Suppose you are chatting with your friend, who lives on the moon. He tells you he has just won a Newton of gold in a contest. Excitedly, you tell him that you entered the Earth version of the same contest and also won a Newton of gold. Who is richer

Answer:

PE = 137.2931 J

Explanation:

PE = 137.2931 J

Answer:

When reviewing the correct answer is A

Explanation:

The magnetic force is given by the expression

           F = qv xB

where the bold letters indicate vectors, from this expression the module can be calculated

          F = = q v b sin θ

the direction of the force is given by the rule of the right hand, for a positive charge the speed held by the thumb, the extended fingers point in the direction of the magnetic field and the palm points the direction of the force

in this case

the speed is in the negative part of the z axis

the force is in the negative direction of the axis and

consequently the magnetizing field is in the positive direction of the x axis

When reviewing the correct answer is A

The magnitude of a vector G pointed 36.9° clockwise from the positive y-axis, with an x-component of 3, is 5.

The magnitude of the vector is given by:

\( \overline{G} = \sqrt{G_{x}^{2} + G_{y}^{2}} \)

Where:

\( G_{x}\): is the x-component of the vector G = 3

\(G_{y}\): is the y-component of the vector G

We need to calculate the y-component of the vector. We can use the following trigonometric function:

\( tan(\theta) = \frac{G_{x}}{G_{y}} \)

Where:

θ: is the angle = 36.9° (clockwise from the positive y-axis)

Hence, the y-component of the vector is:

\( G_{y} = \frac{G_{x}}{tan(\theta)} = \frac{3}{tan(36.9)} = 4 \)

Now, the magnitude of the vector is:

\( \overline{G} = \sqrt{G_{x}^{2} + G_{y}^{2}} = \sqrt{(3)^{2} + (4)^{2}} = 5 \)

Therefore, the magnitude of the vector G is 5.

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In the experiment, place a ringing alarm clock inside a vacuum chamber, and observe that when the chamber is evacuated, the sound from the alarm clock cannot be heard, illustrating that sound does not travel through a vacuum.

To illustrate that sound requires a medium for its propagation and does not travel through a vacuum, you can perform the following experiment:

Take two identical bells or sound-producing devices and place them in separate chambers, one in a vacuum chamber and the other in a chamber filled with air.

Ensure that both chambers are isolated from external noise sources.

Activate the sound-producing devices simultaneously, creating sound waves in both chambers.

Observe and listen for the sound produced in each chamber.

In the chamber filled with air, you will hear the sound clearly, as air molecules transmit the sound waves, allowing them to propagate and reach our ears.

However, in the vacuum chamber, you will not hear any sound because there is no medium (such as air) for the sound waves to travel through. Without molecules to transmit the vibrations, the sound cannot reach our ears.

This experiment demonstrates that sound requires a medium, such as air or other substances, to propagate and be perceived by our ears. In a vacuum, where there is an absence of molecules, sound cannot travel.

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Considering the definition of precision and accuracy, the mass readings of the digital balance are accurate but not precise.

Precision as the proximity between the indications or measured values ​​of the same measurand, obtained in repeated measurements, under specified conditions.

Accuracy is defined as the closeness between the measured value and the "true" value of the measurand.

In other words, accuracy is how close a measurement is to the true value, while precision is how close the values ​​of several measurements are to a point.

Precision and accuracy are independent of each other. Thus, the results in the values ​​of a measurement can be precise and not exact (and vice versa).

A set of 500-g masses is placed one at a time on a digital balance during quality control testing. The mass readings are 397 g, 401 g, and 403 g.

In this case, the measurement is accurate, since the results of each individual measurement are quite similar. But the measurements are not exact (not precise) because the results are far from the real value.

In summary, the mass readings of the digital balance are accurate but not precise.

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The gravitational force that the moon has on a person with a mass of 50 kg is approximately 1.15 N.

The gravitational force between two objects depends on their masses and the distance between them. This force is given by the formula:

F = (G × m₁ × m₂) / r² where F is the gravitational force, m₁ and m₂ are the masses of the two objects, r is the distance between them, and G is the gravitational constant, which has a value of 6.7 × 10⁻¹¹ N m²/kg².

Using this formula, we can find the gravitational force that the moon has on a person with a mass of 50 kg.

The mass of the moon is 7 × 10²² kg, and the distance between the moon and the person is 380,000,000 m.

Therefore, we have:

m₁ = 50 kg

m₂ = 7 × 10²² kg

r = 380,000,000 m

G = 6.7 × 10⁻¹¹ N m²/kg²

Substituting these values into the formula, we get:

F = (G × m₁ × m₂) / r²

F = (6.7 × 10⁻¹¹ × 50 kg × 7 × 10²² kg) / (380,000,000 m)²

F = 1.15 N

Therefore, the gravitational force that the moon has on a person with a mass of 50 kg is approximately 1.15 N.

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The ball will strike the ground after 8.04 seconds.

Using the kinematic equation for displacement:

y = y0 + v0t - 1/2g*t^2

where:

We want to findt, let's substitute the values:

0 = 58.52 + 19.50t - 1/2(9.81)*t^2

4.905t^2 - 19.50t - 58.52 = 0

Using the quadratic formula:

t = (-b ± sqrt(b^2 - 4ac)) / 2a

where:

t = (-(-19.50) ± sqrt((-19.50)^2 - 4(4.905)(-58.52))) / 2(4.905)

t = (19.50 ± 31.37) / 9.81

The two possible solutions are:

t1 = 5.61 s (ball on the way up)

t2 = 8.04 s (ball on the way down)

Since the question is asking for when the ball strikes the ground, we take the larger solution, which is:

t = 8.04 s

In other words, the ball will strike the ground after 8.04 seconds.

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a) The total surface area of tin G in terms of π is 170π cm².

b) The mass of tin H is 336 g.

To solve the given problem, we need to determine the total surface area of tin G in terms of π and the mass of tin H. Since the mass of an empty cylindrical tin is proportional to its surface area, we can use the given information to find the solutions.

a) Total surface area of tin G in terms of π:

The surface area of a cylinder consists of two circular bases and the lateral surface area. The formula for the lateral surface area of a cylinder is given by:

Lateral surface area = 2πrh

where r is the radius of the base and h is the height of the cylinder.

In the case of tin G, the given dimensions are a radius of 5 cm and a height of 12 cm. Substituting these values into the formula, we can calculate the lateral surface area:

Lateral surface area = 2π(5 cm)(12 cm)

Lateral surface area = 120π cm²

Since the total surface area of the cylinder includes the two circular bases as well, we need to add their areas. The area of a circle is given by:

Area of a circle = πr²

The radius of the circular base of tin G is 5 cm, so the area of each circular base is:

Area of each circular base = π(5 cm)²

Area of each circular base = 25π cm²

To find the total surface area of tin G, we sum the lateral surface area and the areas of the two circular bases:

Total surface area of tin G = Lateral surface area + 2 × Area of each circular base

Total surface area of tin G = 120π cm² + 2 × 25π cm²

Total surface area of tin G = 120π cm² + 50π cm²

Total surface area of tin G = 170π cm²

Therefore, the total surface area of tin G in terms of π is 170π cm².

b) Mass of tin H:

We are given that the surface area of tin H is 792π cm². We can assume that the same proportionality factor applies as in tin G, so we can set up the following proportion:

(surface area of tin G) / (mass of tin G) = (surface area of tin H) / (mass of tin H)

Using the given values, we have:

(170π cm²) / (72 g) = (792π cm²) / (mass of tin H)

Cross-multiplying and solving for the mass of tin H, we get:

(170π cm²) × (mass of tin H) = (72 g) × (792π cm²)

mass of tin H = (72 g) × (792π cm²) / (170π cm²)

mass of tin H = 336 g

Therefore, the mass of tin H is 336 g.

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The time taken for the ball to reach its maximum height is 1 second.

To calculate the time taken for the ball to reach its maximum height, we can use the kinematic equation for vertical motion. The equation is:

v = u + at

Where:

v = final velocity

u = initial velocity

a = acceleration

t = time

In this case, the ball is thrown vertically upwards, so the initial velocity (u) is 10 m/s (considering upwards as positive) and the acceleration (a) is -10 m/s² (negative because it opposes the motion).

The final velocity (v) at the maximum height will be zero because the ball momentarily comes to a stop before reversing its direction. Therefore, we can rewrite the equation as:

0 = 10 - 10t

Simplifying the equation, we get:

10t = 10

Dividing both sides by 10, we find:

t = 1 second

Therefore, the time taken for the ball to reach its maximum height is 1 second.

During this time, the ball covers the distance required to reach the maximum height, overcoming the gravitational acceleration. After reaching the maximum height, it will start to descend towards the ground due to the gravitational pull.

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The elasticity of supply of labor varies among occupations. The supply of labor is elastic for occupations (a) and (b) and inelastic for occupations (c).

The elasticity of the supply of labor is an important concept that measures the responsiveness of the quantity of labor supplied to changes in the wage rate. An occupation's supply of labor is said to be elastic if its elasticity is greater than 1, inelastic if the elasticity is less than 1, and unitary elastic if the elasticity of supply equals 1. Let's calculate the elasticity of supply for the following occupations and determine whether the supply of labor is elastic, inelastic, or unitary elastic.

a. %ΔES = 7, %ΔW = 3

The formula for the elasticity of supply is (% change in quantity supplied / % change in wage). Therefore, the elasticity of supply for this occupation would be:

Elasticity of supply = (7% / 3%) = 2.33

Since the elasticity of supply is greater than 1, the supply of labor is elastic.

b. ES = 120, W = $8

E’S = 90, W’ = $6

The formula for the elasticity of supply is ((% change in quantity supplied) / (% change in wage)). Therefore, the elasticity of supply for this occupation would be:

Elasticity of supply = ((90 - 120) / ((90 + 120) / 2)) / ((6 - 8) / ((6 + 8) / 2))

The elasticity of supply = (-30 / 105) / (-2 / 7)

Elasticity of supply = 2.00

Since the elasticity of supply is greater than 1, the supply of labor is elastic.

c. ES = 100, W = $5

E’S = 120, W’= $7

The formula for the elasticity of supply is ((% change in quantity supplied) / (% change in wage)). Therefore, the elasticity of supply for this occupation would be:

Elasticity of supply = ((120 - 100) / ((120 + 100) / 2)) / ((7 - 5) / ((7 + 5) / 2))

The elasticity of supply = (20 / 110) / (2 / 6)

Elasticity of supply = 0.81

Since the elasticity of supply is less than 1, the supply of labor is inelastic. The elasticity of supply is a critical concept in labor economics and helps us understand how changes in wage rates affect the quantity of labor supplied in different occupations.

Complete question:

As with the own-wage elasticity of demand for labor, the elasticity of supply of labor can be similarly classified. The elasticity of the supply of labor is elastic if the elasticity is greater than 1. It is inelastic if the elasticity is less than 1, and it is unitary elastic if the elasticity of supply equals 1. For each of the following occupations, calculate the elasticity of supply, and state whether the supply of labor is elastic, inelastic, or unitary elastic. E’s and W’ are the original supply of workers and wages. and are the new supply of workers and wages.

a %ΔES = 7, %ΔW = 3

b. ES = 120, W = $8

E’S = 90, W’ = $6

c. ES = 100, W = $5

E’S = 120, W’= $7

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The time that was taken for the movement of the item is observed as 3 seconds.

The equations of motion describe the motion of objects in terms of their position, velocity, acceleration, and time.

For the equation;

v = u + at

This equation relates the final velocity (v) of an object to its initial velocity (u), acceleration (a), and time (t). If three of these variables are known, the equation can be rearranged to solve for the unknown variable.

We know that;

v = u - gt

We know that the object would come to rest after being thrown.

0 = 30 - 10t

-30 = - 10t

t = 3 seconds

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Answer: 1. height of cylinder 2. temperature of cylinder 3.mass of cylinder 4.temp. of cylinder

Explanation:

im doing it rn ! hope this helps :)

The dependent variable gets impacted by changes to the independent variable. Therefore, in the below given ways blanks can be filled.

The variable that the experimenter controls is the independent variable. The variable that adapts to the independent variables is known as the dependent variable. The two factors could be connected through cause and effect. The dependent variable gets impacted by changes to the independent variable.

The experiment was divided into two parts. For the first part of the experiment, the height of cylinder was intentionally manipulated. This was independent variable. the dependent variable measured was the  temperature of cylinder.

For the second part of experiment, the mass of cylinder was intentionally manipulated. This was the independent variable. The dependent variable measured was the temperature of cylinder.

Therefore, in the above given ways blanks can be filled.

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Answer:

I would say B

Explanation:

the other ones don't seem right

\( \boxed{\sf Correct \: Answer \: is \: \frac{Q}{2} \& \frac{Q}{2} }\)

Refer attachment for complete solution!

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If the impulse is strong enough and lasts for a sufficient amount of time, the go-kart will eventually come to a stop.

Option A is correct.

impulse is described as the integral of a force, F, over the time interval, t, for which it acts. Since force is a vector quantity, impulse is also a vector quantity.

If the force is insufficient to stop the go-kart entirely, it will slow down but continue to move. The force and duration of the impulse, along with the mass and speed of the go-kart, will all affect how much deceleration occurs.

Given that momentum plus impulse equals zero, the go-kart's change in momentum as a result of the impulse will be equal in amount but will move in the opposite direction of its original momentum.

As a result, the go-kart's final momentum will be zero, suggesting that it has either stopped or is travelling very slowly.

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Answer:

Β. 16 με

Explanation:

Data provided in the question

Number of electrons removed = 10^14

And, the charge on one electron = \(1.6\times 10^ {-19C}\)

Based on the above information, the charged on the sphere is

Therefore when we remove the electrons

So, the equation would be

\(10^{14} \times 1.6 \times 10^{-19 C}\)

= \(1.6 \times 10\)

Therefore the same amount of the positive charged would be developed

Hence, the correct option is B.

Hi there!

A.

We can calculate the gravitational field strength using the following equation:

\(g = \frac{Gm_p}{r^2}\)

G = Gravitational Constant

mp = mass of planet (kg)

r = radius (m)

Plug in the given values:

\(g = \frac{(6.67*10^{-11})*(5.68*10^{24})}{(6.03*10^7)^2} = \boxed{0.104 N/kg}\)

B.

The force can be calculated using:

\(F_g = \frac{Gm_1m_2}{r^2}\)

Plug in the values:

\(F_g = \frac{(6.67*10^{-11})(5.68*10^{24})(50)}{(6.04*10^7)^2} = \boxed{5.209N}\)

Answer:

\(\boxed {\boxed {\sf g=0.104 \ N/kg \ and \ F_g= 5.2 \ N }}\)

Explanation:

A. Gravitational Field Strength

The gravitational field strength can be calculated using the following formula:

\(g= \frac{Gm}{r^2}\)

G, or the universal gravitational constant, is 6.67 × 10⁻¹¹ N*m²/kg². The mass of Saturn is 5.68 × 10²⁴ kilograms. The radius of Saturn is 6.03×10⁷ meters.

Substitute these values into the formula.

\(g= \frac{ (6.67 \times 10^{-11} \ N*m^2/kg^2) (5.68 \times 10^{24} \ kg)}{(6.03 \times 10^{7} \ m )^2}\)

Multiply the numerator and square the denominator.

\(g= \frac{ 3.78856 \times 10^{14} \ N *m^2/kg }{3.63609 \times 10^{15} \ m^2}\)

Divide.

\(g= 0.1041932405 \ N/kg\)

The original measurements of mass and radius have 3 significant figures, so our answer must have the same. For the number we found, that is the thousandth place. The 1 in the ten-thousandth place tells us to leave the 4 in the thousandth place.

\(\boxed {g \approx 0.104 \ N/kg}\)

B. Force of Gravity

The force of gravity is calculated using the following formula:

\(F_g= mg\)

The mass of the object is 50 kilograms. We just calculated the gravitational field strength, which is 0.104 Newtons per kilogram. Substitute these values into the formula.

\(F_g= (50 \ kg)(0.104 \ N/kg)\)

Multiply. The units of kilograms cancel.

\(\boxed {F_g=5.20 \ N}\)

When light passes from air into water, it slows down and bend towards the normal.

When light travels from glass to air its speed increases and bend away from the normal.

When light travels from air to glass, speed decreases.

When light travels from air to water wavelength increase as refractive index of air is less than the water.

When light travels from water into air, its speed increases and it bend away from the normal.

Refraction is defined as the bending of light at the surface of two media when it changes medium of propagation.

When light passes from an optically rarer medium to optically denser medium. its speed decreases and it bend towards the normal. When light passes from the denser medium to a rarer medium, its speed increases and it bends away from the normal.

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The angles between X, Y, and Z are θx = θy = 63.6, θz = 27.2 with the resultant vector R = i + 2j + 4k.

From the given,

the resultant vector, R = i+2j+4k

Rx = 1

Ry = 2

Rz = 4

R² = Rx² + Ry² + Rz²

   = (1)² + (2)² + (4)²

  = 1+4+16

= 21

R = √21

 = 4.5

Thus, the resultant vector, R is 4.5.

The angles between x, y, and z.

cosθx = Rx/R = 1/4.5

θx = cos⁻¹ (0.22) = 77.1° in X- axis.

cosθy = Ry/R = 2/4.5

θy = cos⁻¹(0.44) = 63.6° in Y-axis.

cosθz = Rz/R = 4/4.5

θz = cos⁻¹(0.88) = 27.2 in Z-axis.

The angles are θx = 77.1°, θy =63.6°, and θz = 27.2° along X, Y, and Z axis.

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Answer:

T/√8

Explanation:

From Kepler's law, T² ∝ R³ where T = period of planet and R = radius of planet.

For planet A, period = T and radius = 2R.

For planet B, period = T' and radius = R.

So, T²/R³ = k

So, T²/(2R)³ = T'²/R³

T'² = T²R³/(2R)³

T'² = T²/8

T' = T/√8

So, the number of hours it takes Planet B to complete one revolution around the star is T/√8

The correct expression for the number of hours it takes Planet B to complete one revolution around the star is \(\frac{T}{\sqrt{8} }\).

The given parameters;

From Kepler's law, the period of planet is related to radius as follows;

\(\frac{T_1^2}{R_1^3} = \frac{T_2^2}{R_2^3} \\\\T_2 ^2 = \frac{T_1^2 \times R_2^3}{R_1^3} \\\\T_2 = \sqrt{\frac{T_1^2 \times R_2^3}{R_1^3} } \\\\T_2 = \sqrt{\frac{T_1^2 \times R_2^3}{R_1^3} }\\\\T_2 = T_1 \sqrt{\frac{ R_2^3}{(2R_2)^3} }\\\\T_2 = T_1 \sqrt{\frac{R_2^3}{8R_2^3} } \\\\T_2 = T_1 \sqrt{\frac{1}{8} } \\\\T_2 = \frac{T_1}{\sqrt{8} }\\\\T_B = \frac{T_A}{\sqrt{8} } = \frac{T}{\sqrt{8} }\)

Thus, the correct expression for the number of hours it takes Planet B to complete one revolution around the star is \(\frac{T}{\sqrt{8} }\).

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Answer:

The work done in bringing the plates together is 5.9 x 10⁻¹⁰ J.

Explanation:

Given;

potential difference between the plates, V = 10 V

length of each square side of the plates, L = 20 cm = 0.2 m

area of the plates, A = 0.2 x 0.2 = 0.04 m²

separation of the plates, d = 3 cm = 0.03 m

The work done in bringing the plates together is calculated as;

W = ¹/₂qV

\(W = \frac{1}{2} (\frac{\epsilon_0 A }{d}V) \times V\\\\W = \frac{\epsilon_0 A V^2}{2d}\\\\W = \frac{8.85 \times 10^{-12} \ \times \ 0.04\ \times \ 10^2}{2(0.03)} \\\\W = 5.9 \times 10^{-10} \ J\)

Therefore, the work done in bringing the plates together is 5.9 x 10⁻¹⁰ J.

The total kinetic energy of each wheel is; 45 J, and each wheel reaches a maximum height of approximately 2.3 meters.

The total kinetic energy of each wheel is the sum of the translational kinetic energy of the center of mass and the rotational kinetic energy due to the rolling motion. For each wheel, the translational kinetic energy is given by;

K_trans = (1/2)mv²

where m is mass of the wheel and v is linear speed of the center of mass, which is 6.0 m/s.

K_trans = (1/2)(2.0 kg)(6.0 m/s)² = 36 J

The rotational kinetic energy due to rolling motion is given by:

K_rot = (1/2)Iω²

where I is moment of inertia of the wheel and ω is angular velocity of the wheel, which is related to the linear speed by ω = v/R, where R is radius of the wheel.

For a solid disk rotating about its center, the moment of inertia is given by I = (1/2)mr², where r is radius of the disk.

K_rot = (1/2)(1/2)(2.0 kg)(0.5 m)²(6.0 m/s)/(0.5 m)²

= 9 J

Therefore, total kinetic energy of each wheel is;

K_total = K_trans + K_rot = 36 J + 9 J

= 45 J

When each wheel rolls or slides up the incline, its kinetic energy is gradually converted to potential energy due to the increase in height. At the maximum height reached, all the kinetic energy has been converted to potential energy.

The maximum height reached by each wheel can be found using the conservation of energy, which states that the total mechanical energy (kinetic energy + potential energy) of the wheel is constant, assuming no energy is lost to friction or other non-conservative forces.

At the maximum height, the kinetic energy is zero and the potential energy is equal to the initial kinetic energy;

mgh = K_total

where m is mass of the wheel, g is acceleration due to gravity, h is the maximum height reached, and K_total is the total kinetic energy of the wheel, which is 45 J.

Solving for h, we get;

h = K_total/(mg) = 45 J/(2.0 kg)(9.81 m/s²) ≈ 2.3 m

Therefore, each wheel reaches a maximum height of 2.3 meters.

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Answer:

Displacement will be 5m west

Distance would be 21m No direction

60

because mass of an object never change

but weight can change for example if it's

mass is 60kg 5he wieght will be 60kg * 9.8m/s²

=588N

The momentum of the ball in motion is -0.68 kg m/s, and the force between the ball and the wall is -6.8 N.

The state of motion of an object with a certain mass is termed as momentum. It is the product of the mass and velocity of the moving object and is a vector quantity.

It is expressed as: p = m × v

First, let's calculate the initial momentum of the ball before it strikes the wall:

p₁ = m₁× v₁ = 40 g × 10 m/s = 0.04 kg ×  10 m/s = 0.4 kg m/s

Where  m₁ is the mass of the ball and v₁ is its initial velocity.

Next, let's calculate the final momentum of the ball after it bounces off the wall:

p₂ = m₁× v₂= 40 g × (-7 m/s) = -0.04 kg × 7 m/s = -0.28 kg m/s

where v₂ is the velocity of the ball after it bounces off the wall.

The change in momentum of the ball is then:

Δp = p₂- p₁ = (-0.28 kg m/s) - (0.4 kg m/s) = -0.68 kg m/s

Note that the change in momentum is negative, indicating that the ball's momentum has decreased in magnitude and changed direction.

To calculate the force between the ball and the wall,

J = Δp

where J is the impulse and Δp is the change in momentum.

The impulse is also equal to the force multiplied by the time during which the force is applied:

J = F × Δt

where F is the force and Δt is the time during which the force is applied.

Setting these two equations equal to each other, we get:

F × Δt = Δp

Solving for the force, we get:

F = Δp / Δt = (-0.68 kg m/s) / (0.1 s) = -6.8 N

The negative sign indicates that the force exerted by the ball on the wall is directed opposite to the direction of the ball's motion, as expected.

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The change in the momentum of the ball will be 0.68kgm/sec. While the force that acts on the body will be 0.68 N.

The measurement of mass in motion is called momentum. Momentum is equal to its mass multiplied by its velocity. Mathematically it is given as;

Momentum = Mass x Velocity

The given data in the problem is

ball mass ( m)= 40 g=0.040 kg

speed of the ball(v) = 10 m/s

rebound speed(V )= -7 m/s

The change in the momentum of the body is given by,

ΔP = mv - mv'

Δp= 0.040 x 10 - 0.057 x (-7)

ΔP = 0.68 kg.m/s

Hence the change in the momentum of the body will be 0.68 kg.m/s.

Impulse is defined as the product of force and time interval of contact.

ΔP = force *time

force = ΔP/time

force = 0.68/1

force = 0.68

Hence the force that acts on the body will be 0.68 N.

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The sled's speed can be calculated by considering the acceleration, frictional force, and time. After substituting the given values and performing the calculations, the final speed is determined to be 12.25 m/s.

To calculate the speed of the sled after 2.50 seconds, we can use the equations of motion and consider the forces acting on the sled.

Let's denote the initial speed of the sled as v0, the final speed as vf, the acceleration as a, the time as t, and the coefficient of friction as μ.

Initially, the rocket sled is accelerating, so we can use the equation:

vf = v0 + at

Since the sled is skidding along its rails after the rocket engine stops, the only horizontal force acting on the sled is the force of friction. The frictional force can be calculated using the equation:

frictional force = coefficient of friction * normal force

Since the sled is moving horizontally, the normal force is equal to the weight of the sled, which can be calculated as:

weight = mass * gravity

Now, we can determine the acceleration of the sled using Newton's second law:

frictional force = mass * acceleration

Combining the equations and substituting the values, we have:

vf = v0 + (frictional force / mass) * t

To find the frictional force, we need to calculate the weight of the sled and then multiply it by the coefficient of friction:

frictional force = (mass * gravity) * coefficient of friction

Substituting this back into the previous equation, we get:

vf = v0 + ((mass * gravity * coefficient of friction) / mass) * t

Simplifying further, we have:

vf = v0 + (gravity * coefficient of friction) * t

Now we can substitute the given values into the equation. Assuming the acceleration due to gravity is approximately 9.8 m/s², the coefficient of friction is 0.5, the initial speed is 0 m/s (since the sled starts from rest), and the time is 2.50 s, we can calculate the final speed:

vf = 0 + (9.8 * 0.5) * 2.50

vf = 12.25 m/s

Therefore, the sled is moving at a speed of 12.25 m/s after 2.50 seconds.

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Answer:

Your average speed is 60 kilometers per hour

Explanation:

240 divided by 4 is 60

240/4=60

The amount of time which the impetus was implemented is 3.04 seconds.

The momentum of the automobile is 34124.26 kg*m/s.

In order to figure out the time, the following formula for impulse can be applied: impulse = force x time. Reformulating and rearranging this equation, we reach the derivative of time = impulse / force. With the provided calculations of 536.49 N*s divided by 176.32 N, these figures conclude that the amount of time which the impetus was implemented is 3.04 seconds.

Additionally, we can use the formula of momentum = mass x velocity to further determine the vehicular testament of import. When applying these specified numbers of 2546.9 kg and 13.4 m/s respectively, the momentum of the automobile is 34124.26 kg*m/s.

momentum = 2546.9 kg x 13.4 m/s

= 34124.26 kg

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The current in a circuit that has a resistance of 30 ohms and a power of 2 watts is 0.2581 Ampere.

Solution:

The power in an electrical circuit is given by the equation:

\(P = I^{2} R\)

I = Current in the circuit

R = Resistance offered by the circuit

P = 2 watts

R = 30 Ω

I =?

2Watts = \(I^{2}\)x30Ω

\(I = \sqrt{\frac{2Watts}{30} }\)

I = 0.2581 Ampere.

The current through a resistor is inversely proportional to its resistance value. Resistance is a measure of resistance to the flow of current in an electrical circuit. Resistance is measured in ohms, represented by the Greek letter omega.

Electric current is the flow of charge through matter. The material or conductor through which current flows is often a metal wire, but current can also flow through some gases, liquids, and other materials. The circuit can be wired in two ways. Current is the speed at which charge flows. Resistance is the tendency of a material to resist the flow of electrical charges.

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