3)Bh, where B is the area of the base and h is the height of the pyramid.

We know that the base of the pyramid is a square with side lengths of 13 yards, so its area is 13^2 = 169 square yards. We also know that the volume of the pyramid is 1450 cubic yards.

Substituting these values into the formula, we get:
1450 = (1/3)(169)h

Multiplying both sides by 3, we get:
4350 = 169h

Dividing both sides by 169, we get:
h = 25.74

Therefore, the height of the pyramid is approximately 25.74 yards.

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Answer:

volunteer coordinator

Explanation:

because they are volunteering for that and in most of the cases they do not expect to be paid

The f(4) using is found using newton's interpolating polynomials of order 4.

function y=CL10_Exercise(part)

%% Input

% part: string for part a,b,c,d

%

%% Output

% y value of the underlying function at x=4

%

%% Write your code here

X=[1,2,3,5,6];

Y=[15,8,5.5,30,52];

x=4;

y=1;

switch part

case 'a'

%% Newton interpolation (Order 4)

a=X;

b=Y;

%x=input('Enter x: ');

[m,n]=size(a);

fx=0;

for i=1:n

%_____________Calculating Dividing Difference_____________________

s=0;

for j=1:i

p=1;

for k=1:i %Denominator part product

if(k~=j)

p=p*(a(j)-a(k));

end

end

s=s+b(j)/p; %summation f(x)/product

end

%_________________________________________________________________

p=1;

for j=1:i-1 %coefficient part of f[...]

p=p.*(x-a(j));

end

fx=fx+s.*p; %Polynomial!

end

y=fx;

case 'b'

%% not-a-knot spline

case 'c'

%% clamped spline

case 'd'

%% Hermite spline

end

end

Hence, the f(4) using is found using newton's interpolating polynomials of order 4.

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Answer:

fan

Explanation:

Answer:

It is possible for a marginal weld to perform its job successfully in some cases, but it is generally not recommended as it may be more likely to fail or cause other problems compared to a high-quality weld. It is important to use high-quality welding techniques and materials to ensure that the weld is strong and able to perform its intended function effectively.

Explanation:

A weld is considered marginal if it meets the minimum acceptable standards for quality, but is not necessarily of the highest quality. In some cases, a marginal weld may be able to perform its intended job successfully, but it may be more susceptible to failure or other issues compared to a high-quality weld.

Whether a marginal weld can perform its job successfully depends on a number of factors, including the type of materials being welded, the conditions under which the weld is being made, and the intended use of the welded joint. In some cases, a marginal weld may be sufficient for a low-stress application, but it may not be able to withstand higher levels of stress or strain.

Answer:

yes maybe

Explanation:

I have a project and everyone in the world will know about it.

Answer:

both

Explanation:

Answer:

D) All of the above.

Answer:

I am not sure it's confusing