Answer:
52,915 multiplied by 2% (0.02)
Step-by-step explanation:
52,915*0.02= $1058.30
4# is a two digit number ,where # represents the digit at ones place . 7999 ÷ 4# lies between ---------
Answer:
\(7999 \div 4\#\) lies between 163.245 and 199.975
Step-by-step explanation:
Given
2 digit = 4#
Required
The range of \(7999 \div 4\#\)
Let
\(\# = 0\) --- the smallest possible value of #
So:
\(7999 \div 40 = 199.975\)
Let
\(\# = 9\) --- the largest possible value of #
So:
\(7999 \div 49 = 163.245\)
Hence, \(7999 \div 4\#\) lies between 163.245 and 199.975
1) Consider the interval 0≤x≤L. What is the second derivative, with respect to x, of the wave function ψn(x) in this interval? Express your answer in terms of n, x, L, and C as needed.
d2dx2ψn(x) =
2) What is U(x)ψn(x) in the interval 0≤x≤L? Express your answer in terms of n, L, and C as needed.
U(x)ψn(x) =
3) E is an as yet undetermined constant: the energy of the particle. What is Eψn(x) in the interval 0≤x≤L? Express your answer in terms of n, L, E, and C.
Eψn(x) =
Thus, 1) The second derivative, with respect to x, of the wave function: d2dx2ψn(x) = -Cn^2(pi/L)^2sin(n*pi*x/L).
2) U(x)ψn(x) = 0
3) Eψn(x) = -Cn^2(pi/L)^2Esin(n*pi*x/L)
1) The second derivative, with respect to x, of the wave function ψn(x) in the interval 0≤x≤L can be found by applying the second derivative operator to the wave function:
d2dx2ψn(x) = -Cn^2(pi/L)^2sin(n*pi*x/L)
where n is the quantum number and C is the normalization constant.
2) U(x)ψn(x) is the product of the potential energy function U(x) and the wave function ψn(x) in the interval 0≤x≤L. If the potential energy function is zero in this interval, then U(x)ψn(x) is also zero.
Therefore, U(x)ψn(x) = 0.
3) Eψn(x) is the product of the energy E and the wave function ψn(x) in the interval 0≤x≤L. Substituting the wave function expression from part 1 into this product, we get:
Eψn(x) = -Cn^2(pi/L)^2Esin(n*pi*x/L)
where E is the energy of the particle.
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Answer the question in the photo
Answer:
Step-by-step explanation:
\((\sqrt{m} )^3 \times (\sqrt[3]{m} )^4 \div (\sqrt[6]{m} )^5 = (m^\frac{1}{2})^3 \times (m^\frac{1}{3})^4 \div (m^\frac{1}{6})^5\)
\(= m^\frac{3}{2} \times m^\frac{4}{3} \div m^\frac{5}{6}\)
\(=m^{(\frac{3}{2}+\frac{4}{3} -\frac{5}{6} )}\)
\(=m^{(\frac{9}{6} +\frac{8}{6}-\frac{5}{6})}\)
\(=m^\frac{12}{6}\)
\(=m^2\)
Which modified box plot represents the data set? 39, 39, 3, 40, 46, 48, 60, 62, 62.
Answer:
To find this question, you first should put your data values in order from least to greatest. Doing so would look like this:
39, 39, 3 , 40 , 46 , 48 , 60 , 62 ,62
Now find the median, the middle number. This would be 46. This would also be the middle point on your box and whisker plot. Looking at your answer choices, the only one that has the middle point at 46 is the last one. So that is your answer.
Step-by-step explanation:
Answer:
its 39
Step-by-step explanation:
A piece of wire is 7/8m long broke into two piece one piece is 1/4 m long how long is the other one ?
Answer: 5/8m
Step-by-step explanation:
From the question, we are informed that a piece of wire is 7/8m long and broken into two piece. We are further told that one piece is 1/4 m long.
The length of the other piece of wire would be calculated as:
= 7/8 - 1/4
= 7/8 - 2/8
= 5/8m
| Dmitry is making a recipe that uses 1 pound of wheat flour and 10 ounces of almond flour. How much flour will he use in all?
If Dmitry is making a recipe that uses 1 pound of wheat flour and 10 ounces of almond flour then he will require total 26 ounces of flour.
Given that Dmitry is making a recipe that uses 1 pound quantity of wheat flour and 10 ounces of almond flour.
We are required to find the total quantity of total flour that Dmitry uses.
Quantity or amount is basically a property that can exist as a multitude or magnitude,
We know that 1 pound is equal to 16 ounces.
Quantity of wheat flour=1 pound
In 1 pound of wheat flour=16 ounces of wheat flour.
Quantity of almond flour=10 ounces
Total requirement of flour=16+10
=26 ounces.
Hence if Dmitry is making a recipe that uses 1 pound of wheat flour and 10 ounces quantity of almond flour then he will require 26 ounces of flour.
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How would you describe the shape of the normal distribution?
The shape of the normal distribution is bell shape and it is also symmetrical from the left and right sides about the origins (mean).
What is a normal distribution?
A normal distribution is a function on some random variables, which represent the set of all those random variables in a symmetrical bell shape about the mean value.
It shows that the probability of occurrence of some data which is distributed over a function is more at or around the mean.
It is also known as probability distribution curve.
The normal distribution has two parameters:
MeanStandard deviationWhat is the shape of the normal distribution?
The normal distribution curve is at it's peak at the mean value. This shows that the probability of occurrence of the data or value is more concentrated or distributed about the mean. It is also symmetric about the mean. As we more further from the mean, we see that the normal distribution curve gradually decreases showing that the probability of occurrence of the data or the values decreases. The shape that this curve forms is like a bell-shaped. So the shape of normal distribution is bell shape.
Hence, the shape of the normal distribution is bell shape and it is also symmetrical from the left and right sides about the origins (mean).
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an environmental protection agency study of 12 automobiles revealed a correlation of 0.47 between engine size and emissions. at the .01 significance level, they want to test whether or not the population correlation is positive. what is the computed value of the test statistic? 0.47 0.22 2.94 1.68
The computed value of the test statistic is 2.94.
What is Statistics?Statistics is the discipline that concerns the collection, organization, analysis, interpretation, and presentation of data.
We have a sample size of n = 12, engine size (x) and emissions (y) are the two variables being correlated, and the sample correlation coefficient is r = 0.47.
The null hypothesis is that the population correlation is zero (H0: ρ = 0) and the alternative hypothesis is that the population correlation is positive (Ha: ρ > 0).
To compute the test statistic, we need to first calculate the degrees of freedom (df), which is (n-2) = 10 in this case.
We can then use the formula for the test statistic, which is:
t = (r√(df)) / √1 - r²
Substituting the values we have, we get:
t = (0.47 √10) / √(1 - 0.47²)
t = 2.94
Therefore, the computed value of the test statistic is 2.94.
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30-60-90 right triangles
Answer:
i think it is either 31 or 15.5
Step-by-step explanation:
Answer:
Step-by-step explanation:
pythagoras theorem.
a squared plus b squared equals hypotenuse squared
a=7
b=24
49+576=625
square root is 25
that's your answer. c=25.
Which inequality represents all values of × for which the quotient below is lefined?
SOLUTION
Given the question in the image, the following are the solution steps to answer the question.
STEP 1: Write the given expression
\(\sqrt{28(x-1)}\div\sqrt{8x^2}\)STEP 2: Simplify the expression
For the quotient to be defined, the numerator and the denominator must be greater than zero, this means that:
\(\begin{gathered} \sqrt{8x^2}>0 \\ \mathrm{Square\:both\:sides} \\ \left(\sqrt{8x^2}\right)^2>0^2 \\ 8x^2>0 \\ x<0\quad \mathrm{or}\quad \:x>0 \end{gathered}\)For the numerator,
\(\begin{gathered} \mathrm{Square\:both\:sides} \\ \left(\sqrt{28\left(x-1\right)}\right)^2>0^2 \\ \mathrm{Simplify} \\ 28x-28>0 \\ x>1 \\ \mathrm{Combine\:the\:intervals} \\ x>1\quad \mathrm{and}\quad \:x\ge \:1 \\ x>1 \end{gathered}\)Merging both interval, we have:
\(\begin{gathered} x<0,x>0,x>1 \\ x>1 \end{gathered}\)Hence, the answer is given as:
\(x>1\)What is the solution of the inequality shown
below?
y+7≤-1
The solution to the inequality is y ≤ -8. This means that any value of y that is less than or equal to -8 will satisfy the original inequality.
To solve the inequality y + 7 ≤ -1, we need to isolate the variable y on one side of the inequality sign.
Starting with the given inequality:
y + 7 ≤ -1
We can begin by subtracting 7 from both sides of the inequality:
y + 7 - 7 ≤ -1 - 7
y ≤ -8
The solution to the inequality is y ≤ -8. This means that any value of y that is less than or equal to -8 will satisfy the original inequality.
In the context of a number line, all values to the left of -8, including -8 itself, will make the inequality true. For example, -10, -9, -8, -8.5, and any other value less than -8 will satisfy the inequality. However, any value greater than -8 will not satisfy the inequality.
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The following question may be like this:
What is a solution of the inequality shown below? y+7≤-1
evaluate ∫cx ds, where c is a. the straight line segment x=t, y= t 5, from (0,0) to (20,4) b. the parabolic curve x=t, y=t2, from (0,0) to (3,9)
(a) ∫cx ds for the straight line segment x=t, y=t⁵ from (0,0) to (20,4):
∫cx ds = ∫t * √(1 + 25t⁸) dt
(b) ∫cx ds for the parabolic curve x=t, y=t² from (0,0) to (3,9):
∫cx ds = ∫t * √(1 + 4t²) dt
What is the linear function?
A linear function is defined as a function that has either one or two variables without exponents. It is a function that graphs to a straight line.
a. Evaluating ∫cx ds for the straight line segment x=t, y=t⁵ from (0,0) to (20,4):
First, we need to parameterize the curve. Let's define t as the parameter:
x = t
y = t⁵
Now, we can find the differential ds:
ds = √(dx² + dy²)
= √((dt)² + (5t⁴ dt)²)
= √(1 + 25t⁸) dt
Next, we substitute the parameterized values into the integral:
∫cx ds = ∫t * √(1 + 25t⁸) dt
Since the integral involves a square root, it might be difficult to find an exact solution. Numerical methods or approximation techniques may be required to evaluate this integral.
b. Evaluating ∫cx ds for the parabolic curve x=t, y=t² from (0,0) to (3,9):
Again, we parameterize the curve using t:
x = t
y = t²
Find the differential ds:
ds = √(dx² + dy²)
= √((dt)² + (2t dt)²)
= √(1 + 4t²) dt
Substitute the parameterized values into the integral:
∫cx ds = ∫t * √(1 + 4t²) dt
This integral may also require numerical methods or approximation techniques to evaluate it, as it involves a square root.
hence, (a) ∫cx ds for the straight line segment x=t, y=t⁵ from (0,0) to (20,4):
∫cx ds = ∫t * √(1 + 25t⁸) dt
(b) ∫cx ds for the parabolic curve x=t, y=t² from (0,0) to (3,9):
∫cx ds = ∫t * √(1 + 4t²) dt
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Determine the mean and standard deviation of the variable X in each of the following binomial distributions. a. n=5 and π=0.10 b. n=3 and π=0.40 c. n=5 and r=0.50 d. n=3 and π=0.80 a. When n=5 and π=0.10, determine the mean. μ= (Type an integer or a decimal. Do not round.)
The mean (μ) for the given binomial distribution is 0.50.
To calculate the mean (μ) of a binomial distribution, we multiply the number of trials (n) by the probability of success in a single trial (π). Let's examine each scenario in detail:
a. When n = 5 and π = 0.10:
μ = 5 * 0.10
= 0.50
For this binomial distribution, with 5 trials and a success probability of 0.10, the mean (μ) is 0.50. This means that, on average, we would expect to have 0.50 successes per trial.
b. When n = 3 and π = 0.40:
μ = 3 * 0.40
= 1.20
In this case, the mean (μ) of the binomial distribution is 1.20. It indicates that, on average, there would be 1.20 successes per trial when there are 3 trials and a success probability of 0.40.
c. When n = 5 and π = 0.50:
μ = 5 * 0.50
= 2.50
For a binomial distribution with 5 trials and a success probability of 0.50, the mean (μ) is 2.50. This means that, on average, we would expect to have 2.50 successes per trial.
d. When n = 3 and π = 0.80:
μ = 3 * 0.80
= 2.40
In this scenario, the mean (μ) of the binomial distribution is 2.40. It suggests that, on average, we would expect to have 2.40 successes per trial when there are 3 trials and a success probability of 0.80.
The mean (μ) provides a measure of the central tendency or the average number of successes in a binomial distribution based on the given parameters.
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What is the greatest common factor of 20x^2,10x, 15
Answer: The greatest common factor is 5.
Which of the following are solutions to the inequality 5 < X ?
The inequality:
\(\begin{gathered} 55 \end{gathered}\)Basically tells us that the solutions will be the numbers strictly greater than 5, so:
\(\begin{gathered} 3>5 \\ False \\ ---- \\ 8>5 \\ True \\ ---- \\ 10>5 \\ True \\ ---- \\ 6>5 \\ True \end{gathered}\)Therefore, the solutions are:
8, 10, 6
tree that is 12 feet tall casts a shadow that is 6 feet long. What is the distance from the top of the tree to the tip of the shadow? Round to the nearest tenth.
Help
Answer:
13.4
Step-by-step explanation:
The tree to the shadow forms a right angle triangle, so to calculate the distance from the tree tip to the shadow tip we can use pythagoras.
a^2 +b^2 = c^2
12^2 +6^2 = 144 +36 = 180 =c^2
Square root of 180 is approx 13.42.
To the nearest 10th = 13.4
1. What is the perimeter of the figure below. Simplify.
4x^3-5x 2x^3+6x 6x^3+x
Answer:
\(12x^3+2x\)
Step-by-step explanation:
The perimeter of a polygon is equal to the sum of its sides.
The sides in the triangle shown have lengths \(2x^3+6x\), \(4x^3-5x\), and \(6x^3+x\) in no specific order.
Since its perimeter is given by the sum of its sides, the perimeter is equal to:
\(2x^3+6x+4x^3-5x+6x^3+x\)
Combine like terms:
\(\boxed{12x^3+2x}\)
Please select the correct answer from the group of answer choices for each part of the question:
1a. Consider the computing load of a sum of 100 scalar variables and one matrix subtraction of a pair of two-dimensional array with dimensions 100x100. Assume the matrix subtraction is fully parallelizable, calculate the speedup using 100 processors assuming 10 processors carry 20% of the load and the rest load is shared among the rest 90 processors evenly?
A: 101/3
B: 101/2
C: 101
D: 100
1b: For the following vector MIPS code DAXPY which performs Y=a x X+Y, fill the two blank instructions.
L.d $f1, a($sp) ;load scalar a
Lv $v0, 0($s0) ;load vector x
__________________ ;vector-scalar multiply
Lv $v2, 0($s1) ;load vector y
___________________ ;add y to product
Sv $v3, 0($s1) ; store the result
A:
mul.d $v1, $v0, $f1
add.d $v3, $v1, $v2
B:
mulvs.d $v1, $v0, $f1
addv.d $v3, $v1, $v2
C:
mul.d $v2, $v0, $f1
add.d $v3, $v1, $v2
D:
mulvs.d $v2, $v0, $f1
addv.d $v3, $v1, $v2
1c. Which of the following statement is incorrect?
A: Both multithreading and multicore rely on parallelism to get more efficiency from a chip.
B: In coarse-grained multithreading, switching between threads only happens after significant events such as last-level cache miss.
C: In fine-grained multithreading, switching between threads happens after every instruction.
D: Simultaneous multithreading (SMT) uses threads to improve resource utilization of statically scheduled processor.
1d. In the roofline model, the attainable GFLOPs/sec is set by _____?
A: Peak Memory BW x Arithmetic Intensity
B: Peak Floating-Point Performance
C: Min (Peak Memory BW x Arithmetic Intensity, Peak Floating-Point Performance)
D: Max (Peak Memory BW x Arithmetic Intensity, Peak Floating-Point Performance)
The correct answer is D: Max (Peak Memory BW x Arithmetic Intensity, Peak Floating-Point Performance).
1a. C: 101 to calculate the speedup, we need to consider the computing load distribution among the processors. In this case, 10 processors carry 20% of the load, which means each of these processors handles 2% of the load. The remaining 90 processors share the rest of the load evenly, so each processor among these 90 handles (100% - 20%) / 90 = 0.8889% of the load.
The speedup can be calculated using Amdahl's Law, which states that the speedup is limited by the portion of the program that cannot be parallelized. In this case, the matrix subtraction is fully parallelizable, so the only portion that cannot be parallelized is the sum of the scalar variables.
The speedup formula is given by: Speedup = 1 / [(1 - p) + (p / n)], where p is the portion that can be parallelized and n is the number of processors.
In this case, p = 0.02 (for the 10 processors) and n = 100. Substituting these values into the formula, we get: Speedup = 1 / [(1 - 0.02) + (0.02 / 100)] = 1 / 0.99 = 1.0101.
Therefore, the correct answer is C: 101.
1b. A:
mul.d $v1, $v0, $f1
add.d $v3, $v1, $v2
The code snippet performs the DAXPY operation, which multiplies a scalar value (a) with a vector (x) and adds the result to another vector (y). The blank instructions should be filled with the above choices.
1c. C: In fine-grained multithreading, switching between threads happens after every instruction.
In fine-grained multithreading, switching between threads happens after every instruction, which is an incorrect statement. Fine-grained multithreading allows switching between threads at a much finer granularity, such as cycle-by-cycle or instruction-by-instruction, to improve resource utilization.
1d. B: Peak Floating-Point Performance
In the roofline model, the attainable GFLOPs/sec is set by the peak floating-point performance of the processor. The roofline model is a performance model that visualizes the performance limitations of a system based on the memory bandwidth and arithmetic intensity of the code. The attainable performance is determined by the lower value between the peak memory bandwidth and the peak floating-point performance. Therefore, the correct answer is B: Peak Floating-Point Performance.
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which choice is equivalent to the expression below ? sqrt -12
The expression that is equivalent to √-12 is √12i
What are complex numbers?In mathematics, a complex number is an element of a number system that extends the real numbers with a specific element denoted i, called the imaginary unit and satisfying the equation\(i^{2}=-1}\) every complex number can be expressed in the forma + bi, where a and b are real numbers.
Given here, √-12= √12×√-1
= √12i
Hence, The expression that is equivalent to √-12 is √12i
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A research team aboard an underwater research vessel descends 1,500 feet beneath the surface of the water.
They then rise 525 feet and descend again 350 feet.Where are t
hey currently located?
Answer:
1325 feet below the surface
The statement new int[3]{1, 2, 3}; allocates an array of three initialized integers on the heap. (True or False)
The statement "new int[3]{1, 2, 3};" allocates an array of three initialized integers on the heap. This statement is True.
In C++, the "new" keyword is used to dynamically allocate memory on the heap. The statement "new int[3]{1, 2, 3};" allocates an array of three integers and initializes them with the values 1, 2, and 3.
The "new int[3]" part of the statement allocates memory for three integers on the heap. The square brackets [3] indicate that an array of size 3 should be allocated. The "int" specifies the type of the elements in the array.
The "{1, 2, 3}" part of the statement initializes the elements of the array with the specified values. In this case, the array elements are initialized to 1, 2, and 3 respectively.
By using the "new" keyword with the initialization values enclosed in curly braces, the array is allocated on the heap and the elements are initialized at the same time.L
Therefore, the statement "new int[3]{1, 2, 3};" does indeed allocate an array of three initialized integers on the heap, making the statement True.
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Solve the following inequality
23x +1 > -45
Answer:
-2
Step-by-step explanation:
23x + 1 > - 45
or, 23x > - 45 - 1
or, 23x > - 46
or, x > - 46/23
or, x > - 2
hope it will help you☺
Help asap!
Miguel asks each person in his work group to estimate the cost of their project. Three people have not yet turned in
their estimates by the time Miguel must provide cost estimates to his boss. Which type of reasoning must Miguel use to
finish his own estimates?
A. abductive
B. deductive
C. inductive
D. unsound
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What is the solution to this equation?
5x+15 + 2x = 24 +4x
A. x = 3
B. x=9/11
C. x = 13
D. x =39/11
Answer:
the answer is A x = 3
Step-by-step explanation:
5x + 15 +2x = 24 + 4x
or, 5x + 2x - 4x = 24 - 15
or, 3x = 9
or, x = 9/3
x = 3
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Write a cosine function that has a midline of 2, an amplitude of 3 and a period of 7π4\frac{7\pi}{4}47π.
The cosine function with a midline of 2, an amplitude of 3, and a period of 7π/4 is f(x) = 3 cos(8x/7) + 2.
A cosine function that has a midline of 2, an amplitude of 3, and a period of 7π/4 can be written in the form:
f(x) = A cos(Bx) + C, where:
A = amplitude
= 3C
= midline
= 2B
= 2π/period
= 2π / (7π/4)
= 8/7
We will get the cosine function after substituting the values of A, B, and C in the general form:
f(x) = 3 cos(8x/7) + 2
Thus, the cosine function with a midline of 2, an amplitude of 3, and a period of 7π/4 is f(x) = 3 cos(8x/7) + 2.
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simplify the expression
(5j + 1)(7) =
Answer: 7+35j
Step-by-step explanation: First we have to distribute 7 to 1 and 5j. So, (7*1)+(7*5j). So our final answer would be 7+35j
write 7.171717 as a mixed number
Answer:
7 17/99
Step-by-step explanation:
A water treatment plant needs to maintain the ph of the water in the reservoir at a certain level. To monitor this, they take 2 oz. Of water at 37 locations every hour, measure the ph at each of those locations, and find their average. If the ph level of the reservoir is ok, the results at each location will have varying results, with an average ph of 8. 5 and a standard deviation of 0. 22. If the ph level of the reservoir is ok, what is the probability that the sample average is more than 8. 42?.
A water treatment plant needs to maintain the ph of the water in the reservoir at a certain level. Then the probability that the sample is more than 8.42 is 0.0029 or 0.29%.
Using the normal distribution and the central limit theorem,
The mean is μ = 8.5
The standard deviation is σ = 0.22 .
A sample of 37 is taken, hence n = 37, s = 0.22/√37 i.e. s = 0.0362
The probability that the sample average is more than 8.40 is the p-value of Z when X = 8.4, hence:
Z = X - μ/σ
Z = 8.4 - 8.5/0.0362
Z = 2.76
Z = -2.76 has a p-value 0.0029
0.0029 = 0.29% probability that the sample average is more than 8.40.
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Can you put it into a single fraction
It should be noted that the addition of 3/4 and 1/16 as a single fraction will be 13/16.
How to calculate the valueIn order to add the fractions 3/4 and 1/16, we need to find a common denominator. The smallest common multiple of 4 and 16 is 16.
First, let's convert 3/4 to have a denominator of 16:
3/4 = (3/4) * (4/4) = 12/16
Now we can add the fractions:
12/16 + 1/16 = 13/16
Therefore, the sum of 3/4 and 1/16 is 13/16.
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Can you put it into a single fraction the addition of 3/4 and 1/16.
Let f be a function with third derivative f (x) = (4x + 1) 7. What is the coefficient of (x - 2)^4 in the fourth-degree Taylor polynomial for f about x = 2 ?
a. ¼
b. 3/4. c. 9/2. d. 18
We can use the Taylor series formula to find the fourth-degree Taylor polynomial for f about x = 2. The answer is d. 18
\(f(2) = f(2) = 405\)
\(f'(2) = 29\)
\(f''(2) = 28\)
\(f'''(2) = 168\)
The fourth-degree Taylor polynomial is:
P4(x) \(= f(2) + f'(2)(x-2) + (f''(2)/2!)(x-2)^2 + (f'''(2)/3!)(x-2)^3 + (f''''(c)/4!)(x-2)x^{2}\)^4
where c is some number between 2 and x.
Using the given third derivative, we can find the fourth derivative:
\(f''''(x) = (4x + 1) ^6 * 4\)
Plugging in x = c, we have:\(f''''(c) = (4c + 1) ^6 * 4\)
Therefore, the coefficient of \((x-2)^4\) in the fourth-degree Taylor polynomial is:\((f''''(c)/4!) = [(4c + 1) ^6 * 4] / 24\)
We need to evaluate this at c = 2:\([(4c + 1) ^6 * 4] / 24 = [(4*2 + 1) ^6 * 4] / 24 = 18\)
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