Suppose you are camping on a mountain and the air temperature is very cold. How would you keep warm? Would you build a fire or set up a tent?

The dynamic viscosity is generally greater for liquids, as compared to gases.Viscosity is a measure of the resistance of fluids to flow.

A fluid's viscosity is determined by its internal friction, and it is divided into two categories: dynamic viscosity and kinematic viscosity. Dynamic viscosity, also known as absolute viscosity, is the resistance of fluid to shear or tensile stress, whereas kinematic viscosity is the dynamic viscosity divided by the density of the fluid.

The dynamic viscosity of gases is lower than that of liquids. It implies that gases have a lower resistance to flow than liquids, which have a higher resistance to flow due to their internal friction. As a result, it takes more force to move liquids than it does to move gases.

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Answer:

2250N

Explanation:

W= mg,

where W= weight

m= mass

g= acceleration due to gravity

Given that the body is 90kg, m= 90kg.

Acceleration due to gravity of planet

= 2.5(10)

= 25 m/s²

Weight of body on planet

= 90(25)

= 2250N

*Mass is the amount of matter an object has and is constant (same on earth and the planet).

Answer:

Here

mass=90kg

time=2.5second

acceleration due to gravity=10m/s

now,,,

Force=???

Force=mass*acceleration

Force=90*10

Force=900N

Answer:c

Explanation:

The net force acting on the charge Q is in the direction D. The net force is the sum of forces from the two point charges Q+ each.

According to Coulomb's law of force, the electrostatic force between two charges separated by a distance of r is given as follows:

Fq =  k q1 q2 /r²

where, k is a constant.

As per this equation, the electrostatic force between two charges will increase as the magnitude of charge increases and the force decreases as the distance between them increases.

Here, the forces acting on the point charge Q- are the forces from the two Q+ charges. They are of different distances from the charges.  The force in the direction E will be greater here. The net force on -Q is acting in the direction D.

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The way to make 3d soft body objects interact pressing against the surface of each other increase friction is given below

The way to make 3d soft body objects interact pressing against the surface of each other increase friction is by:

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Two vertical walls are separated by a distance of 1.5 m, the length of the longest board that can be propped between the walls is approximately 1.4 meters.

To determine the length of the longest board that can be propped between the walls, we need to consider the conditions for equilibrium and the maximum static friction force.

Let's denote the coefficient of static friction between the board and wall 2 as μ.

For the board to be in equilibrium, the net force and net torque acting on it must be zero.

1. Net force in the vertical direction:

The weight of the board (mg) is balanced by the normal force (N) exerted by the walls.

mg = N

2. Net torque:

The torque exerted by the weight of the board about the point where it contacts wall 1 must be balanced by the torque exerted by the static friction force.

The torque due to weight (mg) about the contact point is zero since it acts along the line of contact.

The torque due to static friction (fs) about the contact point is fs * L/2, where L is the length of the board.

Since the board is in equilibrium, the torque due to static friction must balance the torque due to weight:

fs * L/2 = 0

Therefore, the length of the longest board that can be propped between the walls is determined by the condition when the static friction force reaches its maximum value and is on the verge of sliding:

fs max * L/2 = mg

The maximum static friction force (fs max) is given by:

fs max = μ * N

Substituting this into the equation above:

μ * N * L/2 = mg

μ * mg * L/2 = mg

Canceling out the mass and rearranging the equation, we find:

L/2 = 1/μ

L = 1.32/μ

Substituting the given coefficient of static friction (μ = 0.98) into the equation:

L = 1.32/0.98

L ≈ 1.4 meters

Therefore, the length of the longest board that can be propped between the walls is approximately 1.4 meters.

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Answer:

1.6 m/s

Explanation:

First you need to find the momentums of each disc by multiplying their velocities with mass.

disc 1: 7*1= 7 kg m/s

disc 2: 1*9= 9 kg m/s

Second, you need to find the total momentum of the system by adding the momentums of each sphere.

9+7= 16 kg m/s

Because momentum is conserved, this is equal to the momentum of the composite body.

Finally, to find the composite body's velocity, divide its total momentum by its mass. This is because mass*velocity=momentum

16/10=1.6

The velocity of the composite body is 1.6 m/s.

Answer:

1 year = 365 days

because Earth Revolution is the movement of the Earth around the Sun

The earth takes 1 year or 365 days to complete one revolution around the sun. Thus option A is correct.

Rotation and revolution refer to the circular motion of the objects. Rotation is defined as the circular motion of the object about its own axis whereas revolution refers to the circular motion around the other object.

The Earth rotates around its own axis which is called Earth's rotation. The Earth takes 24 hours to rotate on its own axis and the Earth's rotation causes day and night on Earth.

The earth revolves around the Sun which is called Earth's revolution. The Earth takes 365 days to complete one revolution around the Sun and the 365 days is calculated as 1 year. The full revolution of Earth is responsible for climate and seasonal change.

Combined spinning and revolution of Earth lead to changes in daily weather and global climate conditions by affecting wind directions, temperature, and ocean currents, etc.

Thus the Earth takes 1 year to complete one revolution around the Sun. Hence, the ideal solution is Option A.

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The 0.83 Amperes of current will be produced when 100 W lamp is connected to 120 voltage source.

Current is defined as the flow of charge per unit time. It is related with power and voltage. The formula to be used for current calculation is -

P = VI, where P is power, V is voltage and I refers to current.

Keep the values in formula to find the value of current.

I = 100/120

Performing division on Right Hand Side of the equation to calculate current

I = 0.83 Amperes

Thus, the generated current will be 0.83 Amperes.

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Answer:

a transverse wave is a moving wave whose oscillations are perpendicular to the direction of the wave or path of propagation

Explanation:

wave oscillate along paths at right angles to the direction of the wave’s advance.

Explanation:

Answer:

1.95 * 10^8 ms-1

Explanation:

Let us recall that;

Refractive index (n) = Frequency of light in air/Frequency of light in another medium

If Frequency of light in air = 5.09 x 10^14 Hz

Refractive index of sodium chloride = 1.54

Then;

Frequency of light in sodium chloride =  Frequency of light in air/Refractive index of sodium chloride

Therefore;

Frequency of light in sodium chloride =  5.09 x 10^14 Hz/1.54

Frequency of light in sodium chloride =  3.31 x 10^14 Hz

So;

n= Frequency of light in air/Frequency of light in sodium chloride = Speed of light in air/speed of light in sodium chloride

speed of light in sodium chloride = Frequency of light in sodium chloride * Speed of light in air/Frequency of light in air

speed of light in sodium chloride = 3.31 x 10^14 Hz * 3 * 10^8 ms-1/5.09 x 10^14 Hz

speed of light in sodium chloride = 1.95 * 10^8 ms-1

(a) Total mechanical energy is not conserved during the process because there is an external force (gravity) doing work on the ball as it moves up the inclined plane.

The ball gains potential energy as it moves up the incline, which is converted from its initial kinetic energy. Thus, the total mechanical energy of the system increases.

(b) Linear momentum is conserved during the process because there is no net external force acting on the ball in the horizontal direction

. The ball's initial momentum is in the horizontal direction, and it maintains that momentum as it rolls up the incline.

(c) Angular momentum is conserved during the process because there is no net external torque acting on the ball.

The ball's initial angular momentum is due to its rotational motion, and as it rolls up the incline, it continues to rotate about its center of mass with the same angular velocity.

(d) We can apply conservation of mechanical energy to determine the elevation gain of the ball when it comes momentarily to rest. At the moment when the ball comes to rest, all of its initial kinetic energy has been converted into potential energy.

Thus, we can equate the initial kinetic energy to the potential energy at this point:

(1/2)Mv^2 = Mgh

where v is the initial translational speed of the ball (5 m/s), g is the acceleration due to gravity, and h is the elevation gain of the ball. Solving for h, we get:

h = (v^2)/(2g)

This result does not depend on the mass or radius of the ball or the angle of the incline, only on the initial speed of the ball and the acceleration due to gravity.

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Answer:

I think its D.

Explanation:

The total torque created by the two known masses is 1.848 Nm.

We can use the formula for torque, which is given by:

τ = F x r x sin(θ)

where τ is the torque, F is the force applied, r is the distance from the pivot point to the point where the force is applied, and θ is the angle between the force and the lever arm.

For the first mass (193.1 g), the force applied is the weight of the mass, which is:

F1 = m1 x g = 0.1931 kg x 9.81 m/s^2 = 1.893 N

The distance from the pivot point to the point where the force is applied is half the length of the meter stick, which is:

r1 = L/2 = 0.5 m

The angle between the force and the lever arm is 90 degrees, so:

θ1 = 90 degrees

Using these values, we can calculate the torque created by the first mass as:

τ1 = F1 x r1 x sin(θ1) = 1.893 N x 0.5 m x sin(90 degrees) = 0.9465 Nm

For the second mass (183.9 g), we can follow the same procedure and find:

F2 = m2 x g = 0.1839 kg x 9.81 m/s^2 = 1.803 N

r2 = L/2 = 0.5 m

θ2 = 90 degrees

τ2 = F2 x r2 x sin(θ2) = 1.803 N x 0.5 m x sin(90 degrees) = 0.9015 Nm

The total torque created by the two known masses is the sum of these individual torques, which is:

τtotal = τ1 + τ2 = 0.9465 Nm + 0.9015 Nm = 1.848 Nm

Therefore, the total torque created by the two known masses is 1.848 Nm.

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The empty shopping cart is moving at 7.67 m/s.

According to the law of momentum conservation, momentum is only modified by the action of forces as they are outlined by Newton's equations of motion; momentum is never created nor destroyed inside a problem domain.

Total initial momentum = total final momentum

100 kg ×5.0 m/s + 30 kg ×0 m/s = 100 kg ×2.7 m/s + 30 kg ×v

v = (5.0 - 2.7)(100/30) m/s

= 7.67 m/s.

Hence,  the empty shopping cart is moving at  speed of 7.67 m/s.

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To calculate the additional distance the buoy will sink when a man stands on top, we need to consider the change in buoyancy force and the additional weight added to the system.

The buoyancy force is equal to the weight of the fluid displaced by the buoy. In this case, since the buoy is floating vertically, the buoyancy force is equal to the weight of the buoy itself.

Buoyancy force = Weight of the buoy = Mass of the buoy * Gravitational acceleration

Buoyancy force = 1200 kg * 9.8 m/s^2 = 11,760 N

When the man stands on top of the buoy, his weight is added to the system. The additional weight is:

Additional weight = Mass of the man * Gravitational acceleration

Additional weight = 80 kg * 9.8 m/s^2 = 784 N

The additional weight will increase the total weight of the system, and consequently, the buoyancy force will also increase.

The additional distance the buoy will sink can be calculated using Archimedes' principle, which states that the buoyant force is equal to the weight of the fluid displaced by the object.

Additional distance = Additional weight / (Cross-sectional area * Fluid density)

The cross-sectional area of the buoy can be calculated using the diameter:

Cross-sectional area = π * (Diameter/2)^2 = π * (0.9 m / 2)^2

Assuming the fluid density of saltwater is 1025 kg/m^3, we can substitute the values into the equation:

Additional distance = 784 N / (π * (0.9 m / 2)^2 * 1025 kg/m^3)

Calculating the additional distance will provide the specific value based on the given dimensions and assumptions.

In summary, to find the additional distance the buoy will sink when a man stands on top, we consider the change in buoyancy force due to the added weight. By using Archimedes' principle, the additional distance can be calculated by dividing the additional weight by the cross-sectional area of the buoy multiplied by the fluid density.

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Answer:

aceleration doubles

Explanation:

From Newton's secon law, one has

F=m*a

where F is the force, m the mass and a the aceleration.

In general, if m becomes m/2, in order to have the same force,

the acceleration must be doubled:

\(F=m*a=\frac{m}{2} (2*a)\)

In our particular case,

\(12=6*a=\frac{6}{2} (2*a)\\12=3(2*a)\)

Answer:

V = 10m/s for the final velocity.

S = 10m for distance II.

Explanation:

Given the given information:

5m/s2 acceleration

2 seconds Equals time

Because the vehicle begins at rest, its initial velocity is 0m/s.

The first equation of motion would be used to get the ultimate velocity.

V = U + at

We have by substituting into the equation

V = 0 + 5*2

V = 0 + 10

V = 10m/s.

Now, to find the distance covered, we would use the second equation of motion.

S = ut + ½at²

S = 0*2 + ½*5*2²

S = ½*5*4

S = 20/2

S = 10m

The answer is C. I searched it up and people keep on saying that it's B, which is incorrect. I found another question on Brainly where someone said that C was the answer and the person who asked the question said "Correct, thanks."

Answer:

43.3 m/s.

Explanation:

Assuming the potential energy is due to the gravitational potential energy, we can use the conservation of energy to find the kinetic energy:

Total energy = Potential energy + Kinetic energy

Kinetic energy = Total energy - Potential energy

Kinetic energy = 300 J - 40 J = 260 J

However, we need to know the mass of the object to convert the kinetic energy to velocity. We can use the potential energy to find the mass:

Potential energy = mgh

40 J = m(9.81 m/s^2)(300 m)

m = 0.137 kg

Now we can use the kinetic energy to find the velocity:

Kinetic energy = (1/2)mv^2

260 J = (1/2)(0.137 kg)v^2

v^2 = (2*260 J) / 0.137 kg

v = 43.3 m/s (rounded to one decimal place)

Therefore, the kinetic energy is 260 J and the velocity of the object when it reaches the ground is 43.3 m/s.

Answer:

acceleration of 3ms2

Explanation:

we can calculate the net force on the bowling ball from the above equation. Therefore, 30N of force is required to accelerate the bowling ball down the alleyway at a rate of 3ms2

Answer:

carpet

Explanation:

Diffuse reflection is the reflection of light from a surface such that an incident ray is reflected at many angles rather than at just one angle as in the case of specular reflection.

The structure of carpet's surface is as shown. Thus it shows large amount of diffuse reflection.

Answer:

when work is done on the system or heat comes into the system

Answer:

At the point of dropping the object, by Newton's first law due to gravitational force \(F_g\) = m × g, accelerates

By Newton's Second law the object reaches impacts on the air with the gravitational force resulting in changing momentum of m×(Final Velocity - Initial Velocity)

As the velocity increases, the rate of change of momentum becomes equivalent to the gravitational force and by Newton's third law, the action action and reaction are equal and opposite hence they cancel each other out

The body then moves at a constant uniform motion down according to Newton's first law

Explanation:

At the point the object of mass, m, is dropped from the height of the tower, the only force acting on the object is the gravitational force such that the object has an acceleration which is the acceleration due to gravity, g, and the gravitational force is therefore = m × g

As the speed of the object increases while the object is falling with the gravitational acceleration the rate at which the object cuts through layers of air which (by Newton's first law of motion, are at rest ) has some buoyancy effect also increases therefore, the object is constantly increasingly changing the momentum of the air which by Newton's second law results, at an high enough velocity, and by Newton's third law, in a force equal to the applied gravitational force

Therefore, the force of the air drag becomes equal to the gravitational force, cancelling each other out and the object then moves according to Newton;s first law, in uniform motion of a constant speed while still falling down.

A 4kg steel ball moving with a speed of 12m/s in the positive x-direction has a glancing collision with a 6kg ball at rest. After the collision, the 4kg ball moves at an angle of 25 degrees above the x-axis, and the 6kg ball moves at an angle of 40 degrees below the x-axis.The velocities of the two objects after the collision are given by v1f and v2f.

Using the conservation of momentum, we can write: (m1v1i + m2v2i) = (m1v1f + m2v2f) where m1 and v1i are the mass and initial velocity of the 4kg ball, m2 and v2i are the mass and initial velocity of the 6kg ball, and v1f and v2f are the final velocities of the two objects after the collision.

Using the conservation of kinetic energy, we can also write: (1/2)m1v1i² + (1/2)m2v2i² = (1/2)m1v1f² + (1/2)m2v2f² We can use these two equations to solve for v1f and v2f.

First, let's find the initial momentum and kinetic energy of the system:(4kg)(12m/s) + (6kg)(0m/s) = 48kgm/s(1/2)(4kg)(12m/s)² + (1/2)(6kg)(0m/s)² = 288J.

Now, we can use these values to solve for v1f and v2f.

Starting with the momentum equation and substituting in the known values: (4kg)(12m/s) = (4kg)(v1f cos(25°)) + (6kg)(v2f cos(40°)) 48kgm/s = (4kg)(v1f cos(25°)) + (6kg)(v2f cos(40°))

Dividing by 2, we get: 24kgm/s = (2kg)(v1f cos(25°)) + (3kg)(v2f cos(40°))

Solving for v1f cos(25°), we get: v1f cos(25°) = (24kgm/s - 3kgv2f cos(40°))/2kg

Now, let's use the kinetic energy equation to solve for v2f.

Substituting in the known values: 288J = (1/2)(4kg)(v1f sin(25°))² + (1/2)(6kg)(v2f sin(40°))²

Simplifying and solving for v2f, we get: v2f = sqrt((576 - 8v1f² sin²(25°))/(3 sin²(40°)))

Now that we have an expression for v2f, we can substitute it into the momentum equation to solve for v1f.

Substituting in the known values and simplifying, we get: v1f cos(25°) = (24 - 4v1f cos(25°) - 3v2f cos(40°))/2

Solving for v1f, we get: v1f = (24 cos(25°) - 3v2f cos(40°))/6cos(25°) + 2

We can substitute in the value of v2f we found earlier to get:v1f = 2.47m/sv2f = -2.34m/s.

Therefore, the 4kg ball moves at 2.47m/s at an angle of 25 degrees above the x-axis after the collision, and the 6kg ball moves at 2.34m/s at an angle of 40 degrees below the x-axis after the collision.

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Answer:25

Explanation:

Formula(77°F − 32) × 5/9 = 25°C

Answer: The answer is C. 298 K

Explanation:

The time it takes about 7.26 seconds for the car ( starts from rest at time t = 0 and accelerates at −0.6 t + 4 meters/sec² for 0 ≤ t ≤ 12) to go 100 meters.

To determine how long it takes for the car to go 100 meters, we need to use the formula for displacement:

s(t) = \(\frac{1}{2}\) a t² + v₀ t + s₀

Where,

a is the acceleration

v₀ is the initial velocity, and

s₀ is the initial displacement.

In this case, the car starts from rest, so v₀ = 0 and s₀ = 0.

Hence, t:

100 = \(\frac{1}{2}\) (-0.6t + 4) t² + 0 t + 0

100 = -0.3t³ + 2t² 0

= -0.3t³ + 2t² - 100

Using the quadratic formula, we can find the value of t that satisfies this equation:

t = (-2 ± √(2² - 4*(-0.3)*(-100)))/(2*(-0.3))t

= (-2 ± √(-116))/(2*(-0.3))t

≈ 7.26 or t ≈ -4.59

Since t cannot be negative, the answer is t ≈ 7.26. Therefore, it takes about 7.26 seconds for the car to go 100 meters.

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The g - string will stretch by 0.0016 mm.

We have a g - string of a guitar with given specifications.

We have to determine how many mm does a 75-cm-long g - string stretch when it’s first tuned.

According to the question -

The force of tension in the string -

\($v = \sqrt{\frac{T}{\mu} }\)

T = \($v^{2} \mu\) = 250 x 250 x 0.0011 = 68.75 N

The Yung modulus of steel = 2 x \(10^{11}\) N/\(m^{2}\)

the amount by which the g - string will be stretched is given by -

\($\delta L = \frac{LT}{Y(\pi r^{2})}\)

Substituting the values -

\($\delta L = \frac{0.75\times 68.75 }{(2\times 10^{11} )\times (\pi (2.2 \times 10^{-4}\times 2.2\times 10^{-4}) )}\)

\(\delta L=\) 0.0016mm

Hence, the g - string will stretch by 0.0016 mm.

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[ The given question is incomplete. The complete question is

" The G string on a guitar is a 0.46-mm-diameter steel string

with a linear density of 1.1 g/m. When the string is properly

tuned to 196 Hz, the wave speed on the string is 250 m/s. Tuning

is done by turning the tuning screw, which slowly tightens—and

stretches—the string. By how many mm does a 75-cm-long G

string stretch when it’s first tuned? "]

Centrifuge tubes can become pressurized due to the release of gases during a reaction or biological process that occurs within the tube.

The minimum pressure that is reached in this experiment will depend on a number of factors, including the volume of gas produced, the size of the centrifuge tube, and the duration and intensity of the centrifugation process.

This can happen when cells or other biological materials are subjected to high speeds and forces within a centrifuge. The pressure inside the tube can build up as the gas cannot escape the tube, causing it to become pressurized.

It is difficult to estimate the minimum pressure that can be reached without specific details about the experiment being conducted.

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