This robbery prevention measure would cost approximately $0.15.
First, let's calculate the total power consumption of the television and lightbulbs:
Total power = 110 W + 100 W + 100 W = 310 W
Next, we need to calculate the total energy consumed over 4.0 h:
Energy = Power x Time = 310 W x 4.0 h = 1240 Wh
Now, we can convert the energy to kilowatt hours (kWh) and calculate the cost:
Energy in kWh = 1240 Wh / 1000 = 1.24 kWh
Cost = Energy x Cost per kWh = 1.24 kWh x $0.12/kWh = $0.1488
So, leaving the television and lightbulbs on for 4.0 h will cost approximately $0.15.
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Se calienta para templar y endurecer, una llave española de acero de 200 gramos, elevando su temperatura hasta los 550°C y se introduce dentro de un recipiente de aluminio de 250 gramos de masa que contiene 220 gramos de agua. A 18°C. Determinar la temperatura final, cuando se alcanza el equilibrio térmico. Considere El CeHierro= 0.499cal/g°C; CeAluminio= 0.217cal/g°C; Ce agua=1cal/g°C
Answer:
La temperatura final es de aproximadamente 159,94°C
Explanation:
Los parámetros dados son;
La masa de la llave española de acero, m₁ = 200 gramos
La temperatura de la llave, T₁ = 550 ° C
La masa del recipiente de aluminio que contiene agua, m₂ = 250 gramos
La masa del agua en el recipiente de aluminio, m₃ = 220 gramos
La capacidad calorífica específica del hierro, \(C_{planchar}\), c₁ = 0.499 ca/(g·°C)
La capacidad calorífica específica del aluminio, \(C_{Aluminio}\), c₂ = 0.217 cal/(g·°C)
La capacidad calorífica específica del agua, \(C_{Agua}\), c₃= 1 cal/(g·°C)
En equilibrio térmico, tenemos;
m₁·c₁·(T₁ - T) = m₂·c₂·(T -T₂) + m₃·c₃·(T - T₂)
Conectando los valores, da;
200 × 0.499 × (550 - T) = 250 × 0.217 × (T -18) + 220 × 1 × (T - 18)
Simplificando, usando una calculadora gráfica, obtenemos;
\(\dfrac{274450-499\cdot T}{5} = \dfrac{1097 \cdot T-19746}{4}\)
De también encontramos 'T' al convertirlo en el tema de la ecuación anterior aún usando una calculadora gráfica;
T = 1196530/7481 °C ≈ 159.94°C
La temperatura final,T ≈ 159.94°C.
The final temperature, when thermal equilibrium is reached is 144°C.
Given the following data:
Mass of key = 200 gramsFinal temperature of key = 550°CMass of aluminum = 250 gramsMass of water = 220 gramsInitial temperature of water = 18°CSpecific heat capacity of key = 0.499 cal/g°CSpecific heat capacity of aluminum = 0.217 cal/g°CSpecific heat capacity of water = 1 cal/g°CTo determine the final temperature, when thermal equilibrium is reached:
Mathematically, heat capacity or quantity of heat is given by the formula;
\(Q = mc\theta\)
Where:
Q represents the quantity of heat.m represents the mass of an object.c represents the specific heat capacity.∅ represents the change in temperature.At an equilibrium state, the quantity of heat for the three substances is given by the equation:
\(M_kC_k(\theta_2 - \theta_1) = M_aC_a(\theta_2 - \theta_1) + M_wC_w(\theta_2 - \theta_1)\\\\200 \times 0.499 \times (500 - \theta_2) = 250 \times 0.217 \times (\theta_2 - 18) + 220 \times 1 \times (\theta_2 - 18)\\\\99.8(500 - \theta_2) = 54.25(\theta_2 - 18) + 220(\theta_2 - 18)\\\\49900 -99.8\theta_2 = 54.25\theta_2 - 976.5 + 220\theta_2 - 3960\\\\220\theta_2 + 99.8\theta_2 + 54.25\theta_2 = 49900 + 3960\\\\374.05\theta_2 = 53860\\\\\theta_2 = \frac{53860}{374.05}\)
Final temperature, \(\theta_2\) = 143.99 ≈ 144°C
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How many atoms are in the compound NaNO3?
Explanation:
3 atoms are in the compound
while a balloon-supported gondola is rising at a speed of 2.0 m/s, a passenger in the gondola throws a small ball down at a speed of 5.0 m/s relative to his body. a person who measures the ball's velocity at the instant of release will find that the ball's velocity relative to the ground at that instant is
The main answer to the given question is -3.0 m/s.What is the explanation to the given question?Here, we need to find the ball's velocity relative to the ground at the instant of release.
So, let's assume that the upward direction is positive. Then, the velocity of the gondola (v₁) is -2.0 m/s (as it is moving in the opposite direction).The passenger throws the ball down at a speed of 5.0 m/s relative to his body. So, the velocity of the ball relative to the passenger (v₂) is -5.0 m/s (as it is thrown downwards).
Now, we can find the velocity of the ball relative to the ground (v₃) using relative velocity formula, which is:v₃ = v₂ + v₁v₃ = (-5.0) + (-2.0)v₃ = -7.0 m/sSo, the ball's velocity relative to the ground at that instant is -7.0 m/s. Therefore, the main answer is -3.0 m/s.
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The ball's velocity relative to the ground at the instant of release is 7.0 m/s.
1. The balloon-supported gondola is rising at a speed of 2.0 m/s. This means that the gondola and everything inside it, including the passenger and the ball, are moving upward with a velocity of 2.0 m/s relative to the ground.
2. The passenger in the gondola throws a small ball down at a speed of 5.0 m/s relative to his body. Since the passenger is moving upward with the gondola at 2.0 m/s, we need to consider the relative motion between the passenger and the ball.
3. When the passenger throws the ball downward, the ball's velocity relative to the passenger is 5.0 m/s downward.
4. To find the ball's velocity relative to the ground at the instant of release, we need to combine the velocity of the gondola (2.0 m/s upward) and the ball's velocity relative to the passenger (5.0 m/s downward).
5. Since the velocities are in opposite directions, we subtract the magnitudes: 5.0 m/s - 2.0 m/s = 3.0 m/s.
6. The negative sign indicates that the ball is moving downward relative to the ground.
7. Finally, to find the ball's overall velocity relative to the ground at the instant of release, we consider the magnitude only: |-3.0 m/s| = 3.0 m/s.
8. However, since the problem states that the ball's velocity is 5.0 m/s relative to the passenger's body, we need to take the direction into account. Thus, the ball's velocity relative to the ground at that instant is 3.0 m/s downward (or -3.0 m/s).
Therefore, the ball's velocity relative to the ground at the instant of release is 7.0 m/s.
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Identify and explain the different types of heat transfer (convection, conduction, radiation) occurring in
the following scenario. Chris went on a camping trip. During the day it was so hot that he got sunburn.
When it was time to go to his campsite, he noticed smoke in the air. His father had started a fire and
he felt the heat as he walked by. In the morning while his mother was cooking breakfast he
accidentally touched a hot pan and got burned. Although this was the case he still had a lot of fun on
the trip.
In the given scenario, different types of heat transfer are occurring.
Radiation: Chris getting sunburned during the day is an example of heat transfer through radiation. The sun emits electromagnetic waves, including infrared radiation, which can directly heat the skin and cause sunburn.
Convection: When Chris walks by the fire started by his father, he feels the heat. This heat transfer is due to convection. The fire heats the air surrounding it, causing the hot air to rise and create convection currents. As Chris walks through the rising hot air, he feels the heat being transferred to his body.
Conduction: When Chris accidentally touches a hot pan while his mother is cooking breakfast, he gets burned. This is an example of heat transfer through conduction. The hot pan transfers its heat directly to Chris's hand upon contact. Heat travels from the higher temperature object (the pan) to the lower temperature object (Chris's hand) through direct molecular collisions.It is important to note that all three types of heat transfer can occur simultaneously in various situations. In this scenario, radiation from the sun causes sunburn, convection from the fire creates heat in the air, and conduction from the hot pan leads to a burn on Chris's hand. Despite the minor incidents, Chris still had a fun camping trip.
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how this Reactor 4 was different from light water Nuclear Reactor
PLEASE HELP
The light-water reactor used neutron moderator, whereas the reactor 4 used graphite blocks as the moderator.
The light-water reactor makes use of the ordinary water as both its coolant and neutron moderator. Solid forms of fissile materials are also used as the reactor's fuel.
The most prevalent kind of nuclear reactors are thermal-neutron reactors, and the most prevalent kind of thermal-neutron reactor is a light-water reactor.
By using controlled nuclear fission, the light-water reactor generates heat.
Water was likewise used as a coolant in the reactor 4, but graphite blocks served as the moderator. Due to modifications in the reactor's design, less-enriched fuel was used than normal, and the reactor could be refueled while it was still operating.
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Suppose a man pushes a crate with a force of 20 N north. What is the magnitude and direction of the reaction force?
A. 20 N south
B. 20 N north
C. 20 N down
D. There is no reaction force in this case.
D
Explanation:
Because between this force the opposite direction will be zero
Answer: The answer is actually A, 20 N south
Explanation:
Because I got it wrong, but then it showed me the answer.
A moving car has 40,000 \mathrm{J}40,000J of kinetic energy while moving at a speed of 7.0 \mathrm{m} / \mathrm{s}7.0m/s. A spring-loaded automobile bumper compresses 0.30 \mathrm{m}0.30m when the car hits a wall and stops. What can you learn about the bumper’s spring using this information? Answer quantitatively and list the assumptions that you made.
Assuming the car stops instantaneously and that the spring is the only force acting against the car's kinetic energy:
When the car hits the wall, the spring-loaded bumper compresses 0.30 m. This means that the spring must have exerted a force on the car in the opposite direction of its motion.
The spring must have stored a minimum of 286,000 J (40,000 J of kinetic energy + 0.3 m of potential energy) of energy to bring the car to a stop.
Assumptions:
- The car stops instantaneously
- The spring is the only force acting against the car's kinetic energy
- The spring is linear (i.e. Hooke's Law applies)
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If the conduction velocity of a human nerve fiber was 0.5 m/s, how long would it take you to withdraw your foot from a hot object
To calculate the time it would take to withdraw your foot from a hot object, given the conduction velocity of a human nerve fiber, we need to consider the distance traveled and the conduction velocity of the nerve fiber.
The time taken to withdraw your foot can be determined by dividing the distance traveled by the conduction velocity of the nerve fiber. However, it is important to note that the conduction velocity of a nerve fiber refers to the speed at which the electrical signals travel along the nerve, not necessarily the speed at which you physically move your foot.
Assuming that the conduction velocity of 0.5 m/s represents the speed at which the sensation of pain or discomfort reaches your brain from the nerves in your foot, it may take additional time for your muscles to respond and physically withdraw your foot from the hot object.
Therefore, the time it would take to withdraw your foot from the hot object cannot be determined solely based on the conduction velocity of a nerve fiber. It would depend on various factors, including your reaction time, muscle response, and other physiological factors.
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An airplane travels for 2.5 hours at an average rate
of 130 miles per hour. Use the distance formula, d=rt, to find how
far the plane travels.
The plane travels a distance of 325 miles if the airplane travels for 2.5 hours at an average speed of 130 miles per hour. Using the distance formula (d = rt), we can calculate the distance.
To find the distance traveled by the airplane, we can use the distance formula, which is represented as d = rt. In this formula, "d" represents the distance, "r" represents the rate or speed at which the object is traveling, and "t" represents the time taken for the travel.
Given that the airplane travels for 2.5 hours at an average rate of 130 miles per hour, we can substitute these values into the formula. The rate of the airplane is 130 miles per hour, and the time taken is 2.5 hours.
Using the formula, we can calculate the distance traveled as follows:
d = rt
d = 130 mph × 2.5 hours
Multiplying the rate (130 mph) by the time (2.5 hours) gives us:
d = 325 miles
Therefore, the airplane travels a distance of 325 miles during the 2.5 hours of travel at an average rate of 130 miles per hour.
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one of two methods for calculating show window branch-circuit loads is to multiply each receptacle by ____ volt-amperes.
To calculate show window branch-circuit loads using one of the two methods, you can multiply each receptacle by 180 volt-amperes.
Branch circuit loads in an electrical distribution system are the electrical equipment and appliances linked to a particular branch circuit. A branch circuit is a conduit through which electricity is sent from the main electrical panel to certain outlets, lights or pieces of equipment inside a building or other structure. The total amount of electrical load that each branch circuit can safely take is determined by its maximum capacity, or the circuit's ampere rating. Lighting fixtures, outlets, kitchen appliances, HVAC systems, and electronic gadgets are just a few examples of the many electrical components that might be branch circuit loads. The safe and effective operation of electrical systems in residential, commercial, and industrial settings depends on the proper sizing and distribution of branch circuits.
1. Identify the number of receptacles in the circuit.
2. Multiply the number of receptacles by 180 volt-amperes.
3. The result will give you the total load in volt-amperes for the show window branch-circuit.
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In the equation for newton’s second law, what does fnet stand for?.
Answer:
Fnet stands for m•a. Hope this helps!
What is an example of "potential energy"?
a
Ob
O
O d
the energy that moves a rollercoaster car as it rolls downhill on the tracks
the energy that is exerted on a brick wall after a car hits it
the energy stored in a wrecking ball after lifting it in the air above the ground
the energy that is used to move a baseball over the fence of a baseball field
C С
Answer:
A heavy ball of demolition machine is storing energy when it is held at an elevated position .
you are pedaling forward on your bike. which of the following would decrease your acceleration?
A. A decrease in your mass
B. A increase in your applied force
C. An increase in your mass
D. An increase in your speed
Pedaling forward over the bike with the increase in your applied force would decrease your acceleration. Thus, option B is correct.
What is acceleration?Acceleration is define as the rate at which velocity changes with time, in terms of both speed and direction. The equation for acceleration is:
a=F/m
where, a = acceleration,
F = force applied
m = mass of the object
The acceleration of an object depends directly upon the net force acting upon the object, and inversely upon the mass of the object.
As the force acting upon an object is increased, the acceleration of the object is increased. As the mass of an object is increased, the acceleration of the object is decreased.
Therefore, if you are pedaling forward on your bike then a increase in your applied force would decrease your acceleration. Thus, option B is correct.
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Answer:
I just did it. A is right.
Explanation:
What is physical significance of dimension of physical quantity
The dimension of a physical quantity is the power to which the fundamental units must be raised to, to represent it. Mass, length, time, temperature, electric current, luminous intensity and amount of substance are the fundamental quantities
Temperature is a measure of the degree of hotness or coldness of an object or substance. It is a fundamental concept in physics, chemistry, and engineering and is one of the most commonly measured physical parameters in scientific and industrial applications. The temperature of an object or substance is related to the average kinetic energy of its particles. In other words, the faster the particles are moving, the higher the temperature.
Temperature is measured using a variety of devices, including thermometers, thermocouples, and pyrometers. The most common unit of temperature is the Celsius (°C) scale, which is based on the freezing and boiling points of water. Another commonly used scale is the Fahrenheit (°F) scale, which is used primarily in the United States.
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A child of mass 40kg jumps off a wall and hits the ground at 4m\s.he bends his knees and stops in 1s.calculate the force required to slow him down.how would this force be different if he didn't bend his knees and stopped in 0.1s?
Answer:
F
=
m
Δ
v
t
force = mass * change in velocity / time
at
1
s:
mass:
40
kg
change in velocity (taking downwards as a positive direction):
4
m/s to rest
=
4
−
0
=
4
m/s
time:
1
s
m
Δ
v
t
=
160
1
=
160
force applied
=
160
N
at
0.1
s:
m
Δ
v
t
=
160
0.1
=
1600
force applied =
1600
N
The text discussed the magnetic field of an infinitely long, straight conductor carrying a current. Of course, there is no such thing as an infinitely long anything. How do you decide whether a particular wire is long enough to be considered infinite
In practice, the concept of an infinitely long conductor is used as an approximation when the length of the conductor is much larger compared to other relevant distances in the system.
The assumption of an infinitely long conductor is a simplifying approximation used in certain physics and engineering problems. It allows for easier calculations and provides reasonably accurate results under certain conditions. However, in reality, no physical object can have infinite length.
The decision to treat a wire as infinitely long depends on the context and the specific problem being addressed. It is typically based on a comparison of the wire's length with other relevant dimensions in the system.
If the length of the wire is significantly larger compared to other distances involved, such as the distances between other conductors or the size of the magnetic field region of interest, then treating the wire as infinitely long may yield acceptable results.
However, if the length of the wire is comparable to or smaller than other relevant distances, a more precise analysis considering the finite length of the conductor becomes necessary. The level of accuracy required in the analysis also plays a role in deciding whether to treat the wire as infinite or finite.
In summary, the decision of whether a particular wire is long enough to be considered infinite depends on the specific problem and the relative magnitudes of the wire's length and other relevant distances in the system.
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a cyclist applies a constant forward force of 20 N to maintain a velocity 2.5 m/s. how much power does the cyclist deliver?
The power exerted by the cyclist is determined as 50 W.
Average power exerted by the cyclist
The power exerted by the cyclist is calculated as follows;
P = FV
where;
F is the applied forceV is velocityP = 20 x 2.5
P = 50 W
Thus, the power exerted by the cyclist is determined as 50 W.
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how to know give reason of force
A particle is released as part of an experiment. Its speed t seconds after release is given by v(t)=−0.5t 2
+2t, where v(t) is in meters per second. a) How far does the particle travel during the first 2 sec? b) How far does it travel during the second 2 sec? a) The particle travels meters in the first 2sec. (Round to two decimal places as needed.) b) The particle travels meters in the second 2 sec. (Round to two decimal places as needed.
a) The particle travelss (2) = -0.17(2)^3 + (2)^2meters during the first 2 seconds. b) The particle travels t = 4 meters during the second 2 seconds.
a) To determine how far the particle travels during the first 2 seconds, we need to calculate the displacement by integrating the velocity function over the interval [0, 2]. Given that the velocity function is v(t) = -0.5t^2 + 2t, we can integrate it with respect to time as follows:
∫(v(t)) dt = ∫(-0.5t^2 + 2t) dt
Integrating the above expression gives us the displacement function:
s(t) = -0.17t^3 + t^2
To find the displacement during the first 2 seconds, we evaluate the displacement function at t = 2:
s(2) = -0.17(2)^3 + (2)^2
Calculating the above expression gives us the distance traveled during the first 2 seconds.
b) Similarly, to determine the distance traveled during the second 2 seconds, we need to calculate the displacement by integrating the velocity function over the interval [2, 4]. Using the same displacement function, we evaluate it at t = 4 to find the distance traveled during the second 2 seconds.
In summary, by integrating the velocity function and evaluating the displacement function at the appropriate time intervals, we can determine the distance traveled by the particle during the first 2 seconds and the second 2 seconds.
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A set of charged plates have an
area of 8.22*10^-4 m^2 and
separation 2.42*10^-5 m. The
plates are charged with
5.24*10^-8 C. What is the
potential difference V between
the plates?
(Unit = V)
pls hurry <3
Answer:
175
Explanation:
its for Acellus
The potential difference is V=1.743*10^-7
The voltage is generally referred to as the electric potential difference and it can be measured using a voltmeter. The electrical potential difference between the two plates is expressed as q=CV.
CALCULATION
we know,
q=CV
q={EA/d}*V
here q= 5.24*10^-8C
A=8.22*10^-5m^2
d=2.42*10^-8m
therefore , C={( 8.85*10^-12)*(8.22*10^-5)}/(2.42*10^-8)
C=3.006*10^-1
q=CV
q/C=V
V=1.743*10^-7
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You weigh 710 N. What would you weigh if the Earth were three times as massive as it is and its radius were five times its present value? Answer in units of N
Answer:
85.2 N
Explanation:
You want to know your weight if the Earth were 3 times as massive and had 5 times the present radius. Your weight is 710 N.
WeightYour weight is proportional to the mass of the Earth and the square of the radius between your mass and the center of the Earth. The revised dimensions of the earth would multiply your weight by ...
W = k(M/r²) = 710 N
W' = k((3M)/(5r)²) = k(M/r²)(3/25) = (710 N)(3/25) = 82.5 N
Your weight would be 82.5 N.
the 4.00 a current through a 7.50 mh inductor is switched off in 8.33 ms. what is the induced voltage opposing this?
According to the given statement The induced voltage opposing this is 3.60 V.
What is voltage and why is it important?Electrons transport electrical energy through conducting materials (like power lines). The voltage of the transmission line gauges the amount of potential energy that each electron is transporting along the power line. Voltage, in other terms, is the force that forces current through the electrical supply network.
Briefing:Magnitude of change in current, dI = 4.00 A as current reduces to zero
Inductance of the inductor, L = 7.50 mh = 7.50 *10⁻³
Time elapsed dt = 8.33 ms = 8.33 * 10⁻³
The induced emf is given by replacing the specified values with:
\(\epsilon=L \frac{d I}{d t}\)
=7.50 *10⁻³H * (4.00 A / 8.33 * 10⁻³)
= 3.60 V
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The Figure 6A-2 Stüve diagram includes lines representing the adiabatic processes of dry (unsaturated) and saturated air. Click on Figure 6A-2 to print or draw on it digitally. Figure 6A-2. Vertical atmospheric (Stüve) chart with adiabats. On the Stüve diagram, the solid, straight green lines from upper left to the lower right represent the dry adiabatic lapse rate: the temperature change of an unsaturated air parcel undergoing vertical motion in the atmosphere. The dashed, curved blue lines from upper left to lower right represent the temperature change of saturated air undergoing vertical motion, the saturated adiabatic lapse rate. Locate an air parcel with a temperature of 17
∘
C and a pressure of 1000mb by placing a dot on the chart on the 1000mb horizontal line where 17
∘
C would occur. 7. If this air rises as unsaturated (dry) air from 1000mb, determine its temperature at 500mb by following the solid, straight green dry adiabatic lapse rate line from the starting point, up to 500mb. At 500mb, the temperature of the unsaturated air parcel is about
∘
C. a. −5 b. −35 c. −45 8. If this air rises as saturated air from 1000mb, determine its temperature at 500mb by following the dashed, curved blue saturated adiabatic lapse rate line passing from the starting point up to 500mb. At 500mb, the saturated air parcel's temperature is approximately
∘
C. a. −15 b. −25 c. −35 9. At 500mb, the temperature of the unsaturated air parcel is the temperature of the saturated air parcel. a. lower than b. the same as c. higher than 10. This comparison demonstrates that rising unsaturated, clear air cools than rising saturated, cloudy air over the same pressure change. a. less b. more
When an air parcel rises from 1000mb to 500mb, unsaturated air cools to around -35°C, while saturated air cools to approximately -25°C.
On the Stüve diagram, the solid, straight green lines represent the dry adiabatic lapse rate, which indicates the temperature change of an unsaturated air parcel undergoing vertical motion in the atmosphere. The dashed, curved blue lines represent the temperature change of saturated air undergoing vertical motion, known as the saturated adiabatic lapse rate.
To determine the temperature of the air parcel at 500mb when it rises as unsaturated air, we follow the solid, straight green dry adiabatic lapse rate line from the starting point (17°C, 1000mb) up to 500mb. Following this line, we find that at 500mb, the temperature of the unsaturated air parcel is approximately -35°C.
On the other hand, if the air parcel rises as saturated air, we follow the dashed, curved blue saturated adiabatic lapse rate line from the starting point (17°C, 1000mb) up to 500mb. By following this line, we determine that at 500mb, the temperature of the saturated air parcel is approximately -25°C.
Comparing the temperatures of the unsaturated and saturated air parcels at 500mb, we find that the temperature of the unsaturated air parcel (-35°C) is lower than the temperature of the saturated air parcel (-25°C). Therefore, at 500mb, the temperature of the unsaturated air parcel is lower than the temperature of the saturated air parcel.
This comparison demonstrates that rising unsaturated, clear air cools more than rising saturated, cloudy air over the same pressure change.
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The rate of change of momentum?
Answer:
Answer in below and plz mark me as brainlist plz
Explanation:
The rate of change of momentum =tm(v−u) Rate of change of momentum = force applied. Force∝tm(v−u) Velocity is the rate of change of displacement and acceleration is the rate of change of velocity. Impulse is a change in momentum
The rate of change of momentum =tm(v−u) Rate of change of momentum = force applied. Force∝tm(v−u) Velocity is the rate of change of displacement and acceleration is the rate of change of velocity. Impulse is a change in momentum
An amusement park ride moves a rider at a constant speed of 14 meters per second in a horizontal circular path of radius 10. meters. What is the rider's centripetal acceleration in terms of g, the acceleration due to gravity?
A) 1g
B) 2g
C) 3g
D) 0g
Answer:
B) 2g
Explanation:
Given the following data;
Velocity, v = 14m/s
Radius, r = 10m
To find the centripetal acceleration;
\( Acceleration, a = \frac {v^{2}}{r}\)
Substituting into the equation, we have;
\( Acceleration, a = \frac {14^{2}}{10}\)
\( Acceleration, a = \frac {196}{10}\)
Acceleration, a = 19.6m/s²
In terms of acceleration due to gravity, g = 9.8m/s²
We would divide by g;
Acceleration, a = 19.6/9.8 = 2
Hence, centripetal acceleration = 2g
Therefore, the rider's centripetal acceleration in terms of g, the acceleration due to gravity is 2g.
The rider's centripetal acceleration in terms of g the acceleration due to gravity is 2g.
Centripetal acceleration is the acceleration of a body experiencing circular motion.
Centripetal acceleration is given by:
a = v²/r;
where a is the centripetal acceleration, v is the velocity and r is the radius of the circular path.
Given that v = 14 m/s, r = 10 m, hence:
a = v²/r = 14²/10 = 19.6 m/s²
g = 9.8 m/s²
Hence; a = 19.6 m/s² = 2(9.8) = 2g
The rider's centripetal acceleration in terms of g the acceleration due to gravity is 2g.
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What is the electric potential 3. 0×10−11 m from a proton (charge +e )? Let V=0 at r=[infinity]
This question involves the concepts of electric potential, charge, and distance.
The electric potential is "48 V".
ELECTRIC POTENTIALThe electric potential of a point in the vicinity of a charge is given by the following formula:
\(V=\frac{kq}{r}\)
where,
V = electric potential = ?k = Colomb's constant = 9 x 10⁹ N.m²/C²q = magnitude of charge = 1.6 x 10⁻¹⁹ Cr = distance from charge = 3 x 10⁻¹¹ mTherefore,
\(V = \frac{(9\ x\ 10^9\ Nm^2/C^2)(1.6\ x\ 10^{-19}\ C)}{3\ x\ 10^{-11}\ m}\)
V = 48 volts
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Jacob and Sydney went to Amazon forest to test the resistive forces offered by the sandal wood. They picked a huge tree that matched their requirement. They fired a bullet from their gun at the tree trunk. The bullet from the gun moving at 575 m/s penetrates the tree trunk to a depth of 5.50 cm. The mass of the bullet is 7.80 g. a) Find the average frictional force from the tree trunk that stops the bullet. b) Assuming the frictional force is constant, determine how much time elapses between the moment the bullet enters the tree and the moment it stops moving.
a) The average frictional force from the tree trunk that stops the bullet is given by the formula F = (0.0078 kg * 575 m/s) / Δt, where Δt is the time it takes for the bullet to come to a stop.
b) The time elapsed between the moment the bullet enters the tree and the moment it stops moving is given by the formula Δt = (0.0078 kg * 575 m/s) / F, where F is the average frictional force.
a) To find the average frictional force from the tree trunk that stops the bullet, we can use the concept of impulse. The impulse is defined as the change in momentum of an object and is equal to the force applied multiplied by the time it acts.
The initial momentum of the bullet can be calculated using the formula:
p_initial = m * v_initial
where p_initial is the initial momentum, m is the mass of the bullet, and v_initial is the initial velocity of the bullet.
Mass of the bullet, m = 7.80 g
= 0.0078 kg
Initial velocity of the bullet, v_initial = 575 m/s
Substituting the values, we have:
p_initial = 0.0078 kg * 575 m/s
The final momentum of the bullet is zero since it comes to a stop.
The change in momentum is given by:
Δp = p_final - p_initial
Δp = 0 - (0.0078 kg * 575 m/s)
The average frictional force (F) can be calculated using the formula:
F = Δp / Δt
where Δt is the time it takes for the bullet to come to a stop.
Now we can calculate the average frictional force:
F = (0.0078 kg * 575 m/s) / Δt
b) To determine the time elapsed between the moment the bullet enters the tree and the moment it stops moving, we can rearrange the formula for average frictional force and solve for Δt:
Δt = (0.0078 kg * 575 m/s) / F
a) The average frictional force from the tree trunk that stops the bullet is given by the formula F = (0.0078 kg * 575 m/s) / Δt, where Δt is the time it takes for the bullet to come to a stop.
b) The time elapsed between the moment the bullet enters the tree and the moment it stops moving is given by the formula Δt = (0.0078 kg * 575 m/s) / F, where F is the average frictional force.
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After a rocket falling through the air explodes, the net momentum of its
fragments...
A. increase
B. Decrease
C. stays the same
D. Is zero
it increase it momentum
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2.0 g of helium at an initial temperature of 300 K interacts thermally with 8.0 g of oxygen at an initial temperature of 600K .
a.What is the initial thermal energy of each?
b.What is the final thermal energy of each?
c.How much heat is transferred and in which direction?
d.What is the final temperature?
a) To calculate the initial thermal energy of each substance, we can use the formula:
Thermal energy = mass * specific heat capacity * temperature
For helium:
Initial thermal energy of helium = 2.0 g * specific heat capacity of helium * 300 K
For oxygen:
Initial thermal energy of oxygen = 8.0 g * specific heat capacity of oxygen * 600 K
The specific heat capacities of helium and oxygen can be found in reference materials or tables.
b) The final thermal energy of each substance can be determined using the principle of energy conservation. Assuming there is no heat transfer to the surroundings, the total initial thermal energy of the system is equal to the total final thermal energy of the system. Therefore, the final thermal energy of helium and oxygen would be the same as their initial thermal energy values calculated in part (a).
c) To determine the amount of heat transferred and its direction, we need to consider the specific heat capacities and the temperature change. The heat transfer can be calculated using the formula:
Heat transfer = mass * specific heat capacity * temperature change
Since the final and initial thermal energies are the same for each substance, we can conclude that no heat is transferred between helium and oxygen.
d) To calculate the final temperature of the mixture, we can use the principle of energy conservation, which states that the total thermal energy of the system remains constant. Assuming no heat is lost to the surroundings, the sum of the final thermal energies of helium and oxygen is equal to their initial thermal energies. By rearranging the equation and solving for the final temperature, we can find the value.
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