Supriya has a pre-paid electricity connection at home. On a sultry Sunday afternoon, she checks that she only has ₹9 left in the balance. She wants to use the air conditioner (AC), rated at 1.2 kW. The price of electricity is ₹10 /unit in her area. How long can she run the AC before her balance is over and the power runs out?

Answer:

2.93 mm

Explanation:

If you stack 3 nickels on a table, e the table is their center of gravity 2.93 mm

The Centre of gravity is a theoretical term, where the body’s total weight is thought to be concentrated and it predicts the behavior of a moving body when acted on by gravity.

It is also useful in designing static structures like buildings and bridges, the center of gravity is identical to the centre of mass.

For the Moon, the centre of mass is very close to its geometric centre and its centre of gravity is slightly towards the Earth due to the stronger gravitational force on the Moon’s near side.

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The potential energy of a car moving with constant speed during downhill converts into heat energy or sound energy during braking.

Energy cannot be created or destroyed, according to the law of conservation of energy. However, it is capable of change from one form to another.

When a car goes downhill, its potential energy decreases but as the driver applied braking, the gain in potential energy lost during work against the frictional force applied by the brake and converts into  heat energy or sound energy during braking.

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Without additional information, it is not possible to determine the magnitude of the earthquake based solely on the s-p interval and the maximum amplitude of the wave on the seismogram.

The magnitude of an earthquake is a measure of the energy released during the seismic event. It is typically determined using seismograph data, which provides information about the amplitude and duration of seismic waves.

The s-p interval refers to the time difference between the arrival of the S-wave (secondary wave) and the P-wave (primary wave) at a seismograph station. It is used to estimate the distance of the earthquake epicenter from the station. However, the s-p interval alone does not provide enough information to calculate the magnitude of the earthquake.

Similarly, the maximum amplitude of the largest wave on the seismogram, which measures the height of the wave, is not sufficient to determine the magnitude. Magnitude calculations typically involve analyzing multiple data points, waveforms, and characteristics of the seismic waves.

To accurately determine the magnitude of an earthquake, seismologists use a variety of data from multiple seismograph stations, including the amplitude of different waves, the distance between the epicenter and the stations, and other factors.

In order to determine the magnitude of an earthquake, more information and data beyond the s-p interval and the maximum amplitude of the wave on the seismogram are required. A comprehensive analysis using multiple data points and seismograph readings from various stations is necessary to accurately calculate the magnitude of an earthquake.

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Answer:

Yes, greater power is necessary to lift a car with your own body in a dire emergency situation than it would be to lift the same car using a jack.

Explanation:

This is because lifting the car with your body requires a combination of strength, power, and speed, all of which must be generated by your muscles. In contrast, a jack is a tool that uses hydraulic pressure to lift the car, which requires much less effort on your part.

When lifting a car with your body, you are essentially performing a squat or deadlift with an extremely heavy weight. This requires your muscles to produce a tremendous amount of force to overcome the weight of the car and gravity, as well as to generate the speed and power necessary to lift the car quickly and effectively.

In addition, lifting a car with your body requires you to use multiple muscle groups simultaneously, including your legs, back, arms, and core. This makes it a very taxing exercise that can quickly fatigue your muscles and potentially lead to injury if not performed correctly.

In contrast, using a jack to lift a car requires minimal effort on your part, as the hydraulic pressure does the majority of the work. This means that you do not need to generate as much force, speed, or power with your muscles, and can avoid the risk of injury or fatigue associated with lifting the car with your body.

Overall, lifting a car with your body is a remarkable feat that requires a tremendous amount of strength, power, and speed. While it can be done in dire emergency situations, it should not be attempted unless absolutely necessary, and only by individuals who are properly trained and physically capable of performing the lift safely.

Answer:

The answer is B = Series and Parallel

Explanation:

Components connected in series are connected along a single part, so the same current flows through all the components.

Answer:

b) Series; Parallel

Complete Question:

Two solid rods have the same length and are made of the same material with circular cross sections. Rod 1 has a radius r, and rod 2 has a radius r / 2. If a compressive force F is applied to both rods, their lengths are reduced by ΔL1 and ΔL2, respectively. The ratio ΔL1 / ΔL2 is equal to.

Answer:

\(\frac{\triangle L_1}{\triangle L_2} =\frac{1}{4}\)

Explanation:

Since the two rods have the same length, L₁ = L₂ = L

Radius of rod 1, r₁ = r

Radius of rod 2, r₂ = r/2

Cross sectional area of rod 1, \(A_1 = \pi r^2\)

Cross sectional area of rod 2, \(A_2 = \frac{\pi r^2}{4}\)

The same compressive force is applied to the two rods, F₁ = F₂ = F

The rods are said to be made of the same material, this means that they have the same young's modulus.

Young's modulus of rod 1, \(Y_1 = \frac{FL}{A_1 \triangle L_1}\)

Young's modulus of rod 2, \(Y_2 = \frac{FL}{A_2 \triangle L_2}\)

Since Y₁ = Y₂

\(\frac{FL}{A_1 \triangle L_1} = \frac{FL}{A_2 \triangle L_2}\\\\ \frac{1}{A_1 \triangle L_1}= \frac{1}{A_2 \triangle L_2}\\\\\)

\(\frac{\triangle L_1}{\triangle L_2} = \frac{A_2}{A_1}\\\)..............(*)

Put A₁ and A₂ into (*)

\(\frac{\triangle L_1}{\triangle L_2} = \frac{\pi r^2/4 }{\pi r^2}\\\\\frac{\triangle L_1}{\triangle L_2} =\frac{1}{4}\)

Answer:

I think a Kinetic energy of an object is the measure of the work an object can do by the virtue of its motion.”

Hope this help!:)

Answer:

Force has a direct relationship to mass and acceleration. Newton's Second Law, force equals mass times acceleration (F=MA), illustrates their general relationship in an equation.

Explanation:

Relationships to remember:

(Ex: The harder you push a box, the faster it will move)

(Ex: If you add more furniture in the back of a moving company truck, the truck will move slower than it did before the furniture was added)

(Ex: You will need to exert less force to lift a 5-pound weight than a 10-pound weight)

And of course, Newton's Second Law, F=MA sums all of this up in 3 letters and a symbol! If you have any more questions about this problem, please comment on my answer :)

b)To deposit so much silver, a stream of 18 s must be permitted to flow.

It is best to utilize a 6 volt source because most plating tasks typically demand current requirements of 2 to 6 volts.We struggle more to get rid of the extra heat when using 12 volts.There is a need for much bigger rheostats.

Depending on these factors, the process could take a few days to a few weeks.To verify that the surface area has been coated, check the cathode every day.Switch out the battery with such a fresh one if the pace of plating seems excessively slow.

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Explanation:

To find the number of oxygen molecules in a normal breath, we can use the ideal gas law equation, which relates the pressure, volume, temperature, and number of molecules of a gas:

PV = nRT

Where:

P = Pressure (in Pa)

V = Volume (in m³)

n = Number of moles

R = Ideal gas constant (8.314 J/(mol·K))

T = Temperature (in K)

First, let's calculate the number of moles of air inhaled during a normal breath:

V = 5.16 x 10^4 m³ (Volume of air inhaled)

P = 0.967 x 10^5 Pa (Pressure in the lungs)

R = 8.314 J/(mol·K) (Ideal gas constant)

T = 310 K (Temperature)

Rearranging the equation, we get:

n = PV / RT

n = (0.967 x 10^5 Pa) * (5.16 x 10^4 m³) / (8.314 J/(mol·K) * 310 K)

n ≈ 16.84 mol

Next, let's find the number of oxygen molecules inhaled. Since fresh air contains approximately 21% oxygen, we can multiply the number of moles by the fraction of oxygen in the air:

Number of oxygen molecules = n * (0.21)

Number of oxygen molecules ≈ 16.84 mol * 0.21

Number of oxygen molecules ≈ 3.54 mol

Finally, we'll convert the number of moles of oxygen molecules to the actual number of molecules by using Avogadro's number, which is approximately 6.022 x 10^23 molecules/mol:

Number of oxygen molecules = 3.54 mol * (6.022 x 10^23 molecules/mol)

Number of oxygen molecules ≈ 2.13 x 10^24 molecules

Therefore, in a normal breath, there are approximately 2.13 x 10^24 oxygen molecules.

Answer:

the potential energy decreases and the kinetic energy increases

Explanation:

I hope it helps and have an excellent day

The ball that is projected 125 meters straight upward has a total time in the air of: 10.1 s

The formulas for the vertical launch upward and the procedures we will use are:

Where:

Information about the problem:

Applying the maximum height formula and clearing the initial velocity we get:

y max = v₀²/(2*g)

v₀ = √(y max * (2*g))

v₀ = √( 125 m * (2 * 9.8 m/s²))

v₀ = √( 125 m * 19.6 m/s²)

v₀ = √2450 m²/s²

v₀ = 49.497 m/s

Applying the maximum time formula we get:

t max= v₀ / g

t max= 49.497 m/s / 9.8 m/s²

t max = 5.050 s

Applying  the time of flight formula, we get:

t(of) =2 * t max

t(of) =2 * 5.050 s

t(of) = 10.1 s

In physics vertical launch upwards is the motion described by an object that has been launched vertically upwards in which the height and the effect of the earth's gravitational force on the launched object are taken into account.

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The time spent in the air by the ball is 10.01 seconds.

The total time spent in the air by the ball is the sum of the time it spends moving up and the time it spends falling down.

The time spent by the ball moving up - time spent by the ball travelling down.

Time spent by the ball traveling down a distance of 125 meters is calculated using the formula given as follows:

t = √2h/g

Total time spent = 2 * √2h/g

where:

h = 125 m

g = 9.81 m/s²

T = 2 * √(2 * 125/9.81)

T = 10.01 s

Therefore, the time spent in the air by the ball is the sum of the time spent moving up and the time it spends falling down which are both equal.

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The correct option is d. -2.738 V.

We know that, E°cell = E°cathode – E°anodeIn this question, we need to calculate the potential of an aluminum electrode immersed in 0.05 M KOH solution saturated with Al(OH)3. Let us consider the half-reactions occurring at the cathode and anode.2Al(OH)3(s) + 6OH-(aq) ⇌ 2[Al(OH)6]3-(aq) (cathode)Al(s) + 3OH-(aq) ⇌ [Al(OH)3]-(aq) + 3e- (anode). On balancing the above reactions we get:2Al(OH)3(s) ⇌ Al(s) + 3[Al(OH)4]- (aq) + 3OH-(aq). By applying the Nernst equation, we get: For cathode: E°cathode = 0V (Since it is given that Al(OH)6 is saturated). For anode: E°anode = - (0.0592/3) log10{([Al(OH)4]-]^3/[Al][OH^-]^3)}E°anode = - (0.0592/3) log10{([Al(OH)4]-]^3/[OH^-]^3}E°anode = - (0.0592/3) log10(1.8 × 10^-12)E°anode = 1.076V. On substituting the values of E°cathode and E°anode in the formula of E°cell, we get E°cell = E°cathode – E°anodeE°cell = 0 - 1.076 VE°cell = -1.076 V. We know that the potential of the electrode is equal to the standard potential of the electrode plus the electrode potential calculated from the Nernst equation. potential of the aluminum electrode = -1.662 + (-1.076) = -2.738 V. Therefore, the correct option is d. -2.738 V.

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Complete question is;

The abc battery company claims that their batteries last 100 hours, on average. You decide to conduct a test to see if the company's claim is true. You believe that the mean life may be different from the 100 hours the company claims. you decide to collect data on the average battery life (in hours) of a random sample of n = 20 batteries. some of the information related to the hypothesis test is presented below:

Test of H0: μ = 100 versus H1: μ ≠ 100

Sample mean: 98.5

Std error of mean: 0.777

Assuming the life length of batteries is normally distributed, what is the p-value associated with this test?

Answer:

p-value =  0.00001

Explanation:

We are given;

Null hypothesis; H0: μ = 100

Alternative Hypothesis; H1: μ ≠ 100

Sample mean: x = 98.5

Standard error of mean; s = 0.777

To find the test statistic, we will use the formula;

t = (x - μ)/(s/√n)

t = (98.5 - 100)/(0.777/√20)

t = -1.5/0.1737

t = -8.64

Now, from online p-value from t-score calculator attached, using t = -8.64; DF = n - 1 = 20 - 1 = 19; two tail distribution;significance level of 0.05; we have;

The p-value =  0.00001

Answer:

a. X: Slower in gases than liquids Y: Faster in solids than gases Z: Velocity depends on medium.

Explanation:

Speed of sound is fastest in solids. Sound waves travel more quickly in solid, than of liquid and gases. Sound waves travel most slowest in gases. Speed of sound varies significantly and it depends upon medium it is travelling through.  In more rigid medium sounds velocity will be faster.

Answer:

15.34 i think

Explanation:

Answer:

90.82%digrash silsho

The movement of air masses across North America from west to east is consistent with global flow of wind over the continent.

The movement of air masses across North America from west to east is consistent with the global flow of wind over the continent. This is due to  general circulation of the Earth's atmosphere, which is driven by differences in temperature and pressure.

At the equator, warm air rises, creating low-pressure zone. As the air rises, it cools and releases moisture, thus creating tropical rainforests. This rising air then moves north and south, where it cools and sinks back to surface, thus creating high-pressure zones. The cool air then flows back toward equator, completing the circulation pattern known as Hadley cell.

In the mid-latitudes, the circulation pattern is more complex, with several cells interacting to create the prevailing westerlies that blow from west to east across North America.

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Answer:

\(V=1.76\times 10^{-4}\ V\)

Explanation:

Given that,

The diameter of a wire, d = 1.628 mm

Radius, r = 0.814  mm = 0.000814m

Current, I = 12.5 mA

The length of the wire, l = 2m

The resistivity of the wire, \(\rho=1.47\times 10^{-8}\ \Omega-m\)

We need to find the potential difference across the wire. We know that the resistance of the wire is given by :

\(R=\rho\dfrac{l}{A}\)

Also, V = IR

\(\dfrac{V}{I}=\rho\dfrac{l}{A}\\\\V=\dfrac{\rho l I}{A}\\\\V=\dfrac{1.47\times 10^{-8}\times 2\times 12.5\times 10^{-3}}{\pi \times (0.000814)^2}\\\\V=1.76\times 10^{-4}\ V\)

So, the potential difference of the wire is \(1.76\times 10^{-4}\ V\).

Answer:

Scalar, a physical quantity that is completely described by its magnitude; examples of scalars are volume, density, speed, energy, mass, and time. Other quantities, such as force and velocity, have both magnitude and direction and are called vectors.

Explanation:

Scalar quantities give a magnitude, while vector quantities give a magnitude and a direction. The answer will be a measurement that does not change, regardless of the direction of action. Displacement is a measure of length in a given direction; distance is the scalar version of displacement. ... Mass is a scalar quantity.

examples of scalar quantities are mass, speed, distance, time, energy, density, volume, temperature, distance, work and so on

Answer:

Scalar, a physical quantity that is completely described by its magnitude; examples of scalars are volume, density, speed, energy, mass, and time. Other quantities, such as force and velocity, have both magnitude and direction and are called vectors.

Answer:

10.71 mL

Explanation:

We know,

=> density= mass/volume

=> 1.4 = 15 / Volume

=> volume= 15/1.4 mL

=> volume= 10.71 mL

Answer:

increasing the masses of the objects and increasing the distance between the objects

Answer:

1.07 nT

Explanation:

We know that E/B = c where E = electric field amplitude = 320 mV/m = 0.32 V/m, B = magnetic field amplitude and c = speed of light = 3 × 10⁸ m/s.

So, B = E/c

Substituting E and c into B, we have

B = E/c

= 0.32 V/m ÷ 3 × 10⁸ m/s

= 0.1067 × 10⁻⁸ T

= 1.067 × 10⁻⁹ T

= 1.067 nT

≅ 1.07 nT

Let d2 be the hole's diameter. Therefore, the coefficient d2 = d1 (1 + alpha dt) remains constant.

Since a circle's center must be the longest distance between any two points on the circle, the diameter is essentially twice as large as the radius. The distance around a circle or the duration of a circuit along a circle can be used to define its circumference.

The distance that runs through the center of a circle through one point on its surface to another is known as the diameter of the circle.

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The statements true in regards to heat is 3. Heat is a form of energy, can be reflected by a mirror, and cannot pass through a vacuum.

Heat is a form of energy. Heat is the transfer of thermal energy from one object to another. Thermal energy is the energy of motion of the particles in an object. Heat can be reflected by a mirror. Heat is a form of electromagnetic radiation, and electromagnetic radiation can be reflected by mirrors.

Heat cannot pass through a vacuum. Heat is a form of electromagnetic radiation, and electromagnetic radiation cannot pass through a vacuum. Heat is not an electromagnetic radiation. It is a form of energy that is transferred from one object to another because of a difference in temperature.

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Complete question:

Which of the following statements are true regarding heat?

(a) Heat is a form of energy

(b) Heat can be reflected by mirror

(c) Heat is an electromagnetic radiation

(d) Heat can pass through vacuum

Select the correct answer from the codes given below :

1. 1, 2 and 3

2. 2, 3 and 4

3. 1, 2 and 4

4. 1, 3 and 4

a. The probability that a tire will be too narrow is approximately 0.0918 or 9.18% , b. The probability that a tire will be too wide is approximately 0.0918 or 9.18% , c. The probability that a tire will be defective is approximately 0.8164 or 81.64%.

In order to determine the probabilities for the width of the cyclocross tires, we can use the concept of standard normal distribution. The mean width of the tires is 23 mm, and the standard deviation is 0.15 mm.

a. To find the probability that a tire will be too narrow (below 22.8 mm), we need to calculate the z-score corresponding to this lower specification limit. The z-score is given by the formula:

z = (x - μ) / σ

where x is the lower specification limit, μ is the mean, and σ is the standard deviation. Plugging in the values, we get:

z = (22.8 - 23) / 0.15 = -1.33

Using a standard normal distribution table or a statistical software, we can find that the probability of a z-score being less than -1.33 is approximately 0.0918. Therefore, the probability that a tire will be too narrow is approximately 0.0918 or 9.18%.

b. Similarly, to find the probability that a tire will be too wide (above 23.2 mm), we calculate the z-score corresponding to the upper specification limit:

z = (23.2 - 23) / 0.15 = 1.33

Using the same table or software, we find that the probability of a z-score being greater than 1.33 is approximately 0.0918. Thus, the probability that a tire will be too wide is approximately 0.0918 or 9.18%.

c. To calculate the probability that a tire will be defective, we need to find the area under the normal curve outside the specification limits. This can be done by subtracting the sum of the probabilities obtained in parts a and b from 1:

P(defective) = 1 - P(narrow) - P(wide)

P(defective) = 1 - 0.0918 - 0.0918

P(defective) = 0.8164

Therefore, the probability that a tire will be defective is approximately 0.8164 or 81.64%.

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The change in gravitational potential energy stored in 16 Jule.

What is gravitational potential energy?

gravitational potential energy

In classical mechanics, of the  gravitational potential at in a  location is equal to the work per unit mass that's would be needed to Move an object to that locations from a fixed references  location. It is analogous to the electric potential with the mass playing the role of charge.

Sol-As per the given question ∆PE = mgh

M= skg

g= 4m/s^2

∆h = 2m

∆PE = 2m×4m×2m

= 16 Joules.

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The EMF of a cell represents its maximum potential difference, while the potential difference across the cell when passing a current through an external resistance is reduced due to the internal resistance of the cell.

The electromotive force (EMF) of a cell refers to the maximum potential difference that the cell can provide when it is not connected to any external circuit. It is essentially the voltage produced by the chemical reactions occurring within the cell. On the other hand, the potential difference across the cell when it is passing a current through an external resistance is often lower than the EMF.

This difference in values can be attributed to the internal resistance of the cell. When a current is drawn from the cell, it encounters resistance within the cell itself due to factors such as the resistance of the electrolyte and the internal structure of the cell. This internal resistance causes a voltage drop within the cell, reducing the potential difference across the external circuit.

According to Ohm's Law (V = I * R), when current flows through a resistance (R), a voltage drop (V) occurs. In this case, the internal resistance of the cell causes a voltage drop within the cell itself. Hence, the potential difference across the external resistance is slightly lower than the EMF of the cell.

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