Probability of both televisions not working = 0.00049
The probability that both televisions do not workSuppose you just received a shipment of ten televisions. Two of the televisions are defective. If two televisions are randomly selected without replacement, we have to compute the probability that both televisions do not work.
Let A be the event that the first television does not work and B be the event that the second television does not work. If we are selecting without replacement, the events A and B are dependent. Let’s solve for P(A and B).
Probability of the first television not working is 2/10 as there are two defective televisions in the shipment and probability of the second television not working given that the first one doesn't work is 1/9.
So, P(A and B) = P(A) * P(B|A) = 2/10 * 1/9P(A and B) = 0.0222
Since there are two televisions that are randomly selected, we have a total of 10C2 ways of doing this. Thus, the probability that both televisions do not work is given by:
P(A and B) = 0.0222
Number of ways to select two televisions out of ten televisions: 10C2 = (10 * 9) / (2 * 1) = 45
Probability of both televisions not working: P(A and B) = 0.0222
Probability of both televisions not working = (P(A and B)) / (10C2)
Probability of both televisions not working = 0.0222/45
Probability of both televisions not working = 0.00049
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6 Given: TY XY, ZTVY = ZXWY Prove: ATVY = AXWY Statements Reasons 1. TY ~ XY 1. Given 2. Given 2. LTVY & LXWY 3. 3. 4. 4. 5. 5. OTVY Z OXWY Gina wison All Things Aige
Statement 3:
\(TV\cong XW\)Reason: Law of cosines
Statement 4:
\(VY\cong WY\)Reason: Law of cosines
Proof
We have the following situation:
Because the law of cosines,
\(\begin{gathered} a^2=c^2+d^2-2cd\cos (b) \\ a^2=e^2+f^2-2ef\cos (b) \end{gathered}\)Therefore,
\(c^2+d^2-2cd\cos (b)=e^2+f^2-2ef\cos (b)\)Given the system of equations below. Use the Inverse of the matrix method to solve. x+2y+3z=11
2x+4y+5z=21
3x+5y+6z=27
The solution of the given system of equations is x = -4, y = 5 and z = 2 is the answer.
The system of equations given below:x + 2y + 3z = 11;2x + 4y + 5z = 21;3x + 5y + 6z = 27.
Here, we will solve this system of equations using inverse of the matrix method as follows:
We can write the given system of equations in matrix form as AX = B where, A = [1 2 3; 2 4 5; 3 5 6], X = [x; y; z] and B = [11; 21; 27].
The inverse of matrix A is given by the formula: A-1 = (1/ det(A)) [d11 d12 d13; d21 d22 d23; d31 d32 d33] where,
d11 = A22A33 – A23A32 = (4 × 6) – (5 × 5) = -1,
d12 = -(A21A33 – A23A31) = -[ (2 × 6) – (5 × 3)] = 3,
d13 = A21A32 – A22A31 = (2 × 5) – (4 × 3) = -2,
d21 = -(A12A33 – A13A32) = -[(2 × 6) – (5 × 3)] = 3,
d22 = A11A33 – A13A31 = (1 × 6) – (3 × 3) = 0,
d23 = -(A11A32 – A12A31) = -[(1 × 5) – (2 × 3)] = 1,
d31 = A12A23 – A13A22 = (2 × 5) – (3 × 4) = -2,
d32 = -(A11A23 – A13A21) = -[(1 × 5) – (3 × 3)] = 4,
d33 = A11A22 – A12A21 = (1 × 4) – (2 × 2) = 0.
We have A-1 = (-1/1) [0 3 -2; 3 0 1; -2 1 0] = [0 -3 2; -3 0 -1; 2 -1 0]
Now, X = A-1 B = [0 -3 2; -3 0 -1; 2 -1 0] [11; 21; 27] = [-4; 5; 2]
Therefore, the solution of the given system of equations is x = -4, y = 5 and z = 2.
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C Laurel is moving and will have a
new mortgage of $2500. What
must Laurel increase her net
income to in order to keep her
housing cost at 25%?
Laurel must increase her net income to $10,000 in order to keep her housing costs at 25%.
To determine how much Laurel must increase her net income in order to keep her housing costs at 25%, we need to know the following information:
The amount of Laurel's new mortgage, which is $2500
The percentage of Laurel's net income that she wants to use for housing costs, which is 25%
To find the amount of net income that Laurel needs to maintain a housing cost of 25%, we can use the following formula:
Net income = Mortgage / (Housing cost percentage)
Substituting the values from the problem, we get:
Net income = $2500 / (25/100)
Net income = $2500 / 0.25
Net income = $10,000
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Laurel must increase her net income to $10,000 to keep her housing costs at 25%.
How to determine how much Laurel must increase her net income?The amount of Laurel's new mortgage is $2500
The percentage of Laurel's net income that she wants to use for housing costs, which is 25%
To find the amount of net income that Laurel needs to maintain a housing cost of 25%, we can use the following formula:
Net income = Mortgage / (Housing cost percentage)
Substituting the values from the problem, we get:
Net income = $2500 / (25/100)
Net income = $2500 / 0.25
Net income = $10,000
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A bolt manufacturer is very concerned about the consistency with which his machines produce bolts. The bolts should be 0.2 centimeters in diameter. The variance of the bolts should be 0.025. A random sample of 15 bolts has an average diameter of 0.21 cm with a standard deviation of 0.1587. Can the manufacturer conclude that the bolts vary by more than the required variance at α=0.01 level? Step 1 of 5: State the hypotheses in terms of the standard deviation. Round the standard deviation to four decimal places when necessary. A bolt manufacturer is very concerned about the consistency with which his machines produce bolts. The bolts should be 0.2 centimeters in diameter. The variance of the bolts should be 0.025. A random sample of 15 bolts has an average diameter of 0.21 cm with a standard deviation of 0.1587. Can the manufacturer conclude that the bolts vary by more than the required variance at α=0.01 level? Step 2 of 5: Determine the critical value(s) of the test statistic. If the test is twotailed, separate the values with a comma. Round your answer to three decimal places. A bolt manufacturer is very concerned about the consistency with which his machines produce boits. The bolts should be 0.2 centimeters in diameter. The variance of the boits should be 0.025. A random sample of 15 bolts has an average diameter of 0.21 cm with a standard deviation of 0.1587. Can the manufacturer conclude that the bolts vary by more than the required variance at α=0.01 level?
To determine if the bolts vary by more than the required variance, we can conduct a hypothesis test. The null hypothesis (H₀) states that the variance of the bolts is equal to or less than the required variance (σ² ≤ 0.025), while the alternative hypothesis (H₁) states that the variance is greater than the required variance (σ² > 0.025).
Next, we need to determine the critical value(s) of the test statistic. Since we are testing for variance, we will use the chi-square distribution. For a one-tailed test with α = 0.01 and 14 degrees of freedom (n-1), the critical value is 27.488.
Now, we can compare the test statistic to the critical value. The test statistic is calculated as (n-1) * s² / σ², where n is the sample size (15), s² is the sample variance (0.1587²), and σ² is the required variance (0.025).
If the test statistic is greater than the critical value, we reject the null hypothesis and conclude that the bolts vary by more than the required variance. Otherwise, we fail to reject the null hypothesis.
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To determine if the bolts vary by more than the required variance, we can conduct a hypothesis test. The null hypothesis (H₀) states that the variance of the bolts is equal to or less than the required variance (σ² ≤ 0.025), while the alternative hypothesis (H₁) states that the variance is greater than the required variance (σ² > 0.025).
Next, we need to determine the critical value(s) of the test statistic. Since we are testing for variance, we will use the chi-square distribution. For a one-tailed test with α = 0.01 and 14 degrees of freedom (n-1), the critical value is 27.488.
Now, we can compare the test statistic to the critical value. The test statistic is calculated as (n-1) * s² / σ², where n is the sample size (15), s² is the sample variance (0.1587²), and σ² is the required variance (0.025).
If the test statistic is greater than the critical value, we reject the null hypothesis and conclude that the bolts vary by more than the required variance. Otherwise, we fail to reject the null hypothesis.
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what is the slope of a line perpendicular to the line whose equation is x+4=28
The slope of a line perpendicular to the line is -4
The equation is x -4y = 28
The equation for the line is
y = mx + c
where m = slope
c = y-intercept
Here the equation is x - 4y = 28
4y = x - 28
y = x/4 - 7
So the slope of this line is 1/4
Now we have to find the slope of the line perpendicular to that line.
We know that,
m1 × m2 = -1
1/4 × m2 = -1
m2 = -4
Therefore the slope of the line perpendicular to the line is -4.
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The complete question is:
Find the slope of a line perpendicular to x-4y=28
What is the purpose of using prefixes in the metric system?
Answer: to scale the base units so that they can represent anything from a very large numeric value
Step-by-step explanation:
to scale the base units so that they can represent anything from a very large numeric value
1. True or False
3 € {1, 2, 3, 4, 5}
True
O False
the anwser for this is true
Answer:
I also think it's true because it mostly made sense to me.
-22 = 6x + 4
Hehehhe I need help agaaaaiiin
Hey there!
\(Answer:\boxed{x=\frac{-13}{3}}\)
\(Explanation:\)
\(-22=6x+4\)
Let's start off with flipping the equation.
\(6x+4=-22\)
Now we need to subtract 4 from both sides of the equation.
\(6x+4-4=-22-4\\6x=-26\)
Now in our third/last step, we will divide both sides by 6.
\(\frac{6x}{6}=\frac{-26}{6}\)
\(x=\frac{-13}{3}\)
\(\boxed{x=\frac{-13}{3}}\text{ is the answer.}\)
Hope this helps!
\(\text{-TestedHyperr}\)
Answer:
wh4t th3 0th3r p3rs0n s41d
Step-by-step explanation:
h33h33h33h33h33h33h33h33hh33h3h3h3h3h333h33hhhhh333333
Evaluate the integral. (Use C for the constant of integration.)
∫tan^4 (x) cos^5 (x) dx
To evaluate the integral ∫tan^4(x) cos^5(x) dx, we can use trigonometric identities to simplify the integrand.
We'll use the power-reducing formula for tan^4(x) and the power-reducing formula for cos^5(x) to simplify the integrand:
∫tan^4(x) * cos^5(x) dx
= ∫(tan^2(x))^2 * (cos^2(x))^2 * cos(x) * cos^2(x) dx
= ∫[(sec^2(x) - 1)^2] * [(1 - sin^2(x))^2] * cos(x) * cos^2(x) dx
Expanding the square terms, we get:
= ∫[(sec^4(x) - 2sec^2(x) + 1)] * [(1 - 2sin^2(x) + sin^4(x))] * cos(x) * cos^2(x) dx
Multiplying the terms together, we have:
= ∫[sec^4(x) - 2sec^2(x) + 1 - 2sin^2(x) + 4sin^4(x) - 2sin^6(x)] * cos^3(x) dx
Now, let's integrate each term separately:
∫sec^4(x) * cos^3(x) dx:
Using the substitution u = sin(x), we have:
∫(1 + u^2)^2 * (1 - u^2) du
Expanding the expression and integrating, we get:
= ∫(1 + 2u^2 + u^4 - u^4 - u^6) du
= u + 2/3 u^3 + 1/5 u^5 - 1/7 u^7 + C
Substituting back u = sin(x), we have:
= sin(x) + 2/3 sin^3(x) + 1/5 sin^5(x) - 1/7 sin^7(x) + C
∫-2sec^2(x) * cos^3(x) dx:
Using the substitution u = sin(x), we have:
∫-2(1 + u^2) * (1 - u^2) du
Expanding the expression and integrating, we get:
= ∫(-2 + 2u^2 - 2u^2 + 2u^4) du
= -2u + 2/3 u^3 - 2/5 u^5 + 2/7 u^7 + C
Substituting back u = sin(x), we have:
= -2sin(x) + 2/3 sin^3(x) - 2/5 sin^5(x) + 2/7 sin^7(x) + C
∫cos^3(x) dx:
Using the substitution u = sin(x), we have:
∫(1 - u^2) du
Integrating, we get:
= u - 1/3 u^3 + C
Substituting back u = sin(x), we have:
= sin(x) - 1/3 sin^3(x) + C
Putting it all together, the complete result of the integral is:
∫tan^4(x) * cos^5(x) dx
= ∫[sec^4(x) - 2sec^2(x) + 1 - 2sin^2(x) + 4sin^4(x) - 2sin^6(x)] * cos^3(x) dx
= ∫sec^4(x) *
cos^3(x) dx - 2∫sec^2(x) * cos^3(x) dx + ∫cos^3(x) dx
= (sin(x) + 2/3 sin^3(x) + 1/5 sin^5(x) - 1/7 sin^7(x)) - 2(-2sin(x) + 2/3 sin^3(x) - 2/5 sin^5(x) + 2/7 sin^7(x)) + (sin(x) - 1/3 sin^3(x)) + C
= sin(x) + 4/3 sin^3(x) - 8/5 sin^5(x) + 20/7 sin^7(x) + C
Therefore, the final result is:
∫tan^4(x) * cos^5(x) dx = sin(x) + 4/3 sin^3(x) - 8/5 sin^5(x) + 20/7 sin^7(x) + C
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PLEASE HELP! DUE TODAY! TY!
In the figure, line segment AB is tangent to the circle at point A. Find the length of line segment AB.
Work:
AB =
Answer: 12 inches
Step-by-step explanation:
A rectangular box weight 2.8 pounds. Width 7.70 inches,depth 7.75 inches and height 1.41 inches what is the length
The length of the rectangular box is given as follows:
1.59 inches.
How to obtain the volume of the rectangular prism?The volume of a rectangular prism, with dimensions length, width and height, is given by the multiplication of these dimensions, as follows:
Volume = length x width x height.
A rectangular box weight 2.8 pounds, and each pound has 27.68 cubic inches, hence the volume in in³ is given as follows:
V = 2.8 x 27.68
V = 77.504 in³.
The width is of 7.70 inches and the height is of 7.75 - 1.41 = 6.34 inches, hence the length is obtained as follows:
7.70 x 6.34l = 77.504
l = 77.504/[7.70 x 6.34]
l = 1.59 inches.
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If $5x-7=13x+17$, what is $6(x-4)$?
Answer:
0(x-4)
Step-by-step explanation:
in my working system i mean just when i try on the place of 4 any number can be inserted
$5x-7=13x+17$,here both gives -22 as a result so
$6(x-4)$=6x-24 and to give the same result or 0
$6(x-4)$=0(x-any number )
can somebody do the first one
Answer:
Step: 1
6x and 8x
Step: 2
remove the three x's on the first one and remove the one x one and 4 circles on the second and they should be even
Step-by-step explanation:
The total cost of a purchase of a number ofChromebooks, x can be represented by the functionc(x) = 250x. Which set of numbers best defines thedomain of c(x)? Explain how you know.A: integersB: Positive IntegersC: Rational NumbersD: Positive Rational Numbers
The Answer is Positive Integers (B)
The number of Chromebooks = x
The total cost of purchasing Chromebooks = c(x)
where x is the domain of c(x)
The number of Chromebooks x can be: {0, 1, 2, 3, 4, 5, 6...}. You cannot have numbers like {0.2, 0.5, 3.8 ...} or any other decimal neither can you have surds like:
\(\sqrt[]{3},\sqrt[]{8},\sqrt[]{55},\text{ and so on}\)Integers contain numbers like: {... , -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, ...}
Positive Integer contains numbers like: {1, 2, 3, 4, 5, ...}
Rational Numbers contain numbers like: {-0.2, -0.1, -0.05, -0.005,0.2, 0.1, 0.05, 0.005,...} and also contain numbers like {... , -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, ...} as in Integers.
Positive rational Numbers are just the positive values of Rational Numbers like: {1, 2, 3, 4, 5, ...} and {0.2, 0.1, 0.05, 0.005,...}
From the information laid out, it is obvious that the only set of values that qualify to be called the domain of c(x) is Positive Integers
The Answer is Positive Integers (B)
1) A lunch service takes 3 ½ hours to complete. If the chef is getting pains $24.80, per hour, what is the total amount earned?
Answer:
The answer is $86.80. The lunch service gains $86.80 in 3 1/2 hours if they get $24.80 per hour.
Step-by-step explanation:
You have to multiply how much they earn per hour, $24.80, by the number of hours they work, 3 1/2. $24.80 times 3 1/2 equals 86.80 so the lunch service earns $86.80 in 3 1/2 hours.
Hope this helps!
Given the function
y
=
(
−
6
+
x
−
6
x
2
)
(
−
9
−
9
x
)
,
y=(−6+x−6x
2
)(−9−9x), find
d
y
d
x
dx
dy
in any form.
Answer:
y=6+2x
Step-by-step explanation:
The long jump pit was recently rebuilt to make it level with the runway. volunteers provided pieces of wood to frame in the pit. each piece of wood provided measures 6 ft, which is approximately 1.8 to 8 7. determine the amount of wood, in meters, needed to rebuild the frame.
The amount of wood, in meters, needed to rebuild the frame is 1.8288 m.
What is amount and example?
amount to (something) : to produce (a total) when added together. The bill amounted to 10 dollars. They have debts amounting to thousands of dollars.
To calculate the amount of wood, in meters, needed to rebuild the frame, we can use the following formula:
wood (m) = (wood (ft) x 0.3048) / 6
Since each piece of wood provided measures 6 ft (approximately 1.8 to 8.7), we can calculate the amount of wood, in meters, needed to rebuild the frame as follows:
wood (m) = (6 ft x 0.3048) / 6
wood (m) = 1.8288 m
Therefore, the amount of wood, in meters, needed to rebuild the frame is 1.8288 m.
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The distance between Boats 2 and Boat 3 is known to be 65 miles. Given the picture below, determine the distance between Boat 1 and Boat 3.
Find the gradient of the line segment between the points (-6,4) and (-4,10).
Answer:
gradient = 3
Step-by-step explanation:
Calculate the gradient using the slope formula
m = \(\frac{y_{2}-y_{1} }{x_{2}-x_{1} }\)
with (x₁, y₁ ) = - 6, 4) and (x₂, y₂ ) = (- 4, 10)
m = \(\frac{10-4}{-4+6}\) = \(\frac{6}{2}\) = 3
Answer:
i hope its clear . the answer is 3 .
What is an equation of the line that passes through the points (0, -3) and (0, -8)?
I believe it would be x = 0.
Hope this helps!
scenario 2, continued next, you prepare for the question-and-answer session that will follow your presentation. what methods help you consider any limitations of your data? select all that apply. 1 point look at the context eliminate the outliers critically analyze the correlations understand the strengths and weaknesses of the tools
The concept is Data Analysis, which is the process of totally applying statistical tools to dissect data. The answer is options B, C, and D.
To help you consider data limitations, critically dissect correlations, examine the environment, and understand tool strengths and sins. Data analysis applies statistical and/ or logical ways to describe, illustrate, epitomize, and estimate data.
Data analysis helps individualities and associations make sense of data. Data analysts typically analyze raw data for insights and trends.
Limitations include:
Lack of alignment within teamsLack of commitment and patienceLow quality of dataPrivacy concernsComplexity & BiasQuestion
You're preparing a question-and-answer session that will follow your donation. Which styles help you to consider data limitations? elect everything that suits you.
A) exclude the outliers
B) Understand the strengths and sins of the tools
C) Critically dissect the correlations
D) Look at the environment
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Which set of numbers includes only integers?
Rational Numbers
Integers
Whole Numbers
Answer:
B
Step-by-step explanation:
Integers are like whole numbers, but they can also be negative.
Some examples of integers are -1, 2, 5 etc.
what is 83% of £408 someone help pls
Dan is stocking up on AA and AAA batteries. He bought 10 packages of batteries for a total of 72 batteries. The AA batteries are sold in packages of 6, and the AAA batteries are sold in packages of 8. Write, but do not solve, a system of equations that can be used to find how many packages of each type of battery Dan bought.
Answer:
x + y = 10
6x + 8y = 72
Step-by-step explanation:
Number of packages = 10
Total batteries = 72
For AA:
batteries per package = 6
Let number of packages = x
For AAA:
batteries per package = 8
Let number of packages = y
Number of AA packages + number of AAA packages = 10
Sum of AA + sum of AAA equals 72 batteries
x + y = 10
6x + 8y = 72
Answer:Answer:
x + y = 10
6x + 8y = 72
Step-by-step explanation:
Number of packages = 10
Total batteries = 72
For AA:
batteries per package = 6
Let number of packages = x
For AAA:
batteries per package = 8
Let number of packages = y
Number of AA packages + number of AAA packages = 10
Sum of AA + sum of AAA equals 72 batteries
x + y = 10
6x + 8y = 72
Step-by-step explanation:
Rounding please help! Math
it is just still 5 I believe :P hope this helps
help pls ;--; mmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm
Answer:
570240000
Step-by-step explanation:
Find all missing angles?
Can SOMEONE PLEASE HELP ME I DONT UNDERSTAND THIS PLEASEE ILL GIVE YOU BRIANLIEST
Answer:
sorry I also dont understand
determine if parallel, perpendicular, or neither
y=-3x+6 and y=1/3x-8
Answer:
Perpendicular!!!
Step-by-step explanation:
-3 and 1/3 are negative recopricals. This means they are perpendicular.
I would take a brainliest
Answer:
perpendicular
Step-by-step explanation:
for an equation to be parallel, the equations would have to have the same slope. for and equation to be perpendicular, the slopes have to be reciprocal, like 5/1 and 1/5, or 2/15 and 15/2. Also, one slope has to be negative. These equations match the definition of perpendicular lines.
For each of the following relations, decide if it is reflexive, symmetric, and or transitive.
Prove your answers.
(a) Ri is the relation on R given by Ri = {(z,y) ERx R: |x-y <1}.
(b) Let A be a set with at least two elements. Let R be the relation on A given by
(c) Rs is the relation on Z given by R3 = {(z,y) ⬠Zà Z: xy > 0).
(d) R, is the relation on Z given by R, = {(2, y) ⬠Zx Z: 3|(à + 2y)}. (e) Rs is the relation on Z given by Rs = {(x,y) ⬠Zx Z: there exists k ⬠N such that
elyk and yak).
In this question, we were given five relations and asked to determine if they are reflexive, symmetric, and/or transitive.
(a) The relation Ri on R is reflexive, symmetric, and transitive.
(b) The relation R on A is not reflexive, not symmetric, and transitive.
(c) The relation Rs on Z is not reflexive, not symmetric, and transitive.
(d) The relation R, on Z is not reflexive, not symmetric, and not transitive.
(e) The relation Rs on Z is reflexive, not symmetric, and transitive.
What is reflexive relation?A reflexive connection is a relationship between items of a set A in which each element is related to itself. As the name implies, the image of each element of the set is its own reflection. In set theory, a reflexive relation is an essential concept.
(a) Ri is reflexive, symmetric, and transitive.
- Reflexive: For any x ∈ R, (x, x) ∈ Ri since |x - x| = 0 < 1.
- Symmetric: For any (x, y) ∈ Ri, we have |x - y| < 1, which implies |y - x| < 1. Therefore, (y, x) ∈ Ri.
- Transitive: For any (x, y), (y, z) ∈ Ri, we have |x - y| < 1 and |y - z| < 1. Adding these inequalities, we get |x - z| < 2, which implies (x, z) ∈ Ri.
(b) R is not reflexive, symmetric, or transitive.
- Not reflexive: For any x ∈ A, (x, x) ∉ R since x - x = 0 is not a positive integer.
- Not symmetric: For any distinct x, y ∈ A, if (x, y) ∈ R, then x - y = 1, which implies y - x = -1 is not a positive integer. Therefore, (y, x) ∉ R.
- Not transitive: Let A = {1, 2, 3} and R = {(1, 2), (2, 3)}. Then (1, 3) is not in R since 3 - 1 = 2 is not a positive integer.
(c) R3 is not reflexive, symmetric, or transitive.
- Not reflexive: For any x ∈ Z, (x, x) ∉ R3 since x * x = x^2 is not greater than 0.
- Symmetric: For any (x, y) ∈ R3, we have xy > 0, which implies yx > 0. Therefore, (y, x) ∈ R3.
- Not transitive: Let x = -1, y = 2, and z = -1. Then (x, y) ∈ R3 and (y, z) ∈ R3, but (x, z) = (-1, -1) ∉ R3 since xz = 1 is not greater than 0.
(d) R, is not reflexive, symmetric, or transitive.
- Not reflexive: For any y ∈ Z, (y, y) ∉ R, since 3 does not divide y + 2y = 3y.
- Not symmetric: For y = 1 and z = 2, we have (2, 1) ∉ R, but (1, 2) ∈ R since 3 divides 1 + 4 = 5.
- Not transitive: Let x = 2, y = 1, and z = 5. Then (x, y) ∈ R, (y, z) ∈ R, but (x, z) = (2, 5) ∉ R since 3 does not divide 2 + 10 = 12.
(e) Rs is the relation on Z given by Rs = {(x,y) ⬠Zx Z: there exists k ⬠N such that elyk and yak).
- Reflexive: This relation is not reflexive because (1, 1) ∉ Rs as there does not exist k such that 1 x k = 1.
- Symmetric: This relation is not symmetric because, for example, (1, 2) ∈ Rs but (2, 1) ∉ Rs since there does not exist k such that 2 x k = 1.
- Transitive: This relation is not transitive. For example, let x = 1, y = 2, and z = 4. Then (x, y) ∈ Rs and (y, z) ∈ Rs, but (x, z) ∉ Rs since there does not exist k such that 1 x k = 4.
In short, in this question, we were given five relations and asked to determine if they are reflexive, symmetric, and/or transitive.
(a) The relation Ri on R is reflexive, symmetric, and transitive.
(b) The relation R on A is not reflexive, not symmetric, and transitive.
(c) The relation Rs on Z is not reflexive, not symmetric, and transitive.
(d) The relation R, on Z is not reflexive, not symmetric, and not transitive.
(e) The relation Rs on Z is reflexive, not symmetric, and transitive.
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