Tanya brought a car into a shop for repairs. When she came back to pick up her car, the mechanic
gave her a bill for $800. Tanya was angry because the mechanic made a few repairs that they had
not agreed upon in advance. Tanya and the mechanic ultimately agreed on a final bill that was
25% lower than the initial bill. What was the amount of the revised bill?
(1 point)

Answer:76

Step-by-step explanation:

the median is the middle number but since there was an even amount of numbers, I chose the middle 2 numbers. Since they were the same number they stay as 1 number making the answer 76.

Answer:

Step-by-step explanation:

2,4

Answer: 36x+54k

Step-by-step explanation:

What is the equation? Where is x supposed to go?

A statement which best describe the transformation from Figure 1 to Figure 2 is: C. reflection over the y-axis.

In Mathematics, a reflection can be defined as a type of transformation which moves every point of the geometric figure by producing a flipped, but mirror image of the geometric figure.

In Geometry, a reflection over the y-axis (y = x) is given by this transformation rule (x, y) → (-x, y). This ultimately implies that, a reflection over the y-axis would maintain the same y-coordinate while the sign of the x-coordinate changes from positive to negative or negative to positive.

By applying a reflection over the y-axis to the coordinates of figure 1, the coordinates of figure 2 include the following:

(x, y)                               →              (-x, y)

Coordinate A = (-6, 5)   →  Coordinate A' = (-(-6), 5) = (6, 5).

Coordinate B = (-4, 5)   →  Coordinate B' = (-(-4), 5) = (4, 5).

Coordinate C = (-3, 5)   →  Coordinate C' = (-(-3), 5) = (3, 5).

Coordinate D = (-5, 4)   →  Coordinate D' = (-(-5), 4) = (5, 4).

Coordinate E = (-5, 3)   →  Coordinate E' = (-(-5), 3) = (5, 3).

Coordinate F = (-7, 3)   →  Coordinate F' = (-(-7), 3) = (7, 3).

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Answer: the number of teachers are 14.4 and the amount of students that don’t own laptops of 5400

Step-by-step explanation:

Answer:

Step-by-step explanation:

A more complicated expression such as 64x3+27y3 64 x 3 + 27 y 3 is also a sum of cubes since 64x3=(4x)3 64 x 3 = ( 4 x ) 3 and 27y3=(3y)3 27 y 3 = ( 3 y ) 3 . Please note, that expressions such as 2x3 2 x 3 are not perfect cubes.

Answer:

Let y = f(x) be a function with an independent variable x and a dependent variable y.

If a function f provides a way to successfully produce a single value y using for that purpose a value for x then that

chosen x-value is said to belong to the domain of f. If there is a requirement that a y-value produced by a function

must be a real number, the following conditions are commonly checked:

1. Denominators cannot equal 0.

2. Radicands (expressions under a radical symbol) of even roots (square roots, etc)  

cannot have a negative value.

3. Logarithms can only be taken of positive values.

4. In word problems physical or other real-life restrictions might be imposed, e.g. time is  

nonnegative, number of items is a nonnegative integer, etc.

Answer:

the domain is a set of all possible numbers inputs for that function, THe range is all the possible output numbers

i hope this helps

A bijection between two sets is constructed below and also proved that it is both one-one and onto.

The phrase "one-to-one function" should not be mistaken with "one-to-one correspondence," which is used to describe bijective functions, in which each element in the codomain is a precise mirror image of a single element in the domain.

Any function that can work with the operations of two algebraic structures is said to be a homomorphism between them. An injective homomorphism is also referred to as a monomorphism for any commonly occurring algebraic structures, particularly vector spaces.

Let t∈T

Then,

t=2k+1, for some k∈Z

Let s=3k

Then,

s∈S and f(s)=2(s/3)+1

=2k+1

=t

Therefore, for every t∈T there exists s∈S such that f(s)=t

Thus, f is onto.

Hence,

f:S  ----> T is a bijective mapping

⇒|S|=|T|

Now, we have to define a mapping f:S ---?T

By f(x)=2(x/3)+1, ∀x∈S

Given,

S={3k|k∈Z} and T={2k+1:k∈Z}

We have to prove:

|S|=|T|

Let x, y∈ S with f(x)=f(y)

Then,

2(x/3)+1=2(y/3)+1

2(x/3)=2(y/3)

(x/3)=(y/3)

x=y

So, f is one-one

Now, we have proved that f is both one-one and onto.

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Answer:

12%

3/25 Would Be Equal To 12%

Given the following equation:

You can solve for the variable "x" by following the steps shown below:

Step 1. Apply the Distributive property by multiplying eact term inside the parentheses by -5:

Step 2. Add the like terms on the left side of the equation:

Step 3. Apply the Substraction property of equality by subtracting 15 from both sides of the equation:

Step 4. Finally, apply the Division property of equality by dividing both sides of the equation by 2:

The answer is:

Did you understand?

Answer:

.02

Step-by-step explanation:

Answer:

false

Step-by-step explanation:

Answer:

false

Step-by-step explanation:

Answer:

C) -3, -1, 1

Step-by-step explanation:

\(f(x)=0\) where the function crosses the x-axis. Therefore, these values of x are -3, -1, and 1.

Answer:

The answer is option A

Step-by-step explanation:

Reflection in the y axis is

(x , y) → ( - x , y)

The coordinates of A are ( 2, -5)

When it's reflected in the y axis it becomes

( - 2 , - 5)

Hope this helps you

Answer:

on my problem the triangle isn't upside down

Step-by-step explanation:

Answer:

Point N and point K

Step-by-step explanation:

The steeper a line is in the graph, the greater the value of the slope of the line would be, and also, the farther it would be from 0. On the other hand, the more gentle and less sloppy a line is, the smaller the value of the slope is, and also, the closer it is to 0.

From the graph given, there are possible set of points in a line that have a gentle line slope.

The first is, points N and K. The slope of this line is ⅑.

The second is, points P and L. The slope of this line is ⅙.

From the two above lines, the one with a slope closest to 0 is the line that runs through points N and K. ⅑ is closer to 0 than ⅙.

Answer:425.25

Step-by-step explanation:

539.50-

35.50-

23.75-

55.00=

Answer:

\(4(x + 1)^{2}(x - 1)^{2}\)

Step-by-step explanation:

STEP 1:

The equation at the end of step 1

\(((4 (x^4)) - 2^3x^2) + 4\)

STEP 2:

The equation at the end of step 2:

\((2^2x^4 - 2^3x^2) + 4\)

STEP 3:

STEP 4: Pulling out like terms

4.1 Pull out like factors:

\(4x^4 - 8x^2 + 4 = 4(x^4 - 2x^2 + 1)\)

Trying to factor by splitting the middle term

4.2 Factoring \(x^4 - 2x^2 + 1\)

The first term is, \(x^4\) its coefficient is 1.

The middle term is,  \(-2x^2\)  its coefficient is -2.

The last term, "the constant", is +1.

Step-1: Multiply the coefficient of the first term by the constant   1 • 1 = 1

Step-2: Find two factors of  1  whose sum equals the coefficient of the middle term, which is -2.

-1 + -1 = -2 That's it

Step-3: Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -1  and  -1

                    x4 - 1x2 - 1x2 - 1

Step-4 : Add up the first 2 terms, pulling out like factors :

                   x2 • (x2-1)

             Add up the last 2 terms, pulling out common factors :

                    1 • (x2-1)

Step-5 : Add up the four terms of step 4 :

                   (x2-1)  •  (x2-1)

            Which is the desired factorization

Trying to factor as a Difference of Squares:

4.3      Factoring:  x2-1

Theory : A difference of two perfect squares,  A2 - B2  can be factored into  (A+B) • (A-B)

Proof :  (A+B) • (A-B) =

        A2 - AB + BA - B2 =

        A2 - AB + AB - B2 =

        A2 - B2

Note :  AB = BA is the commutative property of multiplication.

Note :  - AB + AB equals zero and is therefore eliminated from the expression.

Check : 1 is the square of 1

Check :  x2  is the square of  x1

Factorization is :       (x + 1)  •  (x - 1)

Trying to factor as a Difference of Squares:

4.4      Factoring:  x2 - 1

Check : 1 is the square of 1

Check :  x2  is the square of  x1

Factorization is :       (x + 1)  •  (x - 1)

Multiplying Exponential Expressions:

4.5    Multiply  (x + 1)  by  (x + 1)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is  (x+1)  and the exponents are :

         1 , as  (x+1)  is the same number as  (x+1)1

and   1 , as  (x+1)  is the same number as  (x+1)1

The product is therefore,  (x+1)(1+1) = (x+1)2

Multiplying Exponential Expressions:

4.6    Multiply  (x-1)  by  (x-1)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is  (x-1)  and the exponents are :

         1 , as  (x-1)  is the same number as  (x-1)1

and   1 , as  (x-1)  is the same number as  (x-1)1

The product is therefore,  (x-1)(1+1) = (x-1)2

Final result :

 4 • (x + 1)2 • (x - 1)2

The perimeter and area of each of the composite figure is:

a. Area: 138.6 mm²; Perimeter = 50.27 mm.

b. Area: 120.5 cm²; Perimeter = 42.7 cm

c. Area: 521.1 mm²; Perimeter: 95.8 mm

Area of a circle = πr²

Area of a triangle = 1/2(base)(height).

Area of a rectangle = (length)(width).

The perimeter of a composite figure = the sum of all lengths of the sides surrounding the composite figure.

a. The area of the composite figure = area of rectangle + area of two semicircles

Two semicircles = 1 circle

Area of the rectangle = (15)(5) = 75 mm²

Area of the two semicircles = πr² = π(4.5²) = 63.6 mm²

The area of the composite figure = 75 + 63.6 = 138.6 mm².

Perimeter = 5(2) + 4(3) + (perimeter of 1 circle)

Perimeter = 5(2) + 4(3) + (2πr)

Perimeter = 5(2) + 4(3) + (2π(4.5))

Perimeter = 50.27 mm.

b. Area = area of triangle + area of square + area of half circle

Area = 1/2(base)(height) + s² + 1/2(πr²)

Base = 5 cm

Height = 7 cm

s = √(7² + 5²) = 8.6 cm [Pythagorean theorem]

r = 8.6/2 = 4.3 cm

Area = 1/2(5)(7) + 8.6² + 1/2(π(4.3²))

Area = 120.5 cm²

Perimeter = 5 + 7 + 8.6 + 8.6 + (perimeter of half circle)

Perimeter = 5 + 7 + 8.6 + 8.6 + 1/2(2πr)

Perimeter = 5 + 7 + 8.6 + 8.6 + (2π(4.3))

Perimeter = 42.7 cm

c. Area = area of triangle + area of rectangle + area of half circle

Area = 1/2(base)(height) + (length)(width) + 1/2(πr²)

Base = 32 - 20 = 12 mm

Height = 14 mm

Length = 20 mm

Width = 14 mm

r = 1/2(20) = 10 mm

Area = 1/2(12)(14) + (20)(14) + 1/2(π(10²))

Area = 521.1 mm²

Perimeter = 14 + 32 + hypotenuse of the triangle + (perimeter of half circle)

Hypotenuse = √(12² + 14²) = 18.4 mm

Perimeter of half circle = 1/2(2πr) = 1/2(2π(10)) = 31.4

Perimeter of the composite figure = 14 + 32 + 18.4 + 31.4

Perimeter of the composite figure = 95.8 mm

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It is a rectangular region with u and v values ranging from 1 to 2.

To find the Jacobian of the transformation x = 3u, y = 2uv, we need to compute the partial derivatives ∂x/∂u, ∂x/∂v, ∂y/∂u, and ∂y/∂v.

Given:

x = 3u

y = 2uv

Calculating the partial derivatives:

∂x/∂u = 3

∂x/∂v = 0 (since x does not depend on v)

∂y/∂u = 2v

∂y/∂v = 2u

Now, we can construct the Jacobian matrix J:

J = [∂x/∂u   ∂x/∂v]

   [∂y/∂u   ∂y/∂v]

Substituting the partial derivatives we calculated earlier:

J = [3   0]

   [2v  2u]

Therefore, the Jacobian of the transformation is:

J = [3   0]

   [2v  2u]

To sketch the region described by the inequalities g: 3 < 3u < 6, 2 < 2uv < 4, we can consider the ranges of u and v that satisfy these conditions.

From the inequality 3 < 3u < 6, we have:

1 < u < 2

From the inequality 2 < 2uv < 4, we can divide both sides by 2:

1 < uv < 2

Since u and v must both be greater than 1, we can determine the range of v:

1 < v < 2

Now, we can sketch the region in the u-v plane bounded by the conditions:

1 < u < 2

1 < v < 2

It is a rectangular region with u and v values ranging from 1 to 2.

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Answer:

please mark as brainlist answers

Answer:

the answer is 0.3274 

Step-by-step explanation:

Answer:

7.0 seconds

Step-by-step explanation:

i did the test but how i know this is bc 3 divided by 21 is 7

NOT 9

DON'T USE 9 AS THE ANSWER

Answer:

7.0 seconds

Step-by-step explanation:

Answer:

Subtract 15 from both sides.

5t > 35

Divide both sides by 5.

t > 7

(Sorry, I can't do the > with the _ under it.)

Please mark me Brainliest; I need it to move onto the next level. =D

The mid-point of the sides of this quadrilateral are the vertices of a parallelogram.

You should know that in every parallelogram, the opposite sides are equal and parallel.

The given vertices are (2,4), (5,8), (9,5) and (6,1).

Let the vertices be A,B,C,D And the midpoints of the sides be M, N, O, P

Coordinates of A  (2+5)/2 , (4+8)/2 = (3.5 , 6)

Coordinates of B  (5+9)/2 , (8+5)/2 = (7,6.5)

Coordinates of C  (9+6)/2 , (5+1)/2 = (7.5, 3)

Coordinates of D  (6+2)/2 , (1+4)/2 = (4 , 2.5)

The distance between the vertices is denoted by the formula

distance = \(\sqrt{(x_{1}-x_{2})^{2}+(y_{1}-y_{2})^{2} }\)

AB= √(3.5-7)²+(3-6.5)² = √12.5 = 3.5

BC= √(7-7.5)²+(6.5.3)² = √6.5 = 2.5

CD= √(7.5-4)²+(3-2.5)² = √12.5 = 3.5

DA= √(4-3.5)²+(2.5-6)² = √6.5 = 2.5

From the calculations, it is clear that  the opposite side of the quadrilateral are equal

This means that quadrilateral is a parallelogram

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The correct question:

A quadrilateral has the vertices at the point (2,4), (5,8), (9,5) and (6,1). Show that the mid-point of the sides of this quadrilateral are the vertices of a parallelogram.