Technician A says that a radio may be able to receive AM signals, but not FM signals if the antenna is defective. Technician B says that a good antenna should give a reading of about 500 ohms when
tested with an ohmmeter between the center antenna wire and ground. Which technician is correct?
A. Technician A only
B. Technician B only
C. Both Technician A and Technician B
D. Neither Technician A nor Technician B

Answer:

1. 1111.5MPa

2. 56.1GPa

Explanation:

1. Longitudinal tensile stress can be obtained by obtaining the strength and volume of the fiber reinforcement. The derived formula is given by;

σcl = σm (1 - Vf) + σfVf

Substituting the figures, we will have;

45(1 - 0.30) + 3600(0.30)

45(0.70) + 1080

31.5 + 1080

= 1111.5MPa

2. Longitudinal modulus of elasticity or Young's modulus is the ability of an object to resist deformation. The derived formula is given by;

Ecl = EmVm + EfVf

Substituting the formula gives;

= 2.4 (1 - 0.30) + 131 (0.30)

= 2.4(0.70) + 39.3

= 16.8 + 39.3

= 56.1GPa

Using the appropriate relation, the longitudinal tensile stress and the longitudinal modulus are 1111.50 and 56.10 respectively.

Longitudinal tensile stress can be obtained using the relation :

Substituting the values into the relation:

45(1 - 0.30) + 3600(0.30)

45 × 0.70 + 1080

31.5 + 1080

= 1111.50 MPa

2.)

Longitudinal modulus of elasticity is obtained using the relation :

Substituting the values thus :

2.4 (1 - 0.30) + 131 (0.30)

= 2.4 × 0.70 + 39.3

= 16.8 + 39.3

= 56.10 GPa

Hence, the longitudinal tensile stress and the longitudinal modulus are 1111.50 and 56.10 respectively.

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Answer:

Answer is. (d) all of the above

Answer:

my answer is D

Explanation:

all of the above

Answer: A sample of the representative outcomes or sequences of events for all possible consequences of a model is called a scenario.

To determine the required diameter of the hollow circular column, we can use both the Euler and J.B. Johnson methods.

1. Euler's Formula:

Euler's formula is used to determine the critical buckling load of a column. It is given by:

P_critical = (π² * E * I) / (L_effective)²,

where P_critical is the critical buckling load, E is the modulus of elasticity, I is the moment of inertia, and L_effective is the effective length of the column.

For a hollow circular column, the moment of inertia is given by:

I = (π/64) * (D₂⁴ - D₁⁴),

where D₂ is the outer diameter and D₁ is the inner diameter.

Now, let's calculate the diameter using Euler's formula:

P_critical = (π² * E * [(π/64) * (D₂⁴ - D₁⁴)]) / (L_effective)².

We can rearrange the formula to solve for D₂:

D₂ = ((64 * P_critical * (L_effective)²) / (π² * E * (D₁⁴ - D₂⁴)))^(1/4).

Given:

Load (P) = 10,000 lb,

Length (L) = 40 in,

Modulus of Elasticity (E) for AISI C1020 steel = 29,000 ksi,

D₁ = 0.75D (Diameter ratio),

N = 3 (number of buckling waves).

Using the given diameter ratio, we can express D₂ in terms of D₁:

D₂ = 1.33D₁.

Using Euler's formula, we can calculate the diameter D₂:

D_euler = ((64 * P_critical * (L)²) / (π² * E * (D₁⁴ - D₂⁴)))^(1/4).

2. J.B. Johnson's Formula:

J.B. Johnson's formula is used to determine the allowable load of a column. It is given by:

Allowable Load = (π² * E * I) / [(L_effective / R)² + 1],

where R is the radius of gyration.

The radius of gyration is given by:

R = √(I / A),

where A is the cross-sectional area.

For a hollow circular column:

A = (π/4) * (D₂² - D₁²).

Now, let's calculate the diameter using J.B. Johnson's formula:

Allowable Load = (π² * E * [(π/64) * (D₂⁴ - D₁⁴)]) / [(L_effective / √((π/4) * (D₂² - D₁²)))² + 1].

We can rearrange the formula to solve for D₂:

D₂ = √[((Allowable Load * (L_effective / √((π/4) * (D₂² - D₁²)))² + 1) * (64 * (D₁⁴ - D₂⁴)) / (π² * E))].

Given the same values as above, we can calculate the diameter using J.B. Johnson's formula:

D_jb_johnson = √[((Allowable Load * (L)²) * (64 * (D₁⁴ - D₂⁴)) / (π² * E * √((π/4) * (D₂² - D₁²)))² + 1)].

By substituting the values into the formulas, we can find the respective diameters using both Euler's and J.B. Johnson's methods.

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An example of them working together would be something like building a robot. Technologists would work on this project bc they would code the robot. Engineers would work on this bc they would design the interior. A mathematician would work in this bc a mathematician would calculate the angels of when a robot picks something up or when it turns. A scientist would work on this bc the scientist know about physics. You need physics so u know how much force to apply, how much energy to use, how much mass u need, and how much charge u need.

Explanation:

Answer:

Following are the responses to the given question:

Explanation:

Answer:

They moved fresh water around their vast empire with aqueducts and canals.

Explanation:

Answer:

The timing light is connected to the ignition circuit and used to illuminate the timing marks on the engine's crankshaft pulley or flywheel, with the engine running. The apparent position of the marks, frozen by the stroboscopic effect, indicates the current timing of the spark in relation to piston position.

Explanation:

:)

Answer:

When driving, you should leave enough clear distance in front of you to be able to come to a stop. This is in case the traffic suddenly slows down, causing you to brake. However, stopping distances vary depending on factors like the weather and your driving speed. The stopping distance will increase the faster you drive and the wetter the road is.

Explanation:

Answer:

Whenever you approach a school bus from any direction, which has stopped to pick up or let off passengers while operating its flashing red lights, you must stop your vehicle at least 25 feet from the school bus. The only time you do not have to stop is when you are on the other side of a divided highway. You must stay stopped until the bus has started again or the bus driver stops operating the flashing red lights.

The analytical expression for the output signal ya(t) would be:

ya(t) = (A/2) [cos((F + t)θ) + cos((F - t)θ)]

Let's assume that the transfer function of the system is represented as H(F), where F represents the frequency.

We can express the input cosine signal as cos(2πFt), where t represents time.

The output signal ya(t) can be obtained by multiplying the input signal with the system's transfer function H(F) in the frequency domain. Mathematically, this can be represented as:

Ya(F) = H(F) x Cos(Ft)

Let's assume that at the frequency F, the transfer function H(F) can be represented as H(F) = A x cos(θ),

where A represents the magnitude and θ represents the phase shift.

Substituting this into the equation, we get:

Ya(F) = A x cos(θ) x cos(Ft)

Using the trigonometric identity

cos(A) cos(B) = (1/2)  [cos(A + B) + cos(A - B)]

Ya(F) = (A/2) [cos((F + t)θ) + cos((F - t)θ)]

Therefore, the analytical expression for the output signal ya(t) would be:

ya(t) = (A/2) [cos((F + t)θ) + cos((F - t)θ)]

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Answer: the minimum mass flow rate of air required to generate a power output of 105 MW is 238.2 kg/s

Explanation:

from the T-S diagram, we get the overall pressure ratio of the cycle is 9

Calculate the pressure ratio in each stage of compression and expansion. P1/P2 = P4/P3  = √9 = 3

P5/P6 = P7/P8  = √9 =3  

get the properties of air from, "TABLE A-17 Ideal-gas properties of air", in the text book.

At temperature T1 =300K

Specific enthalpy of air h1 = 300.19 kJ/kg

Relative pressure pr1 = 1.3860  

At temperature T5 = 1200 K

Specific enthalpy h5 = 1277.79 kJ/kg

Relative pressure pr5 = 238  

Calculate the relative pressure at state 2

Pr2 = (P2/P1) Pr5

Pr2 =3 x 1.3860 = 4.158  

get the two values of relative pressure between which the relative pressure at state 2 lies and take the corresponding values of specific enthalpy from, "TABLE A-17 Ideal-gas properties of air", in the text book.  

Relative pressure pr = 4.153

The corresponding specific enthalpy h = 411.12 kJ/kg  

Relative pressure pr = 4.522

The corresponding specific enthalpy h = 421.26 kJ/kg  

Find the specific enthalpy of state 2 by the method of interpolation

(h2 - 411.12) / ( 421.26 - 411.12) =  

(4.158 - 4.153) / (4.522 - 4.153 )

h2 - 411.12 = (421.26 - 411.12) ((4.158 - 4.153) / (4.522 - 4.153))  

h2 - 411.12 = 0.137

h2 = 411.257kJ/kg  

Calculate the relative pressure at state 6.

Pr6 = (P6/P5) Pr5

Pr6 = 1/3 x 238 = 79.33  

Obtain the two values of relative pressure between which the relative pressure at state 6 lies and take the corresponding values of specific enthalpy from, "TABLE A-17 Ideal-gas properties of air", in the text book.  

Relative pressure Pr = 75.29

The corresponding specific enthalpy h = 932.93 kJ/kg  

Relative pressure pr = 82.05

The corresponding specific enthalpy h = 955.38 kJ/kg  

Find the specific enthalpy of state 6 by the method of interpolation.

(h6 - 932.93) / ( 955.38 - 932.93) =  

(79.33 - 75.29) / ( 82.05 - 75.29 )

(h6 - 932.93) = ( 955.38 - 932.93) ((79.33 - 75.29) / ( 82.05 - 75.29 )

h6 - 932.93 = 13.427

h6 = 946.357 kJ/kg

Calculate the total work input of the first and second stage compressors

(Wcomp)in = 2(h2 - h1 ) = 2( 411.257 - 300.19 )

= 222.134 kJ/kg  

Calculate the total work output of the first and second stage turbines.

(Wturb)out = 2(h5 - h6) = 2( 1277.79 - 946.357 )

= 662.866 kJ/kg  

Calculate the net work done

Wnet = (Wturb)out  - (Wcomp)in

= 662.866 - 222.134

= 440.732 kJ/kg  

Calculate the minimum mass flow rate of air required to generate a power output of 105 MW

W = m × Wnet

(105 x 10³) kW = m(440.732 kJ/kg)

m = (105 x 10³) / 440.732

m = 238.2 kg/s

therefore the minimum mass flow rate of air required to generate a power output of 105 MW is 238.2 kg/s

Answer:

the pitch point im pritty sure what is is

The point of contact of two pitch circles of mating gears is called the pitch point.

A pitch point is where two pitch circles frequently come into touch. A common point of contact between two pitch circles of mating gears is called a pitch point. The pitch circle and is centered on the top of the teeth. Dedendum circle, also known as the root circle, is the circle traced through the base of the tooth.

The pressure angle, often known as the “tooth shape,” is the angle at which pressure from one gear's tooth is transferred to another gear's tooth. Pure rolling motion will occur at pitch point.

Therefore, it is pressure point.

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The power dissipated or delivered by element 5 can be calculated by subtracting the power absorbed by elements 1, 2, and 3 from the power delivered by element 4.

Therefore, the power dissipated or delivered by element 5 is P5 = P4 - (P1 + P2 + P3) = 820 mW - (730 mW + 762 mW + 170 mW) = -32 mW. This means that element 5 is absorbing 32 mW of power.The power dissipated or delivered by element 5 can be calculated by subtracting the power absorbed by elements 1, 2, and 3 from the power delivered by element 4. Therefore, the power absorb delivered by element 5 is P5 = P4 - (P1 + P2 + P3) = 820 mW - (730 mW + 762 mW + 170 mW) = -32 mW. This means that element 5 is absorbing 32 mW of power. This is because the total power absorbed by elements 1, 2, and 3 is greater than the power delivered by element 4. Therefore, element 5 must absorb the difference in order to maintain the balance of power in the circuit.

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On axonometric projection, all lines indicating height, width, and depth remain parallel.

In axonometric projection, which is a type of orthographic projection, the lines representing the three dimensions (height, width, and depth) of an object are drawn parallel to each other. This means that regardless of the distance or position of an object in relation to the viewer, the lines representing its dimensions do not converge or diverge.

Axonometric projection is commonly used in technical and architectural drawings to accurately represent three-dimensional objects on a two-dimensional surface. By keeping all lines parallel, it provides a consistent and proportional representation of the object's dimensions.

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As the angle of the ramp is increased, the force parallel increases. Hence, option (a) can be considered as the correct answer.

When the angle of a ramp is increased, the force parallel to the ramp, also known as the parallel component of the gravitational force, does increase. This is because the component of gravity acting parallel to the ramp increases with the angle. However, it's important to note that the total gravitational force acting on an object remains constant regardless of the angle of the ramp.As the angle of the ramp increases, the force required to push or pull an object up the ramp against gravity increases. This is due to the increase in the vertical component of the gravitational force, which opposes the motion up the ramp. The parallel force required to overcome this increased vertical force also increases.

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Answer: Answer is below <3

Explanation: When operating, the cutting or grinding disc may come into contact with a body part, or shatter and throw off pieces at extremely high speed. An operator could easily sustain cuts, abrasions, burns or eye injuries.

The use of the 'what-if' function in MS Excel makes a decision a type of forecast and scenario model.

In MS Excel, the 'what-if' function allows changing the values in cells to check to see how those changes affect the outcome of formulas on the worksheet. When the 'what-if' function of Excel is used to check different outcomes of decisions based on different values on input, it is considered a type of forecast and scenario model.  The forecast and scenario model depicts a strategic method for businesses that is used to plan various potential futures. These scenarios are forecasted on the basis of visible risks and assumed uncertainties existing in a set of plausible situations. In short, it can be said that it helps to model multiple 'what-if' scenarios to be prepared for the future.

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Assuming that the same pressure is applied, but the inside diameter of a conduit is tripled, what is the increase in flow rate of the fluid?

The flow rate of a fluid is directly proportional to the fourth power of the radius of the conduit through which it flows.

According to the formula, if the radius is tripled, the flow rate will increase by a factor of 81.

Hence, the answer is option B:

81 times the initial flow.

The linear velocity of blood flow (cm/sec) in a medium-sized artery is the most significant closest to the wall of the vessel.

The linear velocity of blood flow (cm/sec) in a medium-sized artery is most significant closest to the wall of the vessel.

The velocity of blood flow at the center of the vessel is the lowest, while the velocity of blood flow closest to the wall of the vessel is the greatest.

This effect, which is caused by friction, is referred to as the parabolic flow profile or parabolic velocity profile.

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An affordance in an object's design is how well the user loves the interface. An affordance is not an object's "attribute" as a result (like a physical object or a User Interface).

A user's ability-based potential with an object is referred to as its affordance. An affordance is not an object's "attribute" as a result (like a physical object or a User Interface). A user's ability-based potential with an object is referred to as its affordance. An affordance is not an object's "attribute" as a result (like a physical object or a User Interface). An affordance is instead defined by the interaction between the user and the thing: A door can be opened if you can get to the handle. The door cannot be opened if a young child cannot grasp the handle. An affordance is essentially a potential for an action in the interaction between a user and an object.

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A strategy that may help a visual learner process data is a pie chart or histogram.

The rate of heat addition to the engine is approximately 3355.2 kJ/min. In order to determine the rate of heat addition, we need to calculate the air standard efficiency of the engine first.

The air standard efficiency (η) is given by the equation: η = 1 - (1/r)^(γ-1) where r is the compression ratio and γ is the specific heat ratio (cp/cv). To calculate the compression ratio, we need to determine the minimum and maximum enclosed volumes. The minimum enclosed volume (Vmin) is given as 15 percent of the maximum enclosed volume (Vmax). The compression ratio (r) is then calculated as: r = Vmax/Vmin Given that the engine is a six-cylinder, 4-L engine, we can determine the maximum enclosed volume as: Vmax = (4 L/cylinder) * (6 cylinders) = 24 L = 0.024 m³ And the minimum enclosed volume is: Vmin = 0.15 * Vmax = 0.15 * 0.024 m³ = 0.0036 m³ Thus, the compression ratio is: r = Vmax/Vmin = 0.024 m³ / 0.0036 m³ = 6.67 Next, we can calculate the air standard efficiency using the given specific heat ratio (γ = 1.4) and compression ratio (r = 6.67): η = 1 - (1/6.67)^(1.4-1) = 0.536

The air standard efficiency represents the fraction of the maximum possible work that can be obtained from the engine cycle. We are given that the engine produces 60 hp (1 hp = 746 W) when operated at 2500 rpm. Using the air standard efficiency, we can calculate the rate of heat addition (Qin) using the equation: Qin = (Pout * 60) / (η * N) where Pout is the power output, N is the number of revolutions per minute (rpm), and 60 is a conversion factor from minutes to seconds. Converting the power output to watts: Pout = 60 hp * 746 W/hp = 44760 W Substituting the values into the equation, we have: Qin = (44760 W * 60) / (0.536 * 2500 rpm) = 3355.2 kJ/min Therefore, the rate of heat addition to the engine is approximately 3355.2 kJ/min.

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The number of residual plots that you can view at one time is A. two plots.

Analysis of variance is a collection of statistical models and the estimation procedures that go with them that are used to analyze the differences between means. Ronald Fisher, a statistician, invented ANOVA.

ANOVA, which stands for Analysis of Variance, is a statistical test used to compare the means of multiple groups. ANOVA ("analysis of variance") compares the means of two or more independent groups to see if there is statistical evidence that the associated population means differ significantly.

In conclusion, the correct option is A.

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Answer:

The velocity at section is approximately 42.2 m/s

Explanation:

For the water flowing through the pipe, we have;

The pressure at section (1), P₁ = 300 kPa

The pressure at section (2), P₂ = 100 kPa

The diameter at section (1), D₁ = 0.1 m

The height of section (1) above section (2), D₂ = 50 m

The velocity at section (1), v₁ = 20 m/s

Let 'v₂' represent the velocity at section (2)

According to Bernoulli's equation, we have;

\(z_1 + \dfrac{P_1}{\rho \cdot g} + \dfrac{v^2_1}{2 \cdot g} = z_2 + \dfrac{P_2}{\rho \cdot g} + \dfrac{v^2_2}{2 \cdot g}\)

Where;

ρ = The density of water = 997 kg/m³

g = The acceleration due to gravity = 9.8 m/s²

z₁ = 50 m

z₂ = The reference = 0 m

By plugging in the values, we have;

\(50 \, m + \dfrac{300 \ kPa}{997 \, kg/m^3 \times 9.8 \, m/s^2} + \dfrac{(20 \, m/s)^2}{2 \times 9.8 \, m/s^2} = \dfrac{100 \ kPa}{997 \, kg/m^3 \times 9.8 \, m/s^2} + \dfrac{v_2^2}{2 \times 9.8 \, m/s^2}\)50 m + 30.704358 m + 20.4081633 m = 10.234786 m + \(\dfrac{v_2^2}{2 \times 9.8 \, m/s^2}\)

50 m + 30.704358 m + 20.4081633 m - 10.234786 m = \(\dfrac{v_2^2}{2 \times 9.8 \, m/s^2}\)

90.8777353 m = \(\dfrac{v_2^2}{2 \times 9.8 \, m/s^2}\)

v₂² = 2 × 9.8 m/s² × 90.8777353 m

v₂² = 1,781.20361 m²/s²

v₂ = √(1,781.20361 m²/s²) ≈ 42.204308 m/s

The velocity at section (2), v₂ ≈ 42.2 m/s

The scenario that simulates a transitive access attack may include an attacker who exploits a weakness in a shopping website in order to mimic an end user and obtain services from a distributor.

A transitive access attack may be characterized as a type of misuse of trust that causes issues with securing information or control. It attempts to access a back-end server through another server.

A SQL injection attack is an example of a transitive access attack that can bypass many other security controls. For example, if system A trusts B and system B trusts C, then it is possible for system A to inadvertently trust system C, which might lead to exploitation by a nefarious operator on system C.

Therefore, an attacker exploits a weakness in a shopping website in order to mimic an end user and obtain services from a distributor representing a scenario that simulates a transitive access attack.

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The given filter has the following impulse response,wi sin(nw1)\(+ nw1 * w2 sin(nw2) + nw2 * w2 sin(nw2).\)wi is the angular frequency and w1 and w2 are the two distinct angular frequencies with w1 < w2.

h(0) = cos(wi). The filter has a linear phase.the filter's output is given by:y(n) = ∑k= -∞to ∞ x(k) h(n - k)The discrete-time Fourier transform of the filter's impulse response is given by:H(ejw) = cos(wi) + j [wi sin(w1) + ejw1 w1 sin(w1) + ejw2 w2 sin(w2) + ejw1 (w1 + w2) sin(w2)]Thus, the magnitude response of the filter is given by |H(ejw)| and its phase response is given by arg(H(ejw)).

The filter has two zeroes and two poles located on the unit circle of the z-plane. Both the zeroes lie at z = ejw2 and both the poles lie at z = ejw1.The filter's frequency response is characterized by a bandpass with a central frequency equal to w2 and a band width equal to w2 - w1.

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Answer:B

Explanation: Dead Grass more flammable than wood and Green grass contains water.

Vortex generators on the upper side of the wing surface will decrease the intensity of shock wave induced air separation and increase the critical Mach Number.

So, the correct answer is C.

Vortex generators are small devices that are placed on the upper side of an aircraft's wing surface. They are used to improve the aircraft's performance at high speeds.

The primary function of vortex generators is to control the airflow over the wing surface, which helps to reduce drag and increase lift.

When placed on the upper side of the wing surface, vortex generators can increase the critical Mach number, which is the speed at which air flowing over the wing surface reaches supersonic speed. This helps to prevent the formation of shock waves, which can lead to air separation and reduced lift.

Vortex generators also help to reduce the intensity of shock wave-induced air separation and decrease span wise flow at high Mach numbers, which improves the aircraft's stability and handling.

Hence the correct answer is C.

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