Suppose you adjust your garden hose nozzle for a hard stream of water. You point the nozzle vertically upward at a height of 1.5 m above the ground. When you quickly turn off the nozzle, you hear the water striking the ground next to you for another 1.8 s. What is the water speed as it leaves the nozzle?

The resultant force that water exerts on the overhang sea wall along abc is 179 kN.

Force is a physical quantity that describes the interaction between two objects, such as a push or a pull. It is defined as any influence that causes an object to undergo a change in motion or deformation. Force is a vector quantity, meaning that it has both magnitude (size or strength) and direction.

Component that is horizontal. Because AB is horizontal, there is no horizontal component. The horizontal component of BC's force is.

(Fbc)h =γwhˉA=(1000kg/m3)(9.81m/s2)(1.5m+21(2m))(2m(2m))=98.1(103)N.

Component that is vertical. The weight of the water contained in blocks Abefa and Bcdeb (shown shaded in Fig. a) is equal to the force on AB and the vertical component of the force on BC. Here,

Aabefa=1.5m(2.5m)=3.75m2and

2Abcdeb=(3.5m)(2m)–4π(2m)2=(7–p)m2. Then,

Fab=γwVabefa=(1000kg/m3)(9.81m/s2)[(3.75m2)(2m)] =73.575(103)N=73.6N (FBC)v=γwVbcdeb=(1000kg/m3)(9.81m/s2)[(7–π)m2(2m)] =75.702(103)N

Therefore,

Fbc=(Fbc)²h2+(Fbc)²v2=√[98.1(10³)N]²+[75.702(10³)N]²=123.91(10³)N=124KN

FR²   =(Fbc)²H2+[Fab+(Fbc)v]²

==[98.1(10³)N]² + [(73.6(10³)N)²+75.702(10³)N²]

=178.6(10³)N = 179 kN.

To know more about resultant force , visit:

https://brainly.com/question/16380983

#SPJ1

The speed of the particle when it enters the magnetic-field region is 120,000 m/s.

Magnetic force on the particle is given as;

F = qvB

where;

From Newton's second law, force on an object is given as;

F = ma

where;

ma = qvB

v = ma/qB

v = (3 x 10⁻² x 12)/(3 x 10⁻⁶ x 1)

v = 120,000 m/s

Thus, the speed of the particle when it enters the magnetic-field region is 120,000 m/s.

Learn more about speed here: https://brainly.com/question/6504879

#SPJ1

Answer:

Volume measures liquid

Explanation:

Volume can be measured in meters and centimeters

1.Unit vector in the direction BA: BA/|BA| = (2/3, 2/3, 1/3)

2.The angular velocity (ω) of the body is given as 3 radians per second.

3.Without the position of point P given, it is not possible to write the position vector of P.

4.Left-handed rotation refers to the direction of rotation where the rotation follows the left-hand rule.

5.Position vector of point A: (4, 1, 1)

Position vector of point B: (2, -1, 0)

The direction vector BA = (-2, -2, -1)

1.To determine the unit vector pointing in the direction BA, we subtract the coordinates of point B from the coordinates of point A and normalize the resulting vector.

The direction vector BA is given by:

BA = (4 - 2, 1 - (-1), 1 - 0) = (2, 2, 1)

To obtain the unit vector in the direction of BA, we divide the direction vector by its magnitude:

|BA| = √(2^2 + 2^2 + 1^2) = √(4 + 4 + 1) = √9 = 3

Unit vector in the direction BA: BA/|BA| = (2/3, 2/3, 1/3)

2.The angular velocity (ω) of the body is given as 3 radians per second.

3.Without the position of point P given, it is not possible to write the position vector of P. Please provide the position of point P to proceed with the calculation.

4.Left-handed rotation refers to the direction of rotation where the rotation follows the left-hand rule. In a left-handed coordinate system, if you curl the fingers of your left hand in the direction of rotation, your thumb will point in the direction of the rotation axis. It is the opposite direction to a right-handed rotation.

5.The position vectors of points A and B are:

Position vector of point A: (4, 1, 1)

Position vector of point B: (2, -1, 0)

The direction vector BA can be obtained by subtracting the coordinates of point A from the coordinates of point B:

BA = (2 - 4, -1 - 1, 0 - 1) = (-2, -2, -1)

For more such questions on vector

https://brainly.com/question/30895553

#SPJ8

Answer: A straight line on the coordinate plane where all points on the line have the same y-coordinate.

Explanation: The purpule iine is the horizontal line:

Ans:

C

Explanation:

because it is moving down the stairs

A spring travelling down a flight of stairs has kinetic energy.

Since it is moving, it would be a spring moving down a set of steps. A stretched spring, a compressed spring, and a spring at the top of a set of steps are all in motion.

Kinetic energy is a type of power that a moving object or particle possesses.

An item accumulates kinetic energy when work, which involves the transfer of energy, is done on it by exerting a net force. A moving object or particle has kinetic energy, which depends on both its mass and its rate of motion.

Therefore, A spring travelling down a flight of stairs has kinetic energy.

To learn more about Kinetic energy, refer to the link:

https://brainly.com/question/26472013

#SPJ5

Answer:

i had this question as well!

Explanation:

Answer:

1. to the Mystic 2. A Theme or social value 3. Something that can be valued 4. Can’t be observed/ Noticed.

Explanation:

The speed of how fast the birdman should be to hit the bucket is 18.8 m/s

The only force acting on the height at which birdman flies is the gravitational force field.

Suppose the initial velocity (u) is parallel to the ground when the time (t) hits the ground.

Then, we can use the second equation of motion to determine the time (t) when the bird hits the ground.

\(\mathbf{S = ut + \dfrac{1}{2}gt^2}\)

\(\mathbf{78 \ m =(0)t + \dfrac{1}{2}(9.8)t^2}\)

\(\mathbf{78 \ m =4.9 t^2}\)

\(\mathbf{t^2 = \dfrac{78 \ m}{4.9 m/s^2} }\)

\(\mathbf{t^2 = 15.918 \ s^2}\)

\(\mathbf{t =\sqrt{ 15.918 \ s}}\)

\(\mathbf{t =3.989\ s}}\)

Now, the speed of how fast the birdman should be to hit the bucket can be determined using;

\(\mathbf{Speed = \dfrac{Distance}{Time}}\)

\(\mathbf{Speed = \dfrac{75 \ m }{3.989\ s}}\)

\(\mathbf{Speed = 18.8 m/s}\)

Therefore, we can conclude that the speed of how fast the birdman should be to hit the bucket is 18.8 m/s

Learn more about speed here:

https://brainly.com/question/22610586?referrer=searchResults

If A box of mass 210 kg is pulled from rest with a string of tension 1300n inclined at 35° to the horizontal. if the box moved with a speed of 10m/s and the frictional force between the box and surface is 100 n, Then the distance covered by the box is 10.89 meters.

To calculate the distance covered by the box, we need to analyze the forces acting on it and apply the work-energy principle.

Given:

Mass of the box, m = 210 kg

Tension in the string, T = 1300 N

The angle of inclination, θ = 35°

Frictional force, f = 100 N

Initial speed, u = 0 m/s

Final speed, v = 10 m/s

First, let's resolve the tension force into components parallel and perpendicular to the incline. The parallel component of the tension force can be calculated as:

T_parallel = T * cos(θ)

Next, let's calculate the net force acting on the box along the incline. The net force is given by:

Net force = T_parallel - f

Now, using Newton's second law, we can calculate the acceleration (a) of the box:

Net force = m * a

From the given information, we have the final velocity (v), initial velocity (u), and acceleration (a). We can use the following kinematic equation to calculate the distance covered (s):

v^2 = u^2 + 2as

Rearranging the equation, we get:

s = (v^2 - u^2) / (2a)

Now, let's plug in the given values and calculate the distance covered:

T_parallel = 1300 N * cos(35°) ≈ 1067.35 N

Net force = 1067.35 N - 100 N = 967.35 N

a = (967.35 N) / (210 kg) ≈ 4.61 m/s^2

s = (10 m/s)^2 - (0 m/s)^2 / (2 * 4.61 m/s^2) ≈ 10.89 m

Therefore, the distance covered by the box is approximately 10.89 meters.

To learn more about Newton's law of motion click:

brainly.com/question/29775827

#SPJ1

The coin travels from origin to (4, 5.8) . The displacement is found by using the Pythagorean Theorem and the two sides, 4 and 5.8 to find a hypotenuse length of 7.05

The angle a that this line makes with the + x-axis is given by tan a = 5.8/4. Taking Inv Tan on a calculator gives a = 54.462 deg.

The constant force F acts at an angle of 121 deg

The angle between the force and the displacement, vectors is thus 121 - 54.4,  

so? = 66.6 deg.

The defn of Work is W = F d cos. = (2 N) (7.05 m) cos 66.6 = 5.6J.

Size is simply defined as distance or amount. It represents the absolute or relative direction or magnitude that an object is moving in the sense of motion. Used to describe the size or extent of something. In physics, size generally refers to distance or quantity.

Learn more about Magnitude here:- https://brainly.com/question/24468862

#SPJ4

Originally there must been

1,4775E6 + 2.25E4 = 147.75E4 + 2.25E4 = 150E4 present at start

% = 2.25 / 150 = 1.5 %      of 235 U left

Answer:

the answer is 2

Explanation:

when you solve for this equation it wont make sense but I'm making you read this because I ain't ever seen 2 best friends.

Answer:

You mean in periods.

They have the same number of elctron shells.

But if they are in the same group then they have the sane number oifValence electrons.

Explanation:

The best graph to use if I want to compare the price of six different cars would be a bar graph

A bar graph is a graphical representation of the given data . It uses bars that extend to different heights to depict value .

Bar graphs are used to compare different type of things between different groups or to see changes over a period of time. Hence , bar graph will fits the best if one want to compare the price of six different cars .

To learn more about Bar graphs here :

https://brainly.com/question/12967992

#SPJ1

Answer:

1. 125N

2. 200N

3. 280N

Explanation:

Force= mass × acceleration

1. force= 25×5

= 125N

2. Force= 50×4

=200N

3. Force=70×4

=280N

Answer:

where the y axis is

Explanation:

In more simple terms, a horizontal line on any chart is where the y-axis values are equal. If it has been drawn to show a series of highs in the data, a data point moving above the horizontal line would indicate a rise in the y-axis value over recent values in the data sample.

The time when the particle is at rest is at 1.63 s or 3.36 s.

The velocity is positive at when the time of motion is at \(0<t<1.63 \ s \ \ or \ \ t> 3.36 \ s\).

The total distance traveled in the first 10 seconds is 847 m.

The time when the particle is at rest is calculated as follows;

s(t) = 2t³ - 15t² + 33t + 17

\(v = \frac{ds}{dt} = 6t^2 -30t + 33\\\\at \ rest, \ v = 0\\\\6t^2 - 30t + 33 = 0\\\\6(t- \frac{5}{2} )^2- \frac{9}{2} = 0\\\\t = 1.63\ s \ \ or \ 3.36 \ s\)

The velocity is positive at when the time of motion is as follows;

\(0<t<1.63 \ s \ \ or \ \ t> 3.36 \ s\).

The total distance traveled in the first 10 seconds is calculated as follows;

\(2(10)^3 - 15(10)^2 + 33(10) + 17 = 847 \ m\)

Learn more about motion of particles here: https://brainly.com/question/11066673

Answer:

rocks are vertical.

Explanation:

I'm so sorry if I'm wrong this is what I think

2. 20kmh 3. 68.6 m

Source: Trust me bro

Elements are arranged on the periodic table in terms of valence electrons based on their atomic number and electron configuration.

1. Elements are arranged on the periodic table in terms of valence electrons based on their atomic number and electron configuration. The valence electrons are the outermost electrons in an atom's electron shell, and they are crucial in determining the chemical properties and reactivity of elements.

2. Evidence from data tables can be shown by examining the electron configuration and the group and period numbers of various elements on the periodic table. Here is a simplified example:

Element   | Electron Configuration | Group | Period |

--------------------------------------------

Hydrogen  | 1s^1                              | 1     | 1      |

Lithium       | [He] 2s^1                     | 1     | 2      |

Carbon       | [He] 2s^2 2p^2          | 14    | 2      |

Oxygen      | [He] 2s^2 2p^4          | 16    | 2      |

Neon          | [He] 2s^2 2p^6          | 18    | 2      |

--------------------------------------------

3. The evidence from the data table supports the claim that the arrangement of elements on the periodic table is based on valence electrons.

- Group Trend: Elements within the same group (vertical columns) share the same number of valence electrons. In the example table, Hydrogen, Lithium, and Neon are all in Group 1, indicating they have 1 valence electron.

- Period Trend: Elements within the same period (horizontal rows) have the same number of electron shells. In the example table, Hydrogen and Lithium are in Period 1, indicating they have their valence electron in the first energy level. Carbon, Oxygen, and Neon are in Period 2, indicating they have their valence electrons in the second energy level.

By examining the electron configurations, group numbers, and period numbers, we can clearly see the trends and patterns in the number of valence electrons for both groups and periods on the periodic table. This evidence supports the claim that the arrangement of elements on the periodic table is based on their valence electrons, which play a crucial role in determining their chemical behavior and properties.

For more such questions on the periodic table:

https://brainly.com/question/15987580

#SPJ8

The theory that has been proposed that would explain the neurology of memory are;

The neurophysiology of learning  can be described as the theory that cover the three main cognitive processes and this can be regarded as core value of the the information processing system.

It should be noted that the  information processing system usually make use of the  brains  which helps to remember information through attention, perception and all this are found in the functionality of the brain system in the human system.

Therefore, All of these are correct.

Learn more about memory at:

https://brainly.com/question/25040884

#SPJ1

A cyclist must lean into a turn to prevent tipping over in the other direction.The frictional force provides the centripetal force necessary to turn the cyclist to the left.But the frictional force also produces a clockwise torque that will cause the rider and the bicycle to tip clockwise to the right.The force is provided by the friction of the tires.

Answer:

to become stable

Explanation:

when it bends it body, it moves closer to the center of gravity which makes the bicycle stable and hence the turn can be taken easily

Answer:

A capacitor is formed from two square plates of edge length a and separation d, with d <

Explanation:

A capacitor is formed from two square plates of edge length a and separation d, with d <

a) The speed of the 6.00 kg block after descending 0.800 m is 2.07 m/s.

b) We cannot calculate the work done by the friction force.

c) The net work done on the system of two blocks during the 0.800 m downward displacement of the 6.00 kg block is 29.13 J. The work done by gravity is 47.04 J, the work done by friction is unknown, and the work done by the tension in the rope is zero.

(a) The work done on the 6.00 kg block by gravity can be calculated using the formula:

Work_gravity = force_gravity * displacement * cos(theta),

where force_gravity is the weight of the block, displacement is the downward displacement of the block, and theta is the angle between the force and displacement vectors (which is 0 degrees in this case).

The weight of the block is given by:

force_gravity = mass * acceleration_due_to_gravity = 6.00 kg * 9.8 m/s^2 = 58.8 N.

Plugging in the values, we get:

Work_gravity = 58.8 N * 0.800 m * cos(0) = 47.04 J.

The work done on the 6.00 kg block by the tension in the rope is given by:

Work_tension = tension * displacement * cos(theta).

Plugging in the values, we get:

Work_tension = 37.0 N * 0.800 m * cos(180) = -29.6 J.

The negative sign indicates that the tension is in the opposite direction of the displacement.

Using the work-energy theorem, we can find the speed of the 6.00 kg block after descending 0.800 m:

Work_net = change_in_kinetic_energy.

Since the block starts from rest, its initial kinetic energy is zero. Therefore:

Work_net = Final_kinetic_energy - Initial_kinetic_energy = 1/2 * mass * velocity^2.

Solving for velocity, we get:

velocity = sqrt(2 * Work_net / mass).

The net work done on the block is the sum of the work done by gravity and the tension:

Work_net = Work_gravity + Work_tension = 47.04 J - 29.6 J = 17.44 J.

Plugging in the values, we get:

velocity = sqrt(2 * 17.44 J / 6.00 kg) = 2.07 m/s.

Therefore, the speed of the 6.00 kg block after descending 0.800 m is 2.07 m/s.

(b) The total work done on the 8.00 kg block during the 0.800 m displacement can be calculated using the work-energy theorem:

Work_net = change_in_kinetic_energy.

Since the 8.00 kg block is not moving vertically, its initial and final kinetic energies are zero. Therefore:

Work_net = Final_kinetic_energy - Initial_kinetic_energy = 0.

The work done on the 8.00 kg block by the tension in the rope is given by:

Work_tension = tension * displacement * cos(theta).

Plugging in the values, we get:

Work_tension = 37.0 N * 0.800 m * cos(0) = 29.6 J.

The work done on the 8.00 kg block by the friction force can be calculated using the formula:

Work_friction = force_friction * displacement * cos(theta),

where force_friction is the frictional force on the block. However, the problem statement does not provide the value of the friction force. Therefore, we cannot calculate the work done by the friction force.

(c) The net work done on the system of two blocks during the 0.800 m displacement of the 6.00 kg block can be found using the work-energy theorem:

Work_net = change_in_kinetic_energy.

Since the system starts from rest, the initial kinetic energy of the system is zero. Therefore:

Work_net = Final_kinetic_energy - Initial_kinetic_energy = 1/2 * (6.00 kg + 8.00 kg) * velocity^2.

Simplifying, we get:

Work_net = 1/2 * 14.00 kg * velocity^2.

Using the value of velocity calculated in part (a), we get:

Work_net = 1/2 * 14.00 kg * (2.07 m/s)^2 = 29.13 J.

The work done on the system of two blocks by gravity is the sum of the work done on the individual blocks by gravity:

Work_gravity_system = Work_gravity_6kg + Work_gravity_8kg = 47.04 J + 0 J = 47.04 J.

The work done on the system of two blocks by the tension in the rope is the sum of the work done on the individual blocks by the tension:

Work_tension_system = Work_tension_6kg + Work_tension_8kg = -29.6 J + 29.6 J = 0 J.

Therefore, the net work done on the system of two blocks during the 0.800 m downward displacement of the 6.00 kg block is 29.13 J. The work done by gravity is 47.04 J, the work done by friction is unknown, and the work done by the tension in the rope is zero.

Note: The calculations for part (b) and (c) were based on the given information, but the value of the friction force was not provided in the problem statement.

For more such questions on work done, click on:

https://brainly.com/question/8119756

#SPJ8

Answer:

A. the motion of an object along a curved path

Answer: 0.3 m/sec

Explanation:

Vrel = (Vs-Vm) = (0.8-0.5) = 0.3 m/sec

Answer:

0.3 m/s east

Explanation:

According to the triangle law of vector addition, the outcome must be zero if the sum of two forces remains force.

what is the resultant vector ?

A resultant vector is a vector that combines the effects of all the vectors. The resultant vector is the result of adding two or more vectors.

The vector combo of two or more single vectors is the resulting vector definition. Each vector has an x-component (right or left direction) and a y-component (up or down direction), however one of them may be zero. The resulting vector has an x component equal to the total of the single vectors' x components and a y component equal to the sum of the separate vectors' y components. For three-dimensional vectors, the resultant's z-component is equal to the total of the single vectors' z-components. This essay will concentrate on vectors in two dimensions.

A resultant vector differs from a single vector in that the former represents the force, speed, or other quantity from a single source, whereas the latter represents the force, speed, or other quantity from several sources.

In this case, the three forces will not keep the particle in equilibrium, hence the net force will not be zero and the particle will move with an acceleration.

To learn more about resultant vector follow the given link: https://brainly.com/question/11823989

#SPJ9